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  • mysql data being inserted twice via php

    - by Jascha
    I can't for the life of me figure out why this function is causing multiple entries into my database table... When I run the function I end up with two records stacked on top of each one second apart here is the function: function generate_signup_token(){ $connection = new DB_Connect(); // <--- my database connection class $ip = mysql_real_escape_string($_SERVER['REMOTE_ADDR']); $sign_up_token = uniqid(mt_rand(), true); $_SESSION['signup_token'] = $sign_up_token; $sign_up_token = mysql_real_escape_string($sign_up_token); $query = "INSERT INTO `token_manager` (`ip_address`, `signup_token`) VALUES ('$ip', '$sign_up_token')"; mysql_query($query); } generate_signup_token();

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  • Partitioning a table in mysql after creation

    - by erik
    I have a table with a bunch of data already in it. I know how to create a partitioned table or alter an already existing partitioned table, but can I add partitions to a table after it has been created, has data in it, without losing the data? The other option is to dump all the data, recreate the table with the partitions and then insert it all back it. Is that the only way? Thanks.

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  • Import Data from Excel Spreadsheet or CVS into MySQL

    - by Kelly Roper
    I have a spreadsheet which really has only one complicated table. I basically convert the spreadsheet to a cvs and use a groovy script to generate the INSERT scripts. However, I cannot do this with a table that has 28 fields with data within some of the fields on the spreadsheet that make importing into the CVS even more complicated. So the fields in the new CVS are not differentiated properly or my script has not accounted for it. Does anyone have any suggestions on a better approach to do this? Thanks.

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  • MySQL: count enumerated values?

    - by John Isaacks
    If my table looks like this: daily_individual_tracking', 'CREATE TABLE `daily_individual_tracking` ( `daily_individual_tracking_id` int(10) unsigned NOT NULL auto_increment, `daily_individual_tracking_date` date NOT NULL default ''0000-00-00'', `sales` enum(''no'',''yes'') NOT NULL COMMENT ''no'', `repairs` enum(''no'',''yes'') NOT NULL COMMENT ''no'', `shipping` enum(''no'',''yes'') NOT NULL COMMENT ''no'', PRIMARY KEY (`daily_individual_tracking_id`) ) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=latin1 basically the fields can be either yes or no. How can I count how many yes's their are for each column over a date range? Thanks!!

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  • mysql: get all rows into 1 column

    - by andufo
    hi, i have 3 tables: post (id_post, title) tag (id_tag, name) post_tag (id_post_tag, id_post, id_tag) Lets suppose that id_post 3 has 4 linked tags 1,2,3,4 (soccer, basket, tennis and golf). Is there a way to return something like this in ONE row? col 1 id_post = 3 col 2 tags = soccer basket tennis golf Thanks

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  • mysql left join

    - by user1019538
    I have two table one is index and another is the price structure as under table : index : column : trandate ,indexcode Table : price : Column: trandate,symbol,price i want to know the missing price. I issue the query select i.trandate,i.indexcode,p.trandate,p.price from index i left join price p on i.trandate = p.trandate where p.symbol='ABC' and indexcode="New" the above query does not show the null date even though various price in missing in price table. Only reason i understand is that the index table does not have the symbol field that's why...but as per theory if you want to show all the rows of one table and only the match value of another table then use the left or right join query...please anybody can help

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  • MySQL - Selecting the top occurring entries

    - by RC
    Hi, Should be a simple one. Database is mydb. One of the columns is mydata. What SELECT query do I need in order to select the top 3 occurring results from mydata, but sorted alphabetically? For example, if my data is this: mydata ====== kilo (x 1 occurrence) lima (x 9 occurrences) golf (x 5 occurrences) echo (x 9 occurrences) zulu (x 8 occurrences) How do I get it to return "echo, lima, zulu", which are the top three frequently occurring entries sorted alphabetically? Thanks! EDIT: Just to add, they need to be distinct entries. Thanks!

