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• Rake migration aborted

  - by user2537714

  I'm running Ruby 2.0.0 and I installed it correctly. Just loaded up a gem 'devise' and as I tried to migrate my database changes, it wouldn't work: $ rake db:migrate rake aborted! attr_accessible is extracted out of Rails into a gem. Please use new recommended protection model for params(strong_parameters) or add protected_attributes to your Gemfile to use old one. Then, following another Stackoverflow post, they recommended installing Bundler. I did that successfully and got this: $ bundle exec rake db:migrate rake aborted! attr_accessible is extracted out of Rails into a gem. Please use new recommended protection model for params(strong_parameters) or add protected_attributes to your Gemfile to use old one. Is anyone up to the challenge to help?

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• How to Execute an Oracle SQL Statements with VBScript

  - by Arno Conradie

  I am trying to execute an Oracle SQL statement or Oracle Functions through Microsoft VBScript and the loop throught the result set or display the value returned by the function So far I have managed to connect to Oracle via SQLPlus*, but now I am stuck. Can anybody help? Dim output Dim WshShell, oExec, input set WshShell = CreateObject("WScript.Shell") set oEnv=WshShell.Environment("Process") cmdString = "C:\Oracle\11g\product\11.1.0\ruby\BIN\sqlplus.exe -S stradmin/stradmin@ruby select * from dual" Set oExec = WshShell.Exec(cmdString) WScript.Echo "Status" & oExec.Status Do While oExec.Status = 0 WScript.Sleep 2 Loop input = "" Do While Not oExec.StdOut.AtEndOfStream input = input & oExec.StdOut.Read(1) Loop wscript.echo input

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• IntelliSense: expression must have integral or enum type

  - by user1743737

  Guys i need someone fix this problem ? when i compile that code i have this error: Error: IntelliSense: expression must have integral or enum type i have problem in this part: Console(0, V("seta sv_hostname " + servername + ";\n")); so how i can fix that if (strncmp(command, V("exec config_mp"), 14) == 0) { if (GAME_MODE == 'D') { CIniReader iniReader(V(".\\teknogods.ini")); char *servername = iniReader.ReadString(V("Settings"),V("Servername"),""); if (strcmp(servername,"") == 0) { info("Server name set to defult."); } else { //Console(0, V("seta scr_teambalance 1;\n")); Console(0, V("seta sv_hostname " + servername + ";\n")); info("server name set to: %s.", servername); } } }

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• Can a Windows batch file call another program without waiting for that program to finish?

  - by iconoclast

  I'm using Windows 7, and have a simple batch file to copy portable executables off my thumb drive to %TEMP%, and then start them. The goal is to prevent Windows from holding my thumbdrive hostage until I kill all the programs I started up from it. However the control flow does not continue to the next app unless I kill the first one, which obviously doesn't work for this purpose. In a Unix shell script I'd simply add & after the executable I start up, but I can't find an equivalent for batch files. How can I do this?

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• Map keycode 133+54 to shift+control+c in Linux for Mac keyboard?

  - by Edward_178118

  On Linux Mint 13 - Mate using the Terminal program Terminator with a Mac keyboard. I want the command key for COPY/PASTE to behave as it does on the Mac. I have been able to change it to treat the command key as a control key, and this works fine for most apps except in the Terminal program. Using xev when I press command+c it's a keycode of 133 + 54. This is a ^c to the Terminal app which acts like a ^c in a shell. The default for COPY which can be changed in Terminator is Shift+Control+c. Is there a way to map the keycode of 133 + 54 to Shift+Control+c, but only for the Terminator app? Thanks!

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• can not access dlink 604 set up interface

  - by user36089

  Hello everyone I used dlink-di604 enthernet board as router to share web access. My ISP provides the service base on Ethernet rathern than base on Ethernet pppoe mode. It is manually setup ipv4, subnet mask , DNS, Gateway etc Log in using web user name&password. I use http://192.168.0.2 try to access dlink di604 setup inferface, but failed I call command ipconfig /all Dos shell displayed: Ethernet adapter Local Connection: Physical Address: 00-3c-56-79-19-49 IPv4 address:10.7.8.225 subnet mask: 255.255.255.0 default gate way: 10.7.8.1 DNS servers 10.10.10.10 What is the correct way to access dlink 604 setup interface and set to share web access? Welcome any comment Thanks interdev

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• how to setup a ssh acount with no terminal but port forwarding?

