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  • How to load data on option box in php

    - by user225269
    I'm having trouble loading the mysql data on the html form option box using php. Here's my code: <?php $con = mysql_connect("localhost","myuname","mypassword"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $idnum= mysql_real_escape_string($_POST['idnum']); $result = mysql_query("SELECT * FROM student WHERE IDNO='$idnum'"); ?> <?php while ( $row = mysql_fetch_array($result) ) { ?> <tr> <td width="30" height="35"><font size="2">*I D Number:</td> <td width="30"><input name="idnum" type="text" maxlength="5" value="<?php echo $row["IDNO"]; ?>" readonly="readonly"></td> </tr> My problem is loading it here: <td><font size="2">Gender</td> <td> <select name="gender" id="gender"> <font size="2"> <option value="<?php echo $line['IDNO']; ?> "><?php $line['GENDER'] ; ?></option> </select></td></td> The table looks like this: IDNO | GENDER 123 | M 321 | F What am I supposed to do?To load the exact gender corresponding to the IDNO?

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  • mod_rewrite: no access to real files and directories

    - by tshabalala
    Hello. I use mod_rewrite/.htaccess for pretty URLs. I forward all the requests to my index.php, like this: RewriteRule ^/?([a-zA-Z0-9/-]+)/?$ /index.php [NC,L] The index.php then handles the requests. I'm also using this condition/rule to eliminate trailing slashes (or rather rewrite them to the URL without a trailing slash, with a 301 redirect; I'm doing this to avoid duplicate content and because I like no trailing slashes better): RewriteCond %{HTTP_HOST} !^\.localhost$ [NC] RewriteRule ^(.+)/$ http://%{HTTP_HOST}/$1 [R=301,L] This works well, except that I now get an infinite loop when trying to access a (real) directory (the rewrite rule removes the trailing slash, the server adds it again, ...). I solved this by setting the DirectorySlash directive to Off: DirectorySlash Off I don't know how good this solution is, I don't feel too confident about it tbh. Anyway, what I'd like to do is completely ignore "real" files and directories, since I don't need them and I only use pretty URLs with "virtual" files/directories anyway. This would allow me to avoid the DirectorySlash workaround/hack too. Is this possible? Thanks!

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  • json parser empty result

    - by graybow
    I'm new in gwt and new in using firebug.I have valid json result from tesdb3.php {"item": [{"kode":"002","nama":"bambang gentolet"}, {"kode":"012","nama":"Algiz"}]} I add the xml with inherits name='com.google.gwt.json.JSON'/ inherits name="com.google.gwt.http.HTTP" / then i try to show it in the gwt with this code. public class Tesdb3 implements EntryPoint { String url= "http://localhost/phpmyadmin/tesdb3/datauser.php"; public void LoadData() throws RequestException{ RequestBuilder builder = new RequestBuilder(RequestBuilder.GET, URL.encode(url)); builder.sendRequest(null, new RequestCallback(){ @Override public void onError(Request request, Throwable exception) { Window.alert("error " + exception); } public void onResponseReceived(Request request, Response response) { if (200 == response.getStatusCode()) { Window.alert("ok -" + response.getText() + "-" + response.getStatusCode()); } else { Window.alert("error2 -" + response.getText()+ response.getStatusText() + "-" + response.getStatusCode()); } } }); } public void onModuleLoad() { try { LoadData(); } catch (RequestException e) { e.printStackTrace(); } } } I run it in development mode. not hosted mode. My code didn't show any error. But the result in window alert is "error2 --OK-0". result Net from firebug is 7 request: get Tesdb3.html?gwt.codeserv = 200ok get Tesdb3.css = 200ok get tesdb3.nocache.js = 200ok get hosted.html?tesdb3 = aborted get standard.css = 304 not modified get hosted.html?tesdb3 = 403 not modified get datauser.php = 200ok my question is: Why the response status code is 0, and the response status text is 'OK'? there was no eror in json or java code. why response.getText is empty? Why i can't get any json result even a single character?