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  • Mysql / Django - Begin auto increment to 1

    - by ark
    Hi, I have a django script which loads data, the beginning of the script deletes all datas in database. So when I execute 1st time this script, the auto increment primary keys begin to 1 to 15 (if 15 objects) and if I want to reload data, I reexecute the script. My issue is when I execute it again, pks numbers begin to 16 (for 2nd launch), I would like each time auto_increment begins to 1, is it possible whitout regenerating tables structure each time ? Thanks

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  • mysql conditional query - complicated!

    - by emre
    i want to get distinct values for a field, let say: field1... ok this needs a query like: "select distint(field1) from table" however for some records, field1 is empty and there is another column that is an alternative to field1, which is field2. now; for the records where field1 is empty i need to use the value of field2. i think i need sort of a conditional select statement with if control something like: "select distinct( (if(field1!='') field1 else field2) ) from table" but i have no idea on how to write it. any help is appricated...

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  • Php/Mysql - need help to insert and update multiple rows with a single query

    - by Guanche
    Hello, is there any way how in this situation insert and update DB with single queries? $message = 'Hello to all group members'; $userdata = mysql_query("SELECT memberid, membernick FROM members WHERE groupid='$cid'") or die('Error'); while(list($memberid, $membernick) = mysql_fetch_row($userdata)) { $result1 = mysql_query("INSERT INTO messages VALUES (NULL,'$membernick', '$memberid', '$message')") or die('Error'); $result2 = mysql_query("UPDATE users SET new_messages=new_messages+1, total_messages=total_messages+1 WHERE id='$memberid'") or die('Error'); }

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  • How to refactor this MySQL code?

    - by Jader Dias
    SELECT * ( SELECT * FROM `table1` WHERE `id` NOT IN ( SELECT `id` FROM `table2` WHERE `col4` = 5 ) group by `col2` having sum(`col3`) > 0 UNION SELECT * FROM `table1` WHERE `id` NOT IN ( SELECT `id` FROM `table2` WHERE `col4` = 5 ) group by `col2` having sum(`col3`) = 0 ) t1; For readability and performance reasons, I think this code could be refactored. But how?

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  • Add results from MySQL?

    - by NardCake
    Not quite sure how descriptive that title was but this is what I want to do. I scripted a URL shortener today and it's working fine, I just want to add some stats on the bottom of it saying how many links there are and how many clicks there are. Now everytime a user clicks one of the links it +1 the column in the database then it redirects the user. I want to query that and add all of those numbers together from each row. I attempted a while loop which im not surprised didn't work: while($rows = mysql_fetch_assoc($check_count)){ $clicks = $rows['clicks']; $clicks = $clicks+$clicks; } If you don't understand please ask and if you do understand it means alot for any response!

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  • Table for each region in MySQL

    - by King Wu
    There are four regions with more than one million records total. Should I create a table with a region column or a table for each region and combine them to get the top ranks? If I combine all four regions, none of my columns will be unique so I will need to also add an id column for my primary key. Otherwise, name, accountId & characterId would be candidate keys or should I just add an id column anyways. Table: ---------------------------------------------------------------- | name | accountId | iconId | level | characterId | updateDate | ----------------------------------------------------------------

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  • best way to prgram php and mysql query

    - by air
    most of times in our pages we need to print only 1 field value of table in loop. for example <?php for($i=1;$i<=mysql_num_rows($result);$i++) { echo $row['name']; $sql1="select industry from table_industry where profid='".$row['prof']."'"; $result1=mysql_query($sql1); $row1=mysql_fetch_array($result1); echo $row1['industry']; ?> } ?> above is one PHP code just for example where we think that $row['prof'] carry value of profession ID and we print profession of each person. for example we have 5000+ record in table and above loop will execute for 5000+ times what will be the best way to print value of industry field from table table_industry Same code which i write above ? any other php code suggestion for faster execution and less use of resources? Thanks

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  • how to update mysql with inputs and checkboxes

    - by Ronnie Chester Lynwood
    hi. with this code: <? if (isset($_POST['onay'])) { foreach ($_POST['secilen'] as $zuha) { $olay = mysql_query("update mp3 SET aktif = '1' WHERE id = '$zuha'"); } if ($olay) { echo "islem tamam"; exit; } } ?> and with this form: (select * from mp3 aktif = '0') <form name="form" method="post"> <input readonly type="text" name="id" value="<?=$haciosman['id']?>" /> <input type="text" name="baslik" value="<?=$haciosman['baslik']?> <input type="checkbox" name="secilen[]" value="<?=$haciosman['id']?>"> <input type="submit" name="onay" value="Onayla" /> I can set "aktif to 1" for each row that i checked. but i want to update "baslik" too! how can i update each "baslik" with that php code?

