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  • PHP: Fastest way possible to read contents of a file.

    - by SoLoGHoST
    Ok, I'm looking for the fastest possible way to read all of the contents of a file via php with a filepath on the server, also these files can be huge. So it's very important that it does a READ ONLY to it as fast as possible. Is reading it line by line faster than reading the entire contents? Though, I remember reading up on this some, that reading the entire contents can produce errors for huge files. Is this true?

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  • Formatting not retained in paste from Ditto (clipboard manager). Plain text pasted instead [Solved] Add supported types

    - by Jeff Kang
    I'm trying to use Ditto on the Ditto documentation. If I were to copy the table of contents, then paste it (without Ditto) to the word processor, I get http://i.imgur.com/V1GU3.png, and the formatting is maintained. As as a result of the copy operation, the table of contents also goes into the Saved Items List (= History List = Lists the Clips saved from the Clipboard) in Ditto’s Main Window: I open a blank document to paste from Ditto instead of the default clipboard, and press either Ctrl-`, the default Ditto window activation Global Hot Key, or click the tray icon. From this point, I can do 3 things to close the Ditto window, and place the item on the clipboard (the default clipboard?). Select the item, and press Enter Put the cursor on the item, and double-click Select the item, and press Ctrl-c 1) and 2) send a right-click where the cursor is, after the Ditto window closes (presumably to have the paste option ready to access?): Ctrl-c just closes the Ditto window. Whichever method is used, the contents are pasted in what I believe is plain text: http://i.imgur.com/mQAZH.png How do I keep the formatting that the default clipboard keeps? Thanks.

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  • Is there a way to efficiently yield every file in a directory containing millions of files?

    - by Josh Smeaton
    I'm aware of os.listdir, but as far as I can gather, that gets all the filenames in a directory into memory, and then returns the list. What I want, is a way to yield a filename, work on it, and then yield the next one, without reading them all into memory. Is there any way to do this? I worry about the case where filenames change, new files are added, and files are deleted using such a method. Some iterators prevent you from modifying the collection during iteration, essentially by taking a snapshot of the state of the collection at the beginning, and comparing that state on each move operation. If there is an iterator capable of yielding filenames from a path, does it raise an error if there are filesystem changes (add, remove, rename files within the iterated directory) which modify the collection? There could potentially be a few cases that could cause the iterator to fail, and it all depends on how the iterator maintains state. Using S.Lotts example: filea.txt fileb.txt filec.txt Iterator yields filea.txt. During processing, filea.txt is renamed to filey.txt and fileb.txt is renamed to filez.txt. When the iterator attempts to get the next file, if it were to use the filename filea.txt to find it's current position in order to find the next file and filea.txt is not there, what would happen? It may not be able to recover it's position in the collection. Similarly, if the iterator were to fetch fileb.txt when yielding filea.txt, it could look up the position of fileb.txt, fail, and produce an error. If the iterator instead was able to somehow maintain an index dir.get_file(0), then maintaining positional state would not be affected, but some files could be missed, as their indexes could be moved to an index 'behind' the iterator. This is all theoretical of course, since there appears to be no built-in (python) way of iterating over the files in a directory. There are some great answers below, however, that solve the problem by using queues and notifications. Edit: The OS of concern is Redhat. My use case is this: Process A is continuously writing files to a storage location. Process B (the one I'm writing), will be iterating over these files, doing some processing based on the filename, and moving the files to another location. Edit: Definition of valid: Adjective 1. Well grounded or justifiable, pertinent. (Sorry S.Lott, I couldn't resist). I've edited the paragraph in question above.

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  • Need to have JProgress bar to measure progress when copying directories and files

    - by user1815823
    I have the below code to copy directories and files but not sure where to measure the progress. Can someone help as to where can I measure how much has been copied and show it in the JProgress bar public static void copy(File src, File dest) throws IOException{ if(src.isDirectory()){ if(!dest.exists()){ //checking whether destination directory exisits dest.mkdir(); System.out.println("Directory copied from " + src + " to " + dest); } String files[] = src.list(); for (String file : files) { File srcFile = new File(src, file); File destFile = new File(dest, file); copyFolder(srcFile,destFile); } }else{ InputStream in = new FileInputStream(src); OutputStream out = new FileOutputStream(dest); byte[] buffer = new byte[1024]; int length; while ((length = in.read(buffer)) > 0){ out.write(buffer, 0, length); } in.close(); out.close(); System.out.println("File copied from " + src + " to " + dest); }

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  • Referencing java resource files for cold fusion

    - by Chimeara
    I am using a .Jar file containing a .properties file in my CF code, however it seems unable to find the .properties file when run from CF. My java code is: String key =""; String value =""; try { File file = new File("src/test.properties"); FileInputStream fileInput = new FileInputStream(file); Properties properties = new Properties(); properties.load(fileInput); fileInput.close(); Enumeration enuKeys = properties.keys(); while (enuKeys.hasMoreElements()) { key = (String) enuKeys.nextElement(); value = properties.getProperty(key); //System.out.println(key + ": " + value); } } catch (FileNotFoundException e) { e.printStackTrace(); key ="error"; } catch (IOException e) { e.printStackTrace(); key ="error"; } return(key + ": " + value); I have my test.properties file in the project src folder, and make sure it is selected when compiling, when run from eclipse it gives the expected key and value, however when run from CF I get the caught errors. My CF code is simply: propTest = CreateObject("java","package.class"); testResults = propTest.main2(); Is there a special way to reference the .properties file so CF can access it, or do I need to include the file outside the .jar somewhere?

