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• SQL Saturday and Exploring Data Privacy

  - by Johnm

  I have been highly impressed with the growth of the SQL Saturday phenomenon. It seems that an announcement for a new wonderful event finds its way to my inbox on a daily basis. I have had the opportunity to attend the first of the SQL Saturday's for Tampa, Chicago, Louisville and recently my home town of Indianapolis. It is my hope that there will be many more in my future. This past weekend I had the honor of being selected to speak amid a great line up of speakers at SQL Saturday #82 in Indianapolis. My session topic/title was "Exploring Data Privacy". Below is a brief synopsis of my session: Data Privacy in a Nutshell        - Definition of data privacy        - Examples of personally identifiable data        - Examples of Sensitive data Laws and Stuff        - Various examples of laws, regulations and policies that influence the definition of data privacy        - General rules of thumb that encompasses most laws Your Data Footprint        - Who has personal information about you?        - What are you exchanging data privacy for?        - The amazing resilience of data        - The cost of data loss Weapons of Mass Protection       - Data classification       - Extended properties       - Database Object Schemas       - An extraordinarily brief introduction of encryption       - The amazing data professional  <-the most important point of the entire session! The subject of data privacy is one that is quickly making its way to the forefront of the mind of many data professionals. Somewhere out there someone is storing personally identifiable and other sensitive data about you. In some cases it is kept reasonably secure. In other cases it is kept in total exposure without the consideration of its potential of damage to you. Who has access to it and how is it being used? Are we being unnecessarily required to supply sensitive data in exchange for products and services? These are just a few questions on everyone's mind. As data loss events of grand scale hit the headlines in a more frequent succession, the level of frustration and urgency for a solution increases. I assembled this session with the intent to raise awareness of sensitive data and remind us all that we, data professionals, are the ones who have the greatest impact and influence on how sensitive data is regarded and protected. Mahatma Gandhi once said "Be the change you want to see in the world." This is guidance that I keep near to my heart as I approached this topic of data privacy.

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• PHP - Retrieve Data From mySQL Server

  - by Kevin

  Hello, Does anyone know how to retrieve a piece of data and display the results in php file? A similar query that I would enter is something like this: SELECT 'email' FROM 'users' WHERE 'username' = 'bob' Thus, the result would be just the email. Thanks, Kevin

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• XP can't read data from transferred HD

  - by Alexander Miller

  Computer A, running XP, died. XP was installed on a fresh HD in computer B. Slaved data-backup HD from A was installed as slave on B. B will not read it; shows only 2 folders, Recycler and System Volume Info. All of these are older machines with IDE drives. What's going on & how can I read/transfer the data from the transferred drive? This was only a trial run. Actually I will need to transfer the master HD from A - which has XP on it - and read from its data partition because (blush) the backup drive was not up to date.

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• How to use Insert .. select, with conditional vars from insert

  - by WmasterJ

  I have two separate tables both with user id columns uid. I want to take a value from all users in one table and insert it into the correct row for the correct user in the other table. INSERT INTO users2 (picture) SELECT pv.value FROM profile_values as pv, users2 as u WHERE pv.uid = u.uid AND pv.fid = 31 AND users2.uid=u.uid; But it's not working because i seem not to have access to users2.uid inside of the select statement. How would I accomplish this?

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• Reiserfs partition data recovery

  - by user991554

  i am having windows xp as my os. but i have raiserfs partions created by suse linux on same HDD. i need to recover data from the linux partitions now. i created opensuse live usb and booted from it. but it is showing free space in disk manager instead of linux partitions. but i accessed from one windows application(e.g Ext2Read ) which is showing linux partitions but not able to recover data from them as they are demo applications. why opensuse live usb os showing free space instead of linux partitions. Any other metyhod to recover data from them?

