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• Recreating "presentModalViewController"?

  - by Benjohn Barnes

  I'm using a UIImagePickerController set up as a camera with an overlay view. I want to present a modal view controller on top on this. When I do so, though, the camera view "closes". This would be okay, but when I dismissModalViewControllerAnimated, I see the closed camera, and there is a long and annoying delay before it reopens. I would like to avoid this. Unless someone has a better approach, I am planning to simply perform the transition that presentModalViewController would perform myself. However, if I take my modal view from it's controller and add it as a sub view of the camera overlay view, like this: [[_imagePickerController cameraOverlayView] addSubview: [viewController view]]; then the modal view doesn't show up at all, and the application crashes with an EXC_BAD_ACCESS in my "modal" view's layoutSubViews. Where as, if I present it with presentModalViewController, everything works fine. Clearly, presentModalViewController is also doing some other stuff. Does anyone know what this is so that I can recreate it?

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• Cocoa Touch: Why doesn't UINavigationController render 'Back' button?

  - by Joshua

  When I push a view controller it animates properly and slides in, the only problem is that no 'Back' button is rendered up top.The back button is still there, I can still tap it, it just doesn't render on the screen. This behavior is identical in both the simulator and on multiple devices. Is this a known issue or bug? Using 3.1.3 of the iPhone SDK. More information: It renders it for further levels, just not on the second level of nav controller. So Main Page (No back button - OK). Second level page (back button, but doesn't render - not OK). Third level page (Back button there and rendering - OK).

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• Updating DetailViewController from RootController

  - by Stefano Salmaso

  I'm trying to create an iPad application with a similar user interface to Apple's Mail application, i.e: RootView controller (table view) on the left hand side of the split view for navigation with a multiple view hierarchy. When a table cell is selected a new table view is pushed on the left hand side The new view on the left side can update the detail view. I can accomplish both tasks BUT NOT TOGETHER. I mean I can make a multi-level table view in the RootController.(HERE you can find the working source code). Or I can make a single-level table view in the RootController which can update the detailViewController (here there is the source code:http://www.megaupload.com/?d=D6L0463G). Can anyone tell me how to make a multi-level table in the RootController which can update a detailViewController? There is more source code at the link but below is the method in which I presume I have to declare a new detailViewController (which has to be put in the UISplitViewController): - (void)tableView:(UITableView *)TableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { NSDictionary *dictionary = [self.tableDataSource objectAtIndex:indexPath.row]; //Get the children of the present item. NSArray *Children = [dictionary objectForKey:@"Children"]; // if([Children count] == 0) { /* Create and configure a new detail view controller appropriate for the selection. */ NSUInteger row = indexPath.row; UIViewController <SubstitutableDetailViewController> *detailViewController = nil; if (row == 0) { FirstDetailViewController *newDetailViewController = [[FirstDetailViewController alloc]initWithNibName:@"FirstDetailView" bundle:nil]; detailViewController = newDetailViewController; } if (row == 1) { SecondDetailViewController *newDetailViewController = [[SecondDetailViewController alloc]initWithNibName:@"SecondDetailView" bundle:nil]; detailViewController = newDetailViewController; } // Update the split view controller's view controllers array. NSArray *viewControllers = [[NSArray alloc] initWithObjects:self.navigationController, detailViewController, nil]; splitViewController.viewControllers = viewControllers//nothing happens..... [viewControllers release];// } else { //Prepare to tableview. RootViewController *rvController = [[RootViewController alloc]initWithNibName:@"RootViewController" bundle:[NSBundle mainBundle]]; //Increment the Current View rvController.current_level += 1; //Set the title; rvController.current_title = [dictionary objectForKey:@"Title"]; //Push the new table view on the stack [self.navigationController pushViewController:rvController animated:YES]; rvController.tableDataSource = Children; [rvController.tableView reloadData]; //without this instrucion,items won't be loaded inside the second level of the table [rvController release]; } }

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• Yet another Rails routing question

  - by danhere

  I can't seem to grasp the Rails routing just yet. I want to be able to link the site to, for example, ...com/store/xbox360/Mass Effect 2 (which is /store(my controller)/:system/:title). I have the database entries that include the :system and :title variables (?). How would I route these to show up and filter these entries? Or is this something I need to set up in the controller? I'm lost. Thanks so much for your help.

