Search Results

Search found 6517 results on 261 pages for 'localhost'.

Page 226/261 | < Previous Page | 222 223 224 225 226 227 228 229 230 231 232 233  | Next Page >

  • Storing data in a MySQL database using MySQL & PHP

    - by comma
    I'm new to PHP and MySQL and I'm trying to store a users entered data from the following fields $skill, $experience, $years which a user can also add additional fields of $skill, $experience, $years if needed so in instead of 1 of each field there might be multiples of each field. I was wondering how can I store the fields in my MySQL database using PHP and MySQL? I have the following script but I know its wrong. can some one help me fix the script listed below? Here is the PHP and MySQL code. $skill = serialize($_POST['skill']); $experience = serialize($_POST['experience']); $years = serialize($_POST['years']); for (($s = 0; $s < count($skill); $s++) && ($x = 0; $x < count($experience); $x++) && ($g = 0; $g < count($years); $g++)){ $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $query1 = "INSERT INTO learned_skills (skill, experience, years) VALUES ('" . $skill[$s] . "', '" . $experience[$x] . "', '" . $years[$g] . "')"; if (!mysqli_query($mysqli, $query1)) { print mysqli_error($mysqli); return; } } Here is my MySQL table. CREATE TABLE learned_skills ( id INT UNSIGNED NOT NULL AUTO_INCREMENT, skill TEXT NOT NULL, experience TEXT NOT NULL, years INT NOT NULL, PRIMARY KEY (id) ); CREATE TABLE u_skills ( id INT UNSIGNED NOT NULL AUTO_INCREMENT, skill_id INT UNSIGNED NOT NULL, users_id INT UNSIGNED NOT NULL, PRIMARY KEY (id) );

    Read the article

  • tomcat wont start up on linux machine

    - by David
    hi, im new to linux but after spending the day i have got linux running. installed java and tomcat. my goal is host my app with this linux box i've just set up. i know it all works fine from my windows based machine but it is my laptop so i'm planning this as my dedicated server. following many many forums i've now got tomcat 7 installed. however i cannot get it to start. changing to the tomcat directory and "./startup.sh" i get output Using CATALINA_BASE: /usr/local/tomcat Using CATALINA_HOME: /usr/local.tomcat Using CATALINA_TMPDIR: /usr/local/tomcat/temp Using JRE_HOME: usr/lib/jvm/java-6-sun/ Using CLASSPATH: /usr/local/tomcat/bin/bootstrap.jar:/usr/local.tomcat/bin/c\tomcat-juli.jar thats the end of theoutput. however localhost:8080 is not up. and in the tomcat log file is the error "eval: 1: usr/lib/jvm/java-6-sun//bin/java: not found" hopfully there is some expert here who can help me with this problem. please note that im a novice when it comes to linux. thankyou oh and my version of linux is Ubuntu 10.04 LTS - the Lucid Lynx

    Read the article

  • Implimenting Zend MVC for my existing site-first step?

    - by Joel
    Hi guys, OK-newbie question here. I'll try not to bombard SO with lots of questions-and hopefully this first one will show me the method I'll need to follow for subsequent conversions. I have a web-based calendar system that I developed, but it was coded for me procedurally (using PHP). I'm now working on learning OO and wanting to integrate this site into my localhost Zend Framework and slowly start converting parts to OO and the Zend Framework MVC process in particular. As I've said before, I understand that this will be a slow process, and when I'm done, I still probably won't have anything as OO friendly as if I had rewritten it from scratch, but I'd like to use this as a learning experience. So, I have dropped the whole site into my localhose/zend/Public folder, and everything is showing up great and linking to the database, etc. My question is-what would be the easiest first component to switch over to the MVC model? This site has a bit of everything-forms, login, authentication, some jQuery, etc. Can anyone point to a tutorial that would address what I'm trying to do? If indeed, a form would be one of the simpler things to switch, can someone walk me through those changes? Another idea is changing over all the header info, etc? Thanks for any pointers on where to start! EDIT: Also, I understand that SO is mainly for specific coding questions-I'm happy to share specific code, once I have an idea about which section to tackle first...

