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  • sudo command and how to auto get password

    - by user108988
    I got a problem that: I have a file .sh #!/bin/bash var=$(zenity --forms --title="T?t gi? v? yêu nhé" \ --text="V? mu?n t?t máy sau bao nhiêu phút n?a" \ --separator="," \ --add-entry="V? di?n s? vào dây") case $? in 0) sudo shutdown -h $var ;; 1) exit 0;; -1) echo "An unexpected error has occurred." ;; esac How can sudo command autofill the password from echo command or a file. I read about sudo -S options, but i dont know how it works. Anyone can give an example about it! Thanks guys

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  • How do I force the system to look for new sound devices?

    - by John Zeringue
    I have a small flat screen TV (Toshiba) that I often connect via HDMI to my laptop (an HP Pavilion dv4) and use as a computer monitor. When I do this, I prefer to use the TV's speakers, particularly when I'm watching video, because the sound quality is much better. However, when I connect the HDMI cable after turning on my computer (rather than having it plugged in before booting up), Sound Settings does not list the TV as an output device, and I am forced to reboot. I was curious if there is an easier solution to this, perhaps a CLI command to check for new sound outputs. Does anyone know of something like this or have another solution? To clarify, I believe this is a software problem. The HDMI always works, and I can switch my desktop over to the TV at any time. The issue is that, if the HDMI wasn't connected during start up, the TV will not appear as an output option in the Sound Settings GUI. So, unless I'm mistaken, my question is not HDMI specific, but rather a general usage question about manipulating sound settings from the command line.

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  • Why do packages fail to install from command line

    - by calebB
    Every once in a while I can't install packages in Ubuntu 11.04. I'll try to run the software center and it and it will pop up then disappear. If I call it from the command line it says it seg-faults. And then trying to install anything from the command line I get this: sudo apt-get install pdftk Reading package lists... Done And thats all I get for anything I try. Usually restarting fixes the problem but its very annoying.

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  • Stucked in the grub command prompt

    - by user903645
    I have a windows xp os, and I ve decided to give ubuntu a shot. I installed and It when rebooting it did boot by default windows. I red several forums and after entering those commands: sudo mkdir /mnt/ubuntu sudo mount /dev/sda2 /mnt/ubuntu sudo grub-install /dev/sda --root -directory=/mnt/ubuntu after rebooting the system showed me the command grub. And I cannot get anywhere. I don t have a windows cd to fix anything. so how can I launch windows from this command grub? Thanks... I am in a real mess.

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  • (SYSLINUX QUESTION) How to launch command prompt once syslinux boots up

    - by user1294023
    I have created a bootable USB drive using SYSLINUX I am booting my x86 system correctly. Once system boots I want to stop at console (command prompt) where I can type linux commands (cd etc) and run my executable file manually. Does that mean I have to have busy box installed (for basic commands). What makes system stop at command prompt? I do have /dev/console. My serial console is tty1. Any help is appreciated. #syslinux.cfg serial 0 9600 default MyProgram prompt 1 label Linux display message.msg timeout 100 kernel bzImage append console=tty1,9600 vga=773 initrd initrd.img

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  • Does anyone really understand how HFSC scheduling in Linux/BSD works?