  - by admalledd

  I am trying to set up a new user account I can give to friends so they can SSH into my forward computer, and only allow forwarding of certain ports. I do not want my friends to have a shell, or be able to change what ports to where they are allowed to forward. example session: joe(friend) connects using PuTTY (that I have pre-set, he isn't good with computers) to example.com(my Internet facing computer) forwarding ports 8080,1990,25565 to him(with what ever end ports he wants, preferably they stay the same numbers) example ssh command to do similar (but he can still change the ports on my computer!) ssh -N [email protected] -p443 -L8080:192.168.1.2:8080 -L1990:127.0.0.1:1990 -L25565:127.0.0.1:25565 then, same story with other friend smith(same ports, same user even) except he is using linux, so cant use putty. is it possible to also leave default SSH functinality for all other users but this one? I found this when I was searching google, but alas, I did not quite understand what was being suggested, and I don't think they covered restricting port forwarding

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• Cannot use `su` or `sudo` after set up key-based access to SSH

  - by OrangeTux

  I'm following this tuturial to setup key-based access to the SSH I created a user. I add copy the key to the client via ssh-copy-id <username>@<host> Becasuse ssh <username>@<host> still prompts for a password I run ssh-add on the local machine. The terminal doens't prompt for a password, I can login without using a password. But I cannot run su anymore. Every input for the password results in Authentication failure. I tried it again. But before coping the key, I added to the sudoer file. Copied key, ssh-add. But now I cannot login to my SSH shell att all? How can I setup a key-based SSH access with the possibiluty to use su or sudo?

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• How do I securely share my server?

  - by Blue

  I have a large dedicated server running Debian and I want to share it with about 6 friends of mine. I know I can simply just use adduser to create user accounts for them, but I want to know if they can, even as a regular user without root permissions, do anything malicious. I know by default they have read permissions for other users in the /home, and can solve that with chmod, but I just want to make sure that there's nothing else they can do. And also, is there any kind of script or program that makes it easier to create and manage shell users on a server?

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• Cannot start jboss remotely in ruby (Net::SSH)

  - by Jared

  I am trying to start/stop jboss remotely with ruby Net::SSH library. I am able to stop jboss with the following code: require 'net/ssh' Net::SSH.start('xx.xx.xx.xx', 'jboss', :password => "jboss") do |session| session.open_channel do |channel| channel.request_pty(:term => 'xterm') do |ch, success| raise "could not request pty!" unless success channel.exec "/etc/init.d/jboss_new stop\n" end puts "shell opened" channel.on_data do |channel, data| puts data sleep 1 if data =~ /Password: / sleep 2 channel.send_data("jboss\n") end end end end But when I substitute stop with start I get nothing in return, jboss is not started. I changed password to invalid and get a response su: Authentication failure Is there any gimmick here? Can you please advise what is wrong?

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• Replace single character in windows filenames

  - by Matt Rogish

  I have a Win2k3 server that has a whole bunch of filenames that need renamed. Basically, I just need all - (dashes) replaced with _ (underscores), no matter where they are in the string. Assume that there are no duplicates. I can do this on my mac with a little script but the files are too large and crazy to transfer to my mac, rename, then go back to the server. Would love to do this in a command shell and not have to download a renamer or any add'l software. Thanks!

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• How can I display host name on windows desktop

  - by Martin

  I do a lot of work on Windows Server 2008 remote desktops and often lose track of which host I am currently logged on to. Is there a way of displaying (without installing any non-standard apps) the host name or IP address of the host I am connected to in either the wallpaper or the notification area? I tried creating files in the desktop with the name of the machine - but my roaming profile shows the same set of desktop files on every machine, so that was scuppered. Duh! In shell windows this is easy: just set the prompt to display the host name. Surely there is a simple way of doing the same for the graphical desktop.

