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  • Get Specific part of a String in Javascript

    - by streetparade
    I have a string containing something like this "Hello bla bla bla bla ok, once more bla können. // this is static: it doesn't change This is a text, this also a text. // this is dynamically added text it can change each time My name mysurename // this is also static text www.blabla.com " Now I have content and I have to get the first part of the string and the third part, I want to be able to have 3 parts, I think I have to split it using something like split(); string1 = "Hello bla bla bla bla ok, once more bla können.; string2 = ""; // i have this part string3 ="My name mysurename"; If it helps the first part ends with "können. " and the third part ends with the url above // its a fictional URL

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  • regexp uppercase to lowercase

    - by luccio
    Hi, is it possible to transform regexp pattern match to lowercase? var pattern:RegExp; var str:String = "HI guys"; pattern = /([A-Z]+)/g; str = str.replace(pattern, thisShouldBeLowerCase); Output should look like this: "hi guys" Thx

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  • Simple regex split

    - by user1383058
    I have the following string: string = "Peter Pan, Pete Sampras; Little Pete" And I need to split it up by name: split_string = ["Peter Pan", "Pete Sampras", "Little Pete"] I am trying to use re.findall but am having a bit of trouble with it: print re.findall(r'[,;]', string) [";", ";", ";"] What am I doing wrong here and how would I properly use re.findall here or an equivalent to split up the string?

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  • Python code to use a regular expression to make sure a string is alphanumeric plus . - _

    - by Warlax
    Hi, I looked and searched and couldn't find what I needed although I think it should be simple (if you have any Python experience, which I don't). Given a string, I want to verify, in Python, that it contains ONLY alphanumeric characters: a-zA-Z0-9 and . _ - examples: Accepted: bill-gates Steve_Jobs Micro.soft Rejected: Bill gates -- no spaces allowed [email protected] -- @ is not alphanumeric I'm trying to use: if re.match("^[a-zA-Z0-9_.-]+$", username) == True: But that doesn't seem to do the job...

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  • regular expression or replace function in where clause of a mysql query.

    - by Salil
    Hi All, I write a mysql query select * from table where name like '%salil%' which works fine but it will no return records with name 'sal-il', 'sa@lil'. So i want a query something like below select * from table where remove_special_character_from(name) like '%salil%' remove_special_character_from(name) is a mysql method or a regular expression which remove all the special characters from name before like executed.

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  • MySQL REGEXP: matching blank entries

    - by Erwin Paglinawan
    Hi, I have this SQL condition that is supposed to retrieve all rows that satisfy the given regexp condition: country REGEXP ('^(USA|Italy|France)$') However, I need to add a pattern for retrieving all blank country values. Currently I am using this condition country REGEXP ('^(USA|Italy|France)$') OR country = "" How can achieve the same effect without having to include the OR clause? Thanks, Erwin

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  • case-insensitive regexp match on non-english text in perl cgi script

    - by jonny
    ok. I have list of catalog paths and need to filter out some of them. Match pattern comes in non-Unicode encoding. Tried following: require 5.004; use POSIX qw(locale_h); my $old_locale = setlocale(LC_ALL); setlocale(LC_ALL, "ru_RU.cp1251"); @{$data -> {doc_folder_rights}} = grep { $_->{doc_folder} =~/$_REQUEST{q}/i; # catalog path pattern in $_REQUEST{q} } @{$data -> {doc_folder_rights}}; setlocale(LC_ALL, $old_locale); What I need is case-insensitive regexp pattern matching when pattern contains russsian letters.

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  • How to start a marquee with JavaScript based on user input?