    - by Mecki
    I read the original SIGCOMM '97 PostScript paper about HFSC, it is very technically, but I understand the basic concept. Instead of giving a linear service curve (as with pretty much every other scheduling algorithm), you can specify a convex or concave service curve and thus it is possible to decouple bandwidth and delay. However, even though this paper mentions to kind of scheduling algorithms being used (real-time and link-share), it always only mentions ONE curve per scheduling class (the decoupling is done by specifying this curve, only one curve is needed for that). Now HFSC has been implemented for BSD (OpenBSD, FreeBSD, etc.) using the ALTQ scheduling framework and it has been implemented Linux using the TC scheduling framework (part of iproute2). Both implementations added two additional service curves, that were NOT in the original paper! A real-time service curve and an upper-limit service curve. Again, please note that the original paper mentions two scheduling algorithms (real-time and link-share), but in that paper both work with one single service curve. There never have been two independent service curves for either one as you currently find in BSD and Linux. Even worse, some version of ALTQ seems to add an additional queue priority to HSFC (there is no such thing as priority in the original paper either). I found several BSD HowTo's mentioning this priority setting (even though the man page of the latest ALTQ release knows no such parameter for HSFC, so officially it does not even exist). This all makes the HFSC scheduling even more complex than the algorithm described in the original paper and there are tons of tutorials on the Internet that often contradict each other, one claiming the opposite of the other one. This is probably the main reason why nobody really seems to understand how HFSC scheduling really works. Before I can ask my questions, we need a sample setup of some kind. I'll use a very simple one as seen in the image below: Here are some questions I cannot answer because the tutorials contradict each other: What for do I need a real-time curve at all? Assuming A1, A2, B1, B2 are all 128 kbit/s link-share (no real-time curve for either one), then each of those will get 128 kbit/s if the root has 512 kbit/s to distribute (and A and B are both 256 kbit/s of course), right? Why would I additionally give A1 and B1 a real-time curve with 128 kbit/s? What would this be good for? To give those two a higher priority? According to original paper I can give them a higher priority by using a curve, that's what HFSC is all about after all. By giving both classes a curve of [256kbit/s 20ms 128kbit/s] both have twice the priority than A2 and B2 automatically (still only getting 128 kbit/s on average) Does the real-time bandwidth count towards the link-share bandwidth? E.g. if A1 and B1 both only have 64kbit/s real-time and 64kbit/s link-share bandwidth, does that mean once they are served 64kbit/s via real-time, their link-share requirement is satisfied as well (they might get excess bandwidth, but lets ignore that for a second) or does that mean they get another 64 kbit/s via link-share? So does each class has a bandwidth "requirement" of real-time plus link-share? Or does a class only have a higher requirement than the real-time curve if the link-share curve is higher than the real-time curve (current link-share requirement equals specified link-share requirement minus real-time bandwidth already provided to this class)? Is upper limit curve applied to real-time as well, only to link-share, or maybe to both? Some tutorials say one way, some say the other way. Some even claim upper-limit is the maximum for real-time bandwidth + link-share bandwidth? What is the truth? Assuming A2 and B2 are both 128 kbit/s, does it make any difference if A1 and B1 are 128 kbit/s link-share only, or 64 kbit/s real-time and 128 kbit/s link-share, and if so, what difference? If I use the seperate real-time curve to increase priorities of classes, why would I need "curves" at all? Why is not real-time a flat value and link-share also a flat value? Why are both curves? The need for curves is clear in the original paper, because there is only one attribute of that kind per class. But now, having three attributes (real-time, link-share, and upper-limit) what for do I still need curves on each one? Why would I want the curves shape (not average bandwidth, but their slopes) to be different for real-time and link-share traffic? According to the little documentation available, real-time curve values are totally ignored for inner classes (class A and B), they are only applied to leaf classes (A1, A2, B1, B2). If that is true, why does the ALTQ HFSC sample configuration (search for 3.3 Sample configuration) set real-time curves on inner classes and claims that those set the guaranteed rate of those inner classes? Isn't that completely pointless? (note: pshare sets the link-share curve in ALTQ and grate the real-time curve; you can see this in the paragraph above the sample configuration). Some tutorials say the sum of all real-time curves may not be higher than 80% of the line speed, others say it must not be higher than 70% of the line speed. Which one is right or are they maybe both wrong? One tutorial said you shall forget all the theory. No matter how things really work (schedulers and bandwidth distribution), imagine the three curves according to the following "simplified mind model": real-time is the guaranteed bandwidth that this class will always get. link-share is the bandwidth that this class wants to become fully satisfied, but satisfaction cannot be guaranteed. In case there is excess bandwidth, the class might even get offered more bandwidth than necessary to become satisfied, but it may never use more than upper-limit says. For all this to work, the sum of all real-time bandwidths may not be above xx% of the line speed (see question above, the percentage varies). Question: Is this more or less accurate or a total misunderstanding of HSFC? And if assumption above is really accurate, where is prioritization in that model? E.g. every class might have a real-time bandwidth (guaranteed), a link-share bandwidth (not guaranteed) and an maybe an upper-limit, but still some classes have higher priority needs than other classes. In that case I must still prioritize somehow, even among real-time traffic of those classes. Would I prioritize by the slope of the curves? And if so, which curve? The real-time curve? The link-share curve? The upper-limit curve? All of them? Would I give all of them the same slope or each a different one and how to find out the right slope? I still haven't lost hope that there exists at least a hand full of people in this world that really understood HFSC and are able to answer all these questions accurately. And doing so without contradicting each other in the answers would be really nice ;-)

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  • Does anyone really understand how HFSC scheduling in Linux/BSD works?

