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  • Simple MySQL Query taking 45 seconds (Gets a record and its "latest" child record)

    - by Brian Lacy
    I have a query which gets a customer and the latest transaction for that customer. Currently this query takes over 45 seconds for 1000 records. This is especially problematic because the script itself may need to be executed as frequently as once per minute! I believe using subqueries may be the answer, but I've had trouble constructing it to actually give me the results I need. SELECT customer.CustID, customer.leadid, customer.Email, customer.FirstName, customer.LastName, transaction.*, MAX(transaction.TransDate) AS LastTransDate FROM customer INNER JOIN transaction ON transaction.CustID = customer.CustID WHERE customer.Email = '".$email."' GROUP BY customer.CustID ORDER BY LastTransDate LIMIT 1000 I really need to get this figured out ASAP. Any help would be greatly appreciated!

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  • I need unusual ordering mysql results

    - by Patrick
    Im trying to order results ASCENDING from the current date this is what im using now; SELECT * FROM friends JOIN bdays ON bdays.user = friends.friendname WHERE username = $userid ORDER BY DATE_FORMAT(date, '%m %d') any ideas? example ordering by date now, sorts the birthdays starting at january what i need, is instead of starting the list at january, is starting it from the current date. So, instead of; January February March April May June July August September November December It will order them like this; April (current month/day) May June July August September November December January February March April (all the way up to yesterday)

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  • mysql random generated value

    - by bbutle01
    I need to generate a random alpha/numeric to give to users that they come to the site to enter. I dont' know much about random numbers and such, I know there are seeding issues and such, but I'm not sure what they are. So, I used this: select substrING(md5(concat_ws('-',md5(username_usr), MD5(zip_usr), MD5(id_usr), MD5(created_usr))),-12) from users_usr Is this safe? I used concat_ws because sometimes zip is null, but the others never are. And yes, I know this is kinda short, but 1. They have to enter the last 4 of their social, 2. It's 1 time use, 3. There's no private data displayed back in the application and 4. I may use captcha, but since there's no private data, thats probably overkill. THanks

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  • MySQL slow query

    - by andrhamm
    SELECT items.item_id, items.category_id, items.title, items.description, items.quality, items.type, items.status, items.price, items.posted, items.modified, zip_code.state_prefix, zip_code.city, books.isbn13, books.isbn10, books.authors, books.publisher FROM ( ( items LEFT JOIN bookitems ON items.item_id = bookitems.item_id ) LEFT JOIN books ON books.isbn13 = bookitems.isbn13 ) LEFT JOIN zip_code ON zip_code.zip_code = items.item_zip WHERE items.rid = $rid` I am running this query to get the list of a user's items and their location. The zip_code table has over 40k records and this might be the issue. It currently takes up to 15 seconds to return a list of about 20 items! What can I do to make this query more efficient?

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  • problems with mysql "or"

    - by Simon
    i have a problem with "and" "or" syntax!!! here is my query. . . SELECT `act1`.`name`, `act1`.`surname`, `act2`.`name`, `act2`.`surname`, `act3`.`name`, `act3`.`surname` FROM videos, actors AS act1, actors AS act2, actors AS act3 WHERE videos.ident = 'somethink' AND ( act1.id = videos.id_actor1 OR act2.id = videos.id_actor2 OR act3.id = videos.id_actor3 ) it returns me all variations of {name, surname}, but why!!! i want the name and surname of first axactly, second and thirth, if they exist!!! halp me please

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  • Grouping timestamps by interval between timestamps, then calculating from group MySQL