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• Fast Data Executive Round Table FY14 event kit

  - by JuergenKress

  We are very interested to run joint marketing events jointly with you as our partners! At our SOA Community Workspace (SOA Community membership required) you can find a new Fast Data Executive Round Table FY14 event kit. This event is designed at senior IT and executives level for the purposes of education, awareness, and thought leadership around the subject of big data; and a specific flavor of big data - Fast Data - that has begun to spark the imagination of many Oracle customers. Fast Data is not new. It’s a term that was invented initially by Ovum’s Tony Baer as a way to represent the collection of ‘high velocity’ solutions with respect to the big data. For Oracle, the Fast Data campaign in FY13 began as a way to tie a broader set of solutions together (SOA/Business Process Management, Data Integration and Business Analytics) under a set of use cases focused on real-time, high velocity data. It has helped to give Oracle a leap-frog advantage over many of the niche integration vendors (i.e. Informatica, Pega, Tibco, Software AG, Terracotta) who haven’t been able to address these types of end-to-end use cases which rely on the combination of filtering, in-memory data processing, correlation, real-time data movement and transformation, end-to-end analytics, and business process management. Only Oracle can address all the dimensions of fast data, and only Oracle can provide a set of engineered solutions to address this space. This event is designed to continue that thought leadership momentum and raise the awareness about what Oracle Fast Data solutions are designed to solve. It’s designed to highlight real customer solutions and articulate the business benefits that fast data can address. This is not an event that gets into the esoteric technical standards of Hadoop, NoSQL, and in-memory data grids. This is an event that instead gets into the heart of business problems that big data has left un-addressed and charts the path for next steps in fast data. Get the Fast Data Executive Round Table FY14 event kit here. Support marketing campaigns We can support such events by: Oracle speakers - contact your partner manager Marketing budget - contact your A&C marketing manager Event location - free use of Oracle Customer Visitor Centers conference rooms Promote your event at events.oracle.com: http://tinyurl.com/eventspecialized E-Blast: invite customers to your event – contact your A&C marketing manager For additional marketing kits e.g for Business Process Managementplease visit our SOA Community Workspace. SOA & BPM Partner Community For regular information on Oracle SOA Suite become a member in the SOA & BPM Partner Community for registration please visit www.oracle.com/goto/emea/soa (OPN account required) If you need support with your account please contact the Oracle Partner Business Center. Blog Twitter LinkedIn Facebook Wiki Mix Forum Technorati Tags:

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• How do I echo out something different when reached last row?

  - by Josh Brown

  I am wanting to not echo out the comma at the end of the echo after the last row. How can I do that? Here is my code: <?php header("Content-type: application/json"); echo '{"points":['; mysql_connect("localhost", "user", "password"); mysql_select_db("database"); $q = "SELECT venues.id, venues.lat, venues.lon, heat_indexes.temperature FROM venues, heat_indexes WHERE venues.id = heat_indexes.venue_id"; $res = mysql_query($q) or die(mysql_error()); while ($point = mysql_fetch_assoc($res)) { echo $point['lat'] . "," . $point['lon'] . "," . $point['temperature'] . ","; } mysql_free_result($res); echo ']}'; ?>

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• "No database selected" even when db clearly selected

  - by Someone

  One of my webpages gets a recurring error: "No database selected", even though the DB is selected. Right about now it's a 50-50 chance whether the page will load just fine, or whether I receive this error. After one or two reloads, the page works again. I am including the exact same connection file on my other pages, and I don't have this problem. What could be the cause of this? I'm using ensim pro for webhosting. TIA.

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• Help with grasping (INNER?) JOIN

  - by Greenie

  I'm having trouble building a query. I can do what I want in 3 different queries. SELECT id FROM table1 WHERE url LIKE '%/$downloadfile' put that in $url_id SELECT item_id FROM table2 WHERE rel_id = '$url_id'" put that in $item_id SELECT rel_id FROM table2 WHERE rel_id = '$item_id' AND field_id = '42'" put that in $user_id But from reading examples on joins and inner joins I think there's a more elegant way. I cant wrap my brain around writing a better query (but would like to) I can describe how it should go: table1 fields: id, url table2 fields item_id, rel_id, field_id I know the last part of table1.url (LIKE '%/$filename') with that I select table1.id. table1.id is equal to one entry in table2.rel_id. So get that and select the table2.item_id. In table2 there is another entry which has the same table2.item_id and it will have a table2.field_id = '42' And finally the value I need is the table2.rel_id where the table2.field_id was 42. I will fetch that value and put it in $user_id Can this be done with one query using joins/inner joins?

