Search Results

Search found 63877 results on 2556 pages for 'mysql error 1452'.

Page 220/2556 | < Previous Page | 216 217 218 219 220 221 222 223 224 225 226 227  | Next Page >

  • comparing rows on a mysql table

    - by user311324
    Ok here's the deal I got one table with a bunch of client information. Each client makes up to one purchase a year which is represented by an individual row. there's a column for the year and there's a column the contains a unique identifier for each client. What I need to do is to construct a query that takes last year and this year and shows me which clients were here made a purchase last year but not make a purchase this year. I also need to build a query that shows me which clients did not make a purchase last year and the year before last but did make a purchase this year.

    Read the article

  • mysql bug database error

    - by user963499
    Why is that when I search a row in my database, it ended up 0 results? In fact, there are rows that meet my search criterion when I view them manually, but the search button doesnt work as it is. Heres how you can see there are rows that have '0000-00-00 00:00:00' in them, but when I used the search feature, it ended up like this: take note that Im entering it in the right field which is 'AcctStopTime'. TIA

    Read the article

  • MySQL LEFT JOIN issue with three WHERE statements

    - by jhat
    I am building a note taking app for myself with tag filtering functions, but am having an issue when trying to grab notes with the tags. The tag filter needs to use AND not IN, because it will help better narrow down what I am looking for. My tables are configured like this: + notes note_id | note_title | note_uid + tags tag_id | tag_title + notes_tags nt_id | nt_note_id | nt_tag_id The notes_tags table keeps track of all notes' tags. I am not worried about returning any information about tags, so here is an example LEFT JOIN I am using currently to only get notes with only 1 tag. SELECT * FROM notes_tags LEFT JOIN notes ON note_id = nt_note_id WHERE note_uid IN ( 1 ) AND nt_tag_id = 10 This query runs perfect, it grabs all of the notes with that single tag. However, I am having issues "pinpointing" my notes using a query like this: SELECT * FROM notes_tags LEFT JOIN notes ON note_id = nt_note_id WHERE note_uid IN ( 1 ) AND nt_tag_id = 10 AND nt_tag_id = 11 What am I doing wrong with the syntax?

    Read the article

  • mysql - How select a akin records?

    - by zeroonea
    I have a table with name varchar address varchar country varchar city varchar ..... to store address of location example: name|address|country HaLong hotel|156 blahblah street|Vietnam Hotel Ha Long|156 blah blah|Vietnam Two rows above is duplicate data. I have a form, when user submit new location. The code need to find akin records to give a message (ex: This location already in db, use it or create new?) How to make a query to get akin record like this?

    Read the article

  • Possibly simple PHP/MYSQL issue with retrieving and showing data

    - by envoys
    I have been racking my brains over this for a while now. Here is the data i have in the sql data base as an example: ID | TYPE | DATA 1 | TXT | TEST 2 | PHP | php 3 | JS | JAVASCRIPT That is just an example, there are multiple listing for TXT, PHP and JS throughout the table. What I want to do is retrive all the data and display it all into separate drop down/select boxes. Meaning, select box one would list all data with type TXT, select box two would list all data with type PHP and select box 3 would list all data with type JS. The only way I have came about doing this is doing individual sql queries for each different type. I know there is a way to do it all in 1 query and then display it the way I want to but I just can't seem to figure out how and I know its going to drive me nuts when someone helps and I see just how they did it. Thanks for the input.

    Read the article

  • Why my mysql DISTINCT doesn't work ?

    - by belaz
    Hello, Why the two query below return duplicate member_id and not the third ? i need the second query to work with distinct. Anytime i run a GROUP BY, this query is incredibly slow and the resultset doesn't return the same value as distinct (the value is wrong). SELECT member_id, id FROM ( SELECT * FROM table1 ORDER BY created_at desc ) as u LIMIT 5 +-----------+--------+ | member_id | id | +-----------+--------+ | 11333 | 313095 | | 141831 | 313094 | | 141831 | 313093 | | 12013 | 313092 | | 60821 | 313091 | +-----------+--------+ SELECT distinct member_id, id FROM ( SELECT * FROM table1 ORDER BY created_at desc ) as u LIMIT 5 +-----------+--------+ | member_id | id | +-----------+--------+ | 11333 | 313095 | | 141831 | 313094 | | 141831 | 313093 | | 12013 | 313092 | | 60821 | 313091 | +-----------+--------+ SELECT distinct member_id FROM ( SELECT * FROM table1 ORDER BY created_at desc ) as u LIMIT 5 +-----------+ | member_id | +-----------+ | 11333 | | 141831 | | 12013 | | 60821 | | 64980 | +-----------+ my table sample CREATE TABLE `table1` ( `id` int(11) NOT NULL AUTO_INCREMENT, `member_id` int(11) NOT NULL, `s_type_id` int(11) NOT NULL, `created_at` datetime DEFAULT NULL, PRIMARY KEY (`id`), KEY `s_FI_1` (`member_id`), KEY `s_FI_2` (`s_type_id`) ) ENGINE=InnoDB AUTO_INCREMENT=313096 DEFAULT CHARSET=utf8;