    - by Emile
    To put this question into context, I'm trying to calculate "time in app" based on an event log. Assume the following table: user_id event_time 2 2012-05-09 07:03:38 3 2012-05-09 07:03:42 4 2012-05-09 07:03:43 2 2012-05-09 07:03:44 2 2012-05-09 07:03:45 4 2012-05-09 07:03:52 2 2012-05-09 07:06:30 I'd like to get the difference between the highest and lowest event_time from a set of timestamps that are within 2 minutes of eachother (and grouped by user). If a timestamp is outside of a 2 minute interval from the set, it should be considered a part of another set. Desired output: user_id seconds_interval 2 7 (because 07:03:45 - 07:03:38 is 7 seconds) 3 0 (because 07:03:42) 4 9 (because 07:03:52 - 2012-05-09 07:03:43) 2 0 (because 07:06:30 is outside 2 min interval of 1st user_id=2 set) This is what I've tried, although I can't group on seconds_interval (even if I could, I'm not sure this is the right direction): SELECT (max(tr.event_time)-min(tr.event_time)) as seconds_interval FROM some_table tr INNER JOIN TrackingRaw tr2 ON (tr.event_time BETWEEN tr2.event_time - INTERVAL 2 MINUTE AND tr2.event_time + INTERVAL 2 MINUTE) GROUP BY seconds_interval

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  • mySql table returning JSON that needs formatting for a iPhone UITableview

    - by Michael Robinson
    I have a php query the returns the following JSON format from a table. [{"memberid":"18", "useridFK":"30", "loginName":"Johnson", "name":"Frank", "age":"23", "place":"School", }, It needs the following format: [{"memberid":"18" { "useridFK":"30", "loginName":"Johnson", "name":"Frank", "age":"23", "place":"School",} }, I can figure out where/how to convert this, Where would I create the formatting following: (1) In the php return? (2) the JSON instructions for deserialization? or (3) Some kinb of Obj-C coding instruction? My end use is a simple Drill Down table using the NSObject, so when I select "memberid" row, I'll get the child/detail list on the next UITableview. My Data.plist will look like the following: Root: Dictionary V Rows: Array V Item 0: Dictionary Title: String 18 V Children Array V Item 0 Dictionary Title String 30 etc. Thanks in advance, this site rocks.

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  • MySQL: Copy a field to another table

    - by harpax
    I have a table posts that could look like this: id | title | body | created | .. ------------------------------------------- I would like to use the boolean search feature that is offered by a MyISAM Table, but the posts table is InnoDB. So I created another table 'post_contents' that looks like this: post_id | body -------------------- That table is already filled with some contents and I can use the boolean search. However, I need to move the title field in the post_contents table as well and then copy the existing title-data to the new field. I know about the INSERT .. SELECT syntax, but I don't seem to be able to create the correct query.

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  • Partition of tables in MySQL

    - by Joel
    Hello, I have read that in a case where a table has many columns, but most of the time only one of them is used (say a title column in a forum post), a way to increase performance would be a partition to two tables, where one will contain only the title and the other one will contain the other columns (such as the forum post body). However, in case I use select ForumTitle from Forum; won't that be good enough to prevent the load of all columns (such as the forum post's body) to the memory, and eliminate the need of partition? Thanks, Joel

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  • MySQL how to sum subgroup first then sum total

    - by Sunry
    My data in table_1 and table_2. table_1 id_1 num ids_2 3 33 666,777,888 4 44 111,222,333 table_2 id_2 num 111 1 222 2 333 3 666 6 777 7 888 8 I only know how to do what I want with two steps: First LEFT JOIN to get: SELECT 1.id_1, sum(2.num) FROM table_1 AS 1 LEFT JOIN table_2 AS 2 on FIND_IN_SET(2.id_2, 1.ids_2) GROUP BY 1.id_1; id_1 sum(2.num) 3 6+7+8 4 1+2+3 Then LEFT JOIN with table_1 again to sum(table_1.num+sum(2.num)): id_1 sum(table_1.num+sum(table_2.num)) 3 6+7+8+33 4 1+2+3+44 Can I do it in only one SQL?

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  • mySQL Left Join on multiple tables with conditions

    - by Jarrod
    Hi, I have a problem. I have 4 tables: Invoice_Payment, Invoice, Client, and Calendar Basically, I have the below query, which works well, except, months with no date_due don't return. I.E only months with a date_due will be returned. I think I have to use a left join and join the calendar table with something like: LEFT JOIN Calendar ON Invoice_Payments.date_paid = Calendar.date_field. But I'm having no luck SELECT MONTHNAME(Invoice_Payments.date_paid) as month, SUM(Invoice_Payments.paid_amount) AS total FROM Invoice, Client, Invoice_Payments WHERE Client.registered_id = 1 AND Client.id = Invoice.client_id And Invoice.id = Invoice_Payments.invoice_id AND date_paid IS NOT NULL GROUP BY YEAR(Invoice_Payments.date_paid), MONTH(Invoice_Payments.date_paid) Any help appreciated.