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• Data transfer speed to USB storage connected to wifi router very slow

  - by RonakG

  Here is my setup. A Linksys Cisco E3200 wifi router. A MacbookPro running OS X Lion 10.7.4. A Seagate GoFlex 1TB hard drive connected to wifi router via the USB port. When I try to transfer data from my MBP to the HDD, the data transfer rate is very low. I'm getting around 3MB/s write speed. This is very slow compared to the speed I get when HDD is directly connected to the MBP. The HDD is NTFS formatted. And the router provides access to HDD using Samba share. So I connect to the HDD using smb://. What is the limiting factor here affecting the data transfer rate?

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• How to select parent row only if has at least one child?

  - by Matt McCormick

  I have a simple one-to-many relationship. I would like to select rows from the parent only when they have at least one child. So, if there are no children, then the parent row is not returned in the result set. Eg. Parent: +--+---------+ |id| text | +--+---------+ | 1| Blah | | 2| Blah2 | | 3| Blah3 | +--+---------+ Children +--+------+-------+ |id|parent| other | +--+------+-------+ | 1| 1 | blah | | 2| 1 | blah2 | | 3| 2 | blah3 | +--+------+-------+ I want the results to be: +----+------+ |p.id|p.text| +----+------+ | 1 | Blah | | 2 | Blah2| +----+------+

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• Data model for timesheet to task and/or timesheet to project?

  - by John

  Let's say I want to make a simple project tracking system. A manager can create a project. Then he can create tasks for that project. Team members can record the hours they work for each task or for the project as a whole. Is the following design for the t_timesheet table a good idea? timesheet_id - primary key, autoincrement project_id - not null, foreign key constraint to t_project task_id - nullable, foreign key constraint to t_task user_id - not null, foreign key constraint to t_user hours - decimal Or should I do something like this: timesheet_id - primary key, autoincrement task_id - not null, foreign key constraint to t_task user_id - not null, foreign key constraint to t_user hours - decimal In the second option, I intend to always have a record in t_task labelled "miscellaneous items" with a foreign key to the relevant t_project record. Then I'll be able to track all hours for a project that aren't for any particular task. Are any of the ideas above good? What would be better?

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• PHP While Loops from Arrays

  - by Michael

  I have a table that contains members names and a field with multiple ID numbers. I want to create a query that returns results where any values in the ID fields overlap with any values in the array. For example: lastname: Smith firstname: John id: 101, 103 I have Array #1 with the values 101, 102, 103 I want the query to output all members who have the values 101 or 102 or 103 listed in their id field with multiple ids listed. Array ( [0] => 101 [1] => 102 [2] => 103 ) $sql="SELECT firstname, lastname, id FROM members WHERE id LIKE '%".$array_num_1."%'"; $result=mysql_query($sql); while ($rows=mysql_fetch_array($result)) { echo $rows['lastname'].', '.$rows['firstname'].'-'.$rows['id']; }

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• mysqli returns only one row instead of multiple rows

  - by Tristan

  Hello, i'm totally new to mysqli and i took a generated code and adapted it for my need. public function getServeurByName($string) { $stmt = mysqli_prepare($this->connection, "SELECT DISTINCT * FROM $this->tablename where GSP_nom=?"); $this->throwExceptionOnError(); mysqli_stmt_bind_param($stmt, 's', $string); $this->throwExceptionOnError(); mysqli_stmt_execute($stmt); $this->throwExceptionOnError(); mysqli_stmt_bind_result($stmt, $row->idServ, $row->timestamp, ........... ........... $row->email); if(mysqli_stmt_fetch($stmt)) { $row->timestamp = new DateTime($row->timestamp); return $row; } else { return null; } } the problem, this example i took the template on returns only one row instead of all the records. how to fix that please ?

