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Search found 408 results on 17 pages for 'unzip'.

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  • unzip and maintain directory structure of archives

    - by Ramy
    On fedora-13, I tried using: unzip -j [nameof.zip] but this doesn't seem to maintain the folder structure of the original archive. I REALLY need to maintain this structure because the archive is a backup of all my m4a's which are being converted to mp3. If I just convert it as is, then i'll just have a single massive directory full of mp3's, but they won't be in their respective "artist" folder.

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  • unzip and maintain directory structure or archives

    - by Ramy
    On fedora-13, I tried using: unzip -j [nameof.zip] but this doesn't seem to maintain the folder structure of the original archive. I REALLY need to maintain this structure because the archive is a backup of all my m4a's which are being converted to mp3. If I just convert it as is, then i'll just have a single massive directory full of mp3's, but they won't be in their respective "artist" folder.

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  • Unzip password protected Zip file in SSIS

    - by MarcoF
    Does anyone know how to Unzip password protected files in an SSIS package? We have an SSIS package that currently use java.util.zip to unzip zip file and has been working perfectly for some time now. They now want to password protect the files and unfortunetly this library cannot do it. We are using a SQL server 2008 with .Net 3.5 on the windows server 2008 R2.

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  • uncompressing .zip file in linux [closed]

    - by Suren
    hi, I have a .zip file (It contains multiple files, ex: file1.txt file2.txt file3.txt.. n so on) in a directory. And my query is: How to extract the files from .zip archive to the very same directory and how to create the list of all the files extracted from .zip archive.** The extracted file name should be printed like this in the file named: file_list: file1.txt file2.txt file3.txt filen.txt I have tried the following command assuming that my .zip file name is "data.zip". unzip -qoj data.zip | unzip -ql data.zip > file_list I have used unzip -qoj data.zip to extract all the files in the same directory(quietly,overwrite,junk_path). When I try to insert -l with the first unzip command then the command doesn't extract the file in the current and only files are listed thats why I have to used unzip again after the first pipe(If I am making a mistake here let me know please). I get the following output Length Date Time Name -------- ---- ---- ---- 0 12-21-09 14:25 data/ 6148 12-21-09 14:25 data/.DS_Store 0 12-21-09 14:25 __MACOSX/ 0 12-21-09 14:25 __MACOSX/data/ 82 12-21-09 14:25 __MACOSX/data/._.DS_Store 82 12-11-09 13:59 data/file1.txt 120 12-11-09 13:59 data/file2.txt 166 12-11-09 13:59 data/file3.txt -------- ------- 6598 8 files How do I extract only file1.txt file2.txt file3.txt from this stdout? Is it possible to do this with linux command or I have to write a perl script for this? Thank you.

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  • Windows command line built-in compression/decompression tool?

    - by Will Marcouiller
    I need to write a batch file to unzip files to their current folder from a given root folder. Folder 0 |----- Folder 1 | |----- File1.zip | |----- File2.zip | |----- File3.zip | |----- Folder 2 | |----- File4.zip | |----- Folder 3 |----- File5.zip |----- FileN.zip So, I wish that my batch file is launched like so: ocd.bat /d="Folder 0" Then, make it iterate from within the batch file through all of the subfolders to unzip the files exactly where the .zip files are located. So here's my question: Does the Windows (from XP at least) have a command line for its embedded zip tool? Otherwise, shall I stick to another third-party util?

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  • Windows command line built-in compression/extraction tool?

    - by Will Marcouiller
    I need to write a batch file to unzip files to their current folder from a given root folder. Folder 0 |----- Folder 1 | |----- File1.zip | |----- File2.zip | |----- File3.zip | |----- Folder 2 | |----- File4.zip | |----- Folder 3 |----- File5.zip |----- FileN.zip So, I wish that my batch file is launched like so: ocd.bat /d="Folder 0" Then, make it iterate from within the batch file through all of the subfolders to unzip the files exactly where the .zip files are located. So here's my question: Does the Windows (from XP at least) have a command line for its embedded zip tool? Otherwise, shall I stick to another third-party util?

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  • Using DotNetZip Library unzip file with non ASCII characters

    - by Morten Lyhr
    I'm trying to unzip a file, using DotNetZip Library. The file contains folders and files with danish characters (æøåÆØÅ). TotalCommander, 7Zip, Windows own zip all extract the files correctly, but DotNetZip Library mangles the danish characters. Ex: File_æøåÆØÅ.txt becomes File_æ¢åÆ¥Å.txt insted of aø it contains a ¢. insted of a Ø it contains a ¥. Code: using (var zipFile = ZipFile.Read(@"File_æøåÆØÅ.zip")) { zipFile.ExtractAll(@"File_æøåÆØÅ", ExtractExistingFileAction.OverwriteSilently); } I'm using the default encoding("da-DK" culture), I have tried other encodings like UTF8 etc. How can I unzip a file containing filenames with Danish characters?

