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  • How can I implement Unix grep in Perl?

    - by Ankit Rathod
    How can I implement grep of Unix in Perl? I tried to use Perl's built-in grep. Here is the code which is not working: $pattern = @ARGV[0]; $file= @ARGV[1]; open($fp,$file); @arr = <$fp>; @lines = grep $pattern, @arr; close($fp); print @lines; And by the way, i am trying only basic grep functionality not full featured and secondly i don't want to do string parsing myself. I want to use inbuilt grep or some function of Perl. Thanks in advance :)

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  • How can I modify complex command-line argument strings in Perl?

    - by mmccoo
    I have a command line that I'm trying to modify to remove some of the arguments. What makes this complex is that I can have nested arguments. Say that I have this: $cmdline = "-a -xyz -a- -b -xyz -b- -a -xyz -a-" I have three different -xyz flags that are to be interpreted in two different contexts. One is the -a context and the other is the -b context. I want to remove the "a" -xyz's but leave the ones in the "b" -xyz. in the above case, I want: -a -a- -b -xyz -b- -a -a- Alternately, if I have: -a -123 -a- -b -xyz -b- -a -xyz -a-" I want: -a -123 -a- -a -xyz -a- -b -xyz -b- -a -a- It's this second case that I'm stuck on. How can I most effectively do this in Perl?

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  • Using perl to split a line that may contain whitespace

    - by Tommy Fisk
    Okay, so I'm using perl to read in a file that contains some general configuration data. This data is organized into headers based on what they mean. An example follows: [vars] # This is how we define a variable! $var = 10; $str = "Hello thar!"; # This section contains flags which can be used to modify module behavior # All modules read this file and if they understand any of the flags, use them [flags] Verbose = true; # Notice the errant whitespace! [path] WinPath = default; # Keyword which loads the standard PATH as defined by the operating system. Append with additonal values. LinuxPath = default; Goal: Using the first line as an example "$var = 10;", I'd like to use the split function in perl to create an array that contains the characters "$var" and "10" as elements. Using another line as an example: Verbose = true; # Should become [Verbose, true] aka no whitespace is present This is needed because I will be outputting these values to a new file (which a different piece of C++ code will read) to instantiate dictionary objects. Just to give you a little taste of what it might look like (just making it up as I go along): define new dictionary name: [flags] # Start defining keys => values new key name: Verbose new value val: 10 # End dictionary Oh, and here is the code I currently have along with what it is doing (incorrectly): sub makeref($) { my @line = (split (/=/)); # Produces ["Verbose", " true"]; }

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  • Regular expression to extract text between either square or curly brackets

    - by ObiWanKenobi
    Related to my previous question, I have a string on the following format: this {is} a [sample] string with [some] {special} words. [another one] What is the regular expression to extract the words within either square or curly brackets, ie. {is} [sample] [some] {special} [another one] Note: In my use case, brackets cannot be nested. I would also like to keep the enclosing characters, so that I can tell the difference between them when processing the results.

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  • onmouseover problems with JavaScript (rendered using django and django-imagekit)

    - by Michael Moreno
    I'm using Imagekit. View.py includes: def pics(request): p = Photo.objects.all() return render_to_response('Shots.html', {'p': p}) The following simple code in the template will generate associated images: {% for p in p %} <img src = "{{ p.display.url }}"> <img src = "{{ p.thumbnail_image.url }}"> {% endfor %} I'm attempting to generate a series of thumbnails {{ p.thumbnail_image.url }} which, when mouseover'd, will generate the slightly larger version of the image, {{ p.display.url }} via Javascript. The following code in the template attempts to do so: <html> <head> <HEAD> <script language="Javascript"> { image1 = new Image image2 = new Image image1.src = {{ p.thumbnail_image.url }} image2.src = {{ p.display.url }} </script> </head> <body> {% for p in p %} <a href="" onMouseOver="document.rollover.src= image2.src onMouseOut="document.rollover.src= image1.src"> <img src="{{ p.thumbnail_image.url }}" border=0 name="rollover"></a> {% endfor %} </body> </html> This will display the series of thumbnails, but the larger image will not display when mouseover'd. I believe it has to do with how I'm specifying the variable {{ p.display.url }}.

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  • Replacing Part of Text Using Sed

    - by neversaint
    I have the following text file Eif2ak1.aSep07 Eif2ak1.aSep07 LOC100042862.aSep07-unspliced NADH5_C.0.aSep07-unspliced LOC100042862.aSep07-unspliced NADH5_C.0.aSep07-unspliced What I want to do is to remove all the text starting from period (.) to the end. But why this command doesn't do it? sed 's/\.*//g' myfile.txt What's the right way to do it?

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  • Mercurial/.hgignore - How do I ignore everything but the contents of a folder?

    - by Beibin
    I have a NetBeans project and the Mercurial repository is in the project root. I would like it to ignore everything except the contents of the "src" and "test" folders, and .hgignore itself. I'm not familiar with regular expressions and can't come up with one that will do that. The ones I tried: (?!src/.*) (?!test/.*) (?!^.hgignore) (?!src/.|test/.|.hgignore) These seem to ignore everything, I can't figure out why. Any advice would be great.

