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  • python-wordmatching

    - by challarao
    Write two functions, called countSubStringMatch and countSubStringMatchRecursive that take two arguments, a key string and a target string. These functions iteratively and recursively count the number of instances of the key in the target string. You should complete definitions for def countSubStringMatch(target,key): and def countSubStringMatchRecursive (target, key): For the remaining problems, we are going to explore other substring matching ideas. These problems can be solved with either an iterative function or a recursive one. You are welcome to use either approach, though you may find iterative approaches more intuitive in these cases of matching linear structures.

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  • Python: Picking an element without replacement

    - by wpeters
    I would like to slice random letters from a string. Given s="howdy" I would like to pick elements from 's' without replacement but keep the index number. For example >>> random.sample(s,len(s)) ['w', 'h', 'o', 'd', 'y'] is close to what I want, but I would actually prefer something like [('w',2), ('h',0), ('o',1), ('d',3), ('y',4)] with letter-index pairs. This is important because the same letter appears in 's' more than once. ie) "letter" where 't' appears twice but I need to distinguish the first 't' from the 'second'. Ideally I actually only need to pick letters as I need them but scrambling and calculating all the letters in a list (as shown above) is ok.

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  • Python os.path.walk() method

    - by Aaron Moodie
    I'm currently using the walk method in a uni assignment. It's all working fine, but I was hoping that someone could explain something to me. in the example below, what is the a parameter used for on the myvisit method? >>> from os.path import walk >>> def myvisit(a, dir, files): ... print dir,": %d files"%len(files) >>> walk('/etc', myvisit, None) /etc : 193 files /etc/default : 12 files /etc/cron.d : 6 files /etc/rc.d : 6 files /etc/rc.d/rc0.d : 18 files /etc/rc.d/rc1.d : 27 files /etc/rc.d/rc2.d : 42 files /etc/rc.d/rc3.d : 17 files /etc/rc.d/rcS.d : 13 files

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  • Python 3: list atributes within a class object

    - by MadSc13ntist
    is there a way that if the following class is created; I can grab a list of attributes that exist. (this class is just an bland example, it is not my task at hand) class new_class(): def __init__(self, number): self.multi = int(number) * 2 self.str = str(number) a = new_class(2) print(', '.join(a.SOMETHING)) * the attempt is that "multi, str" will print. the point here is that if a class object has attributes added at different parts of a script that I can grab a quick listing of the attributes which are defined.

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  • Distributing a Python library (single file)

    - by Alfred
    Hello. For my project I would be using the argparse library. My question is, how do I distribute it with my project. I am asking this because of the technicalities and legalities involved. Do I just: Put the argparse.py file along with my project. That is, in the tar file for my project. Create a package for it for my distro? Tell the user to install it himself? Sorry for being such a noob, but I new to all this.

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  • Downloading files from an http server in python

    - by cellular
    Using urllib2, we can get the http response from a web server. If that server simply holds a list of files, we could parse through the files and download each individually. However, I'm not sure what the easiest, most pythonic way to parse through the files would be. When you get a whole http response of the generic file server list, through urllib2's urlopen() method, how can we neatly download each file?

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  • "Slice" out one element from a python dictionary

    - by BCS
    I have a dictionary: D = { "foo" : "bar", "baz" : "bip" } and I want to create new dictionary that has a copy of one of it's elements k. So if k = "baz": R = { "baz" : "bip" } what I'v got now is: R = { k : D[k] } But in my case k is a complex expression and I've got a whole stack of these. Caching k in a temporary looks about as ugly as the original option. What I'm looking for is a better (cleaner) way to do this.

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  • Python: Problems finding string in website source code

    - by j00niner
    I open a website with urlopen. I then put the website sourcecode into a variable like so source = website.read() When I just print the source it comes out formatted correctly, however when I try to iterate through each line each character is it's own line. for example when I just print it looks like this <HTML> title</html> When I do this for line in source: print line it looks like this < H T M L ... etc I need to find a string that starts with "var" and then print that entire line.

