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  • Converting a CGRect of a object in a subview in UITableViewCell in UITable to CGRect with respect to

    - by user362956
    Hey, I want to converte a CGRect "aRect" of a object in a subview in UITableViewCell in UITable to CGRect with respect to self.view. The problem is that aRect is with respect to the subview in the table cell. But i want to make it so that it is with respect to self.view What i tried is this rect = [self.view convertRect:aRect.frame toView:cellView]; but it doesn't work. So how to convert it?

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  • How do I put logic in a View a scope or method in a Model?

    - by Angela
    I have the following in the view: <% unless contact_email.statuses.empty?%> (<%= contact_email.statuses.find(:last).status%>) <% end %> contact_email is an instance of a specific model. Could I do something like this? class ContactEmail < ActiveRecord::Base attr_accessible :contact_id, :email_id, :status, :subject, :body, :date_created, :date_sent def status unless contact_email.statuses.empty? contact_email.statuses.find(:last).status end end end is there a better way to do this? is there a way to use the || operator for a default if empty? Basically, I would like to be able to do the following in the View: <%= contact_email.status = IF there is a value, then display it, if not, show nothing.

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  • Calling a method from another view in objective-c. (iphone sdk).

    - by MarcZero
    Hello. I am currently creating a multi-view game on the iPhone platform. I have my main view start to play some background music upon loading. I then go to another view and start the game. I am trying to get the background music from the original view to stop once I start the game. I am having trouble getting the stop playing music message to my original view. Here is the relevant info: The main view where the sound is played from is just a subView of the programViewController class called *viewController. The heading is in the programAppDelegate class. The sound is done using the AVAudioPlayer class and plays fine when the program starts up and when I navigate to other subviews that are added on by going through the menu system. In the view that I want to start the game, I attempt to call the instance of the class to turn of the player but anytime I use this format of code: [viewController #######]; It gives a build error of "viewController undeclared" no matter what I put after the "viewController" in the message.I have attempted to import the programAppDelegate.h file but it still gives the same error. I realize this might be a simple misunderstanding of the objective-c language but I cannot find any info on this issue. I am a recent convert from Java so I am trying to wrap my head around everything. Thank you for your time!

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  • Class Method not working in objective c

    - by byteSlayer
    In my code I have a class called 'ProfileShareViewController', In which I have imported another class I have created called 'OwnProfileData', And I have also created an Instance of that class (class = OwnProfileData) as a property Of 'ProfileShareViewController' and synthesized it (instance called 'OwnProfile'). In another class I have called 'EditProfileViewController', I have imported the 'ProfileShareViewController', and now I am trying to change a property of the OwnProfile object from the ProfileShareViewController within the EditProfileViewController class. For some reason that doesn't work. I have Tried typing: [[ProfileShareViewController ownProfile] setName:@"Ido"]; (The property I am trying to set is Name, and as it is synthesized in OwnProfileData, I am using 'setName'). This doesn't work and I get the warning: "No known class method for selector 'ownMethod'. Any Idea as for why that might happen and how I can fix this? Thanks for your comments! Any support is highly appreciated!

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  • SQLite user_version() expression

    - by ralf.w.
    how can I get user_version into an expression (for SELECT or WHERE) ? I would also appreciate any clue to how to save ANY global variable in SQLite. Does anyone know of such an extension (dll) ? BTW: I know that PRAGMA user_version; gives me the right answer, but I cannot use that inside a WHERE-clause !

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  • In Python, is there a way to call a method on every item of an iterable? [closed]

    - by Thane Brimhall
    Possible Duplicate: Is there a map without result in python? I often come to a situation in my programs when I want to quickly/efficiently call an in-place method on each of the items contained by an iterable. (Quickly meaning the overhead of a for loop is unacceptable). A good example would be a list of sprites when I want to call draw() on each of the Sprite objects. I know I can do something like this: [sprite.draw() for sprite in sprite_list] But I feel like the list comprehension is misused since I'm not using the returned list. The same goes for the map function. Stone me for premature optimization, but I also don't want the overhead of the return value. What I want to know is if there's a method in Python that lets me do what I just explained, perhaps like the hypothetical function I suggest below: do_all(sprite_list, draw)