    Read the article

  • jquery window.unload triggers post after unload

    - by index
    I am trying to do a post to server before unloading a page and I followed this and it's working fine. My problem is the $.post on window.unload is triggered after it has unloaded. I tried it with a signout link and checking on my logs, I get the following: Started GET "/signout" for 127.0.0.1 at 2012-11-22 00:15:08 +0800 Processing by SessionsController#destroy as HTML Redirected to http://localhost:3000/ Completed 302 Found in 1ms Started GET "/" for 127.0.0.1 at 2012-11-22 00:15:08 +0800 Processing by HomeController#index as HTML Rendered home/index.html.erb within layouts/application (0.4ms) Rendered layouts/_messages.html.erb (0.1ms) Completed 200 OK in 13ms (Views: 12.9ms) Started POST "/unloading" for 127.0.0.1 at 2012-11-22 00:15:08 +0800 Processing by HomeController#unloading as */* Parameters: {"p1"=>"1"} WARNING: Can't verify CSRF token authenticity Completed 500 Internal Server Error in 0ms NoMethodError (undefined method `id' for nil:NilClass): app/controllers/home_controller.rb:43:in `unloading' First part is the signout and then user gets redirected to root then it runs the post ('/unloading'). Is there a way to make the '/unloading' execute first then execute whatever the unload action was? I have this as my jquery post $(window).unload -> $.ajax { async: false, beforeSend: (xhr) -> xhr.setRequestHeader('X-CSRF-Token', $('meta[name="csrf-token"]').attr('content')) , url: '/unloading' , type: 'Post' , data: { p1: '1' } }

    Read the article

  • http post request with cross-origin in javascript

    - by Calamarico
    i have a problem with a http post call in firefox. I know that when there are a cross origin, firefox first do a OPTIONS before the POST to know the access-control-allow headers. With this code i dont have any problem: Net.requestSpeech.prototype.post = function(url, data) { if(this.xhr != null) { this.xhr.open("POST", url); this.xhr.onreadystatechange = Net.requestSpeech.eventFunction; this.xhr.setRequestHeader("Content-Type", "application/json; charset=utf-8"); this.xhr.send(data); } } I test this code with a simple html that invokes this function. Everything is ok and i have the response of the OPTIONS and POST, and i process the response. But, i'm trying to integrate this code with an existen application with uses jquery (i dont know if this is a problem), when the send(data) executes in this case, the browser (firefox) do the same, first do a OPTION request, but in this case dont receive the response of the server and puts this message in console: [18:48:13.529] OPTIONS http://localhost:8111/ [undefined 31ms] Undefined... the undefined is because dont receive the response, but the code is the same, i dont know why in this case the option dont receive the response, someone have an idea? i debug my server app and the OPTIONS arrive ok to the server, but it seems like the browser dont wait to the response. edit more later: ok i think that the problem is when i run with a simple html with a SCRIPT tag that invokes the method who do the request run ok, but in this app that dont receive the response, i have a form that do a onsubmit event, i think that the submit event returns very fast and the browser dont have time to get the OPTIONS request. edit more later later: WTF, i resolve the problem make the POST request to sync: this.xhr.open("POST", url, false); The submit reponse very quickly and can't wait to the OPTION response of the browser, any idea to this?

    Read the article

  • Rails: Added new Action in Controller, but there is no path?

    - by Newbie
    Hello! I try to do following: A user is on his profile page. Now he edits his profile. He klicks on update and the data is saved. Now I want to redirect the user to another kind of profile-edit-page. I did the following in my users_controller.rb: def update @user = User.find(params[:id]) respond_to do |format| if @user.update_attributes(params[:user]) flash[:notice] = 'User was successfully updated.' if(@user.team_id != nil) format.html { redirect_to(@user) } else format.html { redirect_to choose_team_path } end format.xml { head :ok } else format.html { render :action => "edit" } format.xml { render :xml => @user.errors, :status => :unprocessable_entity } end end end def choose_team @user = User.find(params[:id]) end I created a view: /users/choose_team.html.erb Now I get the following error: undefined local variable or method `choose_team_path' for #<UsersController:0x1f56650> So I added choose_team to my routes.rb: map.choose_team 'choose-team', :controller => 'users', :action => 'choose_team' Now, after submitting my first edit form, it redirects me to http://localhost:3000/choose-team and I get following error: Couldn't find User without an ID What I want: If a user has no team_id, he should be redirected to my choose_team.html.erb for choosing a team, else he should be redirected to his profile/show. How to do this?

