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  • Nginx works on my linux machine but is not accessible from other computers in my local network

    - by crooveck
    In my LAN network I have a server with Scientific Linux (RedHat or Fedora based distro), I've done yum install nginx but the welcome page is not accessible from other computers in my network. When I do telnet open localhost 80 and then GET / HTTP/1.0 I get some html code from nginx, so it's running for sure. But when I want to connect remotly, doing telnet open 192.168.3.130 80 I get: Trying 192.168.3.130... telnet: Unable to connect to remote host: No route to host So I assume that there is something wrong with my network settings, maybe iptables or something else? Next step, I turned off iptables: service iptables stop and it helped, now I can connect remotely using telnet. So I think, I need to fix my iptables rules. I did some googling and found this rule -A INPUT -m state --state NEW -m tcp -p tcp --dport 80 -j ACCEPT but it still didn't allow me to connect remotely when iptables is up. Can someone please help me setting a proper iptables configuration?

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  • Total network data sent/received of a non-daemon Linux process?

    - by leden
    I'm looking for a simple and effective way of measuring total bytes received/sent from a single process upon its termination. Basically, I am looking for a tool which has the interface similar to "time" and "/usr/bin/time", e.g. measure-net-data <prog_to_run> <prog_args> Received (b): XYZ Sent (b): ABC I know that there are many tools for bandwidth/network monitoring, but as far I can tell all of them are performing the measurements it real-time, which is inappropriate not only because of overhead but also because of the inconvenience - I would need to stop the program, capture the output of the tool and then kill it. I have seen that newer versions of Linux 2.6.20+ provide /proc/<pid>/io/ which contain the information I'm looking for; however, everything under /proc/<pid> when the process terminates, so I'm again back to the same problem as with any network monitoring tool.

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  • Program to Queue Files for Copy/Move/Delete in linux?

    - by laliga
    I've search the net for Linux's answer to something like Teracopy (Windows)... but could not find anything suitable. The closest things i got are: Krusader. Mentioned in their features but indicated as 'not implemented yet'. MiniCopier. A java based app http://a.courreges.free.fr/projets/minicopier/minicopier-en.php rsync is not an option. Can someone recommend me a simple file copy tool that can queue files for copy/move/delete? Preferably if I can drag and drop from Nautilus. If something like this does not exist, can someone please tell me why? ...am I the only person that needs something like this?

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  • How to save your Linux state (suspend to disk) periodically to recover from crashes?

    - by WoLpH
    One in a while my laptop crashes/dies because of a bad/empty battery, crappy wifi driver or whatever other reason. For a while I've wondered if it's possible to force Linux to periodically save the state (like vmware snapshots) to disk so you can restore from that with possibly slightly outdated work but at least with all of your apps open in the same state you've left them. I don't really see the point in having to boot everything from cratch constantly, although KDE saves your state on logout, that doesn't happen periodically (by default) either. It would make it much nicer to recover from your crashes if your ram was written to disk periodically. Anyone know if there's a system call to do this without also shutting down the machine? Even a manual button to save the entire state would be nice.

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  • A "quick" vector editor (SVG) for Linux (for annotating images?)

    - by sdaau
    I often need to take a bitmap (.png) image, and draw some lines or text on top of it, and possibly export a new, thusly "annotated" image. I know I can basically do all this in inkscape - but inkscape is a complex program, and it needs almost a minute to start up properly on my PCs. So I was thinking - is there something like a "mini" vector editor for Linux, which would start up fast, and allow me to: Right-click, open an image in this editor program The program scales the active "document"/"window size" to the size of the image I can zoom in/zoom out (and possibly crop) the image I can add at least lines, boxes and text in different colors? A bonus for me would be to have the overlay graphics saved as SVG format, say with the same filename as the image - as in, "image.png.svg" being saved in the same directory where the original "image.png" is located (thus allowing opening and editing these "annotations" further, either in this editor, or possibly in inkscape). And another bonus would be the export of the annotated image to a bitmap. Anyone know about anything like this?

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  • Cisco IOS policy route for router originated VPN traffic

    - by Paul
    We have a Cisco IOS router with two DSL connections. One of them is intended for general traffic (ADSL), the other for VPN links (BDSL) and various other traffic. So the default route is the ADSL link, and we have a combination of static routes for the VPN traffic, and policy routes for other traffic types that should go out the BDSL link. For site to site traffic, this is fine, we just static route the public IPs and remote networks out of the BDSL line. The policy based routing works fine for any internal traffic that matches an ACL. The problem is now that there are remote VPN sites originating from dynamic addresses, so we cannot use static routes. The replies to incoming ISAKMP requests are following the default route out of the ADSL (despite there being no crypto map on that interface). I want to route the outgoing VPN traffic out of the BDSL. I have tried adding udp/500 and esp to and from the route-map acl that pushes traffic out of the BDSL line, but it doesn't match, presumably because the route-map happen earlier than the IPSec stuff. Any ideas how I can do this? IOS ver: 12.4.13T.

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  • Too many argumants for function

    - by Stas Kurilin
    I'm starting learning Lisp with Java background. In SICP's exercise there is many tasks where students should create abstract functions with many parameters, like (define (filtered-accumulate combiner null-value term a next b filter)...) in exercise 3.11. In Java (language with safe, static typing discipline) - method with more than 4 arguments usually smells, but in Lisp/Scheme it doesnt, does it? I'm wandering how many arguments do you use in you functions? If you use it in production, do you make such many layers?

