Search Results

Search found 28744 results on 1150 pages for 'higher order functions'.

Page 193/1150 | < Previous Page | 189 190 191 192 193 194 195 196 197 198 199 200  | Next Page >

  • Call an action from another controller

    - by Brian
    I have two different objects: contracts, and task orders. My requirements specify that in order to view the Details for either object, the Url should be "http://.../Contract/Details" or "http://.../TaskOrder/Details" depending on which type. They are both very similar and the details pages are almost identical, so I made a class that can either be a contract or a task order, and has a variable "objectTypeID" that says which type it is. I wrote the action "Details" in the task order controller, but now I want to call that from the contract controller instead of recopying the code. So is there any way to have the url still say ".../Contract/Details" but call the action in the TaskOrder controller instead? I tried using TaskOrderController TOController = new TaskOrderController(); TOController.Details(id); This would have worked except that I can't use the HttpContext.Session anymore, which I used several times in the action.

    Read the article

  • Did I choose proper career path? [closed]

    - by Liston Catch
    I am a C# Junior. My company has it's own enterprise documents-flow system written, my job along with 10 other programmers is to write modules/add-ons for it. I am totally bored of this job, I dont like Microsoft's technologies stack (dont hate me here, just subjective), but it's plain boring, enterprise is boring (subjective again, everyone's tastes differ), days on this work last long and I am tired of it. In short - I dont like my job. In my spare time I am doing PHP-development and I totally like it. I am also doing web-design, so I am LAMP-kind of guy who loves his Ubuntu and does design aswell. I know that most programmers don't do design themselves, so some person is either all about design or all about coding, but I enjoy both and do both. I often get interesting sites orders, I love to make whole websites with all the design, I love the feeling of site completeness, I enjoy talking with customers. I like that PHP is simple and skill cap is lower than one of java, meaning I can become expert in it after some years. But C# (and J2EE also) pay more, and I am doing really good in C#. But I dont like it. I can go for J2EE, platform itself seems more fun to me rather than .NET, but EE development is still boring to me. But it seems higher payed, easier to find job (since PHP is too common for its easiness. But if you are expert in something it doesnt matter, right? Just a higher skillcap.) Question: I want to go on with freelance. I want to have an opportunity to start my own startup in web. Actually I have a browser-game already written by myself, it earns me around 500$ per month which I am really proud of since I am 21 only and still noob in coding. I want to find part-time PHP job. 3 days per week so I can get some stable income, I can work in team and learn from them, social factor matters aswell as ensurance and diversity. I also want my total income (freelance + part-time job + own startup maybe)to be not too much less than one I have working in EE development sector. Maximum of 25% lower, but not more. Is it all possible if I stick with web-development (LAMP + HTML/CSS/JS/Jquery/AJAX)? Or is it easier to reach my goals with EE development?

    Read the article

  • Selected number of records from database in DB2.

    - by Abhi
    Hi All, I have to fetch only 50 records at a time from database(DB2), for this I have been usig Row_Number but now the persons are telling that this Row_Number is not stable and has bugs in it so now I have to write a different querry for the same as I have to fetch only 50 records at a time. so please can any body help me out for the same. Thanks in advance. The Query which I have been using is SELECT PLC.* FROM ( SELECT ROW_NUMBER() OVER (ORDER BY PRDLN_CTLG_OID) AS Row, PRDLN_CTLG_OID, PRODUCT_LINE_OID AS PRODUCT_LINE_OID, RTRIM(CATALOG_ID) AS CATALOG_ID, FROM PROD_LINE_CATALOG WHERE PRODUCT_LINE_OID=:productLineOID AND ACTV_IND = 1 ORDER BY CATALOG_ID) PLC WHERE Row >= :startIndex AND Row <= :endIndex ORDER BY PLC.CATALOG_ID DESC WITH UR

    Read the article

  • c# How to make linq master detail query for 0..n relationship?

