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  • Clean installation of RHEL 5.5 claims package "desktops" is missing

    - by TKguru42
    Hi all, I'm a student worker in the CS department of my university, so please forgive me for any unprofessional descriptions. Simplified explanations are appreciated. I recently replaced some bad graphics cards in a few public workstations. The machines are all the same model. Before putting them back on the network I did fresh installs of RHEL---first I tried 5.4, but yum update ran into all sorts of ugly dependency errors and if I tried to remove any of the problematic packages, the whole operating system FUBAR'd. Using RHEL 5.5 gave me the same errors during install saying that "java.1.5.1-sun*" and "desktops" were missing, but yum update didn't have any dependency problems. Now that I tried logging in through the GUI, I encounter no GUI past the standard RHEL login page. The desktop is a uniform light teal and there's no system tray. An xclock window and an xterm window are open, and Firefox opens automatically, but that's it. Nothing else. What's REALLY confusing is that the computer claims that gnome is already installed, except it clearly isn't working. Any help or advice is greatly appreciated. If it helps, our department uses kickstart to run our standard Linux installs. I can try to get the script if that would be of use. Thank you!

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  • Best way to laod a large file into arraylist in java

    - by user1730833
    I have a file whose size is about 300mb i want to read the contents line by line and then add it into arraylist. So i have made an object of array list a1 , then reading the file using bufferedreader , after that when i add the lines from file into arraylist it gives an error Exception in thread "main" java.lang.OutOfMemoryError: Java heap space. Please tell me what should be the solution for this.

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  • Why wait should always be in synchronized block

    - by diy
    Hi gents, We all know that in order to invoke Object.wait() , this call must be placed in synchronized block,otherwise,IllegalMonitorStateException is thrown.But what's the reason for making this restriction?I know that wait() releases the monitor, but why do we need to explicitly acquire the monitor by making particular block synchronized and then release the monitor by calling wait() ? What is the potential damage if it was possible to invoke wait() outside synch block, retaining it's semantics - suspending the caller thread ? Thanks in advance

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  • Best way to get a query result

    - by xgoan
    I'm developing an application that gets large images from an Internet server which is the best way to download this images, without freeze the entire application? I mean background download. I have thought about download it in another thread.

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  • How to get IE to open JavaScript as text

    - by Pete
    I am running IE 9. Up until last week sometime, if I would put the URL of a JavaScript file in the address bar, it would show the JavaScript as text in the browser window. Now when I do that, it wants to download the JavaScript file. How can I revert it to the previous handling? This is annoying since I'm developing a web application and if I can get it to display the .js files as text in the browser, then I can refresh it to force the cache to update. Update: I've tested on several co-workers machines. For some, browsing to .js files renders them in the browser (IE 9 in all cases). In others, it asks for a download. File associations don't seem to have any effect. One co-worker we tested with IE and Chrome. IE wanted to download it, but Chrome rendered it as text. This makes me think it's an IE issue and not an OS issue.

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  • [winapi] Three questions about editbox ?

    - by subSeven
    Hello! I have three questions about editbox control in WINAPI (i can't find information on msdn about this) 1. How to disable moving typeing cursor with mouse, arrows, backspace in editbox ? I want to make typing like in command line in dos, but with out backspace. Can I write some piece of text with red color, and another with blue ? How to write to editbox control from another thread ?

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  • Singleton & Multithreading in Java

    - by vivek jagtap
    What is the preferred way to work with Singleton class in multithreaded environment? Suppose if I have 3 thread, and all they try to access getInstance() method of singleton class at the same time - What would happen if no synchronization is maintained? Is it good practice to use synchronized getInstance() method or use synchronized block inside getInstance(). Please advise if there is any other way out.

