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  • ATI Proprietary Driver Over/Underscan setting ignored after reboot

    - by Lassi
    I installed the proprietary driver (fglrx-updates) on Ubuntu 12.10 64-bit for my graphics card (ATI Radeon HD 7570). I am using two displays, one connected with DVI, one with HDMI. I set the desktop to be expanded to both screens and disabled the under scan for the HDMI screen, which is always for some reason enabled on HDMI screens. Now the issue. Everything was fine until I restarted my computer. After reboot, the screen connected with HDMI cable had the black borders again, meaning that the under scan is again enabled. I checked the ATI CCC, and under scan was disabled. However, moving the slider to enable under scan and then back to zero fixed the issue -- temporarily. The same issue is repeated every time I restart my computer. The settings remains the same, but the computer seems to ignore it. Any ideas how I could solve the issue?

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  • Graphical net and text

    - by chesheerkys
    Hello! My task is to make a control, that behaves itself like RichTextBox, but contains a graphical net. The only task, this net is solving, is to be visible. It should be solution in overriding OnPaint method, but it doesn't. This code: protected override void OnPaint(System.Windows.Forms.PaintEventArgs e) { base.OnPaint(e); ...//drawing a line } gives me RichTextBox without of text This code: protected override void WndProc(ref System.Windows.Forms.Message m) { base.WndProc(ref m); if (m.Msg == 15) { Graphics g = this.CreateGraphics(); g.DrawLine(new Pen(Color.White, 1), new Point(0, 0), new Point(400, 400)); } } sometimes draws extra lines Actually since these two ways don't work, I don't know what to try. Waiting for your advices :) BR Dmitry P.S. I’ve heard a lot about great opportunities of WPF, but I’m not really common with this technology and don’t know what to start with. P.P.S. Sorry for my English, it’s not my natural language.

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  • tail stops displaying in case of a log rotation

    - by Rudy Vissers
    I have to tail the log of a server (servicemix) and the log rotation is enabled. As soon as the rotation happens, tail stops displaying. I did some investigations and it is a bug in Debian : Debian Bug Report. The bug has been around for a long time ago. Does anyone knows if this bug in Ubuntu is to be fixed? I'm on Ubuntu 12.04 64 bit. I don't have to mention that this bug is total hell! Every time I have the problem, I have to interrupt the command tail and re-execute the command!

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  • android custom map marker bounds

    - by max4ever
    Hello i am using a resized version of this marker( http://www.clker.com/clipart-orange-pin-4.html ) for showing markers in google maps on android. The problem is i don't know how to make the marker point match the coordinates. The arrow point is at about 1/5 of the Width coordinates and MAX of the Height. here is my class public class GestionaleItemizedOverlay extends com.google.android.maps.ItemizedOverlay { public GestionaleItemizedOverlay(Drawable defaultMarker, Context context) { //super(boundCenterBottom(defaultMarker)); super(boundCenter(defaultMarker)); this.mContext = context; } ... And this this.marker_poi = this.getContext().getResources().getDrawable(R.drawable.marker); this.marker_poi.setBounds(this.marker_poi.getIntrinsicWidth() / 2, this.marker_poi.getIntrinsicHeight(), this.marker_poi.getIntrinsicWidth() / 2, 0); new GestionaleItemizedOverlay(this.poi, this.context); Do i need to setBounds on the marker before passing it to the constructor? and why does super(defaultMarker) makes all the markers not to show ?

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  • Charles Barkley syndrome

    - by dacracot
    Charles Barkley was an excellent basketball player, a hall of fame, and a dream team member. He played for the 76ers, Suns, and Rockets. Yet he never won an NBA championship. Some might argue this was because he was never surrounded by other players of his caliber, and in the NBA, you can't win on your own. So what does this have to do with programming? How many of you out there feel like Sir Charles? Leading your team in every category, KLOCs, bugs fixed, systems configured... Always the one pushing for improvements, upgrading systems, negotiating with customers... Feeling like you are carrying the team. Anger just under the surface. Only to retire eventually, without "the ring"1. 1: Keep in mind, Charles never blamed his team. He just performed at his best.

