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  • Sending emails with CodeIgniter in a local XAMPP server

    - by KeyStroke
    Hi, I'm trying to send emails through localhost (XAMPP Windows 1.7.3 installation), but I've been trying for hours with no success. This is the last code I tried: $config = Array( 'protocol' => 'smtp', 'smtp_host' => 'ssl://smtp.gmail.com', 'smtp_port' => 465, 'smtp_user' => '[email protected]', 'smtp_pass' => 'mypassword', ); $this->load->library('email', $config); $this->email->set_newline("\r\n"); $this->email->from('[email protected]', 'My Name'); $this->email->to('[email protected]'); $this->email->subject('Email Test'); $this->email->message('Testing the email class.'); if($this->email->send()) { echo 'Your email was sent.'; } else { show_error($this->email->print_debugger()); } Whenever I tried to load this the page shows that it's loading but nothing happens. Is there anything I need to setup in my server to insure email delivery? I messed with php.ini and sendmail's config a bit with no luck. And openSSL isn't available in case that matters. Any idea what's wrong?

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  • Codeigniter .htaccess not working in subdirectory

    - by xzdead
    I have this codeingniter project structure webRoot | |/application | | | |/controllers | | | |/admin | |/public | | | |/admin | | | | | |/css | | |/img | |/css | |/img And this is my .htacess file, located in /public. I use this in every local project running xampp: <IfModule mod_rewrite.c> RewriteEngine On RewriteBase / RewriteCond %{REQUEST_FILENAME} !-f RewriteRule ^(.*)$ index.php/$1 [L] </IfModule> <IfModule !mod_rewrite.c> # If we don't have mod_rewrite installed, all 404's # can be sent to index.php, and everything works as normal. # Submitted by: ElliotHaughin ErrorDocument 404 /index.php </IfModule> It works fine in localhost, but doesn't work in a dreamhost server. I always get "no input file specified". So after searching the web and trying lots of combinations, the best I got is this .htaccess file: Options +FollowSymLinks RewriteEngine On RewriteCond %{REQUEST_FILENAME} !-d RewriteCond %{REQUEST_FILENAME} !-f RewriteRule ^ index.php [L] With this one, if I go to http://development.mydomain.com - I see the codeigniter welcome page But if I go to: http://development.mydomain.com/admin - I see the directory listing of /public/admin and doesn't execute the controller in /application/controllers/admin Again, if I go to: http://development.mydomain.com/admin/admin - I see the private area, it executes the controller and goes to the default controller defined in routes, "dashboard" This works fine too: http://development.mydomain.com/admin/dashboard I have set in my config file: $config['index_page'] = ''; $config['base_url'] = ''; $config['uri_protocol'] = 'AUTO'; I think that whatever is wrong in my .htaccess is causing other path issues I have with my project. Any help would be great. Thanks to all in advance EDIT: I removed this line: RewriteCond %{REQUEST_FILENAME} !-d because admin directory exists, that's why I see the public directory listing. But now I see the codeigniter welcome page when I go to http://development.mydomain.com/admin So now my .htaccess file looks like: Options +FollowSymLinks RewriteEngine On RewriteCond %{REQUEST_FILENAME} !-f RewriteRule ^ index.php [L] #RewriteRule ^(.*)$ /index.php?/$1 [L] I also tried with the commented RewriteRule but I get the same result.

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  • mysql to excel genration using php

    - by pmms
    <?php // DB Connection here mysql_connect("localhost","root",""); mysql_select_db("hitnrunf_db"); $select = "SELECT * FROM jos_users "; $export = mysql_query ( $select ) or die ( "Sql error : " . mysql_error( ) ); $fields = mysql_num_fields ( $export ); for ( $i = 0; $i < $fields; $i++ ) { $header .= mysql_field_name( $export , $i ) . "\t"; } while( $row = mysql_fetch_row( $export ) ) { $line = ''; foreach( $row as $value ) { if ( ( !isset( $value ) ) || ( $value == "" ) ) { $value = "\t"; } else { $value = str_replace( '"' , '""' , $value ); $value = '"' . $value . '"' . "\t"; } $line .= $value; } $data .= trim( $line ) . "\n"; } $data = str_replace( "\r" , "" , $data ); if ( $data == "" ) { $data = "\n(0) Records Found!\n"; } header("Content-type: application/octet-stream"); header("Content-Disposition: attachment; filename=your_desired_name.xls"); header("Pragma: no-cache"); header("Expires: 0"); print "$header\n$data"; ? the above code is used for genrating mysql to excel sheet but we are getting following error the file youare trying to open, 'users.xls',is in a different format than specified by the file extension. verify that the file is not corrupted and is from a trusted source before opening the file. do you want to open the file now?