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  • Android - doInBackground() error in AsyncTask

    - by AimanB
    What my app here basically does is it captures a photo or import from gallery, and when the Upload button is pressed, the image will be uploaded to a localhost server. Before I implemented AsyncTask into the process, it doesn't have any problem uploading whatsoever. Now that I've put AsyncTask, everything went wrong. I don't know which part that I do wrong in this phase. This is what logcat shows when I try to upload an image file: 10-28 17:23:25.989: E/AndroidRuntime(3356): FATAL EXCEPTION: AsyncTask #5 10-28 17:23:25.989: E/AndroidRuntime(3356): java.lang.RuntimeException: An error occured while executing doInBackground() 10-28 17:23:25.989: E/AndroidRuntime(3356): at android.os.AsyncTask$3.done(AsyncTask.java:299) 10-28 17:23:25.989: E/AndroidRuntime(3356): at java.util.concurrent.FutureTask.finishCompletion(FutureTask.java:352) 10-28 17:23:25.989: E/AndroidRuntime(3356): at java.util.concurrent.FutureTask.setException(FutureTask.java:219) 10-28 17:23:25.989: E/AndroidRuntime(3356): at java.util.concurrent.FutureTask.run(FutureTask.java:239) 10-28 17:23:25.989: E/AndroidRuntime(3356): at android.os.AsyncTask$SerialExecutor$1.run(AsyncTask.java:230) 10-28 17:23:25.989: E/AndroidRuntime(3356): at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1080) 10-28 17:23:25.989: E/AndroidRuntime(3356): at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:573) 10-28 17:23:25.989: E/AndroidRuntime(3356): at java.lang.Thread.run(Thread.java:856) 10-28 17:23:25.989: E/AndroidRuntime(3356): Caused by: java.lang.RuntimeException: Can't create handler inside thread that has not called Looper.prepare() 10-28 17:23:25.989: E/AndroidRuntime(3356): at android.os.Handler.<init>(Handler.java:197) 10-28 17:23:25.989: E/AndroidRuntime(3356): at android.os.Handler.<init>(Handler.java:111) 10-28 17:23:25.989: E/AndroidRuntime(3356): at android.widget.Toast$TN.<init>(Toast.java:324) 10-28 17:23:25.989: E/AndroidRuntime(3356): at android.widget.Toast.<init>(Toast.java:91) 10-28 17:23:25.989: E/AndroidRuntime(3356): at android.widget.Toast.makeText(Toast.java:238) 10-28 17:23:25.989: E/AndroidRuntime(3356): at com.aiman.webshopper.UploadImageActivity$1execMultiPostAsync.doInBackground(UploadImageActivity.java:268) 10-28 17:23:25.989: E/AndroidRuntime(3356): at com.aiman.webshopper.UploadImageActivity$1execMultiPostAsync.doInBackground(UploadImageActivity.java:1) 10-28 17:23:25.989: E/AndroidRuntime(3356): at android.os.AsyncTask$2.call(AsyncTask.java:287) 10-28 17:23:25.989: E/AndroidRuntime(3356): at java.util.concurrent.FutureTask.run(FutureTask.java:234) This is my code for the Upload activity: public class UploadImageActivity extends Activity implements OnItemSelectedListener { InputStream inputStream; private ImageView imageView; String the_string_response; private static final int SELECT_PICTURE = 0; private static final int CAMERA_REQUEST = 1888; private static final String SERVER_UPLOAD_URI = "...myserver.php"; @Override protected void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_upload_image); imageView = (ImageView) findViewById(R.id.imgUpload); } public void capturePhoto(View view) { Intent cameraIntent = new Intent( android.provider.MediaStore.ACTION_IMAGE_CAPTURE); File f = new File(android.os.Environment.getExternalStorageDirectory(), "temp.jpg"); cameraIntent.putExtra(MediaStore.EXTRA_OUTPUT, Uri.fromFile(f)); startActivityForResult(cameraIntent, CAMERA_REQUEST); } public void pickPhoto(View view) { // TODO: launch the photo picker Intent intent = new Intent(); intent.setType("image/*"); intent.setAction(Intent.ACTION_GET_CONTENT); startActivityForResult(Intent.createChooser(intent, "Select Picture"), SELECT_PICTURE); } @Override protected void onActivityResult(int requestCode, int resultCode, Intent data) { super.onActivityResult(requestCode, resultCode, data); if (requestCode == CAMERA_REQUEST && resultCode == RESULT_OK) { File f = new File(Environment.getExternalStorageDirectory() .toString()); for (File temp : f.listFiles()) { if (temp.getName().equals("temp.jpg")) { f = temp; break; } } try { BitmapFactory.Options bitmapOptions = new BitmapFactory.Options(); Bitmap bitmap = BitmapFactory.decodeFile(f.getAbsolutePath(), bitmapOptions); imageView.setImageBitmap(bitmap); String path = android.os.Environment .getExternalStorageDirectory() + File.separator + "Phoenix" + File.separator + "default"; f.delete(); OutputStream outFile = null; File file = new File(path, String.valueOf(System .currentTimeMillis()) + ".jpg"); try { outFile = new FileOutputStream(file); bitmap.compress(Bitmap.CompressFormat.JPEG, 85, outFile); outFile.flush(); outFile.close(); } catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } catch (Exception e) { e.printStackTrace(); } } catch (Exception e) { e.printStackTrace(); } } if (requestCode == SELECT_PICTURE && resultCode == RESULT_OK) { Bitmap bitmap = getPath(data.getData()); imageView.setImageBitmap(bitmap); } } private Bitmap getPath(Uri uri) { String[] projection = { MediaStore.Images.Media.DATA }; Cursor cursor = getContentResolver().query(uri, projection, null, null, null); int column_index = cursor.getColumnIndexOrThrow(projection[0]); cursor.moveToFirst(); String filePath = cursor.getString(column_index); cursor.close(); // Convert file path into bitmap image using below line. Bitmap bitmap = BitmapFactory.decodeFile(filePath); return bitmap; } public void uploadPhoto(View view) { try { executeMultipartPost(); } catch (Exception e) { e.printStackTrace(); } } public void executeMultipartPost() throws Exception { class execMultiPostAsync extends AsyncTask<String, Void, String>{ @Override protected String doInBackground(String... params){ // Choose image here BitmapDrawable drawable = (BitmapDrawable) imageView.getDrawable(); Bitmap bitmap = drawable.getBitmap(); ByteArrayOutputStream stream = new ByteArrayOutputStream(); bitmap.compress(Bitmap.CompressFormat.JPEG, 50, stream); // compress to // which // format // you want. byte[] byte_arr = stream.toByteArray(); String image_str = Base64.encodeBytes(byte_arr); ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(); nameValuePairs.add(new BasicNameValuePair("image", image_str)); try { HttpClient httpclient = new DefaultHttpClient(); /* * HttpPost(parameter): Server URI */ HttpPost httppost = new HttpPost(SERVER_UPLOAD_URI); httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs)); HttpResponse response = httpclient.execute(httppost); the_string_response = convertResponseToString(response); } catch (Exception e) { Toast.makeText(UploadImageActivity.this, "ERROR " + e.getMessage(), Toast.LENGTH_LONG).show(); System.out.println("Error in http connection " + e.toString()); } return the_string_response; } @Override protected void onPostExecute(String result) { super.onPostExecute(result); Toast.makeText(UploadImageActivity.this, "Response " + result, Toast.LENGTH_LONG) .show(); } public String convertResponseToString(HttpResponse response) throws IllegalStateException, IOException { String res = ""; StringBuffer buffer = new StringBuffer(); inputStream = response.getEntity().getContent(); int contentLength = (int) response.getEntity().getContentLength(); // getting // content // lengt Toast.makeText(UploadImageActivity.this, "contentLength : " + contentLength, Toast.LENGTH_LONG).show(); if (contentLength < 0) { } else { byte[] data = new byte[512]; int len = 0; try { while (-1 != (len = inputStream.read(data))) { buffer.append(new String(data, 0, len)); // converting to // string and // appending to // stringbuffer } } catch (IOException e) { e.printStackTrace(); } try { inputStream.close(); // closing the stream } catch (IOException e) { e.printStackTrace(); } res = buffer.toString(); // converting stringbuffer to string Toast.makeText(UploadImageActivity.this, "Result : " + res, Toast.LENGTH_LONG).show(); // System.out.println("Response => " + // EntityUtils.toString(response.getEntity())); } return res; } } execMultiPostAsync exec = new execMultiPostAsync(); exec.execute(); } } Can someone please check if I put the AsyncTask task correctly in this activity? I think I've made a mistake somewhere.