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• How to get count of another table in a left join

  - by Sinan

  I have multiple tables post id Name 1 post-name1 2 post-name2 user id username 1 user1 2 user2 post_user post_id user_id 1 1 2 1 post_comments post_id comment_id 1 1 1 2 1 3 I am using a query like this: SELECT post.id, post.title, user.id AS uid, username FROM `post` LEFT JOIN post_user ON post.id = post_user.post_id LEFT JOIN user ON user.id = post_user.user_id ORDER BY post_date DESC It works as intended. However I would like the get the number of comments for each post too. So how can i modify the this query so I can get the count of comments. Any ideas?

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• mysqli real_escape_string problem

  - by tridat

  When im inserting to the database on my dev server the text goes in fine, for example "that's" is "that's" in the db. when uploading the exact same code to production server (hosted on a reseller account at bluehost) "that's" becomes "that\'s", im not double escaping, its exactly the same code, what could be the issue here?

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• MySQL error problem

  - by comma

  I keep getting the error listed below but it only says line 1 what does this mean and how do I fix it? Here is the error I keep getting? You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1 here is the code. if (isset($_POST['info_submitted'])) { $user_id = '5'; $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT learned_skills.*, users_skills.* FROM learned_skills INNER JOIN users_skills ON learned_skills.id = users_skills.skill_id WHERE user_id='$user_id'"); $skill = $_POST['skill']; $experience = $_POST['experience']; $year = $_POST['year']; if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $query1 = mysqli_query($mysqli,"INSERT INTO learned_skills (skill, experience, year) VALUES ('" . $skill . "', '" . $experience . "', '" . $year . "')"); } if (!mysqli_query($mysqli, $query1)) { print mysqli_error($mysqli); return; } $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT id FROM learned_skills WHERE id='" . $skill . "' AND experience='" . $experience . "' AND year='" . $year . "'"); if (!$dbc) { print mysqli_error($mysqli); } else { while($row = mysqli_fetch_array($dbc)){ $id = $row["id"]; } } $query2 = "INSERT INTO users_skills (skill_id, user_id, date_created) VALUES ('$id', '$user_id', NOW())"; if (!mysqli_query($mysqli, $query2)) { print mysqli_error($mysqli); return; } if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE learned_skills JOIN users_skills ON (users_skills.skill_id = learned_skills.id) SET skill = '$skill', experience = '$experience', year = '$year'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; } if (!$dbc) { print mysqli_error($mysqli); return; } }

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• Invalid SQL Query

  - by svovaf

  I have the next query that in my opinion is a valid one, but I keep getting error telling me that there is a proble on "WHERE em.p4 = ue.p3" - Unknown column 'ue.p3' in 'where clause'. This is the query: SELECT DISTINCT ue.p3 FROM table1 AS ue INNER JOIN table2 AS e ON ue.p3 = e.p3 WHERE EXISTS( SELECT 1 FROM ( SELECT (COUNT(*) >= 1) AS MinMutual FROM table4 AS smm WHERE smm.p1 IN ( SELECT sem.p3 FROM table3 AS sem INNER JOIN table2 AS em ON sem.p3 = em.p3 WHERE em.p4 = ue.p3 AND sem.type = 'friends' AND em.p2 = 'normal' ) AND smm.p5 IN ( 15000,15151 ) ) AS Mutual WHERE Mutual.MinMutual = TRUE) LIMIT 11 If I execute the sub-query which is inside the EXISTS function, everything is O.K. PLEASE HELP!

