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  • What could be the Consequence of inserting "id" in any autoincrementing 'id' containing table?

    - by Parth
    What could be the Consequence of inserting "id" in any autoincrementing 'id' containing table? If I have a Tabe in which I have configured the column "id" as the auto incrmented, But still I am using an INSERT query in which id is defined, like wise INSERT INTO XYZ (id) values ('26'); How does it going to effect the table and the process related to it.. Is it "no issues" to do this? or it should be avoided?

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  • Similar SQL queries returning different results...

    - by Pablo
    Here are the SQL Queries: $sql1 = "SELECT count(thread) AS total FROM comments WHERE thread=1 AND parent_id=0 "; $sql2 = "SELECT count(thread) AS total FROM comments, users WHERE thread=1 AND parent_id=0 AND users.user_id=comments.user_id "; $sql3 = "SELECT comments.*, users.username AS username FROM comments, users WHERE thread=1 AND parent_id=0 AND users.user_id=comments.user_id ORDER BY date LIMIT 10, 5 "; My question is why would $sql1 and $sql2 would return two different results? $sql1 returns 61 rows $sql2 returns 56 rows The 5th line in $sql2 is just for testing, is not required, is just a variation of $sql1 which gets the total rows for a pagination.

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  • Drupal - db_fetch_array returns NULL for every row

    - by darudude
    I'm using Drupal's db_fetch_array to fetch rows from my db_query. However, every row returned is equal to NULL. Typing the query into PHP myadmin works, so I have no idea whats going on. db_num_rows returns the number of rows as well. Here is the code: if(count($rebuild_ids)) { $ids=implode(",",$rebuild_ids); $type_stmt = "SELECT * from {" . ItemType::$type_table_name . "} where id IN ($ids)"; $new_items=db_query($type_stmt); if(!$new_items || db_num_rows($new_items) == 0) { return; } while($row = db_fetch_array($new_items)); { if ($row!=NULL) { echo "I work!" $game_items[] = $row['id']; ItemInstance::$nid_to_item_type_code[$row['nid']] = $row['id']; } } } However, it never gets into the third if statement (i.e. never echos "I work!") Any ideas?

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  • PHP/MySQL Interview - How would you have answered?

    - by martincarlin87
    I was asked this interview question so thought I would post it here to see how other users would answer: Please write some code which connects to a MySQL database (any host/user/pass), retrieves the current date & time from the database, compares it to the current date & time on the local server (i.e. where the application is running), and reports on the difference. The reporting aspect should be a simple HTML page, so that in theory this script can be put on a web server, set to point to a particular database server, and it would tell us whether the two servers’ times are in sync (or close to being in sync). This is what I put: // Connect to database server $dbhost = 'localhost'; $dbuser = 'xxx'; $dbpass = 'xxx'; $dbname = 'xxx'; $conn = mysql_connect($dbhost, $dbuser, $dbpass) or die (mysql_error()); // Select database mysql_select_db($dbname) or die(mysql_error()); // Retrieve the current time from the database server $sql = 'SELECT NOW() AS db_server_time'; // Execute the query $result = mysql_query($sql) or die(mysql_error()); // Since query has now completed, get the time of the web server $php_server_time = date("Y-m-d h:m:s"); // Store query results in an array $row = mysql_fetch_array($result); // Retrieve time result from the array $db_server_time = $row['db_server_time']; echo $db_server_time . '<br />'; echo $php_server_time; if ($php_server_time != $db_server_time) { // Server times are not identical echo '<p>Database server and web server are not in sync!</p>'; // Convert the time stamps into seconds since 01/01/1970 $php_seconds = strtotime($php_server_time); $sql_seconds = strtotime($db_server_time); // Subtract smaller number from biggest number to avoid getting a negative result if ($php_seconds > $sql_seconds) { $time_difference = $php_seconds - $sql_seconds; } else { $time_difference = $sql_seconds - $php_seconds; } // convert the time difference in seconds to a formatted string displaying hours, minutes and seconds $nice_time_difference = gmdate("H:i:s", $time_difference); echo '<p>Time difference between the servers is ' . $nice_time_difference; } else { // Timestamps are exactly the same echo '<p>Database server and web server are in sync with each other!</p>'; } Yes, I know that I have used the deprecated mysql_* functions but that aside, how would you have answered, i.e. what changes would you make and why? Are there any factors I have omitted which I should take into consideration? The interesting thing is that my results always seem to be an exact number of minutes apart when executed on my hosting account: 2012-12-06 11:47:07 2012-12-06 11:12:07