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  • Trying to draw an image to a form, but not refreshing

    - by flavour404
    Hi, We are using graphics context of a form to draw an image. However it works fine on initial paint but the image is not being updated unless we set a breakpoint and run it in debug mode, stepping through each time. What is a good way of making a seperate thread to paint on to a form every second? Thanks.

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  • Interconnecting Emulator Instances Android

    - by blah01
    Hi all I want to communicate two emulators via DatagramSocket in Android. Each of them is a Node in a P2P system. Thus each of them has a server Thread and client Thread (created per GUI event). This is how I create server public static final String SERVERIP = "10.0.2.15"; //... run() { InetAddress serverAddr = InetAddress.getByName(SERVERIP); DatagramSocket socket = new DatagramSocket(SERVERPORT,serverAddr); while(true) { byte[] buf = new byte[29]; DatagramPacket packet = new DatagramPacket(buf, buf.length); socket.receive(packet); //... } } The port is given by the user during initializing application. The client part (requesting some data) InetAddress serverAddr = InetAddress.getByName("10.0.2.2"); //... Log.i("Requester", "Trying to connect to device port = "+target); DatagramSocket socketJ = new DatagramSocket(); byte[] bufJ = Adaptor.createStringMsg(Adaptor.createJoingMsg(id, Location.getX(), Location.getY())).getBytes(); DatagramPacket packetJ = new DatagramPacket(bufJ, bufJ.length, serverAddr, target); Log.i("Requester", "Sending: '" + new String(bufJ) + "'"); socketJ.send(packetJ); Log.i("Requester", "Done."); Some additional info. The Node1 (emulatorA) has a server on port 8000 and Node2 (emulatorB) has a server on port 8001. The target port for "client part" is read properly. What tried to do is to set the redirection as such: //emulatorA redir add tcp:8000:8000 //emulatorB redir add tcp:8001:8001 However I can not get any communication beetwen those 2 emulators. As far as I understood the android tutorial about it should work like this redir add tcp:localhostPort:emulatorPort. I'm stuck with it :/. Can anyone point me the mistake or give some good advice. For the record while I was testing communication on a single device (client faking other node) everything worked, so I don't think there is a bug in the code. Btw does any one knows how can I get 2 set of logs for those 2 emulators (logA, logB)? It would help me a lot.

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  • SQL Server 2005 Disk Configuration: Single RAID 1+0 or multiple RAID 1+0s?

    - by mfredrickson
    Assuming that the workload for the SQL Server is just a normal OLTP database, and that there are a total of 20 disks available, which configuration would make more sense? A single RAID 1+0, containing all 20 disks. This physical volume would contain both the data files and the transaction log files, but two logical drives would be created from this RAID: one for the data files and one for the log files. Or... Two RAID 1+0s, each containing 10 disks. One physical volume would contain the data files, and the other would contain the log files. The reason for this question is due to a disagreement between me (SQL Developer) and a co-worker (DBA). For every configuration that I've done, or seen others do, the data files and transaction log files were separated at the physical level, and were placed on separate RAIDs. However, my co-workers argument is that by placing all the disks into a single RAID 1+0, then any IO that is done by the server is potentially shared between all 20 disks, instead of just 10 disks in my suggested configuration. Conceptually, his argument makes sense to me. Also, I've found some information from Microsoft that seems to supports his position. http://technet.microsoft.com/en-us/library/cc966414.aspx In the section titled "3. RAID10 Configuration", showing a configuration in which all 20 disks are allocated to a single RAID 1+0, it states: In this scenario, the I/O parallelism can be used to its fullest by all partitions. Therefore, distribution of I/O workload is among 20 physical spindles instead of four at the partition level. But... every other configuration I've seen suggests physically separating the data and log files onto separate RAIDs. Everything I've found here on Server Fault suggests the same. I understand that a log files will be write heavy, and that data files will be a combination of reads and writes, but does this require that the files be placed onto separate RAIDs instead of a single RAID?

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  • IIS Web Farm Framework servers are automatically set to "unavailable" even when they are healthy... And they never return to the available state!

