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  • how do i design a high pass filters in matlab without using the builtin function?

    - by noura
    hello everyone, i'm just not sure how to draw the frequency response (H) of the high pass filter? after drawing the frequency response i can get the b coefficient by taking the ifft of (H). so yeah, for a low pass filter, with a cutoff frequency of say pi/2 : the frequency response code will be H = exp(-1*j*w*4).*(((0 <= w) & (w<= pi/2)) | ((2*pi - pi/2 <= w) & (w<=2*pi)); sincr the response is "1" between 0 and pi/2 and between (2*pi - pi/2) and 2*pi. can you help me write H for a high pass filter? thanx in advance.

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  • Please recommend the one SQL book for a developer without a lot of SQL experience.

    - by Hamish Grubijan
    I have too many hobbies outside of my profession, so I am hoping to read just one good book, and get a tad better at SQL. My background: took one boring, theoretical class in databases, was exposed to SQL professionally (in addition to several other languages and technologies) for a year and a half. I've done about 5 years of C#/Java stuff professionally. By "professionally" I mean doing it full-time while someone paid me more than $25/hr for it - not necessarily that I created masterpieces along the way :) I want to become better at SQL (coding aspect; DBA is not of particular importance to me right now). I am looking for one book to give me a solid foundation in it. When I needed to learn some C from almost a scratch, I used (and loved) this book: http://www.amazon.com/Programming-Language-2nd-Brian-Kernighan/dp/0131103628 I am hoping to find one just like this for SQL. I am not doing web development now or in a near future, and I am looking for something that is hopefully not specific to any one sub-industry. Thanks in advance.

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  • Can I db.put models without db.getting them first?

    - by Liron
    I tried to do something like ss = Screenshot(key=db.Key.from_path('myapp_screenshot', 123), name='flowers') db.put([ss, ...]) It seems to work on my dev_appserver, but on live I get this traceback: 05-07 09:50PM 19.964 File "/base/data/home/apps/quixeydev3/12.341796548761906563/common/appenginepatch/appenginepatcher/patch.py", line 600, in put E 05-07 09:50PM 19.964 result = old_db_put(models, *args, **kwargs) E 05-07 09:50PM 19.964 File "/base/python_runtime/python_lib/versions/1/google/appengine/ext/db/init.py", line 1278, in put E 05-07 09:50PM 19.964 keys = datastore.Put(entities, rpc=rpc) E 05-07 09:50PM 19.964 File "/base/python_runtime/python_lib/versions/1/google/appengine/api/datastore.py", line 284, in Put E 05-07 09:50PM 19.965 raise _ToDatastoreError(err) E 05-07 09:50PM 19.965 InternalError: the new entity or index you tried to insert already exists I happen to know just the ID of an existing Screenshot entity I want to update; that's why I was manually constructing its key. Am I doing it wrong?

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  • Delete the last instance of a certain string from a text file without changing the other instances o

    - by fraXis
    Hello, I have a C# program where I am using a lot of RegEx.Replace to replace text in my text file. Here is my problem. In my text file, I have a code such as "M6T1". This code is listed in numerous places in the text file. However, I only want to delete it from the bottom (last instance) in the text file. There will always be a "M6T1" at the bottom of the text file, but it is not always the last line. It could be the 3rd line from the bottom, the 5th line from the bottom etc. I only want to get rid of the last instance of "M6T1" so RegEx.Replace won't work here. I don't want to interfer with the other "M6T1"'s in the other locations in the text file. Can someone please give me a solution to this problem? Thanks

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  • How can install sqlite-ruby on linux when sqlite3 is not in /usr/local ?