    - by Mecki
    I read the original SIGCOMM '97 PostScript paper about HFSC, it is very technically, but I understand the basic concept. Instead of giving a linear service curve (as with pretty much every other scheduling algorithm), you can specify a convex or concave service curve and thus it is possible to decouple bandwidth and delay. However, even though this paper mentions to kind of scheduling algorithms being used (real-time and link-share), it always only mentions ONE curve per scheduling class (the decoupling is done by specifying this curve, only one curve is needed for that). Now HFSC has been implemented for BSD (OpenBSD, FreeBSD, etc.) using the ALTQ scheduling framework and it has been implemented Linux using the TC scheduling framework (part of iproute2). Both implementations added two additional service curves, that were NOT in the original paper! A real-time service curve and an upper-limit service curve. Again, please note that the original paper mentions two scheduling algorithms (real-time and link-share), but in that paper both work with one single service curve. There never have been two independent service curves for either one as you currently find in BSD and Linux. Even worse, some version of ALTQ seems to add an additional queue priority to HSFC (there is no such thing as priority in the original paper either). I found several BSD HowTo's mentioning this priority setting (even though the man page of the latest ALTQ release knows no such parameter for HSFC, so officially it does not even exist). This all makes the HFSC scheduling even more complex than the algorithm described in the original paper and there are tons of tutorials on the Internet that often contradict each other, one claiming the opposite of the other one. This is probably the main reason why nobody really seems to understand how HFSC scheduling really works. Before I can ask my questions, we need a sample setup of some kind. I'll use a very simple one as seen in the image below: Here are some questions I cannot answer because the tutorials contradict each other: What for do I need a real-time curve at all? Assuming A1, A2, B1, B2 are all 128 kbit/s link-share (no real-time curve for either one), then each of those will get 128 kbit/s if the root has 512 kbit/s to distribute (and A and B are both 256 kbit/s of course), right? Why would I additionally give A1 and B1 a real-time curve with 128 kbit/s? What would this be good for? To give those two a higher priority? According to original paper I can give them a higher priority by using a curve, that's what HFSC is all about after all. By giving both classes a curve of [256kbit/s 20ms 128kbit/s] both have twice the priority than A2 and B2 automatically (still only getting 128 kbit/s on average) Does the real-time bandwidth count towards the link-share bandwidth? E.g. if A1 and B1 both only have 64kbit/s real-time and 64kbit/s link-share bandwidth, does that mean once they are served 64kbit/s via real-time, their link-share requirement is satisfied as well (they might get excess bandwidth, but lets ignore that for a second) or does that mean they get another 64 kbit/s via link-share? So does each class has a bandwidth "requirement" of real-time plus link-share? Or does a class only have a higher requirement than the real-time curve if the link-share curve is higher than the real-time curve (current link-share requirement equals specified link-share requirement minus real-time bandwidth already provided to this class)? Is upper limit curve applied to real-time as well, only to link-share, or maybe to both? Some tutorials say one way, some say the other way. Some even claim upper-limit is the maximum for real-time bandwidth + link-share bandwidth? What is the truth? Assuming A2 and B2 are both 128 kbit/s, does it make any difference if A1 and B1 are 128 kbit/s link-share only, or 64 kbit/s real-time and 128 kbit/s link-share, and if so, what difference? If I use the seperate real-time curve to increase priorities of classes, why would I need "curves" at all? Why is not real-time a flat value and link-share also a flat value? Why are both curves? The need for curves is clear in the original paper, because there is only one attribute of that kind per class. But now, having three attributes (real-time, link-share, and upper-limit) what for do I still need curves on each one? Why would I want the curves shape (not average bandwidth, but their slopes) to be different for real-time and link-share traffic? According to the little documentation available, real-time curve values are totally ignored for inner classes (class A and B), they are only applied to leaf classes (A1, A2, B1, B2). If that is true, why does the ALTQ HFSC sample configuration (search for 3.3 Sample configuration) set real-time curves on inner classes and claims that those set the guaranteed rate of those inner classes? Isn't that completely pointless? (note: pshare sets the link-share curve in ALTQ and grate the real-time curve; you can see this in the paragraph above the sample configuration). Some tutorials say the sum of all real-time curves may not be higher than 80% of the line speed, others say it must not be higher than 70% of the line speed. Which one is right or are they maybe both wrong? One tutorial said you shall forget all the theory. No matter how things really work (schedulers and bandwidth distribution), imagine the three curves according to the following "simplified mind model": real-time is the guaranteed bandwidth that this class will always get. link-share is the bandwidth that this class wants to become fully satisfied, but satisfaction cannot be guaranteed. In case there is excess bandwidth, the class might even get offered more bandwidth than necessary to become satisfied, but it may never use more than upper-limit says. For all this to work, the sum of all real-time bandwidths may not be above xx% of the line speed (see question above, the percentage varies). Question: Is this more or less accurate or a total misunderstanding of HSFC? And if assumption above is really accurate, where is prioritization in that model? E.g. every class might have a real-time bandwidth (guaranteed), a link-share bandwidth (not guaranteed) and an maybe an upper-limit, but still some classes have higher priority needs than other classes. In that case I must still prioritize somehow, even among real-time traffic of those classes. Would I prioritize by the slope of the curves? And if so, which curve? The real-time curve? The link-share curve? The upper-limit curve? All of them? Would I give all of them the same slope or each a different one and how to find out the right slope? I still haven't lost hope that there exists at least a hand full of people in this world that really understood HFSC and are able to answer all these questions accurately. And doing so without contradicting each other in the answers would be really nice ;-)

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  • Can't install NPM after installing Node on EC2 Linux instance?

    - by frequent
    I'm trying my first attempt on getting a node server set up on an amazon ec2 linux instance. I think I made it quite far. First problem I ran into was when trying to make Node the connection timed out after a while, so I need three attempts until I got this: LINK(target) /home/ec2-user/node/out/Release/node: Finished touch /home/ec2-user/node/out/Release/obj.target/node_dtrace_header.stamp touch /home/ec2-user/node/out/Release/obj.target/node_dtrace_provider.stamp touch /home/ec2-user/node/out/Release/obj.target/node_dtrace_ustack.stamp touch /home/ec2-user/node/out/Release/obj.target/node_etw.stamp make[1]: Leaving directory `/home/ec2-user/node/out' ln -fs out/Release/node node Which tells me, "Node is done", although I'm not sure it is also working as it should. Following this,this and this tutorial, I'm now stuck at installing npm. I think I first cloned into the wrong folder, which always gave me error 127, but even if I'm doing this: cd ~ git clone git://github.com/isaacs/npm.git cd npm sudo -s PATH=/usr/local/bin:$PATH make install I'm still getting this: #after cloning# make[1]: Entering directory `/root/npm' node cli.js install bash: node: command not found make[1]: *** [node_modules/.bin/ronn] Error 127 make[1]: Leaving directory `/root/npm' make: *** [man/man3/start.3] Error 2 Question:: Since I'm pretty much a newby at everything I'm trying here, can someone please tell me what I'm doing wrong and how to get npm to install? Also, in case I cloned into the wrong folder, is there a way to remove the "false clone" or is this not written to disk until I call make install and I don't need to worry? Thanks for helping out!