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  • update query not working in array

    - by Suresh PHP Begginer
    here my code: i want to update the field by array. i just fetch the data's from table then i want to update the the field for same table // select query to get the value for($j=0;$j<count($capacity);$j++) { $capaci=$capacity[$j]; // select query to get the value $sql2=mysql_query("SELECT recieved-allocate*plate_quantity as ans from total_values where capacity='$capaci'"); while($fetch=mysql_fetch_array($sql2)) { $recieves=$fetch['ans']; $sql3="update total_values set recieved='$recieves' where capacity='$capaci' and month='$mon'"; mysql_query($sql3); } }

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  • Same object in different nib files?

    - by Michael
    View1 object, which is UIViewController subclass is the same object as File's Owner of View1 nib. So I should manually set the class in both places, one in MainWindow and another in View1 nib files? This sound artificial to me... Either I'm doing something wrong or there has to be better way.

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  • returning values from function or method multiple times by only calling the class once

    - by Sokhrat Sikar
    I have a members.php file that shows my websites members. I echo members name by using foreach method. A method of Members class returns an array, then I use foreach loop in the members.php file to echo the members. I am trying to aovid writing php code in my members.php file. Is there a way to avoid using foreach inside members.php file? For example, is it possible to return value from a method couple of times? (by only calling the object once). Just like how we normally call the functions? This question doesn't make sense, but I am just trying to see if there is a away around this issue?

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  • Can I do this in only one query ?

    - by Paté
    Merry christmas everyone, I Know my way around SQL but I'm having a hard time figuring this one out. First here are my tables (examples) User id name friend from //userid to //userid If user 1 is friend with user 10 then you a row with 1,10. User 1 cannot be friend with user 10 if user 10 is not friend with user 1 so you have 1,10 10,1 It may look weird but I need those two rows per relations. Now I'm trying to make a query to select the users that have the most mutual friend with a given user. For example User 1 is friend with user 10,9 and 7 and user 8 is friend with 10,9 and 7 too ,I want to suggest user 1 to invite him (like facebook). I want to get like the 10 first people with the most mutual friend. The output would be like User,NumOfMutualFriends I dont know if that can be done in a single query ? Thanks in advance for any help.

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  • IBOutlets are always nil

    - by Jonas
    Hi, In IB I have subclassed the File Owner and the subclass loads my .nib. The subclass itself doesn't need access to the IBOutlets so they're instance variables in another class, which I added as a subclass of NSObject in the .nib. Then I connected the interface elements to that object. But somehow, in the class that "owns" the IBOutlets, they show up as nil. What am I doing wrong here?

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  • compiling c code in windows xp

    - by pablo
    i have c code that was compiled on windows NT with microsoft visual studio 6.0. I am migrating this code to a new machine using windows xp. What ide is suitable for this? I dont think ms visual 6.0 has been designed for xp...can i just use visual studio c++ to compile c code and keep the same functionality?

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  • undefined method `output_data' for #<EventManager:0x007fa4220320c8> (NoMethodError)

    - by Roger Camps
    I keep getting this error: event_manager.rb:83:in': undefined method output_data' for #<EventManager:0x007fc5018320c0> (NoMethodError) I am following the exercise on this website: Here is my code (My error comes towards the end with DEF OUTPUT_DATA ...): # Dependencies require "csv" # Class Definition class EventManager INVALID_PHONE_NUMBER = "0000000000" INVALID_ZIPCODE = "00000" def initialize puts "EventManager Initialized." filename = "event_attendees.csv" @file = CSV.open(filename, {:headers => true, :header_converters => :symbol}) end def print_names @file.each do |line| puts line.inspect puts line[2] + " " + line[3] end end #printing home phone number method def print_numbers @file.each do |line| number = clean_number(line[:homephone]) puts number end end #cleaning numbers method def clean_number(number) cleaner= number.delete('.' + ')' + '(' + '-') if cleaner.length == 10 # Do Nothing elsif cleaner.length == 11 if cleaner.start_with?("1") cleaner = cleaner[1..-1] else cleaner = INVALID_PHONE_NUMBER end else cleaner = INVALID_PHONE_NUMBER end return cleaner end def clean_zipcode(original) if original.nil? zipcode = INVALID_ZIPCODE elsif original.length < 5 while original.length < 5 original = original.insert(0, "0") end else return original end return zipcode end def print_zipcodes @file.each do |line| zipcode = clean_zipcode(line[:zipcode]) puts zipcode end def output_data output = CSV.open("event_attendees_clean.csv", "w") @file.each do |line| output << line end end end end # Script manager = EventManager.new #manager.print_numbers #manager.print_zipcodes manager.output_data I've tried several things, checked all through the internet and I just can't figure it out myself. I will really appreciate any help. Thank you in advance!

