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  • Mysql- "FLUSH TABLES WITH READ LOCK" started automatically

    - by ming yeow
    I would like to understand how this happened. I was running a query that would take a long time, but should not lock up any table. However, my dbs were practically down - it seems like it was being locked up by "FLUSH TABLES WITH READ LOCK" 03:21:31 select type_id, count(*) from guid_target_infos group by type_id 02:38:11 select type_id, count(*) from guid_infos group by type_id 02:24:29 FLUSH TABLES WITH READ LOCK But i did not start this command. can someone tell me why it was started automatically?

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  • Help needed with simple mysql group by query

    - by Jack
    This query fails when I add the line shown... :BEGIN FAIL: I have this so far Select Companyid, count(*) as cnt from mytable where State is not null and cnt = 1 <------------------------- FAIL group by CompanyID :END FAIL: Any way to do this? Here's a long winded background if it'll help.... I have a single table query. here's a sample of the table: CompanyID, State 1,OH 1,IL 1,NY 2,IL 3,NY 3,OH 4,NY 5,CA 5,WA I want a query that'll return something like this: 2,IL 4,NY I have this so far Select Companyid, count(*) as cnt from mytable where State is not null group by CompanyID This gives me a count of the number of records for each company. IE: 1,3 2,1 3,2 4,1 5,2 Now I want to filter the above list to just the two records with one result. I tried adding another where clause, but it failed: BEGIN FAIL: I have this so far Select Companyid, count(*) as cnt from mytable where State is not null and cnt = 1 <-------------------- FAIL group by CompanyID END FAIL:

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  • MySQL: difference of two result sets

    - by Zombies
    How can I get the set difference of two result sets? Say I have a result set (just one column in each): result1: 'a' 'b' 'c' result2: 'b' 'c' I want to minus what is in result1 by result2: result1 - result2 such that it equals: difference of result1 - result2: 'a'

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  • In PHP + MySQL, How do I join many tables with conditions

    - by Moe
    Hi, I'm trying to get the users full activity throughout the website. I need to Join many tables throughout the database, with that condition that it is one user. What I currently have written is: SELECT * FROM comments AS c JOIN rphotos AS r ON c.userID = r.userID AND c.userID = '$defineUserID'; But What it is returning is everything about the user, but it repeats rows. For instance, for one user he has 6 photos and 5 comments So I expect the join to return 11 rows. Instead it returns 30 results like so: PhotoID = 1; CommentID = 1; PhotoID = 1; CommentID = 2; PhotoID = 1; CommentID = 3; and so on... What am i doing wrong?

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  • Optimise & improve performance of this MYSQL query

    - by David
    SELECT u.id, u.honour, COUNT(*) + 1 AS rank FROM user_info u INNER JOIN user_info u2 ON u.honour < u2.honour WHERE u.id = '$id' AND u2.status = 'Alive' AND u2.rank != '14' This query is currently utterly raping my server. It works out based on your honour what rank you are within the 'user_info' table which stores it out of all our users. Screenshot for explain. http://cl.ly/370z0v2Y3v2X1t1r1k2A SELECT u.id, u.honour, COUNT(*)+1 as rank FROM user_info u USE INDEX (prestigeOptimiser) INNER JOIN user_info u2 ON u.honour < u2.honour WHERE u.id='3' AND u2.status='Alive' AND u2.rank!='14'

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  • Different meaning in the mysql code?

    - by Emre Saracoglu
    $result=mysql_query("select * from dosyabegeni where veri_id='" . get_custom_field('dwcode') . "'"); Not Working It says the number and the screen, but the application does not work veri_id='" . get_custom_field('dwcode') . "'"); veri_id='" . echo get_custom_field('dwcode') . "'"); Working veri_id='HelloTest'"); veri_id='1234567890'"); veri_id='" . $_GET['test'] . "'"); Main Codes <?php include('/home/emre2010/public_html/EntegreOz/DosyaBegeni/config.php'); $result=mysql_query("select * from dosyabegeni where veri_id='" .get_custom_field('dwcode') . "'"); while($row = mysql_fetch_array($result)) { $sira_id=$row['sira_id']; $veri_id=$row['veri_id']; $begeni=$row['begeni']; ?> <div class="reviewbox"> <div class="summarywrap"> <div class="summarywrapinner"> <div class="summary"> <div class="reviewsection"><div class="rating points"> <a href="#" class="begeni" id="<?php echo $sira_id; ?>"> <span style="color:#fff;" align="center"> <?php echo $begeni; ?> </span> </a> <p class="ratingtext">completed!</p></div> </div><div class="clear"></div> <div class="clear"></div> </div> <div class="ratingsummary"></div> <div class="clear"></div> </div> <div class="clear"></div> </div> What's the problem?