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  • How do I keep folders synced and backed up between two macs using a Linux NAS (rsync?)

    - by Hultner
    I've got two primary computers, one Mac Pro and one MacBook Pro for when I'm on the go. I've also got a Linux sever which also acts as NAS. Currently I backup the entire computers to an external drive with Time Machine which is rather useless and doesn't sync anything. What I really want to do is to keep my important files synced between both computers and my NAS (which is running RAID 5), that way I'm not backing up easily replaceable systemfiles and I've got all my important files in 3 places where two of them are running raid so at least 5 drives would have to crash at the same time before actual data loss occur. Folders I want to keep synced is basically my photo, documents, development, mamp and work folders and then I want to keep the user library folder backed up but not synced. I'm thinking that I'd have to use rsync but don't know how. Before suggesting Dropbox and similar suggestions I don't want to use them because of several reasons some of them being security (Dropbox obviously proved this), Speed (sometimes I'll sync gigabytes of data and that will be significantly faster locally and probably even through VPN as I have a Gigabit pipe), Space (space on my NAS is cheap and only practically limited by my needs), reliability (even if my internet were to go down I still need to be able to keep my files synced incase I'd need to go somewhere on the fly), price (I already have all the hardware and for the amount of gigabytes and bandwidth I'd need I doubt that there's any free or cheap service). Those are my main reason for wanting to keep it locally. I'm sorry for any spelling or grammatical mistakes that I've might have done. I'm writing this on my smartphone from a shaky train and English isn't my mother tongue. I gratefully appreciate any answers even if only partly solving my problem.

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  • Is it possible to be a professional studying on your own?

    - by Marc Jr
    I read economics at university(nothing to see with linux, isn't it? :P). I have some basic knowledge about booting process, Linux Kernel compiling from source and stuff like that. But of course I have still much to learn sometimes some errors appears and "voila" I am lost. I had: Ubuntu, Fedora, OpenSuse, Arch.. using Gentoo now. I'd like to know what you linux users, professionals, administrators... would think it is the best way to learn linux in a professional way. Is it worth studying it and passing the LPIC test enough to work in the linux world? or do I need going to IT uni? I've heard LFS is a good way of learning about linux, is that real? I've been thinking about getting to LFS learn about more deeply about the linux process and learning scripts. It is possible to do this way? if anyone has a tip or a good way of doing, maybe someone did it. Any tip is very welcome. Words from a person in love with linux. :D The best, Marc

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  • Usage of putty in command line from Hudson

    - by kij
    Hi, I'm trying to use putty in command line from an hudson job. The command is the following one: putty -ssh -2 -P 22 USERNAME@SERVER_ADDR -pw PASS -m command.txt Where 'command.txt' is a shell script to execute in the server through SSH. If i launch this command from the Window command prompt, it works, the shell script is executed on the server machine. If i launch a build of the hudson job configured with this batch command, it doesn't work. The build is running... and running... and running.. without doing anything, and i have to stop it manually. So my question is: Is it possible to launch an external programm (i.e. putty) from an hudson job ? ps: i tried SSH plugin but... not a really good plugin (pre/post build, fail status of the commands launched not caught by hudson, etc.) Thanks in advance for your help. Best regards. kij EDIT: These are the build logs: [workspace] $ cmd /c call C:\WINDOWS\TEMP\hudson7429256014041663539.bat C:\Hudson\jobs\Artifact deployer\workspace>putty -ssh -2 -P 22 USER@SERV_ADD -pw PASS -m com.txt Le build a été annulé Finished: ABORTED And the Hudson.err.log file at the same time (after a stop): 3 juin 2010 18:27:28 hudson.model.Run run INFO: Artifact deployer #6 aborted java.lang.InterruptedException at java.lang.ProcessImpl.waitFor(Native Method) at hudson.Proc$LocalProc.join(Proc.java:179) at hudson.Launcher$ProcStarter.join(Launcher.java:278) at hudson.tasks.CommandInterpreter.perform(CommandInterpreter.java:83) at hudson.tasks.CommandInterpreter.perform(CommandInterpreter.java:58) at hudson.tasks.BuildStepMonitor$1.perform(BuildStepMonitor.java:19) at hudson.model.AbstractBuild$AbstractRunner.perform(AbstractBuild.java:601) at hudson.model.Build$RunnerImpl.build(Build.java:174) at hudson.model.Build$RunnerImpl.doRun(Build.java:138) at hudson.model.AbstractBuild$AbstractRunner.run(AbstractBuild.java:416) at hudson.model.Run.run(Run.java:1241) at hudson.model.FreeStyleBuild.run(FreeStyleBuild.java:46) at hudson.model.ResourceController.execute(ResourceController.java:88) at hudson.model.Executor.run(Executor.java:124) My shell script only write "hello" in a "hello.txt" file on the server, and nothing is done.

