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  • VBA/SQL recordsets

    - by intruesiive
    The project I'm asking about is for sending an email to teachers asking what books they're using for the classes they're teaching next semester, so that the books can be ordered. I have a query that compares the course number of this upcoming semester's classes to the course numbers of historical textbook orders, pulling out only those classes that are being taught this semester. That's where I get lost. I have a table that contains the following: -Professor -Course Number -Year -Book -Title The data looks like this: professor year course number title smith 13 1111 Pride and Prejudice smith 13 1111 The Fountainhead smith 13 1222 The Alchemist smith 12 1111 Pride and Prejudice smith 11 1222 Infinite Jest smith 10 1333 The Bible smith 13 1333 The Bible smith 12 1222 The Alchemist smith 10 1111 Moby Dick johnson 12 1222 The Tipping Point johnson 11 1333 Anna Kerenina johnson 10 1333 Everything is Illuminated johnson 12 1222 The Savage Detectives johnson 11 1333 In Search of Lost Time johnson 10 1333 Great Expectations johnson 9 1222 Proust on the Shore Here's what I need the code to do "on paper": Group the records by professor. Determine every unique course number in that group, and group records by course number. For each unique course number, determine the highest year associated. Then spit out every record with that professor+course number+year combination. With the sample data, the results would be: professor year course number title smith 13 1111 Pride and Prejudice smith 13 1111 The Fountainhead smith 13 1222 The Alchemist smith 13 1333 The Bible johnson 12 1222 The Tipping Point johnson 11 1333 Anna Kerenina johnson 12 1222 The Savage Detectives johnson 11 1333 In Search of Lost Time I'm thinking I should make a record set for each teacher, and within that, another record set for each course number. Within the course number record set, I need the system to determine what the highest year number is - maybe store that in a variable? Then pull out every associated record so that if the teacher ordered 3 books the last time they taught that class (whether it was in 2013 or 2012 and so on) all three books display. I'm not sure I'm thinking of record sets in the right way, though. My SQL so far is basic and clearly doesn't work: SELECT [All].Professor, [All].Course, Max([All].Year) FROM [All] GROUP BY [All].Professor, [All].Course; Thanks for your help.

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  • Alternative site to Mike Gunderloy's "The Daily Grind" (Larkware)?

    - by splattne
    As a developer who is always looking for new resources and information, I loved Mike Gunderloy's blog "The Daily Grind" on www.larkware.com ("We get up early, so you don't have to.") Unfortunately (for me) Mike decided to discontinue the blog in December 2007. So, my question: is there a similar blog / site which provides such good links and resources on a daily basis? I couldn't find one. Thanks! Update: to be clear: I am specifically looking for a site like larkware.com, a kind of aggregator/meta-site of information about interesting articles, components, software for (.NET) developers.

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  • SQL: Add counters in select

    - by etarvt
    Hi, I have a table which contains names: Name ---- John Smith John Smith Sam Wood George Wright John Smith Sam Wood I want to create a select statement which shows this: Name 'John Smith 1' 'John Smith 2' 'Sam Wood 1' 'George Wright 1' 'John Smith 3' 'Sam Wood 2' In other words, I want to add separate counters to each name. Is there a way to do it without using cursors?

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  • 9 New BizTalk Wencasts in the Light & Easy Series

    - by Alan Smith
    During the MVP summit in February I managed to catch up with a few of the BizTalk MVPs who had recorded new webcasts for the “BizTalk Light & Easy” series. The 9 new webcasts are online now at CloudCasts. ·         BizTalk 2010 and Windows Azure – Paul Somers ·         BizTalk and AppFabric Cache Part 1 – Mike Stephenson ·         BizTalk and AppFabric Cache Part 2 – Mike Stephenson ·         Integration to SharePoint 2010 Part 1 – Mick Badran ·         Integration to SharePoint 2010 Part 2 – Mick Badran ·         Better BizTalk Testing by Taking Advantage of the CAT Logging Framework – Mike Stephenson ·         Calling Business Rules from a .NET Application – Alan Smith ·         Tracking Rules Execution in a .NET Application – Alan Smith ·         Publishing a Business Rules Policy as a Service – Alan Smith The link is here. Big thanks to Paul, Mike and Mick for putting the time in. “BizTalk Light & Easy” is an ongoing project, if you are feeling creative and would like to contribute feel free to contact me via this blog. I can email you some tips on webcasting and the best formats to use.

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  • How are views constructed in Josh Smith's MVVM sample?

    - by Wim Coenen
    Being new to both WPF and MVVM, I'm studying Josh Smith's article on the MVVM pattern and the accompanying sample code. I can see that the application is started in app.xaml.cs by constructing a MainWindow object, wiring it to a MainWindowViewModel object and then showing the main window. So far so good. However, I can't find any code which instantiates the AllCustomersView or CustomerView classes. Using "find all references" on the constructors of those views comes up with nothing. What am I missing here?

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  • Exchange Server 2007 Forwarding Circles

    - by LorenVS
    Hello, I asked a question quite a while ago about two members of an organization who wanted to receive all of each other's emails, and yet maintain seperate mailboxes. (so all emails to mike@company get sent to mike and dave and all emails to dave@company get sent to mike and dave). At the time, I actually only needed to implement one side of this (only mikes emails got sent to both receipients) and (with the help of ServerFault) I set up forwarding on dave's inbox so that all of his emails would also be sent to mike. I'm now in a situation where I have to implement the other side of this relation (such that mike's emails will also forward to dave). I still remember how to set up the forwarding rule, but I'm worried that I might be creating a circular forwarding rule such that mike@compnay forwards to dave@company which forwards to mike@company and so on. Can anyone clear up my confusion (just want to make sure I don't make a stupid mistake). Thanks a ton

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  • Why is gcc failing with "unrecognized command line option "-L/lusr/opt/mpfr-2.4.2/lib" "?

