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  • will destroyed() be emitted if the constructor of a class derived from QObject throws?

    - by PorkyBrain
    Ive seen Qt GUI syntax like the following all over the place: myDialog::myDialog(QWidget *parent, Qt::WFlags flags):QDialog(parent, flags) { QPushButton *button = new QPushButton("&Download", this); QVBoxLayout *layout = new QVBoxLayout(this); //something that can throw here layout ->addWidget(button ); setLayout(layout); } I've always wondered if this can leak in the event of an exception because the "this" I'm giving as a parent to button and layout is not fully constructed so it might not destroy its children. I tried it out in MSVC2010 Qt4.8.3 and it looks like as soon as the base QObject class is fully created (which is done first of course) it is ok to pass "this" to other objects in the constructor, they will destroyed correctly. I haven't found the spot in the Qt docs guaranteeing this though, can someone point me to it so I have assurance that this will not change in the future?

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  • Package Installer misbehavoir

    - by rantravee
    Hi, I am unable to understand and fix the following behavior displayed by the Package Installer : in my application when I press on a "update application" button I download from a web server un update apk (in case there is) and start the Package Installer afterwards to install the package. Everything goes well and after the installation finishes there is displayed a view with two buttons "open" and "done" . However pressing the "open" button fails to open the installed update as it should even if the intent to the startup activity is sent as I observed in logcat . Pressing on menu button and going through the applications installed I am able to find the updated app and start it from here . What should I do to start the update by pressing open in the final Package Installed view ?

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  • Parent/Child forms communication issue

    - by user361583
    Hi, I am very new to Visual C++ programming, but I have to write simple program which needs to do two things: ( I am using MS Visual C++ ) main ( parent ) form should be displayed when program starts, and after clicking a button on it, second form should be shown. Second form ( child ) also has a button, but this one should ( after clicking, of course ) show current X,Y child form position but on ( important ): parent form. And this is where i got stuck. I can display child form with: a) adding #include "child.h" in parent form.h b) adding child ^child_form; in public: section and afterwards using: child_form = gcnew child(); child_form-Show(); I was googling for two days now and cannot find a way to get it the other way: click on a button on child_form and display it's coordinates on parent form on label-text :/ when i tried to add #include "child.h" in child_form I just got error saying: "there are to many include files..." I really need to get this done and I would really appreciate any suggestions. Thanks in advance :)

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  • Android : How to start an activity in a tab?

    - by Miya
    Hi, I am using tabs in my application. I have 3 tabs : home, services, contact us. In the 'home tab', there is 'login button' and my requirement is when I click the login button, it should display the view for 'login' in the same tab itself. That means it should start another activity (login.class) and display corresponding view (login.xml). And the tabs should be displayed at the top as before. But when I click the login button, it should start login activity, but the tabs are disappeared. How can I start an activity in the same tab itself? Please help me. Thank you...

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  • facebook and twitter buttons doesn't work

    - by Justin
    I am building a website in dreamweaver cs5. for some reason, the facebook like button and twitter share as well as follow button doesn't work. facebook like button shows nothing. (in the area, chrome says page cannot be found), twitter buttons show the hyperlink tweet and it tweets but the icon doesn't show up. The code for both are generated from facebook and twitter itself. I haven't hosted the site yet. I and coding and previewing it. Is that the reason for them not to work? I also tried addthis.com widget. It didn't show up as it should have. Please help! Many thanks.

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  • When to save a variable in viewstate?

    - by Umut
    Hi, I have searched the web for the answer and saw that mostly variables are saved in viewstate on page.prerender event. However, when I save a variable in viewstate on prerender or load events, how can it store the changed value of the variable? Let's say, after page load, user clicked a button and the value of the variable was changed in onClick event of the button. Then the postback event raised since the button was clicked. According to me, the new value should have been lost and cannot be saved in the viewstate if I save the variable in the viewstate only in prerender event. Shouldn't I save the variable in the viewstate just before the postback event rises? Am I wrong? If so, how can viewstate store the new value of the variable? Thanks for the answer in advance..

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  • How can I dismiss the view appeared by touching Add item in UINavigationController ?