    Read the article

  • Codeigniter .htaccess not working in subdirectory

    - by xzdead
    I have this codeingniter project structure webRoot | |/application | | | |/controllers | | | |/admin | |/public | | | |/admin | | | | | |/css | | |/img | |/css | |/img And this is my .htacess file, located in /public. I use this in every local project running xampp: <IfModule mod_rewrite.c> RewriteEngine On RewriteBase / RewriteCond %{REQUEST_FILENAME} !-f RewriteRule ^(.*)$ index.php/$1 [L] </IfModule> <IfModule !mod_rewrite.c> # If we don't have mod_rewrite installed, all 404's # can be sent to index.php, and everything works as normal. # Submitted by: ElliotHaughin ErrorDocument 404 /index.php </IfModule> It works fine in localhost, but doesn't work in a dreamhost server. I always get "no input file specified". So after searching the web and trying lots of combinations, the best I got is this .htaccess file: Options +FollowSymLinks RewriteEngine On RewriteCond %{REQUEST_FILENAME} !-d RewriteCond %{REQUEST_FILENAME} !-f RewriteRule ^ index.php [L] With this one, if I go to http://development.mydomain.com - I see the codeigniter welcome page But if I go to: http://development.mydomain.com/admin - I see the directory listing of /public/admin and doesn't execute the controller in /application/controllers/admin Again, if I go to: http://development.mydomain.com/admin/admin - I see the private area, it executes the controller and goes to the default controller defined in routes, "dashboard" This works fine too: http://development.mydomain.com/admin/dashboard I have set in my config file: $config['index_page'] = ''; $config['base_url'] = ''; $config['uri_protocol'] = 'AUTO'; I think that whatever is wrong in my .htaccess is causing other path issues I have with my project. Any help would be great. Thanks to all in advance EDIT: I removed this line: RewriteCond %{REQUEST_FILENAME} !-d because admin directory exists, that's why I see the public directory listing. But now I see the codeigniter welcome page when I go to http://development.mydomain.com/admin So now my .htaccess file looks like: Options +FollowSymLinks RewriteEngine On RewriteCond %{REQUEST_FILENAME} !-f RewriteRule ^ index.php [L] #RewriteRule ^(.*)$ /index.php?/$1 [L] I also tried with the commented RewriteRule but I get the same result.

    Read the article

  • Assigning values to the lable through database depending on listbox values

    - by SurajVitekar
    I want to assign the values of five labels from database regarding to values selected in listbox. The db query returns single column with multiple records. Please help. I'm working with C# 2010 and MS SQL. My current code is: private void listBox1_SelectedIndexChanged(object sender, EventArgs e) { try { String c1, c2; c1 = "NULL"; MessageBox.Show("LB index :"+listBox1.SelectedIndex.ToString()); //p = listBox1.SelectedItem.ToString(); SqlConnection con = new SqlConnection(); con.ConnectionString = "Data Source=localhost;Initial Catalog=eVoting;Integrated Security=True;Pooling=False"; con.Open(); MessageBox.Show("List bOx sect :"+listBox1.SelectedValue.ToString()); SqlCommand cmd = new SqlCommand("select Firstname from candidates where position ='" + listBox1.SelectedValue.ToString() + "'", con); int index = 0; SqlDataReader reader = cmd.ExecuteReader(); while(reader.Read()) { if (index == 0) { c1 = reader[index].ToString(); radioButton1.Text = c1; } if (index == 1) { c1 = reader[index].ToString(); radioButton2.Text = c1; } if (index == 2) { c1 = reader[index].ToString(); radioButton3.Text = c1; } if (index == 3) { c1 = reader[index].ToString(); radioButton4.Text = c1; } if (index == 4) { c1 = reader[index].ToString(); radioButton4.Text = c1; } if (index == 5) { c1 = reader[index].ToString(); radioButton5.Text = c1; } MessageBox.Show("c1 :" + c1); index++; } } catch (Exception E) { } }

    Read the article

  • Barcode not generated in C# web forms?

    - by Sinsil Mathew
    I am trying for create a barcode in my web form.for that i download font IDAutomationHC39M and install in my system,then i run my wesite in localhost but barcode cannot be generated.This is my code protected void Button1_Click1(object sender, EventArgs e) { string barCode = TextBox1.Text; System.Web.UI.WebControls.Image imgBarCode = new System.Web.UI.WebControls.Image(); using (Bitmap bitMap = new Bitmap(barCode.Length * 40, 80)) { using (Graphics graphics = Graphics.FromImage(bitMap)) { Font oFont = new Font("IDAutomationHC39M", 16); PointF point = new PointF(2f, 2f); SolidBrush blackBrush = new SolidBrush(Color.Black); SolidBrush whiteBrush = new SolidBrush(Color.White); graphics.FillRectangle(whiteBrush, 0, 0, bitMap.Width, bitMap.Height); graphics.DrawString("*" + barCode + "*", oFont, blackBrush, point); } using (MemoryStream ms = new MemoryStream()) { bitMap.Save(ms, System.Drawing.Imaging.ImageFormat.Png); byte[] byteImage = ms.ToArray(); Convert.ToBase64String(byteImage); imgBarCode.ImageUrl = "data:image/png;base64," + Convert.ToBase64String(byteImage); } plBarCode.Controls.Add(imgBarCode); } And the result is appear like that code

