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  • significance of index name in creating an index (mySQL)

    - by Will
    I've done something like this in order to use on duplicate key update: CREATE UNIQUE INDEX blah on mytable(my_col_to_make_an_index); and its worked just fine. I'm just not sure what the purpose of the index name is -- in this case 'blah'. The stuff I've read says to use one but I can't fathom why. It doesn't seem to be used in queries, although I can see it if I export the schema. So ... what purpose does the index name serve? If it helps the line in the CREATE TABLE ends up looking like: UNIQUE KEY `clothID` (`clothID`)

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  • MySQL : Calculate business day difference between two dates column

    - by yokoyoko
    My sql query returns back two columns, first column is "date created" and second column is "date updated", first column has a prior timestamp with respect to second column. I need to add a third column which can display business day hrs (9:00am to 5:00pm) response i.e. if date created is 2012-01-01 09:00:20 and "dated updated" is 4:00pm same day then third column should display 7 hrs If date created is 2012-01-01 16:00:20 (4:00pm) and "date updated" is 10:00m on 2012:01:02 (2nd Jan) then third column should display 2 hrs. It should exclude Saturday and Sunday. Can you please suggest appropriate SQL query for this.

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  • Mysql insert into 2 tables

    - by Spidfire
    I want to make a insert into 2 tables visits: visit_id int | card_id int registration: registration_id int | type enum('in','out') | timestamp int | visit_id int i want something like: INSERT INTO `visits` as v ,`registration` as v (v.`visit_id`,v.`card_id`,r.`registration_id`, r.`type`, r.`timestamp`, r.`visit_id`) VALUES (NULL, 12131141,NULL, UNIX_TIMESTAMP(), v.`visit_id`); I wonder if its possible

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  • problem in using while loop in php&mysql

    - by Mac Taylor
    hey guys im using a while loop to show my latest forum topics now i need to count some fields either I'm trying to do it in one query and here is my code : $result = $db->sql_query("SELECT t.*,p.*, SUM(t.topic_approved='1') AS Amount_Of_Topics, SUM(t.topic_views) AS Amount_Of_Topic_Views, SUM(t.topic_replies) AS Amount_Of_Topic_Replies, SUM(p.post_approved ='1') AS Amount_Of_Posts FROM bb3topics t left join bb3posts p ON t.topic_id=p.topic_id ORDER BY t.topic_last_post_id DESC LIMIT 10 " ); while( $row = $db->sql_fetchrow($result) ) { problem : this code shows only one forum topic and not the rest , but if i remove sum() part from it , then it shows the rest is there anything wrong with my query code ?!

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  • MySQL count/sum fields

    - by Conor H
    Hi There, What I am trying to achieve is a report on daily financial transactions. With my SQL query I would like to count the total number of cash transactions, the total cash value and the same for checks. I only want to do this for a specified date. Here is a snippet of the query that I am having trouble with. These sum and count commands are processing all the data in the table and not for the selected date. (SELECT SUM(amount) FROM TRANSACTION WHERE payment_type.name = 'cash') AS total_cash, (SELECT COUNT(*) FROM TRANSACTION WHERE payment_type.name = 'cash') AS total_cash_transactions Sorry if I havent posted enough detail as I haven't time. If you need more info just ask.. Cheers.

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  • Removing groups of similar records in MySQL query

    - by user1182155
    I'm trying to wrap my head around this... (it may be simple, been a long day!) I have a database with sometimes multiple similar records... ie. Apples 2008-09-03 Apples 2012-01-01 Apples 2013-10-24 Oranges 2012-01-04 What I need to do is do a query that will show only records that haven't been updated today... So in this case, since Apples has an entry that was updated today, none of the records for the Apples should appear in the results. Oranges should be the only record it returns. I have a query similar to this... SELECT fruit FROM fruitnames where date < CURDATE() Which works to remove the record that was updated today... But it keeps the other records for Apples (obviously)... How would I remove those results as well?

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  • How to get this done in mysql?

    - by bala3569
    Consider i have a registartion table and there is field prefLocationId and it contains value like this 1,2,3,2,1,4 and so many.... And i have a table prefLocation which looks like this Id LocationName 1 Chennai 2 Mumbai 3 Kolkatta 4 Delhi and i want to select record of users and show values like Chennai,Mumbai,Kolkatta,Mumbai,Chennai,Delhi and so on...

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  • MySQL Query - WHERE and IF?