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  • mysql - combining columns and tables

    - by Phil Jackson
    Hi, I'm not much of a SQL man so I'm seeking help for this one. I have a site where I have a database for all accounts and whatnot, and another for storing actions that the user has done on the site. Each user has their own table but I want to combine the data of each user group ( all users that are "linked together" ) and order that data in the time the actions took place. Heres what I have; <?php $query = "SELECT `TALKING_TO` FROM `nnn_instant_messaging` WHERE `AUTHOR` = '" . DISPLAY_NAME . "' AND `TALKING_TO` != ''"; $query = mysql_query( $query, $CON ) or die( "_error_ " . mysql_error()); if( mysql_num_rows( $query ) != 0 ) { $table_str = ""; $select_ref_clause = "( "; $select_time_stamp_clause = "( "; while( $row = mysql_fetch_array( $query ) ) { $table_str .= "`actvbiz_networks`.`" . $row['TALKING_TO'] . "`, "; $select_ref_clause .= "`actvbiz_networks`.`" . $row['TALKING_TO'] . ".REF`, "; $select_time_stamp_clause .= "`actvbiz_networks`.`" . $row['TALKING_TO'] . ".TIME_STAMP`, "; } $table_str = $table_str . "`actvbiz_networks`.`" . DISPLAY_NAME . "`"; $select_ref_clause = substr($select_ref_clause, 0, -2) . ") AS `REF`, "; $select_time_stamp_clause = substr($select_time_stamp_clause, 0, -2) . " ) AS `TIME_STAMP`"; }else{ $table_str = "`actvbiz_networks`.`" . DISPLAY_NAME . "`"; $select_ref_clause = "`REF`, "; $select_time_stamp_clause = "`TIME_STAMP`"; } $where_clause = $select_ref_clause . $select_time_stamp_clause; $query = "SELECT " . $where_clause . " FROM " . $table_str . " ORDER BY TIME_STAMP"; die($query); $query = mysql_query( $query, $CON ) or die( "_error_ " . mysql_error()); if( mysql_num_rows( $query ) != 0 ) { }else{ ?> <p>Currently no actions have taken place in your network.</p> <?php } ?> The code above returns the sql statement: SELECT ( `actvbiz_networks`.`john_doe.REF`, `actvbiz_networks`.`Emmalene_Jackson.REF`) AS `REF`, ( `actvbiz_networks`.`john_doe.TIME_STAMP`, `actvbiz_networks`.`Emmalene_Jackson.TIME_STAMP` ) AS `TIME_STAMP` FROM `actvbiz_networks`.`john_doe`, `actvbiz_networks`.`Emmalene_Jackson`, `actvbiz_networks`.`act_web_designs` ORDER BY TIME_STAMP I really am learning on my feet with SQL. Its not the PHP I have a problem with ( I can quite happly code away with PHP ) I'ts just help with the SQL statement. Any help much appreciated, REgards, Phil

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  • php and mysql user tracking and reporting

    - by inertiahz
    Hi, I currently have a table which consists of user information and lesson id; the table layout looks like: ---------------------------------------------------- |employeeID|numVisits|lessonID1|lessonID2|lessonID3| ---------------------------------------------------- |33388 |2 |1 |0 |3 | and a lessons table which contains the information about the lesson: ------------------------------------------------------ |lessonID |cateogry |title |filepath |numberviews| ------------------------------------------------------ |1 |beginner |lesson |file:// |10 | Within the lessonID fields in the user table is an integer which tracks how many times someone has clicked on a lesson. Now what I am trying to do is in a report I have the top 5 people who have visited the site and would like to then be able to drill down into what lessons they have clicked on. Can anyone help with this? Or would restructuring the way the database is be an easier task? Thanks

