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  • Python built-in id() not consistent:

    - by Dannellyz
    Hoping someone can explain the following discrepancy: >>> s1 = "Cyber security" >>> s2 = "Cyber security" >>> id(s1) == id(s1) True >>> id(s1) == id(s2) False >>> s1 = "cyber" >>> s2 = "cyber" >>> id(s1) == id(s2) True >>> s2 = "cyber " >>> s2 = "cyber " >>> id(s1) == id(s2) False Why does the space make the id() False, yet different variables with no spaces are True?

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  • Serialize the @property methods in a Python class.

    - by ashchristopher
    Is there a way to have any @property definitions passed through to a json serializer when serializing a Django model class? example: class FooBar(object.Model) name = models.CharField(...) @property def foo(self): return "My name is %s" %self.name Want to serialize to: [{ 'name' : 'Test User', 'foo' : 'My name is Test User', },]

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  • Python: How should I make instance variables available?

    - by swisstony
    Suppose I have: class myclass: def __init__(self): self.foo = "bar" where the value of foo needs to be available to users of myclass. Is it OK to just read the value of foo directly from an instance of myclass? Should I add a get_foo method to myclass or perhaps add a foo property? What's the best practice here?

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  • Python/Django: log to console under runserver, log to file under Apache

    - by Justin Grant
    How can I send trace messages to the console (like print) when I'm running my Django app under manage.py runserver, but have those messages sent to a log file when I'm running the app under Apache? I reviewed Django logging and although I was impressed with its flexibility and configurability for advanced uses, I'm still stumped with how to handle my simple use-case. My apologies for not being able to find the answer elsewhere-- this is a newbie question I know.

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  • what is a good way to do countif in python

    - by tolomea
    I want to count how many members of an iterable meet a given condition. I'd like to do it in a way that is clear and simple and preferably reasonably optimal. My current best ideas are: sum(meets_condition(x) for x in my_list) and len([x for x in my_list if meets_condition(x)]) The first one being iterator based is presumably faster for big lists. And it's the same form as you'd use for testing any and all. However it depends on the fact that int(True) == 1, which is somewhat ugly. The second one seems easier to read to me, but it is different from the any and all forms. Does anyone have any better suggestions? is there a library function somewhere that I am missing?

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  • Need help in writting re in python

    - by laspal
    Hi, My string is mystring = "<tr><td><span class='para'><b>Total Amount : </b>INR (Indian Rupees) 100.00</span></td></tr>" My problem here is I have to search and get the total amount test = re.search("(Indian Rupees)(\d{2})(?:\D|$)", mystring) but my test give me None. How can I get the values and values can be 10.00, 100.00, 1000.00 Thanks

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  • python convert 12 bit image encoded in a string to 8 bit png

    - by ks
    I have a string that is read from a usb apogee camera that is a 12-bit grayscale image with the 12-bits each occupying the lowest 12 bits of 16-bits words. I want to create a 8-bit png from this string by ignoring the lowest 4 bits. I can convert it to a 16-bit image where the highest 4 bits are always zero using PIL with import Image imageStr is the image string imageSize is the image size img=Image.fromstring("I", imageSize, imageStr, "raw", "I;16", 0,1) img.save("MyImage.png", "PNG") Anyway I can do something similar to create a 8-bit image without completely unpacking the string doing arithmetic and making a new string?

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  • Appending item to lists - python

    - by ariel
    I have a list lets say a=[[1,2],[3,4],[5,6]]. I want to add to each item in a the char 'a'. when I use a=[x.append('a') for x in a] it return [None,None,None]. But if I use a1=[x.append('a') for x in a] then it do someting odd. a and not a1 is [[1,2,a],[3,4,a],[5,6,a]]. I don't understand why the first return [None, None, None] nor why the second works on a.

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  • change values in a list - python

    - by ariel
    I have this code: a=[['a','b','c'],['a','f','c'],['a','c','d']] for x in a: for y in x: if 'a' in x: x.replace('a','*')` but the result is: a=[['a','b','c'],['a','f','c'],['a','c','d']] and bot a=[['b','c'],['f','c'],['c','d']] What should I do so the changes will last?

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  • How do you create a daemon in Python?

    - by DavidM
    Searching on Google reveals x2 code snippets. The first result is to this code recipe which has a lot of documentation and explanation, along with some useful discussion underneath. However, another code sample, whilst not containing so much documentation, includes sample code for passing commands such as start, stop and restart. It also creates a PID file which can be handy for checking if the daemon is already running etc. These samples both explain how to create the daemon. Are there any additional things that need to be considered? Is one sample better than the other, and why?

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  • Difference Between Two Lists with Many Duplicates in Python

    - by Paul
    I have several lists that contain many of the same items and many duplicate items. I want to check which items in one list are not in the other list. For example, I might have one list like this: l1 = ['a', 'b', 'c', 'b', 'c'] and one list like this: l2 = ['a', 'b', 'c', 'b'] Comparing these two lists I would want to return a third list like this: l3 = ['c'] I am currently using some terrible code that I made a while ago that I'm fairly certain doesn't even work properly shown below. def list_difference(l1,l2): for i in range(0, len(l1)): for j in range(0, len(l2)): if l1[i] == l1[j]: l1[i] = 'damn' l2[j] = 'damn' l3 = [] for item in l1: if item!='damn': l3.append(item) return l3 How can I better accomplish this task?