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  • regular expression for indian vehicle number

    - by I Like PHP
    i need validation for indian vehicle NUMBER here are condition list let expression is (x)(y)(z)(m)(a)(b)(c) 1. (x) contains only alphabets of length 2. 2. (y) may be - or single space ' ' 3. (z) contains only numbers of length 2 4. (m) may be or , or single space ' ' 5. length of (a) can be 2 or 3. contains alphanumeric value with minimum one alphabetic character. 6. (b) may be - or single space ' ' ( similar to (y) ) 7. (c) contains only numbers of length 4 i show you the various examples of vehicle number valid number RJ-14,NL-1234 RJ-01,4M-5874 RJ-07,14M-2345 RJ 07,3M 2345 RJ-07,3M-8888 RJ 07 4M 2345 RJ 07,4M 2933 invalid number RJ-07 3M 1234 ( both (y) and (b) should be same). RJ-07 M3-1234 ((a) must ends with alphabat). rj-07 M3-123 ( length of (c) must be 4).

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  • Regular Expression for Decimal or Blank

    - by Phil P
    Sorry for the potentially dumb question but I am trying to pull together a regular expression that will allow: A number with 1 or 2 numbers before a decimal point, and 0-6 numbers after the decimal point. However I also need to allow the field to be blank if so required. Valid Examples 0.952321 1.20394 12.12 25 Blank Invalid Examples 123.45678 1.1234567 Please can anyone help?

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  • TSQL Email Validation (without regex)

    - by Eric Z Beard
    Ok, there are a million regexes out there for validating an email address, but how about some basic email validation that can be integrated into a TSQL query for Sql Server 2005? I don't want to use a CLR procedure or function. Just straight TSQL. Has anybody tackled this already?

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  • How to use regular expression in lxml xpath?

    - by Arty
    I'm using construction like this: doc = parse(url).getroot() links = doc.xpath("//a[text()='some text']") But I need to select all links which have text beginning with "some text", so I'm wondering is there any way to use regexp here? Didn't find anything in lxml documentation

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  • validate hostname string in Python

    - by kostmo
    Following up to Regular expression to match hostname or IP Address? and using Restrictions on valid host names as a reference, what is the most readable, concise way to match/validate a hostname/fqdn (fully qualified domain name) in Python? I've answered with my attempt below, improvements welcome.

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  • PHP regular expression find and append to string

    - by Gary
    I'm trying to use regular expressions (preg_match and preg_replace) to do the following: Find a string like this: {%title=append me to the title%} Then extract out the title part and the append me to the title part. Which I can then use to perform a str_replace(), etc. Given that I'm terrible at regular expressions, my code is failing... preg_match('/\{\%title\=(\w+.)\%\}/', $string, $matches); What pattern do I need? :/

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  • Function to hide sloppy phone numbers..

    - by Frank Malina
    I need to hide phone numbers (and maybe other contact details) in user generated content to protect my users from anonymous web. Input is very random, therefore I'd be looking to replace anything that looks like a phone number (e.g.: string of 3 or more numbers) with just dots, and also perhaps remove some exotic notations of e-mail addresses. What is the best way to do this? Nice and slick, reusable. Give away your secret regexes. Write in any language. Except perhaps COBOL :) function privacy($str){ // protect phone numbers // protect e-mail addresses // protect web addresses }

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  • getting started with lex

    - by cambr
    I need to format some hexdump like this: 00010: 02 03 04 05 00020: 02 03 04 08 00030: 02 03 04 08 00010: 02 03 04 05 00020: 02 03 04 05 02 03 04 05 02 03 04 08 to 02 03 04 05 02 03 04 08 02 03 04 02 03 04 05 02 03 04 05 02 03 04 05 02 03 04 a) remove the address fields, if present b) remove any 08 at the end of a paragraph (followed by an empty line) c) remove any empty lines How can this be done using lex? thanks!

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  • split a string based on pattern in java - capital letters and numbers

    - by rookie
    Hi all I have the following string "3/4Ton". I want to split it as -- word[1] = 3/4 and word[2] = Ton. Right now my piece of code looks like this:- Pattern p = Pattern.compile("[A-Z]{1}[a-z]+"); Matcher m = p.matcher(line); while(m.find()){ System.out.println("The word --> "+m.group()); } It carries out the needed task of splitting the string based on capital letters like:- String = MachineryInput word[1] = Machinery , word[2] = Input The only problem is it does not preserve, numbers or abbreviations or sequences of capital letters which are not meant to be separate words. Could some one help me out with my regular expression coding problem. Thanks in advance...