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  • trying to backup mysql database using php

    - by user225269
    I got this code from this site: http://www.php-mysql-tutorial.com/wikis/mysql-tutorials/using-php-to-backup-mysql-databases.aspx But I'm just a beginner so I don't know what the config.php and opendb.php suppose to mean. Do I have to create those 2 files in order for this code to work? If yes, then how do I create it, it isn't included in the site how to create it. <?php include 'config.php'; include 'opendb.php'; $tableName = 'mypet'; $backupFile = 'backup/mypet.sql'; $query = "SELECT * INTO OUTFILE '$backupFile' FROM $tableName"; $result = mysql_query($query); include 'closedb.php'; ?> can I just include these lines on the top code so that I will not be putting the include 'opendb.php' anymore: $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("Hospital", $con);

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  • Delay PHP execution until JavaScript cookie set?

    - by Adam184
    I am trying to delay PHP execution until a cookie is set through JavaScript. The code is below, I trimmed the createCookie JavaScript function for simplicity (I've tested the function itself and it works). <?php if(!isset($_COOKIE["test"])) { ?> <script type="text/javascript"> $(function() { // createCookie script createCookie("test", 1, 3600); }); </script> <?php // Reload the page to ensure cookie was set if(!isset($_COOKIE["test"])) { header("Location: http://localhost/asdf.php/"); } } ?> At first I had no idea why this didn't work, however after using microtime() I figured out that the PHP after the <script> was executing before the jQuery ready function. I reduced my code significantly to show a simple version that is answerable, I am well aware that I am able to use setcookie() in PHP, the requirements for the cookie are client-side. I understand mixing PHP and JavaScript is incorrect, but any help on how to make this work (is there a PHP delay? - I tried sleep(), didn't work and didn't think it would work, since the scripts would be delayed as well) would be greatly appreciated.

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  • j_security_check to SSO in different module under Oracle App Server?

    - by thebearinboulder
    I have an existing j2ee application running on Oracle App Server. It is targeted towards paying customers so the content is secured and a SSO module properly intercepts all requests for secured content. Now the company is adding a unbranded public-facing module with a number of unsecured pages. At one point the user is expected to register for a free account and log in to proceed further. Think doctors adding a public-facing site with information for potential patients, or lawyers adding a public-facing site with information for potential clients. There's some information on the session and the usual approach would be to authenticate the user, persist the session information using the now-known user id, invalidate the existing session (to prevent certain types of attacks), the reload the session information before returning to the user. I can't just persist it under the session id since that's about to change. The glitch is that the existing application already has an SSO module and I get a 404 error every time I try to direct to j_security_check. I've tried that, /sso/j_security_check, even http://localhost/sso/j_security_check, all without success. I noticed that an earlier question said that tomcat requires access to a secured page before j_security_check is even visible. I don't know if that's the case with Oracle AS. Ideas? Or is the best approach to continue arguing that we have a different user base so it would be better to handle authentication in our own module anyway?

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  • how to delete a line from file using awk filtered by some string

    - by embedded
    I have a file delimited by space. I need to write an awk command that receives a host name argument and it should replace the host name if it already defined in the file. It must be a full match not partially - if the file contains this host name: localhost searching for "ho" will fail and it will be added to the end of the file. another option is a delete: again awk receives host name argument and it should remove it from the file if exists. This is what I have so far: (It needs some enhancements) if [ "$DELETE_FLAG" == "" ]; then # In this case the entry should be added or updated # if clause deals with updating an existing entry # END clause deals with adding a new entry awk -F"[ ]" "BEGIN { found = 0;} \ { \ if ($2 == $HOST_NAME) { \ print \"$IP_ADDRESS $HOST_NAME\"; \ found = 1; \ } else { \ print \$0; \ } \ } \ END { \ if (found == 0) { \ print \"$IP_ADDRESS $HOST_NAME\"; } \ } " \ /etc/hosts > /etc/temp_hosts else # Delete an existing entry awk -F'[ ]' '{if($2 != $HOST_NAME) { print $0} }' /etc/hosts > /etc/temp_hosts fi Thanks

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  • How do I format a Uri when binding an Image in Silverlight?

