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  • ResultSet and aggregation

    - by kachanov
    Ok, I admit my situation is special There is a data system that supports SQL-92 and JDBC interface However the SQL requets are pretty expensive, and in my application I need to retreive the same data multiple times and aggregate it ("group by") on different fields to show different dimensions of the same data. For example on one screen I have three tables that show the same set or records but aggregated by City (1st grid), by Population (2nd grid), by number of babies (3rd grid) This amounts to 3 SQL queries (which is very slow), UNLESS anyone of you can suggest any idea any library from apache commons or from google code, so that I can select all records into ResultSet and get 3 arrays of data group by different fields from this single ResultSet. Am I'm missing some obvious and unexpected solution to this problem?

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  • Page not rewriting in ExpressionEngine

    - by Andrew
    I recently just launched an ExpressionEngine site and one of the last steps I take is removing index.php from the URL. In the case of this site, the default template group is called "site". Long story short, after removing index.php from the URL, all pages continue to work great with the exception of my contact page, which also lives in the "site" template group. Going to http://example.com/contact/ gives me a 404 while going to http://example.com/site/contact produces the desired result. In past ExpressionEngine site setups (including my own) this has never happened, so does anyone have thoughts on why this might not be working?

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  • MySQL Count If using 4 tables or Perl

    - by user1726133
    Hi I have a relatively convoluted query that relies on 4 different tables, unfortunately I do not have control of this data, but I do have to query it. I ran this simpler query and it works using just table 1 and table 2 SELECT actor, receiver, count(IF(t2.group1 = "anxiety behavior", 1,0)) AS 'anxiety' FROM ethogram_edited_obs_behaviors t1 JOIN ethogram_behaviors t2 on t1.behavior = t2.behavior_code GROUP BY actor; Below are the 4 tables I need and the query I tried that didn't work Table 1 | Table 2 | Table 3 | Table 4 Actor | Behavior | Behavior | type of Behavior | subject | sex | subject |subject_code er frown | frown anxiety behavior | Eric M | Eric | er Here is the query that is failing SELECT actor, count(IF(t2.group1 = "anxiety behavior", 1,0) AND(t3.sex = "M", 1,0)) AS 'anxiety', FROM ethogram_edited_obs_behaviors t1 JOIN ethogram_behaviors t2 on t1.behavior = t2.behavior_code JOIN subject_code t3 on t1.actor = t3.behavior_code1 JOIN subjects t4 on t3.subject = t4.yerkes_code GROUP BY actor; Any help would be much appreciated!! Thanks :) P.S. if this is easier to do in Perl tips also much appreciated

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  • Aggregate functions in ANSI SQL

    - by morpheous
    I want to use multiple aggregate functions in a query. All the examples i have seem on aggregate functions however, are trivial. Typically, they are of the form: SELECT field1,agg_func1, agg_func2 GROUP BY SOME_COLUMNS HAVING agg_func1 OP SOME_SCALAR Where: OP: is a boolean operator (e.g. <, = etc) SOME_SCALAR: is a scalar (i.e. a constant number) What I want to know is if it is possible to write (IN ANSI SQL) queries like: SELECT field1,agg_func1, agg_func2, agg_func3 GROUP BY SOME_COLUMNS HAVING (agg_func1 OP1 agg_func2) OP2 (agg_func2 OP3 agg_func3) Where: OP[N] are boolean operators or ANSI SQL clause operators like 'BETWEEN', 'LIKE', 'IN' etc. Also, assuming this is possible (I have not seen any documentation saying otherwise) are there any efficiency/performance considerations (i.e. penalties) when the HAVING clause consists of a boolean expression combining the output of the aggregate functions - instead of the normal comparison of the output of the aggregate with a constant number (e.g. min('salary') 100 ) - which is often used in the most banal examples involving aggregate functions?

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  • LINQ count query returns a 1 instead of a 0