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  • login not working when changing from mysql to mysqli

    - by user1438647
    I have a code below where it logs a teacher in by matching it's username and password in the database, if correct, then log in, if incorrect, then display a message. <?php session_start(); $username="xxx"; $password="xxx"; $database="mobile_app"; $link = mysqli_connect('localhost',$username,$password); mysqli_select_db($link, $database) or die( "Unable to select database"); foreach (array('teacherusername','teacherpassword') as $varname) { $$varname = (isset($_POST[$varname])) ? $_POST[$varname] : ''; } ?> <form action="<?php echo htmlentities($_SERVER['PHP_SELF']); ?>" method="post" id="teachLoginForm"> <p>Username</p><p><input type="text" name="teacherusername" /></p> <!-- Enter Teacher Username--> <p>Password</p><p><input type="password" name="teacherpassword" /></p> <!-- Enter Teacher Password--> <p><input id="loginSubmit" type="submit" value="Login" name="submit" /></p> </form> <?php if (isset($_POST['submit'])) { $query = " SELECT * FROM Teacher t WHERE (t.TeacherUsername = '".mysqli_real_escape_string($teacherusername)."') AND (t.TeacherPassword = '".mysqli_real_escape_string($teacherpassword)."') "; $result = mysqli_query($link, $query); $num = mysqli_num_rows($result); $loged = false; while($row = mysqli_fetch_array($result)) { if ($_POST['teacherusername'] == ($row['TeacherUsername']) && $_POST['teacherpassword'] == ($row['TeacherPassword'])) { $loged = true; } $_SESSION['teacherforename'] = $row['TeacherForename']; $_SESSION['teachersurname'] = $row['TeacherSurname']; $_SESSION['teacherusername'] = $row['TeacherUsername']; } if ($loged == true){ header( 'Location: menu.php' ) ; }else{ echo "The Username or Password that you Entered is not Valid. Try Entering it Again."; } mysqli_close($link); } ?> Now the problem is that even if the teacher has entered in the correct username and password, it still doesn't let the teacher log in. When the code above was the old mysql() code, it worked fine as teacher was able to login when username and password match, but when trying to change the code into mysqli then it causes login to not work even though username and password match. What am I doing wrong?

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  • Need help with some complex SQL query

    - by Psyche
    Hello guys, I need some help with a complex SQL query. Here's my setup: there are two tables, one with authors, and another with books. The books table contains a field named "author" which holds author's id. If a book has more than one author, then the "author" field will contain all the authors ids separated by ";" (something like 2;34;234). On the website I have to list all the books written by an author. If there's only one author, its simple, but how can I get those books where the author I'm interested in is the second or third author? Many thanks.

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  • mysql - How select a akin records?

    - by zeroonea
    I have a table with name varchar address varchar country varchar city varchar ..... to store address of location example: name|address|country HaLong hotel|156 blahblah street|Vietnam Hotel Ha Long|156 blah blah|Vietnam Two rows above is duplicate data. I have a form, when user submit new location. The code need to find akin records to give a message (ex: This location already in db, use it or create new?) How to make a query to get akin record like this?

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  • mysql: managing memory usage

    - by every_answer_gets_a_point
    i am doing a delete with a LIKE statement my keybuffer is 25m, the sort buffer size is 256k the delete has been taking over 2 hours should i increase memory usage? there are about 50 megs of data in the table from which i am deleting, thats about 500,000 rows is there anything else i can do on the adminsitration size to speed up this delete?

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  • MySQL Joining three tables

    - by text
    I am doing a query with three tables, the problem was one table has many occurrences of id of another. sample data: users: id answers: id:1 user_answer :1 id:1 user_answer :2 id:1 user_answer :3 Questions: id:1 answers :answer description id:2 answers :answer description id:3 answers :answer description How can I get all user information and all answer and its description, I used GROUP by user.id but it only returns only one answer. I want to return something like this list all of users answer: Name Q1 Q2 USERNAME ans1,ans2 ans1,ans2 comma separated description of answer here

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  • MSYQL ~ Why does this query only select a single row?