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  • Need help optimizing MYSQL query with join

    - by makeee
    I'm doing a join between the "favorites" table (3 million rows) the "items" table (600k rows). The query is taking anywhere from .3 seconds to 2 seconds, and I'm hoping I can optimize it some. Favorites.faver_profile_id and Items.id are indexed. Instead of using the faver_profile_id index I created a new index on (faver_profile_id,id), which eliminated the filesort needed when sorting by id. Unfortunately this index doesn't help at all and I'll probably remove it (yay, 3 more hours of downtime to drop the index..) Any ideas on how I can optimize this query? In case it helps: Favorite.removed and Item.removed are "0" 98% of the time. Favorite.collection_id is NULL about 80% of the time. SELECT `Item`.`id`, `Item`.`source_image`, `Item`.`cached_image`, `Item`.`source_title`, `Item`.`source_url`, `Item`.`width`, `Item`.`height`, `Item`.`fave_count`, `Item`.`created` FROM `favorites` AS `Favorite` LEFT JOIN `items` AS `Item` ON (`Item`.`removed` = 0 AND `Favorite`.`notice_id` = `Item`.`id`) WHERE ((`faver_profile_id` = 1) AND (`collection_id` IS NULL) AND (`Favorite`.`removed` = 0) AND (`Item`.`removed` = '0')) ORDER BY `Favorite`.`id` desc LIMIT 50;

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  • how to avoid deadlock in mysql

    - by noam
    I have the following query (all tables are innoDB) INSERT INTO busy_machines(machine) SELECT machine FROM all_machines WHERE machine NOT IN (SELECT machine FROM busy_machines) and machine_name!='Main' LIMIT 1 Which causes a deadlock when I run it in threads, obviously because of the inner select, right? The error I get is: (1213, 'Deadlock found when trying to get lock; try restarting transaction') How can I avoid the deadlock? Is there a way to change to query to make it work, or do I need to do something else?

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  • MYSQL if statement question...

    - by Dennis_M
    Is there any way to get the if statement to evaluate a query? SELECT if(50,'EQ_Type','*') FROM EQUIPMENT; Resulting in: +-----------------------+ | IF(50,'EQ_Type','*') | +-----------------------+ | EQ_Type | | EQ_Type | | EQ_Type | | EQ_Type | | EQ_Type | | EQ_Type | | EQ_Type | | EQ_Type | | EQ_Type | +-----------------------+ 9 rows in set (0.00 sec) I would like the above statement to be equivalent to the following: SELECT 'EQ_Type' FROM EQUIPMENT; And produce: +--------------+ | EQ_Type | +--------------+ | ENGINE | | ENGINE | | ENGINE | | TRAILER | | TRAILER | | TRAILER | | WATER TENDER | | WATER TENDER | | WATER TENDER | +--------------+ Thanks for any help

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  • sql jdbc getgeneratedkeys with mysql returns column "id" not found

    - by iamrohitbanga
    I want to retrieve the most recently updated value in the table using an insert query. these are the datatypes in my sql table. int(11) // primary key auto increment, not being assigned by sqlQuery varchar(30) timestamp // has a default value. but i am explicit assigning it using CURRENT_TIMESTAMP varchar(300) varchar(300) varchar(300) int(11) varchar(300) // java code statement.executeUpdate(sqlQuery, Statement.RETURN_GENERATED_KEYS); ResultSet rs = statement.getGeneratedKeys(); System.out.println("here: " + rs.getMetaData().getColumnCount()); System.out.println("here1: " + rs.getMetaData().getColumnName(1)); // none of the following 3 works System.out.println("id: " + rs.getInt(1)); System.out.println("id: " + rs.getInt("GENERATED_KEY")); System.out.println("id: " + rs.getInt("id")); for a bit of background see this

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