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• SQL query to retrieve financial year data grouped by the year

  - by mlevit

  Hi, I have a database with lets assume two columns (service_date & invoice_amount). I would like to create an SQL query that would retrieve and group the data for each financial year (July to June). I have two years of data so that is two financial years (i.e. 2 results). I know I can do this manually by creating an SQL query to group by month then run the data through PHP to create the financial year data but I'd rather have an SQL query. All ideas welcome. Thanks

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• MySQL LEFT OUTER JOIN virtual table

  - by user1707323

  I am working on a pretty complicated query let me try to explain it to you. Here is the tables that I have in my MySQL database: students Table --- `students` --- student_id first_name last_name current_status status_change_date ------------ ------------ ----------- ---------------- -------------------- 1 John Doe Active NULL 2 Jane Doe Retread 2012-02-01 students_have_courses Table --- `students_have_courses` --- students_student_id courses_course_id s_date e_date int_date --------------------- ------------------- ---------- ---------- ----------- 1 1 2012-01-01 2012-01-04 2012-01-05 1 2 2012-01-05 NULL NULL 2 1 2012-01-10 2012-01-11 NULL students_have_optional_courses Table --- `students_have_optional_courses` --- students_student_id optional_courses_opcourse_id s_date e_date --------------------- ------------------------------ ---------- ---------- 1 1 2012-01-02 2012-01-03 1 1 2012-01-06 NULL 1 5 2012-01-07 NULL Here is my query so far SELECT `students_and_courses`.student_id, `students_and_courses`.first_name, `students_and_courses`.last_name, `students_and_courses`.courses_course_id, `students_and_courses`.s_date, `students_and_courses`.e_date, `students_and_courses`.int_date, `students_have_optional_courses`.optional_courses_opcourse_id, `students_have_optional_courses`.s_date, `students_have_optional_courses`.e_date FROM ( SELECT `c_s_a_s`.student_id, `c_s_a_s`.first_name, `c_s_a_s`.last_name, `c_s_a_s`.courses_course_id, `c_s_a_s`.s_date, `c_s_a_s`.e_date, `c_s_a_s`.int_date FROM ( SELECT `students`.student_id, `students`.first_name, `students`.last_name, `students_have_courses`.courses_course_id, `students_have_courses`.s_date, `students_have_courses`.e_date, `students_have_courses`.int_date FROM `students` LEFT OUTER JOIN `students_have_courses` ON ( `students_have_courses`.`students_student_id` = `students`.`student_id` AND (( `students_have_courses`.`s_date` >= `students`.`status_change_date` AND `students`.current_status = 'Retread' ) OR `students`.current_status = 'Active') ) WHERE `students`.current_status = 'Active' OR `students`.current_status = 'Retread' ) `c_s_a_s` ORDER BY `c_s_a_s`.`courses_course_id` DESC ) `students_and_courses` LEFT OUTER JOIN `students_have_optional_courses` ON ( `students_have_optional_courses`.students_student_id = `students_and_courses`.student_id AND `students_have_optional_courses`.s_date >= `students_and_courses`.s_date AND `students_have_optional_courses`.e_date IS NULL ) GROUP BY `students_and_courses`.student_id; What I want to be returned is the student_id, first_name, and last_name for all Active or Retread students and then LEFT JOIN the highest course_id, s_date, e_date, and int_date for the those students where the s_date is since the status_change_date if status is 'Retread'. Then LEFT JOIN the highest optional_courses_opcourse_id, s_date, and e_date from the students_have_optional_courses TABLE where the students_have_optional_courses.s_date is greater or equal to the students_have_courses.s_date and the students_have_optional_courses.e_date IS NULL Here is what is being returned: student_id first_name last_name courses_course_id s_date e_date int_date optional_courses_opcourse_id s_date_1 e_date_1 ------------ ------------ ----------- ------------------- ---------- ---------- ------------ ------------------------------ ---------- ---------- 1 John Doe 2 2012-01-05 NULL NULL 1 2012-01-06 NULL 2 Jane Doe NULL NULL NULL NULL NULL NULL NULL Here is what I want being returned: student_id first_name last_name courses_course_id s_date e_date int_date optional_courses_opcourse_id s_date_1 e_date_1 ------------ ------------ ----------- ------------------- ---------- ---------- ------------ ------------------------------ ---------- ---------- 1 John Doe 2 2012-01-05 NULL NULL 5 2012-01-07 NULL 2 Jane Doe NULL NULL NULL NULL NULL NULL NULL Everything is working except one thing, I cannot seem to get the highest students_have_optional_courses.optional_courses_opcourse_id no matter how I form the query Sorry, I just solved this myself after writing this all out I think it helped me think of the solution. Here is the solution query: SELECT `students_and_courses`.student_id, `students_and_courses`.first_name, `students_and_courses`.last_name, `students_and_courses`.courses_course_id, `students_and_courses`.s_date, `students_and_courses`.e_date, `students_and_courses`.int_date, `students_optional_courses`.optional_courses_opcourse_id, `students_optional_courses`.s_date, `students_optional_courses`.e_date FROM ( SELECT `c_s_a_s`.student_id, `c_s_a_s`.first_name, `c_s_a_s`.last_name, `c_s_a_s`.courses_course_id, `c_s_a_s`.s_date, `c_s_a_s`.e_date, `c_s_a_s`.int_date FROM ( SELECT `students`.student_id, `students`.first_name, `students`.last_name, `students_have_courses`.courses_course_id, `students_have_courses`.s_date, `students_have_courses`.e_date, `students_have_courses`.int_date FROM `students` LEFT OUTER JOIN `students_have_courses` ON ( `students_have_courses`.`students_student_id` = `students`.`student_id` AND (( `students_have_courses`.`s_date` >= `students`.`status_change_date` AND `students`.current_status = 'Retread' ) OR `students`.current_status = 'Active') ) WHERE `students`.current_status = 'Active' OR `students`.current_status = 'Retread' ) `c_s_a_s` ORDER BY `c_s_a_s`.`courses_course_id` DESC ) `students_and_courses` LEFT OUTER JOIN ( SELECT * FROM `students_have_optional_courses` ORDER BY `students_have_optional_courses`.optional_courses_opcourse_id DESC ) `students_optional_courses` ON ( `students_optional_courses`.students_student_id = `students_and_courses`.student_id AND `students_optional_courses`.s_date >= `students_and_courses`.s_date AND `students_optional_courses`.e_date IS NULL ) GROUP BY `students_and_courses`.student_id;