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  • core data editor problems

    - by Peyman
    I was recommended by someone in Stack Overflow to use Core Data Editor http://christian-kienle.de/CoreDataEditor/ to manage the sqlite persistent store. However the latest version (3.0) crashes on launch everytime. Older versions load but I see nothing when i point the config to the persistent store and the object model directories. There is no documentation either. can someone point me to the right place to sort this problem? I am trying to find a more manageable way to coordinate core data development than sqlite consoles. thank you

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  • which euler rotations can i use ?

    - by melis
    i have two cartesian coordinates. There are xyz and BIG XYZ. I want to make these are paralel each other.forexample , x paralel to X ,y paralel to Y and z paralel to Z. I use rotation matris but I have a lot of different rotation matris . for example I have 3D point in xyz cartesien coordinates and its called A. and I want to change cartesien coordinate to BIG XYZ and find the same 3D point in this coordinates its called B.Until now it is okay. But when I used different rotational matris , points were changed.what can I do? Which Euler rotations can i use?

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  • Slowdowns when reading from an urlconnection's inputstream (even with byte[] and buffers)

    - by user342677
    Ok so after spending two days trying to figure out the problem, and reading about dizillion articles, i finally decided to man up and ask to for some advice(my first time here). Now to the issue at hand - I am writing a program which will parse api data from a game, namely battle logs. There will be A LOT of entries in the database(20+ million) and so the parsing speed for each battle log page matters quite a bit. The pages to be parsed look like this: http://api.erepublik.com/v1/feeds/battle_logs/10000/0. (see source code if using chrome, it doesnt display the page right). It has 1000 hit entries, followed by a little battle info(lastpage will have <1000 obviously). On average, a page contains 175000 characters, UTF-8 encoding, xml format(v 1.0). Program will run locally on a good PC, memory is virtually unlimited(so that creating byte[250000] is quite ok). The format never changes, which is quite convenient. Now, I started off as usual: //global vars,class declaration skipped public WebObject(String url_string, int connection_timeout, int read_timeout, boolean redirects_allowed, String user_agent) throws java.net.MalformedURLException, java.io.IOException { // Open a URL connection java.net.URL url = new java.net.URL(url_string); java.net.URLConnection uconn = url.openConnection(); if (!(uconn instanceof java.net.HttpURLConnection)) { throw new java.lang.IllegalArgumentException("URL protocol must be HTTP"); } conn = (java.net.HttpURLConnection) uconn; conn.setConnectTimeout(connection_timeout); conn.setReadTimeout(read_timeout); conn.setInstanceFollowRedirects(redirects_allowed); conn.setRequestProperty("User-agent", user_agent); } public void executeConnection() throws IOException { try { is = conn.getInputStream(); //global var l = conn.getContentLength(); //global var } catch (Exception e) { //handling code skipped } } //getContentStream and getLength methods which just return'is' and 'l' are skipped Here is where the fun part began. I ran some profiling (using System.currentTimeMillis()) to find out what takes long ,and what doesnt. The call to this method takes only 200ms on avg public InputStream getWebPageAsStream(int battle_id, int page) throws Exception { String url = "http://api.erepublik.com/v1/feeds/battle_logs/" + battle_id + "/" + page; WebObject wobj = new WebObject(url, 10000, 10000, true, "Mozilla/5.0 " + "(Windows; U; Windows NT 5.1; en-US; rv:1.9.2.3) Gecko/20100401 Firefox/3.6.3 ( .NET CLR 3.5.30729)"); wobj.executeConnection(); l = wobj.getContentLength(); // global variable return wobj.getContentStream(); //returns 'is' stream } 200ms is quite expected from a network operation, and i am fine with it. BUT when i parse the inputStream in any way(read it into string/use java XML parser/read it into another ByteArrayStream) the process takes over 1000ms! for example, this code takes 1000ms IF i pass the stream i got('is') above from getContentStream() directly to this method: public static Document convertToXML(InputStream is) throws ParserConfigurationException, IOException, SAXException { DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); DocumentBuilder db = dbf.newDocumentBuilder(); Document doc = db.parse(is); doc.getDocumentElement().normalize(); return doc; } this code too, takes around 920ms IF the initial InputStream 'is' is passed in(dont read into the code itself - it just extracts the data i need by directly counting the characters, which can be done thanks to the rigid api feed