    - by Mike
    My sysadmin recently installed a new version of GCC, in /lusr/opt/gcc-4.4.3. I tested it as follows: mike@canon:~$ cat test.c int main(){ return 0; } mike@canon:~$ gcc test.c /lusr/opt/gcc-4.4.3/libexec/gcc/i686-pc-linux-gnu/4.4.3/cc1: error while loading shared libraries: libmpfr.so.1: cannot open shared object file: No such file or directory After informing my sysadmin about this, he said to add /lusr/opt/mpfr-2.4.2/lib:/lusr/opt/gmp-4.3.2/lib to my LD_LIBRARY_PATH. After doing this, I get the following error: mike@canon:~$ gcc test.c cc1: error: unrecognized command line option "-L/lusr/opt/mpfr-2.4.2/lib" First, my sysadmin wasn't entirely sure this was the best workaround(though he did say it worked for him...), so is there a better solution? Second, why am I getting a linker error from cc, and how can I fix it? Some information which may be helpful: mike@canon:~$ env | grep mpfr OLDPWD=/lusr/opt/mpfr-2.4.2/lib LD_LIBRARY_PATH=/lusr/opt/mpfr-2.4.2/lib:/lusr/opt/gmp-4.3.2/lib: mike@canon:~$ echo $LDFLAGS (the above is a blank line)

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  • SEO impact on subdomain for full name and obscure ccTLD

    - by Dan Christian
    There have been a few questions on subdomains and their impact on SEO, mostly in comparison to subfolders. The closest question I've found is this question but it still doesn't completely answer my query. I'm setting up a blog for 'Sam Smith'. It's imperative the SEO is based around his full name as he is a prominent blogger and his name is his value. All ccTLD variations of 'samsmith' (samsmith.com, samsmith.cc etc) are taken. However there has been the opportunity to register an obscure ccTLD for 'smith'. In regards to SEO value purely from the URL... 1) Will there be any negative SEO implications on searches for 'Sam Smith' when setting up the subdomain as 'sam.smith.' compared to a more regular 'samsmith.' domain? Will a search engine recognise the subdomain as the full name as oppose to just 'smith'? 2) Are there any negative SEO implications with an obscure ccTLD. For instance if Sam Smith was a prominent blogger in Canada with most of his audience based there, would there be any negative SEO if he had, for example, a .co ccTLD.

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  • Filter rows on the basis of "First Name" + "Last Name" in SQL

    - by Raghav Khunger
    Hi, I have a user table in my database which contains two columns FirstName and LastName. Now in my front end there is a textbox to filter out the users from this table. Let's suppose I am taking that input from the front end in the form of a input parameter "@SEARCHKEYWORD". I have created a sample below: DECLARE @Test TABLE ([ID] INT IDENTITY, [FNAME] NVARCHAR(100), [LNAME] NVARCHAR(100) ) INSERT INTO @Test( FNAME, LNAME ) SELECT 'John','Resig' UNION ALL SELECT 'Dave','Ward' UNION ALL SELECT 'Peter','Smith' UNION ALL SELECT 'Dave','Smith' UNION ALL SELECT 'Girija','Acharya' UNION ALL SELECT 'Devendra', 'Gujel' UNION ALL SELECT 'Arjit', 'Gupta' DECLARE @SEARCHKEYWORD NVARCHAR(100) SELECT * FROM @Test WHERE FNAME +' '+ LNAME LIKE @SEARCHKEYWORD i.e. so far I have thought of this query to filter out the rows but it is not giving the desired results: SELECT * FROM @Test WHERE FNAME +' '+ LNAME LIKE @SEARCHKEYWORD Here are the desired outputs which I needed for the inputs mentioned below: --WHEN @SEARCHKEYWORD='John Resig' --Desired OUTPUT: the row which contains 'John','Resig' --WHEN @SEARCHKEYWORD='Ac' --Desired OUTPUT: the row which contains 'Girija','Acharya' --WHEN @SEARCHKEYWORD='Smith' --Desired OUTPUT: the row which contains 'Peter','Smith' and 'Dave','Smith' --WHEN @SEARCHKEYWORD='g' --Desired OUTPUT: the row which contains 'Devendra', 'Gujel' and 'Arjit', 'Gupta' --WHEN @SEARCHKEYWORD='Smith' --Desired OUTPUT: the row which contains 'Peter','Smith' and 'Dave','Smith'

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  • Excel VBA Text To Column

    - by Pat
    This is what I currently have: H101 John Doe Jane Doe Jack Doe H102 John Smith Jane Smith Katie Smith Jack Smith And here is what I want: H101 John Doe H101 Jane Doe H101 Jack Doe H102 John Smith H102 Jane Smith H102 Katie Smith H102 Jack Smith Obviously I want to do this on a bigger scale. The number of columns is between 1 & 6, so I cant limit it that way. I was able to get a script that allows me to put each individual on one row. However, I am having a hard time getting the first column to copy over to each row. Sub ToOneColumn() Dim i As Long, k As Long, j As Integer Application.ScreenUpdating = False Columns(2).Insert i = 0 k = 1 While Not IsEmpty(Cells(k, 3)) j = 3 While Not IsEmpty(Cells(k, j)) i = i + 1 Cells(i, 1) = Cells(k, 1) //CODE IN QUESTION Cells(i, 2) = Cells(k, j) Cells(k, j).Clear j = j + 1 Wend k = k + 1 Wend Application.ScreenUpdating = True End Sub Like I said, it was working fine to get everyone each on their own row, but can't figure out how to get that first column. It seems like it should be so simple, but it's bugging me. Any help is greatly appreciated.