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  • How to evaluate text strings provided by sed/grep/whatever?

    - by T.J.
    This is for UNIX shell programming. It have to be supported by multiple UNIX platforms including Solaris, Linux, and AIX. I have this scenario -- I am to read from a text file a string that may or may not contain an environment variable that may or may not be defined. For example: <foo.bar> This error code was found: $(error_code) I have the following code: statement=$(sed -n $1'p' $messagefile) echo $echo_flag $statement $1 = line number supplied to this particular function/script. $messagefile = filename of log file. $echo_flag = "-e" in Linux, otherwise, empty. $(error_code) = 42. Instead of getting this when running: <foo.bar> This error code was found: 42 I still get this: <foo.bar> This error code was found: $(error_code) How exactly do I tell the shell script that the value of statement should be evaluated further beyond what sed have done?

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  • Playing a .TS file on iOS

    - by Jonathan Grynspan
    We're working with some hardware that produces files in the .TS format, and we'd like to play them on an iOS device. (The files are internally consistent with what iOS supports--MPEG-4 video, AAC audio.) We've been investigating three options so far: Roll our own integrated HTTP Live Streaming server and serve up a faux M3U8 playlist from within the app. This... doesn't seem to want to play nice, and we've had mixed luck actually getting the .TS files to play on devices. Unwrap the MPEG-4 and AAC data from the TS file and re-wrap it as MP4. This, I'm told, is exceedingly difficult to do, and I haven't found anything useful online that could shed light on how to do it. We've got code in the pipeline to do it but it won't be ready until long after we need it. If we could do it, I could easily subclass NSURLProtocol and have it working within a matter of hours minutes. Use FFmpeg to implement option #2. FFmpeg seems like a possible solution but it isn't configured to build for iOS and I don't have the background to get it working (whereas the rest of our engineers don't have the Apple background needed.) I think #2 is our best bet, but as I don't know the ins and outs of MPEG-2 TS and MPEG-4, I don't have the ability to put it together myself. Does anybody have any insight into this problem? Perhaps some experience playing local TS files on iOS, or some tips on converting from TS to MP4?

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  • Invoking [SKProductsRequest start] hangs on iOS 4.0

    - by figelwump
    Encountering an issue with SKProductsRequest that is specific to iOS 4.0. The problematic code: - (void)requestProductData { NSSet *productIdentifiers = [NSSet setWithObjects:kLimitedDaysUpgradeProductId, kUnlimitedUpgradeProductId, nil]; self.productsRequest = [[SKProductsRequest alloc] initWithProductIdentifiers:productIdentifiers]; self.productsRequest.delegate = self; [self.productsRequest start]; } - (void)productsRequest:(SKProductsRequest *)request didReceiveResponse:(SKProductsResponse *)response { NSLog(@"didReceiveResponse"); } When [SKProductsRequest start] is invoked, the productsRequest:didReceiveResponse: delegate method is never invoked; further, the entire app hangs and is completely unresponsive to input. Obviously, this is a huge issue for our iOS 4.0 users as it not only breaks payments but makes the app completely unusable. Some other things to note: this only happens on iOS 4.0; iOS 4.2, 3.x are fine. Also: if the delegate is not set on the SKProductsRequest (i.e. comment out the line "self.productsRequest.delegate = self;"), the app doesn't hang (but of course in that case we have no way of getting the product info). Also, the problem still reproduces with everything stripped out of the productsRequest:didReceiveResponse: callback (that method never actually gets called). Finally, if the productIdentifiers NSSet object is initialized to an empty set, the hang doesn't occur. Has anybody else experienced this? Any ideas/thoughts on what could be going on here, and how we might be able to work around this?

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  • Does anyone really understand how HFSC scheduling in Linux/BSD works?