    - by JK
    Given a classic DB structure of Orders has zero or more OrderLines and OrderLine has exactly one Product, how do I write a linq query to express this? The output would be OrderNumber - OrderLine - Product Name Order-1 null null // (this order has no lines) Order-2 1 Red widget I tried this query but is not getting the orders with no lines var model = (from po in Orders from line in po.OrderLines select new { OrderNumber = po.Id, OrderLine = line.LineNumber, ProductName = line.Product.ProductDescription, } ) I think that the 2nd from is limiting the query to only those that have OrderLines, but I dont know another way to express it. LINQ is very non-obvious if you ask me!

    Read the article

  • SEO Tips and Advice - Part 3

    "White-hat" SEO strategies will help you to achieve higher quality search traffic results for your website. There are certain activities which should never be used and can destroy a website's credibility with the internet community. If you are thinking of hiring an SEO company, you definitely need to be aware of what strategies work and what doesn't.

    Read the article

  • postgres - group by on multiple columns - master/detail type table

    - by smpillay
    I have a table order(orderid, ordernumber, clientid, orderdesc etc.,) and a corresponding status for that order on an order_status table ( statusid, orderid, statusdesc, statusNote, statustimestamp) say I have a record in order as below orderid orderumber clientid orderdesc 1111 00980065 ABC blah..blah.. and a corresponding status entries statusid orderid statusdesc statusNote statustimestamp 11 1111 recvd status blah yyyy-mm-dd:10:00 12 1111 clientproce status blah yyyy-mm-dd:11:00 13 1111 clientnotice status blah yyyy-mm-dd:15:00 14 1111 notified status blah yyyy-mm-dd:17:00 How can I get the following result (latest timestamp along with multiple columns) 1111 14 00980065 ABC blah..blah.. notified status blah yyyy-mm-dd:17:00

    Read the article

  • Exposing PageRank

    Does PageRank matter? More than a few self proclaimed SEO experts say NO, but common sense dictates that it does, even though some low PageRank (PR) sites with just the correct combination of keywords outperform higher PR sites in Search Engine Results Pages (SERPS). When we externally compare sites for PageRank, we're comparing Toolbar PageRank which doesn't necessarily match Google's internal page rank.

    Read the article

  • How Search Engine Optimization Will Bring You More Real Estate Leads!

    Most real estate agents out there today are struggling, weighed down in the quagmire that has burdened our financial system and driven many out of the business altogether. Nonetheless, marketing your services is still at a premium and many do not have the funds needed to receive this valuable service. Many agent are wondering if there is a way they can do their own SEO and achieve a higher search engine ranking to bring in more leads from their website, and the easy answer is yes!

    Read the article

  • MySQL Query to receive random combinations from two tables.

    - by Michael
    Alright, here is my issue, I have two tables, one named firstnames and the other named lastnames. What I am trying to do here is to find 100 of the possible combinations from these names for test data. The firstnames table has 5494 entries in a single column, and the lastnames table has 88799 entries in a single column. The only query that I have been able to come up with that has some results is: select * from (select * from firstnames order by rand()) f LEFT JOIN (select * from lastnames order by rand()) l on 1=1 limit 10; The problem with this code is that it selects 1 firstname and gives every lastname that could go with it. While this is plausible, I will have to set the limit to 500000000 in order to get all the combinations possible without having only 20 first names(and I'd rather not kill my server). However, I only need 100 random generations of entries for test data, and I will not be able to get that with this code. Can anyone please give me any advice?

    Read the article

  • SEO Content - A Major Part of Your SEO Strategy

    Search Engine Optimization is a dynamic process and it involves a lot of factors that can be broadly be divided into on page and off page factors. Among the on page factors the content that is presented on the web page plays a very significant role in the determination of the rank of that page. With the right kind of SEO content you can increase the relevance of the page for the search engine thus making it rank higher for that particular keyword.

    Read the article

  • Dear XM Radio: I can't upgrade my device.

    <b>Attaboy:</b> "I was looking forward to doing the update until I visited the link they provided, where I discovered that I would be required to have Windows XP SP2 with Windows Media Player 11 or higher to flash the radio."

    Read the article

  • How to Increase Website Traffic Through Search Engine Optimization

    Search engine optimization is the process of discovering the most pertinent targeted keywords and phrases which are important to your niche target audience and placing them within all of the content on your website and sales material. Doing this on a continual basis will ensure that your website will increasingly rank higher on the search engines.

