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  • Need a MYSQL query to compare two tables and only output non matching results

    - by ee12csvt
    I have two tables in my database, one contains a list of items with other information on these items. The other table is contains a list of photographs of these items. The items table gives each item a unique identifier,which is used in the photographs table to identifier which item has been photographed. I need to output a list of items that are not linked to a photograph in the second table. Any ideas on how I can do this?

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  • Duplicate / Copy records in the same MySQL table

    - by Digits
    I have been looking for a while now but I can not find an easy solution for my problem. I would like to duplicate a record in a table, but of course, the unique primary key needs to be updated. I have this query: INSERT INTO invoices SELECT * FROM invoices AS iv WHERE iv.ID=XXXXX ON DUPLICATE KEY UPDATE ID = (SELECT MAX(ID)+1 FROM invoices) the problem is that this just changes the ID of the row instead of copying the row. Does anybody know how to fix this ? Thank you verrry much, Digits //edit: I would like to do this without typing all the field names because the field names can change over time.

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  • Getting id of row just inserted into MySQL database

    - by James P
    I have my table columns set like this: likes(id, like_message, timestamp) id is the primary key that is auto incrementing. This is the SQL that I use to add a row: $sql = "INSERT INTO `likes` (like_message, timestamp) VALUES ('$likeMsg', $timeStamp)"; Everything works, but now I need to throw back the id attribute of the newly inserted row. For example, if I insert a row and the id of that row is 13, I need to echo out 13 so my AJAX request can pick that up and use it. Any help would be appreciated, as well as related code samples. Thanks :)

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  • MySQL: NOW() giving me zeros

    - by Tunji Gbadamosi
    I have a table which I want to record the timestamp of every order at every insertion time. However, I'm getting zero values for the timestamps. Here's my schema: CREATE TABLE IF NOT EXISTS orders( order_no VARCHAR(16) NOT NULL, volunteer_id VARCHAR(16) NOT NULL, date TIMESTAMP DEFAULT NOW(), PRIMARY KEY (order_no), FOREIGN KEY (volunteer_id) REFERENCES volunteer(id) ON UPDATE CASCADE ON DELETE CASCADE)

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  • Confusing alias mySQL

    - by Taylor
    I keep getting the same number outputted for the Total Sales, Minimum Sale, Largest Sale and Average Sale. The Total Invoices is working perfectly, but I cant seem to figure out how to fix the other ones. Here's the query: SELECT SUM( b.`Number of Invoices`) AS `Total Invoices`, SUM( b.`Total Customer Purchases`) AS `Total Sales`, MIN( b.`Total Customer Purchases`) AS `Minimum Sale`, MAX( b.`Total Customer Purchases`) AS `Largest Sale`, AVG( b.`Total Customer Purchases`) AS `Average Sale` FROM (SELECT a.CUS_CODE, COUNT(a.`Number of Invoices`) AS `Number of Invoices`, SUM(a.`Invoice Total`) AS `Total Customer Purchases` FROM ( SELECT CUS_CODE, LINE.INV_NUMBER AS `Number of Invoices`, SUM(LINE.LINE_UNITS * LINE.LINE_PRICE) AS `Invoice Total` FROM `ttriggs`.`INVOICE`, `ttriggs`.`LINE` WHERE INVOICE.INV_NUMBER = LINE.INV_NUMBER GROUP BY CUS_CODE, LINE.INV_NUMBER ) a ) b GROUP BY b.CUS_CODE; Heres the database diagram https://www.dropbox.com/s/b8cy5l29jwh8lyv/1_edit.jpg Subquery generates: CUS_CODE 10011 Number of Invoices 8 Total Customer Purchases 1119.03 Any help is greatly appreciated, Thanks!

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  • Creating an array from a MySQL table

    - by Rob
    I'm trying to create an array to use for a curl_multi_exec, but I can't seem to create the array properly. Here is my code: $SQL = mysql_query("SELECT url FROM urls") or die(mysql_error()); //Query the shell table while($resultSet = mysql_fetch_array($SQL)){ $urls[]=$resultSet; } echo $urls; //Test that the array works But when I run this script, all it does is echo "Array" I have no idea what I'm doing wrong, I've checked around google a bit, but can't figure it out. Any insight would be appreciated.

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  • Incrementing through mysql PHP

    - by Rawdon
    I am looking at try to increment and decrement by three records through a table and present those records. Say if the id '4' is currently active. I want the to be display the ID's and category of 3.2.1 and 5.6.7 from an increment and decrement So far I have: $stmt = $db->query("SELECT id, category FROM test"); $stmt->execute(); while ($results = $stmt->fetch(PDO::FETCH_ASSOC)) { $current = $results['id']; $category = $results['category']; $next = array(array('slide_no' => $current, 'category' => $category)); } print_r($next); Now with this, I am getting back every row in the table. I'm now getting confused on how I could increment and decrement the records by 3 and make sure that the category will also increment correctly. Thank you very much.