    - by srikanth rongali
    I have added add(+ symbol button) button to my navigation controller. When I click it a view appears from bottom. I added a navigation bar and two buttons to it. One save and one cancel button. And the view have one textEdit box. After editing I can save or cancel. If I touch cancel I need the view to disappear like it should go down again. I think all iPhone , iPodTouch users use it. Like when they touch Add item then a view appears from bottom and when they cancel it goes down again. How can I make in this way in my application.

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  • What is wrong with selecting with my drop down element.

    - by Babiker
    <html> <head> <script type='text/javascript' language='javascript' src="http://localhost/javascript/jquery-1.4.2.js"> </script> <script type='text/javascript' language='javascript'> $(document).ready(function(){ $("#button").mousedown(function(){ dropDownMenu = $("#dropDownMenu"); alert(dropDownMenu.options[0].text); }); }); </script> </head> <body> <select id="dropDownMenu"><option>Test</option></select><br> <input id="button" type="button"> </body> </html>

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  • How to require a checkbox to be checked at client side before form gets submitted to server in MVC 3?

    - by Projapati
    I have a Terms and Condition checkbox on my signup page. I want to make it required like my few other fields on the form before posting to server. This validation must be done at client side. Anyone knows how to do it properly? I am using MVC 3, jquery.validate.min.js and jquery.validate.unobtrusive.min.js Model: [Required(ErrorMessage = "terms and condition")] [Display(Name = "terms")] public bool Terms { get; set; } View: @Html.CheckBoxFor(m => m.Terms, new { @class = "cb" }) Terms & Condition <button type="submit" id="btnSubmit" class="btn">Signup</button> Also, Is it possible to call/trap some JS function when the submit button is clicked? That way I can easily use jquery to do validation and then submit? Thanks for reading

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  • Browser Detection, do's and don'ts. Is this ok?

    - by JCOC611
    So, I understand that browser detection (ie. navigator.userAgent) shouldn't be used to decide which object method/property to use; yet, I want to set some simple CSS with JavaScript depending on the browser. However, it's not enough to justify a completely new StyleSheet. So is it OK if I use Browser Detection to decide what CSS to apply to an element? EDIT Ok, let's be SPECIFIC. I'm talking about a text-shadow inside a button (<input type="button"/>) The text inside the button isn't vertically centered in all browsers, so I tweak this with JS depending on the browser.

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  • jQuery display problem?

    - by SLAPme
    How do I hide the #changes-saved code using jQuery? For example let's say the code is displayed when the user clicks the submit button and then leaves the current web page and then returns back to the web page and the #changes-saved is no longer displayed until the submit button is clicked again. Here is the jQuery code. $(function() { $('#changes-saved').hide(); $(".save-button").click(function() { $.post($("#contact-form").attr("action"), $("#contact-form").serialize(), function(html) { $("div.contact-info-form").html(html); $('#changes-saved').append('<li>Changes saved!</li>').show().pause(1000).hide(); }); return false; // Prevent normal submit. }); });

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  • AddClass onClick won't work

    - by QTaylor
    I'm having some problems getting some simple jQuery to work; I'm trying to add a class called fadeInLeft to my body element on click. Here's the code: $('.contact-button').click(function() { $('body').addClass('fadeInLeft') }); HTML (from comment left by OP, below): <div id="contact" class="bounceInRight animated four"> <a href="#" class="contact-button"> Say Hello </a> </div><!--End of contact--> contact-button is the class of the link, fadeInLeft is the class I want to add when the link is clicked. Any idea why this would not work ?

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  • PHP Variable Passing in Foreach on same page

    - by tooly228
    I've been struggling this for a while and I simply can't figure this out. Here is my code: <?php foreach($list as $id =>$name) { echo("<td style=\"vertical-align:middle;\"> <a href=\"item=$id#confirm\" role=\"button\" data-toggle=\"modal\"> Buy</a></td></tr>"); }?> <html> <div class="modal small hide fade" id="confirm" tabindex="-1" role="dialog" aria- labelledby="myModalLabel" aria-hidden="true"> <a href="redeem.php?item=<?php echo $id; ?>"><button class="btn btn-danger"> Buy</button></a></div> The main issue here is that the $id from the foreeach is not the same as the $id in the div class link. Instead the link is the end value of the foreach list.