    - by Mecki
    I read the original SIGCOMM '97 PostScript paper about HFSC, it is very technically, but I understand the basic concept. Instead of giving a linear service curve (as with pretty much every other scheduling algorithm), you can specify a convex or concave service curve and thus it is possible to decouple bandwidth and delay. However, even though this paper mentions to kind of scheduling algorithms being used (real-time and link-share), it always only mentions ONE curve per scheduling class (the decoupling is done by specifying this curve, only one curve is needed for that). Now HFSC has been implemented for BSD (OpenBSD, FreeBSD, etc.) using the ALTQ scheduling framework and it has been implemented Linux using the TC scheduling framework (part of iproute2). Both implementations added two additional service curves, that were NOT in the original paper! A real-time service curve and an upper-limit service curve. Again, please note that the original paper mentions two scheduling algorithms (real-time and link-share), but in that paper both work with one single service curve. There never have been two independent service curves for either one as you currently find in BSD and Linux. Even worse, some version of ALTQ seems to add an additional queue priority to HSFC (there is no such thing as priority in the original paper either). I found several BSD HowTo's mentioning this priority setting (even though the man page of the latest ALTQ release knows no such parameter for HSFC, so officially it does not even exist). This all makes the HFSC scheduling even more complex than the algorithm described in the original paper and there are tons of tutorials on the Internet that often contradict each other, one claiming the opposite of the other one. This is probably the main reason why nobody really seems to understand how HFSC scheduling really works. Before I can ask my questions, we need a sample setup of some kind. I'll use a very simple one as seen in the image below: Here are some questions I cannot answer because the tutorials contradict each other: What for do I need a real-time curve at all? Assuming A1, A2, B1, B2 are all 128 kbit/s link-share (no real-time curve for either one), then each of those will get 128 kbit/s if the root has 512 kbit/s to distribute (and A and B are both 256 kbit/s of course), right? Why would I additionally give A1 and B1 a real-time curve with 128 kbit/s? What would this be good for? To give those two a higher priority? According to original paper I can give them a higher priority by using a curve, that's what HFSC is all about after all. By giving both classes a curve of [256kbit/s 20ms 128kbit/s] both have twice the priority than A2 and B2 automatically (still only getting 128 kbit/s on average) Does the real-time bandwidth count towards the link-share bandwidth? E.g. if A1 and B1 both only have 64kbit/s real-time and 64kbit/s link-share bandwidth, does that mean once they are served 64kbit/s via real-time, their link-share requirement is satisfied as well (they might get excess bandwidth, but lets ignore that for a second) or does that mean they get another 64 kbit/s via link-share? So does each class has a bandwidth "requirement" of real-time plus link-share? Or does a class only have a higher requirement than the real-time curve if the link-share curve is higher than the real-time curve (current link-share requirement equals specified link-share requirement minus real-time bandwidth already provided to this class)? Is upper limit curve applied to real-time as well, only to link-share, or maybe to both? Some tutorials say one way, some say the other way. Some even claim upper-limit is the maximum for real-time bandwidth + link-share bandwidth? What is the truth? Assuming A2 and B2 are both 128 kbit/s, does it make any difference if A1 and B1 are 128 kbit/s link-share only, or 64 kbit/s real-time and 128 kbit/s link-share, and if so, what difference? If I use the seperate real-time curve to increase priorities of classes, why would I need "curves" at all? Why is not real-time a flat value and link-share also a flat value? Why are both curves? The need for curves is clear in the original paper, because there is only one attribute of that kind per class. But now, having three attributes (real-time, link-share, and upper-limit) what for do I still need curves on each one? Why would I want the curves shape (not average bandwidth, but their slopes) to be different for real-time and link-share traffic? According to the little documentation available, real-time curve values are totally ignored for inner classes (class A and B), they are only applied to leaf classes (A1, A2, B1, B2). If that is true, why does the ALTQ HFSC sample configuration (search for 3.3 Sample configuration) set real-time curves on inner classes and claims that those set the guaranteed rate of those inner classes? Isn't that completely pointless? (note: pshare sets the link-share curve in ALTQ and grate the real-time curve; you can see this in the paragraph above the sample configuration). Some tutorials say the sum of all real-time curves may not be higher than 80% of the line speed, others say it must not be higher than 70% of the line speed. Which one is right or are they maybe both wrong? One tutorial said you shall forget all the theory. No matter how things really work (schedulers and bandwidth distribution), imagine the three curves according to the following "simplified mind model": real-time is the guaranteed bandwidth that this class will always get. link-share is the bandwidth that this class wants to become fully satisfied, but satisfaction cannot be guaranteed. In case there is excess bandwidth, the class might even get offered more bandwidth than necessary to become satisfied, but it may never use more than upper-limit says. For all this to work, the sum of all real-time bandwidths may not be above xx% of the line speed (see question above, the percentage varies). Question: Is this more or less accurate or a total misunderstanding of HSFC? And if assumption above is really accurate, where is prioritization in that model? E.g. every class might have a real-time bandwidth (guaranteed), a link-share bandwidth (not guaranteed) and an maybe an upper-limit, but still some classes have higher priority needs than other classes. In that case I must still prioritize somehow, even among real-time traffic of those classes. Would I prioritize by the slope of the curves? And if so, which curve? The real-time curve? The link-share curve? The upper-limit curve? All of them? Would I give all of them the same slope or each a different one and how to find out the right slope? I still haven't lost hope that there exists at least a hand full of people in this world that really understood HFSC and are able to answer all these questions accurately. And doing so without contradicting each other in the answers would be really nice ;-)

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  • Does anyone really understand how HFSC scheduling in Linux/BSD works?