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  • MySQL: How to do a conditional update?

    - by Tom
    Hi, I'm trying to a create an update statement along the following lines: TABLE car: id | owner_id | type | status An owner can have multiple cars. UPDATE car c SET c.type = 1 WHERE c.owner_id IN ($ids) AND c.status = [1 IF IT EXISTS, ELSE 0] $ids is reasonably small (under 50 values). It seems simple but I can't seem to get my head around it because I can't use a SELECT subquery with an UPDATE to the same table. Anyone? Thanks

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  • MySQL, select from different table... IF

    - by gubbfett
    I'm having a small trouble since it was a long time ago i studies databases and querys. For example i'll have two tables for cd:s, one with data and one with alternative translations. In the CD-table i have the original language, and it looks something like this Table for CDs (cds): id | name | language ----------------------- 1 | aaa | en 2 | bbb | en 3 | ccc | fi Table for languages (languages): cd_id | language | name ----------------------- 1 | fi | AAA 1 | de | AAACHTUNG 3 | en | CCC Now, i want to get all these cd:s in for example german, if there's no translation made i want it to be in the original language... How can i do this?

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  • Merging some columns of two mysql tables where id = fileid

    - by garg
    There are two tables TableA filedata_id | user_id | filename 1 | 1 | file.txt 2 | 1 | file2.txt TableB a_id | date | filedataid | counter | state | cat_id | subcat_id | med_id 99 | 1242144 | 1 | 2 | v | 55 | 56 | 90 100 | 1231232 | 2 | 3 | i | 44 | 55 | 110 I want to move columns cat_id, subcat_id, med_id to TableA where tableA.filedata_id = TableB.filedataid The result should be: TableA filedata_id | user_id | filename | cat_id | subcat_id | med_id 1 | 1 | file.txt | 55 | 56 | 90 2 | 1 | file2.txt | 44 | 55 | 110 and so on. Is there a way to do this easily?

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  • MySQL using function IN with variable

    - by misanov
    I have problem querying table with variable in IN function. SELECT s.date, (SELECT GROUP_CONCAT(value) FROM value WHERE id_value IN(s.ref_values) ) AS vals FROM stats s ORDER BY s.date DESC LIMIT 1 Where s.ref_values is '12,22,54,15'. I get only one return for first number (12). When I insert that value directly in IN(12,22,54,15) it finds all 4. So, there must be problem with using variable in IN. What am I doing wrong?

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  • How to search mulitple value seperated by commas in mysql

    - by Fero
    Hi all, How to search multiple values separated by commas. ex: table name : searchTest id name keyword 1 trophy1 test1,test2,test3 2 trophy2 test2,test5 Points: If i search for test2 both results trophy1 and trophy2 should be display. If i search for trophy1 then trophy1 should be as result. How to solve this issue. thanks in advance

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  • Sort MySQL query result by a alphanumeric field

    - by Jason Shultz
    I'm querying a table in a db using php. one of the fields is a column called "rank" and has data like the following: none 1-bronze 2-silver 3-gold ... 10-ambassador 11-president I want to be able to sort the results based on that "rank" column. any results where the field is "none" get excluded, so those don't factor in. As you can already guess, right now the results are coming back like this: 1-bronze 10-ambassador 11-president 2-silver 3-gold Of course, I would like for it to be sorted so it is like the following: 1-bronze 2-silver 3-gold ... 10-ambassador 11-president Right now the query is being returned as an object. I've tried different sort options like natsort, sort, array_multisort but haven't got it to work the way I'm sure it can. I would prefer keeping the results in an object form if possible. I'm passing the data on to a view in the next step. although, it's perfectly acceptable to pass the object to the view and then do the work there. so it's not an issue after all. :) thank you for your help. i'm hoping I'm making sense.

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  • mysql extra columns with same name from two tables

    - by salmane
    Table 1 has columns : entry_id user_id ... Table 2 has columns : entry_id user_id ... the user_id entry is not always the same so I would like to extract both of them so I can later on compare them in my script SELECT * FROM table1 as t1 INNER JOIN table2 as t2 on t1.entry_id=t2.entry_id WHERE t1.user_id='%s' I would like to extract t1.user_id and t2.user_id ...the problem is the result array has only user_id thank you

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  • Mysql ADDDATE() or DATE_ADD() with table columns?