    Read the article

  • JSON Response {"d":"128.00"} but displaying "128"

    - by TGuimond
    Hi all, I have been working on a shopping cart that the user can add/remove order items as they please and am returning an updated sub-total via a webservice using jQuery $.ajax Here is how I am calling the webservice and setting the sub-total with the response. //perform the ajax call $.ajax({ url: p, data: '{' + s + '}', success: function(sTotal) { //order was updated: set span to new sub-total $("#cartRow" + orderID).find(".subTotal").text(sTotal); }, failure: function() { //if the orer was not saved //console.log('Error: Order not deleted'); } }); The response I am getting seems perfectly fine: {"d":"128.00"} When I display the total on the page it displays as 128 rather than 128.00 I am fully sure it is something very simple and silly but I am so deep into it now I need someone with a fresh brain to help me out!! Cheers :)

    Read the article

  • MySQL "IS IN" equivalent?

    - by nute
    A while ago I worked on a MS-SQL project and I remember a "IS IN" thing. I tried it on a MySQL project and it did not work. Is there an equivalent? Workaround? Here is the full query I am trying to run: SELECT * FROM product_product, product_viewhistory, product_xref WHERE ( (product_viewhistory.productId = product_xref.product_id_1 AND product_xref.product_id_2 = product_product.id) OR (product_viewhistory.productId = product_xref.product_id_2 AND product_xref.product_id_1 = product_product.id) ) AND product_product.id IS IN (SELECT DISTINCT pvh.productId FROM product_viewhistory AS pvh WHERE pvh.cookieId = :cookieId ORDER BY pvh.viewTime DESC LIMIT 10) AND product_viewhistory.cookieId = :cookieId AND product_product.outofstock='N' ORDER BY product_xref.hits DESC LIMIT 10 It's pretty big ... but the part I am interested in is: AND product_product.id IS IN (SELECT DISTINCT pvh.productId FROM product_viewhistory AS pvh WHERE pvh.cookieId = :cookieId ORDER BY pvh.viewTime DESC LIMIT 10) Which basically says I want the products to be in the "top 10" of that sub-query. How would you achieve that with MySQL (while trying to be efficient)?

    Read the article

  • SEO - Surprisingly Beneficial For Your Site!

    More than three-fourth of the site hunters who can reach you only through the search engines. Visitors can be attracted by rising higher in search engine ranking results done through search engine optimization. An SEO India company can always aid in bringing your site to better position, thus increasing your revenue earning.

    Read the article

  • SEOmoz Linkscape - Use and Review

    The inbound links play an important role to gain success in search engines. To rank top in the search engines you need to gain large number of good and top quality back links to the site. More the number of links more will the page rank and thus stand higher in the search engine ranking. So there is a tool through which we can increase the back links to the site called SEOmoz Linkscape.

    Read the article

  • The Power of a Sitemap

    You have a website and would like search engine bots to index it. This is because you would like to higher your standings in search engine results. The only thing that would seem reasonable to do is to create back links either in the pages or script to enhance the pages indexing.

    Read the article

  • How can I get the count of orders placed from my database?

    - by user1360564
    I am preparing a chart which will display the number of orders placed for a particular day in the current month and year. I wanted the count of orders placed for each day. I am showing the count of orders on the y-axis and the day on the x-axis. In my database, there is table called "order" in which order data is placed: order date, user_id, order_price, etc. For example, if on 4 July, 10 orders are placed, on 5 july, 20 orders are placed, and so on. How can I get the count of orders placed for day of the current month?

    Read the article

  • Easy Search Engine Optimisation Advice - DIY SEO

    Search Engine Optimisation (SEO) is the term used to describe the actions a webmaster takes to improve the search engine rankings of their website - simply put, this means moving your website higher in the list in search engines such as Google, when a web user searches for the products/services you offer. This article offers a basic guide to the search engine optimisation process. Although they may help to improve rankings they are by no means all-encompassing, but rather a starting point for your SEO campaign.

    Read the article

< Previous Page | 189 190 191 192 193 194 195 196 197 198 199 200  | Next Page >