    - by Scott
    I haven't been able to find an answer to this. I have a database that has image paths in it ("images/myimage.jpg"). These images exist on my asp.net site which is also where I host the SL. I want to bind these images to my ListBox control so that the image displays. I have read that since I have a string value, "images/myimage.jpg", that I need to convert it to a BitMap image. I have done this: the xaml: <Image Source="{Binding ImageFile, Converter={StaticResource ImageConverter}}"/> the ImageConverter class: public object Convert(object value, Type targetType, object parameter, CultureInfo culture) { try { Uri source= new Uri(value.ToString()); return new BitmapImage(source); } catch(Exception ex) { return new BitmapImage(); } } I get an error when creating the Uri, "The Format of the URI could not be determined". What am I doing wrong? If I create a Uri that looks like this: http://localhost:49723/images/myimage.jpg, it works just fine. Why doesn't just "images/myimage.jpg" work?

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  • ruby on rails basics help

    - by CHID
    Hi, i created a scaffolded application in rails by the name of product. The product_controller.rb file contains the following. class ProductsController ApplicationController def new @product = Product.new respond_to do |format| format.html # new.html.erb format.xml { render :xml = @product } end end def create @product = Product.new(params[:product]) respond_to do |format| if @product.save flash[:notice] = 'Product was successfully created.' format.html { redirect_to(@product) } format.xml { render :xml = @product, :status = :created, :location = @product } else format.html { render :action = "new" } format.xml { render :xml = @product.errors, :status = :unprocessable_entity } end end end Now when the url http://localhost:3000/products/create is given Where new product link is clicked, control is transferred to new definition in the controller class and then an instance variable @product is created. BUT WHERE IS THIS VARIABLE PASSED? The funtion inturn calls new.rhtml which contains <% form_for(@product) do |f| % #all form elments declaration <% f.submit "Create" % <%= end % Here @product is initialized in the controller file and passed to this new.rhtml. So where does form_for(@product) gets the data? How does the control gets tranfered to create function in controller file when submit button is clicked? No where action is specified to the controller file. in the create function, wat does redirec_to(@product) specify where @product is an object received from the new.html file... I am very much confused on the basics of ROR. Somone pls help me clarify this. pardon me for making such a big post. I have lots of doubts in this single piece of code

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  • deployd authentification using jquery ajax

    - by user2507987
    I have installed deployd in my debian 7.0.0 64 bit, I have also succesfully installed mongodb in it, I have create some collection and user collection in deployd dashboard, then using user guide how to connect and query the table in deployd, I choose jquery ajax to log in to deployd from my localhost site and after login success I try to get/post some data, but somehow deployd return access denied. I have create collection name it people, and then at the GET, POST, PUT Event I have write this code : cancelUnless(me, "You are not logged in", 401); then using this ajax code, I try to login and POST new people data: $(document).ready(function(){ /* Create query for username and password for login */ var request = new Object; request.username = 'myusername'; request.password = 'mypassword'; submitaddress = "http://myipaddress:myport/users/login"; $.ajax({ type: "POST", url: submitaddress, data: request, cache: false, success: function(data){ var returndata = eval(data); /* After Login success try to post people data */ if (returndata){ var request2 = new Object; request2.name = 'People Name'; submitaddress2 = "http://myipaddress:myport/people"; $.ajax({ type: "POST", url: submitaddress2, data: request2, cache: false, success: function(){ } }) } } } }); }) The login process success, it's return session id and my user id, but after login success and I try to POST people data it's return "You are not logged in", can anyone help me, what is the correct way to login to deployd using jquery from other website(cross domain)?