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  • Importing data from a text file using python

    - by Will
    I have a text file containing data in rows and columns (~17000 rows in total). Each column is a uniform number of characters long, with the 'unused' characters filled in by spaces. For example, the first column is 11 characters long, but the last four characters in that column are always spaces (so that it appears to be a nice column when viewed with a text editor). Sometimes it's more than four if the entry is less than 7 characters. The columns are not otherwise separated by commas, tabs, or spaces. They are also not all the same number of characters (the first two are 11, the next two are 8 and the last one is 5 - but again, some are spaces). What I want to do is import the entires (which are numbers) in the last two columns if the second column contains the string 'OW' somewhere in it. Any help would be greatly appreciated.

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  • Replace special characters in python

    - by Marcos Placona
    Hi, I have some text coming from the web as such: £6.49 Obviously I would like this to be displayed as: £6.49 I have tried the following so far: s = url['title'] s = s.encode('utf8') s = s.replace(u'Â','') And a few variants on this (after finding it on this very same forum) But still no luck as I keep getting: UnicodeDecodeError: 'ascii' codec can't decode byte 0xc3 in position 100: ordinal not in range(128) Could anyone help me getting this right? UPDATE: Adding the reppr examples and content type u'Star Trek XI &#xA3;3.99' u'Oscar Winners Best Pictures Box Set \xc2\xa36.49' Content-Type: text/html; charset=utf-8 Thanks in advance

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  • deleting unaccessed files using python

    - by damon
    My django app parses some files uploaded by the user.It is possible that the file uploaded by the user may remain in the server for a long time ,without it being parsed by the app.This can increase in size if a lot of users upload a lot of files. I need to delete those files not recently parsed by the app -say not accessed for last 24 hours.I tried like this import os import time dirname = MEDIA_ROOT+my_folder filenames = os.listdir(dirname) filenames = [os.path.join(dirname,filename) for filename in filenames] for filename in filenames: last_access = os.stat(filename).st_atime #secs since epoch rtime = time.asctime(time.localtime(last_access)) print filename+'----'+rtime This shows the last accessed times for each file..But I am not sure how I can test if the file access time was within the last 24 hours..Can somebody help me out?

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  • undo or reverse argsort(), python

    - by Vincent
    Given an array 'a' I would like to sort the array by columns "a.sort(axis=0)" do some stuff to the array and then undo the sort. By that I don't mean re sort but basically reversing how each element was moved. I assume argsort() is what I need but it is not clear to me how to sort an array with the results of argsort() or more importantly apply the reverse/inverse of argsort() Here is a little more detail I have an array a, shape(a) = rXc I need to sort each column aargsort = a.argsort(axis=0) # May use this later aSort = a.sort(axis=0) now average each row aSortRM = asort.mean(axis=1) now replace each col in a row with the row mean. is there a better way than this aWithMeans = ones_like(a) for ind in range(r) # r = number of rows aWithMeans[ind]* aSortRM[ind] Now I need to undo the sort I did in the first step. ????

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  • merging indexed array in Python

    - by leon
    Suppose that I have two numpy arrays of the form x = [[1,2] [2,4] [3,6] [4,NaN] [5,10]] y = [[0,-5] [1,0] [2,5] [5,20] [6,25]] is there an efficient way to merge them such that I have xmy = [[0, NaN, -5 ] [1, 2, 0 ] [2, 4, 5 ] [3, 6, NaN] [4, NaN, NaN] [5, 10, 20 ] [6, NaN, 25 ] I can implement a simple function using search to find the index but this is not elegant and potentially inefficient for a lot of arrays and large dimensions. Any pointer is appreciated.

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  • Python 3: list atributes within a class object

    - by MadSc13ntist
    is there a way that if the following class is created; I can grab a list of attributes that exist. (this class is just an bland example, it is not my task at hand) class new_class(): def __init__(self, number): self.multi = int(number) * 2 self.str = str(number) a = new_class(2) print(', '.join(a.SOMETHING)) * the attempt is that "multi, str" will print. the point here is that if a class object has attributes added at different parts of a script that I can grab a quick listing of the attributes which are defined.

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  • regex in python, can this be improved upon?

    - by tipu
    I have this piece of code that finds words that begin with @ or #, p = re.findall(r'@\w+|#\w+', str) Now what irks me about this is repeating \w+. I am sure there is a way to do something like p = re.findall(r'(@|#)\w+', str) That will produce the same result but it doesn't, it instead returns only # and @. How can that regex be changed so that I am not repeating the \w+? This code comes close, p = re.findall(r'((@|#)\w+)', str) But it returns [('@many', '@'), ('@this', '@'), ('#tweet', '#')] (notice the extra '@', '@', and '#'.

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