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  • type casting in mysql

    - by muralikalpana
    i have passportno(varchar) in database. i am entering values like this 001,002,003. and i want to display like sorting order. now i wrote query like this "select * from passport_registration where status=1 ORDER BY passportno" then displaying output like this......077,088,099,100,1000,1001,1009,101,1010 i want to diplay sort order. how to do?

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  • Mysql insert into 2 tables

    - by Spidfire
    I want to make a insert into 2 tables visits: visit_id int | card_id int registration: registration_id int | type enum('in','out') | timestamp int | visit_id int i want something like: INSERT INTO `visits` as v ,`registration` as v (v.`visit_id`,v.`card_id`,r.`registration_id`, r.`type`, r.`timestamp`, r.`visit_id`) VALUES (NULL, 12131141,NULL, UNIX_TIMESTAMP(), v.`visit_id`); I wonder if its possible

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  • MySQL select date, join statistic data - how?

    - by Webnet
    I have some statistics I need to report on a monthly basis. I need my query to return 0's for statistics which aren't there. The only way I know to do this is to use SQL to generate a list of days within the specified time period and LEFT JOIN the statistic data that I need to report on. Problem is.... I've never not selected from a table like that... how do I do that?

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  • Multidimensional Array To Mysql Codeigniter

    - by rochellecanale
    A little help how can I create an input query using this array? Or how can I pass it in the table? my table layout sample is this: sales_table id | product_name | price | qty | subtotal This is derived from the var_dump() function. Here is my code in array //array code from unserialized function $products = unserialize($this->session->userdata('product_list')); //This is the output. Array ( [2] => Array ( [id] => 2 [product_name] => NOKIA 5110 [product_desc] => Cellphone [product_price] => 500.00 [product_qty] => 1 [product_amount] => 500 [product_code] => NOKI2012-84353 ) [3] => Array ( [id] => 3 [product_name] => HP IPAQ RW6828 [product_desc] => Cellphone [product_price] => 1500.00 [product_qty] => 1 [product_amount] => 1500 [product_code] => HP I2012-08386 ) )

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  • php mysql , update query is not working

    - by Michael
    I'm trying to update some info into database but for some reasons it doesn't update. Also I'm not getting error in the server logs. mysql_query("UPDATE `view_item` SET `item_number` = $item_number, `title` = $title, `price` = $price, `shipping` = $shipping, `location` = $location, `start_time` = $start_time, `end_time` = $end_time, `seller_userName` = $seller_userName, `seller_UserNum` = $seller_UserNum, `number_of_bids` = $number_of_bids, `picture_link` = $picture_link WHERE `item_number` = $item_number");

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  • MySQL Multiple "AND" Query

    - by Mark J
    I have a table with 2 columns (see below). A member can have multiple responses to a question RESPONSES --------- member_id INT response_id INT SAMPLE DATA member_id -- response_id 1 -- 3 1 -- 5 2 -- 1 2 -- 5 2 -- 9 3 -- 1 3 -- 5 3 -- 6 What I need to do is query the table for member that meet ALL response criteria. For example I need to select all members that have a response_id of 1 AND 5. I am using the following query: SELECT DISTINCT member_id FROM responses WHERE response_id = 1 AND response_id = 5. I would expect to get back member_id's 2,3. However I am getting nothing returned. I used EXPLAIN and it shows there is an error in my where query. What am I doing wrong? Also, is there a function similar to IN where all the criteria must be met in order to return true? Thanks for your help.