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  • New user register, script auto create problems!

    - by SKY
    Hi, im currently trying to create a php script that when a new user register, a script (eg:wordpress,blog etc..) will install for them. I'm currently got the code below for just single setup, but how can i setup a form for multi user? which only allowing them to input the username (subdomain) and password. <?php class scriptname_Config { public static $title = 'new_script_title'; // Domain name and path where new script will installed in public static $domain = 'username.domain.com'; public static $absolutePath = '/new_register_username/'; // Settings for general mysql database public static $db = array( 'host' => 'localhost', 'database' => 'scriptname', 'user' => 'root', 'password' => '', 'prefix' => 'scriptname_' ); } define( 'scriptname_BASE_URL', 'http://'.scriptname_Config::$domain.scriptname_Config::$absolutePath ); ?> Or any tutorial that will help is appreciate! Thanks!

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  • How to do something when AVQueuePlayer finishes the last playeritem

    - by user1634529
    I've got an AVQueuePlayer which I'm creating from an array of 4 AVPlayerItems, and it all plays fine. I want to do something when the last item in the queue finishes playing, I've looked a load of answers on here and this is the one that looks most promising for what I want: The best way to execute code AFTER a sound has finished playing In my button handler i have this code: static const NSString *ItemStatusContext; [thePlayerItemA addObserver:self forKeyPath:@"status" options:0 context:&ItemStatusContext]; [[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(playerItemDidReachEnd) name:AVPlayerItemDidPlayToEndTimeNotification object:thePlayerItemA]; theQueuePlayer = [AVQueuePlayer playerWithPlayerItem:thePlayerItemA]; [theQueuePlayer play]; and then I have a function to handle playerItemDidReachEnd: - (void)playerItemDidReachEnd:(NSNotification *)notification { // Do stuff here NSLog(@"IT REACHED THE END"); } But when I run this I get an Internal Inconsistency Exception: An -observeValueForKeyPath:ofObject:change:context: message was received but not handled. Key path: status Observed object: <AVPlayerItem: 0x735a130, asset = <AVURLAsset: 0x73559c0, URL = file://localhost/Users/mike/Library/Application%20Support/iPhone%20Simulator/5.0/Applications/A0DBEC13-2DA6-4887-B29D-B43A78E173B8/Phonics%2001.app/yes.mp3>> Change: { kind = 1; } What am I doing wrong?

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  • jquery window.unload triggers post after unload

    - by index
    I am trying to do a post to server before unloading a page and I followed this and it's working fine. My problem is the $.post on window.unload is triggered after it has unloaded. I tried it with a signout link and checking on my logs, I get the following: Started GET "/signout" for 127.0.0.1 at 2012-11-22 00:15:08 +0800 Processing by SessionsController#destroy as HTML Redirected to http://localhost:3000/ Completed 302 Found in 1ms Started GET "/" for 127.0.0.1 at 2012-11-22 00:15:08 +0800 Processing by HomeController#index as HTML Rendered home/index.html.erb within layouts/application (0.4ms) Rendered layouts/_messages.html.erb (0.1ms) Completed 200 OK in 13ms (Views: 12.9ms) Started POST "/unloading" for 127.0.0.1 at 2012-11-22 00:15:08 +0800 Processing by HomeController#unloading as */* Parameters: {"p1"=>"1"} WARNING: Can't verify CSRF token authenticity Completed 500 Internal Server Error in 0ms NoMethodError (undefined method `id' for nil:NilClass): app/controllers/home_controller.rb:43:in `unloading' First part is the signout and then user gets redirected to root then it runs the post ('/unloading'). Is there a way to make the '/unloading' execute first then execute whatever the unload action was? I have this as my jquery post $(window).unload -> $.ajax { async: false, beforeSend: (xhr) -> xhr.setRequestHeader('X-CSRF-Token', $('meta[name="csrf-token"]').attr('content')) , url: '/unloading' , type: 'Post' , data: { p1: '1' } }

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  • Jython & Mysql - what is the current practice for connection?

