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  • Why does this MySQL Query hang?

    - by zzapper
    SELECT * FROM tbl_order_head AS o INNER JOIN tbl_orders_log AS c ON o.PAYMENT_TRANSACTION_LOG_ID=c.TRANSACTION_ID WHERE o.VISUAL_ID = '77783'; tbl_order_head 67,000 (30 fields) records, tbl_orders_log 17000 (5 fields) records. I don't know if it would eventually return as I am running it on a live server and fear overloading. I am doing similar queries and much more complex queries successfully.

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  • two where conditions in a mysql query

    - by Kaartz
    I have a table like below |date|dom|guid|pid|errors|QA|comm| |2010-03-22|xxxx.com|jsd3j234j|ab|Yes|xxxxxx|bad| |2010-03-22|xxxx.com|jsd3j234j|ab|No|xxxxxx|| |2010-03-22|xxxx.com|jsd3j234j|if|Yes|xxxxxx|bad| |2010-03-22|xxxx.com|jsd3j234j|if|No|xxxxxx|| |2010-03-22|xxxx.com|jsd3j234j|he|Yes|xxxxxx|bad| |2010-03-22|xxxx.com|jsd3j234j|he|No|xxxxxx|| I want to retrieve the total count of "dom" referred to each "QA" and also I need the count of "errors" detected by the "QA" SELECT date, count(dom), QA FROM reports WHERE date="2010-03-22" GROUP BY QA |2010-03-22|2|ab| |2010-03-22|2|if| |2010-03-22|2|he| SELECT date, count(dom), count(errors), QA FROM reports WHERE errors="Yes" GROUP BY QA |2010-03-22|1|ab| |2010-03-22|1|if| |2010-03-22|1|he| I want to combine the above two queries, is it possible. If I use the below query, I am not getting the desired result. SELECT date, count(dom), QA, count(errors) FROM reports WHERE date="2010-03-22" AND errors="Yes" GROUP BY QA I want the below output |2010-03-22|2|ab|1| |2010-03-22|2|if|1| |2010-03-22|2|he|1| Please help me.

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  • How to build unlimited level of menu through PHP and mysql

    - by Starx
    Well, to build my menu my menu I use a db similar structure like this To assign another submenu for existing submenu I simply assign its parent's id as its value of parent field. parent 0 means top menu now there is not problem while creating submenu inside another submenu now this is way I fetch the submenu for the top menu <ul class="topmenu"> <? $list = $obj -> childmenu($parentid); //this list contains the array of submenu under $parendid foreach($list as $menu) { extract($menu); echo '<li><a href="#">'.$name.'</a></li>'; } ?> </ul> What I want to do is. I want to check if a new menu has other child menu and I want to keep on checking until it searches every child menu that is available and I want to display its child menu inside its particular list item like this Home ........

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  • ORDER BY column_name help (via link in HTML table view) (PHP MySQL

    - by Derek
    My output for my table in HTML has several columns such as userid, name, age, dob. The table heading is simply the title of the column name, I want this to be a link, and when clicked, the selected column is sorted in order, ASC, and then DESC (on next click). I thought this was pretty straight forward but I'm having some difficulty. So far, I have produced this, and no output is taken, apart from the URL works by displaying 'users.php?orderby=userid' <?php if(isset($_GET['orderby'])){ $orderby = $_GET['orderby']; $query_sv = "SELECT * FROM users BY ".mysql_real_escape_string($orderby)." ASC"; } //default query else{ $query_sv = "SELECT * FROM users BY user_id DESC"; } ?> <tr> <th><a href="<?php echo $_SERVER['php_SELF']."?orderby=userid";?>">User ID</a></th> Hoefully if I get this working, I can sort the users by D.O.B. next also using the same principles. Does anyone have any ideas?