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  • SQL query error while trying to put a file in the database

    - by DaGhostman Dimitrov
    Hey Guys I have a big problem that I have no Idea why.. I have few forms that upload files to the database, all of them work fine except one.. I use the same query in all(simple insert). I think that it has something to do with the files i am trying to upload but I am not sure. Here is the code: if ($_POST['action'] == 'hndlDocs') { $ref = $_POST['reference']; // Numeric value of $doc = file_get_contents($_FILES['doc']['tmp_name']); $link = mysqli_connect('localhost','XXXXX','XXXXX','documents'); mysqli_query($link,"SET autocommit = 0"); $query = "INSERT INTO documents ({$ref}, '{$doc}', '{$_FILES['doc']['type']}') ;"; mysqli_query($link,$query); if (mysqli_error($link)) { var_dump(mysqli_error($link)); mysqli_rollback($link); } else { print("<script> window.history.back(); </script>"); mysqli_commit($link); } } The database has only these fields: DATABASE documents ( reference INT(5) NOT NULL, //it is unsigned zerofill doc LONGBLOB NOT NULL, //this should contain the binary data mime_type TEXT NOT NULL // the mime type of the file php allows only application/pdf and image/jpeg ); And the error I get is : You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '00001, '????' at line 1 I will appreciate every help. Cheers!

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  • Nested Routes Show Action: What objects does it expect?

    - by NoahClark
    Here is the relevant line from my rake routes: client_note GET /clients/:client_id/notes/:id(.:format) notes#show When I try passing in the objects like <%= client_note_path([client, @notes.first]) %>> I get: No route matches {:action=>"show", :controller=>"notes", :client_id=>[#<Client id: 5, ... , #<Note id: 9, ...]} Which made me think to try a client ID. So, I tried: <%= client_note_path([client.id, @notes.first]) %> which gives me: No route matches {:action=>"show", :controller=>"notes", :client_id=>[5, #<Note id: 9,content: "He just bought a brand new bobcat, be sure to charg...", client_id: 5, created_at: "2012-06-11 16:18:16", updated_at: "2012-06-11 16:18:16">]} Which, made me want to try just passing in a client ID. <%= client_note_path(client.id) %> No route matches {:action=>"show", :controller=>"notes", :client_id=>5} Still not what I'm looking for. I want to be able to show an individual note which can normally be found at a url like looks like: http://localhost:3000/clients/2/notes/3/

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  • tomcat wont start up on linux machine

    - by David
    hi, im new to linux but after spending the day i have got linux running. installed java and tomcat. my goal is host my app with this linux box i've just set up. i know it all works fine from my windows based machine but it is my laptop so i'm planning this as my dedicated server. following many many forums i've now got tomcat 7 installed. however i cannot get it to start. changing to the tomcat directory and "./startup.sh" i get output Using CATALINA_BASE: /usr/local/tomcat Using CATALINA_HOME: /usr/local.tomcat Using CATALINA_TMPDIR: /usr/local/tomcat/temp Using JRE_HOME: usr/lib/jvm/java-6-sun/ Using CLASSPATH: /usr/local/tomcat/bin/bootstrap.jar:/usr/local.tomcat/bin/c\tomcat-juli.jar thats the end of theoutput. however localhost:8080 is not up. and in the tomcat log file is the error "eval: 1: usr/lib/jvm/java-6-sun//bin/java: not found" hopfully there is some expert here who can help me with this problem. please note that im a novice when it comes to linux. thankyou oh and my version of linux is Ubuntu 10.04 LTS - the Lucid Lynx

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  • Discusses some issues related to mvc2.0