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• page not show after issuing zf command

  - by Nazmin

  hello guys, just simple question, recently i have setup a web server to build project using zend framework, after setup and see those welcome page saying that you are creating websites powered by zendframework, then i try issuing command, $ zf create controller alert i get the message that saying that i've successfully create controller, view and so on, but when i try to navigate to the page by URL, ex: www.mywebapp.com/alert the page is broken, i've check those tuts but none of them showing this case. can some one define which step i've skip? update: (25/5/2010) so i've found that there is no problem, is just that i've not configured properly my route to my web apps, so i have to type URL like this: www.mywebapp.com/index.php/alert how am I going to change this? i mean i want to explode "index.php" out of URL.

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• Strategies for generating Zend Cache Keys

  - by emeraldjava

  ATM i'm manually generating a cache key based on the method name and parameters, then follow to the normal cache pattern. This is all done in the Controller and i'm calling a model class that 'extends Zend_Db_Table_Abstract'. public function indexAction() { $cache = Zend_Registry::get('cache'); $individualleaguekey = sprintf("getIndividualLeague_%d_%s",$leagueid,$division->code); if(!$leaguetable = $cache->load($individualleaguekey)) { $table = new Model_DbTable_Raceresult(); $leaguetable = $table->getIndividualLeague($leagueid,$division,$races); $cache->save($leaguetable, $individualleaguekey); } $this->view->leaguetable = $leaguetable; .... I want to avoid the duplication of parameters to the cache creation method and also to the model method, so i'm thinking of moving the caching logic away from my controller class and into model class packaged in './model/DbTable', but this seems incorrect since the DB model should only handle SQL operations. Any suggestions on how i can implement a clean patterned solution?

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• cakephp why can't I have an admin route and a superuser route?

  - by Jack B Nimble

  In core.php I can define Configure::write('Routing.admin', 'admin'); and /admin/controller/index will work. but if I define both Configure::write('Routing.admin', 'admin'); Configure::write('Routing.superuser', 'superuser'); and try to look at /superuser/blah/index/ instead of it saying the controller doesn't exist it says Error: SuperuserController could not be found. instead of saying Error: BlahController could not be found. When I first read the documentation I was under the impression I could run both routes, and not just one or the other. Is there something more I need to do?

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• zend_acl: Adding extra resources dynamically and getting a param predispatch

  - by Timmeh

  First sorry about the woffle as I'm not sure how best to describe this. Basically I am not sure how I can get param in the bootstrap before the controller is loaded, but here is the long winded version... I have got an acl class storing all my default resources in. All my page/post content is a database and I want the admin the ability to choose who which role the page would become available. I know it is possible just to loop through the database table and add them all in at once, but I am concerned that this is a drain on resources. I have it working whereby my access check plugin can call a dynamic permission function, but I need to get the parameter of the current page ID and it's permission to set it before the controller is loaded. Does that make sense or am I worry over nothing and I should just get the resources of all the pages at once? thanks in advance for reading my garble!!

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• How to programatically set cell.textLabel.text from a different view?

  - by Andy

  I've got a view controller, call it VC1, that's a table view. When I tap a cell in the table view, I am presented with a new view controller, call it VC2, which is a short list of choices. After making a choice, I want to dismiss VC2 and set the cell.textLabel.text property of the VC1 cell I originally tapped to the value I selected in VC2. Conceptually speaking, what is the proper way to do this? I've tried a handful of different approaches, but all of them seem wonky at best, and only one of them actually worked - although it was the most cumbersome of all, passing references to both view controllers and table view cells and all kinds of things. It just feels like I'm making a mountain out of what is probably a mole hill. This is such a common paradigm that I find it hard to believe there's not a simple method for doing it. Thanks in advance for any input you can offer.

