I am new to using Jquery using mysql and
PHP
I am using the following code to pull the data. But there is not data or error displayed.
JQUERY:
<html>
<head>
<script>
function doAjaxPost() {
// get the form values
var field_a = $("#field_a").val();
$("#loadthisimage").show();
$.ajax({
type: "POST",
url: "serverscript.
php",
data: "ID="+field_a,
success: function(resp){
$("#resposnse").html(resp);
$("#loadthisimage").hide();
},
error: function(e){
alert('Error: ' + e);
}
});
}
</script>
</head>
<body>
<select id="field_a">
<option value="data_1">data_1</option>
<option value="data_2">data_2</option>
</select>
<input type="button" value="Ajax Request" onClick="doAjaxPost()">
<a href="#" onClick="doAjaxPost()">Here</a>
</form>
<div id="resposnse">
<img src="ajax-loader.gif" style="display:none" id="loadthisimage">
</div>
</body>
and now serverscript.
php
<?php
if(isset($_POST['ID'])) {
$nm = $_POST['ID'];
echo $nm;
//insert your code here for the display.
mysql_connect("localhost", "root", "pop") or die(mysql_error());
mysql_select_db("JPro") or die(mysql_error());
$result1 = mysql_query("select Name from results where ID = \"$nm\" ") or die(mysql_error());
// store the record of the "example" table into $row
while($row1 = mysql_fetch_array( $result1 )) {
$tc = $row1['Name'];
echo $tc;
}
}
?>