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  • How can I use the Boost Graph Library to lay out verticies?

    - by Mike
    I'm trying to lay out vertices using the Boost Graph Library. However, I'm running into some compilation issues which I'm unsure about. Am I using the BGL in an improper manner? My code is: PositionVec position_vec(2); PositionMap position(position_vec.begin(), get(vertex_index, g)); int iterations = 100; double width = 100.0; double height = 100.0; minstd_rand gen; rectangle_topology<> topology(gen, 0, 0, 100, 100); fruchterman_reingold_force_directed_layout(g, position, topology); //Compile fails on this line The diagnostics produced by clang++(I've also tried GCC) are: In file included from test.cpp:2: /Volumes/Data/mike/Downloads/boost_1_43_0/boost/graph/fruchterman_reingold.hpp:95:3: error: no member named 'dimensions' in 'boost::simple_point<double>' BOOST_STATIC_ASSERT (Point::dimensions == 2); ^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ In file included from test.cpp:2: In file included from /Volumes/Data/mike/Downloads/boost_1_43_0/boost/graph/fruchterman_reingold.hpp:13: In file included from /Volumes/Data/mike/Downloads/boost_1_43_0/boost/graph/graph_traits.hpp:15: In file included from /Volumes/Data/mike/Downloads/boost_1_43_0/boost/tuple/tuple.hpp:24: /Volumes/Data/mike/Downloads/boost_1_43_0/boost/static_assert.hpp:118:49: note: instantiated from: sizeof(::boost::STATIC_ASSERTION_FAILURE< BOOST_STATIC_ASSERT_BOOL_CAST( B ) >)>\ ^ In file included from test.cpp:2: /Volumes/Data/mike/Downloads/boost_1_43_0/boost/graph/fruchterman_reingold.hpp:95:3: note: instantiated from: BOOST_STATIC_ASSERT (Point::dimensions == 2); ^ ~~~~~~~ /Volumes/Data/mike/Downloads/boost_1_43_0/boost/graph/fruchterman_reingold.hpp:95:31: note: instantiated from: BOOST_STATIC_ASSERT (Point::dimensions == 2); ~~~~~~~^ /Volumes/Data/mike/Downloads/boost_1_43_0/boost/graph/fruchterman_reingold.hpp:417:19: note: in instantiation of template class 'boost::grid_force_pairs<boost::rectangle_topology<boost::random::linear_congruential<int, 48271, 0, 2147483647, 399268537> >, boost::iterator_property_map<__gnu_cxx::__normal_iterator<boost::simple_point<double> *, std::vector<boost::simple_point<double>, std::allocator<boost::simple_point<double> > > >, boost::vec_adj_list_vertex_id_map<boost::property<boost::vertex_name_t, std::basic_string<char>, boost::no_property>, unsigned long>, boost::simple_point<double>, boost::simple_point<double> &> >' requested here make_grid_force_pairs(topology, position, g)), ^ /Volumes/Data/mike/Downloads/boost_1_43_0/boost/graph/fruchterman_reingold.hpp:431:3: note: in instantiation of function template specialization 'boost::fruchterman_reingold_force_directed_layout<boost::rectangle_topology<boost::random::linear_congruential<int, 48271, 0, 2147483647, 399268537> >, boost::adjacency_list<boost::listS, boost::vecS, boost::undirectedS, boost::property<boost::vertex_name_t, std::basic_string<char>, boost::no_property>, boost::no_property, boost::no_property, boost::listS>, boost::iterator_property_map<__gnu_cxx::__normal_iterator<boost::simple_point<double> *, std::vector<boost::simple_point<double>, std::allocator<boost::simple_point<double> > > >, boost::vec_adj_list_vertex_id_map<boost::property<boost::vertex_name_t, std::basic_string<char>, boost::no_property>, unsigned long>, boost::simple_point<double>, boost::simple_point<double> &>, boost::square_distance_attractive_force, boost::attractive_force_t, boost::no_property>' requested here fruchterman_reingold_force_directed_layout ^ test.cpp:48:3: note: in instantiation of function template specialization 'boost::fruchterman_reingold_force_directed_layout<boost::rectangle_topology<boost::random::linear_congruential<int, 48271, 0, 2147483647, 399268537> >, boost::adjacency_list<boost::listS, boost::vecS, boost::undirectedS, boost::property<boost::vertex_name_t, std::basic_string<char>, boost::no_property>, boost::no_property, boost::no_property, boost::listS>, boost::iterator_property_map<__gnu_cxx::__normal_iterator<boost::simple_point<double> *, std::vector<boost::simple_point<double>, std::allocator<boost::simple_point<double> > > >, boost::vec_adj_list_vertex_id_map<boost::property<boost::vertex_name_t, std::basic_string<char>, boost::no_property>, unsigned long>, boost::simple_point<double>, boost::simple_point<double> &> >' requested here fruchterman_reingold_force_directed_layout(g, position, topology); ^ 1 error generated.