    - by Sector7B
    Just trying jython for the first time, because something came up at work that would fit for this perfect for it. I assume jython can make mysql jdbc connection using the mysql jdbc driver. After googling and reading, however I am having problems and it seems jython specific and probably simple. so i do jython: Jython 2.5.1 (Release_2_5_1:6813, Sep 26 2009, 13:47:54) [Java HotSpot(TM) 64-Bit Server VM (Apple Inc.)] on java1.6.0_17 Type "help", "copyright", "credits" or "license" for more information. >>> import sys >>> print sys.path ['', '/JYTHONPATH/mysql-connector-java-5.1.10-bin.jar', '/WorkArea/Apps/jython/jython2.5.1/Lib', '__classpath__', '__pyclasspath__/', '/WorkArea/Apps/jython/jython2.5.1/Lib/site-packages'] >>> code i'm running from java.lang import * from java.sql import * driverName="com.mysql.jdbc.Driver" Class.forName(driverName) url = "jdbc:mysql://localhost/test?user=jgreenaw&password=" con = DriverManager.getConnection(url) stmt = con.createStatement() output riux:Desktop$ jython pymysql.py Traceback (most recent call last): File "pymysql.py", line 7, in <module> Class.forName(driverName) at java.net.URLClassLoader$1.run(URLClassLoader.java:200) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:188) at java.lang.ClassLoader.loadClass(ClassLoader.java:315) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:330) at java.lang.ClassLoader.loadClass(ClassLoader.java:250) at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:398) at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Class.java:169) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) java.lang.ClassNotFoundException: java.lang.ClassNotFoundException: com.mysql.jdbc.Driver any advice? thanks

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  • How to change database connection without compiling, using JBoss Seam?

    - by MLB
    Hi there: I am developing a web site in Eclipse using JBoss Seam 1.2. My site uses a database (named ALregcli) hosted in a MySQL server. That database has only one table named trazasfallos. The server I am using is local (localhost). When I deploy the site in an "X HOST", the MySQL server it is not in the same computer... the server is in an "Y HOST", so, the connection will not be stablished to the database. I was changing the Context.xml, but it didn't work. The only way it worked was changing the host to connect to in the Context.xml and "recompiling" all the project. Then, it generates the new version of the compiled class trazasfallos.class, and this is the file I have to overwrite for connecting to a new database server. The point is that I want to make the change without "recompiling" anything... Maybe there is a way to make only a "text change" and it will work (maybe in a .xml file)... but I don't know how to do it!! The question is: how to change the connection to the database without recompiling anything in the site?? I am sorry about my English, I am from Cuba.

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  • JQuery-AJAX: No further request after timeout and delay in form post

    - by Nogga
    I got a form containing multiple checkboxes. This form shall be sent to the server to receive appropriate results from a server side script. This is already working. What I would achieve now: 1) Implementing a timeout: This is already working, but as soon as a timeout occurs, a new request is not working anymore. 2) Implementing a delay in requesting results: A delay shall be implemented so that not every checkbox is resulting in a POST request. This is what I have right now: function update_listing() { // remove postings from table $('.tbl tbody').children('tr').remove(); // get the results through AJAX var request = $.ajax({ type: "POST", url: "http://localhost/hr/index.php/listing/ajax_csv", data: $("#listing_form").serialize(), timeout: 5000, success: function(data) { $(".tbl tbody").append(data); }, error: function(objAJAXRequest, strError) { $(".tbl tbody").append("<tr><td>failed " + strError + "</td></tr>"); } }); return true; } Results are for now passed as HTML table rows - I will transform them to CSV/JSON in the next step. Thanks so much for your advice.