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  • How to put buttons in a html page in a jQuery dialog

    - by Robert
    eHello everyone,the following is my code to display a jquery dialog window with a closing button "OK": <script type="text/javascript"> $(function(){$("#dialog").dialog({autoOpen:false,bgiframe:true,buttons: { "OK": function() { $(this).dialog("close"); } }, width:500, height: 350, modal: true, show: 'slide', hide:'slide', title:"Similar Trends Detected in 2nd DataSet"}); $("#userid").focus(); }); function showForm(matches){ $("#dialog").html(matches).dialog("open");} Currently it runs by supplying a string variable "matches",then the content of the variable gets displayed on the dialog frame. Now me and my teammate want to extend this dialog a little,we want to attach a button to every line inside the html content("matches" variable),please note that we don't want buttons in the dialog(like another "OK" button),but we want buttons "inside" the frame (the actual html content). So I would like some help here,how could I modify my "matches" variable,to have buttons also shown inside the dialog. Thanks.

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  • Run C# code after running all javascript codes

    - by Devi
    I am having a form in which a button is there on click of that button i am calling a javascript function in which i am displaying like 3.. 2.. 1 kind of effect then i am returning true. But after showing 3 only return true is getting executed and the form is getting submitted. How to stop form submitting before running the script. Edit: function jsFun() { timerCount(3); //Calling the Timer Function. } var t; function timerCount(cDown) { if (cDown == 0) { clearTimeout(t); return true; } $('#<%= mainContainer.ClientID %>').html(cDown); cDown = cDown - 1; t = setTimeout('timerCount(' + cDown + ')', 1000); } <asp:Button ID="btnStarts" runat="server" Text="Start" OnClientClick="return jsFun();" OnClick="btn_click" />

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  • (database) im trying to create a form in access 2007 with 2 drop down boxes to view a report by state or name

    - by jeff orris
    im an intern at a database mngmt company and the boss is training me in access...i took the access tutorials and were definitely not enough info involved to do a what seems a simple task.my problem is this: i have a simple table with contact info with 16 colums (Local_Utility, Requested_User_Type, First_Name, Last_Name, Address 1, Address 2, Country, State, City, Zip, Phone_Number, Username\Email, Password, Confirm Password, and Parcel_Number), with 6 rows of names (keep in mind this is just a test to help me from the boss) I created a form and with 2 drop down boxes (Last Name and State) and im trying to create a view button to view an individual report for a query i made for just simple contact info with 6 colums (Last_Name, First_Name, Address1, City, State, and Phone_Number) Problem1 is that i can view the query with the view by name or state button but cant view a simple individual report from the query using the button Problem2 is that for criteria on the query i put Forms!frmMyparamForm!txtMyStateParamField for the state drop box it works, but when i use Forms!frmMyparamForm!txtMyNameParamField it doesnt and that annoying parameter box pops up Problem3 is that after i close the query, all the states and names in my dropdown box on the form disappear Im a beginner at this please help me

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  • files get uploaded just before they get cancelled