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  • If statement in MySQL query with PHP

    - by user1104854
    Is it possible to use an if statement in a MySQL query in a similar what I'm showing? I want to grab some information for upcoming events(not ones with previous dates). ini_set('date.timezone', 'America/New_York'); $timestamp = date('m/d/Y'); $sql = "select eventID,eventTitle,eventDate from events where eventLocationID = $locationID ORDER BY eventDate DESC IF(eventDate > $timestamp) "; I really want to avoid doing post-query if statements that will only print if it's after today's date because I run it through a pagination function, and I'd really prefer to avoid tinkering with that.

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  • SQL query for fetching friend list

    - by Bhavyanshu
    I need help with SQL query. I have two tables. One is users and other one is userfriends users table: aid email firstname 1 [email protected] example 2 [email protected] example2 3 [email protected] example3 4 [email protected] example4 userfriends tables: reqid email friendemail status 1 [email protected] [email protected] 1 (example1 is frnds with example2) 2 [email protected] [email protected] 2 (example2 request pending) 3 [email protected] [email protected] 1 (example1 is frnds with example3) 4 [email protected] [email protected] 1 (example1 is frnds with example4) So when status is 2 the add request is pending and at status 1 they are friends. What i want is that i want to retrieve the complete friendlist for user example1. I want to pull out names from users table for corresponding output from previous query to display as friendlist.

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  • Can a tab bar controller added to a uitableview?

    - by Sheehan Alam
    I have a View that contains a UITableView and a UITabBarController. I have set my IBOutlets, but the UITabbarController does not appear. Do I need to do anything else to allow it to appear? Note: I don't want the tab-bar to be displayed throughout the entire application. Only on one specific view.

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  • Sql Server query performance

    - by Macros
    I have a stored procedure on a busy database which constantly come out top in the list of expensive queries (by some way). The query is very simple, it takes a single parameter (@ID, int) which is the primary key of the table, and selects the record that matches that ID. The primary key is an identity field with a clustered index, so I am stumped as to how to optimise this any further? The query is as follows CREATE PROCEDURE [dbo].[P_Call_Get] @ID int = null AS select ID, AppID, AgentID, AgentLogin, Ext, VDN, VDNName, Skill, SkillName, CallFrom, TelNoFrom, ParentCallID, CallStart, ACWStart, CallEnd, Outcome, StageID, TxTo, TxSuccess, ServiceID, DiallerID, CRC, TSCallID, CallDirection, [Manual], CallBackAgent, CallBackDateTime, Notes from P_Call where (ID = @ID or @ID is null) Not sure the best way to post the execution plan - all it shows is that 100% of the operation is taken up by the clustered index scan

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  • Query string problem if we use header

