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  • How to apply GROUP_CONCAT in mysql Query

    - by Query Master
    How to apply GROUP_CONCAT in this Query if you guys have any idea or any alternate solution about this please share me. Helps are definitely appreciated also (see Query or result required) Query SELECT WEEK(cpd.added_date) AS week_no,COUNT(cpd.result) AS death_count FROM cron_players_data cpd WHERE cpd.player_id = 81 AND cpd.result = 2 AND cpd.status = 1 GROUP BY WEEK(cpd.added_date); Query output result screen Result Required 23,24,25 AS week_no 2,3,1 AS death_count

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  • Mysql Performance Question - Essentially about normalizing efficiency

    - by freqmode
    Hi there. Just a quick question about database performance. I'll outline my site purpose below as background. I'm creating a dictionary site that saves the words users define to a database. What I'm wondering is whether or not to create a words table for each user or to keep one massive words table. This site will be used for entire schools so the single words table would be massive! The database structure is as follows: A user table with: User_ID PRIMARY KEY Username First Last Password Email Country Research Standings SendInfo Donated JoinedOn LastLogin Logins Correct Attempts Admin Active And one word table with: User_ID PRIMARY KEY Word Vocab Spell Defined DefinedAttempted Spelled SpelledAttempted Sentenced SentencedAttempted So what I'm asking is , performance-wise, should I create a new table for each user when they join the site - each user could have hundreds or thousands of words over time? Or is it better to have one massive table with thousands and thousands of records and filter by User_ID. I don't think I'll perform many table joins. My gut feeling is to create a new table for each user, but I thought I'd ask for expert advice! Thanks in advance.

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  • Using a comma seperated data in MYSQL "IN" clause

    - by Sashi Kant
    I have a column in one of my table where I store multiple ids seperated by comma's. Is there a way in which I can use this column's value in the "IN" clause of a query. The column(city) has values like 6,7,8,16,21,2 I need to use as Select * from table where e_ID in (Select city from locations where e_Id=?) I am satisfied with Crozin's answer, but I am open to suggestions, views and options. Feel free to share your views.

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  • Validate a date range within MySQL query

    - by fishcracker
    (This question may seem easy or kind of noobish, by that I pardon my ignorance.) I used PDO query to use SELECT then fetch some values, it comes to a point that I need to fetch only some entries that within its start date and end date. My database +----------+-----------------+----------------------+--------------------+ | id (INT) | title (VARCHAR) | start_date (VARCHAR) | end_date (VARCHAR) | +----------+-----------------+----------------------+--------------------+ | 1 | buddy | 2012-11-26 | 2012-11-30 | | 2 | metro | 2012-12-05 | 2012-12-20 | | 3 | justin | 2012-11-28 | 2012-12-01 | +----------+-----------------+----------------------+--------------------+ My query is as follows: $query = "SELECT title, start_date, end_date FROM debts WHERE start_date >= CURDATE() AND end_date >= CURDATE()"; What I want to achieve is whenever the start_date is today or greater but not exceeding the end_date it will be valid. This will return the row for id 1, however if I change the start_date to 2012-11-25, it will fail due to the first condition on AND. I'm really confuse on this since I am new to this, is there any built-in function to handle this kind of situation?

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  • MySQL parameter resource error

    - by Derek
    Here is my error: Warning: mysql_query() expects parameter 2 to be resource, null given... This refers to line 23 of my code which is: $result = mysql_query($sql, $connection) My entire query code looks like this: $query = "SELECT * from users WHERE userid='".intval( $_SESSION['SESS_USERID'] )."'"; $result = mysql_query($query, $connection) or die ("Couldn't perform query $query <br />".mysql_error()); $row = mysql_fetch_array($result); I don't have a clue what has happpened here. All I wanted to do was to have the value of the users 'fullname' displayed in the header section of my web page. So I am outputting this code immediately after to try and achieve this: echo 'Hello '; echo $row['fullname']; Before this change, I had it working perfectly, where the session variable of fullname was echoed $_SESSION['SESS_NAME']. However, because my user can update their information (including their name), I wanted the name displayed in the header to be updated accordingly, and not displaying the session value.