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  • Reuse remote ssh connections and reduce command/session logging verbosity?

    - by ewwhite
    I have a number of systems that rely on application-level mirroring to a secondary server. The secondary server pulls data by means of a series of remote SSH commands executed on the primary. The application is a bit of a black box, and I may not be able to make modifications to the scripts that are used. My issue is that the logging in /var/log/secure is absolutely flooded with requests from the service user, admin. These commands occur many times per second and have a corresponding impact on logs. They rely on passphrase-less key exchange. The OS involved is EL5 and EL6. Example below. Is there any way to reduce the amount of logging from these actions. (By user? By source?) Is there a cleaner way for the developers to perform these ssh executions without spawning so many sessions? Seems inefficient. Can I reuse the existing connections? Example log output: Jul 24 19:08:54 Cantaloupe sshd[46367]: pam_unix(sshd:session): session closed for user admin Jul 24 19:08:54 Cantaloupe sshd[46446]: Accepted publickey for admin from 172.30.27.32 port 33526 ssh2 Jul 24 19:08:54 Cantaloupe sshd[46446]: pam_unix(sshd:session): session opened for user admin by (uid=0) Jul 24 19:08:54 Cantaloupe sshd[46446]: pam_unix(sshd:session): session closed for user admin Jul 24 19:08:54 Cantaloupe sshd[46475]: Accepted publickey for admin from 172.30.27.32 port 33527 ssh2 Jul 24 19:08:54 Cantaloupe sshd[46475]: pam_unix(sshd:session): session opened for user admin by (uid=0) Jul 24 19:08:54 Cantaloupe sshd[46475]: pam_unix(sshd:session): session closed for user admin Jul 24 19:08:54 Cantaloupe sshd[46504]: Accepted publickey for admin from 172.30.27.32 port 33528 ssh2 Jul 24 19:08:54 Cantaloupe sshd[46504]: pam_unix(sshd:session): session opened for user admin by (uid=0) Jul 24 19:08:54 Cantaloupe sshd[46504]: pam_unix(sshd:session): session closed for user admin Jul 24 19:08:54 Cantaloupe sshd[46583]: Accepted publickey for admin from 172.30.27.32 port 33529 ssh2 Jul 24 19:08:54 Cantaloupe sshd[46583]: pam_unix(sshd:session): session opened for user admin by (uid=0) Jul 24 19:08:54 Cantaloupe sshd[46583]: pam_unix(sshd:session): session closed for user admin Jul 24 19:08:54 Cantaloupe sshd[46612]: Accepted publickey for admin from 172.30.27.32 port 33530 ssh2 Jul 24 19:08:54 Cantaloupe sshd[46612]: pam_unix(sshd:session): session opened for user admin by (uid=0) Jul 24 19:08:54 Cantaloupe sshd[46612]: pam_unix(sshd:session): session closed for user admin Jul 24 19:08:55 Cantaloupe sshd[46641]: Accepted publickey for admin from 172.30.27.32 port 33531 ssh2 Jul 24 19:08:55 Cantaloupe sshd[46641]: pam_unix(sshd:session): session opened for user admin by (uid=0) Jul 24 19:08:55 Cantaloupe sshd[46641]: pam_unix(sshd:session): session closed for user admin Jul 24 19:08:55 Cantaloupe sshd[46720]: Accepted publickey for admin from 172.30.27.32 port 33532 ssh2 Jul 24 19:08:55 Cantaloupe sshd[46720]: pam_unix(sshd:session): session opened for user admin by (uid=0) Jul 24 19:08:55 Cantaloupe sshd[46720]: pam_unix(sshd:session): session closed for user admin Jul 24 19:08:55 Cantaloupe sshd[46749]: Accepted publickey for admin from 172.30.27.32 port 33533 ssh2 Jul 24 19:08:55 Cantaloupe sshd[46749]: pam_unix(sshd:session): session opened for user admin by (uid=0) Jul 24 19:08:55 Cantaloupe sshd[46749]: pam_unix(sshd:session): session closed for user admin Jul 24 19:08:55 Cantaloupe sshd[46778]: Accepted publickey for admin from 172.30.27.32 port 33534 ssh2 Jul 24 19:08:55 Cantaloupe sshd[46778]: pam_unix(sshd:session): session opened for user admin by (uid=0) Jul 24 19:08:55 Cantaloupe sshd[46778]: pam_unix(sshd:session): session closed for user admin Jul 24 19:08:55 Cantaloupe sshd[46857]: Accepted publickey for admin from 172.30.27.32 port 33535 ssh2

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  • Why am I seeing MailSlot Browse messages on unrouted ports of my Linux box?

