Managing a log stream in C++ in a cout-like notation
- by Andry
Hello!
I have a class in c++ in order to write log files for an application of mine. I have already built the class and it works, it is something like this:
class Logger {
std::string _filename;
public:
void print(std::string tobeprinted);
}
Well, it is intuitive that, in order to print a line in the log file, for an object of Logger, it is simply necessary to do the following:
Logger mylogger("myfile.log");
mylogger.print(std::string("This is a log line"));
Well. Using a method approach is not the same as using a much better pattern like << is.
I would like to do the following:
Logger mylogger("myfile.log");
mylogger << "This is a log line";
That's all. I suppose I must overload the << operator... But overloading using this signature (the classic one):
ostream& operator<<(ostream& output, const MyObj& o);
But I do not have a ostream...
So, should I do as follows?
Logger& operator<<(Logger& output, const std::string& o);
Is this the right way?
Thanks