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  • Mysql regexp performance question

    - by Tim
    Rumour has it that this; SELECT * FROM lineage_string where lineage like '%179%' and lineage regexp '(^|/)179(/|$)' Would be faster than this; SELECT * FROM lineage_string where lineage regexp '(^|/)179(/|$)' Can anyone confirm ? Or know a decent way to test the speed of such queries. Thanks

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  • MySQL foreign key constraints, cascade delete

    - by Cudos
    Hello. I want to use foreign keys to keep the integrity and avoid orphans (I already use innoDB). How do I make a SQL statment that DELETE ON CASCADE? Secondly, that using DELETE ON CASCADE. E.g. if I delete a category then it would delete products related to that category even though there are other categories related to those products. The pivot table "categories_products" creates a many-to-many relationship between the two other tables. categories - id (INT) - name (VARCHAR 255) products - id - name - price categories_products - categories_id - products_id

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  • Adding relative week number column to MySQl results

    - by Anthony
    I have a table with 3 columns: user, value, and date. The main query returns the values for a specific user based on a date range: SELECT date, value FROM values WHERE user = '$user' AND date BETWEEN $start AND $end What I would like is for the results to also have a column indicating the week number relative to the date range. So if the date range is 1/1/2010 - 1/20/2010, then any results from the first Sun - Sat of that range are week 1, the next Sun - Sat are week 2, etc. If the date range starts on a Saturday, then only results from that one day would be week 1. If the date range starts on Thursday but the first result is on the following Monday, it would be week 2, and there are no week 1 results. Is this something fairly simple to add to the query? The only ideas I can come up with would be based on the week number for the year or the week number based on the results themselves (where in that second example above, the first result always gets week 1).

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  • (mySQL) Unable to query 2 tables properly for data

    - by Devner
    I have 2 tables. One is 'page_links' and the other is 'rpp'. Table page_links is the superset of table rpp. The following is the schema of my tables: -- Table structure for table `page_links` -- CREATE TABLE IF NOT EXISTS `page_links` ( `page` varchar(255) NOT NULL, `page_link` varchar(100) NOT NULL, `heading_id` tinyint(3) unsigned NOT NULL, PRIMARY KEY (`page`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; -- -- Dumping data for table `page_links` -- INSERT INTO `page_links` (`page`, `page_link`, `heading_id`) VALUES ('a1.php', 'A1', 8), ('b1.php', 'B1', 8), ('c1.php', 'C1', 5), ('d1.php', 'D1', 5), ('e1.php', 'E1', 8), ('f1.php', 'F1', 8), ('g1.php', 'G1', 8), ('h1.php', 'H1', 1), ('i1.php', 'I1', 1), ('j1.php', 'J1', 8), ('k1.php', 'K1', 8), ('l1.php', 'L1', 8), ('m1.php', 'M1', 8), ('n1.php', 'N1', 8), ('o1.php', 'O1', 8), ('p1.php', 'P1', 4), ('q1.php', 'Q1', 5), ('r1.php', 'R1', 4); -- Table structure for table `rpp` -- CREATE TABLE IF NOT EXISTS `rpp` ( `role_id` tinyint(3) unsigned NOT NULL, `page` varchar(255) NOT NULL, `is_allowed` tinyint(1) NOT NULL, PRIMARY KEY (`role_id`,`page`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; -- -- Dumping data for table `rpp` -- INSERT INTO `rpp` (`role_id`, `page`, `is_allowed`) VALUES (3, 'a1.php', 1), (3, 'b1.php', 1), (3, 'c1.php', 1), (3, 'd1.php', 1), (3, 'e1.php', 1), (3, 'f1.php', 1), (3, 'h1.php', 1), (3, 'i1.php', 1), (3, 'l1.php', 1), (3, 'm1.php', 1), (3, 'n1.php', 1), (4, 'a1.php', 1), (4, 'b1.php', 1), (4, 'q1.php', 1), (5, 'r1.php', 1); WHAT I AM TRYING TO DO: I am trying to query both the above tables (in a single query) in such a way that all the pages from page_links are displayed along with the is_allowed value from rpp for a particular role. For example, I want to get the is_allowed value of all the pages from rpp for role_id = 3 and at the same time, list all the available pages from page_links. A clear example of my expected result would be: page is_allowed role_id ---------------------------------------- a1.php 1 3 b1.php 1 3 c1.php 1 3 d1.php 1 3 e1.php 1 3 f1.php 1 3 g1.php NULL NULL h1.php 1 3 i1.php 1 3 j1.php NULL NULL k1.php NULL NULL l1.php 1 3 m1.php 1 3 n1.php 1 3 o1.php NULL NULL p1.php NULL NULL q1.php NULL NULL r1.php NULL NULL One more example of my desired result could be achieved by doing a LEFT JOIN rpp ON page_links.page = rpp.page but we need to omit using role_id = 3 (or any value) to be able to get that. But I do want to specify the role_id as well and get the results. I need the query to be able to get this result. I would appreciate any replies that could help me with this. If you can suggest me any changes as well to the table(s) design to be able to achieve the desired result, that's good as well. Thanks in advance.