    - by nmichaels
    I have a Linux box (Debian squeeze) with several NICs. The ones of interest are: eth3 - my main link to the network (dhcp on 10.20.30.0/24) eth0 - the first connection to my test network (static: 192.168.1.2) eth4 - the second connection to my test network (static: 192.168.1.1) My routing table looks like this: $ sudo route Kernel IP routing table Destination Gateway Genmask Flags Metric Ref Use Iface 10.20.30.0 * 255.255.255.0 U 0 0 0 eth3 default 10.20.30.254 0.0.0.0 UG 0 0 0 eth3 I have the 2 test net ports connected to each other with a crossover cable and an instance of wireshark running on each port. Every once in a while, I'll see a packet like the following show up. Who could be doing this, and how do I convince them to stop? I do have Samba running on the machine (for a cifs mount) but don't see why it would be sending packets out to unrouted ports. I had a Windows VM running in VMWare Client and thought that might be causing it, but it still happens without it. What I want is totally silent interfaces so I can run some tests with Scapy over them.

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  • Why is my filesystem being mounted read-only in linux?

    - by Tim
    I am trying to set up a small linux system based on Gentoo on a VirtualBox machine, as a step towards deploying the same system onto a low-spec Single Board Computer. For some reason, my filesystem is being mounted read-only. In my /etc/fstab, I have: /dev/sda1 / ext3 defaults 0 0 none /proc proc defaults 0 0 none /sys sysfs defaults 0 0 none /dev/shm tmpfs defaults 0 0 However, once booted /proc/mounts shows rootfs / rootfs rw 0 0 /dev/root / ext3 ro,relatime,errors=continue,barrier=0,data=writeback 0 0 proc /proc proc rw,nosuid,nodev,noexec,relatime 0 0 sysfs /sys sysfs rw,nosuid,nodev,noexec,relatime 0 0 udev /dev tmpfs rw,nosuid,relatime,size=10240k,mode=755 0 0 devpts /dev/pts devpts rw,nosuid,noexec,relatime,gid=5,mode=620 0 0 none /dev/shm tmpfs rw,relatime 0 0 usbfs /proc/bus/usb usbfs rw,nosuid,noexec,relatime,devgid=85,devmode=664 0 0 binfmt_misc /proc/sys/fs/binfmt_misc binfmt_misc rw,nosuid,nodev,noexec,relatime 0 0 (the above may contain errors: there's no practical way to copy and paste) The partition at /dev/hda1 is clearly being mounted OK, since I can read all the data, but it's not being mounted as described in fstab. How might I go about diagnosing / resolving this? Edit: I can remount with mount -o remount,rw / and it works as expected, except that /proc/mounts reports /dev/root mounted at / rather than /dev/sda1 as I'd expect. If I try to remount with mount -a I get mount: none already mounted or /sys busy mount: according to mtab, sysfs is already mounted on /sys Edit 2: I resolved the problem with mount -a (the same error was occuring during startup, it turned out) by changing the sysfs and proc lines to proc /proc proc [...] sysfs /sys sysfs [...] Now mount -a doesn't complain, but it doesn't result in a read-write root partition. mount -o remount / does cause the root partition to be remounted, however.

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  • How can I set the CD audio volume in Linux?

    - by user1296362
    In Windows 7 Control Panel - Sound - Sound Properties window there's an slider for setting CD Audio volume: And it's pretty strange that I can't find corresponding one in generic Linux mixers: alsamixer or amixer. I connected a CD drive to try to set CD audio volume with cdcd (CD Player): $ cdcd setvol 0 Invalid volume It isn't actually an invalid volume, it is because ioctl() call fails. I found that out after searching and changing a bit the source code of this utility (in the libcdaudio): --- cdaudio.c.orig 2004-09-09 06:26:20.000000000 +0600 +++ cdaudio.c 2012-05-30 21:34:34.167915521 +0600 @@ -578,8 +578,10 @@ cdvol_data.CDVOLCTRL_BACK_RIGHT_SELECT = CDAUDIO_MAX_VOLUME; #endif - if(ioctl(cd_desc, CDAUDIO_SET_VOLUME, &cdvol) < 0) - return -1; + if(ioctl(cd_desc, CDAUDIO_SET_VOLUME, &cdvol) < 0) { + printf("*** cd_set_volume: ioctl() returned error\n"); + return -1; + } return 0; } By the way cdcd's get volume command yields rather weird output: Left Right Front 1281734864 32767 Back 0 0 Also I tried aumix: $ aumix -c 0 But all with no success. I read from this manual — http://tldp.org/HOWTO/Alsa-sound-6.html (section 6.2 The mixer) that CD channel can present in amixer output. Maybe some drivers for sound card are missing in my Ubuntu 12.04 LTS installation. Though I don't think it's the case: $ lsmod | grep snd snd_mixer_oss 22602 0 snd_hda_codec_hdmi 32474 1 snd_hda_codec_realtek 223867 1 snd_hda_intel 33773 4 snd_hda_codec 127706 3 snd_hda_codec_hdmi,snd_hda_codec_realtek,snd_hda_intel snd_hwdep 13668 1 snd_hda_codec snd_pcm 97188 3 snd_hda_codec_hdmi,snd_hda_intel,snd_hda_codec snd_seq_midi 13324 0 snd_rawmidi 30748 1 snd_seq_midi snd_seq_midi_event 14899 1 snd_seq_midi snd_seq 61896 2 snd_seq_midi,snd_seq_midi_event snd_timer 29990 2 snd_pcm,snd_seq snd_seq_device 14540 3 snd_seq_midi,snd_rawmidi,snd_seq snd 78855 19 snd_mixer_oss,snd_hda_codec_hdmi,snd_hda_codec_realtek,snd_hda_intel,snd_hda_codec,snd_hwdep ,snd_pcm,snd_rawmidi,snd_seq,snd_timer,snd_seq_device soundcore 15091 1 snd snd_page_alloc 18529 2 snd_hda_intel,snd_pcm All I need is just mute or set to 0 volume level of CD Audio channel, like I did in Windows 7, to get rid of sibilant noise in the speakers.