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  • Completely remove user account and create another with same name in Windows 7

    - by TeaJay
    Here's my question simply and then the details in case they help to get me an appropriate answer. Question: How can I completely and permanently delete a user account in Windows 7 so that I can create another one with the same user name without the computer name extension added, eg Jane Smith not Jane Smith.computer name? The details: I just did a clean install of Windows 7 Professional 32 bit. (My laptop crashed, I reinstalled Vista and restored backup files but things weren't working so I decided to just get Windows 7 since I had to start over anyway). I used Windows Easy Transfer to save just about everything, even customizing to include a user's appdata from Windows.old which was created when I reinstalled Vista -- not knowing that another windows.old file would be created with the installation of Windows 7. After installing Windows 7, I used Windows Easy Transfer to transfer the user file, appdata, to the new user account which I gave the same name (Jane Smith) in case having a different name would cause problems with reading files or something. Afterwards, I realized that I did not want ALL of that junk. So, I thought no problem, I'll just delete the user account I just created, nothing lost, and create another one this time transferring only the files I wanted (using the customize option in windows easy transfer). I wanted to keep the same user name, e.g. Jane Smith, so after I deleted the user account I checked the files, and I didn't see. It was late so I went to bed and the next morning I created a new user with that same name (Jane Smith). The files looked fine if I remember correctly. Meanwhile, I updated the computer and it restarted a couple times. As I was moving files to the "Jane Smith" user account file, things weren't working as they should. I was actually moving files to the deleted user account and that the current user account was named "Jane Smith.computer name" and that's where the files needed to go. I don't like this. It's too confusing. I want just "Jane Smith". How can I do this without just changing the user name (which doesn't change it in the file path etc)? I want the first one GONE. If I can't do this, is it a problem to create an account with another name and still transfer files to it without path or other problems? I hope this question makes sense and that someone can help me. Thank you in advance!

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  • Help using left outer joins in SQL...

    - by Waffles
    I'm trying to create a list of people, their friends, and their friends of friends. My table of people is this: People: NAME Jow Smith Sandy Phil Friends LIKER LIKEE jow smith smith jow sandy phil Now, what I want is a table like this: User Friend FriendofFriend Jow smith jow Smith jow smith sandy phil phil I'm trying to create a table using the following: SELECT P.NAME, F.LIKEE, F2.LIKEE FROM PEOPLE P LEFT OUTER JOIN FRIENDS F ON P.NAME = F.LIKER LEFT OUTER JOIN FRIENDS F2 ON F.LIKEE = F2.LIKER But the above isn't working. How can I get a table of people and their friends, regardless of whether or not they actually HAVE any friends?

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  • There seems to be some 'lingering' SSH connections on my server. How do I fix it?

    - by mike
    [root@server mike]# w 14:43:35 up 83 days, 1:25, 1 user, load average: 0.00, 0.00, 0.00 USER TTY FROM LOGIN@ IDLE JCPU PCPU WHAT mike pts/1 dsl-IP.w 14:43 0.00s 0.01s 0.03s sshd: mike [priv] [root@server mike]# ps aux | grep ssh root 1350 0.0 0.1 5276 1044 ? Ss Aug27 0:00 /usr/sbin/sshd root 14328 0.0 0.2 8020 2580 ? Ss 12:49 0:00 sshd: dave [priv] dave 14332 0.0 0.1 8020 1532 ? S 12:49 0:00 sshd: dave@notty dave 14333 0.0 0.1 4696 1444 ? Ss 12:49 0:00 /usr/lib/openssh/sftp-server root 14344 0.0 0.2 8020 2580 ? Ss 12:59 0:00 sshd: dave [priv] dave 14347 0.0 0.1 8168 1564 ? S 13:00 0:00 sshd: dave@notty dave 14348 0.0 0.1 4700 1504 ? Ss 13:00 0:00 /usr/lib/openssh/sftp-server root 14351 0.0 0.2 8020 2580 ? Ss 13:04 0:00 sshd: dave [priv] dave 14355 0.0 0.1 8168 1560 ? S 13:04 0:00 sshd: dave@notty dave 14356 0.0 0.1 4696 1472 ? Ss 13:04 0:00 /usr/lib/openssh/sftp-server root 14373 0.0 0.2 8020 2584 ? Ss 13:15 0:00 sshd: dave [priv] dave 14377 0.0 0.1 8168 1560 ? S 13:15 0:00 sshd: dave@notty dave 14378 0.0 0.1 4704 1500 ? Ss 13:15 0:00 /usr/lib/openssh/sftp-server root 14385 0.0 0.2 8020 2584 ? Ss 13:28 0:00 sshd: dave [priv] dave 14389 0.0 0.1 8168 1592 ? S 13:28 0:00 sshd: dave@notty dave 14390 0.0 0.1 4696 1508 ? Ss 13:28 0:00 /usr/lib/openssh/sftp-server root 14392 0.0 0.2 8020 2588 ? Ss 13:30 0:00 sshd: dave [priv] dave 14396 0.0 0.1 8168 1604 ? S 13:30 0:00 sshd: dave@notty dave 14397 0.0 0.1 4696 1492 ? Ss 13:30 0:00 /usr/lib/openssh/sftp-server root 14402 0.0 0.2 8020 2584 ? Ss 13:33 0:00 sshd: dave [priv] dave 14406 0.0 0.1 8020 1536 ? S 13:33 0:00 sshd: dave@notty dave 14407 0.0 0.1 4696 1460 ? Ss 13:33 0:00 /usr/lib/openssh/sftp-server root 14428 0.0 0.2 8020 2584 ? Ss 13:45 0:00 sshd: dave [priv] dave 14432 0.0 0.1 8168 1580 ? S 13:45 0:00 sshd: dave@notty dave 14433 0.0 0.1 4704 1512 ? Ss 13:45 0:00 /usr/lib/openssh/sftp-server root 14439 0.0 0.2 8020 2580 ? Ss 13:53 0:00 sshd: dave [priv] dave 14443 0.0 0.1 8020 1532 ? S 13:53 0:00 sshd: dave@notty dave 14444 0.0 0.1 4696 1448 ? Ss 13:53 0:00 /usr/lib/openssh/sftp-server root 14480 0.0 0.2 8020 2584 ? Ss 14:11 0:00 sshd: dave [priv] dave 14484 0.0 0.1 8168 1588 ? S 14:11 0:00 sshd: dave@notty dave 14485 0.0 0.1 4704 1492 ? Ss 14:11 0:00 /usr/lib/openssh/sftp-server root 14487 0.0 0.2 8020 2580 ? Ss 14:12 0:00 sshd: dave [priv] dave 14490 0.0 0.1 8020 1552 ? S 14:12 0:00 sshd: dave@notty dave 14492 0.0 0.1 4696 1472 ? Ss 14:12 0:00 /usr/lib/openssh/sftp-server root 14510 0.0 0.2 8020 2584 ? Ss 14:35 0:00 sshd: dave [priv] dave 14514 0.0 0.1 8168 1568 ? S 14:35 0:00 sshd: dave@notty dave 14515 0.0 0.1 4700 1492 ? Ss 14:35 0:00 /usr/lib/openssh/sftp-server root 14517 0.0 0.2 8020 2580 ? Ss 14:37 0:00 sshd: dave [priv] dave 14521 0.0 0.1 8020 1548 ? S 14:38 0:00 sshd: dave@notty dave 14522 0.0 0.1 4696 1464 ? Ss 14:38 0:00 /usr/lib/openssh/sftp-server root 14538 0.0 0.2 8020 2620 ? Ss 14:43 0:00 sshd: mike [priv] mike 14542 0.0 0.1 8020 1560 ? S 14:43 0:00 sshd: mike@pts/1 root 14554 0.0 0.0 1720 560 pts/1 S+ 14:43 0:00 grep ssh As you can see above, I, mike, am logged into SSH executing commands. This is shown from the w command. However, there's an odd amount of SSH related processes currently running. I figured dave's sftp session might not show up in the output of w for whatever reason but that doesn't explain all the running processes... What's wrong? :/