format): public static parsedBattlePage convertBattleToXMLWithoutDOM(InputStream is) throws IOException { // Point A BufferedReader br = new BufferedReader(new InputStreamReader(is)); LinkedList ll = new LinkedList(); String str = br.readLine(); while (str != null) { ll.add(str); str = br.readLine(); } if (((String) ll.get(1)).indexOf("error") != -1) { return new parsedBattlePage(null, null, true, -1); } //Point B Iterator it = ll.iterator(); it.next(); it.next(); it.next(); it.next(); String[][] hits_arr = new String[1000][4]; String t_str = (String) it.next(); String tmp = null; int j = 0; for (int i = 0; t_str.indexOf("time") != -1; i++) { hits_arr[i][0] = t_str.substring(12, t_str.length() - 11); tmp = (String) it.next(); hits_arr[i][1] = tmp.substring(14, tmp.length() - 9); tmp = (String) it.next(); hits_arr[i][2] = tmp.substring(15, tmp.length() - 10); tmp = (String) it.next(); hits_arr[i][3] = tmp.substring(18, tmp.length() - 13); it.next(); it.next(); t_str = (String) it.next(); j++; } String[] b_info_arr = new String[9]; int[] space_nums = {13, 10, 13, 11, 11, 12, 5, 10, 13}; for (int i = 0; i < space_nums.length; i++) { tmp = (String) it.next(); b_info_arr[i] = tmp.substring(space_nums[i] + 4, tmp.length() - space_nums[i] - 1); } //Point C return new parsedBattlePage(hits_arr, b_info_arr, false, j); } I have tried replacing the default BufferedReader with BufferedReader br = new BufferedReader(new InputStreamReader(is), 250000); This didnt change much. My second try was to replace the code between A and B with: Iterator it = IOUtils.lineIterator(is, "UTF-8"); Same result, except this time A-B was 0ms, and B-C was 1000ms, so then every call to it.next() must have been consuming some significant time.(IOUtils is from apache-commons-io library). And here is the culprit - the time taken to parse the stream to string, be it by an iterator or BufferedReader in ALL cases was about 1000ms, while the rest of the code took 0ms(e.g. irrelevant). This means that parsing the stream to LinkedList, or iterating over it, for some reason was eating up a lot of my system resources. question was - why? Is it just the way java is made...no...thats just stupid, so I did another experiment. In my main method I added after the getWebPageAsStream(): //Point A ba = new byte[l]; // 'l' comes from wobj.getContentLength above bytesRead = is.read(ba); //'is' is our URLConnection original InputStream offset = bytesRead; while (bytesRead != -1) { bytesRead = is.read(ba, offset - 1, l - offset); offset += bytesRead; } //Point B InputStream is2 = new ByteArrayInputStream(ba); //Now just working with 'is2' - the "copied" stream The InputStream-byte[] conversion took again 1000ms - this is the way many ppl suggested to read an InputStream, and stil it is slow. And guess what - the 2 parser methods above (convertToXML() and convertBattlePagetoXMLWithoutDOM(), when passed 'is2' instead of 'is' took, in all 4 cases, under 50ms to complete. I read a suggestion that the stream waits for connection to close before unblocking, so i tried using HttpComponentsClient 4.0 (http://hc.apache.org/httpcomponents-client/index.html) instead, but the initial InputStream took just as long to parse. e.g. this code: public InputStream getWebPageAsStream2(int battle_id, int page) throws Exception { String url = "http://api.erepublik.com/v1/feeds/battle_logs/" + battle_id + "/" + page; HttpClient httpclient = new DefaultHttpClient(); HttpGet httpget = new HttpGet(url); HttpParams p = new BasicHttpParams(); HttpConnectionParams.setSocketBufferSize(p, 250000); HttpConnectionParams.setStaleCheckingEnabled(p, false); HttpConnectionParams.setConnectionTimeout(p, 5000); httpget.setParams(p); HttpResponse response = httpclient.execute(httpget); HttpEntity entity = response.getEntity(); l = (int) entity.getContentLength(); return entity.getContent(); } took even longer to process(50ms more for just the network) and the stream parsing times remained the same. Obviously it can be instantiated so as to not create HttpClient and properties every time(faster network time), but the stream issue wont be affected by that. So we come to the center problem - why does the initial URLConnection InputStream(or HttpClient InputStream) take so long to process, while any stream of same size and content created locally is orders of magnitude faster? I mean, the initial response is already somewhere in RAM, and I cant see any good reasong why it is processed so slowly compared to when a same stream is just created from a byte[]. Considering I have to parse million of entries and thousands of pages like that, a total processing time of almost 1.5s/page seems WAY WAY too long. Any ideas? P.S. Please ask in any more code is required - the only thing I do after parsing is make a PreparedStatement and put the entries into JavaDB in packs of 1000+, and the perfomance is ok ~ 200ms/1000entries, prb could be optimized with more cache but I didnt look into it much.