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  • Using NULL in MySQL

    - by JPro
    The data in my dabatase comes from an external source and where ever there is no data passed, I keep NULL in those places. Can anyone tell me if there are any implications in using NULL to represent empty value? Should I follow some other convention like 'data_not_available'? or something like that? Can anyone suggest?

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  • PHP & MySQL checked checkbox problem

    - by BeepU
    I'm trying to check if the checkbox has been checked and display the check mark for the user to see when they check there account settings. I want to know how can I fix this problem using PHP so that the check mark is displayed every time the user views their account settings? Here is the HTML. <input type="checkbox" name="privacy_policy" id="privacy_policy" value="yes" />

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  • Question about Benchmark funcion in Mysql ( Incredible results ).

    - by xRobot
    I have 2 tables: author with 3 millions of rows. book with 20 miles rows. . So I have benchmarked this query with a join: SELECT BENCHMARK(100000000, 'SELECT book.title, author.name FROM `book` , `author` WHERE book.id = author.book_id ') And this is the result: Query took 0.7438 sec ONLY 0.7438 seconds for 100 millions of query with a join ??? Do I make some mistakes or this is the right result ?

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  • select command in mysql doesnot return any row

    - by jeyshree
    i created a database using the command CREATE TABLE login_table2(user_name VARCHAR(32), first_name VARCHAR(32), last_name VARCHAR(32), password VARCHAR(64)); then i inserted a data using command INSERT INTO login_table2(user_name ,first_name , last_name , password ) VALUES('ramya', 'ramya', 'muthu', 'India'); the data got inserted into the table. then i inserted another set of data using command INSERT INTO login_table2(user_name ,first_name , last_name , password ) VALUES('jeyshree', 'jey', 'shree', 'India'); the data got inserted into the table too. then i gave the command SELECT first_name FROM login_table2; the command displayed all the first_ name in the table. however when i gave the command SELECT password FROM login_table2 WHERE user_name = 'ramya'; it does not fetch anything though the entry exist in the table.mention where i am going wrong.awaiting your reply.

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  • Combining 2 Mysql update statments(same col, different values, different conditions)

    - by Paul Atkins
    Hi guys, I have been doing some searching but have not been able to find an answer for this so thought I would ask here as the people here know everything :) I am trying to combine these 2 update queries into one query. UPDATE addresses SET is_default='0' WHERE id!='1' UPDATE addresses SET is_default='1' WHERE id='1' I assume this should be too hard to accomplish but i cant seem to work it out :( Thanks Paul

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  • MySQL doesn't use index in join query

    - by Kocsonya Laci
    I have two tables: comments(id(primary key), author, ip(index)) and visitors(id(primary key), date_time, ip(index)) I want to join them like that: SELECT visitors.date_time FROM comments LEFT JOIN visitors ON ( comments.ip = visitors.ip ) WHERE comments.author = 'author' LIMIT 10 It works, but very slow.. In EXPLAIN it shows that it doesn't use the index on the visitors table: id select_type table type possible_keys key key_len ref rows Extra 1 SIMPLE comments ref author author 78 const 9660 Using where 1 SIMPLE visitors ALL NULL NULL NULL NULL 8033 Any ideas? Thanks!