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• adding a div with data()

  - by Dizzy Bryan High

  Hi people am generating a list of flash swfs, the information comes from an ajax call which returns a json object which i loop through to create the rows of data using my makeAppRow function. makeAppRow = function(myData){ var myStr = '<div class="fileEntry">' myStr = myStr +'<div class="appDate">'+dateFormat(myData.date_swf, "dS mmmm, yyyy, h:MM TT")+'</div>' myStr = myStr +'<div class="appName">'+myData.name_swf+'</div>' myStr = myStr +'<div class="appOptions" data>' myStr = myStr +'<div class="gotoAppBtn" data-options="'+myData+'">Open App</div>' myStr = myStr +'</div>' myStr = myStr +'</div>' $('#appData').append(myStr); } I need the json data to be attached to the gotoAppBtn so that when its clicked i can read in the data from the attached json object and use it in my click function, as you can see ive been trying to embed the data using the html5 data but i cant get it to work. <div class="gotoAppBtn" data-options="'+myData+'">Open App</div> i have a function so that when the button is clicked it loads in an swf. $('.gotoAppBtn').live('click', function(){ //alert('button clicked') var myData = $(this).data("options") alert('../userfiles/'+myData.id_ugp+'/'+myData.id_swf+'/'+myData.launchfile_swf+'') console.log(myData); var flashvars = {}; var params = {}; params.menu = "false"; params.quality = "best"; params.scale = "noscale"; var attributes = {}; attributes.id = "flashAppDisplay"; attributes.name = "flashAppDisplay"; swfobject.embedSWF( '../userfiles/'+myData.id_ugp+'/'+myData.id_swf+'/'+myData.launchfile_swf+'', 'flashAppDisplay', myData.width_swf, myData.height_swf, myData.version_swf ,"../FAVideo/expressInstall.swf", flashvars, params, attributes) }); but the data does not seem to be there, any pointers on where i am going wrong, or a better way to achive this???