    - by hao123
    ???????????????,???????? ??: ???????:1????????2????????3???? ?????????????? ??????:1???????:http://demo.com/admin/News/index 2???????:http://demo.com/s7mmer/News/index 3?????:http://demo.com/News/index ??asp.net mvc1.0???????????,?????,??asp.net mvc2.0???Areas?? ??: ???????,?????????????Admin?areas,??VS?????????????areas????,????????????????? ??????????: 1?????????Areas???? 2??Areas ???????? 3?????,?Areas?????????MyAreaRegistration.cs ????: ?? using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.Mvc; using System.Web.Routing; namespace S7mmer.Web { public class AdminAreaRegistration : AreaRegistration { public override string AreaName { get { return "Admin"; } } public override void RegisterArea(AreaRegistrationContext context) { //?????????? context.MapRoute( "AdminController_default", "Admin/{controller}/{action}/{id}", new { controller = "Home", action = "Index", id = "" }, // Parameter defaults new string[] { "S7mmer.Web.Areas.Admin.Controllers" }//controllers????? ); } } public class S7mmerAreaRegistration : AreaRegistration { public override string AreaName { get { return "S7mmer"; } } public override void RegisterArea(AreaRegistrationContext context) { //?????????? context.MapRoute( "S7mmerController_default", "S7mmer/{controller}/{action}/{id}", new { controller = "Home", action = "Index", id = "" }, // Parameter defaults new string[] { "S7mmer.Web.Areas.S7mmer.Controllers" }//controllers????? ); } } public class WebSiteAreaRegistration : AreaRegistration { public override string AreaName { get { return "WebSite"; } } public override void RegisterArea(AreaRegistrationContext context) { //?????????? context.MapRoute( "WebSiteController_default", "{controller}/{action}/{id}", new { controller = "Home", action = "Index", id = "" }, // Parameter defaults new string[] { "S7mmer.Web.Areas.WebSite.Controllers" }//controllers????? ); } } } 4??Areas?????Admin????????NewsController.cs 5??NewsController.cs??public ActionResult Index()?????view,??? ???news????index.aspx 6????????Global.asax??,?Application_Start()????AreaRegistration.RegisterAllAreas(); protected void Application_Start() { AreaRegistration.RegisterAllAreas(); // RegisterRoutes(RouteTable.Routes); } ????? http://localhost:1108/admin/News/index,??????????! ??????????????????,???????????????,????

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  • Why do you have to call URLConnection#getInputStream to be able to write out to URLConnection#getOutputStream?

    - by John
    I'm trying to write out to URLConnection#getOutputStream, however, no data is actually sent until I call URLConnection#getInputStream. Even if I set URLConnnection#doInput to false, it still will not send. Does anyone know why this is? There's nothing in the API documentation that describes this. Java API Documentation on URLConnection: http://download.oracle.com/javase/6/docs/api/java/net/URLConnection.html Java's Tutorial on Reading from and Writing to a URLConnection: http://download.oracle.com/javase/tutorial/networking/urls/readingWriting.html import java.io.IOException; import java.io.OutputStreamWriter; import java.net.URL; import java.net.URLConnection; public class UrlConnectionTest { private static final String TEST_URL = "http://localhost:3000/test/hitme"; public static void main(String[] args) throws IOException { URLConnection urlCon = null; URL url = null; OutputStreamWriter osw = null; try { url = new URL(TEST_URL); urlCon = url.openConnection(); urlCon.setDoOutput(true); urlCon.setRequestProperty("Content-Type", "text/plain"); //////////////////////////////////////// // SETTING THIS TO FALSE DOES NOTHING // //////////////////////////////////////// // urlCon.setDoInput(false); osw = new OutputStreamWriter(urlCon.getOutputStream()); osw.write("HELLO WORLD"); osw.flush(); ///////////////////////////////////////////////// // MUST CALL THIS OTHERWISE WILL NOT WRITE OUT // ///////////////////////////////////////////////// urlCon.getInputStream(); ///////////////////////////////////////////////////////////////////////////////////////////////////////// // If getInputStream is called while doInput=false, the following exception is thrown: // // java.net.ProtocolException: Cannot read from URLConnection if doInput=false (call setDoInput(true)) // ///////////////////////////////////////////////////////////////////////////////////////////////////////// } catch (Exception e) { e.printStackTrace(); } finally { if (osw != null) { osw.close(); } } } }

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  • javax.xml.bind.MarshalException

    - by sandeep
    Hi, I am getting javax.xml.bind.MarshalException error. I am sending List from my webservice to the backingbean and I have this error. Here is my code: Backing bean @WebServiceRef(wsdlLocation = "http://localhost:26565/Login_webserviceService/Login_webservice?WSDL") public String login() { System.out.println("Login Phase entered"); int result = 0; List list; List finalList = null; try { Weblogin.LoginWebserviceService service = new Weblogin.LoginWebserviceService(); Weblogin.LoginWebservice port = service.getLoginWebservicePort(); result = port.login(voterID, password); Weblogin.LoginWebservice port1 = service.getLoginWebservicePort(); list = port1.candDetails(1); finalList = list; this.setList(finalList); } catch (Exception e) { e.printStackTrace(); } if (result == 1) return "polling"; else return "login"; } Webservice public List candDetails(int pollEvent) { List resultList = null; List finalList = null; try { if (pollEvent == 1) { resultList = em.createNamedQuery("Cantable.findAll").getResultList(); finalList = resultList; } } catch (Exception e) { e.printStackTrace(); } return resultList; }