    - by user1763986
    Got a little situation here where I am trying to cancel a file's upload. What I have done is stated that if the user clicks on the "Cancel" button, then it will simply remove the iframe so that it does not go to the page where it uploads the files into the server and inserts data into the database. Now this works fine if the user clicks on the "Cancel" button in quickish time the problem I have realised though is that if the user clicks on the "Cancel" button very late, it sometimes doesn't remove the iframe in time meaning that the file has just been uploaded just before the user has clicked on the "Cancel" button. So my question is that is there a way that if the file does somehow get uploaded before the user clicks on the "Cancel" button, that it deletes the data in the database and removes the file from the server? Below is the image upload form: <form action="imageupload.php" method="post" enctype="multipart/form-data" target="upload_target_image" onsubmit="return imageClickHandler(this);" class="imageuploadform" > <p class="imagef1_upload_process" align="center"> Loading...<br/> <img src="Images/loader.gif" /> </p> <p class="imagef1_upload_form" align="center"> <br/> <span class="imagemsg"></span> <label>Image File: <input name="fileImage" type="file" class="fileImage" /></label><br/> <br/> <label class="imagelbl"><input type="submit" name="submitImageBtn" class="sbtnimage" value="Upload" /></label> </p> <p class="imagef1_cancel" align="center"> <input type="reset" name="imageCancel" class="imageCancel" value="Cancel" /> </p> <iframe class="upload_target_image" name="upload_target_image" src="#" style="width:0px;height:0px;border:0px;solid;#fff;"></iframe> </form> Below is the jquery function which controls the "Cancel" button: $(imageuploadform).find(".imageCancel").on("click", function(event) { $('.upload_target_image').get(0).contentwindow $("iframe[name='upload_target_image']").attr("src", "javascript:'<html></html>'"); return stopImageUpload(2); }); Below is the php code where it uploads the files and inserts the data into the database. The form above posts to this php page "imageupload.php": <body> <?php include('connect.php'); session_start(); $result = 0; //uploads file move_uploaded_file($_FILES["fileImage"]["tmp_name"], "ImageFiles/" . $_FILES["fileImage"]["name"]); $result = 1; //set up the INSERT SQL query command to insert the name of the image file into the "Image" Table $imagesql = "INSERT INTO Image (ImageFile) VALUES (?)"; //prepare the above SQL statement if (!$insert = $mysqli->prepare($imagesql)) { // Handle errors with prepare operation here } //bind the parameters (these are the values that will be inserted) $insert->bind_param("s",$img); //Assign the variable of the name of the file uploaded $img = 'ImageFiles/'.$_FILES['fileImage']['name']; //execute INSERT query $insert->execute(); if ($insert->errno) { // Handle query error here } //close INSERT query $insert->close(); //Retrieve the ImageId of the last uploded file $lastID = $mysqli->insert_id; //Insert into Image_Question Table (be using last retrieved Image id in order to do this) $imagequestionsql = "INSERT INTO Image_Question (ImageId, SessionId, QuestionId) VALUES (?, ?, ?)"; //prepare the above SQL statement if (!$insertimagequestion = $mysqli->prepare($imagequestionsql)) { // Handle errors with prepare operation here echo "Prepare statement err imagequestion"; } //Retrieve the question number $qnum = (int)$_POST['numimage']; //bind the parameters (these are the values that will be inserted) $insertimagequestion->bind_param("isi",$lastID, 'Exam', $qnum); //execute INSERT query $insertimagequestion->execute(); if ($insertimagequestion->errno) { // Handle query error here } //close INSERT query $insertimagequestion->close(); ?> <!--Javascript which will output the message depending on the status of the upload (successful, failed or cancelled)--> <script> window.top.stopImageUpload(<?php echo $result; ?>, '<?php echo $_FILES['fileImage']['name'] ?>'); </script> </body> UPDATE: Below is the php code "cancelimage.php" where I want to delete the cancelled file from the server and delete the record from the database. It is set up but not finished, can somebody finish it off so I can retrieve the name of the file and it's id using $_SESSION? <?php // connect to the database include('connect.php'); /* check connection */ if (mysqli_connect_errno()) { printf("Connect failed: %s\n", mysqli_connect_error()); die(); } //remove file from server unlink("ImageFiles/...."); //need to retrieve file name here where the ... line is //DELETE query statement where it will delete cancelled file from both Image and Image Question Table $imagedeletesql = " DELETE img, img_q FROM Image AS img LEFT JOIN Image_Question AS img_q ON img_q.ImageId = img.ImageId WHERE img.ImageFile = ?"; //prepare delete query if (!$delete = $mysqli->prepare($imagedeletesql)) { // Handle errors with prepare operation here } //Dont pass data directly to bind_param store it in a variable $delete->bind_param("s",$img); //execute DELETE query $delete->execute(); if ($delete->errno) { // Handle query error here } //close query $delete->close(); ?> Can you please provide an sample code in your answer to make it easier for me. Thank you

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  • How to change size of UIButton

    - by Adam
    I'm trying to resize a UIButton in my iPhone app. I have a UIButton synthesized and when I call the following code, it moves on the screen, but the width & height of the button never change. button.frame.size = CGRectMake(104, 68, 158, 70); For example, when I change the height (70) to 40, the height of the button does not change. If I change the x or y, however, it will move on the screen. Any ideas?