    Read the article

  • Cant fetch production db results using Google app engine remote_api

    - by Alon
    Hey, im trying to work out with /remote_api with a django-patch app engine app i got running. i want to select a few rows from my online production app locally. i cant seem to manage todo so, everything authenticates fine, it doesnt breaks on imports, but when i try to fetch something it just doesnt print anything. Placed the test python inside my local app dir. #!/usr/bin/env python # import os import sys # Hardwire in appengine modules to PYTHONPATH # or use wrapper to do it more elegantly appengine_dirs = ['myworkingpath'] sys.path.extend(appengine_dirs) # Add your models to path my_root_dir = os.path.abspath(os.path.dirname(__file__)) sys.path.insert(0, my_root_dir) from google.appengine.ext import db from google.appengine.ext.remote_api import remote_api_stub import getpass APP_NAME = 'Myappname' os.environ['AUTH_DOMAIN'] = 'gmail.com' os.environ['USER_EMAIL'] = '[email protected]' def auth_func(): return (raw_input('Username:'), getpass.getpass('Password:')) # Use local dev server by passing in as parameter: # servername='localhost:8080' # Otherwise, remote_api assumes you are targeting APP_NAME.appspot.com remote_api_stub.ConfigureRemoteDatastore(APP_NAME, '/remote_api', auth_func) # Do stuff like your code was running on App Engine from channel.models import Channel, Channel2Operator myresults = mymodel.all().fetch(10) for result in myresults: print result.key() it doesnt give any error or print anything. so does the remote_api console example google got. when i print the myresults i get [].

    Read the article

  • servicestack Razor view with request and response DTO

    - by user7398
    I'm having a go with the razor functionality in service stack. I have a razor cshtml view working for one of my response DTO's. I need to access some values from the request DTO in the razor view that have been filled in from some fields from the REST route, so i can construct a url to put into the response html page and also label some form labels. Is there anyway of doing this? I don't want to duplicate the property from the request DTO into the response DTO just for this html view. Because i'm trying to emulate an existing REST service of another product, i do not want to emit extra data just for the html view. eg http://localhost/rest/{Name}/details/{Id} eg @inherits ViewPage<DetailsResponse> @{ ViewBag.Title = "todo title"; Layout = "HtmlReport"; } this needs to come from the request dto NOT @Model <a href="/rest/@Model.Name">link to user</a> <a href="/rest/@Model.Name/details/@Model.Id">link to user details</a>

    Read the article

  • Problem consuming a dataset via a .NET web service from Flex-ActionScript

    - by DEH
    Hi, I am returning a .NET dataset to Flex Actionscript via a web service. Actionscript snippet as follows: var websvc:WebService = new WebService(); websvc.useProxy=false; websvc.wsdl = "http://localhost:13229/test/mysvc.asmx?WSDL"; websvc.loadWSDL(); var operation:Operation = new Operation(null, "GetData"); operation.arguments.command="xx_gethierdata_"+mode+"_"+identifier; operation.addEventListener(ResultEvent.RESULT, onResultHandler, false, 0, true); operation.addEventListener(FaultEvent.FAULT, onFaultHandler, false, 0, true); operation.resultFormat="object"; websvc.operations = [operation]; operation.send(); Once in the onResultHandler function I have access to the datatable - I then want to grab the column names. The following code outputs my column names: for each (var tcolumn:Object in datatable.Columns){trace('Column:'+tcolumn);} This works ok, but the column names are encoded, so a column name that is actually "1-9" is output as "_x005B_1-9_x005D_" Anyone know the best way to decode the column name? I could replace all the encoding strings, but surely there is a better way? Thanks

    Read the article

  • Entering Content Into A MySQL Database Via A Form

    - by ThatMacLad
    I've been working on creating a form that submits content into my database but I decided that rather than using a drop down menu to select the date I'd rather use a textfield. I was wondering what changes I will need to make to my table creation file. <?php mysql_connect ('localhost', 'root', 'root') ; mysql_select_db ('tmlblog'); $sql = "CREATE TABLE php_blog ( id int(20) NOT NULL auto_increment, timestamp int(20) NOT NULL, title varchar(255) NOT NULL, entry longtext NOT NULL, PRIMARY KEY (id) )"; $result = mysql_query($sql) or print ("Can't create the table 'php_blog' in the database.<br />" . $sql . "<br />" . mysql_error()); mysql_close(); if ($result != false) { echo "Table 'php_blog' was successfully created."; } ?> It's the timestamp that I need to edit to enter in via a textfield. The Title and Entry are currently being entered via that method anyway.

    Read the article

  • Jython & Mysql - what is the current practice for connection?

    - by Sector7B
    Just trying jython for the first time, because something came up at work that would fit for this perfect for it. I assume jython can make mysql jdbc connection using the mysql jdbc driver. After googling and reading, however I am having problems and it seems jython specific and probably simple. so i do jython: Jython 2.5.1 (Release_2_5_1:6813, Sep 26 2009, 13:47:54) [Java HotSpot(TM) 64-Bit Server VM (Apple Inc.)] on java1.6.0_17 Type "help", "copyright", "credits" or "license" for more information. >>> import sys >>> print sys.path ['', '/JYTHONPATH/mysql-connector-java-5.1.10-bin.jar', '/WorkArea/Apps/jython/jython2.5.1/Lib', '__classpath__', '__pyclasspath__/', '/WorkArea/Apps/jython/jython2.5.1/Lib/site-packages'] >>> code i'm running from java.lang import * from java.sql import * driverName="com.mysql.jdbc.Driver" Class.forName(driverName) url = "jdbc:mysql://localhost/test?user=jgreenaw&password=" con = DriverManager.getConnection(url) stmt = con.createStatement() output riux:Desktop$ jython pymysql.py Traceback (most recent call last): File "pymysql.py", line 7, in <module> Class.forName(driverName) at java.net.URLClassLoader$1.run(URLClassLoader.java:200) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:188) at java.lang.ClassLoader.loadClass(ClassLoader.java:315) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:330) at java.lang.ClassLoader.loadClass(ClassLoader.java:250) at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:398) at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Class.java:169) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) java.lang.ClassNotFoundException: java.lang.ClassNotFoundException: com.mysql.jdbc.Driver any advice? thanks