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  • Issue selenium code maintenance

    - by Rajasankar
    I want to group the common methods in one file and use it. For example, login to a page using selenium may be used in multiple times. Define that in class A and call it in class B. However, it throws null pointer exception. class A has public void test_Login() throws Exception { try{ selenium.setTimeout("60000"); selenium.open("http://localhost"); selenium.windowFocus(); selenium.windowMaximize(); selenium.windowFocus(); selenium.type("userName", "admin"); selenium.type("password", "admin"); Result=selenium.isElementPresent("//input[@type='image']"); selenium.click("//input[@type='image']"); selenium.waitForPageToLoad(Timeout); } catch(Exception ex) { System.out.println(ex); ex.printStackTrace(); } } with all other java syntax in class B public void test_kk() throws Exception { try { a.test_Login(); } catch(Exception ex) { System.out.println(ex); ex.printStackTrace(); } } with all syntax. When I execute class B, I got this error, java.lang.NullPointerException at A.test_Login(A.java:32) at B.test_kk(savefile.java:58) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source) at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source) at java.lang.reflect.Method.invoke(Unknown Source) at junit.framework.TestCase.runTest(TestCase.java:168) at junit.framework.TestCase.runBare(TestCase.java:134) at com.thoughtworks.selenium.SeleneseTestCase.runBare(SeleneseTestCase.j ava:212) at junit.framework.TestResult$1.protect(TestResult.java:110) at junit.framework.TestResult.runProtected(TestResult.java:128) at junit.framework.TestResult.run(TestResult.java:113) at junit.framework.TestCase.run(TestCase.java:124) at junit.framework.TestSuite.runTest(TestSuite.java:232) at junit.framework.TestSuite.run(TestSuite.java:227) at junit.textui.TestRunner.doRun(TestRunner.java:116) at junit.textui.TestRunner.doRun(TestRunner.java:109) at junit.textui.TestRunner.run(TestRunner.java:77) at B.main(B.java:77) I hope someone must have tried this before. I may miss something here.

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  • C# Linq to SQL connection string (newbie)

    - by Chris'o
    i am a new linq to sql learner and this is my very first attempt to create a data viewer program. The idea is simple, i'd like to create a software that is able to view content of a table in a database. That's it. I got an early problem here already and i have seen many tutes and articles online but I still cant fix the bug. Here is my code: static void Main(string[] args) { string cs = "Data Source=localhost;Initial Catalog=somedb;Integrated Security=SSPI;"; var db = new DataClasses1DataContext(cs); db.Connection.Open(); foreach (var b in db.Mapping.GetTables()) Console.WriteLine(b.TableName); Console.ReadKey(true); } When I tried to check db.connection.equals(null); it returns false, so i thought i have connected successfully to the database since there is no error at all. But the code above doesn't print anything out to the screen. I kind of lost and don't know what's going on here. Does anyone know what is going wrong here?

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  • Storing data in a MySQL database using MySQL & PHP

    - by comma
    I'm new to PHP and MySQL and I'm trying to store a users entered data from the following fields $skill, $experience, $years which a user can also add additional fields of $skill, $experience, $years if needed so in instead of 1 of each field there might be multiples of each field. I was wondering how can I store the fields in my MySQL database using PHP and MySQL? I have the following script but I know its wrong. can some one help me fix the script listed below? Here is the PHP and MySQL code. $skill = serialize($_POST['skill']); $experience = serialize($_POST['experience']); $years = serialize($_POST['years']); for (($s = 0; $s < count($skill); $s++) && ($x = 0; $x < count($experience); $x++) && ($g = 0; $g < count($years); $g++)){ $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $query1 = "INSERT INTO learned_skills (skill, experience, years) VALUES ('" . $skill[$s] . "', '" . $experience[$x] . "', '" . $years[$g] . "')"; if (!mysqli_query($mysqli, $query1)) { print mysqli_error($mysqli); return; } } Here is my MySQL table. CREATE TABLE learned_skills ( id INT UNSIGNED NOT NULL AUTO_INCREMENT, skill TEXT NOT NULL, experience TEXT NOT NULL, years INT NOT NULL, PRIMARY KEY (id) ); CREATE TABLE u_skills ( id INT UNSIGNED NOT NULL AUTO_INCREMENT, skill_id INT UNSIGNED NOT NULL, users_id INT UNSIGNED NOT NULL, PRIMARY KEY (id) );

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  • Parsing large txt files in ruby taking a lot of time?