    - by Prash
    I'm not quite sure how to right this query. Basically, I'm going to have a table with two columns (OS and country_code) - more columns too, but those are the conditional ones. These will be either set to 0 for all, or specific ones, separated by commas. Now, what I'm trying achieve is pull data from the table if the OS and country_code = 0, or if they contain matching data (separated by commas). Then, I have a column for time. I want to select rows where the time is GREATER than the time column, unless the column time_t is set to false, in which case this shouldn't matter. I hope I explained it right? This is what I kind of have so far: $get = $db->prepare("SELECT * FROM commands WHERE country_code = 0 OR country_code LIKE :country_code AND OS = 0 OR OS LIKE :OS AND IF (time_t = 1, expiry > NOW()) "); $get->execute(array( ':country_code' => "%{$data['country_code']}%", ':OS' => "%{$data['OS']}%" ));

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  • Help with PHPExcel Library and mySQL data from a table

    - by user547363
    Hello! Everyone.. I have this script $query = "SELECT id,last_name,first_name FROM users WHERE tmima_id='6'"; $result = @mysql_query($query); while($row = mysql_fetch_array($result)) { $i = 3; $emp_id = $row['id']; $cell = 'A'.$i; $objPHPExcel->setActiveSheetIndex(0) ->setCellValue($cell, $row['last_name']. $row['first_name']); $i++; } But in the .xls file it prints only one user. Why id doesnt print all of the users ? W Thanks in advance.

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  • mysql split value from one field to two

    - by tsiger
    Hello, I 've got a table field (membername) which contains both the last name and the first name of users. Is it possible to split those into 2 fields (memberfirst - memberlast)? All the records have this format "Firstname Lastname" (without quotes and a space in between).

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  • MySql product\tag query optimisation - please help!

    - by Nige
    Hi There I have an sql query i am struggling to optimise. It basically is used to pull back products for a shopping cart. The products each have tags attached using a many to many table product_tag and also i pull back a store name from a separate store table. Im using group_concat to get a list of tags for the display (this is why i have the strange groupby orderby clauses at the bottom) and i need to order by dateadded, showing the latest scheduled product first. Here is the query.... SELECT products.*, stores.name, GROUP_CONCAT(tags.taglabel ORDER BY tags.id ASC SEPARATOR " ") taglist FROM (products) JOIN product_tag ON products.id=product_tag.productid JOIN tags ON tags.id=product_tag.tagid JOIN stores ON products.cid=stores.siteid WHERE dateadded < '2010-05-28 07:55:41' GROUP BY products.id ASC ORDER BY products.dateadded DESC LIMIT 2 Unfortunately even with a small set of data (3 tags and about 12 products) the query is taking 00.0034 seconds to run. Eventually i want to have about 2000 products and 50 tagsin this system (im guessing this will be very slooooow). Here is the ExplainSql... id|select_type|table|type|possible_keys|key|key_len|ref|rows|Extra 1|SIMPLE|tags|ALL|PRIMARY|NULL|NULL|NULL|4|Using temporary; Using filesort 1|SIMPLE|product_tag|ref|tagid,productid|tagid|4|cs_final.tags.id|2| 1|SIMPLE|products|eq_ref|PRIMARY,cid|PRIMARY|4|cs_final.product_tag.productid|1|Using where 1|SIMPLE|stores|ALL|siteid|NULL|NULL|NULL|7|Using where; Using join buffer Can anyone help?

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  • MySQL select date, join statistic data - how?

    - by Webnet
    I have some statistics I need to report on a monthly basis. I need my query to return 0's for statistics which aren't there. The only way I know to do this is to use SQL to generate a list of days within the specified time period and LEFT JOIN the statistic data that I need to report on. Problem is.... I've never not selected from a table like that... how do I do that?

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  • Question about Benchmark function in Mysql ( Incredible results ).

    - by xRobot
    I have 2 tables: author with 3 millions of rows. book with 20 miles rows. . So I have benchmarked this query with a join: SELECT BENCHMARK(100000000, 'SELECT book.title, author.name FROM `book` , `author` WHERE book.id = author.book_id ') And this is the result: Query took 0.7438 sec ONLY 0.7438 seconds for 100 millions of query with a join ??? Do I make some mistakes or this is the right result ?

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  • mysql :ordering table with day names

    - by Meko
    Hi.I am trying to get day of names with and correct order like Monday ,Tuesday.. But in my table I have records that after Monday comes Friday or I have Thursday between two Tuesday .I want to order them like Monday ,Monday ,Tuesday ,Tuesday, Wednesday so on .But I don`t want to group them. I used this query but it does not make order select Day_Name from mydb.schedule where Room_NO=(510) And Week_NO =(1) it outputs Monday Monday Tuesday Wednesday Wednesday Tuesday Thursday Thursday Thursday how can I correct it?

