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  • Notification framework for java

    - by rmarimon
    I'm in the process of developing a web application (java + jsp) that can send notifications to users. The user can subscribe to multiple events generated by the application and can choose to receive the messages associated with those events via multiple channels (email, sms, growl?, messenger); perhaps different messages through different channels; perhaps a daily message digest. Everything must be configurable by the user. Is there some framework that deals with this?

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  • Set the JAXB context factory initialization class to be used

    - by user1902288
    I have updated our projects (Java EE based running on Websphere 8.5) to use a new release of a company internal framework (and Ejb 3.x deployment descriptors rather than the 2.x ones). Since then my integration Tests fail with the following exception: [java.lang.ClassNotFoundException: com.ibm.xml.xlxp2.jaxb.JAXBContextFactory] I can build the application with the previous framework release and everything works fine. While debugging i noticed that within the ContextFinder (javax.xml.bind) there are two different behaviours: Previous Version (Everything works just fine): None of the different places brings up a factory class so the default factory class gets loaded which is com.sun.xml.internal.bind.v2.ContextFactory (defined as String constant within the class). Upgraded Version (ClassNotFound): There is a resource "META-INF/services/javax.xml.bind.JAXBContext" beeing loaded successfully and the first line read makes the ContextFinder attempt to load "com.ibm.xml.xlxp2.jaxb.JAXBContextFactory" which causes the error. I now have two questions: What sort is that resource? Because inside our EAR there is two WARs and none of those two contains a folder services in its META-INF directory. Where could that value be from otherwise? Because a filediff showed me no new or changed properties files. No need to say i am going to read all about the JAXB configuration possibilities but if you have first insights on what could have gone wrong or help me out with that resource (is it a real file i have to look for?) id appreciate a lot. Many Thanks! EDIT (according to comments Input/Questions): Out of curiosity, does your framework include JAXB JARs? Did the old version of your framework include jaxb.properties? Indeed (i am a bit surprised) the framework has a customized eclipselink-2.4.1-.jar inside the EAR that includes both a JAXB implementation and a jaxb.properties file that shows the following entry in both versions (the one that finds the factory as well as in the one that throws the exception): javax.xml.bind.context.factory=org.eclipse.persistence.jaxb.JAXBContextFactory I think this is has nothing to do with the current issue since the jar stayed exactly the same in both EARs (the one that runs/ the one with the expection) It's also not clear to me why the old version of the framework was ever selecting the com.sun implementation There is a class javax.xml.bind.ContextFinder which is responsible for initializing the JAXBContextFactory. This class searches various placess for the existance of a jaxb.properties file or a "javax.xml.bind.JAXBContext" resource. If ALL of those places dont show up which Context Factory to use there is a deault factory loaded which is hardcoded in the class itself: private static final String PLATFORM_DEFAULT_FACTORY_CLASS = "com.sun.xml.internal.bind.v2.ContextFactory"; Now back to my problem: Building with the previous version of the framework (and EJB 2.x deployment descriptors) everything works fine). While debugging i can see that there is no configuration found and thatfore above mentioned default factory is loaded. Building with the new version of the framework (and EJB 3.x deployment descriptors so i can deploy) ONLY A TESTCASE fails but the rest of the functionality works (like i can send requests to our webservice and they dont trigger any errors). While debugging i can see that there is a configuration found. This resource is named "META-INF/services/javax.xml.bind.JAXBContext". Here are the most important lines of how this resource leads to the attempt to load 'com.ibm.xml.xlxp2.jaxb.JAXBContextFactory' which then throws the ClassNotFoundException. This is simplified source of the mentioned javax.xml.bind.ContextFinder class: URL resourceURL = ClassLoader.getSystemResource("META-INF/services/javax.xml.bind.JAXBContext"); BufferedReader r = new BufferedReader(new InputStreamReader(resourceURL.openStream(), "UTF-8")); String factoryClassName = r.readLine().trim(); The field factoryClassName now has the value 'com.ibm.xml.xlxp2.jaxb.JAXBContextFactory' (The day i understand how to format source code on stackoverflow will be my biggest step ahead.... sorry for the formatting after 20 mins it still looks the same :() Because this has become a super lager question i will also add a bounty :)

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  • VBA WinHTTPRequest and submitting forms

    - by Hazerider
    Hi. I spent all day yesterday trying to figure out how to submit a form using WinHTTPRequest. I can do it pretty easily with an InternetExplorer object, but the problem is that I need to save a PDF file that gets returned, and I am not sure how to do this with the IE object. Here is the relevant HTML code snippet: <div class="loginHome-left"> <fieldset> <h3>Log in Using</h3> <form> <label for="standardLogin" accesskey="s"> <input name="useLogin" id="standardLogin" value="standard" type="radio" checked="true">Standard Login</label> &nbsp; <label for="rsaSecurID" accesskey="r"> <input name="useLogin" value="rsaSecur" type="radio" id="rsaSecurID" onclick="redirectLogin('ct_logon_securid');return false;">RSA SecurID</label> &nbsp; <label for="employeeNTXP" accesskey="e"> <input name="useLogin" id="employeeNTXP" value="employee" type="radio" onclick="redirectLogin('ct_logon_external_nt');return false; "> Employee Windows Login<br></label> </form> <br> <div class="error">Error: ...</div><br> <form onSubmit="if(validate(this)) {formSubmit();} return false;" name="passwdForm" method="post" action="/UAB/ct_logon"> <input value="custom" name="pageId" type="hidden"> <input value="custom" name="auth_mode" type="hidden"> <input value="/UAB/ct_logon" name="ct_orig_uri" type="hidden"> <INPUT VALUE="" NAME="orig_url" TYPE="hidden"> <input value="" name="lpSp" type="hidden"> <label for="user"> <strong>Username</strong> </label> <input autocomplete="off" name="user" type="text" value="" class="txtFld" onkeypress="return handleEnter(this, event);"> <br> <label for="EnterPassword"> <strong>Password</strong>&nbsp;&nbsp;(<a tabindex="-1" href="/UAB/BCResetWithSecrets">Forgot Your Password?</a>) </label> <input autocomplete="off" name="password" type="password" class="txtFld" onkeypress="return handleEnter(this, event);"> <INPUT id="rememberLogin" name="lpCookie" type="checkbox"> <label for="rememberLogin">Remember My Login Information</label><br> </form> <div class="right"> <br> <input type="image" src="/BC_S/images/bclogin/btn_login.gif" name="" value="Submit" onClick="if(validate(document.forms['passwdForm'])){formSubmit();}return false;"> </div> <div class="clearfix"></div> </fieldset> </div> In order to log in through InternetExplorer, I do the following: Sub TestLogin() Dim ie As InternetExplorer, doc As HTMLDocument, form As HTMLFormElement, inp As Variant Set ie = New InternetExplorer ie.Visible = True ie.navigate "https://URL of the login page" Do Until ie.readyState = READYSTATE_COMPLETE Loop Set doc = ie.document For Each form In doc.forms If InStr(form.innerText, "Password") <> 0 Then form.elements("user").Value = "my_name" form.elements("password").Value = "my_password" Exit For Else End If Next 'This is the unnamed input with an image that is used to submit the form' doc.all(78).Click ie.navigate "https://url of the PDF" Do Until ie.readyState = READYSTATE_COMPLETE Loop Dim filename As String, filenum As Integer filename = "somefile.pdf" filenum = FreeFile Open filename For Binary Access Write As #filenum Write #filenum, doc.DocumentElement.innerText Close #filenum ie.Quit Debug.Print Set ie = Nothing End Sub What I really would like to do is something along the lines of the following: Sub TestLogin3() Dim whr As New WinHttpRequest, postData As String whr.Open "POST", "https://live.barcap.com/UAB/ct_logon", False whr.setRequestHeader "User-Agent", "Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.0)" whr.setRequestHeader "Connection", "Keep-Alive" whr.Send whr.WaitForResponse postData = "user=paschom1&password=change01" 'Or the following?' postData = "user=paschom1&password=change01&orig_url=&pageId=custom&auth_mode=custom&ct_orig_uri=/BC/dispatcher&lpSp=&lpCookie=off" whr.Send postData whr.WaitForResponse Debug.Print whr.responseText End Sub It just refuses to work though. Not sure if I need to use more setRequestHeader with Content-Form or something similar, and if I do, not sure what exactly I am supposed to pass it. If anyone has any advice regarding this, it would be hugely appreciated. I could probably use a perl module to do it, but I would rather keep it all in VBA if possible. Thanks, Marc.