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• Killing Mysql processes staying in sleep command.

  - by Shino88

  Hey I am connecting a MYSQL database through hibernate and i seem to have processes that are not being killed after they are finished in the session. I have called flush and close on each session but when i check the server the last processes are still there with a sleep command. This is a new problem which i am having and was not the case yesterday. Is there any way i can ensure the killng of theses processes when i am done with a session. Below is an example of one of my classes. public JSONObject check() { //creates a new session needed to add elements to a database Session session = null; //holds the result of the check in the database JSONObject check = new JSONObject(); try{ //creates a new session needed to add elements to a database SessionFactory sessionFactory = new Configuration().configure().buildSessionFactory(); session = sessionFactory.openSession(); if (justusername){ //query created to select a username from user table String hquery = "Select username from User user Where username = ? "; //query created Query query = session.createQuery(hquery); //sets the username of the query the values JSONObject contents query.setString(0, username); // executes query and adds username string variable String user = (String) query.uniqueResult(); //checks to see if result is found (null if not found) if (user == null) { //adds false to Jobject if not found check.put("indatabase", "false"); } else { check.put("indatabase", "true"); } //adds check to Jobject to say just to check username check.put("justusername", true); } else { //query created to select a username and password from user table String hquery = "Select username from User user Where username = :user and password = :pass "; Query query = session.createQuery(hquery); query.setString("user", username); query.setString("pass", password); String user = (String) query.uniqueResult(); if(user ==null) { check.put("indatabase", false); } else { check.put("indatabase", true); } check.put("justusername", false); } }catch(Exception e){ System.out.println(e.getMessage()); //logg.log(Level.WARNING, " Exception", e.getMessage()); }finally{ // Actual contact insertion will happen at this step session.flush(); session.close(); } //returns Jobject return check; }

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• MySQL - How to convert data_length to actual size?

  - by ming yeow

  I am trying to optimize the database buffer size, but i am finding the SHOW TABLE STATUS rather cryptic. I know that the data length is "165719261184"- how do i convert that into actual megabytes?

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• [Ruby on Rails] Data Structure

  - by siulamvictor

  I am building a online form, with about 20 multiple choice checkboxes. I can get the nested data with this command. raise params.to_yaml I need to store these data and call them again later. I want to sort out which user chose which specific checkbox, i.e. who chose checkbox no.2? What's the best way to store these data in database?

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• php connecting to mysql server(localhost) very slow

  - by Ahmad

  actually its little complicated: summary: the connection to DB is very slow. the page rendering takes around 10 seconds but the last statement on the page is an echo and i can see its output while the page is loading in firefox (IE is same). in google chrome the output becomes visible only when the loading finishes. loading time is approximately the same across browsers. on debugging i found out that its the DB connectivity that is creating problem. the DB was on another machine. to debug further. i deployed the DB on my local machine .. so now the DB connection is at 127.0.0.1 but the connectivity still takes long time. this means that the issue is with APACHE/PHP and not with mysql. but then i deployed my code on another machine which connects to DB remotely.and everything seems fine. basically the application uses couple of mod_rewrite.. but i removed all the .htaccess files and the slow connectivity issue remains.. i installed another APACHE on my machine and used default settings. the connection was still very slow. i added following statements to measure the execution time $stime = microtime(); $stime = explode(" ",$stime); $stime = $stime[1] + $stime[0]; // my code -- it involves connection to DB $mtime = microtime(); $mtime = explode(" ",$mtime); $mtime = $mtime[1] + $mtime[0]; $totaltime = ($mtime - $stime); echo $totaltime; the output is 0.0631899833679 but firebug Net panel shows total loading time of 10-11 seconds. same is the case with google chrome i tried to turn off windows firewall.. connectivity is still slow and i just can't quite find the reason.. i've tried multiple DB servers.. multiple apaches.. nothing seems to be working.. any idea of what might be the problem?

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