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  • MySQL date query only returns one year, when multiple exist

    - by Bowman
    I'm a part-time designer/developer with a part-time photography business. I've got a database of photos with various bits of metadata attached. I want to query the database and return a list of the years that photos were taken, and the quantity of photos that were taken in that year. In short, I want a list that looks like this: 2010 (35 photos) 2009 (67 photos) 2008 (48 photos) Here's the query I'm using: SELECT YEAR(date) AS year, COUNT(filename) as quantity FROM photos WHERE visible='1' GROUP BY 'year' ORDER BY 'year' DESC Instead of churning out all the possible years (the database includes photos from 2010-2008), this is the sole result: 2010 (35 photos) I've tried a lot of different syntax but at this point I'm giving in and asking for help!

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  • MySQL Query exceptions

    - by Wayne
    In one page, it should show records that has the following selected month from the drop down menu and it is set in the ?month=March So the query will do this $sql = "SELECT * FROM schedule WHERE month = '" . Clean($_GET['month']) . "' AND finished='0' ORDER BY date ASC"; But it shows records that has a value of 2 in the finished column and I don't want the query to include this. I've tried $sql = "SELECT * FROM schedule WHERE month = '" . Clean($_GET['month']) . "' AND finished='0' OR finished = '1' OR finished = '3' ORDER BY date ASC"; But it shows records on different months when it shouldn't be. So basically I want the record to exclude the records that has the value of 2 in the record that will not be shown in the page.

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  • MySQL: Count occurrences of known (or enumerated) distinct values

    - by Eilidh
    After looking at how to count the occurrences of distinct values in a field, I am wondering how to count the occurrences of each distinct value if the distinct values are known (or enumerated). For example, if I have a simple table - TrafficLight Colour ------------ ------ 1 Red 2 Amber 3 Red 4 Red 5 Green 6 Green where one column (in this case Colour) has known (or enumerated) distinct values, how could I return the count for each colour as a separate value, rather than as an array, as in the linked example. To return an array with a count of each colour (using the same method as in the linked example), the query would be something like SELECT Colour COUNT(*) AS ColourCount FROM TrafficLights GROUP BY Colour, and return an array - Colour ColourCount ------ ----------- Red 3 Amber 1 Green 2 What I would like to do is to return the count for each Colour AS a separate total (e.g. RedCount). How can I do this?

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  • Mysql partition error?

    - by drake
    I have a kinda table like this: CREATE TABLE test ( id MEDIUMINT NOT NULL AUTO_INCREMENT, user VARCHAR(30), time VARCHAR(30), status VARCHAR(30), origin VARCHAR(30), PRIMARY KEY (id) ) ENGINE=MyISAM; PARTITION BY RANGE(id) ( PARTITION p0 VALUES LESS THAN (500000), PARTITION p1 VALUES LESS THAN (1000000), PARTITION p2 VALUES LESS THAN (1500000), PARTITION p3 VALUES LESS THAN (2000000), PARTITION p4 VALUES LESS THAN (2500000) ) I have Three questions: 1) I have here an #1064 error; 2) How can i set split test.user as alphabetic range in partition; 3) How can i check that the partition was successful;

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  • Mysql regexp performance question

    - by Tim
    Rumour has it that this; SELECT * FROM lineage_string where lineage like '%179%' and lineage regexp '(^|/)179(/|$)' Would be faster than this; SELECT * FROM lineage_string where lineage regexp '(^|/)179(/|$)' Can anyone confirm ? Or know a decent way to test the speed of such queries. Thanks

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  • Problem with auto increment primary key (MySQL).

    - by mathon12
    I have 2 tables each using other's primary key as a foreign key. The primary keys for both are set to auto_increment. The problem is, when I try to create and entry into one of the tables, I have no idea what the primary key of the entry is and can't figure out what to put in the other table as a foreign key. What should I do? Do I drop auto_increment altogether and cook up a unique identifier for each entry so I can use it to address the created entries? I'm using PHP, if that's relevant. Thanks.

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  • Levenshtein: MySQL + PHP

    - by user317005
    $word = strtolower($_GET['term']); $lev = 0; $q = mysql_uqery("SELECT `term` FROM `words`"); while($r = mysql_fetch_assoc($q)) { $r['term'] = strtolower($r['term']); $lev = levenshtein($word, $r['term']); if($lev >= 0 && $lev < 5) { $word = $r['term']; } } how can I move all that into just one query? don't want to have to query through all terms and do the filtering in php.