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• Can't get ZSH working on CentOS

  - by waveslider

  I've been using zsh for a couple of years now on Ubuntu and really like it a lot. I've installed it on our production server as well, which is running CentOS 5.2 However, I just installed it via yum on a new VM I created to use as a development box, to replicate our production box as closely as possible. Although yum shows that it is definitely installed (/bin/zsh) and that it is set as my shell, it does not appear to be working. Instead of creating the .zshrc and .profile files in my home directory, it created a .tcshrc file. Also, I did not receive the default configuration menu that is always displayed once you begin using ZSH, and none of the features (like advanced tab comple

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• Looking for a way execute a task on all files in a directory (recursively) on Windows

  - by stzzz1

  I have a huge number of mp4 video files that needs to have a volume boost. I need a way to execute a ffmpeg audio filter on all files in a specified base directory (and in subdirectories as well). My problem is that I'm working on a Windows computer and I have no knowledge of its shell syntax. I would like to do the equivalent of what this bash script does : TARGET_FILES=$(find /path/to/dir -type f -name *.mp4) for f in $TARGET_FILES do ffmpeg -i $f -af 'volume=4.0' output.$f done I spent quite some time this afternoon looking for a solution but the recursive nature of what I need (that is so simple with find!) isn't too clear. Any help would be greatly appreciated!

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• Avoiding jagged text when pasting into vi?

  - by overtherainbow

  Hello Although I have no problem using SecureCRT (5.1.2 build 274) to work from Windows and connect to PC's running Linux, I have a problem when connecting to an embedded Asterisk appliance that provides"vi" through BusyBox 1.4.1 (2008-03-10). The issue I'm having, is that when I paste code into vi, the text appears jagged like this: <?php try { $dbh = new PDO("sqlite:./db.sqlite"); $dbh->exec("CREATE TABLE IF NOT EXISTS customer (id INTEGER PRIMARY KEY AUTOINCREMENT, name VARCHAR(255))"); Does someone what the problem is? Is there a way to reconfigure either BusyBox or SecureCRT so that I can paste successfully? Thank you.

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• How can I change standart input/output of another program?

  - by Azad Salahli

  I have a console application written in c++. It simply reads an integer from standard input(keyboard) and writes another integer to standard output(screen). Now I want to give some tests to that program and check its answers using another program. In another words, I want to write electron judge for that program. I want that program(which I want to test) to read from file and write to file without changing source code. How can I do that. I tried assigning input&output to files before executing c++ program, but it did not worked. assign(input,'temp.in'); reset(input); assign(output,'temp.out'); rewrite(output); exec('domino.exe'); close(input); close(output);

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• Dynamic order by without using dynamic sql ?

  - by Rohit

  I have the following stored procedure which can be sorted ascending and descending on TemplateName,CreatedOn and UploadedBy. The following SP when runs doesnot sort records.if i replace 2,3,4 by columnname, i got an error message "Conversion failed when converting the nvarchar value 'Test Template' to data type int.".Please suggest how to achieve sorting. CREATE PROCEDURE [dbo].[usp_SEL_GetRenderingTemplate] ( @facilityID INT, @sortOrder VARCHAR(5), @sortExpression VARCHAR(100), @errorCode INT OUTPUT ) AS BEGIN SET NOCOUNT ON ; BEGIN TRY SET @sortOrder = CASE @sortOrder WHEN 'Ascending' THEN 'ASC' WHEN 'Descending' THEN 'DESC' ELSE 'ASC' END SELECT TemplateID, TemplateName, CreatedOn, ( [user].LastName + ' ' + [user].FirstName ) AS UploadedBy FROM Templates INNER JOIN [user] ON [user].UserID = Templates.CreatedBy WHERE facilityid = @facilityID ORDER BY CASE WHEN @sortExpression = 'TemplateName' AND @sortOrder = 'ASC' THEN 2 WHEN @sortExpression = 'CreatedOn' AND @sortOrder = 'ASC' THEN 3 WHEN @sortExpression = 'UploadedBy' AND @sortOrder = 'ASC' THEN 4 END ASC, CASE WHEN @sortExpression = 'TemplateName' AND @sortOrder = 'DESC' THEN 2 WHEN @sortExpression = 'CreatedOn' AND @sortOrder = 'DESC' THEN 3 WHEN @sortExpression = 'UploadedBy' AND @sortOrder = 'DESC' THEN 4 END DESC SET @errorCode = 0 END TRY BEGIN CATCH SET @errorCode = -1 DECLARE @errorMsg AS VARCHAR(MAX) DECLARE @utcDate AS DATETIME SET @errorMsg = CAST(ERROR_MESSAGE() AS VARCHAR(MAX)) SET @utcDate = CAST(GETUTCDATE() AS DATETIME) EXEC usp_INS_LogException 'usp_SEL_GetFacilityWorkTypeList', @errorMsg, @utcDate END CATCH END