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  • Best database (mysql) structure for this case:

    - by robert
    we have three types of data (tables): Book (id,name,author...) ( about 3 million of rows) Category (id,name) ( about 2000 rows) Location (id,name) ( about 10000 rows) A Book must have at least 1 type of Category (up to 3) AND a Book must have only one Location. I need to correlate this data to get this query faster: Select Books where Category = 'cat_id' AND Location = 'loc_id' Select Books where match(name) against ('name of book') AND Location = 'loc_id' Please I need some help. Thanks

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  • [mysql] having a number in

    - by Wiika
    Hi all, ID Name Hidden 1 Mika 1,4,2 2 Loca 0 3 Nosta 4 4 Like 2 can someone give me a query that will return as a result rows ID 1 & 3 something like this SELECT * FROM table WHERE Hidden HAVING(4) Thanks, I Appreciate

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  • mysql select update

    - by Tillebeck
    Hi I have read quite a few selcet+update questions in here but cannot understand how to do it. So will have to ask from the beginning. I would like to update a table based on data in another table. Setup is like this: - TABLE a ( int ; string ) ID WORD 1 banana 2 orange 3 apple - TABLE b ( "comma separated" string ; string ) WORDS TEXTAREA 0 banana -> 0,1 0 orange apple apple -> BEST:0,2,3 ELSE 0,2,3,3 0 banana orange apple -> 0,1,2,3 Now I would like to for each word in TABLE a append ",a.ID" to b.WORDS like: SELECT id, word FROM a (for each) -> UPDATE b SET words = CONCAT(words, ',', a.id) WHERE b.textarea like %a.word% Or even better: replace the word found in b.textarea with ",a.id" so it is the b.textarea that ends up beeing a comma separeted string of id's... But I do not know if that is possible.

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  • C#:checking existing record in database Mysql

    - by Meko
    HI.I searched this question inform and I found solution to change column property Unique Index.Now If I try to insert same record cmd.ExecuteNonQuery() gives error that record exist ,but how can use this exception to give user a message that record exist and must enter new one ? I am trying to make some thing like if(cmd.ExecuteNonQuery() !=true ) { MessageBox.Show("User Exists"); } But I dont know what returns cmd.ExecuteNonQuery() ? Or I must get records using reader in table and compare them with text in Textfiel?

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  • MySQL inner join different results

    - by Darryl at NetHosted
    I am trying to work out why the following two queries return different results: SELECT DISTINCT i.id, i.date FROM `tblinvoices` i INNER JOIN `tblinvoiceitems` it ON it.userid=i.userid INNER JOIN `tblcustomfieldsvalues` cf ON it.relid=cf.relid WHERE i.`tax` = 0 AND i.`date` BETWEEN '2012-07-01' AND '2012-09-31' and SELECT DISTINCT i.id, i.date FROM `tblinvoices` i WHERE i.`tax` = 0 AND i.`date` BETWEEN '2012-07-01' AND '2012-09-31' Obviously the difference is the inner join here, but I don't understand why the one with the inner join is returning less results than the one without it, I would have thought since I didn't do any cross table references they should return the same results. The final query I am working towards is SELECT DISTINCT i.id, i.date FROM `tblinvoices` i INNER JOIN `tblinvoiceitems` it ON it.userid=i.userid INNER JOIN `tblcustomfieldsvalues` cf ON it.relid=cf.relid WHERE cf.`fieldid` =5 AND cf.`value` REGEXP '[A-Za-z]' AND i.`tax` = 0 AND i.`date` BETWEEN '2012-07-01' AND '2012-09-31' But because of the different results that seem incorrect when I add the inner join (it removes some results that should be valid) it's not working at present, thanks.

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  • Dividing numbers between rows in MySQL + PHP