    - by APShredder
    Hello everybody. I am trying to use JavaScript to start a marquee when a user puts their name into a textbox and then clicks a button. I've got an idea as to how to do it, but my script never fully works. Any help is appreciated! Here's what I have so far: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <title></title> <script type="text/javascript"> function StartMarquee() { var text = document.getElementById(namebox); if (text != null) { document.write("<marquee behavior='scroll' direction='right'>Hello " + text + "!</marquee>"); } else { alert("Enter your name first!!!"); } } </script> </head> <body> <table style="margin:0px auto 0px auto;"> <tr><td>Enter your name!</td> <td><input type="text" id="namebox"/></td> <td><input type="button" value="Enter" onclick="StartMarquee()"/></td></tr> </table> </body> </html>

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  • jquery wait till large document is loaded

    - by Martijn
    In my web application I call a document can be huge. This document is loaded into an iframe. I have a title, buttons and the text which all depends on this document. The text is from the large document and is displayed in the iframe. I'd like to show an animated gif while the document is loading on 3 places (1: document title, 2: document buttons, 3: document text, the iframe) I've tried the onload event on the Iframe, but this doesn't give the me the desired effect. Here's my code that loads the document: function loadDocument(id, doc) { $("#DocumentContent").show(); $("#ButtonBox").show(); // Clear dynamic menu items $("#DynamicMenuContent").html(""); $("#PageContent").html(""); // Load document in frame $("#iframeDocument").attr("src", 'ViewDoc.aspx?id=' + id + '&doc=' + doc + ''); // $("#iframeDocument").attr("src", "Graphics/loader.gif"); // Load menu items $.ajax({ url: "ShowButtons.aspx?id=" + id + "&doc=" + doc, success: function(data) { $("#DynamicMenuContent").html(data) }, error: function(xhr, err, e) { alert("error: " + err) } }); // Set document title $("#documentTitle").load("GetDocumentInfo.aspx?p=title"); } My questions, how can I display a loader gif while the document is loaded? And remove the gif when the document is ready?

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  • preg_replace to capitalize a letter after a quote

    - by Summer
    I have names like this: $str = 'JAMES "JIMMY" SMITH' I run strtolower, then ucwords, which returns this: $proper_str = 'James "jimmy" Smith' I'd like to capitalize the second letter of words in which the first letter is a double quote. Here's the regexp. It appears strtoupper is not working - the regexp simply returns the unchanged original expression. $proper_str = preg_replace('/"([a-z])/',strtoupper('$1'),$proper_str); Any clues? Thanks!!

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  • Regular expression to match maximium of five words.

    - by KhanS
    I have a regular expression ^[a-zA-Z+#-.0-9]{1,5}$ which validates that the word contains alpha-numeric characters and few special characters and length should not be more than 5 characters. How do I make this regular expression to accept a maximum of five words matching the above regular expression.

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  • Changing input name attribute

    - by Parhs
    Hello! I have some hidden inputs like this <input name="exam.normals[1].blahblah" ..../> I would like somehow to replace the [1] with a number that I want (index). I aint lazy but I am trying to find a good way to do this... A solution would be a replace of exam.normals[1] with exam.normals[+ index +] but I should substr the whole string first.... With regexp I don’t know how to do the replace. good...

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  • Converting John Resig's JavaScript Templating Engine to work with PHP Templates

    - by Serhiy
    I'm trying to convert the John Resig's Templating Engine to work with PHP. Essentially what I would like to achieve is the ability to use certain Kohana Views via a JavaScript templating engine, that way I can use the same views for both a standard PHP request and a jQuery AJAX request. I'm starting with the basics and would like to be able to convert http://github.com/nje/jquery-tmpl/blob/master/jquery.tmpl.js To work with php like so... ### From This ### <li><a href="{%= link %}">{%= title %}</a> - {%= description %}</li> ### Into This ### <li><a href="<?= $link ?>"><?= $title ?></a> - <?= description ?></li> The RexEx in it is a bit over my head and it's apparently not as easy as changing the %} to ? in lines 148 to 158. Any help would be highly appreciated. I'm also not sure of how to take care of the $ difference that PHP variables have. Thanks, Serhiy

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  • Regular Expression for any number divisible by 60 using C# .Net ?

    - by Steve Johnson
    Hi there, I need to apply validation on input time intervals that are taken in as seconds. Now i am not really good at Regular expressions. So can any body help making a regular expression that can test whether a number is divisible by 60. I was wondering if i could use to test one that check that the number is divisible by 10 and then check whether the same is divisible by 6. For number divisible by 10 here [\d*0] is the expression i guess. Please correct me if i am wrong. Hope somebody solves my problem. Thanks

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  • PHP email validation question?