    - by hershey92
    below is the code to download a txt file from internet approx 9000 lines and populate the database, I have tried a lot but it takes a lot of time more than 7 minutes. I am using win 7 64 bit and ruby 1.9.3. Is there a way to do it faster ?? require 'open-uri' require 'dbi' dbh = DBI.connect("DBI:Mysql:mfmodel:localhost","root","") #file = open('http://www.amfiindia.com/spages/NAV0.txt') file = File.open('test.txt','r') lines = file.lines 2.times { lines.next } curSubType = '' curType = '' curCompName = '' lines.each do |line| line.strip! if line[-1] == ')' curType,curSubType = line.split('(') curSubType.chop! elsif line[-4..-1] == 'Fund' curCompName = line.split(" Mutual Fund")[0] elsif line == '' next else sCode,isin_div,isin_re,sName,nav,rePrice,salePrice,date = line.split(';') sCode = Integer(sCode) sth = dbh.prepare "call mfmodel.populate(?,?,?,?,?,?,?)" sth.execute curCompName,curSubType,curType,sCode,isin_div,isin_re,sName end end dbh.do "commit" dbh.disconnect file.close 106799;-;-;HDFC ARBITRAGE FUND RETAIL PLAN DIVIDEND OPTION;10.352;10.3;10.352;29-Jun-2012 This is the format of data to be inserted in the table. Now there are 8000 such lines and how can I do an insert by combining all that and call the procedure just once. Also, does mysql support arrays and iteration to do such a thing inside the routine. Please give your suggestions.Thanks.

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  • after assembling jar - No Persistence provider for EntityManager named ....

    - by alabalaa
    im developing a standalone application and it works fine when starting it from my ide(intellij idea), but after creating an uberjar and start the application from it javax.persistence.spi.PersistenceProvider is thrown saying "No Persistence provider for EntityManager named testPU" here is my persistence.xml which is placed under meta-inf directory: <persistence-unit name="testPU" transaction-type="RESOURCE_LOCAL"> <provider>org.hibernate.ejb.HibernatePersistence</provider> <class>test.model.Configuration</class> <properties> <property name="hibernate.connection.username" value="root"/> <property name="hibernate.connection.driver_class" value="com.mysql.jdbc.Driver"/> <property name="hibernate.connection.password" value="root"/> <property name="hibernate.connection.url" value="jdbc:mysql://localhost:3306/test"/> <property name="hibernate.show_sql" value="true"/> <property name="hibernate.dialect" value="org.hibernate.dialect.MySQLInnoDBDialect"/> <property name="hibernate.c3p0.timeout" value="300"/> <property name="hibernate.hbm2ddl.auto" value="update"/> </properties> </persistence-unit> and here is how im creating the entity manager factory: emf = Persistence.createEntityManagerFactory("testPU"); im using maven and tried the assembly plug-in with the default configuration fot it, i dont have much experience with assembling jars and i dont know if im missing something, so if u have any ideas ill be glad to hear them

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  • No operations allowed after statement closed issue

    - by Washu
    I have the next methods in my singleton to execute the JDBC connections public void openDB() throws ClassNotFoundException, IllegalAccessException, InstantiationException, SQLException { Class.forName("com.mysql.jdbc.Driver").newInstance(); String url = "jdbc:mysql://localhost/mbpe_peru";//mydb conn = DriverManager.getConnection(url, "root", "admin"); st = conn.createStatement(); } public void sendQuery(String query) throws SQLException { st.executeUpdate(query); } public void closeDB() throws SQLException { st.close(); conn.close(); } And I'm having a problem in a void where i have to call this twice. private void jButton1ActionPerformed(ActionEvent evt) { Main.getInstance().openDB(); Main.getInstance().sendQuery("call insertEntry('"+EntryID()+"','"+SupplierID()+"');"); Main.getInstance().closeDB(); Main.getInstance().openDB(); for(int i=0;i<dataBox.length;i++){ Main.getInstance().sendQuery("call insertCount('"+EntryID()+"','"+SupplierID()+"','"+BoxID()+"'); Main.getInstance().closeDB(); } } I have already tried to keep the connection open and send the 2 querys and after that closed and it didnt work... The only way it worked was to not use the methods, declare the commands for the connection and use different variables for the connection and the statement. I thought that if i close the Connecion and the Statement I could use the variable once again since is a method but I'm not able to. Is there any way to solve this using my methods for the JDBC connection?