    - by Charles
    I am trying to install sqlite3 and sqlite-ruby (ruby 1.8.6) on a linux box where I do not have root. I downloaded the sqlite3 source, binaries, and shared library and placed them all in a directory called sqlite3 I then try to install sqlite-ruby using gem install sqlite-ruby --with-sqlite-dir=the_path_sqlite/sqlite3 but I keep getting the error... checking for main() in -lsqlite... no checking for sqlite.h... no * extconf.rb failed * Could not create Makefile due to some reason, probably lack of necessary libraries and/or headers. Check the mkmf.log file for more details. You may need configuration options. Provided configuration options: --with-opt-dir --without-opt-dir --with-opt-include --without-opt-include=${opt-dir}/include --with-opt-lib --without-opt-lib=${opt-dir}/lib --with-make-prog --without-make-prog --srcdir=. --curdir --ruby=/data/scratch/bettbra/common/packages/ruby-1.8.6/bin/ruby --with-sqlite-dir --with-sqlite-include --without-sqlite-include=${sqlite-dir}/include --with-sqlite-lib --without-sqlite-lib=${sqlite-dir}/lib --with-sqlitelib --without-sqlitelib

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  • assembling an object graph without an ORM -- in the service layer or data layer?

    - by Hans Gruber
    At my current gig, our persistence layer uses IBatis going against SQL Server stored procedures (puke). IMHO, this approach has many disadvantages over the use of a "true" ORM such NHibernate or EF, but the one I'm trying to address here revolves around all the boilerplate code needed to map data from a result set into an object graph. Say I have the following DTO object graph I want to return to my presentation layer: IEnumerable<CustomerDTO> |--> IEnumerable<AddressDTO> |--> LatestOrderDTO The way I've implemented this is to have a discrete method in my DAO class to return each IEnumerable<*DTO>, and then have my service class be responsible for orchestrating the calls to the DAO. It then returns the fully assembled object graph to the client: public class SomeService(){ public SomeService(IDao someDao){ this._someDao = someDao; } public IEnumerable<CustomerDTO> ListCustomersForHistory(int brokerId){ var customers = _someDao.ListCustomersForBroker(brokerId); foreach (customer in customers){ customer.Addresses = someDao.ListCustomersAddresses(brokerId); customer.LatestOrder = someDao.GetCustomerLatestOrder(brokerId); } } return customers; } My question is should this logic belong in the service layer or the should I make my DAO such that it instead returns the assembled object graph. If I was using NHibernate, I assume that this kind of relationship association between objects comes for "free"?

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  • Can I share code & resources between Android projects without using a library?

    - by Tom
    The standard advice for sharing code & resources between Android projects is to use a library. Personally I find this works poorly if (a) the shared code changes a lot, or (b) your computer isn't fast enough. I also don't want to get into deploying multiple APK's, which seems to be necessary when I use dependent projects (i.e. Java Build Path, Projects Tab). On the other hand, sharing a folder of source code by using the Eclipse linked source feature works great (Java Build Path, Source tab, Link Source button), but for these two issues: 1) I can't use the same technique to share resources. I can create the link to the resources parent folder but then things get wonky and the shared resources don't get compiled (I'm using ADT 21). 2) So then I settle for copying the shared resources into each project, but this doesn't work because either. The shared code can't import the copy of its resources because it doesn't know the package name of the project that uses it. The solution I've been using is to access the resources dynamically, but that has become cumbersome as the number of resources grows. So, I need a solution to either (1) or (2), or I'll have to go back to a library project. (Or maybe there is another option I haven't thought of?)

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  • How to read a file line using php in a javascript variable without the breakline character ?

    - by coolboycsaba
    I have a txt file on the server which contains 10 lines of text. The text file is rewritten sometimes, and I get new lines using "\r\n". My problem shows when I want to load the lines in javascript variables. I do it like this, but this work only for numbers or for the last line of the file, because its not using the breakline tag: var x = '<?php echo $file[0]; ?>'; Ive tried to alert(x) but it`s not working.... (working only if I read the last line) Any idead ?

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  • Submiting a Form without Refreshing the page with jQuery and Ajax Not updating MySQL database.