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  • Google App Engine: Difficulty with Users API (or maybe just a Python syntax problem)

    - by Rosarch
    I have a simple GAE app that includes a login/logout link. This app is running on the dev server at the moment. The base page handler gets the current user, and creates a login/logout url appropriately. It then puts this information into a _template_data dictionary, for convenience of subclasses. class BasePage(webapp.RequestHandler): _user = users.get_current_user() _login_logout_link = None if _user: _login_logout_link = users.create_logout_url('/') else: _login_logout_link = users.create_login_url('/') _template_data = {} _template_data['login_logout_link'] = _login_logout_link _template_data['user'] = _user def render(self, templateName, templateData): path = os.path.join(os.path.dirname(__file__), 'Static/Templates/%s.html' % templateName) self.response.out.write(template.render(path, templateData)) Here is one such subclass: class MainPage(BasePage): def get(self): self.render('start', self._template_data) The login/logout link is displayed fine, and going to the correct devserver login/logout page. However, it seems to have no effect - the server still seems to think the user is logged out. What am I doing wrong here?

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  • Selecting dictionary items by key efficiently in Python

    - by user248237
    suppose I have a dictionary whose keys are strings. How can I efficiently make a new dictionary from that which contains only the keys present in some list? for example: # a dictionary mapping strings to stuff mydict = {'quux': ..., 'bar': ..., 'foo': ...} # list of keys to be selected from mydict keys_to_select = ['foo', 'bar', ...] The way I came up with is: filtered_mydict = [mydict[k] for k in mydict.keys() \ if k in keys_to_select] but I think this is highly inefficient because: (1) it requires enumerating the keys with keys(), (2) it requires looking up k in keys_to_select each time. at least one of these can be avoided, I would think. any ideas? I can use scipy/numpy too if needed.

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  • Python finding n consecutive numbers in a list

    - by lost_in_code
    I want to know how to find if there is a certain amount of consecutive numbers in a row in my list e.g. For example if I am looking for two 1's then: list = [1, 1, 1, 4, 6] #original list list = ["true", "true", 1, 4, 6] #after my function has been through the list. If I am looking for three 1's then: list = [1, 1, 1, 4, 6] #original list list = ["true", "true", "true", 4, 6] #after my function has been through the list. I have tried: list = [1, 1, 2, 1] 1,1,1 in list #typed into shell, returns "(1, 1, True)" Any help would be greatly appreciated, I mainly would like to understand whats going on, and how to check if the next element in the list is the same as the first x amount.

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  • Python: Parsing a colon delimited file with various counts of fields

    - by Mark
    I'm trying to parse a a few files with the following format in 'clientname'.txt hostname:comp1 time: Fri Jan 28 20:00:02 GMT 2011 ip:xxx.xxx.xx.xx fs:good:45 memory:bad:78 swap:good:34 Mail:good Each section is delimited by a : but where lines 0,2,6 have 2 fields... lines 1,3-5 have 3 or more fields. (A big issue I've had trouble with is the time: line, since 20:00:02 is really a time and not 3 separate fields. I have several files like this that I need to parse. There are many more lines in some of these files with multiple fields. ... for i in clients: if os.path.isfile(rpt_path + i + rpt_ext): # if the rpt exists then do this rpt = rpt_path + i + rpt_ext l_count = 0 for line in open(rpt, "r"): s_line = line.rstrip() part = s_line.split(':') print part l_count = l_count + 1 else: # else break break First I'm checking if the file exists first, if it does then open the file and parse it (eventually) As of now I'm just printing the output (print part) to make sure it's parsing right. Honestly, the only trouble I'm having at this point is the time: field. How can I treat that line specifically different than all the others? The time field is ALWAYS the 2nd line in all of my report files.

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  • python and regular expression with unicode

    - by bsn
    I need to delete some unicode symbols from the string '?????? ??????? ???????????? ??????????' I know they exist here for sure. I try: re.sub('([\u064B-\u0652\u06D4\u0670\u0674\u06D5-\u06ED]+)', '', '?????? ??????? ???????????? ??????????') but it doesn't work. String stays the same. ant suggestion what i do wrong?

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  • Python Attributes and Inheritance

    - by user368186
    Say I have the folowing code: class Class1(object): def __init__(self): self.my_attr = 1 self.my_other_attr = 2 class Class2(Class1): def __init__(self): super(Class1,self).__init__() Why does Class2 not inherit the attributes of Class1?

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  • python array.array with strings as data type

    - by Gladius
    Is there an object that acts like array.array, yet can handle strings (or character arrays) as its data type? It should be able to convert the string array to binary and back again, preferably with null terminated strings, however fixed length strings would be acceptable. >>> my_array = stringarray(['foo', 'bar']) >>> my_array.tostring() 'foo\0bar\0' >>> re_read = stringarray('foo\0bar\0') >>> re_read[:] ['foo', 'bar'] I will be using it with arrays that contain a couple million strings.