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• Problem with asp.net mvc route not firing when in <script> tag

  - by Chev

  I cannot get the following route to fire when a url is requested from a script tag. I have the following route: // maps to "/cache/cachecontent/JavaScriptInclude/1/javascript" routes.MapRoute( null, "cache/{action}/{key}/{version}/{type}", new { controller = "Cache", action = "CacheContent", key = "", version = "", type = "" } ); I have a javascript script tag like: <script type="text/javascript" src="/cache/cachecontent/JavaScriptInclude/1/javascript" /> Yet the route is not firing and the controller is not instantiated. If i drop the url into the address bar of the browser all is fine, but is not triggered from the javascript tag? Any ideas?

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• Zend Framework modular app, can't load models for each module, autoloading models?

  - by EricP

  Is there a way to have models for each module? I have 3 modules, one is a "contacts" module. I created a model for it in modules/contacts/models/Codes.php Codes Controller class Contacts_CodesController extends Zend_Controller_Action { public function init() { /* Initialize action controller here */ $this->view->messages = $this->_helper->flashMessenger->getMessages(); } public function indexAction() { $codesTable = new Contacts_Model_Codes(); } Codes Model: class Contacts_Model_Codes extends Zend_Db_Table { protected $_name = 'codes'; } The error I get: Fatal error: Class 'Contacts_Model_Codes' not found in /Applications/MAMP/htdocs/zf_site/application/modules/contacts/controllers/CodesController.php on line 26 thanks

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• rails expiring cache

  - by ash34

  Hi, I entered some products data into a table using a migration. I need to expire the page and fragment cache when I update, add, delete products from this table. I created a sweeper for this. class ProductSweeper < ActionController::Caching::Sweeper observe Product def after_create expire_cache end def after_save expire_cache end def after_update expire_cache end def after_destroy expire_cache end private def expire_cache expire_page(:controller => 'ProductsController', :action => 'index') expire_fragment 'listed_products' end end Then in script/console I update the product name and saved. When I reload my app in the browser it still gives me a cache hit. Cached fragment hit: views/listed_products (0.2ms) Can someone tell me how to expire this cache. I will not be adding, updating, deleting products through a controller action. thanks, ash

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• link_to for calling an action, instead of a button_to

  - by Brian Roisentul

  I'd like to call an action with a link_to button without being redirected to another page(I don't want ajax). For you to have an idea, I'm trying to accomplish a sort "link button" in a search page. So, when the link is clicked, the page should be refreshed showing the list ordered as I tell it in the action. If I do the following in my view, it will ask me for a template called as the action, and I don't want it: <%= link_to 'M&Aacute;S RELEVANTES', search_filter_relevance_path %> My routes file looks like this: map.search_filter_relevance "/anuncios/buscar", :controller => 'announcements', :action => 'search_filter_relevance' And my controller looks like this(I haven't developed the functionality yet): def search_filter_relevance end Any help on this will be appreciated.

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• Navigation Within TabController

  - by David.Chu.ca

  I am trying to use UITabController as may controller in my main window and add navigation controllers to some tab bar items. For example, the first tab has a navigation controller with table view: ![alt text][1] The SettingsViewController is associated with its own NIB file, where a table view is defined. Within that xib file, I have a table view and set it to the outlet of SettingsViewController class property myTableView. The problem is that in the main xib file, for the SettingsViewController navigation, there is one outlet myTableView. I am not sure if I have to set this to somewhere? The exception I get is "[UIViewController _loadViewFromNibNamed:bundle:] loaded the "SettingsViewController" nib but the view outlet was not set." [1]:

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• Changing the title of a MFMailComposeViewController

  - by Badescu Alexandru

  Although i know changing MFMailComposeViewController is fround upon, i'm taking a risk. I found some ideas such as [self presentModalViewController:controller animated:YES]; // Existing line [[[[controller viewControllers] lastObject] navigationItem] setTitle:@"SomethingElse"]; and [[[[(MFMailComposeViewController*)vc navigationBar] items] objectAtIndex:0] setTitle:@" SomethingElse"]; but the odd thing is that the title is "SomethingElse" for like 2 seconds and after that it returns to the subject that is set. I've tried other solutions as well but the same output. I am using SHK (ShareKit) to connect to social. Here is the code from showViewController : if ([vc respondsToSelector:@selector(modalPresentationStyle)]) vc.modalPresentationStyle = [SHK modalPresentationStyle]; if ([vc respondsToSelector:@selector(modalTransitionStyle)]) vc.modalTransitionStyle = [SHK modalTransitionStyle]; [topViewController presentModalViewController:vc animated:YES]; [[[[(MFMailComposeViewController*)vc navigationBar] items] objectAtIndex:0] setTitle:@" "]; [(UINavigationController *)vc navigationBar].barStyle = [(UINavigationController *)vc toolbar].barStyle = [SHK barStyle]; self.currentView = vc;

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• iphone: Accessing Code for Elements Created in Interface Builder

  - by user362685

  I am attempting to create a basic tab-bar application using interface builder. I create a new project in Xcode selecting tab bar application. My question is how can I access the code that instantiates and pushes each of the views when the tab bar buttons are pressed? I would imagine that would be done by the tab bar controller, however when I write the class file from interface builder (filewrite class files), it just creates a blank generic TabBarController.h/TabBarController.m without the methods for pushing each of the views associated with the tab bar elements. I ask this because I would like to pass each view controller a reference to the data model when they are instantiated. Any help would be greatly appreciated, thanks.

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• Combined sign in and registration page?

  - by Ryan

  This is somewhat against rails convention but I am trying to have one controller that manages both user session authentication and user registration. I am having troubles figuring out how to go about this. So far I am merging the User Controller and the Sessions Controller and having the 'new' method deliver both a new usersession and a new user instance. With the new routes in rails 3 though, I am having trouble figuring out how to generate forms for these items. Below is the code: user_controller.rb class UserController < ApplicationController def new @user_session = UserSession.new @user = User.new end def create_user @user = User.new(params[:user]) if @user.save flash[:notice] = "Account Successfully Registered" redirect_back_or_default signup_path else render :action => new end end def create_session @user_session = UserSession.new(params[:user_session]) if @user_session.save flash[:notice] = "Login successful!" redirect_back_or_default login_path else render :action => new end end end views/user/new.html.erb <div id="login_section"> <% form_for @user_session do |f| -%> <%= f.label :email_address, "Email Address" %> <%= f.text_field :email %> <%= f.label :password, "Password" %> <%= f.text_field :password %> <%= f.submit "Login", :disable_with => 'Logining...' %> <% end -%> </div> <div id="registration_section"> <% form_for @user do |f| -%> <%= f.label :email_address, "Email Address" %> <%= f.text_field :email %> <%= f.label :password, "Password" %> <%= f.text_field :password %> <%= f.label :password_confirmation, "Password Confirmation" %> <%= f.text_field :password_confirmation %> <%= f.submit "Register", :disable_with => 'Logining...' %> <% end -%> </div> I imagine I will need to use :url = something for those forms, but I am unsure how to specify. Within routes.rb I have yet to specify either Usersor UserSessions as resources (not convinced that this is the best way to do it... but I could be). I would like, however, the registration and login on the same page and have implemented this by doing the following: routes.rb match 'signup' => 'user#new' match 'login' => 'user#new' What's the best way to go about solving this?