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  • Add autorandr before kdm starts

    - by Serge Tarkovski
    I want to add autorandr before kdm starts. Autorandr works well within KDE, however, in kdm I still have ugly 1024x768 resolution when my external monitor is connected. I tried adding autorandr --change to /etc/kde4/kdm/Xsetup: #! /bin/sh # Xsetup - run as root before the login dialog appears #xconsole -geometry 480x130-0-0 -notify -verbose -fn fixed -exitOnFail -file /dev/xconsole & /sbin/initctl -q emit login-session-start DISPLAY_MANAGER=kdm /usr/local/bin/autorandr --change >> /tmp/autorandr echo "Xsetup finished" >> /tmp/xsetup-finished A debug message in /tmp/xsetup-finished appears correctly. /tmp/autorandr is empty (so it seems autorandr runs without errors). I also tried to move autorandr --change line before /sbin/initctl -q emit login-session-start DISPLAY_MANAGER=kdm with no effect. P.S. Of course, autorandr profiles I created under KDE session, are in my home folder, but Xsetup script runs under root, so I created a symlink from my ~/.autorandr to /root/.autorandr.

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  • How can I solve for the game's world coordinates?

    - by HyperGroups
    I've used 3DReaperDX to get a obj file, the header information are shown as follows: #AR=2.00606, FOV=45.09583(height), Xscale:0.83290, Yscale:0.41519, Zscale:1.0 #************************************************** #ALPHABLENDENABLE: No #ZENABLE: Yes #ZWRITEENABLE: Yes #TWOSIDED: No #INVALID: No #THIN: No #RENDERTARGET_IS_BACKBUFFER: Yes #WIDTH_DO_MATCH: Yes #RGBWRITEDISABLED: No # object DrawCall_0 to come ... g v 2143.35547 6654.99023 25835.37109 v 2243.17773 6296.61523 25957.53906 v 2343.00000 5856.84473 26093.97656 How can I get the game's world coordinates. For example: I can map the scaleTransform to the VertexData scaleTransform={X1scale,Y1scale,Z1scale} {0.8329,0.41519,1.} Is the obj file enough to get the game's world coordinates? I want to put a object in this ground, and the coordinates is the same to that in the Game Engine, And I can place something(with some fixed coordinates) in the Game and then to use 3DReaper to get the obj file. If the file is not enough itself to get the game world coordinates.