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  • java.lang.IllegalArgumentException: Method must not be null

    - by abc
    Nested in org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'org.springframework.beans.factory.config.PropertyPlaceholderConfigurer#0': Initialization of bean failed; nested exception is java.lang.IllegalArgumentException: Method must not be null:java.lang.IllegalArgumentException: Method must not be null i am getting this deployment error while deploying my application. java -version java version "1.6.0_20" Java(TM) SE Runtime Environment (build 1.6.0_20-b02) Java HotSpot(TM) Server VM (build 16.3-b01, mixed mode) while the same build gets deployed successfully in the same server jetty 6.1.3 with following conf. java version "1.6.0_17" spring version used is 2.5.6.SEC01 how to overcome, googling didnt work? 2010-05-13 15:53:20.903::WARN: Failed startup of context org.mortbay.jetty.webapp.WebAppContext@9ad840{/caw,jar:file:/home/jigar/jetty-6.1.3/webapps/caw.war!/} org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'org.springframework.beans.factory.config.PropertyPlaceholderConfigurer#0': Initialization of bean failed; nested exception is java.lang.IllegalArgumentException: Method must not be null at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:480) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory$1.run(AbstractAutowireCapableBeanFactory.java:409) at java.security.AccessController.doPrivileged(Native Method) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:380) at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:264) at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:222) at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:261) at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:185) at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:164) at org.springframework.context.support.AbstractApplicationContext.invokeBeanFactoryPostProcessors(AbstractApplicationContext.java:515) at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:362) at org.springframework.web.context.ContextLoader.createWebApplicationContext(ContextLoader.java:255) at org.springframework.web.context.ContextLoader.initWebApplicationContext(ContextLoader.java:199) at org.springframework.web.context.ContextLoaderListener.contextInitialized(ContextLoaderListener.java:45) at org.mortbay.jetty.handler.ContextHandler.startContext(ContextHandler.java:530) at org.mortbay.jetty.servlet.Context.startContext(Context.java:135) at org.mortbay.jetty.webapp.WebAppContext.startContext(WebAppContext.java:1218) at org.mortbay.jetty.handler.ContextHandler.doStart(ContextHandler.java:500) at org.mortbay.jetty.webapp.WebAppContext.doStart(WebAppContext.java:448) at org.mortbay.component.AbstractLifeCycle.start(AbstractLifeCycle.java:40) at org.mortbay.jetty.handler.HandlerCollection.doStart(HandlerCollection.java:147) at org.mortbay.jetty.handler.ContextHandlerCollection.doStart(ContextHandlerCollection.java:161) at org.mortbay.component.AbstractLifeCycle.start(AbstractLifeCycle.java:40) at org.mortbay.jetty.handler.HandlerCollection.doStart(HandlerCollection.java:147) at org.mortbay.component.AbstractLifeCycle.start(AbstractLifeCycle.java:40) at org.mortbay.jetty.handler.HandlerWrapper.doStart(HandlerWrapper.java:117) at org.mortbay.jetty.Server.doStart(Server.java:210) at org.mortbay.component.AbstractLifeCycle.start(AbstractLifeCycle.java:40) at org.mortbay.xml.XmlConfiguration.main(XmlConfiguration.java:929) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) at org.mortbay.start.Main.invokeMain(Main.java:183) at org.mortbay.start.Main.start(Main.java:497) at org.mortbay.start.Main.main(Main.java:115) Caused by: java.lang.IllegalArgumentException: Method must not be null at org.springframework.util.Assert.notNull(Assert.java:112) at org.springframework.core.BridgeMethodResolver.findBridgedMethod(BridgeMethodResolver.java:63) at org.springframework.beans.GenericTypeAwarePropertyDescriptor.<init>(GenericTypeAwarePropertyDescriptor.java:58) at org.springframework.beans.CachedIntrospectionResults.<init>(CachedIntrospectionResults.java:250) at org.springframework.beans.CachedIntrospectionResults.forClass(CachedIntrospectionResults.java:144) at org.springframework.beans.BeanWrapperImpl.getCachedIntrospectionResults(BeanWrapperImpl.java:252) at org.springframework.beans.BeanWrapperImpl.getPropertyDescriptorInternal(BeanWrapperImpl.java:282) at org.springframework.beans.BeanWrapperImpl.isWritableProperty(BeanWrapperImpl.java:333) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.applyPropertyValues(AbstractAutowireCapableBeanFactory.java:1247) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.populateBean(AbstractAutowireCapableBeanFactory.java:1010) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:472) ... 35 more 2010-05-13 15:53:20.906::WARN: Nested in org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'org.springframework.beans.factory.config.PropertyPlaceholderConfigurer#0': Initialization of bean failed; nested exception is java.lang.IllegalArgumentException: Method must not be null: java.lang.IllegalArgumentException: Method must not be null at org.springframework.util.Assert.notNull(Assert.java:112) at org.springframework.core.BridgeMethodResolver.findBridgedMethod(BridgeMethodResolver.java:63) at org.springframework.beans.GenericTypeAwarePropertyDescriptor.<init>(GenericTypeAwarePropertyDescriptor.java:58) at org.springframework.beans.CachedIntrospectionResults.<init>(CachedIntrospectionResults.java:250) at org.springframework.beans.CachedIntrospectionResults.forClass(CachedIntrospectionResults.java:144) at org.springframework.beans.BeanWrapperImpl.getCachedIntrospectionResults(BeanWrapperImpl.java:252) at org.springframework.beans.BeanWrapperImpl.getPropertyDescriptorInternal(BeanWrapperImpl.java:282) at org.springframework.beans.BeanWrapperImpl.isWritableProperty(BeanWrapperImpl.java:333) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.applyPropertyValues(AbstractAutowireCapableBeanFactory.java:1247) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.populateBean(AbstractAutowireCapableBeanFactory.java:1010) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:472) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory$1.run(AbstractAutowireCapableBeanFactory.java:409) at java.security.AccessController.doPrivileged(Native Method) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:380) at org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:264) at org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:222) at org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:261) at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:185) at org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:164) at org.springframework.context.support.AbstractApplicationContext.invokeBeanFactoryPostProcessors(AbstractApplicationContext.java:515) at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:362) at org.springframework.web.context.ContextLoader.createWebApplicationContext(ContextLoader.java:255) at org.springframework.web.context.ContextLoader.initWebApplicationContext(ContextLoader.java:199) at org.springframework.web.context.ContextLoaderListener.contextInitialized(ContextLoaderListener.java:45) at org.mortbay.jetty.handler.ContextHandler.startContext(ContextHandler.java:530) at org.mortbay.jetty.servlet.Context.startContext(Context.java:135) at org.mortbay.jetty.webapp.WebAppContext.startContext(WebAppContext.java:1218) at org.mortbay.jetty.handler.ContextHandler.doStart(ContextHandler.java:500) at org.mortbay.jetty.webapp.WebAppContext.doStart(WebAppContext.java:448) at org.mortbay.component.AbstractLifeCycle.start(AbstractLifeCycle.java:40) at org.mortbay.jetty.handler.HandlerCollection.doStart(HandlerCollection.java:147) at org.mortbay.jetty.handler.ContextHandlerCollection.doStart(ContextHandlerCollection.java:161) at org.mortbay.component.AbstractLifeCycle.start(AbstractLifeCycle.java:40) at org.mortbay.jetty.handler.HandlerCollection.doStart(HandlerCollection.java:147) at org.mortbay.component.AbstractLifeCycle.start(AbstractLifeCycle.java:40) at org.mortbay.jetty.handler.HandlerWrapper.doStart(HandlerWrapper.java:117) at org.mortbay.jetty.Server.doStart(Server.java:210) at org.mortbay.component.AbstractLifeCycle.start(AbstractLifeCycle.java:40) at org.mortbay.xml.XmlConfiguration.main(XmlConfiguration.java:929) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) at org.mortbay.start.Main.invokeMain(Main.java:183) at org.mortbay.start.Main.start(Main.java:497) at org.mortbay.start.Main.main(Main.java:115) 2010-05-13 15:53:20.964::INFO: Started SelectChannelConnector @ 0.0.0.0:8090