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• Annotation based view mapping

  - by Eqbal

  I am trying to get my head around annotation based mappings and I am having some trouble mapping requests directly to jsp. Do all request have to go through a controller? Is it possible to make it just go to a jsp without declaring a RequestMapping for GET? I am using a InternalResourceViewResolver. Below is my app-servlet.xml <context:annotation-config/> <context:component-scan base-package="com.pioneer.b2broe.web" /> <mvc:annotation-driven /> <mvc:view-controller path="/" view-name="home"/> <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver" p:prefix="/WEB-INF/jsp/" p:viewClass="org.springframework.web.servlet.view.JstlView" p:suffix=".jsp" p:order="2"/>

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• Searching in Ruby on Rails - How do I search on each word entered and not the exact string?

  - by bgadoci

  I have built a blog application w/ ruby on rails and I am trying to implement a search feature. The blog application allows for users to tag posts. The tags are created in their own table and belong_to :post. When a tag is created, so is a record in the tag table where the name of the tag is tag_name and associated by post_id. Tags are strings. I am trying to allow a user to search for any word tag_name in any order. Here is what I mean. Lets say a particular post has a tag that is 'ruby code controller'. In my current search feature, that tag will be found if the user searches for 'ruby', 'ruby code', or 'ruby code controller'. It will not be found if the user types in 'ruby controller'. Essentially what I am saying is that I would like each word entered in the search to be searched for, not necessarily the 'string' that is entered into the search. I have been experimenting with providing multiple textfields to allow the user to type in multiple words, and also have been playing around with the code below, but can't seem to accomplish the above. I am new to ruby and rails so sorry if this is an obvious question and prior to installing a gem or plugin I thought I would check to see if there was a simple fix. Here is my code: View: /views/tags/index.html.erb <% form_tag tags_path, :method => 'get' do %> <p> <%= text_field_tag :search, params[:search], :class => "textfield-search" %> <%= submit_tag "Search", :name => nil, :class => "search-button" %> </p> <% end %> TagsController def index @tags = Tag.search(params[:search]).paginate :page => params[:page], :per_page => 5 @tagsearch = Tag.search(params[:search]) @tag_counts = Tag.count(:group => :tag_name, :order => 'count_all DESC', :limit => 100) respond_to do |format| format.html # index.html.erb format.xml { render :xml => @tags } end end Tag Model class Tag < ActiveRecord::Base belongs_to :post validates_length_of :tag_name, :maximum=>42 validates_presence_of :tag_name def self.search(search) if search find(:all, :order => "created_at DESC", :conditions => ['tag_name LIKE ?', "%#{search}%"]) else find(:all, :order => "created_at DESC") end end end

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• Does to_json require parameters? what about within rails?

  - by Harry Wood

  Does to_json require parameters? what about within rails? I started getting the error "wrong number of arguments (0 for 1)" when doing myhash.to_json Unfortunately I'm not sure when this error started happening, but I guess it relates to some versions of either rails or the json gem. I suppose my code (in a rails controller) is using the ActiveSupport::JSON version of to_json, rather than the to_josn method supported by the json gem. ActiveSupport::JSON vs JSON In environment.rb I have RAILS_GEM_VERSION = '2.3.2' and also config.gem "json", :version=> '1.1.7' It's just a simple hash structure containing primitives which I want to convert in my controller, and it was working, but now I can't seem to run to_json without passing parameters.

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• Cannot resolve view when view is in subdirectory

  - by devzero

  We have a MVC 2.0 / c# 4.0 application that we develop visual studio. We have a part of the site (admin) that we have put in it's own sub directory and with its own routing rules: routes.Add("DomainRoute", new DomainRoute( ConfigurationManager.AppSettings["adminDomain"], // Domain with parameters "{controller}/{action}/{id}", // URL with parameters new { controller = "AdminPage", action = "Admin", id = "", isAdmin = true } We have all the views for the admin site inside an admin sub folder so that you get paths like: \views\admin\auth\login.aspx In the \controllers\admin\authController.aspx file I have a function called login: public ActionResult Login() { return View(); } This works just as it should, ie if i go admin.localhost\auth\login I go to the login page. But if I do a right click in visual studio and "go to view" i get an error "unable to go to matching view". Is there anyway to solve this?