    - by JohannesH
    I have 2 web farm configurations, one with 2 member servers and one with 3 member servers. I have health monitoring set up on both farms and the monitoring tool reports all servers as being healthy. However after a while all the servers are marked as being "Unavailable" and "Healthy" in the "Monitoring and Management" screen (in the "Servers" screen they are all listed with "Yes" in the "Ready for Load Balancing" column). Viewing the event log on both the web farm controller or any of farm servers doesn't reveal anything interesting. there are no warnings or errors in the period where the servers became unavailable. There are a couple of informational events about the worker process getting shut down due to inactivity but I don't hope this is the cause since that would mean that the farms will die during the night when the load is low. Am I missing something? EDIT: Btw, I think its very odd that the application pool shuts down on the servers since the health monitoring system is polling an aspx page on each server. Shouldn't that keep them going? EDIT2: Now I've also experienced this problem with the RTW version of Web Farm Framework 2.

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  • Sun's JVM instruction speed table

    - by Pindatjuh
    Is there a benchmark available how much relative time each instruction costs in a single-thread, average-case scenario (either with or without JIT compiler), for the JVM (any version) by Sun? If there is not a benchmark already available, how can I get this information? E.g.: TIME iload_1 1 iadd 12 getfield 40 etc. Where getfield is equivalent to 40 iload_1 instructions.

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  • Why is sys+user > real in "time command"?

    - by shadyabhi
    I have a program that uses pthread library to do the matrix multiplication of 500x500 matrix. Each thread calculates 50 rows of the matrix. When I run tiem command:- shadyabhi@shadyabhi-desktop:~$ time ./a.out real 0m0.383s user 0m0.810s sys 0m0.000s shadyabhi@shadyabhi-desktop:~$ How come sys+user is greater than real time?

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  • Python multithreading, How is it using multiple Cores?

    - by Sabirul Mostofa
    I am running a multithreaded application(Python2.7.3) in a Intel(R) Core(TM)2 Duo CPU E7500 @ 2.93GHz. I thought it would be using only one core but using the "top" command I see that the python processes are constantly changing the core no. Enabling "SHOW THREADS" in the top command shows diffrent thread processes working on different cores. Can anyone please explain this? It is bothering me as I know from theory that multithreading is executed on a single core.

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  • How to get the name of global active window using Java??

    - by Ansh J
    I am work an Desktop Application in which i need to save the name of corrently focused or active window name(mozilla firefox, or any other file name) in an text file currently I am using getActiveWindow() method of KeyboardFocusManager which give the name of active Window, or null if the active Window is not a member of the calling thread's context. I want to get the name of Global Active window which corrently user is using. Thanks Ansh J Thanks in advance

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  • How to invoke the getView method in the baseAdapter in Android from another WebService Bean?

    - by greysh
    The adapter in my code as follows, I extends the base adapter: @Override public View getView(final int position, View convertView, ViewGroup parent) { ViewHolder vHolder; // if (convertView == null) { vHolder = new ViewHolder(); convertView = mInflater.inflate(R.layout.home_item, null); vHolder.albumIcon = (ImageView) convertView .findViewById(R.id.albumIcon); try { Bitmap icon = aws.getAlbumImg(itemInfolist.get(position) .getAlbumInfoCol().get(0).getAlbumID(), 0); if (icon != null) { vHolder.albumIcon.setImageBitmap(icon); } else { vHolder.albumIcon.setImageBitmap(BitmapFactory.decodeResource( context.getResources(), R.drawable.album)); } } catch (Exception e) { vHolder.albumIcon.setImageBitmap(BitmapFactory.decodeResource( context.getResources(), R.drawable.album)); } convertView.setTag(vHolder); return convertView; } However, I download the imagine asynchronously, When invoke Bitmap icon = aws.getAlbumImg(itemInfolist.get(position).getAlbumInfoCol().get(0).getAlbumID(), 0); Some pictures which haven't downloaded will use the default image, after these picutures have downloaded in another Web Service Bean, I want the Web Service bean sends a message to invoke the getView method in this adapter in order to implement the auto refresh function. But if I change the Web Service Download Bean as follows,it will cause the exception 03-19 07:46:33.241: ERROR/AndroidRuntime(716): android.view.ViewRoot$CalledFromWrongThreadException: Only the original thread that created a view hierarchy can touch its views. HomeAdapter mHomeAdapter; public AlbumWS(HomeAdapter homeAdapter) { mHomeAdapter = homeAdapter; } And after download, public boolean getAlbumImgWS(final ArrayList albumIDs) { new Thread(new Runnable() { @Override public void run() { // TODO Auto-generated method stub AlbumInfoWS aiws = new AlbumInfoWS(); for (int i = 0; i < albumIDs.size(); ++i) { if (ABSCENTALBUMIMGS.contains(albumIDs.get(i))) { continue; } if (FunctionUtil.isExist(albumIDs.get(i))) { continue; } String urlPath = aiws.getAlbumImage("en_US", Config.IMG_ATTIBUTETYPE, albumIDs.get(i)); boolean ret = FunctionUtil.simpleDownload(Config.HOST + urlPath, "/data/data/com.greysh.amped/img/" + albumIDs.get(i) + ".jpg"); if (!ret) { if (!ABSCENTALBUMIMGS.contains(albumIDs.get(i))) { ABSCENTALBUMIMGS.add(albumIDs.get(i)); } } mHomeAdapter.notifyDataSetChanged(); } } }).start(); return true; }