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  • Get column of a mysql entry

    - by Xelluloid
    Is there a possibility to get the name of the column a database entry belongs to? Perhaps I have three columns with column names col1, col2 and col3. Now I want to select for every column the column with the maximum entry, something like this. Select name_of_column(max(col1,col2,col3)). I know that I can ask for the name of the columns by its ordinal position in the information_schema.COLUMNS table but how do I get the ordinal position of a database entry within a table?

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  • List hits per hour from a MySQL table

    - by Axel
    I am trying to work out the hits per hour from a database. Data basically is stored as follows (with other columns) : Table Name: Hits ============================ VisitorIP TIMESTAMP ---------------------------- 15.215.65.65 123456789 I want to display total hits per hour (within the last 6 hours ) including the hours that has no hits. Example of the output: // Assuming now : 21:00 21:00 - 0 hits 20:00 - 1 hits 19:00 - 4 hits 18:00 - 0 hits 17:00 - 2 hits 16:00 - 3 hits i would love to get the data as array, Please note that the stored date is in UNIX time stamp format. and there may be some hours without any hits! Thanks

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  • How to query multiple tables with multiple selects MySQL

    - by brybam
    I'm trying to write a php function that gets all the basic food data(this part works fine in my code) Then grabs all the ingredients related to the ids of the selected items from the query before. Anyone have have any idea why my second array keeps coming back as false? I should be getting 1 array with the list of foods (this works) Then, the second one should be an array with all the ingredients for all the foods that were previously selected...then in my code im planning to work with the array and sort them with the proper foods based on the ids. function getFood($start, $limit) { $one = mysql_query("SELECT a.id, a.name, a.type, AVG(b.r) AS fra, COUNT(b.id) as tvotes FROM `foods` a LEFT JOIN `foods_ratings` b ON a.id = b.id GROUP BY a.id ORDER BY fra DESC, tvotes DESC LIMIT $start, $limit;"); $row = mysql_fetch_array($one); $qry = ""; foreach ($row as &$value) { $fid = $value['id']; $qry = $qry . "SELECT ing, amount FROM foods_ing WHERE fid='$fid';"; } $two = mysql_query($qry); return array ($one, $two); }

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  • Strange behavior of MySQL UPDATE query in PHP?

    - by Prashant
    When I am executing following query then its not updating views column by 1 instead sometimes its updating it by 2 or 3. Say currently views count is 24 then after executing this query it becomes 26 or sometimes its 27. $views = $views + 1; $_SQL = ''; $_SQL = 'UPDATE videos SET views = '.$views.' WHERE VideoId= "'.$videoid.'";'; @mysql_query($_SQL); I am not getting why this is happening, am I missing something or the query is executing 2 times automatically? Please help me to figure out the issue. Thanks

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  • MySQL join problem

    - by David
    Table1 has u_name, Table2 has u_name, u_type and u_admin Table1.u_name is unique. But neither of the 3 fields in Table2 is unique. For any value of Table1.u_name, there are 0 to many entries in Table2 that Table2.u_name equals to that value. For any value of Table1.u_name, there are 0 to 1 entries in Table2 that Table2.u_name equals to that value AND Table2.u_type='S' What I want: Use Table1.u_name to get Table1.*, Table2.u_admin where Table1.u_name=Tabl2.u_name and Table2.u_type='S'. If there is no such entry in Table2 we still need to get Table1.* Please help give me some hints. Thank you so much!

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  • Next and Previous MySQL row based on name

    - by NightMICU
    Hi everyone, I have a table with details on personnel. I would like to create a Next/Previous link based on the individual's last name. Since personnel were not added in alphabetical order, selecting the next or previous row based on its ID does not work. It is a hefty table - the pertinent fields are id, name_l, and name_f. I would like to order by name_l, the individuals' last name. How would I go about accomplishing this task? Thanks!