    - by GeNx
    Will this email validation allow foreign email address like russian, hebrew and so on? And how can I just check for the @ sign? Here is the php code. if (preg_match ('/^[\w.-]+@[\w.-]+\.[A-Za-z]{2,6}$/', $_POST['email'])) { $email = mysqli_real_escape_string($mysqli, strip_tags($_POST['email'])); } else { echo '<p class="error">Please enter a valid email address!</p>'; }

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  • PHP Key name array

    - by Sean McRaghty
    I have an array $data fruit => apple, seat => sofa, etc. I want to loop through so that each key becomes type_key[0]['value'] so eg type_fruit[0]['value'] => apple, type_seat[0]['value'] => sofa, and what I thought would do this, namely foreach ($data as $key => $value) { # Create a new, renamed, key. $array[str_replace("/(.+)/", "type_$1[0]['value']", $key)] = $value; # Destroy the old key/value pair unset($array[$key]); } print_r($array); Doesn't work. How can I make it work? Also, I want everything to be in the keys (not the values) to be lowercase: is there an easy way of doing this too? Thanks.

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  • Parse string with bash and extract number

    - by cleg
    Hello I've got supervisor's status output, looking like this. frontend RUNNING pid 16652, uptime 2:11:17 nginx RUNNING pid 16651, uptime 2:11:17 redis RUNNING pid 16607, uptime 2:11:32 I need to extract nginx's PID. I've done it via grep -P command, but on remote machine grep is build without perl regular expression support. Looks like sed or awk is exactly what I need, but I don't familiar with them. Please help me to find a way how to do it, thanks in advance.

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  • python search replace using wildcards

    - by tom smith
    hi somewhat confused.. but trying to do a search/repace using wildcards if i have something like: <blah.... ssf ff> <bl.... ssf dfggg ff> <b.... ssf ghhjj fhf> and i want to replace all of the above strings with say, <hh >t any thoughts/comments on how this can be accomplished? thanks update (thanks for the comments!) i'm missing something... my initial sample text are: Soo Choi</span>LONGEDITBOX">Apryl Berney Soo Choi</span>LONGEDITBOX">Joel Franks Joel Franks</span>GEDITBOX">Alexander Yamato and i'm trying to get Soo Choi foo Apryl Berney Soo Choi foo Joel Franks Joel Franks foo Alexander Yamato i've tried derivations of name=re.sub("</s[^>]*\">"," foo ",name) but i'm missing something... thoughts... thanks

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  • perl escaping \n or \t

    - by Michael
    I need to escape \n so on output I really get newline or tab $ perl -p -e 's/e/a/ge' now I want each e to be substituted with \n $ perl -p -e 's/e/\n/ge' but even \n gives me an error. this was a simplified example. In real script(makefile) I have substitute := perl -p -e 's/@([^@]+)@/defined $$ENV{$$1} ? $$ENV{$$1} : $$1/ge' and in target I have such a nice command $(substitute) $< > $@ and if the input file for perl contains \n at output I will see it literally... I want to have real newline.

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  • preg_replace, exact opposite of a preg_match

    - by SoLoGHoST
    I need to do a preg_replace for the exact opposite of this preg_match regular expression: preg_match('#^(\w+/){0,2}\w+\.\w+$#', $string); So I need to replace all strings that are not valid with an empty string - '' So it needs to remove the first / and last / if found, and all non-valid characters, that is the only valid characters are A-Z, a-z, 0-9, _, ., and / (if it's not the first or last characters of the string). How can I accomplish this with the preg_replace? Thanks :)

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  • Wanted: a very simple java RegExp API

    - by itsadok
    I'm tired of writing Pattern p = Pattern.compile(... Matcher m = p.matcher(str); if (m.find()) { ... Over and over again in my code. I was going to write a helper class to make it neater, but I then I wondered: is there a library that tries to provide a simpler facade for Regular Expressions in Java? I'm thinking something in the style of commons-lang and Guava.

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