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  • How to get foreignSecurityPrincipal from group. using DirectorySearcher

    - by kain64b
    What I tested with 0 results: string queryForeignSecurityPrincipal = "(&(objectClass=foreignSecurityPrincipal)(memberof:1.2.840.113556.1.4.1941:={0})(uSNChanged>={1})(uSNChanged<={2}))"; sidsForeign = GetUsersSidsByQuery(groupName, string.Format(queryForeignSecurityPrincipal, groupPrincipal.DistinguishedName, 0, 0)); public IList<SecurityIdentifier> GetUsersSidsByQuery(string groupName, string query) { List<SecurityIdentifier> results = new List<SecurityIdentifier>(); try{ using (var context = new PrincipalContext(ContextType.Domain, DomainName, User, Password)) { using (var groupPrincipal = GroupPrincipal.FindByIdentity(context, IdentityType.SamAccountName, groupName)) { DirectoryEntry directoryEntry = (DirectoryEntry)groupPrincipal.GetUnderlyingObject(); do { directoryEntry = directoryEntry.Parent; } while (directoryEntry.SchemaClassName != "domainDNS"); DirectorySearcher searcher = new DirectorySearcher(directoryEntry){ SearchScope=System.DirectoryServices.SearchScope.Subtree, Filter=query, PageSize=10000, SizeLimit = 15000 }; searcher.PropertiesToLoad.Add("objectSid"); searcher.PropertiesToLoad.Add("distinguishedname"); using (SearchResultCollection result = searcher.FindAll()) { foreach (var obj in result) { if (obj != null) { var valueProp = ((SearchResult)obj).Properties["objectSid"]; foreach (var atributeValue in valueProp) { SecurityIdentifier value = (new SecurityIdentifier((byte[])atributeValue, 0)); results.Add(value); } } } } } } } catch (Exception e) { WriteSystemError(e); } return results; } I tested it on usual users with query: "(&(objectClass=user)(memberof:1.2.840.113556.1.4.1941:={0})(uSNChanged>={1})(uSNChanged<={2}))" and it is work, I test with objectClass=* ... nothing help... But If I call groupPrincipal.GetMembers,I get all foreing user account from group. BUT groupPrincipal.GetMembers HAS MEMORY LEAK. Any Idea how to fix my query????

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  • Win32Exception: The directory name is invalid

    - by Mohammadreza
    I'm trying to run a process as a different user that has Administrator privilege in 2 different computers running Vista and their UAC enabled but in one of them I get a Win32Exception that says "The directory name is invalid" Can anyone tell me what is wrong with my code? var myFile = "D:\\SomeFolder\\MyExecutable.exe"; var workingFolder = "D:\\SomeFolder"; var pInfo = new System.Diagnostics.ProcessStartInfo(); pInfo.FileName = myFile; pInfo.WorkingDirectory = workingFolder; pInfo.Arguments = myArgs; pInfo.LoadUserProfile = true; pInfo.UseShellExecute = false; pInfo.UserName = {UserAccount}; pInfo.Password = {SecureStringPassword}; pInfo.Domain = "."; System.Diagnostics.Process.Start(pInfo); UPDATE The application that executes the above code has requireAdministrator execution level. I even set the working folder to "Path.GetDirectoryName(myFile)" and "New System.IO.FileInfo(myFile).DirectoryName"

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  • VS2008 C# error ".ctor' not supported by language

    - by Jim Jones
    C# code: class Program { static void Main(string[] args) { TFWrapper tf; String lexDir = "......."; String lic = "........"; String key = "........."; ArrayList cats = new ArrayList(); Boolean useConj = false; String lang = "english"; String encoding = "auto"; tf = new TFWrapper(lexDir, lic, key, useConj, lang, encoding); } } Managed C++ method being called: TFWrapper::TFWrapper(String^ mlexDir, String^ mlic, String^ mkey, ArrayList catList, Boolean^ m_useConj, String^ m_lang, String^ m_encoding); Getting '.ctor' is not supported by the language error on the last line of C#