    Read the article

  • MySQL: Matching inexact values using "ON"

    - by Brad
    I'm way out of my league here... I have a mapping table (table1) to assign particular values (value) to a whole number (map_nu). My second table (table2), is a collection of averages (avg) (I couldn't figure out how to properly make a markdown table, please feel free to edit!) table1: table2: (value)(Map_nu) (avg) ---- ----- 1 1 1.111 1.045 2 1.2 1.09 3 1.33333 1.135 4 1 1.18 5 1.389 1.225 6 1.42 1.27 7 1.07 1.315 8 1.36 9 1.405 10 I need to find a way to match the averages from table2 to the closest value in table1. It only need to match to the 2 digit past the decimal, so I've added the Truncated function SELECT map_nu FROM `table1` JOIN table2 ON TRUNCATE(table1.value,2)=TRUNCATE(table2.avg,2) I still miss the values that don't match the averages exactly. Is there a way to pick the nearest truncated value? Thanks!

    Read the article

  • please suggest mysql query for this

    - by I Like PHP
    I HAVE TWO TABLES shown below table_joining id join_id(PK) transfer_id(FK) unit_id transfer_date joining_date 1 j_1 t_1 u_1 2010-06-05 2010-03-05 2 j_2 t_2 u_3 2010-05-10 2010-03-10 3 j_3 t_3 u_6 2010-04-10 2010-01-01 4 j_5 NULL u_3 NULL 2010-06-05 5 j_6 NULL u_4 NULL 2010-05-05 table_transfer id transfer_id(PK) pastUnitId futureUnitId effective_transfer_date 1 t_1 u_3 u_1 2010-06-05 2 t_2 u_6 u_1 2010-05-10 3 t_3 u_5 u_3 2010-04-10 now i want to know total employee detalis( using join_id) which are currently working on unit u_3 . means i want only join_id j_1 (has transfered but effective_transfer_date is future date, right now in u_3) j_2 ( tansfered and right now in `u_3` bcoz effective_transfer_date has been passed) j_6 ( right now in `u_3` and never transfered) what i need to take care of below steps( as far as i know ) <1> first need to check from table_joining whether transfer_id is NULL or not <2> if transfer_id= is NULL then see unit_id=u_3 where joining_date <=CURDATE() ( means that person already joined u_3) <3> if transfer_id is NOT NULL then go to table_transfer using transfer_id (foreign key reference) <4> now see the effective_transfer_date regrading that transfer_id whether effective_transfer_date<=CURDATE() <5> if transfer date has been passed(means transfer has been done) then return futureUnitID otherwise return pastUnitID i used two separate query but don't know how to join those query?? for step <1 ans <2 SELECT unit_id FROM table_joining WHERE joining_date<=CURDATE() AND transfer_id IS NULL AND unit_id='u_3' for step<5 SELECT IF(effective_transfer_date <= CURDATE(),futureUnitId,pastUnitId) AS currentUnitID FROM table_transfer // here how do we select only those rows which have currentUnitID='u_3' ?? please guide me the process?? i m just confused with JOINS. i think using LEFT JOIN can return the data i need, or if we use subquery value to main query? but i m not getting how to implement ...please help me. Thanks for helping me alwayz

    Read the article

  • MySQL using function IN with variable

    - by misanov
    I have problem querying table with variable in IN function. SELECT s.date, (SELECT GROUP_CONCAT(value) FROM value WHERE id_value IN(s.ref_values) ) AS vals FROM stats s ORDER BY s.date DESC LIMIT 1 Where s.ref_values is '12,22,54,15'. I get only one return for first number (12). When I insert that value directly in IN(12,22,54,15) it finds all 4. So, there must be problem with using variable in IN. What am I doing wrong?