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  • Php fetch rows from multiple MySQL tables

    - by Jon McIntosh
    Right now I am fetching all of the rows from one of my tables: query = "SELECT * FROM thread WHERE threadid = 2 ORDER BY threadid DESC"; $result = mysql_query($query); $num_rows = mysql_num_rows($result); if((!is_bool($result) || $result) && $num_rows) { while($row = mysql_fetch_array($result)) { $thread = $row['title']; $threadID = $row['threadid']; $poster = $row['postusername']; } What I want to do is go to another table on my database: "post_display", and get the row 'text' where the threadid = 2.

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  • php, mySQL - how to create a table?

    - by user296516
    Hi guys, I have written a code that should check weather there is a table called imei.$addimei and, if not, create it... $userdatabase = mysqli_connect('localhost', 'root', 'marina', 'imei'); ... $result = mysqli_query($userdatabase, "SELECT * FROM imei".$addimei."" ); if ( !$result ) { echo('creating table...'); /// if no such table, make one! mysql_query ( $userdatabase, 'CREATE TABLE imei'.$addimei.'( ID int NOT NULL AUTO_INCREMENT, PRIMARY KEY(ID), EVENT varchar(15), TIME varchar(25), FLD1 varchar(35), FLD2 varchar(35), IP varchar(25), )' ); } Yet the CREATE TABLE somehow doesn't seem to work. Warning: mysql_query() expects parameter 1 to be string, object given in C:\xampp\xampp\htdocs\mobi\mainmenu.php on line 564 Any idea's what wrong? Thanks!

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  • MySQL - display rows of names and addresses grouped by name, where name occures more than once

    - by Stoob
    I have two tables, "name" and "address". I would like to list the last_name and joined address.street_address of all last_name in table "name" that occur more than once in table "name". The two tables are joined on the column "name_id". The desired output would appear like so: 213 | smith | 123 bluebird | 14 | smith | 456 first ave | 718 | smith | 12 san antonia st. | 244 | jones | 78 third ave # 45 | 98 | jones | 18177 toronto place | Note that if the last_name "abernathy" appears only once in table "name", then "abernathy" should not be included in the result. This is what I came up with so far: SELECT name.name_id, name.last_name, address.street_address, count(*) FROM `name` JOIN `address` ON name.name_id = address.name_id GROUP BY `last_name` HAVING count(*) > 1 However, this produces only one row per last name. I'd like all the last names listed. I know I am missing something simple. Any help is appreciated, thanks!

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  • MySql left join on several regs

    - by egidiocs
    Hi there! I have this table1 idproduct(PK) | date_to_go 1 2010-01-18 2 2010-02-01 3 2010-02-21 4 2010-02-03 and this other table2 that controls date_to_go updates id | idproduct(FK) | prev_date_to_go | date_to_go | update_date 1 1 2010-01-01 2010-01-05 2009-12-01 2 1 2010-01-05 2010-01-10 2009-12-20 3 1 2010-01-10 2010-01-18 2009-12-20 4 3 2010-01-20 2010-02-03 2010-01-05 So, in this example, for table1.idproduct #1 2010-01-18 is the actual date_to_go and 2010-01-01 (table2.prev_date_to_go, first reg) is the original date_to_go . using this query select v.idproduct, v.date_to_go, p.prev_date_to_go original_date_to_go from table1 v left join produto_datas p on p.idproduto = v.idproduto group by (v.idproduto) order by v.idproduto can I assume that original_date_to_go will be the first related reg of table2? idproduct | date_to_go | original_date_to_go 1 2010-01-18 2010-01-01 2 2010-02-01 NULL 3 2010-02-21 2010-01-20 4 2010-02-03 NULL

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  • Getting mysql row that doesn't conflict with another row