    - by Mecki
    I read the original SIGCOMM '97 PostScript paper about HFSC, it is very technically, but I understand the basic concept. Instead of giving a linear service curve (as with pretty much every other scheduling algorithm), you can specify a convex or concave service curve and thus it is possible to decouple bandwidth and delay. However, even though this paper mentions to kind of scheduling algorithms being used (real-time and link-share), it always only mentions ONE curve per scheduling class (the decoupling is done by specifying this curve, only one curve is needed for that). Now HFSC has been implemented for BSD (OpenBSD, FreeBSD, etc.) using the ALTQ scheduling framework and it has been implemented Linux using the TC scheduling framework (part of iproute2). Both implementations added two additional service curves, that were NOT in the original paper! A real-time service curve and an upper-limit service curve. Again, please note that the original paper mentions two scheduling algorithms (real-time and link-share), but in that paper both work with one single service curve. There never have been two independent service curves for either one as you currently find in BSD and Linux. Even worse, some version of ALTQ seems to add an additional queue priority to HSFC (there is no such thing as priority in the original paper either). I found several BSD HowTo's mentioning this priority setting (even though the man page of the latest ALTQ release knows no such parameter for HSFC, so officially it does not even exist). This all makes the HFSC scheduling even more complex than the algorithm described in the original paper and there are tons of tutorials on the Internet that often contradict each other, one claiming the opposite of the other one. This is probably the main reason why nobody really seems to understand how HFSC scheduling really works. Before I can ask my questions, we need a sample setup of some kind. I'll use a very simple one as seen in the image below: Here are some questions I cannot answer because the tutorials contradict each other: What for do I need a real-time curve at all? Assuming A1, A2, B1, B2 are all 128 kbit/s link-share (no real-time curve for either one), then each of those will get 128 kbit/s if the root has 512 kbit/s to distribute (and A and B are both 256 kbit/s of course), right? Why would I additionally give A1 and B1 a real-time curve with 128 kbit/s? What would this be good for? To give those two a higher priority? According to original paper I can give them a higher priority by using a curve, that's what HFSC is all about after all. By giving both classes a curve of [256kbit/s 20ms 128kbit/s] both have twice the priority than A2 and B2 automatically (still only getting 128 kbit/s on average) Does the real-time bandwidth count towards the link-share bandwidth? E.g. if A1 and B1 both only have 64kbit/s real-time and 64kbit/s link-share bandwidth, does that mean once they are served 64kbit/s via real-time, their link-share requirement is satisfied as well (they might get excess bandwidth, but lets ignore that for a second) or does that mean they get another 64 kbit/s via link-share? So does each class has a bandwidth "requirement" of real-time plus link-share? Or does a class only have a higher requirement than the real-time curve if the link-share curve is higher than the real-time curve (current link-share requirement equals specified link-share requirement minus real-time bandwidth already provided to this class)? Is upper limit curve applied to real-time as well, only to link-share, or maybe to both? Some tutorials say one way, some say the other way. Some even claim upper-limit is the maximum for real-time bandwidth + link-share bandwidth? What is the truth? Assuming A2 and B2 are both 128 kbit/s, does it make any difference if A1 and B1 are 128 kbit/s link-share only, or 64 kbit/s real-time and 128 kbit/s link-share, and if so, what difference? If I use the seperate real-time curve to increase priorities of classes, why would I need "curves" at all? Why is not real-time a flat value and link-share also a flat value? Why are both curves? The need for curves is clear in the original paper, because there is only one attribute of that kind per class. But now, having three attributes (real-time, link-share, and upper-limit) what for do I still need curves on each one? Why would I want the curves shape (not average bandwidth, but their slopes) to be different for real-time and link-share traffic? According to the little documentation available, real-time curve values are totally ignored for inner classes (class A and B), they are only applied to leaf classes (A1, A2, B1, B2). If that is true, why does the ALTQ HFSC sample configuration (search for 3.3 Sample configuration) set real-time curves on inner classes and claims that those set the guaranteed rate of those inner classes? Isn't that completely pointless? (note: pshare sets the link-share curve in ALTQ and grate the real-time curve; you can see this in the paragraph above the sample configuration). Some tutorials say the sum of all real-time curves may not be higher than 80% of the line speed, others say it must not be higher than 70% of the line speed. Which one is right or are they maybe both wrong? One tutorial said you shall forget all the theory. No matter how things really work (schedulers and bandwidth distribution), imagine the three curves according to the following "simplified mind model": real-time is the guaranteed bandwidth that this class will always get. link-share is the bandwidth that this class wants to become fully satisfied, but satisfaction cannot be guaranteed. In case there is excess bandwidth, the class might even get offered more bandwidth than necessary to become satisfied, but it may never use more than upper-limit says. For all this to work, the sum of all real-time bandwidths may not be above xx% of the line speed (see question above, the percentage varies). Question: Is this more or less accurate or a total misunderstanding of HSFC? And if assumption above is really accurate, where is prioritization in that model? E.g. every class might have a real-time bandwidth (guaranteed), a link-share bandwidth (not guaranteed) and an maybe an upper-limit, but still some classes have higher priority needs than other classes. In that case I must still prioritize somehow, even among real-time traffic of those classes. Would I prioritize by the slope of the curves? And if so, which curve? The real-time curve? The link-share curve? The upper-limit curve? All of them? Would I give all of them the same slope or each a different one and how to find out the right slope? I still haven't lost hope that there exists at least a hand full of people in this world that really understood HFSC and are able to answer all these questions accurately. And doing so without contradicting each other in the answers would be really nice ;-)

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  • Git sh.exe process forking issue on windows XP, slow?