    Read the article

  • No operations allowed after statement closed issue

    - by Washu
    I have the next methods in my singleton to execute the JDBC connections public void openDB() throws ClassNotFoundException, IllegalAccessException, InstantiationException, SQLException { Class.forName("com.mysql.jdbc.Driver").newInstance(); String url = "jdbc:mysql://localhost/mbpe_peru";//mydb conn = DriverManager.getConnection(url, "root", "admin"); st = conn.createStatement(); } public void sendQuery(String query) throws SQLException { st.executeUpdate(query); } public void closeDB() throws SQLException { st.close(); conn.close(); } And I'm having a problem in a void where i have to call this twice. private void jButton1ActionPerformed(ActionEvent evt) { Main.getInstance().openDB(); Main.getInstance().sendQuery("call insertEntry('"+EntryID()+"','"+SupplierID()+"');"); Main.getInstance().closeDB(); Main.getInstance().openDB(); for(int i=0;i<dataBox.length;i++){ Main.getInstance().sendQuery("call insertCount('"+EntryID()+"','"+SupplierID()+"','"+BoxID()+"'); Main.getInstance().closeDB(); } } I have already tried to keep the connection open and send the 2 querys and after that closed and it didnt work... The only way it worked was to not use the methods, declare the commands for the connection and use different variables for the connection and the statement. I thought that if i close the Connecion and the Statement I could use the variable once again since is a method but I'm not able to. Is there any way to solve this using my methods for the JDBC connection?

    Read the article

  • How do I execute queries upon DB connection in Rails?

    - by sycobuny
    I have certain initializing functions that I use to set up audit logging on the DB server side (ie, not rails) in PostgreSQL. At least one has to be issued (setting the current user) before inserting data into or updating any of the audited tables, or else the whole query will fail spectacularly. I can easily call these every time before running any save operation in the code, but DRY makes me think I should have the code repeated in as few places as possible, particularly since this diverges greatly from the ideal of database agnosticism. Currently I'm attempting to override ActiveRecord::Base.establish_connection in an initializer to set it up so that the queries are run as soon as I connect automatically, but it doesn't behave as I expect it to. Here is the code in the initializer: class ActiveRecord::Base # extend the class methods, not the instance methods class << self alias :old_establish_connection :establish_connection # hide the default def establish_connection(*args) ret = old_establish_connection(*args) # call the default # set up necessary session variables for audit logging # call these after calling default, to make sure conn is established 1st db = self.class.connection db.execute("SELECT SV.set('current_user', 'test@localhost')") db.execute("SELECT SV.set('audit_notes', NULL)") # end "empty variable" err ret # return the default's original value end end end puts "Loaded custom establish_connection into ActiveRecord::Base" sycobuny:~/rails$ ruby script/server = Booting WEBrick = Rails 2.3.5 application starting on http://0.0.0.0:3000 Loaded custom establish_connection into ActiveRecord::Base This doesn't give me any errors, and unfortunately I can't check what the method looks like internally (I was using ActiveRecord::Base.method(:establish_connection), but apparently that creates a new Method object each time it's called, which is seemingly worthless cause I can't check object_id for any worthwhile information and I also can't reverse the compilation). However, the code never seems to get called, because any attempt to run a save or an update on a database object fails as I predicted earlier. If this isn't a proper way to execute code immediately on connection to the database, then what is?

    Read the article

  • how to get response from remote server

    - by ruhit
    I have made a desktop application in asp.net using c# that connecting with remote server.I am able to connect but how do i show that my login is successful or not. After that i want to retrieve data from the remote server..........so plz help me.I have written the below code..............is there any better way try { string strId = UserId_TextBox.Text; string strpasswrd = Password_TextBox.Text; ASCIIEncoding encoding = new ASCIIEncoding(); string postData = "UM_email=" + strId; postData += ("&UM_password=" + strpasswrd); byte[] data = encoding.GetBytes(postData); MessageBox.Show(postData); // Prepare web request... //HttpWebRequest myRequest = (HttpWebRequest)WebRequest.Create("http://localhost/ruhit/basic_framework/index.php?menu=login=" + postData); HttpWebRequest myRequest =(HttpWebRequest)WebRequest.Create("http://www.facebook.com/login.php=" + postData); myRequest.Method = "POST"; myRequest.ContentType = "application/x-www-form-urlencoded"; myRequest.ContentLength = data.Length; Stream newStream = myRequest.GetRequestStream(); // Send the data. newStream.Write(data, 0, data.Length); MessageBox.Show("u r now connected"); HttpWebResponse response = (HttpWebResponse)myRequest.GetResponse(); // WebResponse response = myRequest.GetResponse(); StreamReader reader = new StreamReader(response.GetResponseStream()); string str = reader.ReadLine(); while (str != null) { str = reader.ReadLine(); MessageBox.Show(str); } reader.Close(); newStream.Close(); } catch { MessageBox.Show("error connecting"); }