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  • Cant fetch production db results using Google app engine remote_api

    - by Alon
    Hey, im trying to work out with /remote_api with a django-patch app engine app i got running. i want to select a few rows from my online production app locally. i cant seem to manage todo so, everything authenticates fine, it doesnt breaks on imports, but when i try to fetch something it just doesnt print anything. Placed the test python inside my local app dir. #!/usr/bin/env python # import os import sys # Hardwire in appengine modules to PYTHONPATH # or use wrapper to do it more elegantly appengine_dirs = ['myworkingpath'] sys.path.extend(appengine_dirs) # Add your models to path my_root_dir = os.path.abspath(os.path.dirname(__file__)) sys.path.insert(0, my_root_dir) from google.appengine.ext import db from google.appengine.ext.remote_api import remote_api_stub import getpass APP_NAME = 'Myappname' os.environ['AUTH_DOMAIN'] = 'gmail.com' os.environ['USER_EMAIL'] = '[email protected]' def auth_func(): return (raw_input('Username:'), getpass.getpass('Password:')) # Use local dev server by passing in as parameter: # servername='localhost:8080' # Otherwise, remote_api assumes you are targeting APP_NAME.appspot.com remote_api_stub.ConfigureRemoteDatastore(APP_NAME, '/remote_api', auth_func) # Do stuff like your code was running on App Engine from channel.models import Channel, Channel2Operator myresults = mymodel.all().fetch(10) for result in myresults: print result.key() it doesnt give any error or print anything. so does the remote_api console example google got. when i print the myresults i get [].

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  • Assigning values to the lable through database depending on listbox values

    - by SurajVitekar
    I want to assign the values of five labels from database regarding to values selected in listbox. The db query returns single column with multiple records. Please help. I'm working with C# 2010 and MS SQL. My current code is: private void listBox1_SelectedIndexChanged(object sender, EventArgs e) { try { String c1, c2; c1 = "NULL"; MessageBox.Show("LB index :"+listBox1.SelectedIndex.ToString()); //p = listBox1.SelectedItem.ToString(); SqlConnection con = new SqlConnection(); con.ConnectionString = "Data Source=localhost;Initial Catalog=eVoting;Integrated Security=True;Pooling=False"; con.Open(); MessageBox.Show("List bOx sect :"+listBox1.SelectedValue.ToString()); SqlCommand cmd = new SqlCommand("select Firstname from candidates where position ='" + listBox1.SelectedValue.ToString() + "'", con); int index = 0; SqlDataReader reader = cmd.ExecuteReader(); while(reader.Read()) { if (index == 0) { c1 = reader[index].ToString(); radioButton1.Text = c1; } if (index == 1) { c1 = reader[index].ToString(); radioButton2.Text = c1; } if (index == 2) { c1 = reader[index].ToString(); radioButton3.Text = c1; } if (index == 3) { c1 = reader[index].ToString(); radioButton4.Text = c1; } if (index == 4) { c1 = reader[index].ToString(); radioButton4.Text = c1; } if (index == 5) { c1 = reader[index].ToString(); radioButton5.Text = c1; } MessageBox.Show("c1 :" + c1); index++; } } catch (Exception E) { } }

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  • Exploiting Path Traversal Vulnerability

    - by Maputo
    I have a Java Web App running on Tomcat on which I'm supposed to exploit Path traversal vulnerability. There is a section (in the App) at which I can upload a .zip file, which gets extracted in the server's /tmp directory. The content of the .zip file is not being checked, so basically I could put anything in it. I tried putting a .jsp file in it and it extracts perfectly. My problem is that I don't know how to reach this file as a "normal" user from browser. I tried entering ../../../tmp/somepage.jsp in the address bar, but Tomcat just strips the ../ and gives me http://localhost:8080/tmp/ resource not available. Ideal would be if I could somehow rename the somepage.jsp so that it gets extracted in the web directory of the Web App. But then, the Linux filesystem disallows slashes in filenames (e.g. ../../home/webapp/somepage.jsp). Are there maybe any escape sequences that would translate to / after extracting? Any ideas would be highly appreciated. Note: This is a school project in a Security course where I'm supposed to locate vulnerabilities and correct them. Not trying to harm anyone...