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  • Creating a dictionary with list of lists in Python

    - by ghbhatt
    I have a huge file (with around 200k inputs). The inputs are in the form: A B C D B E F C A B D D I am reading this file and storing it in a list as follows: text = f.read().split('\n') This splits the file whenever it sees a new line. Hence text is like follows: [[A B C D] [B E F] [C A B D] [D]] I have to now store these values in a dictionary where the key values are the first element from each list. i.e the keys will be A, B, C, D. I am finding it difficult to enter the values as the remaining elements of the list. i.e the dictionary should look like: {A: B C D; B: E F; C: A B D; D: 0} I have done the following: inlinkDict = {} for doc in text: adoc= doc.split(' ') docid = adoc[0] inlinkDict[docid] = inlinkDict.get(docid,0) + {I do not understand what to put in here} Please help as to how should i add the values to my dictionary. It should be 0 if there are no elements in the list except for the one which will be the key value. Like in example for 0.

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  • bulls and cows game -- programming algorithm(python)

    - by IcyFlame
    This is a simulation of the game Cows and Bulls with three digit numbers I am trying to get the number of cows and bulls between two numbers. One of which is generated by the computer and the other is guessed by the user. I have parsed the two numbers I have so that now I have two lists with three elements each and each element is one of the digits in the number. So: 237 will give the list [2,3,7]. And I make sure that the relative indices are maintained.the general pattern is:(hundreds, tens, units). And these two lists are stored in the two lists: machine and person. ALGORITHM 1 So, I wrote the following code, The most intuitive algorithm: cows and bulls are initialized to 0 before the start of this loop. for x in person: if x in machine: if machine.index(x) == person.index(x): bulls += 1 print x,' in correct place' else: print x,' in wrong place' cows += 1 And I started testing this with different type of numbers guessed by the computer. Quite randomly, I decided on 277. And I guessed 447. Here, I got the first clue that this algorithm may not work. I got 1 cow and 0 bulls. Whereas I should have got 1 bull and 1 cow. This is a table of outputs with the first algorithm: Guess Output Expected Output 447 0 bull, 1 cow 1 bull, 1 cow 477 2 bulls, 0 cows 2 bulls, 0 cows 777 0 bulls, 3 cows 2 bulls, 0 cows So obviously this algorithm was not working when there are repeated digits in the number randomly selected by the computer. I tried to understand why these errors are taking place, But I could not. I have tried a lot but I just could not see any mistake in the algorithm(probably because I wrote it!) ALGORITHM 2 On thinking about this for a few days I tried this: cows and bulls are initialized to 0 before the start of this loop. for x in range(3): for y in range(3): if x == y and machine[x] == person[y]: bulls += 1 if not (x == y) and machine[x] == person[y]: cows += 1 I was more hopeful about this one. But when I tested this, this is what I got: Guess Output Expected Output 447 1 bull, 1 cow 1 bull, 1 cow 477 2 bulls, 2 cows 2 bulls, 0 cows 777 2 bulls, 4 cows 2 bulls, 0 cows The mistake I am making is quite clear here, I understood that the numbers were being counted again and again. i.e.: 277 versus 477 When you count for bulls then the 2 bulls come up and thats alright. But when you count for cows: the 7 in 277 at units place is matched with the 7 in 477 in tens place and thus a cow is generated. the 7 in 277 at tens place is matched with the 7 in 477 in units place and thus a cow is generated.' Here the matching is exactly right as I have written the code as per that. But this is not what I want. And I have no idea whatsoever on what to do after this. Furthermore... I would like to stress that both the algorithms work perfectly, if there are no repeated digits in the number selected by the computer. Please help me with this issue. P.S.: I have been thinking about this for over a week, But I could not post a question earlier as my account was blocked(from asking questions) because I asked a foolish question. And did not delete it even though I got 2 downvotes immediately after posting the question.

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  • Second largest number in list python

    - by Manu Lakaster
    So I have to find THE SECOND LARGEST NUMBER IN A LIST. I am doing it through simple loops.My approach is I am going to divide a list into two parts and then find the largest number into two parts and then compare two nuumbers. I will choose the smaller number from two of them. I can not use ready functions or different approaches. Basically, this is my code....But it does not run correctly....Help me please to fix it because I spent a lot of time on it :( Thanks....P.S. Can we use indices to "divide" a list ??? #!/usr/local/bin/python2.7 alist=[-45,0,3,10,90,5,-2,4,18,45,100,1,-266,706] largest=alist[0] h=len(alist)/2 m=len(alist)-h print(alist) for i in alist: if alist[h]>largest: largest=alist[h] i=i+1 print(largest)

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