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  • Is external JavaScript source available to scripting context inside HTML page?

    - by John K
    When an external JavaScript file is referenced, <script type="text/javascript" src="js/jquery-1.4.4.min.js"></script> is the JavaScript source (lines of code before interpretation) available from the DOM or window context in the current HTML page? I mean by using only standard JavaScript without any installed components or tools. I know tools like Firebug trace into external source but it's installed on the platform and likely has special ability outside the context of the browser sandbox.

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  • How do call this symbolic code transformation ?

    - by erric
    Hi, I often cross this kind of code transformation (or even mathematical transformation) (python example, but applies to any language) I've go a function def f(x): return x I use it into another one. def g(x): return f(x)*f(x) print g(2) leads to 4 But I want to remove the functional dependency, and I change the function g into def g(f): return f*f print g( f(2) ) leads to 4 too How do you call this kind of transformation, locally turning a function into a scalar ?

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  • regex for zip-code

    - by Monu
    I need Regex which can satisfy all my three condtions for zip-code. E.g- 12345 12345-6789 12345 1234 Any pointers and suggestion would be much appreciated. Thanks !

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  • Code is not running on .click of hyperlink

    - by coffeeaddict
    Code is not running on .click when I have this: $(".cancel").click(function() { alert("got here"); $(this).closest(":dialog").dialog("close"); }); <a class="cancel" href=""><img src="images/cancelButton.gif" border="0" /></a> It's got to be something stupid, but I cannot see it.

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  • comment code in netbeans?

    - by ajsie
    a while ago i could comment any code in php with netbeans like this: /* * * */ I just typed /* ENTER and netbeans gave me that lines above. then when i typed @ it gave me a full list of all available tags (author, param and so on). i reinstalled my mac and since then it hasnt worked. someone knows why and how i can activate it? i installed the netbeans for php only.

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  • Taking over someone else's code

    - by tom d
    I am taking over someone elses code. What are some good ways to learn what that programmer did as quickly as possible? I have been running it, stepping through it and looking at the callstack. What else can I do? Sorry I forgot to mention, but there is little documentation and I have been trying to fix simple problems. Thanks!

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  • What is wrong in this c++ code?

    - by narayanpatra
    Why this coder do not show error #include <iostream> int main() { using namespace std; unsigned short int myInt = 99; unsigned short int * pMark = 0; cout << myInt << endl; pMark = &myInt; *pMark = 11; cout << "*pMark:\t" << *pMark << "\nmyInt:\t" << myInt << endl; return 0; } But this one shows : #include<iostream> using namespace std; int addnumber(int *p, int *q){ cout << *p = 12 << endl; cout << *q = 14 << endl; } #include<iostream> using namespace std; int addnumber(int *p, int *q){ cout << *p = 12 << endl; cout << *q = 14 << endl; } int main() { int i , j; cout << "enter the value of first number"; cin >> i; cout << "enter the value of second number"; cin >> j; addnumber(&i, &j); cout << i << endl; cout << j << endl; } In both the code snippets, I am assigning *pointer=somevalue. In first code it do not show any error but it shows error in the line cout << *p = 12 << endl; cout << *q = 14 << endl; What mistake I am doing ?

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  • Example of application to design with fingers (source code)

    - by STD
    Hi, i'm new user about this interesting forum! I want start develop application for android and before starting i want learn about some android feature... the first android feature is how to correlate finger motion in screen with java... Exist some source code that show how to realize application to draw with finger in android screen? can you suggest me where donwload it? thanks

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  • what is the output of this code?

    - by user329820
    Hi,I have wriiten a part of code for you and I want to know the output ,I need your help because there is not any body for helping me also I think that the out put is A ,is this correct? thanks. declare @v1 varchar(20),@v2 varchar(20) select @v1 = 'NULL' if @v1 is null and @v2 is null select 'A' else select 'B'

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  • Safe vs Unsafe code

    - by Lumpy
    Read this question today about safe and unsafe code I then read about it in MSDN but I still don't understand it. Why would you want to use pointers in C#? Is this purely for speed?

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