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  • My presentation layer does not match my model layer even though I have no animations

    - by Kevin McCullough
    On iPhone I have a CALayer that I animate via Core Animation. Then at some point I change view controllers. I then return to the view controller with the CALayer and in viewWillAppear: I set the frame and position properties on my layer to move it back to its starting point. Setting these properties changes the model layer but the presentation layer still has the old values and its presentation layer does not update until the next animation I play. In the CA Programming guide it says "You can query an instance of CALayer for its corresponding presentation layer while an animation transaction is in process." Which, to me, implies that the presentation layer should only be different from the model layer during an animation. But there are no animations currently running. I even used kCATransactionDisableActions to ensure that when I set the position property an implicit animation is not started. Does anyone know why my presentation and model layers are out of sync? Thanks.

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  • Can you tune C runtime heap segment reservation size on XP?

    - by Jason
    When the VC6 C runtime on XP can't serve an allocation request within an existing heap segment, it reserves a new segment. The size of these new segments increase by factors of 2 (until there are not large enough free areas to do that, at which point it falls down to smaller segments.) In any case, is there any way to control this behavior on XP with the VC6 runtime? For example, doubling up to a point, but capping at 64MB segments. If there is no way on XP but there is on 7, that would be good to know too. Or if there is no way on VC6 but there is on VC8 or up would be interesting.

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  • Overriding equals, hashCode and toString in a Clojure deftype

    - by mikera
    I'm trying to create a new type in Clojure using deftype to implement a two dimensional (x,y) coordinate, which implements a "Location" protocol. I'd also like to have this implement the standard Java equals, hashCode and toString methods. My initial attempt is: (defprotocol Location (get-x [p]) (get-y [p]) (add [p q])) (deftype Point [#^Integer x #^Integer y] Location (get-x [p] x) (get-y [p] y) (add [p q] (let [x2 (get-x q) y2 (get-y q)] (Point. (+ x x2) (+ y y2)))) Object (toString [self] (str "(" x "," y ")")) (hashCode [self] (unchecked-add x (Integer/rotateRight y 16))) (equals [self b] (and (XXXinstanceofXXX Location b) (= x (get-x b)) (= y (get-y b))))) However the equals method still needs some way of working out if the b parameter implements the Location protocol. What is the right approach? Am I on the right track?

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  • Using a "local" S3 emulation layer as a replacement for HDFS?

    - by user183394
    I have been testing out the most recent Cloudera CDH4 hadoop-conf-pseudo (i.e. MRv2 or YARN) on a notebook, which has 4 cores, 8GB RAM, an Intel X25MG2 SSD, and runs a S3 emulation layer my colleagues and I wrote in C++. The OS is Ubuntu 12.04LTS 64bit. So far so good. Looking at Setting up hadoop to use S3 as a replacement for HDFS, I would like to do it on my notebook. Nevertheless, I can't find where I can change the jets3t.properties for setting the end point to localhost. I downloaded the hadoop-2.0.1-alpha.tar.gz and searched the source without finding out a clue. There is a similar Q on SO Using s3 as fs.default.name or HDFS?, but I want to use our own lightweight and fast S3 emulation layer, instead of AWS S3, for our experiments. I would appreciate a hint as to how I can change the end point to a different hostname. Regards, --Zack

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  • Zip Code Radius Search question...

    - by KnockKnockWhosThere
    I'm wondering if it's possible to find all points by longitude and latitude within X radius of one point? So, if I provide a latitude/longitude of -76.0000, 38.0000, is it possible to simply find all the possible coordinates within (for example) a 10 mile radius of that? I know that there's a way to calculate the distance between two points, which is why I'm not clear as to whether this is possible... Because, it seems like you need to know the center coordinates (-76 and 38 in this case) as well as the coordinates of every other point in order to determine whether it falls within the specified radius... Is that right?