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  • A Nondeterministic Engine written in VB.NET 2010

    - by neil chen
    When I'm reading SICP (Structure and Interpretation of Computer Programs) recently, I'm very interested in the concept of an "Nondeterministic Algorithm". According to wikipedia:  In computer science, a nondeterministic algorithm is an algorithm with one or more choice points where multiple different continuations are possible, without any specification of which one will be taken. For example, here is an puzzle came from the SICP: Baker, Cooper, Fletcher, Miller, and Smith live on different floors of an apartment housethat contains only five floors. Baker does not live on the top floor. Cooper does not live onthe bottom floor. Fletcher does not live on either the top or the bottom floor. Miller lives ona higher floor than does Cooper. Smith does not live on a floor adjacent to Fletcher's.Fletcher does not live on a floor adjacent to Cooper's. Where does everyone live? After reading this I decided to build a simple nondeterministic calculation engine with .NET. The rough idea is that we can use an iterator to track each set of possible values of the parameters, and then we implement some logic inside the engine to automate the statemachine, so that we can try one combination of the values, then test it, and then move to the next. We also used a backtracking algorithm to go back when we are running out of choices at some point. Following is the core code of the engine itself: Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--Public Class NonDeterministicEngine Private _paramDict As New List(Of Tuple(Of String, IEnumerator)) 'Private _predicateDict As New List(Of Tuple(Of Func(Of Object, Boolean), IEnumerable(Of String))) Private _predicateDict As New List(Of Tuple(Of Object, IList(Of String))) Public Sub AddParam(ByVal name As String, ByVal values As IEnumerable) _paramDict.Add(New Tuple(Of String, IEnumerator)(name, values.GetEnumerator())) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(1, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(2, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Object, Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(3, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Object, Object, Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(4, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Object, Object, Object, Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(5, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Object, Object, Object, Object, Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(6, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Object, Object, Object, Object, Object, Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(7, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Public Sub AddRequire(ByVal predicate As Func(Of Object, Object, Object, Object, Object, Object, Object, Object, Boolean), ByVal paramNames As IList(Of String)) CheckParamCount(8, paramNames) _predicateDict.Add(New Tuple(Of Object, IList(Of String))(predicate, paramNames)) End Sub Sub CheckParamCount(ByVal count As Integer, ByVal paramNames As IList(Of String)) If paramNames.Count <> count Then Throw New Exception("Parameter count does not match.") End If End Sub Public Property IterationOver As Boolean Private _firstTime As Boolean = True Public ReadOnly Property Current As Dictionary(Of String, Object) Get If IterationOver Then Return Nothing Else Dim _nextResult = New Dictionary(Of String, Object) For Each item In _paramDict Dim iter = item.Item2 _nextResult.Add(item.Item1, iter.Current) Next Return _nextResult End If End Get End Property Function MoveNext() As Boolean If IterationOver Then Return False End If If _firstTime Then For Each item In _paramDict Dim iter = item.Item2 iter.MoveNext() Next _firstTime = False Return True Else Dim canMoveNext = False Dim iterIndex = _paramDict.Count - 1 canMoveNext = _paramDict(iterIndex).Item2.MoveNext If canMoveNext Then Return True End If Do While Not canMoveNext iterIndex = iterIndex - 1 If iterIndex = -1 Then Return False IterationOver = True End If canMoveNext = _paramDict(iterIndex).Item2.MoveNext If canMoveNext Then For i = iterIndex + 1 To _paramDict.Count - 1 Dim iter = _paramDict(i).Item2 iter.Reset() iter.MoveNext() Next Return True End If Loop End If End Function Function GetNextResult() As Dictionary(Of String, Object) While MoveNext() Dim result = Current If Satisfy(result) Then Return result End If End While Return Nothing End Function Function Satisfy(ByVal result As Dictionary(Of String, Object)) As Boolean For Each item In _predicateDict Dim pred = item.Item1 Select Case item.Item2.Count Case 1 Dim p1 = DirectCast(pred, Func(Of Object, Boolean)) Dim v1 = result(item.Item2(0)) If Not p1(v1) Then Return False End If Case 2 Dim p2 = DirectCast(pred, Func(Of Object, Object, Boolean)) Dim v1 = result(item.Item2(0)) Dim v2 = result(item.Item2(1)) If Not p2(v1, v2) Then Return False End If Case 3 Dim p3 = DirectCast(pred, Func(Of Object, Object, Object, Boolean)) Dim v1 = result(item.Item2(0)) Dim v2 = result(item.Item2(1)) Dim v3 = result(item.Item2(2)) If Not p3(v1, v2, v3) Then Return False End If Case 4 Dim p4 = DirectCast(pred, Func(Of Object, Object, Object, Object, Boolean)) Dim v1 = result(item.Item2(0)) Dim v2 = result(item.Item2(1)) Dim v3 = result(item.Item2(2)) Dim