    - by HEEEEEEELP
    I'm a newbie to JQuery and have a problem, when I click submit button on the form everything says registration was successful but my MYSQL database was not updated everything worked fine until I tried to add the JQuery to the picture. Can someone help me fix this problem so my database is updated? Thanks Here is the JQuery code. $(function() { $(".save-button").click(function() { var address = $("#address").val(); var address_two = $("#address_two").val(); var city_town = $("#city_town").val(); var state_province = $("#state_province").val(); var zipcode = $("#zipcode").val(); var country = $("#country").val(); var email = $("#email").val(); var dataString = 'address='+ address + '&address_two=' + address_two + '&city_town=' + city_town + '&state_province=' + state_province + '&zipcode=' + zipcode + '&country=' + country + '$email=' + email; if(address=='' || address_two=='' || city_town=='' || state_province=='' || zipcode=='' || country=='' || email=='') { $('.success').fadeOut(200).hide(); $('.error').fadeOut(200).show(); } else { $.ajax({ type: "POST", url: "http://localhost/New%20Project/home/index.php", data: dataString, success: function(){ $('.success').fadeIn(200).show(); $('.error').fadeOut(200).hide(); } }); } return false; }); }); Here is the PHP code. if (isset($_POST['contact_info_submitted'])) { // Handle the form. // Query member data from the database and ready it for display $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.*, contact_info.* FROM users INNER JOIN contact_info ON contact_info.user_id = users.user_id WHERE users.user_id=3"); $user_id = mysqli_real_escape_string($mysqli, htmlentities('3')); $address = mysqli_real_escape_string($mysqli, htmlentities($_POST['address'])); $address_two = mysqli_real_escape_string($mysqli, htmlentities($_POST['address_two'])); $city_town = mysqli_real_escape_string($mysqli, htmlentities($_POST['city_town'])); $state_province = mysqli_real_escape_string($mysqli, htmlentities($_POST['state_province'])); $zipcode = mysqli_real_escape_string($mysqli, htmlentities($_POST['zipcode'])); $country = mysqli_real_escape_string($mysqli, htmlentities($_POST['country'])); $email = mysqli_real_escape_string($mysqli, strip_tags($_POST['email'])); //If the table is not found add it to the database if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO contact_info (user_id, address, address_two, city_town, state_province, zipcode, country, email) VALUES ('$user_id', '$address', '$address_two', '$city_town', '$state_province', '$zipcode', '$country', '$email')"); } //If the table is in the database update each field when needed if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE contact_info SET address = '$address', address_two = '$address_two', city_town = '$city_town', state_province = '$state_province', zipcode = '$zipcode', country = '$country', email = '$email' WHERE user_id = '$user_id'"); } if (!$dbc) { // There was an error...do something about it here... print mysqli_error($mysqli); return; } } Here is the XHTML code. <form method="post" action="index.php"> <fieldset> <ul> <li><label for="address">Address 1: </label><input type="text" name="address" id="address" size="25" class="input-size" value="<?php if (isset($_POST['address'])) { echo $_POST['address']; } else if(!empty($address)) { echo $address; } ?>" /></li> <li><label for="address_two">Address 2: </label><input type="text" name="address_two" id="address_two" size="25" class="input-size" value="<?php if (isset($_POST['address_two'])) { echo $_POST['address_two']; } else if(!empty($address_two)) { echo $address_two; } ?>" /></li> <li><label for="city_town">City/Town: </label><input type="text" name="city_town" id="city_town" size="25" class="input-size" value="<?php if (isset($_POST['city_town'])) { echo $_POST['city_town']; } else if(!empty($city_town)) { echo $city_town; } ?>" /></li> <li><label for="state_province">State/Province: </label> <?php echo '<select name="state_province" id="state_province">' . "\n"; foreach($state_options as $option) { if ($option == $state_province) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li> <li><label for="zipcode">Zip/Post Code: </label><input type="text" name="zipcode" id="zipcode" size="5" class="input-size" value="<?php if (isset($_POST['zipcode'])) { echo $_POST['zipcode']; } else if(!empty($zipcode)) { echo $zipcode; } ?>" /></li> <li><label for="country">Country: </label> <?php echo '<select name="country" id="country">' . "\n"; foreach($countries as $option) { if ($option == $country) { echo '<option value="' . $option . '" selected="selected">' . $option . '</option>' . "\n"; } else if($option == "-------------") { echo '<option value="' . $option . '" disabled="disabled">' . $option . '</option>'; } else { echo '<option value="'. $option . '">' . $option . '</option>'."\n"; } } echo '</select>'; ?> </li> <li><label for="email">Email Address: </label><input type="text" name="email" id="email" size="25" class="input-size" value="<?php if (isset($_POST['email'])) { echo $_POST['email']; } else if(!empty($email)) { echo $email; } ?>" /><br /><span>We don't spam or share your email with third parties. We respect your privacy.</span></li> <li><input type="submit" name="submit" value="Save Changes" class="save-button" /> <input type="hidden" name="contact_info_submitted" value="true" /> <input type="submit" name="submit" value="Preview Changes" class="preview-changes-button" /></li> </ul> </fieldset> </form>