    - by user939951
    I have two tables that link together through an id one is "submit_moderate" and one is "submit_post" The "submit_moderate" table looks like this id moderated_by post 1 James 60 2 Alice 32 3 Tim 18 4 Michael 60 Im using a simple query to get data from the "submit_post" table according to the "submit_moderate" table. $get_posts = mysql_query("SELECT * FROM submit_moderate WHERE moderated_by!='$user'"); $user is the person who is signed in. Now my problem is when I run this query, with the user 'Michael' it will retrieve this 1 James 60 2 Alice 32 3 Tim 18 Now technically this is correct however I don't want to retrieve the first row because 60 is associated with Michael as well as James. Basically I don't want to retrieve that value '60'. I know why this is happening however I can't figure out how to do this. I appreciate any hints or advice I can get.

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  • mysql GROUP_CONCAT

    - by user301766
    I want to list all users with their corropsonding user class. Here are simplified versions of my tables CREATE TABLE users ( user_id INT NOT NULL AUTO_INCREMENT, user_class VARCHAR(100), PRIMARY KEY (user_id) ); INSERT INTO users VALUES (1, '1'), (2, '2'), (3, '1,2'); CREATE TABLE classes ( class_id INT NOT NULL AUTO_INCREMENT, class_name VARCHAR(100), PRIMARY KEY (class_id) ); INSERT INTO classes VALUES (1, 'Class 1'), (2, 'Class 2'); And this is the query statement I am trying to use but is only returning the first matching user class and not a concatenated list as hoped. SELECT user_id, GROUP_CONCAT(DISTINCT class_name SEPARATOR ",") AS class_name FROM users, classes WHERE user_class IN (class_id) GROUP BY user_id; Actual Output +---------+------------+ | user_id | class_name | +---------+------------+ | 1 | Class 1 | | 2 | Class 2 | | 3 | Class 1 | +---------+------------+ Wanted Output +---------+---------------------+ | user_id | class_name | +---------+---------------------+ | 1 | Class 1 | | 2 | Class 2 | | 3 | Class 1, Class 2 | +---------+---------------------+ Thanks in advance

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  • MYSQL Inner Join two table over two keys

    - by bertsisterwanda
    I am doing a query to return all users shopping carts, stored in the sb_carts table. The product information stored in sb_carts is referenced over two keys product_sku and school_id. It needs to reference both to return a unique product with unique stock levels etc. When I execute the following query it returns one row, I am expecting 3 rows. I have tried breaking the inner join into two separate joins but this still returns only 1 result. joining only on one key has the desired result, but may be retuning the wrong product. A left join returns 3 rows but some data is missing product specific Here is a simplified example of what I am doing SELECT sb_carts.product_sku FROM sb_carts INNER JOIN sb_products ON sb_products.sku = sb_carts.product_sku AND sb_products.school_id = sb_carts.school_id WHERE sb_carts.order_id = 0 AND sb_carts.user_id = 2 GROUP BY sb_carts.cart_id

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  • MySQL Dynamicly determine the tabel to use with inner join

    - by user366990
    He guys, I'm stuck with a problem and I hope someone can help me out. I have a date. For example 2009-10-1. This date is used to check in which season I am working. This could be summer or winter. If whe are in the summer the table to use for my inner join whould be 'summer09_rooms'. If winter 'winter09_rooms'. So I basicly whant to do a CASE WHEN in my INNER JOIN. How to accomplish this. The query would look like this: SELECT name, arrival_date, departure_date FROM holliday a INNER JOIN ( CASE when arrival_date BETWEEN 2009-10-1 AND 2009-4-1 THEN summer09_rooms b ELSE winter09_rooms b END ) ON a.dossier=b.dossier Of course this query isn't working but now I hope you'l see what I want to accomplish. Kind regards, Digital Human

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  • PHP, MySQL, jQuery, AJAX: json data returns correct response but frontend returns error