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  • Windows 2003 R2 zip program blocking EXE file

    - by Harvey Kwok
    I have a Windows 2003 R2 Enterprise Edition SP2 32-bit machine with all latest patch (as of 1-6-2011). It's a VM. I have a zip file, including a pdf file, a txt file and a exe file. If I copy the zip file onto the machine via a shared network drive, I can unzip all the files properly without problems. If I put the zip file on my web server and then I download it from there, I can only unzip the pdf file and txt file. The exe file is silently ignored. I searched the web and found somebody reporting similar issue on XP. If I right click on the zip file downloaded from the web server, at the bottom of the general page, it has a warning message saying that "This file came from antoher computer and might be blocked to help protect this computer" I understand that I can solve the problem by simply clicking the "Unblock" button and extract the file again. The things that bothering me is that why the warning message says "might be blocked"? I tried downloading the same zip file from the same web server on to my Windows 7 box with latest patch. It also shows the same warning message. However, even with the warning message, I can extract all the files properly without clicking the "Unblock" button. Is it a bug in Windows 2003 R2 SP1? Is there any security settings controlling this? How likely will the end user seeing this problem? I want to dig into this because I am worrying people downloading my zip file from my web server might see similar problems. The first thought coming to the user's mind will be the zip file is somehow corrupted. Honestly, I didn't know this "Unblock" feature in Windows before I run into this problem. EDIT I just tried it on another Windows 2003 R2 SP1 machine. The zip program doesn't block the EXE file on that machine either. Both Windows 2003 R2 SP1 machines are joining to the same forest.

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  • Change present working directory of a calling shell from a ruby script

    - by Erik Kastman
    I'm writing a simple ruby sandbox command-line utility to copy and unzip directories from a remote filesystem to a local scratch directory in order to unzip them and let users edit the files. I'm using Dir.mktmpdir as the default scratch directory, which gives a really ugly path (for example: /var/folders/zz/zzzivhrRnAmviuee+++1vE+++yo/-Tmp-/d20100311-70034-abz5zj) I'd like the last action of the copy-and-unzip script to cd the calling shell into the new scratch directory so people can access it easily, but I can't figure out how to change the PWD of the calling shell. One possibility is to have the utility print out the new path to stdout and then run the script as part of a subshell (i.e. cd $(sandbox my_dir) ), but I want to print out progress on the copy-and-unzipping since it can take up to 10 minutes, so this won't work. Should I just have it go to a pre-determined, easy-to-find scratch directory? Does anyone have a better suggestion? Thanks in advance for your help. -Erik

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  • Error in unzipping a file from a python script running as daemon

    - by Fedrick
    I am getting an error whenever i try to run following unzip command from a python script which is running as a daemon Command : unzip abcd.zip /dev/null Error End-of-central-directory signature not found$ a zip file, or it constitutes one disk of a multi-part archive. In the latter case the central directory and zipfile comment will be found on the last disk(s) of this archive unzip: cannot find zipfile directory in one of abcd.zip$ abcd.zip.zip, and cannot find abcd.zip.ZIP, period. Could anyone help me in this regard? Thanks in advance.

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  • Can a shell loop do this?

    - by helpwithshell
    Ive seen loops to unzip all zip files in a directory, however, before I run this, I would rather make sure what Im about to run will work right: for i in dir; do cd $i; unzip '*.zip'; rm -rf *.zip; cd ..; done Basically I want it to look at the output of "dir" see all the folders, for each directory cd into it, unzip all the zip archives, then remove them, then cd back and do it again until theres no more. Is this something I should do in a single command or should I consider doing this in perl?