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  • flex accessing children of a list component

    - by pfunc
    when I try to loop through the children of a List component that has buttons in it, I can't seem to access those children. I try for(var btnNum:Number = 0; btnNum < myList.numChildren; btnNum++) { trace(myList.getChildAt(btnNum); } but it is giving some other instance, not the button instances. and the weeklist <mx:List id="myList" dataProvider="{_data.mappoints.week.@number}" > <mx:itemRenderer > <mx:Component> <mx:Button buttonMode="true" toggle="true" alpha="1" width="116" height="35" label="WEEK {data}" > </mx:Button> </mx:Component> </mx:itemRenderer> </mx:List>

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  • What is a good way for a custom accessory view in a UITableViewCell to message the table view contro

    - by Alex Gosselin
    Hi Everyone, I am working on adding a custom accessory view, (a button) to a UITableViewCell, and I need it to tell the table view when it is touched, but I can't figure out how to communicate to the table view what button was pressed. Ideally I'd like to somehow call a function like this: [controller tableView:view didSelectCustomButtonAtIndexPath:indexPath usingCell:self]; when my custom view button is pressed. Sorry if this is a bit vague, I'm not really sure how to explain this well. I am basically looking for how to mimic the implementation for tableView:didSelectRowAtIndexPath: without having to subclass UITableViewCell. Thanks for any help.

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  • Change URL of a saved HTML file

    - by Paul Camilleri
    I am new to HTML so this question might sound a bit lame. Anyways I have a saved webpage on my desktop that when i open it in google chrome i want it to show a specific URL instead of its current location. Any ideas how i might get this to work? I tried using the history.pushState but i have no idea why it is not working. I created a simple page for now to test it: <html> <head> <script> function setURL() { history.pushState("Test","page2", "www.test.com"); } </script> </head> <body> <button type="button" onclick="setURL()">Set Url</button> </body> </html> Any help would be greatly appreciated. Thank you

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  • this.Dispose() Don't release memory used by Form after Closing it .

    - by Ehab Sutan
    Hello, in C# Application. I've a windows form application in which clicking certain button make object from a 2nd Form. On closing this 2nd From by user Memory used by this form not released (from Task Manager). I Tried using this.dispose() on exit button ,tried this.close() , tried form2 =null in the main code ,and tried clearing all controls from this form by code before Disposing and every time the clicks the button memory usage by the application increases more and memory used by previous instance not released. What shall i use to solve this problem ?

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  • Facebook | redirect error

    - by MMRUser
    I have facebook connect button on a page of my site and I want user to redirect to a page after a successful login: here's the code snippet: </script> <fb:login-button onlogin="facebook_onlogin();"> </fb:login-button> <script type="text/javascript"> FB.init("API_KEY", "http://myip/facebookapp/xd_reciver.html/"); function facebook_onlogin() { window.location="http://myip/facebookapp/mypage/" } </script> But when I logged in it redirects to the page INSIDE the pop-up, how can I redirect to the page out side of the popup..

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  • iphone - navigation controller - move to first view from last view without traversing all intermedia

    - by satyam
    i'm working on iphone app which will show 4 buttons in first view. on click of a button, it will load a new view with navigation controller. this navigation controller view allows to travel upto 11 sub views. in 11th sub view, i've a reset button. on click of reset button, i've to go back to navigation controllers first view without traversing all the 11 views? is it possible to achieve it? if yes how? if no, what can be the solution?

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  • Grid View selected index

    - by user2924573
    I have a grid which contains a edit button . When i click the edit button and debug it does not hit to the selected index change event . There are no build errors code behind the grid public void btnModemDetailsEdit_Click(object sender, EventArgs e) { isEdit = true; } protected void gridModemDetails_SelectedIndexChanged(object sender, EventArgs e) { int id = Convert.ToInt32(GridModemDetails.DataKeys[GridModemDetails.SelectedIndex].Values["gridModemDetails_SelectedIndexChanged"].ToString()); } <asp:GridView ID="GridModemDetails" runat="server" Width="435px" DataKeyNames="ModemId" AllowPaging="True" OnSelectedIndexChanged="gridModemDetails_SelectedIndexChanged" AutoGenerateColumns="False"> <Columns> <asp:TemplateField HeaderText="Edit" Visible="True" > <ItemTemplate> <asp:LinkButton ID="btnModemDetailsEdit" AccessibleHeaderText="Edit" ButtonType="Button" Text="Edit" HeaderText="Edit" runat="server" OnClick="btnModemDetailsEdit_Click" runat="server"/> </ItemTemplate> </asp:TemplateField>

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