    - by AndyL
    Git is essential to my workflow. I run MSYS Git on Windows XP on my quad core machine with 3GB of RAM, and normally it is responsive and zippy. Suddenly an issue has cropped up whereby it takes 30 seconds to run any command from the Git Bash command prompt, including ls or cd. Interestingly, from the bash prompt it looks likes ls runs fairly quickly, I can then see the output from ls, but it then takes ~30 seconds for the prompt to return. If I switch to the windows command prompt (by running cmd from the start menu) git related commands also take forever, even just to run. For example git status can take close to a minute before anything happens. Sometimes the processes simply don't finish. Note that I have "MSYS Git" installed as well as regular "MSYS" for things like MinGW and make. I believe the problem is related to sh.exe located in C:\Program Files\Git\bin. When I run ls from the bash prompt, or when I invoke git from the windows prompt, task manager shows up to four instances of sh.exe processes that come and go. Here I am waiting for ls to return and you can see the task manager has git.exe running and four instances of sh.exe: If I ctrl-c in the middle of an ls I sometimes get errors that include: sh.exe": fork: Resource temporarily unavailable 0 [main] sh.exe" 1624 proc_subproc: Couldn't duplicate my handle<0x6FC> fo r pid 6052, Win32 error 5 sh.exe": fork: Resource temporarily unavailable Or for git status: $ git status sh.exe": fork: Resource temporarily unavailable sh.exe": fork: Resource temporarily unavailable sh.exe": fork: Resource temporarily unavailable sh.exe": fork: Resource temporarily unavailable Can I fix this so that git runs quickly again, and if so how? Things I have tried: Reboot Upgrade MSYS Git to most recent version & Reboot Upgrade MSYS to most recent version & Reboot Uninstall MSYS & uninstall and reinstall MSYS Git alone & Reboot I'd very much like to not wipe my box and reinstall Windows, but I will if I can't get this fixed. I can no longer code if it takes me 30 s to run git status or cd.

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  • Can't install NPM after installing Node on EC2 Linux instance?

    - by frequent
    I'm trying my first attempt on getting a node server set up on an amazon ec2 linux instance. I think I made it quite far. First problem I ran into was when trying to make Node the connection timed out after a while, so I need three attempts until I got this: LINK(target) /home/ec2-user/node/out/Release/node: Finished touch /home/ec2-user/node/out/Release/obj.target/node_dtrace_header.stamp touch /home/ec2-user/node/out/Release/obj.target/node_dtrace_provider.stamp touch /home/ec2-user/node/out/Release/obj.target/node_dtrace_ustack.stamp touch /home/ec2-user/node/out/Release/obj.target/node_etw.stamp make[1]: Leaving directory `/home/ec2-user/node/out' ln -fs out/Release/node node Which tells me, "Node is done", although I'm not sure it is also working as it should. Following this,this and this tutorial, I'm now stuck at installing npm. I think I first cloned into the wrong folder, which always gave me error 127, but even if I'm doing this: cd ~ git clone git://github.com/isaacs/npm.git cd npm sudo -s PATH=/usr/local/bin:$PATH make install I'm still getting this: #after cloning# make[1]: Entering directory `/root/npm' node cli.js install bash: node: command not found make[1]: *** [node_modules/.bin/ronn] Error 127 make[1]: Leaving directory `/root/npm' make: *** [man/man3/start.3] Error 2 Question:: Since I'm pretty much a newby at everything I'm trying here, can someone please tell me what I'm doing wrong and how to get npm to install? Also, in case I cloned into the wrong folder, is there a way to remove the "false clone" or is this not written to disk until I call make install and I don't need to worry? Thanks for helping out!

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  • Bash script 'while read' loop causes 'broken pipe' error when run with GNU Parallel

    - by Joe White
    According to the GNU Parallel mailing list this is not a GNU Parallel-specific problem. They suggested that I post my problem here. The error I'm getting is a "broken pipe" error, but I feel I should first explain the context of my problem and what causes this error. It happens when trying to use any bash script containing a 'while read' loop in GNU Parallel. I have a basic bash script like this: #!/bin/bash # linkcheck.sh while read domain do host "$domain" done Assume that I want to pipe in a large list (250mb say). cat urllist | ./linkcheck.sh Running host command on 250mb worth of URLs is rather slow. To speed things up I want to break up the input into chunks before piping it and then run multiple jobs in parallel. GNU Parallel is capable of doing this. cat urllist | parallel --pipe -j0 parallel ./linkcheck.sh {} {} is substituted by the contents of urllist line-by-line. Assume that my systems default setup is capable of running 500ish jobs per instance of parallel. To get round this limitation we can parallelize Parallel itself: cat urllist | parallel -j10 --pipe parallel -j0 ./linkcheck.sh {} This will run 5000'ish jobs. It will also, sadly, cause the error "broken pipe" (bash FAQ). Yet the script starts to work if I remove the while read loop and take input directly from whatever is fed into {} e.g., #!/bin/bash # linkchecker.sh domain="$1" host "$1" Why will it not work with a while read loop? Is it safe to just turn off the SIGPIPE signal to stop the "broken pipe" message, or will that have side effects such as data corruption? Thanks for reading.

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  • How do I keep folders synced and backed up between two macs using a Linux NAS (rsync?)