    Read the article

  • Stop Submit With empty and error Input Values Using PHP

    - by user3615781
    I am using the following code for sending data to database, but it sends the data even the values of the fields are incorrect or empty. So can anyone help me solve this by using php? Here is my code: <?php //Connecting to sql db $connect = mysqli_connect("localhost","root","","form"); /* check connection */ if (!$connect) { die('Connect Error: ' . mysqli_connect_error()); } //Sending data to sql db $result = mysqli_query($connect,"INSERT INTO students(name,email,website,comment,gender) VALUES('$name','$email','$website','$comment','$gender')"); if (!$result) { die('Query Error:'. mysqli_error($connect)); } ?>

    Read the article

  • MySQL Joining three tables

    - by text
    I am doing a query with three tables, the problem was one table has many occurrences of id of another. sample data: users: id answers: id:1 user_answer :1 id:1 user_answer :2 id:1 user_answer :3 Questions: id:1 answers :answer description id:2 answers :answer description id:3 answers :answer description How can I get all user information and all answer and its description, I used GROUP by user.id but it only returns only one answer. I want to return something like this list all of users answer: Name Q1 Q2 USERNAME ans1,ans2 ans1,ans2 comma separated description of answer here

    Read the article

  • Group mysql query by 15 min intervals

    - by gsiener
    I've got a monitoring system that is collecting data every n seconds (n ~=10 but varies). I'd like to aggregate the collected data by 15 minute intervals. Is there a way to corral the timestamp column into 15 minute chunks to allow for grouping to work?

    Read the article

  • MySQL - generate numbers for a group of results

    - by FreeIX
    I need a query to return this result: +---------+-----+-------+ | ref_nid | nid | delta | +---------+-----+-------+ | AA | 97 | 1 | | BB | 97 | 2 | | CC | 97 | 3 | | DD | 98 | 1 | | EE | 98 | 2 | | FF | 98 | 3 | +---------+-----+-------+ However, I do not have the delta column. I need to generate it for each nid group. In other words, I need an auto incremented number for each group of the result.

    Read the article

  • PHP mySQL query's and PHP Variables

    - by jon
    I'm trying to make an OO Login system for a project I'm working on, and am having trouble with inserting variables into the query strings. In the code below, if I replace "$TBL_NAME" with the actual table name it works. Why isn't $TBL_NAME translating to the value of $TBL_NAME? class UserDB { private $TBL_NAME = "users"; public static function CheckLogin($username, $password) { Database::Connect(); $username = stripslashes($username); $password = stripslashes($password); $username = mysql_real_escape_string($username); $password = mysql_real_escape_string($password); $sql="SELECT uid FROM $TBL_NAME WHERE username='$username' AND password='$password' "; $result =mysql_query($sql); $count=mysql_num_rows($result); if ($count==1) return true; else return false; } The Query is returning false.

    Read the article

  • Problem with multi-table MySQL query

    - by mahle
    I have 3 tables. Here is the relevant information needed for each. items prod_id order_id item_qty orders order_id order_date order_status acct_id accounts acct_id is_wholesale items is linked to order by the order_id and orders is linked to accounts via acct_id I need to sum item_qty for all items where prod_id=464 and the order stats is not 5 and where the is_wholesale is 0 and the order_date is between two dates. Im struggling with this and would appreciate any help. Here is what I have but it's not working correctly: SELECT SUM(items.item_qty) as qty FROM items LEFT JOIN orders ON orders.order_id = items.order_id LEFT JOIN accounts on orders.acct_id = accounts.acct_id WHERE items.prod_id =451 AND orders.order_date >= '$from_date' AND orders.order_date <= '$to_date' AND orders.order_status <>5 AND accounts.is_wholesale=0; Again, any help would be greatly appreciated!

    Read the article

  • Check if the current date is between two dates + mysql select query

    - by kj7
    I have following table : id dateStart dateEnd active 1 2012-11-12 2012-12-31 0 2 2012-11-12 2012-12-31 0 I want to compare todays date in between dateStart and dateEnd. Following is my query for this : $todaysDate="2012-26-11"; $db = Zend_Registry::get("db"); $result = $db->fetchAll("SELECT * FROM `table` WHERE active=0 AND {$todaysDate} between dateStart and dateEnd"); return $result; But its not working. Any solution. Thanks in advance.

    Read the article

  • How do I mirror a MySQL database?

    - by user366133
    I'm running two load balanced servers for one website, and I'd like the databases to be synchronized. Queries may be run on either of the two servers because they are both production sites, so the replication can't just work one way. It doesn't have to be in real-time, just fairly accurate so people don't notice a difference when they get switched to a different server.