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  • Listview Swipe inside viewflipper

    - by Faisal Abid
    Im trying to swipe left and right on a listview and get the viewflipper to swtich. Just like the remeberthemilk app and the default news and weather app on the nexus one (Swiping through news topics). Using various tutorials ive found , i came across on one stackoverflow that shows how to implement a swipe gesture class MyGestureDetector extends SimpleOnGestureListener { @Override public boolean onFling(MotionEvent e1, MotionEvent e2, float velocityX, float velocityY) { try { if (Math.abs(e1.getY() - e2.getY()) > SWIPE_MAX_OFF_PATH) return true; // right to left swipe if(e1.getX() - e2.getX() > SWIPE_MIN_DISTANCE && Math.abs(velocityX) > SWIPE_THRESHOLD_VELOCITY) { } else if (e2.getX() - e1.getX() > SWIPE_MIN_DISTANCE && Math.abs(velocityX) > SWIPE_THRESHOLD_VELOCITY) { viewFlipper.setInAnimation(slideRightIn); viewFlipper.setOutAnimation(slideRightOut); viewFlipper.showPrevious(); } } catch (Exception e) { // nothing } return true; } } And i got this working by doing lstView.setOnTouchListener(gestureListener); However sometimes what would happen is the listview setOnItemClickListener would be fired when the person is swiping. How do i prevent this from happening, and only get the setOnItemClickListener fired when the user actually clicks on it list item and not just swiping on it. Thanks, Faisal Abid

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  • CodeIgniter: Passing variables via URL - alternatives to using GET

    - by John Durrant
    I'm new to CodeIgniter and have just discovered the difficulties using the GET method of passing variables via the URL (e.g. domain.com/page.php?var1=1&var2=2). I gather that one approach is to pass the variables in the URI segments but haven't quite figured out how to do that yet as it seems to create the expectation of having a function in the controller named as the specific URI segment???? Anyway Instead of using GET I've decided to use POST by adapting a submit button (disguised as a link) with the variables in hidden input fields. I've created the following solution which seems to work fine, but am wondering whether I'm on the right track here or whether there is an easier way of passing variables via a link within CodeIgniter? I've created the following class in application/libraries/ <?php if ( ! defined('BASEPATH')) exit('No direct script access allowed'); class C_variables { function variables_via_link($action, $link_text, $style, $link_data) { $attributes = array('style' => 'margin:0; padding:0; display: inline;'); echo form_open($action, $attributes); $attributes = array('class' => $style, 'name' => 'link'); echo form_submit($attributes, $link_text); foreach ($link_data as $key => $value){ echo form_hidden($key, $value); } echo form_close(); } } ?> With the following CSS: /* SUBMIT BUTTON AS LINK adapted from thread: http://forums.digitalpoint.com/showthread.php?t=403667 Cross browser support (apparently). */ .submit_as_link { background: transparent; border-top: 0; border-right: 0; border-bottom: 1px solid #00F; border-left: 0; color: #00F; display: inline; margin: 0; padding: 0; cursor: hand /* Added to show hand when hovering */ } *:first-child+html .submit_as_link { /* hack needed for IE 7 */ border-bottom: 0; text-decoration: underline; } * html .submit_as_link { /* hack needed for IE 5/6 */ border-bottom: 0; text-decoration: underline; } Link then created using the following code in the VIEW: <?php $link = new C_variables; $link_data=array('var1' => 1, 'var2' => 2); $link ->variables_via_link('destination_page', 'here is a link!', 'submit_as_link', $link_data); ?> Thanks for your help...

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  • Creating a directory and parents directory in unix

    - by eveo
    I can't believe such a simple homework question is messing with me: Enter the Linux command to create both a parent directory called 'systems' and it's child directory called 'part3' at the same time. Assume that directory 'systems' will branch-off your home directory and that you are in your home directory to start. Use a relative pathname. You entered: mkdir -p ~/part3/systems/ Please try again. Hint: Use mkdir with the appropriate option Tried: mkdir -p ~/systems/part3/ mkdir -p ~systems/part3 mkdir -p ~/systems/part3 mkdir -p ~/systems/part3 mkdir ~/systems/part3/ mkdir ~systems/part3 mkdir ~/systems/part3 mkdir ~/systems/part3

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  • encodingStyle usage in XmlSerializer.Serialize

    - by Vishal Seth
    Can somebody please explain the use of 4th parameter of public void Serialize( XmlWriter xmlWriter, Object o, XmlSerializerNamespaces namespaces, string encodingStyle ) My issue is this: I've following string in one of the fields of my object: "reviewed ?" // music notation When I serialize it, it becomes & # x E; // see it as one word, w/o spaces it won't let me type And it fails when I try to transform this .NET generated XML through another XSL file Is it happening because its serializing using UTF-16? Is there any way I can make it transform using UTF-8 and make this "error" go away? **

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  • WPF Templates error - "Provide value on 'System.Windows.Baml2006.TypeConverterMarkupExtension' threw

    - by jasonk
    I've just started experimenting with WPF templates vs. styles and I'm not sure what I'm doing wrong. The goal below is to alternate the colors of the options in the menu. The code works fine with just the , but when I copy and paste/rename it for the second segment of "MenuChoiceOdd" I get the following error: Provide value on 'System.Windows.Baml2006.TypeConverterMarkupExtension' threw an exception. Sample of the code: <Window x:Class="WpfApplication1.Template_Testing" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Title="Template_Testing" Height="300" Width="300"> <Grid> <Grid.Resources> <ControlTemplate x:Key="MenuChoiceEven"> <Border BorderThickness="1" BorderBrush="#FF4A5D80"> <TextBlock Height="Auto" HorizontalAlignment="Stretch" Margin="0" Width="Auto" FontSize="14" Foreground="SlateGray" TextAlignment="Left" AllowDrop="True" Text="{Binding Path=Content, RelativeSource={RelativeSource TemplatedParent}}"> <TextBlock.Background> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="White" Offset="0" /> <GradientStop Color="#FFC2CCDB" Offset="1" /> </LinearGradientBrush> </TextBlock.Background> </TextBlock> </Border> </ControlTemplate> <ControlTemplate x:Key="MenuChoiceOdd"> <Border BorderThickness="1" BorderBrush="#FF4A5D80"> <TextBlock Height="Auto" HorizontalAlignment="Stretch" Margin="0" Width="Auto" FontSize="14" Foreground="SlateGray" TextAlignment="Left" AllowDrop="True" Text="{Binding Path=Content, RelativeSource={RelativeSource TemplatedParent}}"> <TextBlock.Background> <LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"> <GradientStop Color="White" Offset="0" /> <GradientStop Color="##FFCBCBCB" Offset="1" /> </LinearGradientBrush> </TextBlock.Background> </TextBlock> </Border> </ControlTemplate> </Grid.Resources> <Border BorderBrush="SlateGray" BorderThickness="2" Margin="10" CornerRadius="10" Background="LightSteelBlue" Width="200"> <StackPanel Margin="4"> <TextBlock Height="Auto" HorizontalAlignment="Stretch" Margin="2,2,2,0" Name="MenuHeaderTextBlock" Text="TextBlock" Width="Auto" FontSize="16" Foreground="PaleGoldenrod" TextAlignment="Left" Padding="10" FontWeight="Bold"><TextBlock.Background><LinearGradientBrush EndPoint="0.5,1" StartPoint="0.5,0"><GradientStop Color="LightSlateGray" Offset="0" /><GradientStop Color="DarkSlateGray" Offset="1" /></LinearGradientBrush></TextBlock.Background></TextBlock> <StackPanel Height="Auto" HorizontalAlignment="Stretch" Margin="2,0,2,0" Name="MenuChoicesStackPanel" VerticalAlignment="Top" Width="Auto"> <Button Template="{StaticResource MenuChoiceEven}" Content="Test Even menu element" /> <Button Template="{StaticResource MenuChoiceOdd}" Content="Test odd menu element" /> </StackPanel> </StackPanel> </Border> </Grid> </Window> What am I doing wrong?