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  • Why does PDO print my password when the connection fails?

    - by Joe Hopfgartner
    I have a simple website where I establish a connection to a Mysql server using PDO. $dbh = new PDO('mysql:host=localhost;dbname=DB;port=3306', 'USER', 'SECRET',array(PDO::MYSQL_ATTR_INIT_COMMAND => "SET NAMES utf8")); I had some traffic on my site and the servers connection limit was reached, and the website throw this error, with my PLAIN password in it! Fatal error: Uncaught exception 'PDOException' with message 'SQLSTATE[08004] [1040] Too many connections' in /home/premiumize-me/html/index.php:64 Stack trace: #0 /home/premiumize-me/html/index.php(64): PDO-__construct('mysql:host=loca...', 'USER', 'SECRET', Array) #1 {main} thrown in /home/premiumize-me/html/index.php on line 64 Ironically I switched to PDO for security reasons, this really shocked me. Because this exact error is something you can provoke very easily on most sites using simple http flooding. I now wrapped my conenction into a try/catch clause, but still. I think this is catastrophic! So I am new to PDO and my questino is: What do I have to consider to be safe! How to I establish a connection in a secure way? Are there other known security holes like this one that I have to be aware of?

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  • how can i make sure to get the server response correctly when i invoke the server with QNetworkReque

    - by noname
    I wrote the server site call in Qt, but i haven't get the server response for every server invoking. I have to use the server reply to continue the program flow. The request is correctly reached to server and server do reply.The server is also on my machine. Here is the code how i make the server site call; QNetworkAccessManager nam1 = new QNetworkAccessManager(this); qnetmg=nam1; QObject::connect(nam1, SIGNAL(finished(QNetworkReply*)),this,SLOT(finishedGettingMarker(QNetworkReply*))); QString strurl="http://localhost:8080/ServerWeb"; QUrl url(strurl); QNetworkRequest preq(url); QNetworkReply* reply = nam1->get(preq); qreply=reply; Inside finisedGettingMarker slot, i have already eliminate for QNetworkReply-error case and i used one global variable for QNetworkAccessManager;"qnetmg" and one global variable for QNetworkReply;"qreply". And also i make qnetmg.disconnect(this,0); and qreply.abort(); inside that slot method. But the problem is i haven't got the response for every server invoking time. If anyone who know the way to solve it , please reply me. This situation happened only in Opera. Thanks in advance.

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  • JDBC with JSP fails to insert

    - by StrykeR
    I am having some issues right now with JDBC in JSP. I am trying to insert username/pass ext into my MySQL DB. I am not getting any error or exception, however nothing is being inserted into my DB either. Below is my code, any help would be greatly appreciated. <% String uname=request.getParameter("userName"); String pword=request.getParameter("passWord"); String fname=request.getParameter("firstName"); String lname=request.getParameter("lastName"); String email=request.getParameter("emailAddress"); %> <% try{ String dbURL = "jdbc:mysql:localhost:3306/assi1"; String user = "root"; String pwd = "password"; String driver = "com.mysql.jdbc.Driver"; String query = "USE Users"+"INSERT INTO User (UserName, UserPass, FirstName, LastName, EmailAddress) " + "VALUES ('"+uname+"','"+pword+"','"+fname+"','"+lname+"','"+email+"')"; Class.forName(driver); Connection conn = DriverManager.getConnection(dbURL, user, pwd); Statement statement = conn.createStatement(); statement.executeUpdate(query); out.println("Data is successfully inserted!"); } catch(SQLException e){ for (Throwable t : e) t.printStackTrace(); } %> DB script here: CREATE DATABASE Users; use Users; CREATE TABLE User ( UserID INT NOT NULL AUTO_INCREMENT, UserName VARCHAR(20), UserPass VARCHAR(20), FirstName VARCHAR(30), LastName VARCHAR(35), EmailAddress VARCHAR(50), PRIMARY KEY (UserID) );

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  • Is this a safe PHP mail function?