v4 = result(item.Item2(3)) If Not p4(v1, v2, v3, v4) Then Return False End If Case 5 Dim p5 = DirectCast(pred, Func(Of Object, Object, Object, Object, Object, Boolean)) Dim v1 = result(item.Item2(0)) Dim v2 = result(item.Item2(1)) Dim v3 = result(item.Item2(2)) Dim v4 = result(item.Item2(3)) Dim v5 = result(item.Item2(4)) If Not p5(v1, v2, v3, v4, v5) Then Return False End If Case 6 Dim p6 = DirectCast(pred, Func(Of Object, Object, Object, Object, Object, Object, Boolean)) Dim v1 = result(item.Item2(0)) Dim v2 = result(item.Item2(1)) Dim v3 = result(item.Item2(2)) Dim v4 = result(item.Item2(3)) Dim v5 = result(item.Item2(4)) Dim v6 = result(item.Item2(5)) If Not p6(v1, v2, v3, v4, v5, v6) Then Return False End If Case 7 Dim p7 = DirectCast(pred, Func(Of Object, Object, Object, Object, Object, Object, Object, Boolean)) Dim v1 = result(item.Item2(0)) Dim v2 = result(item.Item2(1)) Dim v3 = result(item.Item2(2)) Dim v4 = result(item.Item2(3)) Dim v5 = result(item.Item2(4)) Dim v6 = result(item.Item2(5)) Dim v7 = result(item.Item2(6)) If Not p7(v1, v2, v3, v4, v5, v6, v7) Then Return False End If Case 8 Dim p8 = DirectCast(pred, Func(Of Object, Object, Object, Object, Object, Object, Object, Object, Boolean)) Dim v1 = result(item.Item2(0)) Dim v2 = result(item.Item2(1)) Dim v3 = result(item.Item2(2)) Dim v4 = result(item.Item2(3)) Dim v5 = result(item.Item2(4)) Dim v6 = result(item.Item2(5)) Dim v7 = result(item.Item2(6)) Dim v8 = result(item.Item2(7)) If Not p8(v1, v2, v3, v4, v5, v6, v7, v8) Then Return False End If Case Else Throw New NotSupportedException End Select Next Return True End FunctionEnd Class    And now we can use the engine to solve the problem we mentioned above:   Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--Sub Test2() Dim engine = New NonDeterministicEngine() engine.AddParam("baker", {1, 2, 3, 4, 5}) engine.AddParam("cooper", {1, 2, 3, 4, 5}) engine.AddParam("fletcher", {1, 2, 3, 4, 5}) engine.AddParam("miller", {1, 2, 3, 4, 5}) engine.AddParam("smith", {1, 2, 3, 4, 5}) engine.AddRequire(Function(baker) As Boolean Return baker <> 5 End Function, {"baker"}) engine.AddRequire(Function(cooper) As Boolean Return cooper <> 1 End Function, {"cooper"}) engine.AddRequire(Function(fletcher) As Boolean Return fletcher <> 1 And fletcher <> 5 End Function, {"fletcher"}) engine.AddRequire(Function(miller, cooper) As Boolean 'Return miller = cooper + 1 Return miller > cooper End Function, {"miller", "cooper"}) engine.AddRequire(Function(smith, fletcher) As Boolean Return smith <> fletcher + 1 And smith <> fletcher - 1 End Function, {"smith", "fletcher"}) engine.AddRequire(Function(fletcher, cooper) As Boolean Return fletcher <> cooper + 1 And fletcher <> cooper - 1 End Function, {"fletcher", "cooper"}) engine.AddRequire(Function(a, b, c, d, e) As Boolean Return a <> b And a <> c And a <> d And a <> e And b <> c And b <> d And b <> e And c <> d And c <> e And d <> e End Function, {"baker", "cooper", "fletcher", "miller", "smith"}) Dim result = engine.GetNextResult() While Not result Is Nothing Console.WriteLine(String.Format("baker: {0}, cooper: {1}, fletcher: {2}, miller: {3}, smith: {4}", result("baker"), result("cooper"), result("fletcher"), result("miller"), result("smith"))) result = engine.GetNextResult() End While Console.WriteLine("Calculation ended.")End Sub   Also, this engine can solve the classic 8 queens puzzle and find out all 92 results for me.   Code highlighting produced by Actipro CodeHighlighter (freeware)http://www.CodeHighlighter.com/--Sub Test3() ' The 8-Queens problem. Dim engine = New NonDeterministicEngine() ' Let's assume that a - h represents the queens in row 1 to 8, then we just need to find out the column number for each of them. engine.AddParam("a", {1, 2, 3, 4, 5, 6, 7, 8}) engine.AddParam("b", {1, 2, 3, 4, 5, 6, 7, 8}) engine.AddParam("c", {1, 2, 3, 4, 5, 6, 7, 8}) engine.AddParam("d", {1, 2, 3, 4, 5, 6, 7, 8}) engine.AddParam("e", {1, 2, 3, 4, 5, 6, 7, 8}) engine.AddParam("f", {1, 2, 3, 4, 5, 6, 7, 8}) engine.AddParam("g", {1, 2, 3, 4, 5, 6, 7, 8}) engine.AddParam("h", {1, 2, 3, 4, 5, 6, 7, 8}) Dim NotInTheSameDiagonalLine = Function(cols As IList) As Boolean For i = 0 To cols.Count - 2 For j = i + 1 To cols.Count - 1 If j - i = Math.Abs(cols(j) - cols(i)) Then Return False End If Next Next Return True End Function engine.AddRequire(Function(a, b, c, d, e, f, g, h) As Boolean Return a <> b AndAlso a <> c AndAlso a <> d AndAlso a <> e AndAlso a <> f AndAlso a <> g AndAlso a <> h AndAlso b <> c AndAlso b <> d AndAlso b <> e AndAlso b <> f AndAlso b <> g AndAlso b <> h AndAlso c <> d AndAlso c <> e AndAlso c <> f AndAlso c <> g AndAlso c <> h AndAlso d <> e AndAlso d <> f AndAlso d <> g AndAlso d <> h AndAlso e <> f AndAlso e <> g AndAlso e <> h AndAlso f <> g AndAlso f <> h AndAlso g <> h AndAlso NotInTheSameDiagonalLine({a, b, c, d, e, f, g, h}) End Function, {"a", "b", "c", "d", "e", "f", "g", "h"}) Dim result = engine.GetNextResult() While Not result Is Nothing Console.WriteLine("(1,{0}), (2,{1}), (3,{2}), (4,{3}), (5,{4}), (6,{5}), (7,{6}), (8,{7})", result("a"), result("b"), result("c"), result("d"), result("e"), result("f"), result("g"), result("h")) result = engine.GetNextResult() End While Console.WriteLine("Calculation ended.")End Sub (Chinese version of the post: http://www.cnblogs.com/RChen/archive/2010/05/17/1737587.html) Cheers,  