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  • Can we only use the front-end of wordpress without any front-end ?

    - by Tristan
    Hello, i just asked a question few minutes ago which led me to this one : I want to know if there is any chance to use only the back-end of wordpress ? I mean, link my admin interface to post news link my visitor interface on my website to the wordpress news so the visitor can access the news So the visitor never find out that i'm using wordpress to generate the news and handle their comments and write my news ? Maybe it's possible but there is no point by doing so ? Thank you

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  • Sending test emails in development without spam or rejection issues.

    - by Micah Burnett
    I run my development environment in a VM and need to test the delivery and appearance of emails from my applications. The problem is when my SMTP server starts delivering a lot of mail to my corporate email account, the server is soon rejected as a source of spam. Of course, the major Internet email providers will also never accept email from such a server. I've delivered to a specified pickup directory and open in outlook express, but the problem is images always display as broken images.

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  • How can I return a Future object with Spring without writing concurrency logic?

    - by Johan
    How can I return a java.util.concurrent.Future object with a Receipt object and only use the @javax.ejb.Asynchronous annotation? And do I need any extra configuration to let Spring handle ejb annotations? I don't want to write any concurrency logic myself. Here's my attempt that doesn't work: @Asynchronous public Future<Receipt> execute(Job job) { Receipt receipt = timeConsumingWork(job); return receipt; }

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  • How can you implement a jQuery feature without having IE prompt users with an Active X warning?

    - by Bijan
    Essentially, I want to implement a jQuery feature on a site that I'm building, but I don't want Internet Explorer users to have to click "Allow Blocked Content". The feature works fine with Safari, Chrome, and Firefox. It's only IE that prompts the users with the Active X warning. I'm using the following jQuery cycle plugin: http://malsup.com/jquery/cycle/ I thought that I might simply have to live with the fact that users have to click on the Active X message when they use the site, but Zendesk (www.zendesk.com) is using the same implementation and that site doesn't prompt me with the warning. Any ideas as to what I'm doing wrong would be appreciated.

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  • How to make CSS/HTML prototyping faster for engineers without strong CSS skills?

    - by rdeshpande
    I've been developing Ruby on Rails applications for some time, and have often found help to develop generate the templates of HTML with accompanying CSS. However, I'd like to make an attempt at doing this myself. Initial experiments leave me feeling like my process is really slow. I'm writing all my Rails code in VIM, which, with accompanying aliases to run the test suite, is pretty fast for me. However, the back-and-forth between browser/VIM to see new changes seems cumbersome - I'm guessing finding an editor with an embedded browser that constantly sees new changes is ideal for this (any suggestions?) So far I've experimented with Blueprint, which at the onset seems like it will save me a ton of time. However, what other tools have helped you do the PSD-HTML/CSS conversion as fast as you can?

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  • PHP: How to overwrite values in one array with values from another without adding new keys to the ar

    - by Svish
    I have an array with default settings, and one array with user-specified settings. I want to merge these two arrays so that the default settings gets overwritten with the user-specified ones. I have tried to use array_merge, which does the overwriting like I want, but it also adds new settings if the user has specified settings that doesn't exist in the default ones. Is there a better function I can use for this than array_merge? Or is there a function I can use to filter the user-specified array so that it only contains keys that also exist in the default settings array? (PHP version 5.3.0) Example of what I want $default = array('a' => 1, 'b' => 2); $user = array('b' => 3, 'c' => 4); // Somehow merge $user into $default so we end up with this: Array ( [a] => 1 [b] => 3 )

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