    - by Eystein
    I've finally got this PHP email script working (didn't work on localhost…), but my concern is that it's not safe. So - is this safe for spamming and any other security pitfalls I'm not aware of? <?php $email = '[email protected]'; $subject = 'Notify about stuff'; $notify = $_REQUEST['email']; if (!preg_match("/\w+([-+.]\w+)*@\w+([-.]\w+)*\.\w+([-.]\w+)*/", $notify)) { echo "<h4>Your email address doesn't validate, please check that you typed it correct.</h4>"; echo "<a href='javascript:history.back(1);'>Back</a>"; } elseif(mail($email, $subject, $notify)) { echo "<h4>Thank you, you will be notified.</h4>"; } else { echo "<h4>Sorry, your email didn't get registered.</h4>"; } ?> Unrelated: is there a PHP function I can use instead of javascript:history.back(1) ?

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  • best way to avoid sql injection

    - by aauser
    I got similar domain model 1) User. Every user got many cities. @OneToMany(targetEntity=adv.domain.City.class...) 2) City. Every city got many districts @OneToMany(targetEntity=adv.domain.Distinct.class) 3) Distintc My goal is to delete distinct when user press delete button in browser. After that controller get id of distinct and pass it to bussiness layer. Where method DistinctService.deleteDistinct(Long distinctId) should delegate deliting to DAO layer. So my question is where to put security restrictions and what is the best way to accomplish it. I want to be sure that i delete distinct of the real user, that is the real owner of city, and city is the real owner of distinct. So nobody exept the owner can't delete ditinct using simple url like localhost/deleteDistinct/5. I can get user from httpSession in my controller and pass it to bussiness layer. After that i can get all cities of this user and itrate over them to be sure, that of the citie.id == distinct.city_id and then delete distinct. But it's rather ridiculous in my opinion. Also i can write sql query like this ... delete from t_distinct where t_distinct.city_id in (select t_city.id from t_city left join t_user on t_user.id = t_city.owner_id where t_user.id = ?) and t_distinct.id = ? So what is the best practice to add restrictions like this. I'm using Hibernate, Spring, Spring MVC by the way.. Thank you

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  • Javascript ( jQuery ) Error: SyntaxError: missing ) after argument list

    - by Obmerk Kronen
    I have the simplest function : jQuery(document).ajaxSuccess(function(e, xhr, settings) { var widget_id_base = '099_cf_samurai_widget'; if(settings.data.search('action=save-widget') != -1 && settings.data.search('id_base=' + widget_id_base) != -1) { // alert(\'yay!'\); my_function_chosen_099(); } }); function my_function_chosen_099(){ jQuery(".chzn-select").chosen(); } which works just fine , but When I add the width Parameter like so : function my_function_chosen_k99(){ jQuery(".chzn-select").chosen(width:'95%'); } it gives me an error of: Error: SyntaxError: missing ) after argument list Source File: http://localhost/my-path/js/o99.chosen.init.js?ver=k99 Line: 20, Column: 41 Source Code: jQuery(".chzn-select").chosen(width:"95%"); .............................................| I have tried escaping: jQuery(".chzn-select").chosen(width:\"95%"\); and even double jQuery(".chzn-select").chosen(width:\\"95%"\\); and in my desperation, even jQuery(".chzn-select").chosen( width:"95%" ); I checked and rechecked the closing of brackets , and also tried with single quotes ' - but nothing . There appear to be a lot of similar questions here , but all I saw was escaping problems, ANd I have tried all that I know .. What is wrong here ?? I assume it is not a simple syntax error - or is it ? ( one which I can not find .. )

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  • Properly handling NSURLConnection errors