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  • Java/MySQL: Working with data in classes

    - by skiwi
    What is the best way to deal with accessing/modifying tables in a database? I have read about the Data Access Object approach, but none of the resources I have found so far indicate a clear implementation of it. So assume you have a database with a table called accounts that has columns id, name, password and email. How would you properly access it within Java? I mean most people know how to do SQL statements, but that is not really the point. I hope people here can be of help. Regards.

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  • MySQL get row closest to NOW()

    - by Christopher McCann
    I have a table with User data such as name, address etc and another table which has a paragraph of text about the user. The reason that they are separate is because we need to record all the old about data. So if the user changes their paragraph - the old one should still be stored. Each bit of about data has a primary key aboutMeID. What I want to do is have a join that pulls their name, address etc and the latest bit of aboutMe data from the other table. I am not sure though how I can order the join to only get the latest about me data. Can someone help?

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  • Splitting tables by field to optimize MySQL?

    - by AK
    Do splitting fields into multiple tables ever yield faster queries? Consider the following two scenarios: Table1 ----------- int PersonID text Value1 float Value2 or Table1 ----------- int PersonID text Value1 Table2 ----------- int PersonID float Value2 If Value1 and Value2 are always being displayed together, I imagine Table1 is always faster because the second schema would require two SELECT statements. But are there any situations where you would choose the second? If the number of records were expected to be really large?

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  • List hits per hour from a MySQL table

    - by Axel
    I am trying to work out the hits per hour from a database. Data basically is stored as follows (with other columns) : Table Name: Hits ============================ VisitorIP TIMESTAMP ---------------------------- 15.215.65.65 123456789 I want to display total hits per hour (within the last 6 hours ) including the hours that has no hits. Example of the output: // Assuming now : 21:00 21:00 - 0 hits 20:00 - 1 hits 19:00 - 4 hits 18:00 - 0 hits 17:00 - 2 hits 16:00 - 3 hits i would love to get the data as array, Please note that the stored date is in UNIX time stamp format. and there may be some hours without any hits! Thanks

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  • MySQL Count If using 4 tables or Perl

    - by user1726133
    Hi I have a relatively convoluted query that relies on 4 different tables, unfortunately I do not have control of this data, but I do have to query it. I ran this simpler query and it works using just table 1 and table 2 SELECT actor, receiver, count(IF(t2.group1 = "anxiety behavior", 1,0)) AS 'anxiety' FROM ethogram_edited_obs_behaviors t1 JOIN ethogram_behaviors t2 on t1.behavior = t2.behavior_code GROUP BY actor; Below are the 4 tables I need and the query I tried that didn't work Table 1 | Table 2 | Table 3 | Table 4 Actor | Behavior | Behavior | type of Behavior | subject | sex | subject |subject_code er frown | frown anxiety behavior | Eric M | Eric | er Here is the query that is failing SELECT actor, count(IF(t2.group1 = "anxiety behavior", 1,0) AND(t3.sex = "M", 1,0)) AS 'anxiety', FROM ethogram_edited_obs_behaviors t1 JOIN ethogram_behaviors t2 on t1.behavior = t2.behavior_code JOIN subject_code t3 on t1.actor = t3.behavior_code1 JOIN subjects t4 on t3.subject = t4.yerkes_code GROUP BY actor; Any help would be much appreciated!! Thanks :) P.S. if this is easier to do in Perl tips also much appreciated

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  • VB.Net MySql command parameter MD5

    - by lampej
    Is it possible to execute a command like this? select * from tbl where col1=md5(@param1) or will the parameter throw off the md5 function? I have been unsuccessful in getting the command to work so far. Please let me know if this needs any further explanation and thank you in advance!