    - by André Figueira
    Hi I am working on a kind of raffle system which divides 1 million random numbers into an x amount of tickets, e.g. 1 million random numbers to 10,000 tickets. Each ticket is a row in a database, we then have another table ticket numbers in which i need to give 100 numbers to each ticket they are related by the ticket id. So at the moment this is my code: //Amount of the 1 million tickets divided to the tickets $numbersPerTickets = $_POST['numbersPerTicket']; //The total cost of the property $propertyPrice = $_POST['propertyPrice']; //The total amount of tickets $totalTickets = NUMBER_CIELING / $numbersPerTickets; //The ticket price $ticketPrice = $propertyPrice / $totalTickets; //Generate array with random numbers up to 999,999 $randomTicketNumbers = createTicketNumbers(); //Creation loop counter $ticketCreationCount = 1; //Loop and create each ticket while($ticketCreationCount <= $totalTickets) { //Create a padded ticket number $ticketNumber = str_pad($ticketCreationCount, 6, 0, STR_PAD_LEFT); $query = ' INSERT INTO tickets( propertyID, ticketNumber, price ) VALUES( "'.$propertyID.'", "'.$ticketNumber.'", "'.$ticketPrice.'" ) '; $db->query($query); //Get the ID of the inserted ticket to use to insert the ticket numbers $ticketID = $db->insert_id; $loopBreak = $numbersPerTickets; $addedNumberCount = 1; foreach($randomTicketNumbers as $key => $value) { $query = ' INSERT INTO ticketNumbers( ticketID, number ) VALUES( "'.$ticketID.'", "'.$value.'" ) '; $db->query($query); unset($randomTicketNumbers[$key]); if($addedNumberCount == $loopBreak){ break; }else{ $addedNumberCount++; } } $ticketCreationCount++; } But this isn't working it adds the right amount of tickets, which in the case for testing is 10,000 but then adds far too many ticket numbers, it ends up exceeding the million numbers in the random tickets array, The random tickets array is just a simple 1 tier array with 1 million numbers sorted randomly.

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  • MySQL whats wrong with my foreign keys?

    - by Skiy
    Hello, what is wrong with the two foreign keys which I have marked with comments? create database db; use db; create table Flug( Flugbez varchar(20), FDatum Date, Ziel varchar(20), Flugzeit int, Entfernung int, Primary Key (Flugbez, FDatum)); create table Flugzeugtyp( Typ varchar(20), Hersteller varchar(20), SitzAnzahl int, Reisegeschw int, primary key (Typ) ); create table flugzeug( Typ varchar(20), SerienNr int, AnschDatum Date, FlugStd int, primary key(Typ,SerienNr), foreign key(Typ) references Flugzeugtyp(Typ)); create table Abflug( Flugbez varchar(20), FDatum Date, Typ varchar(20), Seriennr int, Kaptaen varchar(20), Primary key(Flugbez,FDatum,Typ,SerienNr), Foreign key(Flugbez) references Flug(Flugbez), -- Foreign key(FDatum) references Flug(FDatum), Foreign key(Typ) references Flugzeugtyp(Typ) -- ,Foreign key(SerienNr) references Flugzeug(SerienNr) ); When I uncomment these, I get: ERROR 1005 (HY000): Can't create table 'db.abflug' (errno: 150)

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  • MYSQL - SImple database design

    - by sequelDesigner
    Hello guys, I would like to develop a system, where user will get the data dynamically(what I mean dynamic is, without reloading pages, using AJAX.. but well, it does not matter much). My situation is like this. I have this table, I called it "player", in this player table, I will store the player information like, player name, level, experience etc. Each player can have different clothes, start from tops(shirts), bottoms, shoes, and hairstyle, and each player can have more than 1 tops, bottoms, shoes etc. What I am hesitated or not very sure about is, how do you normally store the data? My current design is like this: Player Table =========================================================================================== id | name | (others player's info) | wearing | tops | bottoms =========================================================================================== 1 | player1 | | top=1;bottom=2;shoes=5;hair=8 | 1,2,3| 7,2,3 Tops Table ===================== id | name | etc... ===================== 1 | t-shirt | ... I am not sure if this design is good. If you are the database designer, how would you design the database? Or how you will store them? Please advise. Thanks

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  • Entering Content Into A MySQL Database Via A Form

    - by ThatMacLad
    I've been working on creating a form that submits content into my database but I decided that rather than using a drop down menu to select the date I'd rather use a textfield. I was wondering what changes I will need to make to my table creation file. <?php mysql_connect ('localhost', 'root', 'root') ; mysql_select_db ('tmlblog'); $sql = "CREATE TABLE php_blog ( id int(20) NOT NULL auto_increment, timestamp int(20) NOT NULL, title varchar(255) NOT NULL, entry longtext NOT NULL, PRIMARY KEY (id) )"; $result = mysql_query($sql) or print ("Can't create the table 'php_blog' in the database.<br />" . $sql . "<br />" . mysql_error()); mysql_close(); if ($result != false) { echo "Table 'php_blog' was successfully created."; } ?> It's the timestamp that I need to edit to enter in via a textfield. The Title and Entry are currently being entered via that method anyway.

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