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  • Using OnNcHItTest for a CWnd not CDialog

    - by dev ray
    I have a CWnd Derived object used in a dialog. I need to be able to drag it anywhere in the dialog. I have a code overriding OnNCHitTest for moving a dialog dragging it from a place other than the title bar. Is there any equivalent code to do the same to move this CWnd. The following code isnt working. UINT CBaseSliderBtn::OnNcHitTest(CPoint point) { UINT ret=CWnd::OnNcHitTest( point ); if (ret == HTCLIENT) return HTCAPTION; } If this isn't the right way, please suggest other optimum method to drag the slider. Thanks

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  • Sequence Diagram Reverse Engineering Tool?

    - by Wayne
    It's essential for me to find a tool that will reverse engineer sequence diagrams by integrating with the debugger. I suppose using the profiler could work also but less desirable. It's a key requirement that the tool in question will record all threads of execution since the app, TickZoom, is heavily parallelized. We just evaluated a most awesome tool from Sparx called Enterprise Architect which integrates with the debugger. It allows you to set a break point, start recording method traces from that break point. It's a lovely design and GUI. Hope it works for you but it only records a single thread of execution so that makes it unusable for us. I will put in a feature request to Sparx. But hope to find a similar tool that already does this since that's the only feature we need--not all the other amazing features that Sparx Enterprise Architect appears to do rather well.

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  • Skype support and dead parrot sketches