    Read the article

  • Selecting Date Range on a PHP form and displaying results from MySQL database

    - by Sarah HSL
    This may be something simple but I cant understand why this wouldn't work.. I have a php form where you can select a date range from drop downs. I've given the field names day, month year, and day1, month1, year1. When clicking submit it takes you to a second php form. Here is the code for second form: <?php $username="***"; $password="***"; $database="****"; mysql_connect('localhost',$username,$password); @mysql_select_db($database) or die( "Unable to select database"); $day = $_GET['day']; $month = $_GET['month']; $year = $_GET['year']; $day1 = $_GET['day1']; $month1 = $_GET['month1']; $year1 = $_GET['year1']; $date1 = "$year-$month-$day"; $date2 = "$year1-$month1-$day1"; $query = "SELECT * FROM main_stock WHERE curr_timestamp BETWEEN '$date1' AND '$date2'"; $result=mysql_query($query); $num=mysql_num_rows($result); ?> <table border="1" cellspacing="2" cellpadding="2"> <tr> <td><b><font face="Arial, Helvetica, sans-serif">Product Description</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Category</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Master Category</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Barcode</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Status</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">TimeStamp</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">New Own</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Serial No.</font></b></td> </tr> <?php $i=0; while ($i < $num) { $f1=mysql_result($result,$i,"product_desc"); $f2=mysql_result($result,$i,"category"); $f3=mysql_result($result,$i,"mastercategory"); $f4=mysql_result($result,$i,"barcode"); $f5=mysql_result($result,$i,"status"); $f6=mysql_result($result,$i,"curr_timestamp"); $f7=mysql_result($result,$i,"newown"); $f8=mysql_result($result,$i,"serial"); ?> <tr> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f1; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f2; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f3; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f4; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f5; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f6; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f7; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f8; ?></font></td> </tr> <?php $i++; } $num_rows = mysql_num_rows($result); echo "$num_rows Rows\n"; mysql_close(); ?> Is there any reason this wouldn't work? I'm not sure where I am going wrong. It displays results when there is another option as well as the date such as 'status' but when this is taken out and I just want to display all the results between the date range it doesn't work.. This works: <?php $username="+++"; $password="+++"; $database="+++"; mysql_connect('localhost',$username,$password); @mysql_select_db($database) or die( "Unable to select database"); $day = $_GET['day']; $month = $_GET['month']; $year = $_GET['year']; $day1 = $_GET['day1']; $month1 = $_GET['month1']; $year1 = $_GET['year1']; $status = $_GET['status']; $date1 = "$year-$month-$day"; $date2 = "$year1-$month1-$day1"; $query = "SELECT * FROM main_stock WHERE status = '$status' AND curr_timestamp BETWEEN '$date1' AND '$date2'"; $result=mysql_query($query); $num=mysql_num_rows($result); ?> <table border="1" cellspacing="2" cellpadding="2"> <tr> <td><b><font face="Arial, Helvetica, sans-serif">Product Description</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Category</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Master Category</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Barcode</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Status</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">TimeStamp</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">New Own</font></b></td> <td><b><font face="Arial, Helvetica, sans-serif">Serial No.</font></b></td> </tr> <?php $i=0; while ($i < $num) { $f1=mysql_result($result,$i,"product_desc"); $f2=mysql_result($result,$i,"category"); $f3=mysql_result($result,$i,"mastercategory"); $f4=mysql_result($result,$i,"barcode"); $f5=mysql_result($result,$i,"status"); $f6=mysql_result($result,$i,"curr_timestamp"); $f7=mysql_result($result,$i,"newown"); $f8=mysql_result($result,$i,"serial"); ?> <tr> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f1; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f2; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f3; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f4; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f5; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f6; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f7; ?></font></td> <td><font face="Arial, Helvetica, sans-serif"><?php echo $f8; ?></font></td> </tr> <?php $i++; } $num_rows = mysql_num_rows($result); echo "$num_rows Rows\n"; mysql_close(); ?> But when the 'status' field is taken out (and obviously the serial drop down in the first form) it stops working...

    Read the article

  • How do I format a Uri when binding an Image in Silverlight?