    Read the article

  • how to do this in MySql Query??

    - by deep
    ID NAME AMT 1 Name1 1000 2 Name2 500 3 Name3 3000 4 Name1 5000 5 Name2 2000 6 Name1 3000 consider above table as sample. am having a problem in my sql query, Am using like this. Select name,amt from sample where amt between 1000 and 5000 it returns all the values in the table between 1000 and 5000, instead I want to get maximum amount record for each name i.e., 3 name3 3000 4 name1 5000 5 name2 2000

    Read the article

  • MYSQL: COUNT with GROUP BY, LEFT JOIN and WHERE clause doesn't return zero values

    - by Paul Norman
    Hi guys, thanks in advance for any help on this topic! I'm sure this has a very simply answer, but I can't seem to find it (not sure what to search on!). A standard count / group by query may look like this: SELECT COUNT(`t2`.`name`) FROM `table_1` `t1` LEFT JOIN `table_2` `t2` ON `t1`.`key_id` = `t2`.`key_id` GROUP BY `t1`.`any_col` and this works as expected, returning 0 if no rows are found. So does: SELECT COUNT(`t2`.`name`) FROM `table_1` `t1` LEFT JOIN `table_2` `t2` ON `t1`.`key_id` = `t2`.`key_id` WHERE `t1`.`another_column` = 123 However: SELECT COUNT(`t2`.`name`) FROM `table_1` `t1` LEFT JOIN `table_2` `t2` ON `t1`.`key_id` = `t2`.`key_id` WHERE `t1`.`another_column` = 123 GROUP BY `t1`.`any_col` only works if there is at least one row in table_1 and fails miserably returning an empty result set if there are zero rows. I would really like this to return 0! Anyone enlighten me on this? Beer can be provided in exchange if you are in London ;-)

    Read the article

  • mysql error dont understand what it is saying

    - by sea_1987
    Cannot add or update a child row: a foreign key constraint fails (`mydb`.`job_listing_has_employer_details`, CONSTRAINT `job_listing_has_employer_details_ibfk_2` FOREIGN KEY (`employer_details_id`) REFERENCES `employer_details` (`id`)) INSERT INTO `job_listing_has_employer_details` (`job_listing_id`, `employer_details_id`) VALUES (6, '5') What does this mean? The two ID's I am inserting into the table exsist.

    Read the article

  • Confusing alias mySQL

    - by Taylor
    I keep getting the same number outputted for the Total Sales, Minimum Sale, Largest Sale and Average Sale. The Total Invoices is working perfectly, but I cant seem to figure out how to fix the other ones. Here's the query: SELECT SUM( b.`Number of Invoices`) AS `Total Invoices`, SUM( b.`Total Customer Purchases`) AS `Total Sales`, MIN( b.`Total Customer Purchases`) AS `Minimum Sale`, MAX( b.`Total Customer Purchases`) AS `Largest Sale`, AVG( b.`Total Customer Purchases`) AS `Average Sale` FROM (SELECT a.CUS_CODE, COUNT(a.`Number of Invoices`) AS `Number of Invoices`, SUM(a.`Invoice Total`) AS `Total Customer Purchases` FROM ( SELECT CUS_CODE, LINE.INV_NUMBER AS `Number of Invoices`, SUM(LINE.LINE_UNITS * LINE.LINE_PRICE) AS `Invoice Total` FROM `ttriggs`.`INVOICE`, `ttriggs`.`LINE` WHERE INVOICE.INV_NUMBER = LINE.INV_NUMBER GROUP BY CUS_CODE, LINE.INV_NUMBER ) a ) b GROUP BY b.CUS_CODE; Heres the database diagram https://www.dropbox.com/s/b8cy5l29jwh8lyv/1_edit.jpg Subquery generates: CUS_CODE 10011 Number of Invoices 8 Total Customer Purchases 1119.03 Any help is greatly appreciated, Thanks!

    Read the article

  • MySQL: Query Cacheing (How do I use memcache?)

    - by Rachel
    I have an query like: SELECT id as OfferId FROM offers WHERE concat(partycode, connectioncode) = ? AND CURDATE() BETWEEN offer_start_date AND offer_end_date AND id IN ("121211, 123341,151512,5145626 "); Now I want to cache the results of this query using memcache and so my question is How can I cache an query using memcache. I am currently using CURDATE() which cannot be used if we want to implement caching and so how can I get current date functionality without using CURDATE() function ?

    Read the article

< Previous Page | 216 217 218 219 220 221 222 223 224 225 226 227  | Next Page >