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  • MySQL: Order by time (MM:SS)?

    - by Shpigford
    I'm currently storing various metadata about videos and one of those bits of data is the length of a video. So if a video is 10 minutes 35 seconds long, it's saved as "10:35" in the database. But what I'd like to do is retrieve a listing of videos by length (longest first, shortest last). The problem I'm having is that if a video is "2:56", it's coming up as longest because the number 2 is more than the number 1 in. So, how can I order data based on that length field so that "10:35" is recognized as being longer than "2:56" (as per my example)?

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  • MySQL: Return grouped fields where the group is not empty, effeciently

    - by Ryan Badour
    In one statement I'm trying to group rows of one table by joining to another table. I want to only get grouped rows where their grouped result is not empty. Ex. Items and Categories SELECT Category.id FROM Item, Category WHERE Category.id = Item.categoryId GROUP BY Category.id HAVING COUNT(Item.id) > 0 The above query gives me the results that I want but this is slow, since it has to count all the rows grouped by Category.id. What's a more effecient way? I was trying to do a Group By LIMIT to only retrieve one row per group. But my attempts failed horribly. Any idea how I can do this? Thanks

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  • convert mysql code to codeigniter

    - by Jethro Tamares Doble
    How can i convert this code into an acceptable codeigniter code: mysql_select_db($database_connection_ched, $connection_ched); $query_Institutions = "SELECT * FROM tb_institutional_profile ORDER BY tb_institutional_profile.institution_name ASC"; $Institutions = mysql_query($query_Institutions, $connection_ched) or die(mysql_error()); $row_Institutions = mysql_fetch_assoc($Institutions); $totalRows_Institutions = mysql_num_rows($Institutions); <td width="192"><select name="institution_id"> <?php do { <option value="<?php echo $row_Institutions['institution_id']?>" ><?php echo $row_Institutions['institution_name']?></option> <?php } while ($row_Institutions = mysql_fetch_assoc($Institutions)); ?> </select></td>

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  • Multiple LIKE, OR MySql Queries Match

    - by Codex73
    Search for: 'chemist' Problem: query which will match a string like 'onechemist' but not 'chemist'. SELECT id,name FROM `records` WHERE name LIKE '%". mysql_real_escape_string($q) ."%' This alternate try won't work: SELECT id,name FROM `records` WHERE name LIKE '%". mysql_real_escape_string($q) ."%' OR name LIKE '". mysql_real_escape_string($q) ."%' OR name LIKE '%". mysql_real_escape_string($q) ."' How could I compile the above into one single query that will match any field which has the string or optimize the query into a better expression?

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  • MySQL look for missing ratings

    - by Dustin
    Hopefully I can ask this without being confusing. I am a photographer and I am having some of our clients rate pictures that we have taken. We have hundreds of pictures in our portfolio that they may be rating. What I want to do is ask our clients to rate pictures again, but only show them the pictures they haven't yet rated. I currently have three tables: one that stores the actual ratings, one that stores the pictures (or location of each picture), and one that stores the information about the rater. I'm using codeigniter for my db management, if that helps at all. What I have so far is this: "SELECT * FROM ratings LEFT JOIN portfolio ON ratings.portfolioid = portfolio.portfolioid" This will give me a row for each rating, but won't show me where a rating is missing for a picture. Thanks in advance!

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  • changing existing duplicate entries in mysql

    - by Mladen
    sorry for the (probably) noob question, but I', new at this stuff. i have a table that has column 'position', and I want to, when inserting a new row, change positions of every row that has position lower than row that is inserted. for example, if I add row with position 4, if there is a duplicate, it should become 5, 5 should shift to 6 and so on... also, is there a way to get highest value for column besides testing it in every row via php?

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  • Multidimensional Array To Mysql Codeigniter

    - by rochellecanale
    A little help how can I create an input query using this array? Or how can I pass it in the table? my table layout sample is this: sales_table id | product_name | price | qty | subtotal This is derived from the var_dump() function. Here is my code in array //array code from unserialized function $products = unserialize($this->session->userdata('product_list')); //This is the output. Array ( [2] => Array ( [id] => 2 [product_name] => NOKIA 5110 [product_desc] => Cellphone [product_price] => 500.00 [product_qty] => 1 [product_amount] => 500 [product_code] => NOKI2012-84353 ) [3] => Array ( [id] => 3 [product_name] => HP IPAQ RW6828 [product_desc] => Cellphone [product_price] => 1500.00 [product_qty] => 1 [product_amount] => 1500 [product_code] => HP I2012-08386 ) )

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