    - by Hultner
    I've got two primary computers, one Mac Pro and one MacBook Pro for when I'm on the go. I've also got a Linux sever which also acts as NAS. Currently I backup the entire computers to an external drive with Time Machine which is rather useless and doesn't sync anything. What I really want to do is to keep my important files synced between both computers and my NAS (which is running RAID 5), that way I'm not backing up easily replaceable systemfiles and I've got all my important files in 3 places where two of them are running raid so at least 5 drives would have to crash at the same time before actual data loss occur. Folders I want to keep synced is basically my photo, documents, development, mamp and work folders and then I want to keep the user library folder backed up but not synced. I'm thinking that I'd have to use rsync but don't know how. Before suggesting Dropbox and similar suggestions I don't want to use them because of several reasons some of them being security (Dropbox obviously proved this), Speed (sometimes I'll sync gigabytes of data and that will be significantly faster locally and probably even through VPN as I have a Gigabit pipe), Space (space on my NAS is cheap and only practically limited by my needs), reliability (even if my internet were to go down I still need to be able to keep my files synced incase I'd need to go somewhere on the fly), price (I already have all the hardware and for the amount of gigabytes and bandwidth I'd need I doubt that there's any free or cheap service). Those are my main reason for wanting to keep it locally. I'm sorry for any spelling or grammatical mistakes that I've might have done. I'm writing this on my smartphone from a shaky train and English isn't my mother tongue. I gratefully appreciate any answers even if only partly solving my problem.

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  • Is it possible to be a professional studying on your own?

    - by Marc Jr
    I read economics at university(nothing to see with linux, isn't it? :P). I have some basic knowledge about booting process, Linux Kernel compiling from source and stuff like that. But of course I have still much to learn sometimes some errors appears and "voila" I am lost. I had: Ubuntu, Fedora, OpenSuse, Arch.. using Gentoo now. I'd like to know what you linux users, professionals, administrators... would think it is the best way to learn linux in a professional way. Is it worth studying it and passing the LPIC test enough to work in the linux world? or do I need going to IT uni? I've heard LFS is a good way of learning about linux, is that real? I've been thinking about getting to LFS learn about more deeply about the linux process and learning scripts. It is possible to do this way? if anyone has a tip or a good way of doing, maybe someone did it. Any tip is very welcome. Words from a person in love with linux. :D The best, Marc

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  • Find all duplicate files by md5 hash

    - by Jamie Curran
    I'm trying to find all duplicate files based upon md5 hash and ordered by file size. So far I have this: find . -type f -print0 | xargs -0 -I "{}" sh -c 'md5sum "{}" | cut -f1 -d " " | tr "\n" " "; du -h "{}"' | sort -h -k2 -r | uniq -w32 --all-repeated=separate The output of this is: 1832348bb0c3b0b8a637a3eaf13d9f22 4.0K ./picture.sh 1832348bb0c3b0b8a637a3eaf13d9f22 4.0K ./picture2.sh 1832348bb0c3b0b8a637a3eaf13d9f22 4.0K ./picture2.s d41d8cd98f00b204e9800998ecf8427e 0 ./test(1).log Is this the most efficient way?

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  • Why am I seeing MailSlot Browse messages on unrouted ports of my Linux box?

    - by nmichaels
    I have a Linux box (Debian squeeze) with several NICs. The ones of interest are: eth3 - my main link to the network (dhcp on 10.20.30.0/24) eth0 - the first connection to my test network (static: 192.168.1.2) eth4 - the second connection to my test network (static: 192.168.1.1) My routing table looks like this: $ sudo route Kernel IP routing table Destination Gateway Genmask Flags Metric Ref Use Iface 10.20.30.0 * 255.255.255.0 U 0 0 0 eth3 default 10.20.30.254 0.0.0.0 UG 0 0 0 eth3 I have the 2 test net ports connected to each other with a crossover cable and an instance of wireshark running on each port. Every once in a while, I'll see a packet like the following show up. Who could be doing this, and how do I convince them to stop? I do have Samba running on the machine (for a cifs mount) but don't see why it would be sending packets out to unrouted ports. I had a Windows VM running in VMWare Client and thought that might be causing it, but it still happens without it. What I want is totally silent interfaces so I can run some tests with Scapy over them.

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  • Linux server apache httpd processes take i/o wait to close to 100% and lock down server