    - by Cal S
    Hi, I have a simple form interface set up that send username and password information to a server: (working) NSString *postData = [NSString stringWithFormat:@"user=%@&pass=%@",[self urlEncodeValue:sysUsername],[self urlEncodeValue:password]]; NSLog(@"Post data -> %@", postData); /// NSData* postVariables = [postData dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES]; NSMutableURLRequest* request = [[[NSMutableURLRequest alloc] init] autorelease]; NSString* postLength = [NSString stringWithFormat:@"%d", [postVariables length]]; NSURL* postUrl = [NSURL URLWithString:@"http://localhost/~csmith/cocoa/test.php"]; [request setURL:postUrl]; [request setHTTPMethod:@"POST"]; [request setValue:postLength forHTTPHeaderField:@"Content-Length"]; [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"]; [request setHTTPBody: postVariables]; NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:NULL error:NULL]; NSLog(@"Post data SENT & returned -> %@", returnData); How do I handle connection errors such as no internet connection, firewall, etc. Also, does this method use the system-wide proxy settings? Many of my users are behind a proxy. Thanks a lot!

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  • How to ensure nginx serves a request from an external IP?

    - by Matt
    I have a strange situation, where my nginx setup stopped handling external requests. I'm pretty stuck. If I hit the domain without a subdomain, I properly get redirected, however, if I request the full url, that fails and doesn't log anything, anywhere. I am able to curl localhost on the server itself, however when I attempt to curl from an external machine, it fails with: curl: (7) couldn't connect to host I've also noticed that bots can get through, I've seen Google hit the log every now and then. My nginx.conf file: upstream mongrels { server 127.0.0.1:5000; } server { listen 80; server_name culini.com; rewrite ^/(.*) http://www.culini.com/$1 permanent; } # the server directive is nginx's virtual host directive. server { # port to listen on. Can also be set to an IP:PORT listen 80; # Set the max size for file uploads to 50Mb client_max_body_size 50M; # sets the domain[s] that this vhost server requests for server_name www.culini.com; # doc root root /var/www/culini/current/public; log_format app '$remote_addr - $remote_user [$time_local] ' '"$request" $status $body_bytes_sent "$http_referer" ' '"$http_user_agent" "$http_x_forwarded_for" [$upstream_addr $upstream_response_time $upstream_status]'; # vhost specific access log access_log /var/www/culini/current/log/nginx.access.log app; error_log /var/www/culini/current/log/nginx.error.log debug; location / { proxy_set_header X-Real-IP $remote_addr; proxy_set_header X-Forwarded-For $proxy_add_x_forwarded_for; proxy_set_header Host $http_host; proxy_redirect false; proxy_max_temp_file_size 0; proxy_intercept_errors on; proxy_ignore_client_abort on; if (-f $request_filename) { break; } if (!-f $request_filename) { proxy_pass http://mongrels; break; } } } Please, please, any help would be greatly appreciated.

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  • java.lang.ClassNotFoundException: com.mysql.jdbc.Driver When run jar file

    - by user1024858
    Hi all, Connection conn = null; String url = "jdbc:mysql://localhost:3306/"; String dbName = "test"; String driver = "com.mysql.jdbc.Driver"; String userName = "root"; String password = "admin"; try { Class.forName(driver).newInstance(); conn = DriverManager.getConnection(url+dbName,userName,password); System.out.println("Connected to the database"); conn.close(); System.out.println("Disconnected from database"); } catch (Exception e) { e.printStackTrace();} I run in eclipse it's ok, but i built to jar file and run on command line java -jar Test.jar i get this error: java.lang.ClassNotFoundException: com.mysql.jdbc.Driver at java.net.URLClassLoader$1.run(Unknown Source) at java.net.URLClassLoader$1.run(Unknown Source) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(Unknown Source) at java.lang.ClassLoader.loadClass(Unknown Source) at sun.misc.Launcher$AppClassLoader.loadClass(Unknown Source) at java.lang.ClassLoader.loadClass(Unknown Source) at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Unknown Source) Please help me how to fix it. Thanks!!!

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