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  • how to get response from remote server

    - by ruhit
    I have made a desktop application in asp.net using c# that connecting with remote server.I am able to connect but how do i show that my login is successful or not. After that i want to retrieve data from the remote server..........so plz help me.I have written the below code..............is there any better way try { string strId = UserId_TextBox.Text; string strpasswrd = Password_TextBox.Text; ASCIIEncoding encoding = new ASCIIEncoding(); string postData = "UM_email=" + strId; postData += ("&UM_password=" + strpasswrd); byte[] data = encoding.GetBytes(postData); MessageBox.Show(postData); // Prepare web request... //HttpWebRequest myRequest = (HttpWebRequest)WebRequest.Create("http://localhost/ruhit/basic_framework/index.php?menu=login=" + postData); HttpWebRequest myRequest =(HttpWebRequest)WebRequest.Create("http://www.facebook.com/login.php=" + postData); myRequest.Method = "POST"; myRequest.ContentType = "application/x-www-form-urlencoded"; myRequest.ContentLength = data.Length; Stream newStream = myRequest.GetRequestStream(); // Send the data. newStream.Write(data, 0, data.Length); MessageBox.Show("u r now connected"); HttpWebResponse response = (HttpWebResponse)myRequest.GetResponse(); // WebResponse response = myRequest.GetResponse(); StreamReader reader = new StreamReader(response.GetResponseStream()); string str = reader.ReadLine(); while (str != null) { str = reader.ReadLine(); MessageBox.Show(str); } reader.Close(); newStream.Close(); } catch { MessageBox.Show("error connecting"); }

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  • before filter not working as expected

    - by Jimmy
    Hey guys I have a ruby on rails app with a before filter setup in my application controller to ensure only the owner can edit a document, but my permission check is always failing even when it shouldn't. Here is the code: def get_logged_in_user id = session[:user_id] unless id.nil? @current_user = User.find(id) end end def require_login get_logged_in_user if @current_user.nil? session[:original_uri] = request.request_uri flash[:notice] = "You must login first." redirect_to login end end def check_current_user_permission require_login logger.debug "user id is #{params[:user_id]}" logger.debug "current user id is #{session[:user_id]}" if session[:user_id] != params[:user_id] flash[:notice] = "You don't have permission to do that." redirect_to :controller => 'home' end end The code to note is in the check_current_user_permission. Here is an example of my log output: user id is 3 current user id is 3 Redirected to http://localhost:3000/home Filter chain halted as [:check_current_user_permission] rendered_or_redirected. Can anyone shed some light into why this is failing? Obviously the user_id of 3 is equal to the session's user_id of 3. What is going wrong?

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  • Perl TCP Server handling multiple Client connections

    - by Matt
    I'll preface this by saying I have minimal experience with both Perl and Socket programming, so I appreciate any help I can get. I have a TCP Server which needs to handle multiple Client connections simultaneously and be able to receive data from any one of the Clients at any time and also be able to send data back to the Clients based on information it's received. For example, Client1 and Client2 connect to my Server. Client2 sends "Ready", the server interprets that and sends "Go" to Client1. The following is what I have written so far: my $sock = new IO::Socket::INET { LocalHost => $host, // defined earlier in code LocalPort => $port, // defined earlier in code Proto => 'tcp', Listen => SOMAXCONN, Reuse => 1, }; die "Could not create socket $!\n" unless $sock; while ( my ($new_sock,$c_addr) = $sock->accept() ) { my ($client_port, $c_ip) = sockaddr_in($c_addr); my $client_ipnum = inet_ntoa($c_ip); my $client_host = ""; my @threads; print "got a connection from $client_host", "[$client_ipnum]\n"; my $command; my $data; while ($data = <$new_sock>) { push @threads, async \&Execute, $data; } } sub Execute { my ($command) = @_; // if($command) = "test" { // send "go" to socket1 print "Executing command: $command\n"; system($command); } I know both of my while loops will be blocking and I need a way to implement my accept command as a thread, but I'm not sure the proper way of writing it.