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  • sudo: apache restarting a service on CentOS

    - by WaveyDavey
    I need my web app to restart the dansguardian service (on CentOS) so it needs to run '/sbin/service dansguardian restart' I have a shellscript in /home/topological called apacherestart.sh which does the following: #!/bin/sh id=`id` /sbin/service dansguardian restart r=$? return $r This runs ok (logger statement in script for testing output to syslog, so I know it's running) To make it run, I put this in /etc/sudoers: User_Alias APACHE=www # Cmnd alias specification Cmnd_Alias HTTPRESTART=/home/topological/apacherestart.sh,/sbin/e-smith/db,/etc/rc7.d/S91dansguardian # Defaults specification # User privilege specification root ALL=(ALL) ALL APACHE ALL=(ALL) NOPASSWD: HTTPRESTART So far so good. But the service does not restart. To test this I created a user david, and fudged the uid/gid in /etc/passwd to be the same as www: www:x:102:102:e-smith web server:/home/e-smith:/bin/false david:x:102:102:David:/home/e-smith/files/users/david:/bin/bash then logged in as david and tried to run the apacherestart.sh. The problem I get is: /etc/rc7.d/S91dansguardian: line 51: /sbin/e-smith/db: Permission denied even though S91dansguardian and db are in the sudoers command list. Any ideas?

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  • Multiple 301 redirect and massive loss of ranking

    - by DoesNotCompute
    I just remade from scratch a website for a client, the client ask me to preverve their ranking by making 301 redirect from the original URL to the new URL. For instance: http://plumber-directory.my-website.com/john-smith-city-1.php became http://directory.my-website.com/plumber/city/john-smith.html So i put the website online for few days until the 301 partially kicks in the google results. Then the client call me back to tell me that his boss want to switch back to the ancients URLs _< So i put a new 301 redirect: http://directory.my-website.com/plumber/city/john-smith.html revert to http://plumber-directory.my-website.com/john-smith-city-1.php Because google had just few days to assimilate the new URLs, it have now the two kinds of URLs in it's own result pages. Also the ranking of the website keeps falling down every day, i suspect google to mistaking those redirects for duplicate content. Is there something i can do to avoid a total loss of rankings?

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  • Oracle presentations at the CIPS ICE Conference, November 5 - 7, Edmonton, Alberta, Canada

    - by Darin Pendergraft
    Oracle will be presenting at the CIPS ICE conference the last week of October in Calgary and the first week of November in Edmonton. Here is a list of the presentations for Edmonton: SHAW Conference Centre • Session Title: Identity and Access Management Integrated; Analyzing the Platform vs Point Solution Approach • Speaker: Darin Pendergraft • Monday, November 5th @ 10:45 AM - 12:00 PM • Session Title: Is Your IT Security Strategy Putting Your Institution at Risk? • Speaker: Spiros Angelopoulos • Monday, November 5th @ 1:45 PM - 3:00 PM Three sessions under the TRAIN: Practical Knowledge Track • Monday, November 5th @ 10:45 AM, 1:45 PM, 3:30 PM • Title: What's new in the Java Platform   Presenter: Donald Smith • Title: Java Enterprise Edition 6   Presenter: Shaun Smith • Title: The Road Ahead for Java SE, JavaFX and Java EE    Presenters: Donald Smith and Shaun Smith To learn more about the conference, and to see the other sessions go to the conference website.