    - by user335810
    I have the following view:- CREATE VIEW tbl_adjudicator_result_view AS SELECT a.adjudicator_id, sar.section_adjudicator_role_id, s.section_id, sdr.section_dance_role_id, d.dance_id, c.contact_id, ro.round_id, r.result_id, c.title, c.first_name, c.last_name, d.name, r.value, ro.type FROM tbl_adjudicator a INNER JOIN tbl_section_adjudicator_role sar on sar.section_adjudicator_role2adjudicator = a.adjudicator_id INNER JOIN tbl_section s on sar.section_adjudicator_role2section = s.section_id INNER JOIN tbl_section_dance_role sdr on sdr.section_dance_role2section = s.section_id INNER JOIN tbl_dance d on sdr.section_dance_role2dance = d.dance_id INNER JOIN tbl_contact c on a.adjudicator2contact = c.contact_id INNER JOIN tbl_round ro on ro.round2section = s.section_id LEFT OUTER JOIN tbl_result r on r.result2adjudicator = a.adjudicator_id AND r.result2dance = d.dance_id When I run the following query directly against the db I get 0 in the count column where there is no result select adjudicator_id, first_name, COUNT(result_id) from tbl_adjudicator_result_view arv where arv.round_id = 16 group by adjudicator_id, first_name However when I use LINQ query I always get 1 in the Count Column var query = from arv in db.AdjudicatorResultViews where arv.round_id == id group arv by new { arv.adjudicator_id, arv.first_name} into grp select new AdjudicatorResultViewGroupedByDance { AdjudicatorId = grp.Key.adjudicator_id, FirstName = grp.Key.first_name, Count = grp.Select(p => p.result_id).Distinct().Count() }; What do I need to change in the View / Linq query.

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  • best way to add route under resource in Laravel 4

    - by passingby
    I would like know if there is a better way to add additional route aside from the default of resource in Laravel 4. I have this code below which is no problem with regard to the functionality, it's just that it seems to be long: <?php Route::group(array('before' => 'auth'), function() { # API Route::group(array('prefix' => 'api'), function() { Route::resource('projects', 'ProjectsController'); Route::resource('projects.groups', 'GroupsController'); Route::post('/projects/{projects}/groups/{groups}/reorder', 'GroupsController@reorder'); }); }); If in Rails Rails.application.routes.draw do # API namespace :api, defaults: { format: 'json' } do scope module: :v1 do resources :projects do resources :groups do member do post :reorder end end end end end end

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  • Nested attributes form for model which belongs_to few models

    - by ExiRe
    I have few models - User, Teacher and TeacherLeader. class User < ActiveRecord::Base attr_accessible ..., :teacher_attributes has_one :teacher has_one :teacher_leader accepts_nested_attributes_for :teacher_leader end class Teacher < ActiveRecord::Base belongs_to :user has_one :teacher_leader end class TeacherLeader < ActiveRecord::Base belongs_to :user belongs_to :teacher end I would like to fill TeacherLeader via nested attributes. So, i do such things in controller: class TeacherLeadersController < ApplicationController ... def new @user = User.new @teacher_leader = @user.build_teacher_leader @teachers_collection = Teacher.all.collect do |t| [ "#{t.teacher_last_name} #{t.teacher_first_name} #{t.teacher_middle_name}", t.id ] end @choosen_teacher = @teachers_collection.first.last unless @teachers_collection.empty? end end And also have such view (new.html.erb): <%= form_for @user, :url => teacher_leaders_url, :html => {:class => "form-horizontal"} do |f| %> <%= field_set_tag do %> <% f.fields_for :teacher_leader do |tl| %> <div class="control-group"> <%= tl.label :teacher_id, "Teacher names", :class => "control-label" %> <div class="controls"> <%= select_tag( :teacher_id, options_for_select( @teachers_collection, @choosen_teacher )) %> </div> </div> <% end %> <div class="control-group"> <%= f.label :user_login, "Login", :class => "control-label" %> <div class="controls"> <%= f.text_field :user_login, :placeholder => @everpresent_field_placeholder %> </div> </div> <div class="control-group"> <%= f.label :password, "Pass", :class => "control-label" %> <div class="controls"> <%= f.text_field :password, :placeholder => @everpresent_field_placeholder %> </div> </div> <% end %> <%= f.submit "Create", :class => "btn btn-large btn-success" %> <% end %> Problem is that select form here does NOT appear. Why? Do i do something wrong?

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  • PHP is_file returns false (incorrectly) for Windows share on Ubuntu

    - by M3Mania
    Ubuntu server, PHP 5.3, connected via Samba to Windows server share. I am using file_exists() to check for availability of file on Windows machine. It returns false, although the filepath does exist. Meanwhile, file_get_contents() on the exact same filepath works fine. I'm wondering if it's a permission issue, since I'm having trouble configuring permissions of the files on the Windows share (it says I don't have permission to change permissions on them). When I look at the permissions through Nautilus, it says the user and group are both root, with 755 rights. I'd like to change the group to www-data, but can't seem to do it.

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  • How should I join these 3 SQL queries in Oracle?