    - by Joe
    SELECT * FROM tbl_houses WHERE (SELECT HousesList FROM tbl_lists WHERE tbl_lists.ID = '123') LIKE CONCAT('% ', tbl_houses.ID, '#') ^ It only selects the row from tbl_houses of the last occuring "tbl_houses.ID" inside tbl_lists.HousesList I need it to select ALL the rows where any ID from tbl_houses exists within tbl_lists.HousesList

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  • Is it possible to download a large database using mysql query

    - by Rose
    i am downloading files from server using WinSCP.Is it possible to write a query to download a large database using mysql query? Or using any other method i have tried with this code but i am not able to get the whole database structure <?php if(file_exists('backup_sql/my_backup.zip')) { unlink('backup_sql/my_backup.zip'); } $tables='*'; $host='MY HOST NAME'; $user='MY_USERNAME'; $pass='MYPASSWORD'; $name='MY_DB_NAME'; $link = mysql_connect($host,$user,$pass); mysql_select_db($name,$link); //get all of the tables if($tables == '*') { $tables = array(); $result = mysql_query('SHOW TABLES'); while($row = mysql_fetch_row($result)) { $tables[] = $row[0]; } } else { $tables = is_array($tables) ? $tables : explode(',',$tables); } $return=''; //cycle through foreach($tables as $table) { $result = mysql_query('SELECT * FROM '.$table); $num_fields = mysql_num_fields($result); //$return.= 'DROP TABLE '.$table.';'; $row2 = mysql_fetch_row(mysql_query('SHOW CREATE TABLE '.$table)); $return.= "\n\n".$row2[1].";\n\n"; for ($i = 0; $i < $num_fields; $i++) { while($row = mysql_fetch_row($result)) { $return.= 'INSERT INTO '.$table.' VALUES('; for($j=0; $j<$num_fields; $j++) { $row[$j] = addslashes($row[$j]); //$row[$j] = ereg_replace("\n","\\n",$row[$j]); if (isset($row[$j])) { $return.= '"'.$row[$j].'"' ; } else { $return.= '""'; } if ($j<($num_fields-1)) { $return.= ','; } } $return.= ");\n"; } } $return.="\n\n\n"; } $rand_var=time(); $files_to_zip = array( "'backup_sql/db-backup-'.$rand_var.'.sql'", ); $name = 'db-backup-'.$rand_var.'.sql'; $data = $return; ?> any one please help me... thank you

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  • Can anybody recommend a good data recovery strategy?

    - by Jurassic_C
    So lets say you've failed at preventing a drive failure, and also, you've failed to make a backup of said drive. Push has come to shove and now you need a way to recover you're precious data. Has anybody out there run into this situation? And if so could you please provide any suggestions on how to recover the data based on your experiences? For example have you used any data recovery services that you could either recommend, or that you would definitely avoid if you had a do-over? Thanks in advance

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  • Outer select column value in joined subquery?

    - by Michael DePetrillo
    Is it possible to use a column value from an outer select within a joined subquery? SELECT table1.id, table2.cnt FROM table1 LEFT JOIN (SELECT COUNT(*) as `cnt` FROM table2 where table2.lt > table1.lt and table2.rt < table1.rt) as table2 ON 1; This results in "Unknown column 'table1.lt' in 'where clause'". Here is the db dump. CREATE TABLE IF NOT EXISTS `table1` ( `id` int(1) NOT NULL, `lt` int(1) NOT NULL, `rt` int(4) NOT NULL) ENGINE=MyISAM DEFAULT CHARSET=latin1; CREATE TABLE IF NOT EXISTS `table2` ( `id` int(1) NOT NULL, `lt` int(1) NOT NULL, `rt` int(4) NOT NULL) ENGINE=MyISAM DEFAULT CHARSET=latin1; INSERT INTO `table1` (`id`, `lt`, `rt`) VALUES (1, 1, 4); INSERT INTO `table2` (`id`, `lt`, `rt`) VALUES (2, 2, 3);

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  • Updating multiple rows with an array

    - by Copephobia
    I have a table that holds user information. One of the columns holds the position of the user in the game they are in. When a game is being created, I need to update the positions of the users of each team. Here is an example: Game id : 7 Team 1 users : 1,2 Team 2 users : 3,4 team1_position : array(1,2) team2_position : array(13,14) What I want to do is update the user table using the array of positions in the SET area. My goal is to be able to update the users without the need for their id (I have different size game boards, so I have multiple position arrays for each board size) How can I do something like this: UPDATE user SET position='(team1_position)' WHERE game = '7' AND team = '1' I feel like it would be a waste of resources to select all the id's of each team and update them separately.