    - by user3682065
    For about 5 days now, and seemingly out of the blue, my linux server has started locking up from time to time. The pattern is always the same as far as I can tell from top and iotop commands around the time it starts happening: One or more httpd processes (usually one) hang and start using up 100% of CPU power, the %wa goes close to 100% and in the iotop I see several httpd processes with 99.99% in the IO column. I'm also running an SVN server on this machine through apache and the one way that I've been consistently able to reproduce this is to do an SVN commit of new files or an SVN update from the repository on this server (I am the only one using this SVN repository). This will always reproduce this scenario successfully, but until very recently I had no problems at all checking in/out of SVN. But sometimes it just happens for no detectable reason at all it seems. So it seems like there is some issue with my Apache that leads it to have processes use up a lot of read/write upon certain triggers. I was wondering if anyone could help me uncover that issue. EDIT: OK now it's happening again: This is top: [root@server ~]# top top - 10:56:54 up 2:59, 5 users, load average: 171.46, 70.35, 27.01 Tasks: 328 total, 2 running, 326 sleeping, 0 stopped, 0 zombie Cpu(s): 1.9%us, 2.0%sy, 0.0%ni, 0.0%id, 96.1%wa, 0.0%hi, 0.0%si, 0.0%st Mem: 2021144k total, 1968192k used, 52952k free, 2500k buffers Swap: 4194288k total, 2938584k used, 1255704k free, 39008k cached PID USER PR NI VIRT RES SHR S %CPU %MEM TIME+ COMMAND 10390 apache 20 0 2774m 936m 6200 D 2.0 47.4 1:52.27 httpd 2149 root 20 0 927m 13m 1040 S 0.7 0.7 1:50.46 namecoind 11 root 20 0 0 0 0 R 0.3 0.0 0:30.10 events/0 23 root 20 0 0 0 0 S 0.3 0.0 0:17.88 kblockd/1 2049 root 20 0 382m 4932 2880 D 0.3 0.2 0:03.67 httpd 2144 root 20 0 1702m 69m 1164 S 0.3 3.5 5:19.68 bitcoind 6325 root 20 0 15164 1100 656 R 0.3 0.1 0:11.09 top 10311 apache 20 0 387m 9496 7320 D 0.3 0.5 0:01.89 httpd 10313 apache 20 0 391m 10m 7364 D 0.3 0.5 0:02.40 httpd 10466 apache 20 0 399m 12m 7392 D 0.3 0.7 0:02.41 httpd 10599 apache 20 0 391m 9324 7340 D 0.3 0.5 0:00.15 httpd 10628 apache 20 0 384m 7620 4052 D 0.3 0.4 0:00.01 httpd 10633 apache 20 0 384m 7048 3504 D 0.3 0.3 0:00.01 httpd 10634 apache 20 0 384m 8012 4048 D 0.3 0.4 0:00.02 httpd 10638 apache 20 0 400m 22m 9.8m D 0.3 1.1 0:01.93 httpd 10640 apache 20 0 385m 8288 4028 D 0.3 0.4 0:00.03 httpd 10641 apache 20 0 401m 21m 6376 D 0.3 1.1 0:01.45 httpd 10759 apache 20 0 385m 8816 3480 D 0.3 0.4 0:01.45 httpd 10773 apache 20 0 384m 8044 3464 D 0.3 0.4 0:00.02 httpd This is an iotop snapshot: Total DISK READ: 5.93 M/s | Total DISK WRITE: 0.00 B/s TID PRIO USER DISK READ DISK WRITE SWAPIN IO> COMMAND 10732 be/4 apache 3.76 K/s 0.00 B/s 0.00 % 58.48 % httpd 876 be/3 root 0.00 B/s 52.68 K/s 0.00 % 52.98 % [jbd2/dm-1-8] 10906 be/4 root 124.17 K/s 0.00 B/s 0.00 % 23.03 % sh -c [ -x /usr/local/psa/admin/sbin/backupmng ] && /usr/local/psa/admin/sbin/backupmng >/dev/null 2>&1 2156 be/4 root 206.94 K/s 0.00 B/s 0.00 % 21.15 % bitcoind 10904 be/4 mysql 0.00 B/s 0.00 B/s 0.00 % 18.94 % mysqld --basedir=/usr --datadir=/var/lib/mysql --user=mysql --log-error=/var/log/mysqld.log --pid-file=/var/run/mysqld/mysqld.pid --socket=/var/lib/mysql/mysql.sock 10773 be/4 apache 7.53 K/s 0.00 B/s 0.00 % 14.77 % httpd 10641 be/4 apache 15.05 K/s 0.00 B/s 0.00 % 11.57 % httpd 10399 be/4 apache 1057.29 K/s 0.00 B/s 43.16 % 10.56 % httpd 10682 be/4 sw-cp-se 158.03 K/s 0.00 B/s 0.00 % 7.45 % sw-engine-cgi -c /usr/local/psa/admin/conf/php.ini -d auto_prepend_file=auth.php3 -u psaadm 10774 be/4 apache 3.76 K/s 0.00 B/s 0.00 % 6.53 % httpd 10624 be/4 apache 0.00 B/s 0.00 B/s 0.00 % 5.53 % httpd 10356 be/4 apache 899.26 K/s 0.00 B/s 35.52 % 4.01 % httpd 10795 be/4 apache 0.00 B/s 0.00 B/s 0.00 % 3.93 % httpd 10804 be/4 apache 7.53 K/s 0.00 B/s 0.00 % 3.08 % httpd 4379 be/4 root 2.89 M/s 0.00 B/s 99.99 % 0.00 % namecoind 10619 be/4 apache 462.80 K/s 0.00 B/s 7.80 % 0.00 % httpd 10636 be/4 apache 3.76 K/s 0.00 B/s 0.00 % 0.00 % httpd 10716 be/4 mysql 105.35 K/s 0.00 B/s 5.92 % 0.00 % mysqld --basedir=/usr --datadir=/var/lib/mysql --user=mysql --log-error=/var/log/mysqld.log --pid-file=/var/run/mysqld/mysqld.pid --socket=/var/lib/mysql/mysql.sock 1988 be/4 root 18.81 K/s 0.00 B/s 0.00 % 0.00 % spamd_full.sock I also ran lsof -p for pid 10390 which was way up top under the top command and this is the bottom line where I can sort of see what request this was and it says CLOSE_WAIT: httpd 10390 apache 34u IPv6 315879 0t0 TCP default-domain.com:https->crawl-66-249-65-91.googlebot.com:42907 (CLOSE_WAIT) I'm still not sure what exactly is causing this all to happen though? I killed that service but %wa and load average remain high, I also stopped mysqld and other services. It really only goes down once I stop httpd altogether, and even then I can't start it without finding remaining hanging httpd processes via "netstat -tulpn", killing those or doing "killall -9 httpd" and after waiting a while for it to cycle through all those then doing /etc/init.d/httpd start

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  • Why is my filesystem being mounted read-only in linux?