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  • View overlapping with RelativeLayout on Android 1.5

    - by Justin
    I am having a problem with views overlapping in a RelativeLayout on Android 1.5... Everything is working fine on Android 1.6 and above. I do understand that Android 1.5 has some issues with RelativeLayout, but I was not able to find anything on StackOverflow or the android beginners group for my specific problem. My layout consists of four sections, each of which are made up of a TextView, a Gallery, and another TextView aligned vertically: Running Apps Recent Apps Services Processes When all four sets of these items are displayed everything works fine. However, my app allows the user to specify that some of these are not displayed. If the user turns off Running Apps, Recent Apps, or Services then the remaining sections all of a sudden overlap eachother. Here is my code for the layout. I'm not sure what I am doing wrong. When the user turns off display of a section I use the View.GONE visibility setting: <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="fill_parent" android:layout_height="fill_parent" android:gravity="center_vertical" android:layout_gravity="center_vertical" android:background="@null" > <!-- Running Gallery View Items --> <TextView style="@style/TitleText" android:id="@+id/running_gallery_title_text_id" android:layout_width="wrap_content" android:layout_height="wrap_content" android:gravity="left" android:paddingLeft="1sp" android:paddingRight="10sp" android:text="@string/running_title" /> <Gallery android:id="@+id/running_gallery_id" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_below="@id/running_gallery_title_text_id" android:spacing="5sp" android:clipChildren="false" android:clipToPadding="false" android:unselectedAlpha=".5" /> <TextView style="@style/SubTitleText" android:id="@+id/running_gallery_current_text_id" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_below="@id/running_gallery_id" android:gravity="center_horizontal" /> <!-- Recent Gallery View Items --> <TextView style="@style/TitleText" android:id="@+id/recent_gallery_title_text_id" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_below="@id/running_gallery_current_text_id" android:gravity="left" android:paddingLeft="1sp" android:paddingRight="10sp" android:text="@string/recent_title" /> <Gallery android:id="@+id/recent_gallery_id" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_below="@id/recent_gallery_title_text_id" android:spacing="5sp" android:clipChildren="false" android:clipToPadding="false" android:unselectedAlpha=".5" /> <TextView style="@style/SubTitleText" android:id="@+id/recent_gallery_current_text_id" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_below="@id/recent_gallery_id" android:gravity="center_horizontal" /> <!-- Service Gallery View Items --> <TextView style="@style/TitleText" android:id="@+id/service_gallery_title_text_id" android:layout_width="wrap_content" android:layout_height="wrap_content" android:layout_below="@id/recent_gallery_current_text_id" android:gravity="left" android:paddingLeft="1sp" android:paddingRight="10sp" android:text="@string/service_title" /> <Gallery android:id="@+id/service_gallery_id" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_below="@id/service_gallery_title_text_id" android:spacing="5sp" android:clipChildren="false" android:clipToPadding="false" android:unselectedAlpha=".5" /> <TextView style="@style/SubTitleText" android:id="@+id/service_gallery_current_text_id" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_below="@id/service_gallery_id" android:gravity="center_horizontal" /> </RelativeLayout> I ommitted the xml for the Processes section in a (somewhat vain) attempt to keep this shorter... What can I do to make this work in Android 1.5? I don't think it is just a matter of reordering the views in the xml because it works fine when everything is displayed.

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  • Unable to determine the URL to the Xap file

    - by Matthew Glace
    I started developing a Silverlight (SL) 4 application hosted in an ASP.NET site using Visual Studio 2010. Now I want to change it so that the SL application runs out of browser as if I had not chosen to host it in a web site when I created the SL project. First, I went to the properties of the web application and removed the SL project from the “Silverlight Applications” tab. Then, I went to the properties of the SL project and made sure the “Out-of-browser Application” option was chosen on the “Debug” tab with the SL project selected in the drop list. Finally, I made sure that the SL project was set as the “StartUp” project for the solution. The solution builds successfully however when I try to run I get the following message in an error dialog: Unable to determine the URL to the Xap file from web [web project name]. I'm assuming this is happening because the SL project is trying to copy the Xap file to the ClientBin folder of the web site. Obviously, the SL and web projects are still linked in some way despite my attempt to unlink the two. I have examined each project file in notepad to find any reference between them with no luck. What’s more frustrating is that I can achieve my desired result by creating a new SL application and un-checking the “Host the Silverlight application in a new or existing Web site in the solution” option. I know I could start my project over from scratch to solve this problem however I’m really curious as to what is causing this error. A Google search yielded no results.

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  • Mongodb vs. Cassandra

    - by ming yeow
    I am evaluating what might be the best migration option. Currently, i am on a sharded mysql (horizontal partition), with most of my data stored in json blobs. I do not have any complex SQL queries( already migrated away after since I partitioned my db) Right now, it seems like both Mongodb and Cassandra would be likely options. My situation lots of reads in every query, less regular writes not worried about "massive" scalability more concerned about simple setup, maintenance and code minimize hardware/server cost

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  • Spring 3.0: Unable to locate Spring NamespaceHandler for XML schema namespace