    - by Greg Low
    We as an industry have a lot to answer for. One thing is the level of support provided for users. Here's the conversation I'm having with Skype right now. It feels like being in a Monty Python skit. I was really hoping that when Microsoft purchased Skype that things might improve. 8:33:44 PM greglowInitial Question/Comment: Subscriptions (Unlimited Country, Unlimited Europe, Unlimited Region, Unlimited World)8:33:44 PM SystemThank you for contacting Skype Customer Support!8:33:49 PM SystemDonna Faye has joined this session!8:33:50 PM SystemConnected with Donna Faye8:33:50 PM SystemThank you for contacting Skype Customer Support!8:33:54 PM SystemPlease hold for the next available Live Support Agent.8:33:59 PM Donna FayeHello! Welcome to Skype Live Support! My name is Donna L. How may I help you?8:34:09 PM greglowI've got a subscription (skypename greglow)8:34:21 PM greglowIt's set to auto-renew8:34:45 PM greglowWhy have I been getting messages about my Skype number expiring, if it's set to renew automatically8:34:54 PM greglowand has recently renewed automatically8:35:09 PM Donna FayeThank you for the information.8:35:29 PM Donna FayeTo better assist you may I know your Skype name, please?8:35:37 PM greglowgreglow8:35:44 PM Donna FayeThank you.8:36:14 PM Donna FayeI understand your concern that you receive an email notification stating that your calling subscription will about to expire. Am I right?8:36:43 PM greglowNo, I got an email telling me that one of my Skype numbers was going to expire8:37:08 PM greglowWhen I went to the website, it said it was part of the subscription and the subscription was set to auto-renew8:37:18 PM greglowThe subscription auto-renewed on Oct XXth8:37:24 PM greglowBut the number still expired8:37:43 PM greglowWhen I logged on today, it said that the number had expired and that I had 52 days left to reactivate it8:37:58 PM greglowI did that but am trying to understand why that happens at all8:38:36 PM greglowWhy do you expire numbers that are part of auto-renewing subscriptions?8:39:49 PM Donna FayeUpon checking your account, your calling subscription link to three Online Numbers.8:39:55 PM greglowcorrect8:40:10 PM greglowbut until an hour or so ago, one of them had expired. why?8:40:54 PM Donna FayeLet me explain to you that now Online Number are detach to a calling subscription unlike before it was attach to the calling subscription so therefore each Online Number will recur individually.8:41:29 PM Donna FayeUpon checking your account it shows that all your Online Number will expire on October XX, 20138:41:44 PM Donna FayeIf you don't want to be charged again for you can cancel it anytime.8:41:59 PM greglowI have set it to charge automatically8:42:06 PM greglowso why do the numbers expire?8:42:32 PM Donna FayeNo they are not expired they are all active.8:42:33 PM greglowif there is an automatic payment set up, why does anything expire?8:42:52 PM greglowyes, but one of them was expired, and I only fixed it a few hours ago8:43:07 PM greglowI'm trying to understand why it expired8:44:54 PM Donna FayeThe email you got just notify you that you should have good enough funding source of your calling subscription and Online Number in order for this to recur.8:45:12 PM greglowAgreed. I did that but the number still expired. Why?8:45:38 PM Donna FayeHowever do not worry on this hence all Online Number are active and not expired.8:45:41 PM greglowWhen I logged on today it said that the number had expired and that I had 52 days left to reactivate it. Why did that happen?8:46:14 PM Donna FayeMay I know the Online Number you are pertaining, please?The number that had expired was (07) XXXX XXXX (Australia)8:49:19 PM Donna FayeOkay, do not worry on this Online Number because this will expire on October XX, 2013.8:49:38 PM Donna FayeThank you for all the information.8:49:46 PM greglowI understand that it won't expire now until next year. I'm trying to understand why it stopped working this time8:49:51 PM greglowso I can avoid that next time8:50:39 PM Donna FayeWhat do yo stop working, you mean that Online Number is unable to be reach out?8:50:59 PM Donna Faye*what do you mean by stop working8:51:18 PM greglowThe Skype number +61 7 XXXX XXXX stopped working because it expired8:51:32 PM Donna FayeNo, this into expired.8:51:34 PM greglowI'm trying to understand why it expired8:51:50 PM greglowSorry I don't follow "this into expired"8:52:39 PM Donna FayeLet me inform you that this Online Number is not expired.8:52:54 PM Donna FayePlease disregard the notification you see on your Skype account.8:53:02 PM greglowSorry, this is getting very frustrating. I already told you I fixed it today. I want to know why it happened.8:53:20 PM Donna FayeHence I can rest assured you that this is active until October XX, 2013.8:53:21 PM greglowSo I can avoid it happening again, on this account, or on our other accounts8:53:34 PM greglowCan I speak to someone who really understands this please?Donna FayeSkype send a notification to Skype users for their Skype product in order for them to be aware the expiration of your product however your Online Number still active on your account hence when your calling subscription Unlimited World recur your Online Number also recur. 8:57:59 PM Donna Faye I do apologize for this matter, please allow me to resolve this issue for you. 9:02:48 PM greglow My question is still the same: if it's set to auto-pay, why did it expire? 9:03:50 PM greglow Why did it stop working? Why did I have to "reactivate" it? 9:04:08 PM greglow Why didn't it just keep working if it's set to auto-pay? 9:04:30 PM greglow This isn't a difficult concept 9:04:34 PM Donna Faye Let me clarify to you that this is not the really expired what is emphasizing on this is when you don't have good enough funding source when you calling subscription recur the Online Number will possibly expired but seem that you have a good funding source then this will continue until 2013. 9:05:10 PM greglow When I logged on today, it was not working, and your website said it had expired and that I had 52 days left to reactivate it 9:05:17 PM greglow Why?and so on, and so on, and so on.... 