    - by Nazgulled
    I have these 3 queries: SELECT title, year, MovieGenres(m.mid) genres, MovieDirectors(m.mid) directors, MovieWriters(m.mid) writers, synopsis, poster_url FROM movies m WHERE m.mid = 1; SELECT AVG(rating) FROM movie_ratings WHERE mid = 1; SELECT COUNT(rating) FROM movie_ratings WHERE mid = 1; And I need to join them into a single query. I was able to do it like this: SELECT title, year, MovieGenres(m.mid) genres, MovieDirectors(m.mid) directors, MovieWriters(m.mid) writers, synopsis, poster_url, AVG(rating) average, COUNT(rating) count FROM movies m INNER JOIN movie_ratings mr ON m.mid = mr.mid WHERE m.mid = 1 GROUP BY title, year, MovieGenres(m.mid), MovieDirectors(m.mid), MovieWriters(m.mid), synopsis, poster_url; But I don't really like that "huge" GROUP BY, is there a simpler way to do it?

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  • SVN: authz directory identifiers not support

    - by ledy
    Without using the authz, all the svn users can login and use the repos without issues. However, I would like to limit the access to some directories - not to be readable or writeable for all users. svnserve --version = 1.6.6 I tried both, granting access to users and groups. I also tried it separate, only group or only user access. [groups] admingroup=i_can_access_anything limitedgroup=i_am_limited [/] #*= @admingroup=rw i_can_access_anything=rw [projectX] #i also tried [repository:/projectX] #*= @limitedgroup=rw i_am_limited=rw Trying to access the / or /projectX at the svn fails. = access denied Without the authz, it works properly, but also grants access to other projects that do not belong to the "limited" user group :-/ Do you see what's wrong there? Thx

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  • Shell Script- each unique user

    - by Dinis Monteiro
    Hi guys I need "for each unique user, report which group they are a member of and when they last logged in" so i have: #!/bin/sh echo "Your initial login:" who | cut -d' ' -f1 | sort | uniq echo "Now is logged:" whoami echo "Group ID:" id -G $whoami case $1 in "-l") last -Fn 10 | tr -s " " ;; *) last -Fn 10 | tr -s " " | egrep -v '(^reboot)|(^$)|(^wtmp a)|(^ftp)' | cut -d" " -f1,5,7 | sort -uM | uniq -c esac My question is: how i can show the each unique user? the script above only show the more recent user logged in the system, but i need all unique users. anyone can help? thanks

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  • I have a SID of a user account, and I want the SIDs of the groups it belongs to. (C#)

    - by JCCyC
    This has to be obtained from a remote machine. The following query works not for SIDs, but for group and account names. "SELECT GroupComponent FROM Win32_GroupUser WHERE PartComponent = \"Win32_UserAccount.Domain='" + accountDomain + "',Name='" + accountName + "'\"" The Win32_Group objects it returns come in the forms of strings, and they only have domain and name (even though Win32_Group has a SID property). I have this sinking feeling I'll have to: Turn the SID into an account name by querying Win32_SID; Perform the query above; Turn each of the resulting group names into SIDs by querying Win32_Group. PLEASE tell me there's a better way.

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  • Achieving AES-256 Channel Encryption with the .NET Compact Framework

    - by Ev
    Hi There, I am working on a business application where the clients are Windows Mobile 6.1 Professional devices. The server is a Java enterprise application. The industry working group recommends AES-256 encryption for client/server communications. This is necessary to gain certification. The encryption doesn't necessarily need to be channel encryption, it could be payload encryption. Channel encryption is preferable. The client and server communicate using SOAP/HTTP, which we are yet to implement. We plan to use WCF on the compact framework. In order to alleviate some of the work required to implement manual encryption/decryption, it would be nice if we could achieve the required encryption either at the TLS level, or somehow using the WS-* standards (I'm not particularly familiar with that group of technologies but I am learning right now). The server supports https with 256-bit AES. Does anybody have an idea on the best way to implement this? Thanks in advance.

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  • A linq join combined with a regex

    - by Geert Beckx
    Is it possible to combine these 2 queries or would this make my code too complex? Also I think there should be a performance gain by combining these queries since I think in the near future my source table could be over 11000 records. This is what i came up with so far : Dim lit As LiteralControl ' check characters not in alphabet Dim r As New Regex("^[^a-zA-Z]+") Dim query = From o In source.ToTable _ Where r.IsMatch(o.Field(Of String)("nam")) lit = New LiteralControl(String.Format("letter: {0}, count: {1}<br />", "0-9", query.Count)) plhAlpabetLinks.Controls.Add(lit) Dim q = From l In "ABCDEFGHIJKLMNOPQRSTUVWXYZ".ToLower.ToCharArray _ Group Join o In source.ToTable _ On l Equals o.Field(Of String)("nam").ToLowerInvariant(0) Into g = Group _ Select l, g.Count ' iterate the alphabet to generate all the links. For Each letter In q.AsEnumerable lit = New LiteralControl(String.Format("letter: {0}, count: {1}<br />", letter.l, letter.Count)) plhAlpabetLinks.Controls.Add(lit) Next Kind regards, G.