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  • MYSQL, Subquery Reference in Union

    - by christian
    Is there any way to reference a subquery in a union? I am trying to do something like the following, and would like to avoid a temporary table, but the subquery will be drawn from a much larger dataset so it makes sense to only do it once.. SELECT * FROM (SELECT * FROM ads WHERE state='FL' AND city='Maitland' AND page='home' ORDER BY RAND()) AS sq WHERE spot = 'full-banner' LIMIT 1 UNION SELECT * FROM sq WHERE spot = 'leaderboard' LIMIT 1 UNION SELECT * FROM sq WHERE spot = 'rectangle1' LIMIT 1 UNION SELECT * FROM sq WHERE spot = 'rectangle2' LIMIT 1 .... etc,, It's a shame that DISTINCT can't be specified for a single column of a result set.

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  • treat mysql longtext as integer in query

    - by InnateDev
    I have a set field in my db that is longtext. I have used prices in this field and cannot change the field type to integer. In my query however I need to sort by these fields and assume I should treat them as an integer. is there another way to query these results to sort by price as an integer and not longtext without having to change the field type? at the moment 3900000 is smaller than 4300 in my result set.

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  • PHP/Mysql issues

    - by queryne
    Php/my sql newbie question. I have a database I've imported into my local phpmyadmin. However it seems I can't access it from my a php application. The connection string seems right and when i try to authenticate user credentials to access database information, no problems. However authenticate everyone and knows when i put in fake credentials. Still it won't pull any other information from the database. For instance, once a users login they should see something like, "Hello username"... that kind of thing. At this point I see "Hello" without the username. Any ideas what i might be missing?

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  • mysql_close(): supplied argument is not a valid MySQL-Link resource

    - by Illes Peter
    Here's what I'm trying to do: I've got a db.php file that does all the db manipulation. It has 2 static methods, connect and deconnect. In my other file i simply use db::connect() and db::deconnect(). The mysql_close($con) in the deconnect method just doesn't know who $con is. Since I don't want to instantiate my class static is the only way to go. Declaring 'private $con' in class db doesn't seem to have an effect. Any ideas? class db { public static function connect() { $dbData = parse_ini_file($_SERVER['DOCUMENT_ROOT'].'/config.ini'); $con = mysql_connect($dbData['host'],$dbData['user'],$dbData['pass']); $db = mysql_select_db($dbData['db']); if ((!$con) || (!$db)) return 0; else return 1; } public static function deconnect() { mysql_close($con); } }

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  • insert a date in mysql database

    - by kawtousse
    I use a jquery datepicker then i read it in my servlet like that: String dateimput=request.getParameter("datepicker");//1 then parse it like that: System.out.println("datepicker:" +dateimput); DateFormat df = new SimpleDateFormat("MM/dd/yyyy"); java.util.Date dt = null; try { dt = df.parse(dateimput); System.out.println("date imput parssé1 est:" +dt); System.out.println("date imput parsée2 est:" +df.format(dt)); } catch (ParseException e) { e.printStackTrace(); } and insert query like that: String query = "Insert into dailytimesheet(trackingDate,activity,projectCode) values ("+df.format(dt)+", \""+activity+"\" ,\""+projet+"\")"; it pass successfully untill now but if i check the record inserted i found the date: 01/01/0001 00:00:00 l've tried to fix it but it still a mess for me.

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  • MySQL select two tables at the same time...

    - by Jerry
    Hi all I have two tables and want to make a query. I tried to get team AA and team BB's image base on table A. I used: SELECT tableA.team1, tableA.team2, tableB.team, tableB.image, FROM tableA LEFT JOIN tableB ON tableA.team1=tableB.team The result only display imageA on the column. Are there any ways to select imageA and image B without using the second query? I appreciate any helps! Thanks a lot! My table structure are: table A team1 team2 ------------ AA BB table B team image ------------- AA imagaA BB imageB

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  • Optimizing Mysql to avoid redundancy but still have fast access to calculable data

    - by diglettpotato
    An example for the sake of the question: I have a database which contains users, questions, and answers. Each user has a score which can be calculated using the data from the questions and answers tables. Therefore if I had a score field in the users table, it would be redundant. However, if I don't use a score field, then calculating the score every time would significantly slow down the website. My current solution is to put it in a score field, and then have a cron running every few hours which recalculates everybody's score, and updates the field. Is there a better way to handle this?

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