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  • Can I use php's fwrite with 644 file permissions?

    - by filip
    I am trying to set up automated .htaccess updating. This clearly needs to be as secure as possible, however right now the best I can do file permission-wise is 666. What can I do to setup either my server or php code so that my script's fwrite() command will work with 644 or better? For instance is there a way to set my script(s) to run as owner?

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  • Beginner servlet question: accessing files in a .war, which path?

    - by Navigateur
    When a third-party library I'm using tries to access a file, I'm getting "Error opening ... file ... (No such file or directory)" even though I KNOW the file is in the WAR. I've tried both packaged (.war) and "exploded" (directory) deployment, and the file is definitely there. I've tried setting full permissions on it too. It's on Unix (Ubuntu). File is war/dict/index.sense and the error is "dict/index.sense (No such file or directory)". It works fine on my Windows computer when running in hosted mode as a GWT app from Eclipse, just not when I transfer it to the Unix machine for deployment. My question is: has anybody experienced this before and/or are there differences in relative path that I should consider i.e. what's the root path for relative file access in a war?

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  • Open default browser as standard user (C++)

    - by Disco
    I'm currently using ShellExecute "open" to open a URL in the user's browser, but running into a bit of trouble in Win7 and Vista because the program runs elevated as a service. When ShellExecute opens the browser, it seems to read the "Local Admin" profile instead of the user's. So for example, if the user at the keyboard has Firefox as his default browser, it may open IE (which is the admin's default). I know that the "runas" verb can be used to elevate, but how do you do it the other way around? Is there a way to open a URL in the default browser on a standard user's desktop from a service?

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  • [Python] How to create a named temporary file in memory?

    - by conradlee
    I would like to use Python's tempfile module to create a temporary file that I will use for communication between processes (use of pipes is awkward). The documentation I've linked to above shows two functions that almost do what I want: tempfile.NamedTemporaryFile # For creating named tempfiles tempfile.SpooledTemporaryFile # For creating tempfiles in memory but actually I want a tempfile that is both named AND in memory. Any ideas?

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  • open text file in android emulator

    - by Karthick
    How to open a text file in android.I am using android 1.5 emulator and eclipse ide.I try to push files to the device emulator.In Eclipse ide android file explorer has the text file and image files in the sdcard.In the Emulator Image files are in the Gallery.How can i see the text file in the android emulator.

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  • Lightbox getting open multiple time on enter.

    - by Salil
    Hi All, I am going through a weird problem while using lightbox . Where ever the new light box is used user is able to open the same light box on same page number of time. For e.g Using tab button go to `Lightbox link`. Press enter --> Light box will open. Press enter --> second light box open below the previous one. and so on....... The problem is occurred when I use tab and entered on the link my focus is not getting changed from the link and so user is able to open multiple lightbox on clicking enter. I try following but it not works for me <a href = '/calenders/add_shipment' onclick ="this.blur()" class='lbOn'> <img src='/images/box-plus.png' style='border:none;'> </a> what should be my approached to get out of this.

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  • C++ Multi Monitor - Find All Visible/Open Windows

    - by Paul
    I'm trying to find all the windows of ANY kind that are open (and have a taskbar 'button'). I have no problems finding the list processes/hWnd's, and then cycling through those, but how do I determine if a process/hwnd has a window open? (even if minimized). I've tried doing different combinations of the window parameters (such as WS_POPUP etc) but none of the parameters (or combinations of parameters) that I could find would give me all the open windows without some sort of false positives. As an example of a false positive was the fact that it gives me two 'windows' for google talk (even though one was open). Another false positive is considering the start menu as an open window. Any ideas? Solutions? I've been working on this for a while and its been driving me a bit insane. Note: I'm doing this for windows 7 (at this point). I'm not sure if there's any difference between how you would do this between XP and 7, but I thought it might be relevant.

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  • Why can't I reserve 1,000,000,000 in my vector ?

    - by vipersnake005
    When I type in the foll. code, I get the output as 1073741823. #include <iostream> #include <vector> using namespace std; int main() { vector <int> v; cout<<v.max_size(); return 0; } However when I try to resize the vector to 1,000,000,000, by v.resize(1000000000); the program stops executing. How can I enable the program to allocate the required memory, when it seems that it should be able to? I am using MinGW in Windows 7. I have 2 GB RAM. Should it not be possible? In case it is not possible, can't I declare it as an array of integers and get away? BUt even that doesn't work. Another thing is that, suppose I would use a file(which can easily handle so much data ). How can I let it read and write and the same time. Using fstream file("file.txt', ios::out | ios::in ); doesn't create a file, in the first place. But supposing the file exists, I am unable to use to do reading and writing simultaneously. WHat I mean is this : Let the contents of the file be 111111 Then if I run : - #include <fstream> #include <iostream> using namespace std; int main() { fstream file("file.txt",ios:in|ios::out); char x; while( file>>x) { file<<'0'; } return 0; } Shouldn't the file's contents now be 101010 ? Read one character and then overwrite the next one with 0 ? Or incase the entire contents were read at once into some buffer, should there not be atleast one 0 in the file ? 1111110 ? But the contents remain unaltered. Please explain. Thank you.

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