    - by Nick Hristov
    My setup is fairly simple: I have a web front-end, back-end is spring-wired. I am using AOP to add a layer of security on my rpc services. It's all good, except for the fact that the web app aborts on launch: [java] SEVERE: Context initialization failed [java] org.springframework.beans.factory.parsing.BeanDefinitionParsingException: Configuration problem: Unable to locate Spring NamespaceHandler for XML schema namespace [http://www.springframework.org/schema/aop] [java] Offending resource: ServletContext resource [/WEB-INF/gwthandler-servlet.xml] Here is the snippet from my xml config file: <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:aop="http://www.springframework.org/schema/aop" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop.xsd"> <aop:config> <aop:aspect id="security" ref="securityAspect" > <aop:pointcut id="securedServices" expression="@annotation(com.fb.boog.common.aspects.Secured)"/> <aop:before method="checkSecurity" pointcut-ref="securedServices"/> </aop:aspect> </aop:config> I read over the internets that it may be my classloading the core of the problem. Doubtful, since here is my WEB-INF/lib directory: ./WEB-INF/lib ./WEB-INF/lib/aopalliance-alpha1.jar ./WEB-INF/lib/aspectj-1.6.6.jar ./WEB-INF/lib/commons-collections.jar ./WEB-INF/lib/commons-logging.jar ./WEB-INF/lib/ehcache-core-1.7.0.jar ./WEB-INF/lib/ejb3-persistence.jar ./WEB-INF/lib/hibernate ./WEB-INF/lib/hibernate/antlr.jar ./WEB-INF/lib/hibernate/asm.jar ./WEB-INF/lib/hibernate/bsh-2.0b1.jar ./WEB-INF/lib/hibernate/cglib.jar ./WEB-INF/lib/hibernate/dom4j.jar ./WEB-INF/lib/hibernate/freemarker.jar ./WEB-INF/lib/hibernate/hibernate-annotations.jar ./WEB-INF/lib/hibernate/hibernate-shards.jar ./WEB-INF/lib/hibernate/hibernate-tools.jar ./WEB-INF/lib/hibernate/hibernate.jar ./WEB-INF/lib/hibernate/jtidy-r8-20060801.jar ./WEB-INF/lib/jabsorb ./WEB-INF/lib/jabsorb/jabsorb-1.3.1.jar ./WEB-INF/lib/jta.jar ./WEB-INF/lib/jyaml-1.3.jar ./WEB-INF/lib/postgresql-8.4-701.jdbc4.jar ./WEB-INF/lib/sjsxp.jar ./WEB-INF/lib/spring ./WEB-INF/lib/spring/org.springframework.aop-3.0.0.RELEASE.jar ./WEB-INF/lib/spring/org.springframework.asm-3.0.0.RELEASE.jar ./WEB-INF/lib/spring/org.springframework.aspects-3.0.0.RELEASE.jar ./WEB-INF/lib/spring/org.springframework.beans-3.0.0.RELEASE.jar ./WEB-INF/lib/spring/org.springframework.context-3.0.0.RELEASE.jar ./WEB-INF/lib/spring/org.springframework.context.support-3.0.0.RELEASE.jar ./WEB-INF/lib/spring/org.springframework.core-3.0.0.RELEASE.jar ./WEB-INF/lib/spring/org.springframework.expression-3.0.0.RELEASE.jar ./WEB-INF/lib/spring/org.springframework.instrument-3.0.0.RELEASE.jar ./WEB-INF/lib/spring/org.springframework.instrument.tomcat-3.0.0.RELEASE.jar ./WEB-INF/lib/spring/org.springframework.jdbc-3.0.0.RELEASE.jar ./WEB-INF/lib/spring/org.springframework.jms-3.0.0.RELEASE.jar ./WEB-INF/lib/spring/org.springframework.orm-3.0.0.RELEASE.jar ./WEB-INF/lib/spring/org.springframework.oxm-3.0.0.RELEASE.jar ./WEB-INF/lib/spring/org.springframework.test-3.0.0.RELEASE.jar ./WEB-INF/lib/spring/org.springframework.transaction-3.0.0.RELEASE.jar ./WEB-INF/lib/spring/org.springframework.web-3.0.0.RELEASE.jar ./WEB-INF/lib/spring/org.springframework.web.portlet-3.0.0.RELEASE.jar ./WEB-INF/lib/spring/org.springframework.web.servlet-3.0.0.RELEASE.jar ./WEB-INF/lib/spring/org.springframework.web.struts-3.0.0.RELEASE.jar ./WEB-INF/lib/testng-5.11-jdk15.jar ./WEB-INF/web.xml

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  • WPF TabControl - how to preserve control state within tab items (MVVM pattern)

    - by Tim Coulter
    I am a newcomer to WPF, attempting to build a project that follows the recommendations of Josh Smith's excellent article describing The Model-View-ViewModel Design Pattern. Using Josh's sample code as a base, I have created a simple application that contains a number of "workspaces", each represented by a tab in a TabControl. In my application, a workspace is a document editor that allows a hierarchical document to be manipulated via a TreeView control. Although I have succeeded in opening multiple workspaces and viewing their document content in the bound TreeView control, I find that the TreeView "forgets" its state when switching between tabs. For example, if the TreeView in Tab1 is partially expanded, it will be shown as fully collapsed after switching to Tab2 and returning to Tab1. This behaviour appears to apply to all aspects of control state for all controls. After some experimentation, I have realized that I can preserve state within a TabItem by explicitly binding each control state property to a dedicated property on the underlying ViewModel. However, this seems like a lot of additional work, when I simply want all my controls to remember their state when switching between workspaces. I assume I am missing something simple, but I am not sure where to look for the answer. Any guidance would be much appreciated. Thanks, Tim Update: As requested, I will attempt to post some code that demonstrates this problem. However, since the data that underlies the TreeView is complex, I will post a simplified example that exhibits the same symtoms. Here is the XAML from the main window: <TabControl IsSynchronizedWithCurrentItem="True" ItemsSource="{Binding Path=Docs}"> <TabControl.ItemTemplate> <DataTemplate> <ContentPresenter Content="{Binding Path=Name}" /> </DataTemplate> </TabControl.ItemTemplate> <TabControl.ContentTemplate> <DataTemplate> <view:DocumentView /> </DataTemplate> </TabControl.ContentTemplate> </TabControl> The above XAML correctly binds to an ObservableCollection of DocumentViewModel, whereby each member is presented via a DocumentView. For the simplicity of this example, I have removed the TreeView (mentioned above) from the DocumentView and replaced it with a TabControl containing 3 fixed tabs: <TabControl> <TabItem Header="A" /> <TabItem Header="B" /> <TabItem Header="C" /> </TabControl> In this scenario, there is no binding between the DocumentView and the DocumentViewModel. When the code is run, the inner TabControl is unable to remember its selection when the outer TabControl is switched. However, if I explicitly bind the inner TabControl's SelectedIndex property ... <TabControl SelectedIndex="{Binding Path=SelectedDocumentIndex}"> <TabItem Header="A" /> <TabItem Header="B" /> <TabItem Header="C" /> </TabControl> ... to a corresponding dummy property on the DocumentViewModel ... public int SelecteDocumentIndex { get; set; } ... the inner tab is able to remember its selection. I understand that I can effectively solve my problem by applying this technique to every visual property of every control, but I am hoping there is a more elegant solution.