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  • how to add column in SQL Query that incl. LEFT OUTER JOIN

    - by radbyx
    I have this Query: SELECT p.ProductName, dt.MaxTimeStamp, p.Responsible FROM Product p LEFT JOIN (SELECT ProductID, MAX(TimeStamp) AS MaxTimeStamp FROM StateLog WHERE State = 0 GROUP BY ProductID, Status) dt ON p.ProductID = dt.ProductID ORDER BY p.ProductName; It works like it should, but now I need to SELECT "State" out too. The tricky part is, that I only want the lastest "TimeStamp" where "State" was false. But now I also need the "State" for the lastest "TimeStamp". I tried this: SELECT p.ProductName, dt.State, dt.MaxTimeStamp, p.Responsible FROM Product p LEFT JOIN (SELECT ProductID, MAX(TimeStamp) AS MaxTimeStamp, State FROM StateLog WHERE State = 0 GROUP BY ProductID, Status) dt ON p.ProductID =dt.ProductID ORDER BY p.ProductName; But it didn't work, because it gave me the "State" for the lastest "TimeStamp". So I hope there is some clever heads out there that can help me. I'm guessing that this is either very simple or very hard to solve.

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  • Unknown Column?

    - by Kenny
    ok im trying to get mutual friends between these Two users, user1 and user92 This is the sql that is successful in displaying them SELECT IF(user_a = 1 OR user_a = 92, user_b, user_a) friend FROM friendship WHERE (user_a = 1 OR user_a = 92) OR (user_b = 1 OR user_b = 92) GROUP BY 1 HAVING COUNT(*) > 1 THis is how it looks friend 61 72 73 74 75 76 77 78 79 80 81 So now i want to select all users after the number 72, and i try to do it with this sql but its not working? It gives me the error, "unknown coulum name friend in where clause" SELECT IF(user_a = 1 OR user_a = 92, user_b, user_a) friend FROM friendship WHERE friend > 72 and (user_a = 1 OR user_a = 92) OR (user_b = 1 OR user_b = 92) GROUP BY 1 HAVING COUNT(*) > 1 what am i doing wrong? or what is the correct way?? thx

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  • Alternative to 'where col in (list)' for MySQL

    - by user210481
    Hi I have the following table T: id 1 2 3 4 col a b a c I want to do a select that returns the id,col when group by(col) having count(col)1 One way of doing it is SELECT id,col FROM T WHERE col IN (SELECT col FROM T GROUP BY(col) HAVING COUNT(col)>1); The intern select (from the right) returns 'a' and main one (left) will return 1,a and 3,a The problem is that the where in statement seems to be extremely slow. In my real case, the results from the internal select has many 'col's, something about 70000 and it's taking hours. Right now it's much faster to do the internal select and the main select getting all ids and upcs and do the intersection locally. MySQL should be able to handle this kind of query efficiently. Can I substitute the where in for a join or something faster? Thanks

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  • Having a Link Only Appear If a Logged-In User Appears on a Dynamic List

    - by John
    Hello, For the function below, I would like the link <div class="footervote"><a href="http://www...com/.../footervote.php">Vote</a></div> to only appear if the logged in user currently appears on editorlist.php. (I. e. if the loginid in the function corresponds to any of the usernames that currently appear in editorlist.php.) Appearing on editorlist.php is something that is dynamic. How can I do this? Thanks in advance, John function show_userbox() { // retrieve the session information $u = $_SESSION['username']; $uid = $_SESSION['loginid']; // display the user box echo '<div id="userbox"> <div class="username">'.$u.'</div> <div class="submit"><a href="http://www...com/.../submit.php">Submit an item.</a></div> <div class="changepassword"><a href="http://www...com/.../changepassword.php">Change Password</a></div> <div class="logout"><a href="http://www...com/.../logout.php">Logout</a></div> <div class="footervote"><a href="http://www...com/.../footervote.php">Vote</a></div> </div>'; } On editorlist.php: $sqlStr = "SELECT l.loginid, l.username, l.created, DATEDIFF(NOW(), l.created) AS days, COALESCE(s.total, 0) AS countSubmissions, COALESCE(c.total, 0) AS countComments, COALESCE(s.total, 0) * 10 + COALESCE(c.total, 0) AS totalScore, DATEDIFF(NOW(), l.created) + COALESCE(s.total, 0) * 10 + COALESCE(c.total, 0) AS totalScore2 FROM login l LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM submission GROUP BY loginid ) s ON l.loginid = s.loginid LEFT JOIN ( SELECT loginid, COUNT(1) AS total FROM comment GROUP BY loginid ) c ON l.loginid = c.loginid GROUP BY l.loginid ORDER BY totalScore2 DESC LIMIT 10"; $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"samplesrec1edit\">"; while ($row = mysql_fetch_array($result)) { echo '<tr>'; echo '<td class="sitename1edit1"><a href="http://www...com/.../members/index.php?profile='.$row["username"].'">'.stripslashes($row["username"]).'</a></td>'; echo '<td class="sitename1edit2">'.($row["countSubmissions"]).'</td>'; echo '<td class="sitename1edit2">'.($row["countComments"]).'</td>'; echo '<td class="sitename1edit2">'.($row["days"]).'</td>'; echo '<td class="sitename1edit2">'.($row["totalScore2"]).'</td>'; echo '</tr>'; } echo "</table>";