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  • Simple Linux program that takes any HTTP/HTTPS request and returns a single page?

    - by ultrasawblade
    I have a Linux box operating as router. There's a NIC that's connected to the internet (WAN), a NIC connected to an 8-port GbE switch (LAN), and a NIC connected to a Linksys wireless N-router (WLAN). Routing between everything is working perfectly. I have security completely disabled on the wireless router, but the WLAN NIC is firewalled such that it will only accept DNS queries and PPTP VPN connections. Currently HTTP/HTTPS traffic and everything else is blocked. I would like to run something that listens on port 80/443 of the WLAN NIC, and, for non VPN'ed connections, given any HTTP/HTTPS request it will return a single webpage saying "Unauthenticated" and explain how to sign into the VPN. A transparent proxy seems to be what I need, but my searches all seem to direct me to Squid, which is already running on my server and seems overkill for this simple task. Is there a simpler, lightweight program out there that does just this or should I just suck it up and run two instances of Squid (or figure out how to configure it)? Or, is this entire VPN thing I'm doing complete nonsense and I should just enable encryption on the wireless router?

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  • How do I set up a shared directory on Linux?

    - by JR Lawhorne
    I have a linux server I want to use to share files between users in my company. Users will access the machine with sftp or secure shell. Here is what I have: cd /home ls -l drwxrwsr-x 5 userA staff 4096 Jul 22 15:00 shared (other listings omitted) I want all users in the staff group to be able to create, modify, delete any file and/or directory in the shared folder. I don't want anyone else to have access to the folder at all. I have: Added the users to the staff group by modifying /etc/group and running grpconv to update /etc/gshadow Run chown -R userA.staff /home/shared Run chmod -R 2775 /home/shared Now, users in the staff group can create new files but they aren't allowed to open the existing files in the directory for edit. I suspect this is due to the primary group id associated with each user which is still set to be the group created when the user was created. So, the PGID of user 'userA' is 'userA'. I'd rather not change the primary group of the users to 'staff' if I can help it but if it is the easiest option, I would consider it. And, a variation on a theme, I'd like to do this same thing with another directory but also allow the apache user to read files in the directory and serve them. What's the best way to set this up?

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  • Help about pure-ftp

    - by hai
    I setup pure-ftp on freebsd behind firewall. On pure-ftp setuped passsi mode ftp(rangle port 50400-50600) and firewall open port from 50400-50600 (include mode IN and out). But i try use ftp client connect but not connect. Nofinication error status: Connecting to 210.245.89.95:21... Status: Connection established, waiting for welcome message... Response: 220---------- Welcome to Pure-FTPd [privsep] ---------- Response: 220-You are user number 1 of 50 allowed. Response: 220-Local time is now 13:20. Server port: 21. Response: 220-IPv6 connections are also welcome on this server. Response: 220 You will be disconnected after 15 minutes of inactivity. Command: USER bk Response: 331 User bk OK. Password required Command: PASS Response: 230 OK. Current directory is / Command: SYST Response: 215 UNIX Type: L8 Command: FEAT Response: 211-Extensions supported: Response: EPRT Response: IDLE Response: MDTM Response: SIZE Response: REST STREAM Response: MLST type;size*;sizd*;modify*;UNIX.mode*;UNIX.uid*;UNIX.gid*;unique*; Response: MLSD Response: ESTA Response: PASV Response: EPSV Response: SPSV Response: ESTP Response: 211 End. Status: Connected Status: Retrieving directory listing... Command: PWD Response: 257 "/" is your current location Command: TYPE I Response: 200 TYPE is now 8-bit binary Command: PASV Response: 227 Entering Passive Mode (210,245,88,98,138,1) Command: MLSD Error: Connection timed out Error: Failed to retrieve directory listing Status: Connecting to 210.245.88.98:21... Status: Connection established, waiting for welcome message... Help me.

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  • Is there any way to force my Linux box to always boot up with a self-assigned IP address?

    - by Jeremy Friesner
    This is perhaps an unusual request: I'm trying to get a Debian Linux box to always give itself a self-assigned IP address (i.e. 169.254.x.y) on boot. In particular, I want it to do that even when there is a DHCP server present on the LAN. That is, it should not request an IP address from the DHCP server. From what I can see in the "man interfaces" text, there is an option for "manual", and an option for "dhcp". Manual assignment won't do, since I need multiple boxes to work on the same LAN without requiring any manual configuration... and "dhcp" does what I want, but only if there is no DHCP server on the LAN. (A requirement is that the functionality of these boxes should not be affected by the presence or absence of a DHCP server). Is there a trick that I can use to get this behavior? EDIT: By "no manual configuration", I mean that I should be able to take this box (headless) to any LAN anywhere, plug in the Ethernet cable, and have it do its thing. I shouldn't have to ssh to the box and edit files to get it working each time it is moved to a different LAN.