    - by John
    How do I do something like the following SELECT ADDDATE(t_invoice.last_bill_date, INTERVAL t_invoice.interval t_invoice.interval_unit) FROM t_invoice ...where the column t_invoice.last_bill_date is a date, t_invoice.interval is an integer and t_invoice.interval_unit is a string. Basically, I want to determine a person's next bill date based on his desired billing frequency. Is there a better way to achieve this?

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  • mysql select help

    - by user344766
    Hi I have a table that looks like this id : productid : featureid and would have the following data: (1, 1, 16) (2, 1, 21) (3, 1, 25) (4, 2, 16) (5, 2, 21) (6, 2, 27) where featureid is a foreign key to another table. I need to select products that have both featureids of 16 and 25, in which case productid 1 but not productid 2 Can someone show me an example of how to format this query.

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  • [MySQL Query] How to limit date?

    - by rasouza
    I'd like to select all entries from a table where date is the last one and only those ones. For example: today is May 16th, the last entries I have from my table is dated from May 15th, but I have older ones (May 14th, May13th, etc). I'd like to select only the dated from May 15th, but it's not this specific date, I need to select every entry dated from the last date I have in my database. How to? Thx in advance

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  • MySql query and table optimisation

    - by Cheeky
    Hi everyone. I am trying to run the following simple query on a table with 500K records. SELECT COUNT(*) AS impressionCount FROM impression WHERE 0 = 0 AND impressionObjectId1 = 'C69A54B8-B828-E2E4-2319A93011DF4120' AND impressionObjectId2 = '1'; This query is taking 10 seconds to run. I have tried creating individual indexes for the impressionObjectId1 and impressionObjectId2 columns, as well as a composite index using both. The composite worked well for a while, but now it is also slow. Here is my table structure: DROP TABLE IF EXISTS `impression`; CREATE TABLE `impression` ( `impressionId` varchar(50) NOT NULL, `impressionObjectId1` varchar(50) NOT NULL, `impressionObjectId2` varchar(50) default NULL, `impressionStampDate` datetime NOT NULL, PRIMARY KEY (`impressionId`), KEY `IX_object` (`impressionObjectId1`,`impressionObjectId2`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 ROW_FORMAT=DYNAMIC COMMENT='InnoDB free: 191488 kB'; Any advice would be greatly appreciated. Thanks EDIT: When adding an EXPLAIN, this is the output: 1, 'SIMPLE', 'impression', 'ref', 'IX_object', 'IX_object', '105', 'const,const', 304499, 'Using where; Using index'

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  • mysql ORDER BY date_time field not sorting as expected

    - by undefined
    I have a field in my database that stores the datetime that an item was added to the database. If I want to sort the items in reverse chronological order I would expect that doing ORDER by date_added DESC would do the trick. But this seems not to work. I also tried ORDER by UNIX_TIMESTAMP(date_added) but this still did not sort the results as I would expect. I also have an auto-increment field that I can use to sort items so I will use this, but I am curious as to why ORDER by datetime was not behaving as expected. any ideas?

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  • PHP & MySQL Problem

    - by Fincha
    I Have a script, getting text from DB and post it on other DB. Problem is, if I have a Text lngen then 840 Words, I can't call this page. Get an error about "Not Found" or "Connection brocken" or what ever. In FF i get no error, only blank page. I found out the Problem is in lenght of the query i send... but how can i fix it??? My it be the Problem, if a query is longer then 6000 Characters?

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  • MySQL Multiple "AND" Query

    - by Mark J
    I have a table with 2 columns (see below). A member can have multiple responses to a question RESPONSES --------- member_id INT response_id INT SAMPLE DATA member_id -- response_id 1 -- 3 1 -- 5 2 -- 1 2 -- 5 2 -- 9 3 -- 1 3 -- 5 3 -- 6 What I need to do is query the table for member that meet ALL response criteria. For example I need to select all members that have a response_id of 1 AND 5. I am using the following query: SELECT DISTINCT member_id FROM responses WHERE response_id = 1 AND response_id = 5. I would expect to get back member_id's 2,3. However I am getting nothing returned. I used EXPLAIN and it shows there is an error in my where query. What am I doing wrong? Also, is there a function similar to IN where all the criteria must be met in order to return true? Thanks for your help.

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  • selecting more than 1 table to get content from [php/Mysql]

    - by SAFSOF
    Hi There i want to get the latest threads/messages i made my code then i made function that calls the code to show last messages in specific board it works great now i want to get latest messages from 2 boards or more in the same function this is the part that chooses the board AND b.id_board = t.id_board' . (empty($vars) ? '' : ' AND b.id_board = ' . $vars . ''). ' i tried to use functionname(1.2.3); but he says no board with id 1.2.3 i tried ("1,2,3") same i wish i made it clear for you i apreciate your help

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