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  • Trouble tunneling my local Wordpress install to the mysql database on appfog

    - by alanmoo
    I've set up a wordpress install on appfog (using rackspace), and cloned the install to my local machine for development. I know the install works (using MAMP) because I created a local mysql database and changed wp-config.php to point to it. However, I want to develop without having to change wp-config.php every time I commit. After doing some research, it seems like the Appfog service Caldecott lets me tunnel into the mysql database on the server, using af tunnel. Unfortunately, I'm having issues with getting it working. Even if I change my MAMP mysql port to something like 8889, and tunnel mysql through port 3306, it looks like it's connected but I still get "Error establishing a database connection" when loading my localhost Wordpress. When I quit the mysql monitor (using ctrl+x, ctrl+c), I get a message stating "Error: 'mysql' execution failed; is it in your $PATH?'. Originally, no, it wasn't, but I've fixed my PATH variable on my local machine so that when I go to Terminal and just type mysql, it loads up. So I guess my question is 2 parts: 1.)Am I going with the right approach for Wordpress development on my local machine and 2.)If so, why is the tunnel not working?

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  • Why my http POST request doesn't go well?

    - by 0x90
    I am trying to make this POST request in ruby. but get back #<Net::HTTPUnsupportedMediaType:0x007f94d396bb98> what I tried is: require 'rubygems' require 'net/http' require 'uri' require 'json' auto_index_nodes =URI('http://localhost:7474/db/data/index/node/') request_nodes = Net::HTTP::Post.new(auto_index_nodes.request_uri) http = Net::HTTP.new(auto_index_nodes.host, auto_index_nodes.port) request_nodes.add_field("Accept", "application/json") request_nodes.set_form_data({"name"=>"node_auto_index", "config" => { "type" => "fulltext", "provider" =>"lucene"} , "Content-Type" => "application/json" }) response = http.request(request_nodes) Tried to write this part: "config" => { "type" => "fulltext", provider" =>"lucene"} , "Content-Type" => "application/json" } like that: "config" => '{ "type" => "fulltext",\ "provider" =>"lucene"},\ "Content-Type" => "application/json"\ }' this try didn't help either: request_nodes.set_form_data({"name"=>"node_auto_index", "config" => '{ \ "type" : "fulltext",\ "provider" : "lucene"}' , "Content-Type" => "application/json" })

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  • Entering Content Into A MySQL Database Via A Form

    - by ThatMacLad
    I've been working on creating a form that submits content into my database but I decided that rather than using a drop down menu to select the date I'd rather use a textfield. I was wondering what changes I will need to make to my table creation file. <?php mysql_connect ('localhost', 'root', 'root') ; mysql_select_db ('tmlblog'); $sql = "CREATE TABLE php_blog ( id int(20) NOT NULL auto_increment, timestamp int(20) NOT NULL, title varchar(255) NOT NULL, entry longtext NOT NULL, PRIMARY KEY (id) )"; $result = mysql_query($sql) or print ("Can't create the table 'php_blog' in the database.<br />" . $sql . "<br />" . mysql_error()); mysql_close(); if ($result != false) { echo "Table 'php_blog' was successfully created."; } ?> It's the timestamp that I need to edit to enter in via a textfield. The Title and Entry are currently being entered via that method anyway.

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  • Trouble accessing fields of a serialized object in Java

    - by typoknig
    I have instantized a class that implements Serializable and I am trying to stream that object like this: try{ Socket socket = new Socket("localhost", 8000); ObjectOutputStream toServer = new ObjectOutputStream(socket.getOutputStream()); toServer.writeObject(myObject); } catch (IOException ex) { System.err.println(ex); } All good so far right? Then I am trying to read the fields of that object like this: //This is an inner class class HandleClient implements Runnable{ private ObjectInputStream fromClient; private Socket socket; // This socket was established earlier try { fromClient = new ObjectInputStream(socket.getInputStream()); GetField inputObjectFields = fromClient.readFields(); double myFristVariable = inputObjectFields.get("myFirstVariable", 0); int mySecondVariable = inputObjectFields.get("mySecondVariable", 0); //do stuff } catch (IOException ex) { System.err.println(ex); } catch (ClassNotFoundException ex) { System.err.println(ex); } finally { try { fromClient.close(); } catch (Exception ex) { ex.printStackTrace(); } } } But I always get the error: java.io.NotActiveException: not in call to readObject This is my first time streaming objects instead of primitive data types, what am I doing wrong? BONUS When I do get this working correctly, is the ENTIRE CLASS passed with the serialized object (i.e. will I have access to the methods of the object's class)? My reading suggests that the entire class is passed with the object, but I have been unable to use the objects methods thus far. How exactly do I call on the object's methods? In addition to my code above I also experimented with the readObject method, but I was probably using it wrong too because I couldn't get it to work. Please enlighten me.

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