    - by avani-nature
    Hai frnds i am new to php actually i am facing following problems in coding please can anyone give the solution? Actually i am having one audio player and i am displaying some word dcoument if i click word document corresponding audio file should play actually when i click doc file it should pop ip with save as and open with for that i am using some header code also i am passing query string in the browser query string is not working if i use header can anyone give me a solution for it below is my code i am attaching <?php $f_name = $_POST["fn"]; $id = $_POST["id1"]; echo $id; //echo "../public_html/sites/default/files/ourfiles/$f_name"; $res2=db_query("select * from mt_files where id='".$id."' "); $row2=db_fetch_array($res2); $job_audio=$row2["audio_name"]; //echo $job_audio; //$job_audi=explode("/",$job_audio); //$job_audio=$job_audi[8]; $job_audio= "C:/xampp/htdocs/med/sites/default/files/audio/$job_audio"; //$job_audio= "C:/Documents and Settings/swuser/My Documents/$job_audio"; //echo $job_audio; echo "<object data='$job_audio' type='application/x-mplayer2' width='150' height='45'> <param name='src' value='$job_audio'> <param name='autoplay' value='true'> <param name='autoStart' value='1'> </object> "; $file = "../mts/sites/default/files/docs/$f_name"; if (file_exists($file)) { header('Content-Description: File Transfer'); header('Content-Type: application/octet-stream'); header('Content-Disposition: attachment; filename='.basename($file)); header('Content-Transfer-Encoding: binary'); header('Expires: 0'); header('Cache-Control: must-revalidate, post-check=0, pre-check=0'); header('Pragma: public'); header('Content-Length: ' . filesize($file)); ob_clean(); flush(); readfile($file); exit; } //The download table query goes here put the $f_name in insert into with the //time varible ?>

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  • TypeError: init_animals() takes 1 positional arguments but 2 were given

    - by libra
    I know this title look familiar to some old questions, but i've looked at every single one of them, none of them solves. And here is my codes: class Island (object):E,W,R,P def __init__(self, x, y): self.init_animals(y) def init_animals(y): pass isle = Island(x,y) However, i got the following error: Traceback (most recent call last): File "<stdin>", line 1, in <module> File "<stdin>", line 3, in __init__ TypeError: init_animals() takes 1 positional arguments but 2 were given Please tell me if i got any mistakes, im so confused by this. Best regards

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  • Filter Phrase Query

    - by alsuelo
    I try to filter a phrase to make a search in my website i've this query, this code working with one word but when i type wit more than one isn't working becuase the print is without spaces. $phrase = $this->getState($this->context.".filter_phrase"); printf("Original string: %s\n", $phrase); if(!empty($phrase)) { $escaped = $db->escape($phrase, true); printf("Escaped string: %s\n", $escaped); $quoted = $db->quote("%" . $escaped . "%" , false); $query->where ('a.title LIKE ' .$quoted); } Example i type king and the output is king , when i type the king the output is theking, i want to know if exist any way to conserve the blank spaces.

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  • 2 table SQL Query weird results

    - by javArc
    Ok this is driving me nuts, I need to write an SQL query that will grab product information from 2 tables. The first table 'products' contains the productId, productname, quantityperunit and unitprice. Now I can search by productname and categoryname individually, but when I try to combine the 2 I get crazy results, Here's the query: "SELECT DISTINCT productId, productname, quantityperunit, unitprice FROM products pr, categories ca WHERE pr.categoryID = ca.categoryID AND ProductName LIKE '%" + searchTerm + "%' OR CategoryName LIKE '%" + searchTerm + "%' excuse the java style in there, here it is formatted better: SELECT DISTINCT productId, productname, quantityperunit, unitprice FROM products pr, categories ca WHERE pr.categoryID = ca.categoryID AND ProductName LIKE 'Tofu' OR CategoryName LIKE 'Tofu' any help would be appreciated.

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  • is there an equivalent to a "Focus Listener" in Objective-C or iPhone SDK? (Coming from Java)

    - by MarcZero
    Hello. I am a student programmer who has taken up Objective-C on my free time as my college doesn't teach it. We have only used Java and basic C so far. I am in the middle of making a program for the iPod and was wondering if there was any type of way to call a method in a class similar to the way a Focus Listener does in Java? I have a view that I would like to call a refresh method (to update the newly inputted titles of buttons from another view) when the view is put at the top and visible again. Is this too easy or is there a more methodical way of doing that? I have tried to just call the method from the other view class but it does not seem to work (says the other class is either undefined or may not accept the method call and crashes on execution). Any insight would be appreciated. Thank you for your time.

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