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  • QueryString problem in .aspx - prints out nothing

    - by user321256
    I need to print out the querystring value "?type=xxx" inside my .aspx-page, why doesn't this work: <%= Request.QueryString("type") %> While this does: <%= Request.QueryString(0) %> The first prints out nothing, the second one prints out the value as expected, but it isn't always the first value I want... Any ideas?

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  • Is there any pros to duplicate browser/keyboard functionality?

    - by metal-gear-solid
    Is it good for user experience to duplicate browser/keyboard functionality? For example: to provide these links on a web-page. "Back to top" link "Print this page" link "Add to Favorite" link "Back" button/link "Text zoom" button Are they really create Site's usability and accessibility? How screen reader will behave these links, will these confuse to screen reader users?

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  • TERM environment variable not set

    - by rahkarp
    I'm using python to develop an app and want to view running processes.The code txt = commands.getoutput("top -d 1") print txt gives an error "TERM Environment Variable not set" Can someone tell me what this means and how to solve this

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  • How to pickle and unpickle objects with self-references and from a class with slots?

    - by EOL
    Is it possible to pickle an object from a class with slots, when this object references itself through one of its attributes? Here is a simple example: import weakref import pickle class my_class(object): __slots__ = ('an_int', 'ref_to_self', '__weakref__') def __init__(self): self.an_int = 42 self.ref_to_self = weakref.WeakKeyDictionary({self: 1}) # __getstate__ and __setstate__ not defined: how should this be done? if __name__ == '__main__': obj = my_class() # How to make the following work? obj_pickled = pickle.dumps(obj) obj_unpickled = pickle.loads(obj_pickled) # Self-references should be kept: print "OK?", obj_unpickled == obj_unpickled.ref_to_self.keys()[0]

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  • problem with list return type??

    - by kaushik
    my list has value such as m=[['na','1','2']['ka','31','45']['ra','3','5'] d=0 r=2 t=m[d][r] print t # this is givin number i.e 2 Now when I use this value u=[] u=m[t] I am getting an err msg saying type error list does take str values... i want to use like this how can i convert that t into a integer?? please suggest.. thanks..

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  • Flex graph printing

    - by vanzylv
    Hi Guys I'm looking for a way to print / save flex graphs, preferably without changing the flex code.Is this possible to to from the client with some kind of JavaScript library.If I need to change the flex,is ALIVEPDF the way to go (converting content to pdf first) or are there simpler solutions to this. Thanks

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  • Python/Django: log to console under runserver, log to file under Apache

    - by Justin Grant
    How can I send trace messages to the console (like print) when I'm running my Django app under manage.py runserver, but have those messages sent to a log file when I'm running the app under Apache? I reviewed Django logging and although I was impressed with its flexibility and configurability for advanced uses, I'm still stumped with how to handle my simple use-case. My apologies for not being able to find the answer elsewhere-- this is a newbie question I know.

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  • python: How to refer to specific item within a list of lists?

    - by user964689
    Python beginner here, I have a list of lists and want to refer to a specific part of that list. For example lol = [[1, 2, 4], [6, 7, 8], [9, 10, 14]] If I just want to print the first item in one of the lists, eg the 1, 6 or 9, how would I do that? I can only find ways to refer to each of the lists seperately eg lol[0] but not to then refer to an item within that list. Thank you in advance for your help! Cheers

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  • word after the space NSlog

    - by DD007
    I am new bie to xcode may be question is silly but I am lagging with my home work. In a file I want to read a specific character after the string. I want to read all the character after the space. ex: asasasasasas wewewewewewe qwqwqwqwqwqw xyz_ 22 aaaaaaaaaaa bbbbbbbbbbb ccccccccccccccc ddddddddddddd fgfgfgfgfgfgfg ererererererer abc_ 12 bbbbbbbbbb dddddddd jkjkjkjkjkjkjk lalallalalalal everything is fine .. but i want to print after "xyz_ 22" as aaaaaaa then bbbb ccc

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  • rake does not returning anything

    - by CHID
    Hi, I jus created a rails application. I created a model using ruby script/generate model Article next i edited the my articles.rb file by adding these lines in self.up method def self.up create_table :articles do |t| t.string :title t.text :body t.string :published_at t.timestamps end end Now i ran rake db:migrate . But migrate does not work, it simply does no print anything. Anyone knows where i am going wrong?

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  • How to iterate a list inside a list in java?

    - by user2142786
    Hi i have two value object classes . package org.array; import java.util.List; public class Father { private String name; private int age ; private List<Children> Childrens; public String getName() { return name; } public void setName(String name) { this.name = name; } public int getAge() { return age; } public void setAge(int age) { this.age = age; } public List<Children> getChildrens() { return Childrens; } public void setChildrens(List<Children> childrens) { Childrens = childrens; } } second is for children package org.array; public class Children { private String name; private int age ; public String getName() { return name; } public void setName(String name) { this.name = name; } public int getAge() { return age; } public void setAge(int age) { this.age = age; } } and i want to print there value i nested a list inside a list here i am putting only a single value inside the objects while in real i have many values . so i am nesting list of children inside father list. how can i print or get the value of child and father both. here is my logic. package org.array; import java.util.ArrayList; import java.util.Iterator; import java.util.List; public class ArrayDemo { public static void main(String[] args) { List <Father> fatherList = new ArrayList<Father>(); Father father = new Father(); father.setName("john"); father.setAge(25); fatherList.add(father); List <Children> childrens = new ArrayList<Children>(); Children children = new Children(); children.setName("david"); children.setAge(2); childrens.add(children); father.setChildrens(childrens); fatherList.add(father); Iterator<Father> iterator = fatherList.iterator(); while (iterator.hasNext()) { System.out.println(iterator.toString()); } } }

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  • Creating an instance within the Class itself

    - by didxga
    What's going on when the assignment statement executed at Line 4, does compiler ignore the new operator and keep the foo variable being null or something else happen to handle this awkward moment? public class Foo { // creating an instance before its constructor has been invoked, suppose the "initializing" // gets printed in constructor as a result of the next line, of course it will not print it private Foo foo = new Foo();//Line 4 public Foo() { System.out.println("initializing"); } }

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  • Write failed, errno 0

    - by EpsilonVector
    I have a client server situation in which I receive data using read(socket, char_buf, BUF_SIZE) and then try to write it into a log file using write(filefd, char_buf, strlen(char_buf)) Strangely enough this fails (write returns -1), and yet the errno is set to 0, and I can print the message, AND the log file descriptor works (I write to it before and after this command). What's going on?? (Working on Linux kernel 2.4 (homework))

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  • PRINTER SET UP IN EXCEL VISUAL BASIC

    - by Gina
    I am trying to assign a cell in excel for the user to type the printer name where they want the print out to go and then use that value in the Application.ActivePrinter = (use the cell value) Even though I have done the programming assigning a name to the cell and using it in a variable it is giving me an error. I have set my variable as string, text, object and variant already and it's not working. Do you know what code should I use to be able to do this?

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  • Exception Handaling in google app engine

    - by Rahul99
    i am raising exception using if UserId == '' and Password == '': raise Exception.MyException , "wrong userId or password" but i want print the error message on same page class MyException(Exception): def __init__(self,msg): Exception.__init__(self,msg)

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