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  • XML and .NET: How to replace specific node with many other ones loaded from raw xml data

    - by Entrase
    Let's suppose we have an element like this one in the main xml file: <group name="gr1" filename="groups/gr1.xml"/>. The second file gr1.xml contains something like this: <item name="i1">Item one</item> <item name="i2">Item two</item> <item name="i3">Item three</item> Note that there is no XML declaration in gr1.xml, just plain items without single parent node. So… Which is the best way to replace <group/> with its <item/>s? I have already tried some things like manual enclosing of gr1.xml content into a single node with XML declaration and loading it into XmlDocument, but it doesn't look like a good solution.

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  • getting rich text from the X clipboard

    - by intuited
    How can rich text be obtained from the X clipboard? For example, if you copy some text from a web browser and paste it into kompozer, it pastes as HTML, with links etc. preserved. However, xclip -o for the same selection just outputs plain text. I'd like to pull the HTML out and into a text editor.

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  • Rails 3 render :partials

    - by user297221
    Hi guys. I am migrating my 1.8.7 rails app to rails 3. But I have a problem with a partial: I have the following partial: in my cms controller : @clients = Client.all group = render_to_string :layout = 'layouts/window', :partial = 'clients/index' in my "clients/index" partial: <%= render :partial = 'clients/item', :collection = @clients % This worked great with rails 1.7.8 but with rails 3 only the partial in the index get's rendered!. So, to clarify this, the group variable in the controller doesn't get the html from the layout. Also the weird thing is that the window layout is _window.erb (if I do window.html.erb or just window.erb rails can't find it which is strange). Does anybody know if this behavior is normal for rails 3? thanxs!

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  • what is a fast way to output h5py dataset to text?

    - by user362761
    I am using the h5py python package to read files in HDF5 format. (e.g. somefile.h5) I would like to write the contents of a dataset to a text file. For example, I would like to create a text file with the following contents: 1,20,31,75,142,324,78,12,3,90,8,21,1 I am able to access the dataset in python using this code: import h5py f = h5py.File('/Users/Me/Desktop/thefile.h5', 'r') group = f['/level1/level2/level3'] dset = group['dsetname'] My naive approach is too slow, because my dataset has over 20000 entries: # write all values to file for index in range(len(dset)): # do not add comma after last value if index == len(dset)-1: txtfile.write(repr(dset[index])) else: txtfile.write(repr(dset[index])+',') txtfile.close() return None Is there a faster way to write this to a file? Perhaps I could convert the dataset into a NumPy array or even a Python list, and then use some file-writing tool? (I could experiment with concatenating the values into a larger string before writing to file, but I'm hoping there's something entirely more elegant)

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  • How do I create a point system in a Rails app that assigns points to users and non-authenticated-use

    - by codyvbrown
    I'm building a question and answer application on top of twitter and I'm hitting some snags because I'm inevitably dealing with two classes of users: authenticated and non-authenticated. The site enable users to give points to other users, who may or may not be authenticated, and I want to create a site-wide point system where the application stores and displays this information on their profile. I want to save this point data to the user because that would be faster and more efficient but non-authenticated users aren't in our system, we only have the twitter handle. So instead we display the points in our system like this: @points = point.all( :select => "tag, count(*) AS count", # Return tag and count :group => 'tag', # Group by the tag :order => "2 desc", :conditions => {:twitter_handle => params[:username]}) Is there a better way to do this? Is there a better way to associate data with non-authenticated users?

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