    - by Devner
    Hi all, I have a user registration form. I am doing server side validation on the fly via AJAX. The quick summary of my problem is that upon validating 2 fields, I get error for the second field validation. If I comment first field, then the 2nd field does not show any error. It has this weird behavior. More details below: The HTML, JS and Php code are below: HTML FORM: <form id="SignupForm" action=""> <fieldset> <legend>Free Signup</legend> <label for="username">Username</label> <input name="username" type="text" id="username" /><span id="status_username"></span><br /> <label for="email">Email</label> <input name="email" type="text" id="email" /><span id="status_email"></span><br /> <label for="confirm_email">Confirm Email</label> <input name="confirm_email" type="text" id="confirm_email" /><span id="status_confirm_email"></span><br /> </fieldset> <p> <input id="sbt" type="button" value="Submit form" /> </p> </form> JS: <script type="text/javascript"> $(document).ready(function() { $("#email").blur(function() { var email = $("#email").val(); var msgbox2 = $("#status_email"); if(email.length > 3) { $.ajax({ type: 'POST', url: 'check_ajax2.php', data: "email="+ email, dataType: 'json', cache: false, success: function(data) { if(data.success == 'y') { alert('Available'); } else { alert('Not Available'); } } }); } return false; }); $("#confirm_email").blur(function() { var confirm_email = $("#confirm_email").val(); var email = $("#email").val(); var msgbox3 = $("#status_confirm_email"); if(confirm_email.length > 3) { $.ajax({ type: 'POST', url: 'check_ajax2.php', data: 'confirm_email='+ confirm_email + '&email=' + email, dataType: 'json', cache: false, success: function(data) { if(data.success == 'y') { alert('Available'); } else { alert('Not Available'); } } , error: function (data) { alert('Some error'); } }); } return false; }); }); </script> PHP code: <?php //check_ajax2.php if(isset($_POST['email'])) { $email = $_POST['email']; $res = mysql_query("SELECT uid FROM members WHERE email = '$email' "); $i_exists = mysql_num_rows($res); if( 0 == $i_exists ) { $success = 'y'; $msg_email = 'Email available'; } else { $success = 'n'; $msg_email = 'Email is already in use.</font>'; } print json_encode(array('success' => $success, 'msg_email' => $msg_email)); } if(isset($_POST['confirm_email'])) { $confirm_email = $_POST['confirm_email']; $email = ( isset($_POST['email']) && trim($_POST['email']) != '' ? $_POST['email'] : '' ); $res = mysql_query("SELECT uid FROM members WHERE email = '$confirm_email' "); $i_exists = mysql_num_rows($res); if( 0 == $i_exists ) { if( isset($email) && isset($confirm_email) && $email == $confirm_email ) { $success = 'y'; $msg_confirm_email = 'Email available and match'; } else { $success = 'n'; $msg_confirm_email = 'Email and Confirm Email do NOT match.'; } } else { $success = 'n'; $msg_confirm_email = 'Email already exists.'; } print json_encode(array('success' => $success, 'msg_confirm_email' => $msg_confirm_email)); } ?> THE PROBLEM: As long as I am validating the $_POST['email'] as well as $_POST['confirm_email'] in the check_ajax2.php file, the validation for confirm_email field always returns an error. With my limited knowledge of Firebug, however, I did find out that the following were the responses when I entered email and confirm_email in the fields: RESPONSE 1: {"success":"y","msg_email":"Email available"} RESPONSE 2: {"success":"y","msg_email":"Email available"}{"success":"n","msg_confirm_email":"Email and Confirm Email do NOT match."} Although the RESPONSE 2 shows that we are receiving the correct message via msg_confirm_email, in the front end, the alert 'Some error' is popping up (I have enabled the alert for debugging). I have spent 48 hours trying to change every part of the code wherever possible, but with only little success. What is weird about this is that if I comment the validation for $_POST['email'] field completely, then the validation for $_POST['confirm_email'] field is displaying correctly without any errors. If I enable it back, it is validating email field correctly, but when it reaches the point of validating confirm_email field, it is again showing me the error. I have also tried renaming success variable in check_ajax2.php page to other different names for both $_POST['email'] and $_POST['confirm_email'] but no success. I will be adding more fields in the form and validating within the check_ajax2.php page. So I am not planning on using different ajax pages for validating each of those fields (and I don't think it's smart to do it that way). I am not a jquery or AJAX guru, so all help in resolving this issue is highly appreciated. Thank you in advance.