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  • MySQL foreign key constraint disappearing

    - by Bramjam
    This is my table: /* oefenreeks leerplan */ CREATE TABLE leerplan_oefenreeks ( leerplan_oefenreeks_id INT PRIMARY KEY AUTO_INCREMENT NOT NULL, leerplan_id INT NOT NULL, oefenreeks_id INT NOT NULL, plaats INT NOT NULL ); /* fk */ ALTER TABLE leerplan_oefenreeks ADD CONSTRAINT fk_leerp_oefenr_leerplan FOREIGN KEY(leerplan_id) REFERENCES leerplan (leerplan_id) ON DELETE CASCADE; ALTER TABLE leerplan_oefenreeks ADD CONSTRAINT fk_leerp_oefenr_oefenreeks FOREIGN KEY(oefenreeks_id) REFERENCES oefenreeks (oefenreeks_id) ON DELETE CASCADE; /* when I execute the nexline, my fk_leerp_oefenr_leerplan constraint vanishes/disappears*/ ALTER TABLE leerplan_oefenreeks ADD CONSTRAINT un_leerp_oefenr UNIQUE(leerplan_id, oefenreeks_id); ALTER TABLE leerplan_oefenreeks ADD CONSTRAINT un_leerp_oefenr_plaats UNIQUE(leerplan_id, plaats); When I go and check only 3 constraints exist. fk_leerp_oefenr_leerplan disappears. I don't understand why this happens.

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  • Next and Previous MySQL row based on name

    - by NightMICU
    Hi everyone, I have a table with details on personnel. I would like to create a Next/Previous link based on the individual's last name. Since personnel were not added in alphabetical order, selecting the next or previous row based on its ID does not work. It is a hefty table - the pertinent fields are id, name_l, and name_f. I would like to order by name_l, the individuals' last name. How would I go about accomplishing this task? Thanks!

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  • PHP/mySQL - using result from 'CONCAT' and 'AS' in 'LIKE' clause

    - by Phil Jackson
    Hi I have the following code; if( ! empty( $post['search-bar'] ) ) { $search_data = preg_replace("#\s\s#is", '', preg_replace("#[^\w\d\s+]#is", '', $post['search-bar'] ) ); $data_array = explode( " ", $search_data ); $data_array = "'%" . implode( "%' OR '%", $data_array ) . "%'"; $query = "SELECT CONCAT( PROFILE_PROFFESION, FIRST_NAME, LAST_NAME, DISPLAY_NAME) AS 'STRING' FROM `" . ACCOUNT_TABLE . "` WHERE STRING LIKE ( " . $data_array . " ) AND BUSINESS_POST_CODE LIKE '" . substr(P_BUSINESS_POST_CODE, 0, 4) . "%'"; $q = mysql_query( $query, $CON ) or die( "_error_" . mysql_error() ); if( mysql_num_rows( $q ) != 0 ) { die(); } } Problem is I want to use the temp col 'STRING' in the where clause but is returning 'unknown coloumn STRING Can any one point me in the right direction, regards Phil

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  • MySQL parameter resource error

    - by Derek
    Here is my error: Warning: mysql_query() expects parameter 2 to be resource, null given... This refers to line 23 of my code which is: $result = mysql_query($sql, $connection) My entire query code looks like this: $query = "SELECT * from users WHERE userid='".intval( $_SESSION['SESS_USERID'] )."'"; $result = mysql_query($query, $connection) or die ("Couldn't perform query $query <br />".mysql_error()); $row = mysql_fetch_array($result); I don't have a clue what has happpened here. All I wanted to do was to have the value of the users 'fullname' displayed in the header section of my web page. So I am outputting this code immediately after to try and achieve this: echo 'Hello '; echo $row['fullname']; Before this change, I had it working perfectly, where the session variable of fullname was echoed $_SESSION['SESS_NAME']. However, because my user can update their information (including their name), I wanted the name displayed in the header to be updated accordingly, and not displaying the session value.

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  • Get column of a mysql entry

    - by Xelluloid
    Is there a possibility to get the name of the column a database entry belongs to? Perhaps I have three columns with column names col1, col2 and col3. Now I want to select for every column the column with the maximum entry, something like this. Select name_of_column(max(col1,col2,col3)). I know that I can ask for the name of the columns by its ordinal position in the information_schema.COLUMNS table but how do I get the ordinal position of a database entry within a table?