    - by Tim
    I am trying to set up a small linux system based on Gentoo on a VirtualBox machine, as a step towards deploying the same system onto a low-spec Single Board Computer. For some reason, my filesystem is being mounted read-only. In my /etc/fstab, I have: /dev/sda1 / ext3 defaults 0 0 none /proc proc defaults 0 0 none /sys sysfs defaults 0 0 none /dev/shm tmpfs defaults 0 0 However, once booted /proc/mounts shows rootfs / rootfs rw 0 0 /dev/root / ext3 ro,relatime,errors=continue,barrier=0,data=writeback 0 0 proc /proc proc rw,nosuid,nodev,noexec,relatime 0 0 sysfs /sys sysfs rw,nosuid,nodev,noexec,relatime 0 0 udev /dev tmpfs rw,nosuid,relatime,size=10240k,mode=755 0 0 devpts /dev/pts devpts rw,nosuid,noexec,relatime,gid=5,mode=620 0 0 none /dev/shm tmpfs rw,relatime 0 0 usbfs /proc/bus/usb usbfs rw,nosuid,noexec,relatime,devgid=85,devmode=664 0 0 binfmt_misc /proc/sys/fs/binfmt_misc binfmt_misc rw,nosuid,nodev,noexec,relatime 0 0 (the above may contain errors: there's no practical way to copy and paste) The partition at /dev/hda1 is clearly being mounted OK, since I can read all the data, but it's not being mounted as described in fstab. How might I go about diagnosing / resolving this? Edit: I can remount with mount -o remount,rw / and it works as expected, except that /proc/mounts reports /dev/root mounted at / rather than /dev/sda1 as I'd expect. If I try to remount with mount -a I get mount: none already mounted or /sys busy mount: according to mtab, sysfs is already mounted on /sys Edit 2: I resolved the problem with mount -a (the same error was occuring during startup, it turned out) by changing the sysfs and proc lines to proc /proc proc [...] sysfs /sys sysfs [...] Now mount -a doesn't complain, but it doesn't result in a read-write root partition. mount -o remount / does cause the root partition to be remounted, however.

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  • placing shell script under systemd control

    - by Calvin Cheng
    Assuming I have a shell script like this:- #!/bin/sh # cherrypy_server.sh PROCESSES=10 THREADS=1 # threads per process BASE_PORT=3035 # the first port used # you need to make the PIDFILE dir and insure it has the right permissions PIDFILE="/var/run/cherrypy/myproject.pid" WORKDIR=`dirname "$0"` cd "$WORKDIR" cp_start_proc() { N=$1 P=$(( $BASE_PORT + $N - 1 )) ./manage.py runcpserver daemonize=1 port=$P pidfile="$PIDFILE-$N" threads=$THREADS request_queue_size=0 verbose=0 } cp_start() { for N in `seq 1 $PROCESSES`; do cp_start_proc $N done } cp_stop_proc() { N=$1 #[ -f "$PIDFILE-$N" ] && kill `cat "$PIDFILE-$N"` [ -f "$PIDFILE-$N" ] && ./manage.py runcpserver pidfile="$PIDFILE-$N" stop rm -f "$PIDFILE-$N" } cp_stop() { for N in `seq 1 $PROCESSES`; do cp_stop_proc $N done } cp_restart_proc() { N=$1 cp_stop_proc $N #sleep 1 cp_start_proc $N } cp_restart() { for N in `seq 1 $PROCESSES`; do cp_restart_proc $N done } case "$1" in "start") cp_start ;; "stop") cp_stop ;; "restart") cp_restart ;; *) "$@" ;; esac From the bash script, we can essentially do 3 things: start the cherrypy server by calling ./cherrypy_server.sh start stop the cherrypy server by calling ./cherrypy_server.sh stop restart the cherrypy server by calling ./cherrypy_server.sh restart How would I place this shell script under systemd's control as a cherrypy.service file (with the obvious goal of having systemd start up the cherrypy server when a machine has been rebooted)? Reference systemd service file example here - https://wiki.archlinux.org/index.php/Systemd#Using_service_file

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  • Simple Linux program that takes any HTTP/HTTPS request and returns a single page?

    - by ultrasawblade
    I have a Linux box operating as router. There's a NIC that's connected to the internet (WAN), a NIC connected to an 8-port GbE switch (LAN), and a NIC connected to a Linksys wireless N-router (WLAN). Routing between everything is working perfectly. I have security completely disabled on the wireless router, but the WLAN NIC is firewalled such that it will only accept DNS queries and PPTP VPN connections. Currently HTTP/HTTPS traffic and everything else is blocked. I would like to run something that listens on port 80/443 of the WLAN NIC, and, for non VPN'ed connections, given any HTTP/HTTPS request it will return a single webpage saying "Unauthenticated" and explain how to sign into the VPN. A transparent proxy seems to be what I need, but my searches all seem to direct me to Squid, which is already running on my server and seems overkill for this simple task. Is there a simpler, lightweight program out there that does just this or should I just suck it up and run two instances of Squid (or figure out how to configure it)? Or, is this entire VPN thing I'm doing complete nonsense and I should just enable encryption on the wireless router?

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