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  • First steps into css - aligning data insite one DIV [on hold]

    - by Andrew
    I am trying to move away from tables, and start doing CSS. Here is my HTML code that I currently trying to place into a nice looking container. <div> <div> <h2>ID: 4000 | SSN#: 4545</h2> </div> <div> <img src="./images/tenant/unknown.png"> </div> <div> <h3>Names Used</h3> Will Smith<br> Bill Smmith<br> John Smith<br> Will Smith<br> Bill Smmith<br> John Smith<br> Will Smith<br> Bill Smmith<br> John Smith<br> </div> <div> <h3>Phones Used</h3> 123456789<br> 123456789<br> 123456789<br> 123456789<br> 123456789<br> 123456789<br> 123456789<br> 123456789<br> </div> <div> <h3>Addresses Used</h3> 125 Main Evanston IL 60202<br> 465 Greenwood St. Schaumburg null 60108<br> 125 Main Evanston IL 60202<br> 465 Greenwood St. Schaumburg null 60108<br> 125 Main Evanston IL 60202<br> 465 Greenwood St. Schaumburg null 60108<br> 125 Main Evanston IL 60202<br> 465 Greenwood St. Schaumburg null 60108<br> 125 Main Evanston IL 60202<br> 465 Greenwood St. Schaumburg null 60108<br> </div> </div> I now understand now I create classes and assign classes to elements. I have no issues doing colors. But I am very confused with elements alignments. Could you suggest a nice way to pack it together with some CSS which I can analyze and take as a CSS starting learning point?

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  • How do you measure the value of your software?

    - by Mike
    Hi, One of the principles of agile is that you should measure working software: Working software is the primary measure of progress - 12 principles of Agile The thing is, while I can measure my software in terms of stories done, bugs squashed or the volume of defect reports decreasing, I'm stuck on how to measure the value of my software. If I use Mike Cohn as an example and his helping SalesForce.com deliver 500% more value to it's customers compared to the previous year* - how do I measure that increase? How do I measure where I am right now? Other metrics he uses are the number of features and the number of features per developer. This is something I could work out if my backlog was in good order and the stories were cut up by 'feature', but we're just starting out with Agile, so I need some way of working out what the value is we deliver now, then use a similar metric in say, six months, to see if we've increased our output. I've heard about measuring value of software by an uptick in revenue, or an increase in customer satisfaction (how would you measure that though?) but those increases could be attributed to anything in the company (sales, accounting, support) and not directly to the work my department is doing. So, how do you guys measure the value of your software and how did you start? Thanks, Mike *Succeeding With Agile - Mike Cohn

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  • UK Partner Briefing – Business Analytics - 24 Sept 2012

    - by Mike.Hallett(at)Oracle-BI&EPM
    Monday 24th September 2012 - Oracle City Office, London Register Here for this important, free briefing Oracle Partners are invited to attend this Business Analytics Partner Briefing on 24th September 2012 in Oracle’s London Moorgate Offices with Particular focus on Exalytics, Endeca and, BI Mobile. Who should attend? Oracle Business Analytics is one of our fastest growing product lines, hence this briefing will be of value to any executives looking for new business opportunities or extending their existing Analytics line of business Background This half day event will inform you of Oracle's Business Analytics strategy, how your organisation can gain commercial advantage from reselling and deploying Oracle's BI portfolio, and the tools and resources to support your sales engagements. Agenda 13:45 – Registration, Coffee, and iPad set up 14:30 – Briefing Commences: Welcome & Introduction to the Business Analytics FY13 Strategy from Mike Pell, VP UK Business Analytics Sales 15:15 – Exalytics: Speed of Thought Analytics 16:00 – Mobile BI & Endeca 16:45 – Event Wrap-up and Q&A 17:00 – Meet the UK BI Sales Team: Networking Please note – If you have an iPad please bring it with you to the session, as we will be helping to set these up with BI Mobile from 13:45 onwards. Click here to register now for this briefing for Oracle Partners. Best regards, Mike Pell                                  Duncan Fitter                           Mike Thompson VP UK Analytics Sales             BA Business Development       Alliances & Channels

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  • How to get the second word from a String?

    - by Pentium10
    Take these examples Smith John Smith-Crane John Smith-Crane John-Henry Smith-Crane John Henry I would like to get the John The first word after the space, but it might not be until the end, it can be until a non alpha character. How would this be in Java 1.5?

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  • Algorithm to compare people names to detect identicalness

    - by Pentium10
    I am working on address book synchronization algorithm. I would like to reuse some code if there exists, but couldn't find one yet. Does someone know about an algorithm that will tell me in numbers/float/procent how much two names are identical. Levenstein distance is not good in this approach, as names and our adddress books are matching the begining of each of the name sections. John Smith should match Smith Jon, Jonathan Smith, Johnny Smith

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  • Add 2 values to 1 key in a PHP array

    - by Mike Munroe
    I have a result set of data that I want to write to an array in php. Here is my sample data: **Name** **Abbrev** Mike M Tom T Jim J Using that data, I want to create an array in php that is of the following: 1|Mike|M 2|Tom|T 3|Jim|j I tried array_push($values, 'name', 'abbreviation') [pseudo code], which gave me the following: 1|Mike 2|M 3|Tom 4|T 5|Jim 6|J I need to do a look up against this array to get the same key value, if I look up "Mike" or "M". What is the best way to write my result set into an array as set above where name and abbreviation share the same key?

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