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  • MySQL count statements error - operand should contain 1 column(s)

    - by jason
    I am trying to do multiple counts everyone was working accept the first sub select (list1) I get an error that reads "Operand should contain 1 column(s)" i'm guessing it has something to do with the AND, but i'm not sure how I would fix this one. Select Count(list0.ustatus) AS finished_count, (Select list1.ustatus, Count(*) From listofupdates list1 Where list1.ustarted != '0000-00-00 00:00:00' AND list1.ustatus != 1) AS start_count, (Select Count(list2.udifficulty) From listofupdates list2 Where list2.udifficulty = 2) AS recheck_count, (Select Count(list3.udifficulty) From listofupdates list3 Where list3.udifficulty = 4) AS question_count From listofupdates list0 Where list0.ustatus = 1

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  • My MYSQL & PHP while code is out of memory, when there is only one row

    - by Sam
    Hey all, why is this code throwing an out of memory error, when there is only 1 row in the database.. $request_db = mysql_query("SELECT * FROM requests WHERE haveplayed='0'") or die(mysql_error()); $request = mysql_fetch_array( $request_db ); echo "<table border=\"1\" align=\"center\">"; while ( $request['haveplayed'] == "0" ) { echo "<tr><td>"; echo $request['SongName']; echo "</td><td>"; echo "<tr><td>"; echo $request['Artist']; echo "</td><td>"; echo "<tr><td>"; echo $request['DedicatedTo']; echo "</td><td>"; } echo "</table>"; Thanks.

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  • changing existing duplicate entries in mysql

    - by Mladen
    sorry for the (probably) noob question, but I', new at this stuff. i have a table that has column 'position', and I want to, when inserting a new row, change positions of every row that has position lower than row that is inserted. for example, if I add row with position 4, if there is a duplicate, it should become 5, 5 should shift to 6 and so on... also, is there a way to get highest value for column besides testing it in every row via php?

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  • How to get this done in mysql?

    - by bala3569
    Consider i have a registartion table and there is field prefLocationId and it contains value like this 1,2,3,2,1,4 and so many.... And i have a table prefLocation which looks like this Id LocationName 1 Chennai 2 Mumbai 3 Kolkatta 4 Delhi and i want to select record of users and show values like Chennai,Mumbai,Kolkatta,Mumbai,Chennai,Delhi and so on...

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  • MySQL: Order by time (MM:SS)?

    - by Shpigford
    I'm currently storing various metadata about videos and one of those bits of data is the length of a video. So if a video is 10 minutes 35 seconds long, it's saved as "10:35" in the database. But what I'd like to do is retrieve a listing of videos by length (longest first, shortest last). The problem I'm having is that if a video is "2:56", it's coming up as longest because the number 2 is more than the number 1 in. So, how can I order data based on that length field so that "10:35" is recognized as being longer than "2:56" (as per my example)?

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  • MYSQL: Udate table column from subquery result

    - by Jhourlad Estrella
    On the Members table are columns "MemberID" and "PointsEarned". I want to update the PointsEarned column from the result of this query: SELECT m.MemberID, m.UserName, ( (SELECT COUNT(*) FROM EventsLog as e WHERE e.MemberID=m.MemberID AND e.EventsTypeID=2)*10 ) + ( (SELECT COUNT(*) FROM EventsLog as e WHERE e.MemberID=m.MemberID AND e.EventsTypeID=3)*3 ) + ( (SELECT COUNT(*) FROM ChatMessages as c WHERE c.MemberID=m.MemberID)*.1 ) as PointsEarned FROM Members as m Can anybody tell me how I should do it with a single query? Thanks!

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  • MYSQL Query using subquery

    - by Michael Quiles
    Cant get this to work can any one help. List the part number, part description, and on_hand value of each part whose number of units on hand is more than the average number of units onhand for all parts use a subquery? SELECT PART_NUM, DESCRIPTION, SUM(ON_HAND * PRICE) ON_HAND_VALUE FROM PART; WHERE MAX(ON_HAND); (AVG(ON_HAND) > ON_HAND);

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  • Seeking assistance with Escaping Data for MySQL queries

    - by JM4
    Please don't send me a link to php.net referencing mysql_real_escape_string as the only response. I have read through the page and while I understand the general concepts, I am having some trouble based on how my INSERT statement is currently built. Today, I am using the following: $sql = "INSERT INTO tablename VALUES ('', '$_SESSION['Member1FirstName'], '$_SESSION['Member1LastName'], '$_SESSION['Member1ID'], '$_SESSION['Member2FirstName'], '$_SESSION['Member2LastName'], '$_SESSION['Member2ID'] .... and the list goes on for 20+ members with some other values entered. It seems most people in the examples already have all their data stored in an array. On my site, I accept form inputs, action="" is set to self, php validation takes place and if validation passes, data is stored into SESSION variables on page 2 then redirected to the next page in the process (page 3) (approximately 8-10 pages in the whole process). thanks!