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  • How do I hide the UITableViewCell border for a custom cell in a group tableview?

    - by Gorgando
    What I am trying to do: I want three buttons side-by-side in a tableviewcell just like in Contacts app. What I've done: I have a custom tableviewcell with three uibuttons in it. I've set the background color of the tableviewcell to be transparent. What I can't figure out: The tableviewcell border is still there! Everything looks great except for the border floating around the 3 buttons. Am I doing this completely wrong? Or is there a simple way to remove/hide the border? Thanks!!!

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  • MSTest VS2010 - DeploymentItem copying files to different locations on different machines

    - by Jack
    I have found that DeploymentItem [TestClass(), DeploymentItem(@"TestData\")] is not copying my test data files to the same location when tests are built and run on different machines. The test data files are copied to the "bin\debug" directory in the test project on my machine, but on my friend's machine they are copied to "TestResults\*name_machine YY-MM-DD HH_MM_SS*\Out". The bin\debug directory on my machine can be obtained with the code: string appDirectory = Path.GetDirectoryNameSystem.Reflection.Assembly.GetExecutingAssembly().Location; and the same code will return "TestResults\*name_machine YY-MM-DD HH_MM_SS*\Out" on my friends PC. This however isn't really the problem. The problem is that the test data files I have made have a folder structure, and this folder structure is only maintained on my machine when copied to bin\debug, whereas on my friends machine only the files are added to the "TestResults\*name_machine YY-MM-DD HH_MM_SS*\Out" directory. This means that tests will pass on my machine and fail on his! Is there a way to ensure that DeploymentItem always copys to the bin\debug folder? Or a way to ensure that the folder structure will be retained when DeploymentItem copies the files to the "TestResults\*name_machine YY-MM-DD HH_MM_SS*\Out" folder?

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  • Curl, twitter oauth problem

    - by Darxval
    Does anyone see a problem with the following Curl call / how the Oauth request is built? (i am trying to get a correctly setup request so i can finish my app) So i am calling the following CURL call: C:\>curl -v -k --data-urlencode "status=Testing2" -H "Authorization: OAuth realm='', oauth_nonce=1276107867blah, oauth_timestamp=1276107867, oauth_consumer_key=yJDLH7BDdVi1OKIINSV7Q, oauth_signature_method=HMAC-SHA1, oauth_version=1.0, oauth_signature=NWU4MDdlNjk0OGIxYWQ1YTkyNmU5YjU1NGYyOTczMmU5ZDg5 YWNkNA==, staus=Testing2 " http://twitter.com/statuses/update.xml?status=Testing2 and i recieve this: * About to connect() to twitter.com port 80 (#0) * Trying 168.143.162.68... connected * Connected to twitter.com (168.143.162.68) port 80 (#0) > POST /statuses/update.xml?status=Testing2 HTTP/1.1 > User-Agent: curl/7.20.1 (i386-pc-win32) libcurl/7.20.1 OpenSSL/0.9.8n zlib/1.2.5 libidn/1.18 libssh2/1.2.5 > Host: twitter.com > Accept: */* > Authorization: OAuth realm='', oauth_nonce=1276106370blah, oauth_timestamp=1276106370, oauth_consumer_key=yJDLH7BDdVi1OKIINSV7Q, oauth_signature_method=HMAC-SHA1, oauth_version=1.0, oauth_signature=MjQzNDA1MGU4NGRmMWVjMzUwZmQ4YzE5NzMzY2I1ZDJlOTRkNmQ2Zg==, staus=Testing2 > Content-Length: 15 > Content-Type: application/x-www-form-urlencoded > < HTTP/1.1 401 Unauthorized < Date: Wed, 09 Jun 2010 18:00:22 GMT < Server: hi < Status: 401 Unauthorized < WWW-Authenticate: Basic realm="Twitter API" < X-Runtime: 0.00548 < Content-Type: application/xml; charset=utf-8 < Content-Length: 164 < Cache-Control: no-cache, max-age=1800 < Set-Cookie: k=209.234.229.21.1276106420885412; path=/; expires=Wed, 16-Jun-10 18:00:20 GMT; domain=.twitter.com < Set-Cookie: guest_id=127610642214871948; path=/; expires=Fri, 09 Jul 2010 18:00:22 GMT < Set-Cookie: _twitter_sess=BAh7CDoPY3JlYXRlZF9hdGwrCIm33h0pAToHaWQiJTkyMjllODE0NTdiYWE1%250AMWU1MzBmNjgwMTFiMDhkYjdlIgpmbGFzaElDOidBY3Rpb25Db250cm9sbGVy%250AOjpGbGFzaDo6Rmxhc2hIYXNoewAGOgpAdXNlZHsA--8ebb3c62d461d28f8fda7b8adab642af66969f7e; domain=.twitter.com; path=/ < Expires: Wed, 09 Jun 2010 18:30:20 GMT < Vary: Accept-Encoding < Connection: close < <?xml version="1.0" encoding="UTF-8"?> <hash> <request>/statuses/update.xml?status=Testing2</request> <error>Could not authenticate with OAuth.</error> </hash> * Closing connection #0 my Parameters are setup like so: var parameters = [encodeURIComponent("status="+status),encodeURIComponent("oauth_token="+ac_token),encodeURIComponent("oauth_consumer_key="+"yJDLH7BDdVi1OKIINSV7Q"),encodeURIComponent("oauth_nonce="+nonce,"oauth_signature_method=HMAC-SHA1"),encodeURIComponent("oauth_timestamp="+timestamp),encodeURIComponent("oauth_version=1.0")] var join = parameters.join("&"); var eparamjoin =encodeURIComponent(join); The key is like so: var key=con_secret+"&"+ac_secret; Signature base string is: var signaturebs = "POST&"+encodeURIComponent(url)+"&"+eparamjoin; giving this: POST&http%3A%2F%2Ftwitter.com%2Fstatuses%2Fupdate.xml&status%253DTesting2%26oauth_token%253D142715285-yi2ch324S3zfyKyJby6WDUZOhCsiQuKNUtc3nAGe%26oauth_consumer_key%253DyJDLH7BDdVi1OKIINSV7Q%26oauth_nonce%253D1276107867blah%26oauth_timestamp%253D1276107867%26oauth_version%253D1.0 and signature built like so: var hmac = Crypto.HMAC(Crypto.SHA1, signaturebs,key ); var signature=Base64.encode(hmac); making the signature: NWU4MDdlNjk0OGIxYWQ1YTkyNmU5YjU1NGYyOTczMmU5ZDg5YWNkNA== Any help would be appreciated thank you!