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  • Threads in C# [Question]

    - by blez
    Thread1/2: do TotalThreads-- on their exit int TotalThreads = 2; void AsyncFunc() { // run thread for Func() } void Func() { // run Thread1 // run Thread2 while(TotalThreads > 0) { /* do nothing */ } // some code } is that bad design?

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  • How to best use GCC with Visual Studio

    - by Oops
    I know this thread http://stackoverflow.com/questions/216025/gcc-with-visual-studio but to me it seems that everything mentioned there is rather outdated and it seems to be the tenor is: don't do it Who knows a better step by step explanation thank you in advance Oops

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  • get return value from 2 threads in C

    - by polslinux
    #include <stdio.h> #include <stdlib.h> #include <pthread.h> #include <stdint.h> #include <inttypes.h> typedef struct tmp_num{ int tmp_1; int tmp_2; }t_num; t_num t_nums; void *num_mezzo_1(void *num_orig); void *num_mezzo_2(void *num_orig); int main(int argc, char *argv[]){ pthread_t thread1, thread2; int tmp=0,rc1,rc2,num; num=atoi(argv[1]); if(num <= 3){ printf("Questo è un numero primo: %d\n", num); exit(0); } if( (rc1=pthread_create( &thread1, NULL, &num_mezzo_1, (void *)&num)) ){ printf("Creazione del thread fallita: %d\n", rc1); exit(1); } if( (rc2=pthread_create( &thread2, NULL, &num_mezzo_2, (void *)&num)) ){ printf("Creazione del thread fallita: %d\n", rc2); exit(1); } t_nums.tmp_1 = 0; t_nums.tmp_2 = 0; pthread_join(thread1, (void **)(&t_nums.tmp_1)); pthread_join(thread2, (void **)(&t_nums.tmp_2)); tmp=t_nums.tmp_1+t_nums.tmp_2; printf("%d %d %d\n", tmp, t_nums.tmp_1, t_nums.tmp_2); if(tmp>2){ printf("Questo NON è un numero primo: %d\n", num); } else{ printf("Questo è un numero primo: %d\n", num); } exit(0); } void *num_mezzo_1(void *num_orig){ int cont_1; int *n_orig=(int *)num_orig; t_nums.tmp_1 = 0; for(cont_1=1; cont_1<=(*n_orig/2); cont_1++){ if((*n_orig % cont_1) == 0){ (t_nums.tmp_1)++; } } pthread_exit((void *)(&t_nums.tmp_1)); return NULL; } void *num_mezzo_2(void *num_orig){ int cont_2; int *n_orig=(int *)num_orig; t_nums.tmp_2 = 0; for(cont_2=((*n_orig/2)+1); cont_2<=*n_orig; cont_2++){ if((*n_orig % cont_2) == 0){ (t_nums.tmp_2)++; } } pthread_exit((void *)(&t_nums.tmp_2)); return NULL; } How this program works: i have to input a number and this program will calculate if it is a prime number or not (i know that it is a bad algorithm but i only need to learn pthread). The problem is that the returned values are too much big.For example if i write "12" the value of tmp tmp_1 tmp_2 into the main are 12590412 6295204 6295208.Why i got those numbers??

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