    - by Scott
    I haven't been able to find an answer to this. I have a database that has image paths in it ("images/myimage.jpg"). These images exist on my asp.net site which is also where I host the SL. I want to bind these images to my ListBox control so that the image displays. I have read that since I have a string value, "images/myimage.jpg", that I need to convert it to a BitMap image. I have done this: the xaml: <Image Source="{Binding ImageFile, Converter={StaticResource ImageConverter}}"/> the ImageConverter class: public object Convert(object value, Type targetType, object parameter, CultureInfo culture) { try { Uri source= new Uri(value.ToString()); return new BitmapImage(source); } catch(Exception ex) { return new BitmapImage(); } } I get an error when creating the Uri, "The Format of the URI could not be determined". What am I doing wrong? If I create a Uri that looks like this: http://localhost:49723/images/myimage.jpg, it works just fine. Why doesn't just "images/myimage.jpg" work?

    Read the article

  • json parser empty result

    - by graybow
    I'm new in gwt and new in using firebug.I have valid json result from tesdb3.php {"item": [{"kode":"002","nama":"bambang gentolet"}, {"kode":"012","nama":"Algiz"}]} I add the xml with inherits name='com.google.gwt.json.JSON'/ inherits name="com.google.gwt.http.HTTP" / then i try to show it in the gwt with this code. public class Tesdb3 implements EntryPoint { String url= "http://localhost/phpmyadmin/tesdb3/datauser.php"; public void LoadData() throws RequestException{ RequestBuilder builder = new RequestBuilder(RequestBuilder.GET, URL.encode(url)); builder.sendRequest(null, new RequestCallback(){ @Override public void onError(Request request, Throwable exception) { Window.alert("error " + exception); } public void onResponseReceived(Request request, Response response) { if (200 == response.getStatusCode()) { Window.alert("ok -" + response.getText() + "-" + response.getStatusCode()); } else { Window.alert("error2 -" + response.getText()+ response.getStatusText() + "-" + response.getStatusCode()); } } }); } public void onModuleLoad() { try { LoadData(); } catch (RequestException e) { e.printStackTrace(); } } } I run it in development mode. not hosted mode. My code didn't show any error. But the result in window alert is "error2 --OK-0". result Net from firebug is 7 request: get Tesdb3.html?gwt.codeserv = 200ok get Tesdb3.css = 200ok get tesdb3.nocache.js = 200ok get hosted.html?tesdb3 = aborted get standard.css = 304 not modified get hosted.html?tesdb3 = 403 not modified get datauser.php = 200ok my question is: Why the response status code is 0, and the response status text is 'OK'? there was no eror in json or java code. why response.getText is empty? Why i can't get any json result even a single character?

    Read the article

  • before filter not working as expected

    - by Jimmy
    Hey guys I have a ruby on rails app with a before filter setup in my application controller to ensure only the owner can edit a document, but my permission check is always failing even when it shouldn't. Here is the code: def get_logged_in_user id = session[:user_id] unless id.nil? @current_user = User.find(id) end end def require_login get_logged_in_user if @current_user.nil? session[:original_uri] = request.request_uri flash[:notice] = "You must login first." redirect_to login end end def check_current_user_permission require_login logger.debug "user id is #{params[:user_id]}" logger.debug "current user id is #{session[:user_id]}" if session[:user_id] != params[:user_id] flash[:notice] = "You don't have permission to do that." redirect_to :controller => 'home' end end The code to note is in the check_current_user_permission. Here is an example of my log output: user id is 3 current user id is 3 Redirected to http://localhost:3000/home Filter chain halted as [:check_current_user_permission] rendered_or_redirected. Can anyone shed some light into why this is failing? Obviously the user_id of 3 is equal to the session's user_id of 3. What is going wrong?

    Read the article

  • Perl TCP Server handling multiple Client connections

    - by Matt
    I'll preface this by saying I have minimal experience with both Perl and Socket programming, so I appreciate any help I can get. I have a TCP Server which needs to handle multiple Client connections simultaneously and be able to receive data from any one of the Clients at any time and also be able to send data back to the Clients based on information it's received. For example, Client1 and Client2 connect to my Server. Client2 sends "Ready", the server interprets that and sends "Go" to Client1. The following is what I have written so far: my $sock = new IO::Socket::INET { LocalHost => $host, // defined earlier in code LocalPort => $port, // defined earlier in code Proto => 'tcp', Listen => SOMAXCONN, Reuse => 1, }; die "Could not create socket $!\n" unless $sock; while ( my ($new_sock,$c_addr) = $sock->accept() ) { my ($client_port, $c_ip) = sockaddr_in($c_addr); my $client_ipnum = inet_ntoa($c_ip); my $client_host = ""; my @threads; print "got a connection from $client_host", "[$client_ipnum]\n"; my $command; my $data; while ($data = <$new_sock>) { push @threads, async \&Execute, $data; } } sub Execute { my ($command) = @_; // if($command) = "test" { // send "go" to socket1 print "Executing command: $command\n"; system($command); } I know both of my while loops will be blocking and I need a way to implement my accept command as a thread, but I'm not sure the proper way of writing it.