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  • Calculating instantaneous speed and acceleration for a simple Car software model

    - by Dylan
    I am trying to model a speedometer and tachometer for a simple software model of a car dashboard. I want this to be relatively simple, so for my purposes I won't likely simulate variables such as drag (or, assume that drag is a constant). But I would like to know the general formulas for: 1) Calculating the RPM, depending on a position of a graphical slider representing the accelerator. 2) Using this information to find the instantaneous speed (or, magnitude of instantaneous velocity?). I am not sure, in the case of 2), what other independent variables I need to consider. Do I need to consider the frequency of rotation of the wheels (assuming a fixed radius), in addition to the RPM? If anyone can give me a rough explanation plus relevant formulas, or alternatively direct me to other trusted resources online (I have had a hard time sifting through info and determining the accuracy), it would be much appreciated.

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  • C++ stack memory still valid?

    - by jbu
    Hi all, If I create an object on the stack and push it into a list, then the object loses scope (outside of the for loop in the example below) will the object still exist in the list? If the list still holds the object, is that data now invalid/possibly corrupt? Please let me know, and please explain the reasoning.. Thanks, jbu class SomeObject{ public: AnotherObject x; } //And then... void someMethod() { std::list<SomeObject> my_list; for(int i = 0; i < SOME_NUMBER; i++) { SomeObject tmp; my_list.push_back(tmp); //after the for loop iteration, tmp loses scope } my_list.front(); //at this point will my_list be full of valid SomeObjects or will the SomeObjects no longer be valid, even if they still point to dirty data }

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  • Changing Emacs Forward-Word Behaviour

    - by gvkv
    As the title says, how does one change the behaviour of emacs forward-word function? For example, suppose [] is the cursor. Then: my $abs_target_path[]= abs_path($target); <M-f> my $abs_target_path = abs[_]path($target); I know I could just use M-f M-b but as far as I'm concerned, that shouldn't be necessary and I'd like to change it. In particular, I want two things: When I press M-f, I want to go to the first character of the next word regardless of whether the point is within a word, within a group of spaces or somewhere else. Customize word-characters on a mode-by-mode basis. After all, moving around in CPerl mode is different than, say, TeX mode. So, in the above example, item 1 would have the cursor would move to the 'a' (and the point to it's left) after hitting M-f. Item 2 would allow me to define underscores and sigils as word characters.

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  • Encrypting and decrypting single file with master password and passphrase

    - by Iori
    Last night my system shutdown unexpectedly and when i restart it, it gave me superblock error. will then i fixed a little but. i was able to retrive my encrypted files which i encrypted my pgp public key but i was not able to retrive my private key or public key now i have ecrypted file which cannot be open because i have lost my private key. is there any way that i can encrypt my file by providing only master password and passphrase and no physical key or private key and when i am on another computer i can easily open it my same master password and passphrase. Thanks in advance

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  • Correct Rotation and Translation with a 4x4 matrix

    - by sFuller
    I am using a 4x4 matrix to transform verts in a shader. I multiply an identity matrix by a rotation matrix by a translation matrix. I am trying to first rotate the verts and then translate them, however in my result, it appears that the verts are being transformed and then rotated. My matrix looks something like this: m00 m01 m02 tx m10 m11 m12 ty m20 m21 m22 tz --- --- --- 1 I am not using OpenGL's fixed function pipeline, I am multiplying matrices on the client side, and uploading the matrix to a GLSL shader. If it helps, I am using my own matrix multiplication code, but I have recreated this problem using matrices on my graphing calculator, so I don't believe my matrix code has errors.. I'll include a visual aid if needed.

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  • Plot smooth line with PyPlot

    - by Paul
    I've got the following simple script that plots a graph: import matplotlib.pyplot as plt import numpy as np T = np.array([6, 7, 8, 9, 10, 11, 12]) power = np.array([1.53E+03, 5.92E+02, 2.04E+02, 7.24E+01, 2.72E+01, 1.10E+01, 4.70E+00]) plt.plot(T,power) plt.show() As it is now, the line goes straight from point to point which looks ok, but could be better in my opinion. What I want is to smooth the line between the points. In Gnuplot I would have plotted with smooth cplines. Is there an easy way to do this in PyPlot? I've found some tutorials, but they all seem rather complex.

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