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  • MYSQL JOIN WHERE ISSUES - need some kind of if condition

    - by Breezer
    Hi Well this will be hard to explain but ill do my best The thing is i have 4 tables all with a specific column to relate to eachother. 1 table with users(agent_users) , 1 with working hours(agent_pers), 1 with sold items(agent_stat),1 with project(agent_pro) the user and the project table is irrelevant in the issue at hand but to give you a better understanding why certain tables is included in my query i decided to still mention them =) The thing is that I use 2 pages to insert data to the working hour and the sold items during that time tables, then i have a third page to summarize everything for current month, the query for that is as following: SELECT *, SUM(sv_p_kom),SUM(sv_p_gick),SUM(sv_p_lunch) FROM (( agent_users LEFT JOIN agent_pers ON agent_users.sv_aid = agent_pers.sv_p_uid) LEFT JOIN agent_stat ON agent_pers.sv_p_uid = agent_stat.sv_s_uid) LEFT JOIN agent_pro ON agent_pers.sv_p_pid=agent_pro.p_id WHERE MONTH(agent_pers.sv_p_datum) =7 GROUP BY sv_aname so the problem is now that i dont want sold items from previous months to get included in the data received, i know i could solve that by simple adding in the WHERE part MONTH(agent_stat.sv_s_datum) =7 but then if no items been sold that month no data at all will show up not the time or anything. Any aid on how i could solve this is greatly appreciated. if there's something that's not so clear dont hesitate to ask and ill try my best to answer. after all my english isn't the best out there :P regards breezer

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  • Mysql many to many problem (leaderborad/scoreboard)

    - by zoko2902
    Hi all! I'm working on a small project in regards of the upcoming World Cup. I'm building a roster/leaderboard/scoredboard based on groups with national teams. The idea is to have information on all upcoming matches within the group or in the knockout phase (scores, time of the match, match stats etc.). Currently I'm stuck with the DB in that I can't come up with a query that would return paired teams in a row. I have these 3 tables: CREATE TABLE IF NOT EXISTS `wc_team` ( `id` INT NOT NULL AUTO_INCREMENT , `name` VARCHAR(45) NULL , `description` VARCHAR(250) NULL , `flag` VARCHAR(45) NULL , `image` VARCHAR(45) NULL , `added` TIMESTAMP NULL DEFAULT CURRENT_TIMESTAMP , PRIMARY KEY (`id`) , CREATE TABLE IF NOT EXISTS `wc_match` ( `id` INT NOT NULL AUTO_INCREMENT , `score` VARCHAR(6) NULL , `date` DATE NULL , `time` VARCHAR(45) NULL , `added` TIMESTAMP NULL DEFAULT CURRENT_TIMESTAMP , PRIMARY KEY (`id`) , CREATE TABLE IF NOT EXISTS `wc_team_has_match` ( `wc_team_id` INT NOT NULL , `wc_match_id` INT NOT NULL , PRIMARY KEY (`wc_team_id`, `wc_match_id`) , I've simplified the tables so we don't go in the wrong direction. Now I've tried al kinds of joins and groupings I could think of, but I never seem to get. Example guery: SELECT t.wc_team_id,t.wc_match_id,c.id.c.name,d.id,d.name FROM wc_team_has_match AS t LEFT JOIN wc_match AS s ON t.wc_match_id = s.id LEFT JOIN wc_team AS c ON t.wc_team_id = c.id LEFT JOIN wc_team AS d ON t.wc_team_id = d.id Which returns: wc_team_id wc_match_id id name id name 16 5 16 Brazil 16 Brazil 18 5 18 Argentina 18 Argentina But what I really want is: wc_team_id wc_match_id id name id name 16 5 16 Brazil 18 Argentina Keep in mind that a group has more matches I want to see all those matches not only one. Any pointer or suggestion would be extremly appreciated since I'm stuck like a duck on this one :).

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