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  • How to configure a Linux kernel based on the modules currently in use?

    - by Carla
    Hello, I'm willing to build a minimal kernel with only the needed things for my machine; so I started by compiling the kernel from the ground up, using the default configuration and adding things that I know for sure I have (i.e.: Ethernet card, WiFi card, ...). But there are several other things not so easy to know about (i.e.: the watchdog timer) so I came across AutoKernConf which supposedly detects the hardware of the machine and generates a kernel configuration file with the settings for the found devices. The problem is it contained several settings repeated and even some which I don't have (I'm using a Dell laptop and one of the things it "found" was something of a Toshiba one). So I ended up building a kernel with the configuration that came out of the make allmodconfig command, which is a kernel with most of the things compiled as modules. Booting into that kernel and running lsmod I can see all of the kernel modules in use (the ones really needed) and I would like to know if there is a tool or some way for me to parse that list and convert it to the corresponding kernel configuration file. Or how to map each one with the appropriate options in the kernel so that I can manually set them. Thank you very much for your time.

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  • Backup solution to backup terabytes and lots of static files on linux server?

    - by user28679
    Which backup tool or solution would you use to backup terabytes and lots of files on a production linux server ? Note that the files are all different and almost never modified, and usage is mostly adding files, so data volume is today 3TB growing all the time at around +15GB/day. Please do not reply rsync. Basic unix tools are not enough, rsync does not keep history, rdiff-backup miserably fails from time to time and screw the history. Moreover these are all file based backup, which put a lot of IOwait just to browse directories and query stat(). But i guess, except R1Soft CDP, there is no way around that. We tried R1Soft CDP backup, which is block level backup, and it proved good and efficient for all our other servers, but systematically fails on the server with 3 terabytes and gazillions of files. That is already more than 2 months that the engineers of R1Soft and datacenter are playing a hot ball game... and still no backup except regular rsync We never tried big commercial solutions, except R1Soft CDP since it was provided as an optional service by the datacented hosting our servers.

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  • How Would I Restrict a Linux Binary to a Limited Amount of RAM?

    - by Ken S.
    I would like to be able to limit an installed binary to only be able to use up to a certain amount of RAM. I don't want it to get killed if it exceeds it, only that that would be the max amount that it could use. The problem I am facing is that I am running an Apache 2.2 server with PHP and some custom code that a developer is writing for us. The problem is that somewhere in there code they launch a PHP exec call that launches ImageMagick's 'convert' to create a resized image file. I'm not privy to a lot of details to the project or the code, but need to find a solution to keep them from killing the server until they can find a way to optimize the code. I had thought that I could do this with /etc/security/limits.conf and setting a limit on the apache user, but it seems to have no effect. This is what I used: www-data hard as 500 If I understand it correctly, this should have limited any apache user process to a maximum to 500kb, however, when I ran a test script that would chew up a lot of RAM, this actually got up to 1.5GB before I killed it. Here is the output of 'ps auxf' after the setting change and a system reboot: USER PID %CPU %MEM VSZ RSS TTY STAT START TIME COMMAND root 5268 0.0 0.0 401072 10264 ? Ss 15:28 0:00 /usr/sbin/apache2 -k start www-data 5274 0.0 0.0 402468 9484 ? S 15:28 0:00 \_ /usr/sbin/apache2 -k start www-data 5285 102 9.4 1633500 1503452 ? Rl 15:29 0:58 | \_ /usr/bin/convert ../tours/28786/.…. www-data 5275 0.0 0.0 401072 5812 ? S 15:28 0:00 \_ /usr/sbin/apache2 -k start Next I thought I could do it with Apache's RlimitMEM setting, but get the same result of it not getting limited. Here is what I have in my apache.conf file: RLimitMEM 500000 512000 It wasn't until many hours later that I figured out that if the process actually reached that amount that it would die with an OOM error. Would love any ideas on how to set this limit so other things could function on the server, and all of them could play together nicely.

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  • Tools required for a Web Development Project..

    - by RBA
    Hi, I wanted to design a project in linux which could contain programming languages(C, perl, PHP, HTML, XML etc) basically a web based project. Why i have chosen to build on Linux is because it is Open Source, and lot many things can be automated through scripting languages, which in windows i don't know. So, i have installed linux on a virtual machine(Host-Windows 2007 & Guest Linux CentOS), CentOS(command line interface). Since i am a beginner, so I want to know what all tools can be used to facilitate and ease my development process. Some which i know are listed below, and request you to please share your experience on this. 1) Using Putty so that can access the Linux machine from anywhere within the network. 2) Since i want to develop on Linux, but want to use windows as developing platform. So have downloaded Eclipse Editor (C/PHP) on windows. But want to know how can i access linux files from here?? 3) Installed Samba, and still trying to figure out how can i access linux files remotely on Windows. 4) Please share your experience, as how can i ease my development process. and what all tools i can use..?? Please let me know if you need any other clarification..

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