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• spring json writes more json then i want

  - by mkoryak

  I am using the json spring view in order to return a simple JSON object from my controller. The problem is that its returning more data then i want. it is returning the validation errors and things inside of my model when all i am doing is this in the controller: Map model = new HashMap() model.put("success", "true"); return new ModelAndView("jsonView", model); If you look at the bottom of this page in the docs it looks like i am getting back data that POST would return. i am not doing a post, i am doing a GET by going directly to the URL with params. How do i get this lib to return just the data in my model?

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• MVC without ORM is not real MVC?

  - by ajsie

  at the moment im integrating ORM (doctrine) into a MVC framework (codeigniter). then it hit me that this was the obvious way of setting up a MVC: the controller calls the models that are representing database tables. look at this picture: MVC + ORM then i wondered, how can a MVC without ORM be real MVC? cause then the models are not real objects, rather aggregations of different functions that perform CRUD, then returning the result to the controller. and there is no need for a state (object properties) i guess so the functions would be all static? correct me if im wrong on this one. i guess a lot of people are using models without ORM. please share your thoughts. how do your models look like?

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• 404 with spring 3

  - by markjason72

  hi I am going through my first lessons with spring 3.I created a dynamic web app in eclipse with the following structure. spring3mvc \src\my.spring.HelloWorldController.java \WebContent | |-----WEB-INF\jsp\hello.jsp |-----index.jsp |-----web.xml |-----WEB-INF\spring-servlet.xml |-----WEB-INF\lib\...*.jar files I created the spring-servlet.xml as below <context:component-scan base-package="my.spring" /> <bean id="viewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView" /> <property name="prefix" value="/WEB-INF/jsp/" /> <property name="suffix" value=".jsp" /> </bean> and coded the controller package my.spring; import org.springframework.stereotype.Controller; import org.springframework.web.bind.annotation.RequestMapping; import org.springframework.web.servlet.ModelAndView; @Controller public class HelloWorldController { @RequestMapping("/hello") public ModelAndView helloWorld() { String message = "Hello World, Spring 3.0!"; return new ModelAndView("hello", "message", message); } } index.jsp has a link to hello view <html> <body> <a href="hello.html">Say Hello</a> </body> </html> finally in hello.jsp I have put <html> <body> ${message} </body> </html> My web.xml has <display-name>Spring3MVC</display-name> <welcome-file-list> <welcome-file>index.jsp</welcome-file> </welcome-file-list> <servlet> <servlet-name>spring</servlet-name> <servlet-class> org.springframework.web.servlet.DispatcherServlet </servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>spring</servlet-name> <url-pattern>*.html</url-pattern> </servlet-mapping> When I run the app on Tomcat6 server( thru eclipse),I can see the index page at http://localhost:8080/Spring3MVC/ .It displays the link to hello page.When I click on it(http://localhost:8080/Spring3MVC/hello.html),I get a 404 error. message /Spring3MVC/hello.html description The requested resource (/Spring3MVC/hello.html) is not available. Any idea how I can solve this? thanks mark.

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• Eliminating static properties - What patterns do I have at my disposal?

  - by Jamie Dixon

  I currently have a type that I inject into my controllers that's used for getting and setting session data. I use this so that I can obtain relevant session information as _sessionData.Username rather than using Session["username"]. I'd like to use this session information across all of my views and would previously have done this by making the SessionData members static instead of injecting the SessionData class into my controller. I want to avoid using static members as well as having to pass the object to the view in each controller. What patterns best suit this type of scenario? What do you do to solve this same problem?

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