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• SSH disconnects active session after 20 minutes

  - by Paramaeleon

  I’ve just set up a new Linux box (OpenSuSE 12.3 on VmWare). Now I stated that my SSH shell sessions are disconnected exactly after 20 minutes, clearly with activity. (Putty: “Network error: Software caused connection abort”) I already set Putty to send keep alives every 64 sec. In sshd_config, I set ClientAliveInterval 50 ClientAliveCountMax 2 and did a deamon reload. Didn’t help. About two minutes after the link breakdown, ssh reports to /var/log/messages: … … sshd[…]: Timeout, client not responding. … … sshd[…]: pam_unix(sshd:session): session closed for user root I don’t encounter this behaviour when connecting to other virtual machines, so I guess the problem isn’t in the network. Any help is appreciated.

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• scp using a password on the command line

  - by spierepf

  I am trying to write a script that will deploy a build created on my desktop machine (windows/cygwin) to a machine in my test environment (linux). I would like to use scp to copy the build to the target machine. The only account on the target machine is root, and I cannot create a special user for this task. The root user is unable to log in using an ssh key (I suspect that this is configured on the ssh server, but I do not know which configuration options control this). At any rate, I cannot change the configuration of the ssh server. My desktop machine uses Cygwin, and I have ssh installed. What I need is the command-line-fu that will allow me to put the password on the command line. I am aware of the dangers of having a plaintext password in a shell script, but that is not a concern here.

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• Ruby w/ Postgres & Sinatra - Query won't order right with parameter??

  - by alleywayjack

  So I set a variable in my main ruby file that's handling all my post and get requests and then use ERB templates to actually show the pages. I pass the database handler itself into the erb templates, and then run a query in the template to get all (for this example) grants. In my main ruby file: grants_main_order = "id_num" get '/grants' do erb :grants, :locals => {:db=>db, :order=>grants_main_order, :message=>params[:message]} end In the erb template: db = locals[:db] getGrants = db.exec("SELECT * FROM grants ORDER BY $1", [locals[:order]]) This produces some very random ordering, however if I replace the $1 with id_num, it works as it should. Is this a typing issue? How can I fix this? Using string replacement with #{locals[:order]} also gives funky results.

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• Write to pipe deadlocking program

  - by avs3323

  Hi, I am having a problem in my program that uses pipes. What I am doing is using pipes along with fork/exec to send data to another process What I have is something like this: //pipes are created up here if(fork() == 0) //child process { ... execlp(...); } else { ... fprintf(stderr, "Writing to pipe now\n"); write(pipe, buffer, BUFFER_SIZE); fprintf(stderr, "Wrote to pipe!"); ... } This works fine for most messages, but when the message is very large, the write into the pipe deadlocks. I think the pipe might be full, but I do not know how to clear it. I tried using fsync but that didn't work. Can anyone help me?