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  • mysql split value from one field to two

    - by tsiger
    Hello, I 've got a table field (membername) which contains both the last name and the first name of users. Is it possible to split those into 2 fields (memberfirst - memberlast)? All the records have this format "Firstname Lastname" (without quotes and a space in between).

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  • MySQL look for missing ratings

    - by Dustin
    Hopefully I can ask this without being confusing. I am a photographer and I am having some of our clients rate pictures that we have taken. We have hundreds of pictures in our portfolio that they may be rating. What I want to do is ask our clients to rate pictures again, but only show them the pictures they haven't yet rated. I currently have three tables: one that stores the actual ratings, one that stores the pictures (or location of each picture), and one that stores the information about the rater. I'm using codeigniter for my db management, if that helps at all. What I have so far is this: "SELECT * FROM ratings LEFT JOIN portfolio ON ratings.portfolioid = portfolio.portfolioid" This will give me a row for each rating, but won't show me where a rating is missing for a picture. Thanks in advance!

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  • Mysql filling in missing dates

    - by bsandrabr
    I have the following query SELECT * FROM attend RIGHT OUTER JOIN noattend ON attend.date = noattend.date2 WHERE attend.date BETWEEN '2010-02-01' AND '2010-04-01' AND attend.customerid =1 ORDER BY date DESC LIMIT 0 , 30 Attend is the table with customerid noattend is the table with a row for each date (date2) I followed the advice in other questions to right outer join it to create values where there is no record in attend but it still isn't filling in the empties any help much appreciated

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  • Mysql query problem

    - by Lost_in_code
    Below is a sample table: fruits +-------+---------+ | id | type | +-------+---------+ | 1 | apple | | 2 | orange | | 3 | banana | | 4 | apple | | 5 | apple | | 6 | apple | | 7 | orange | | 8 | apple | | 9 | apple | | 10 | banana | +-------+---------+ Following are the two queries of interest: SELECT * FROM fruits WHERE type='apple' LIMIT 2; SELECT COUNT(*) AS total FROM fruits WHERE type='apple'; // output 6 I want to combine these two queries so that the results looks like this: +-------+---------+---------+ | id | type | total | +-------+---------+---------+ | 1 | apple | 6 | | 4 | apple | 6 | +-------+---------+---------+ The output has to be limited to 2 records but it should also contain the total number of records of the type apple. How can this be done with 1 query?

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  • How to prevent negative number in Mysql

    - by Jerry
    Hello guys.. I have data which is starting from 0 in my database. My php will add 1 or -1 to the data depending on the user's input. My problem is that if data is 0 and a user try to subtract 1. The data become 4294967295 which is the maximum value of INT data type. Are there anyways to make the data stays in 0 even when the user asks for -1? Thanks for the reply.. my sql command is like below update board set score=score-1 where team='TeamA' //this would generate 4294967295 if the score is 0.....

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  • What's the error in my MySQL statement?

    - by Jim
    The following SQL statement has a syntax error according to phpMyAdmin, but I can't spot what it is. Any ideas? CREATE TABLE allocations( `student_uid` INT unsigned NOT NULL DEFAULT 0, `active` INT unsigned NOT NULL DEFAULT 1, `name` VARCHAR( 255 ) NOT NULL DEFAULT '', `internal_id` VARCHAR( 255 ) DEFAULT '', `tutor_uid` INT NOT NULL DEFAULT 0, `allocater_uid` INT unsigned NOT NULL DEFAULT 0, `time_created` INT NOT NULL DEFAULT 0, `remote_time` FLOAT NOT NULL DEFAULT 0, `next_lesson` VARCHAR NOT NULL DEFAULT -1, PRIMARY KEY ( student_uid ) );

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