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  • Howto unzip ".xz" file with 7z and lzma

    - by neversaint
    I tried to uncompressed a "*.xz" file with both 7z and lzma. But they gave me such message: $ 7z x myfile.fq.xz 7-Zip 4.57 Copyright (c) 1999-2007 Igor Pavlov 2007-12-06 p7zip Version 4.57 (locale=C,Utf16=off,HugeFiles=on,4 CPUs) Processing archive: myfile.fq.xz Error: Can not open file as archive $ 7z x myfile.fq.xz 7-Zip 4.57 Copyright (c) 1999-2007 Igor Pavlov 2007-12-06 p7zip Version 4.57 (locale=C,Utf16=off,HugeFiles=on,4 CPUs) Processing archive: myfile.fq.xz Error: Can not open file as archive and with lzma $ lzma -d myfile.fq.xz J_12.fq.xz: unknown suffix -- unchanged with other option: $ lzma -S .xz -d myfile.fq.xz lzma: SetDecoderProperties() error

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  • Filename encoding broken after unzip on windows

    - by flammi88
    I zipped a directory on my linux server. Many files in the directory have german umlauts in their filename. The filesystem is ext3 and the system locale is set to de_DE.utf8. I used the following command to create the zip file: zip -r somezip.zip somefolder/ I transfered this file via WinSCP to my windows laptop and unzipped it. The issue: All filenames with german umlauts are broken. On my linux server the filenames are displayed correctly. I assume that I made a mistake when i created the zip file. Has someone any ideas how i can perserve the right filename encoding when I zip the files with the zip command on linux?

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  • Filename encoding broken after unzip on windows

    - by flammi88
    I zipped a directory on my linux server. Many files in the directory have german umlauts in their filename. The filesystem is ext3 and the system locale is set to de_DE.utf8. I used the following command to create the zip file: zip -r somezip.zip somefolder/ I transfered this file via WinSCP to my windows laptop and unzipped it. The issue: All filenames with german umlauts are broken. On my linux server the filenames are displayed correctly. I assume that I made a mistake when i created the zip file. Has someone any ideas how i can perserve the right filename encoding when I zip the files with the zip command on linux?

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  • Apache has no rights to unzip file uploaded by DirectAdmin created FTP user

    - by FlyOn
    I know similar things have been asked a thousandfold, but I can't seem to figure it out.. I have recently started renting a VPS. It runs DirectAdmin. I created a reseller account in the admin account, and created a new user (with FTP account) with the reseller account. I logged in with FTP as the created user and uploaded a zip file and a php file which will extract the zip. But when running the script in the browser I get "Permission denied" errors however. Probably because Apache is not in the same group as the users FTP account. Now my question is: How can I solve this once and for all, so that I don't have to do it again for every new user account I create through DirectAdmin?

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  • -Unzip failed...Access is denied- error while adding Android SDK components to Eclipse

    - by vmitsura
    Eclipse (3.5) --Window--Android SDK and AVD Manager--< When Adding SDK Components, there is the following error message: Downloading Documentation for Android SDK, API 7, revision 1 Installing Documentation for Android SDK, API 7, revision 1 Unzip failed: C:\Program Files\Android_SDK\temp\DocPackage.new01\navtree_data.js (Access is denied). This is followed by another message: -Nothing is installed- I use Windows 7 64-bit system. Could anyone please help to get around this? Thank you in advance. vmitsura

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  • While submitting app to iOS App Store, "Unable to unzip application"

    - by Ivan Vucica
    I've successfully submitted "Product Name" to App Store. However, submitting "Product Name Lite", I keep getting the error "Unable to unzip application" in both Application Loader and built-in Xcode's uploader. Error persists even after eliminating spaces from the product name; in fact, I don't think there's whitespace anywhere in the app or the plist anymore. What might be causing this "highly descriptive" error? I'm using Xcode 3.2.5. Attempting to clean, build, and build&archive did not help.

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  • Unzip a folder which is programatically downloaded in Silverlight

    - by subbu
    Hi all, My requirement is this. I am programmatically downloading a folder from a remote server in zipped format using WebClient. This part is done. My folder will have only DLLs and EXEs. Can any one suggest an unzipping algorithim or libraries which can be used for unzipping? http://www.sharpgis.net/post/2009/04/21/REALLY-small-unzip-utility-for-Silverlight.aspx I tried out the method suggested in the above link. But my DLLs and EXEs are getting corrupted. Can any one help me out in this? My programming environment is VS2010 and Silverlight 4.0. Application is OOB and has Elevated Priv

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  • Windows command line compression/extraction tool?

    - by Will Marcouiller
    I need to write a batch file to unzip files to their current folder from a given root folder. Folder 0 |----- Folder 1 | |----- File1.zip | |----- File2.zip | |----- File3.zip | |----- Folder 2 | |----- File4.zip | |----- Folder 3 |----- File5.zip |----- FileN.zip So, I wish that my batch file is launched like so: ocd.bat /d="Folder 0" Then, make it iterate from within the batch file through all of the subfolders to unzip the files exactly where the .zip files are located. So here's my question: Does the Windows (from XP at least) have a command line for its embedded zip tool? Otherwise, shall I stick to another third-party util?

    Read the article

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