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  • SQL - Link to more table information

    - by BioXhazard
    I have a datagrid with 3 of 5 fields from a SQL table. The first databound was changed to an asp:hyperlink so the field can be clicked. What I want to do is, when the user clicks an object in the field, it sends the ID to another page. From there, it uses the request in order to display the required information which is found in the same SQL table. For example: User clicks on a cell in the first column, it brings them to a page with more information on that cell.

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  • SELECT DISTINCT multiple field search?

    - by Patrick
    I'm trying to search multiple fields zc_city and zc_zip for when user input and then return row results for zc_city zc_state and zc_zip $q = strtolower($_GET["q"]); if (!$q) return; $sql = "SELECT DISTINCT zc_city AS zcity FROM search_zipcodes WHERE zc_city LIKE '$q%'"; $rsd = mysql_query($sql); while($rs = mysql_fetch_array($rsd)) { $zcity = $rs['zcity']; echo "$zcity\n"; }

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  • What does `?` stand for in SQL?

    - by user295189
    I have this SQL by a programmer: $sql = " INSERT INTO `{$database}`.`table` ( `my_id`, `xType`, `subType`, `recordID`, `textarea` ) VALUES ( {$my_id}, ?xType, ?subType, {$recordID}, ?areaText ) "; My question is why is he using ? before values? How do I see what values are coming in? I did echo and it shows ?xType as ?xType. No values. What does ? stand for in SQL?

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  • Problem with mysql_query() ;Says resource expected .

    - by user364651
    I have this php file. The lines marked as bold are showing up the error :"mysql_query() expecets parameter 2 to be a resources. Well, the similar syntax on the line on which I have commented 'No error??' is working just fine. function checkAnswer($answerEntered,$quesId) { //This functions checks whether answer to question having ques_id = $quesId is satisfied by $answerEntered or not $sql2="SELECT keywords FROM quiz1 WHERE ques_id=$quesId"; **$result2=mysql_query($sql2,$conn);** $keywords=explode(mysql_result($result2,0)); $matches=false; foreach($keywords as $currentKeyword) { if(strcasecmp($currentKeyword,$answerEntered)==0) { $matches=true; } } return $matches; } $sql="SELECT answers FROM user_info WHERE user_id = $_SESSION[user_id]"; $result=mysql_query($sql,$conn); // No error?? $answerText=mysql_result($result,0); //Retrieve answers entered by the user $answerText=str_replace('<','',$answerText); $answerText=str_replace('>',',',$answerText); $answerText=substr($answerText,0,(strlen($answerText)-1)); $answers=explode(",",$answerText); //Get the questions that have been assigned to the user. $sql1="SELECT questions FROM user_info WHERE user_id = $_SESSION[user_id]"; **$result1=mysql_query($sql1,$conn);** $quesIdList=mysql_result($result1,0); $quesIdList=substr($quesIdList,0,(strlen($quesIdList)-1)); $quesIdArray=explode(",",$quesIdList); $reportCard=""; $i=0; foreach($quesIdArray as $currentQuesId) { $answerEnteredByUser=$answers[$i]; if(checkAnswer($answerEnteredByUser,$currentQuesId)) { $reportCard=$reportCard+"1"; } else { $reportCard=$reportCard+"0"; } $i++; } echo $reportCard; ?> Here is the file connect.php. It is working just fine for other PHP documents. <?php $conn= mysql_connect("localhost","root","password"); mysql_select_db("quiz",$conn); ?>

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  • mysql select help

    - by user344766
    Hi I have a table that looks like this id : productid : featureid and would have the following data: (1, 1, 16) (2, 1, 21) (3, 1, 25) (4, 2, 16) (5, 2, 21) (6, 2, 27) where featureid is a foreign key to another table. I need to select products that have both featureids of 16 and 25, in which case productid 1 but not productid 2 Can someone show me an example of how to format this query.

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  • MySQLi - Should every statement be prepared?

    - by Kerry
    I know its supposed to improve performance and clean strings, but lets say there are no variables? Might just be a SELECT COUNT( `column` ) AS count FROM `table` Should that be prepared? Is there any case that a SELECT statement should not be prepared?

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