    Read the article

  • Why do you have to call URLConnection#getInputStream to be able to write out to URLConnection#getOutputStream?

    - by John
    I'm trying to write out to URLConnection#getOutputStream, however, no data is actually sent until I call URLConnection#getInputStream. Even if I set URLConnnection#doInput to false, it still will not send. Does anyone know why this is? There's nothing in the API documentation that describes this. Java API Documentation on URLConnection: http://download.oracle.com/javase/6/docs/api/java/net/URLConnection.html Java's Tutorial on Reading from and Writing to a URLConnection: http://download.oracle.com/javase/tutorial/networking/urls/readingWriting.html import java.io.IOException; import java.io.OutputStreamWriter; import java.net.URL; import java.net.URLConnection; public class UrlConnectionTest { private static final String TEST_URL = "http://localhost:3000/test/hitme"; public static void main(String[] args) throws IOException { URLConnection urlCon = null; URL url = null; OutputStreamWriter osw = null; try { url = new URL(TEST_URL); urlCon = url.openConnection(); urlCon.setDoOutput(true); urlCon.setRequestProperty("Content-Type", "text/plain"); //////////////////////////////////////// // SETTING THIS TO FALSE DOES NOTHING // //////////////////////////////////////// // urlCon.setDoInput(false); osw = new OutputStreamWriter(urlCon.getOutputStream()); osw.write("HELLO WORLD"); osw.flush(); ///////////////////////////////////////////////// // MUST CALL THIS OTHERWISE WILL NOT WRITE OUT // ///////////////////////////////////////////////// urlCon.getInputStream(); ///////////////////////////////////////////////////////////////////////////////////////////////////////// // If getInputStream is called while doInput=false, the following exception is thrown: // // java.net.ProtocolException: Cannot read from URLConnection if doInput=false (call setDoInput(true)) // ///////////////////////////////////////////////////////////////////////////////////////////////////////// } catch (Exception e) { e.printStackTrace(); } finally { if (osw != null) { osw.close(); } } } }

    Read the article

  • How to configure multiple mappings using FluentHibernate?

    - by chris.baglieri
    First time rocking it with NHibernate/Fluent so apologies in advance if this is a naive question. I have a set of Models I want to map. When I create my session factory I'm trying to do all mappings at once. I am not using auto-mapping (though I may if what I am trying to do ends up being more painful than it ought to be). The problem I am running into is that it seems only the top map is taking. Given the code snippet below and running a unit test that attempts to save 'bar', it fails and checking the logs I see NHibernate is trying to save a bar entity to the foo table. While I suspect it's my mappings it could be something else that I am simply overlooking. Code that creates the session factory (note I've also tried separate calls into .Mappings): Fluently.Configure().Database(MsSqlConfiguration.MsSql2008 .ConnectionString(c => c .Server(@"localhost\SQLEXPRESS") .Database("foo") .Username("foo") .Password("foo"))) .Mappings(m => { m.FluentMappings.AddFromAssemblyOf<FooMap>() .Conventions.Add(FluentNHibernate.Conventions.Helpers .Table.Is(x => "foos")); m.FluentMappings.AddFromAssemblyOf<BarMap>() .Conventions.Add(FluentNHibernate.Conventions.Helpers .Table.Is(x => "bars")); }) .BuildSessionFactory(); Unit test snippet: using (var session = Data.SessionHelper.SessionFactory.OpenSession()) { var bar = new Bar(); session.Save(bar); Assert.NotNull(bar.Id); }

    Read the article

  • Nested Routes Show Action: What objects does it expect?

    - by NoahClark
    Here is the relevant line from my rake routes: client_note GET /clients/:client_id/notes/:id(.:format) notes#show When I try passing in the objects like <%= client_note_path([client, @notes.first]) %>> I get: No route matches {:action=>"show", :controller=>"notes", :client_id=>[#<Client id: 5, ... , #<Note id: 9, ...]} Which made me think to try a client ID. So, I tried: <%= client_note_path([client.id, @notes.first]) %> which gives me: No route matches {:action=>"show", :controller=>"notes", :client_id=>[5, #<Note id: 9,content: "He just bought a brand new bobcat, be sure to charg...", client_id: 5, created_at: "2012-06-11 16:18:16", updated_at: "2012-06-11 16:18:16">]} Which, made me want to try just passing in a client ID. <%= client_note_path(client.id) %> No route matches {:action=>"show", :controller=>"notes", :client_id=>5} Still not what I'm looking for. I want to be able to show an individual note which can normally be found at a url like looks like: http://localhost:3000/clients/2/notes/3/

    Read the article

< Previous Page | 222 223 224 225 226 227 228 229 230 231 232 233  | Next Page >