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• DD-WRT with both https and sshd running in port 443

  - by Bruno

  I have a buffalo router with dd-wrt v24 SP2. After setting up the basic stuff, I enabled the https access to the admin page. Several days later, while setting up remote ssh, I changed the default port from 22 to 443. And now..well :) You got the picture :) I can ssh the router but I have no web access to it's admin page. Before rushing to a cold-hearted configuration reset, is there any way to change the ssh port from a shell? Or make dd-wrt accessible thru basic http?

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• Apache 2 Symbolic link not allowed or link target not accessible

  - by astropanic

  My apache server runs as user foo. I have some Rails applications in /home/foo/app1 /home/foo/app2. Each of them has an vhost <VirtualHost *:80> ServerName app1.foobar.com ServerAlias www.app1.foobar.com DocumentRoot /var/www/html/app1/current/public RailsEnv production <Directory /var/www/html/app1/current/public> AllowOverride all Options -MultiViews </Directory> </VirtualHost> I have a symlink in /var/www/html/app1 : current -> /home/foo/app1/tmp_20102611 All file permissons are set correctly (user foo group foo), I can go through the filesystem from shell. SELINUX is disabled Distro is CentOs 5.5 Which the above symlink I get an 403 and an error entry in error_log Symbolic link not allowed or link target not accessible:/var/www/html/app1/current When I symlink my app in the subdir of /var/www/html instead of /home/foo it works. How I can avoid this error still placing my app in my /home/foo directory ?

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• how to google a symbol keyword like "$?"

  - by ZhengZhiren

  i saw a trick in a book: in a linux shell, we can use &? to get the return value of a command. For example,we run a command,if it exit normally, the return value is 0. And then we type $?,we will get 0 in the screen. i want to google this kind of usage, so i have to type these two symbol $? in the search blank.But the search engine just return nothing to me... i have looked at the google help page, but still can't find a solution. so my question is: how can i search with this kind of keyword. or if you can give me some advise of the usage of $? or sort of thing, that will be also appreciated.

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• Mongo Client RedHat EL5 UT8 Support

  - by Michael Irey

  # mongo MongoDB shell version: 1.6.4 Fri Mar 16 11:55:46 *** warning: spider monkey build without utf8 support. consider rebuilding with utf8 support connecting to: test Mongo Server seems to handle the utf8 characters fine, as well as my php-mongo-client driver. But when I try to query a record that has a utf8 character from the mongo command line client I get: > db.Users.find({age:33}); error:non ascii character detected Fri Mar 16 11:55:43 mongo got signal 11 (Segmentation fault), stack trace: Fri Mar 16 11:55:43 0x440b50 0x3664c302d0 0x3f47e7b6e0 0x3f47e83bbd 0x3f47e254f3 0x3f47e25660 0x3f47e256ee 0x3f47e25792 0x3f47e2876e 0x4b031d 0x443b72 0x445476 0x3664c1d994 0x43fd39 mongo(_Z12quitAbruptlyi+0x3b0) [0x440b50] /lib64/libc.so.6 [0x3664c302d0] /usr/lib64/libjs.so.1 [0x3f47e7b6e0] /usr/lib64/libjs.so.1(js_CompileTokenStream+0x3d) [0x3f47e83bbd] /usr/lib64/libjs.so.1 [0x3f47e254f3] /usr/lib64/libjs.so.1(JS_CompileUCScriptForPrincipals+0x60) [0x3f47e25660] /usr/lib64/libjs.so.1(JS_EvaluateUCScriptForPrincipals+0x3e) [0x3f47e256ee] /usr/lib64/libjs.so.1(JS_EvaluateUCScript+0x22) [0x3f47e25792] /usr/lib64/libjs.so.1(JS_EvaluateScript+0x6e) [0x3f47e2876e] mongo(_ZN5mongo7SMScope4execERKSsS2_bbbi+0xed) [0x4b031d] mongo(_Z5_mainiPPc+0x14a2) [0x443b72] mongo(main+0x26) [0x445476] /lib64/libc.so.6(__libc_start_main+0xf4) [0x3664c1d994] mongo(__gxx_personality_v0+0x269) [0x43fd39] Any ideas or suggestions would be welcome

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