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  • Combine regular expressions for splitting camelCase string into words

    - by stou
    I managed to implement a function that converts camel case to words, by using the solution suggested by @ridgerunner in this question: Split camelCase word into words with php preg_match (Regular Expression) However, I want to also handle embedded abreviations like this: 'hasABREVIATIONEmbedded' translates to 'Has ABREVIATION Embedded' I came up with this solution: <?php function camelCaseToWords($camelCaseStr) { // Convert: "TestASAPTestMore" to "TestASAP TestMore" $abreviationsPattern = '/' . // Match position between UPPERCASE "words" '(?<=[A-Z])' . // Position is after group of uppercase, '(?=[A-Z][a-z])' . // and before group of lowercase letters, except the last upper case letter in the group. '/x'; $arr = preg_split($abreviationsPattern, $camelCaseStr); $str = implode(' ', $arr); // Convert "TestASAP TestMore" to "Test ASAP Test More" $camelCasePattern = '/' . // Match position between camelCase "words". '(?<=[a-z])' . // Position is after a lowercase, '(?=[A-Z])' . // and before an uppercase letter. '/x'; $arr = preg_split($camelCasePattern, $str); $str = implode(' ', $arr); $str = ucfirst(trim($str)); return $str; } $inputs = array( 'oneTwoThreeFour', 'StartsWithCap', 'hasConsecutiveCAPS', 'ALLCAPS', 'ALL_CAPS_AND_UNDERSCORES', 'hasABREVIATIONEmbedded', ); echo "INPUT"; foreach($inputs as $val) { echo "'" . $val . "' translates to '" . camelCaseToWords($val). "'\n"; } The output is: INPUT'oneTwoThreeFour' translates to 'One Two Three Four' 'StartsWithCap' translates to 'Starts With Cap' 'hasConsecutiveCAPS' translates to 'Has Consecutive CAPS' 'ALLCAPS' translates to 'ALLCAPS' 'ALL_CAPS_AND_UNDERSCORES' translates to 'ALL_CAPS_AND_UNDERSCORES' 'hasABREVIATIONEmbedded' translates to 'Has ABREVIATION Embedded' It works as intended. My question is: Can I combine the 2 regular expressions $abreviationsPattern and camelCasePattern so i can avoid running the preg_split() function twice?

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  • data in mysql show after barcode split and matches character

    - by klox
    i need some code for the next step..this my first step: <script> $("#mod").change(function() { var barcode; barCode=$("#mod").val(); var data=barCode.split(" "); $("#mod").val(data[0]); $("#seri").val(data[1]); var str=data[0]; var matches=str.matches(/EE|[EJU]).*(D)/i); }); </script> after matches..i want the result can connect to data base then show data from table inside <div id="value">...how to do that?

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  • How do I locate a particular word in a text file using C#

    - by cmrhema
    Hi, I am sending mails (in asp.net ,c#), having a template in text file (.txt) like below User Name :<User Name> Address : <Address>. I used to replace the words within the angle brackets in the text file using the below code StreamReader sr; sr = File.OpenText(HttpContext.Current.Server.MapPath(txt)); copy = sr.ReadToEnd(); sr.Close(); //close the reader copy = copy.Replace(word.ToUpper(),"#" + word.ToUpper()); //remove the word specified UC //save new copy into existing text file FileInfo newText = new FileInfo(HttpContext.Current.Server.MapPath(txt)); StreamWriter newCopy = newText.CreateText(); newCopy.WriteLine(copy); newCopy.Write(newCopy.NewLine); newCopy.Close(); Now I have a new problem, the user will be adding new words within an angle, say for eg, they will be adding <Salary>. In that case i have to read out and find the word <Salary>. In other words, I have to find all the words, that are located with the angle brackets (<). How do I do that. Kindly do let me know. Thanks.

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  • Objective C - RegexKitLite - Parsing inner contents of a string, ie: start(.*?)end

    - by Stu
    Please consider the following: NSString *myText = @"mary had a little lamb"; NSString *regexString = @"mary(.*?)little"; for)NSString *match in [myText captureComponentsMatchedByRegex:regexString]){ NSLog(@"%@",match); } This will output to the console two things: 1) "mary had a little" 2) "had a" What I want is just the 2nd bit of information "had a". Is there is a way of matching a string and returning just the inner part? I'm fairly new to Objective C, this feels a rather trivial question yet I can't find a less messy way of doing this than incrementing an integer in the for loop and on the second iteration storing the "had a" in an NSString.

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  • Regular expression for a phone number

    - by Zerobu
    Hello, I would like a regular expression in this format. It Must match one of the following formats: * (###)###-#### * ###-###-#### * ###.###.#### * ########## Strip all whitespace. Make sure it's a valid phone number, then (if necessary) translate it to the first format listed above.

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  • Dealing with multiple parameters in Nginx rewrite

    - by x3sphere
    I have a rewrite that nginx calls like so: location ~* (css)$ { rewrite ^(.*),(.*)$ /min/index.php?f=$1,/min/$2 last; } And it's used on pages like this: http://domain.com/min/framework.css,dropdown.css Works all fine and dandy, but it's not scalable. Adding another element to the URL means I have to directly edit the nginx config. Ideally, I'd like to have nginx rewrite according to how many comma-delimited parameters are passed through the URL, rather than setting a fixed amount in the config. Is this possible?

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