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  • Excel 2007 - "The macro may not be available in this workbook" Error

    - by Psycho Bob
    We use an Excel sheet that has been protected to prevent modification of it from end users. All in all they are only able to edit certain tabs to add information that will then be used to generate information on other tabs using equations and such. On the tab with the equations, a button is present called "Prep for Internal Hard Copy Print." This button runs a macro that selects the information on the tab, unprotects it, then sends a print job to the user's default printer that contains the unprotected content. Normally this works like a champ. This time around, however, the macro is throwing the following error: Cannot run the macro "FILENAME.xlsx'!MacroName'. The macro may not be available in this workbook or all macros may be disabled. As far as I can tell, the macros are still present within the workbook. This sheet is normally a .xlsm though the user saved it with a different filename as a .xlsx. Also, the macros appear only as MacroName in the .xlsm file and not "FILENAME.xlsx'!MacroName' as it does in the .xlsx. Finally, when I open the .xlsm it asks if I want to enable the macro content while the .xlsx does not prompt for this. Can anyone tell me what's going on with this sheet or know of a way that I can get the macros working in the .xlsx without having to start over with a different sheet?

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  • SignalR cannot read property client of undefined

    - by polonskyg
    I'm trying to add SignalR to my project (ASPNET MVC 4). But I can't make it work. In the below image you can see the error I'm receiving. I've read a lot of stackoverflow posts but none of them is resolving my issue. This is what I did so far: 1) Ran Install-Package Microsoft.AspNet.SignalR -Pre 2) Added RouteTable.Routes.MapHubs(); in Global.asax.cs Application_Start() 3) If I go to http://localhost:9096/Gdp.IServer.Web/signalr/hubs I can see the file content 4) Added <modules runAllManagedModulesForAllRequests="true"/> to Web.Config 5) Created folder Hubs in the root of the MVC application 6) Moved jquery and signalR scripts to /Scripts/lib folder (I'm not using jquery 1.6.4, I'm using the latest) This is my Index.cshtml <h2>List of Messages</h2> <div class="container"> <input type="text" id="message" /> <input type="button" id="sendmessage" value="Send" /> <input type="hidden" id="displayname" /> <ul id="discussion"> </ul> </div> @section pageScripts { <!--Reference the SignalR library. --> <script src="@Url.Content("~/Scripts/jquery.signalR-1.0.0-rc1.min.js")" type="text/javascript"></script> <!--Reference the autogenerated SignalR hub script. --> <script type="text/javascript" src="~/signalr/hubs"></script> <script src="@Url.Content("~/Scripts/map.js")" type="text/javascript"></script> } This is my IServerHub.cs file (located inside Hubs folder) namespace Gdp.IServer.Ui.Web.Hubs { using Microsoft.AspNet.SignalR.Hubs; [HubName("iServerHub")] public class IServerHub : Hub { public void Send(string name, string message) { Clients.All.broadcastMessage(name, message); } } } And this is map.js $(function () { // Declare a proxy to reference the hub. var clientServerHub = $.connection.iServerHub; // Create a function that the hub can call to broadcast messages. clientServerHub.client.broadcastMessage = function (name, message) { $('#discussion').append('<li><strong>' + name + '</strong>:&nbsp;&nbsp;' + message + '</li>'); }; // Get the user name and store it to prepend to messages. $('#displayname').val(prompt('Enter your name:', '')); // Set initial focus to message input box. $('#message').focus(); // Start the connection. $.connection.hub.start().done(function () { $('#sendmessage').click(function () { // Html encode display name and message. var encodedName = $('<div />').text($('#displayname').val()).html(); var encodedMsg = $('<div />').text($('#message').val()).html(); // Call the Send method on the hub. clientServerHub.server.send(encodedName, encodedMsg); // Clear text box and reset focus for next comment. $('#message').val('').focus(); }); }); }); The DLL's I see references for SignalR are: Microsoft.AspNet.SignalR.Core Microsoft.AspNet.SignalR.Owin Microsoft.AspNet.SignalR.SystemWeb Any ideas how to get it work? Should I make any change because the scripts are in /Script/lib folder? NOTE I'm following the instruction found here on how to set up Windsor Castle to make it work with SignalR, and again, seems that the proxy cannot be created and I'm getting the same error: Cannot read property client of undefined meaning that the proxy to the hub was not created This is how I have it in the server public class IncidentServerHub : Hub and like this in the client var clientServerHub = $.connection.incidentServerHub; Again, I can see the dynamically created file here: /GdpSoftware.Server.Web/signalr/hubs So, Why the proxy is not created? Thanks in advance!!! Guillermo.

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  • Android AppWidget TextView: How to set background color programmaticly

    - by Amit
    I am trying to create an AppWidget, in which the background color of a TextView changes at random at specified periodic interval. The TextView is defined in layout xml file as <?xml version="1.0" encoding="utf-8" ?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/widget" android:layout_width="fill_parent" android:layout_height="wrap_content" android:orientation="vertical" > <TextView android:id="@+id/message" android:background="#ff99ff" android:text="Hello Widget" /> </LinearLayout> In update method, i have loaded the layout as RemoteViews remoteView=new RemoteViews(context.getPackageName(),R.layout.widget_message); To change the background of TextView i used the following statement remoteView.setInt(R.id.message, "setBackgroundResource", R.color.col_1); But i am getting a widget saying problem loading widget. If i remove the above line everything works fine. LogCat says: updateAppWidget couldn't find any view, using error view android.widget.RemoteViews$ActionException: view: android.widget.TextView can't use method with RemoteViews: setBackgroundResource(int)

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  • Android custom widget styles: how to put them into a namespace?

    - by Matthias
    In the ApiDemos, there is a view example called Gallery1 which declares a custom style in attrs.xml, as such: <declare-styleable name="Gallery1"> <attr name="android:galleryItemBackground" /> </declare-styleable> now, I want to do the same thing for my widgets, but using a different namespace. However, as soon as I replace the android: namespace with something else, I get this error: ERROR: In Gallery1, unable to find attribute myns:galleryItemBackground Unable to find attribute? Why does it look for an attribute I am about to declare? Isn't the point of this file to be able to name your own custom attributes? It's interesting to note that it works if you do not supply a custom namespace, but just an attribute name.

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  • Linq to Datarow, Select multiple columns as distinct?

    - by Beta033
    basically i'm trying to reproduce the following mssql query as LINQ SELECT DISTINCT [TABLENAME], [COLUMNNAME] FROM [DATATABLE] the closest i've got is Dim query = (From row As DataRow In ds.Tables("DATATABLE").Rows _ Select row("COLUMNNAME") ,row("TABLENAME").Distinct when i do the above i get the error Range variable name can be inferred only from a simple or qualified name with no arguments. i was sort of expecting it to return a collection that i could then iterate through and perform actions for each entry. maybe a datarow collection? As a complete LINQ newb, i'm not sure what i'm missing. i've tried variations on Select new with { row("COLUMNNAME") ,row("TABLENAME")} and get: Anonymous type member name can be inferred only from a simple or qualified name with no arguments. Also, does anyone know of any good books/resources to get fluent?

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