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  • PHP MySQL INSERT fails due to unique constraint

    - by sjw
    On insert I am catching the unique constraint mysql_errno() 1062. This works fine but I want to find the existing row to re-instate or modify it. Is there are method to obtain the row id on insert fail? I tried mysql_insert_id() but realised that would only return the row I'm inserting (or failed to insert) therefore, I get 0. Is there no option but to issue another mysql_query and simply perform a select on the duplicate value? I just want to make sure there is no better, quicker, more economical way to do this.

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  • Retrieve part of a MySQL column with PHP

    - by Gerardo Marset
    For instance, if I have the following table: +----+---+----------+ | id | a | position | +----+---+----------+ | 0 | 0 | 0 | | 1 | 0 | 1 | | 2 | 1 | 4 | | 3 | 1 | 9 | | 4 | 1 | 6 | | 5 | 1 | 1 | +----+---+----------+ and I want to get an array that contains the first 100 values from position where a is 1 in ascending order, what would I do? Im guessing something like this: $col = mysql_fetch_array( mysql_query(' SELECT `position` FROM `table` WHERE `a`="1" ORDER BY `position` ASC LIMIT 100 ')); I'd expect to get the following array: +-------+-------+ | index | value | +-------+-------+ | 0 | 1 | | 1 | 4 | | 2 | 6 | | 3 | 9 | +-------+-------+ but it doesn't work. ¿What should I do to make it work? Thanks

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  • Single Large v/s Multiple Small MySQL tables for storing Options

    - by Prasad
    Hi there, I'm aware of several question on this forum relating to this. But I'm not talking about splitting tables for the same entity (like user for example) Suppose I have a huge options table that stores list options like Gender, Marital Status, and many more domain specific groups with same structure. I plan to capture in a OPTIONS table. Another simple option is to have the field set as ENUM, but there are disadvantages of that as well. http://www.brandonsavage.net/why-you-should-replace-enum-with-something-else/ OPTIONS Table: option_id <will be referred instead of the name> name value group Query: select .. from options where group = '15' - Since this table is expected to be multi-tenant, the no of rows could grow drastically. - I believe splitting the tables instead of finding by the group would be easier to write & faster to execute. - or perhaps partitioning by the group or tenant? Pl suggest. Thanks

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  • MySQL GROUP_CONCAT + IN() = missing data :-(

    - by Andrew Heath
    Example: Table: box boxID color 01 red 02 blue 03 green Table: boxHas boxID has 01 apple 01 pear 01 grapes 01 banana 02 lime 02 apple 02 pear 03 chihuahua 03 nachos 03 baby crocodile I want to query on the contents of each box, and return a table with each ID, color, and a column that concatenates the contents of each box, so I use: SELECT box.boxID, box.color, GROUP_CONCAT(DISTINCT boxHas.has SEPARATOR ", ") AS contents FROM box LEFT JOIN boxHas ON box.boxID=boxHas.boxID WHERE boxHas.has IN ('apple','pear') GROUP BY box.boxID ORDER BY box.boxID and I get the following table of results: boxID color contents 01 red apple, pear 02 blue apple, pear My question to you is: why isn't it listing ALL the has values in the contents column? Why is my WHERE statement also cropping my GROUP_CONCAT? The table I thought I was going to get is: boxID color contents 01 red apple, banana, grapes, pear 02 blue apple, lime, pear Although I want to limit my boxID results based upon the WHERE statement, I do not want to limit the contents field for valid boxes. :-/ Help?

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  • get value from MySQL database with PHP

    - by Hristo
    $from = $_POST['from']; $to = $_POST['to']; $message = $_POST['message']; $query = "SELECT * FROM Users WHERE `user_name` = '$from' LIMIT 1"; $result = mysql_query($query); while($row = mysql_fetch_array($result, MYSQL_ASSOC)) { $fromID = $row['user_id']; } I'm trying to have $formID be the user_id for a user in my database. Each row in the Users table is like: user_id | user_name | user_type 1 | Hristo | Agent So I want $from = 1 but the above code isn't working. Any ideas why?

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