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  • In Python, are there builtin functions for elementwise boolean operators over boolean lists?

    - by bshanks
    For example, if you have n lists of bools of the same length, then elementwise boolean AND should return another list of that length that has True in those positions where all the input lists have True, and False everywhere else. It's pretty easy to write, i just would prefer to use a builtin if one exists (for the sake of standardization/readability). Here's an implementation of elementwise AND: def eAnd(*args): return [all(tuple) for tuple in zip(*args)] example usage: >>> eAnd([True, False, True, False, True], [True, True, False, False, True], [True, True, False, False, True]) [True, False, False, False, True] thx

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  • How do I create a list of timedeltas in python?

    - by eunhealee
    I've been searching through this website and have seen multiple references to time deltas, but haven't quite found what I'm looking for. Basically, I have a list of messages that are received by a comms server and I want to calcuate the latency time between each message out and in. It looks like this: 161336.934072 - TMsg out: [O] enter order. RefID [123] OrdID [4568] 161336.934159 - TMsg in: [A] accepted. ordID [456] RefNumber [123] Mixed in with these messages are other messages as well, however, I only want to capture the difference between the Out messages and in messages with the same RefID. So far, to sort out from the main log which messages are Tmessages I've been doing this, but it's really inefficient. I don't need to be making new files everytime.: big_file = open('C:/Users/kdalton/Documents/Minicomm.txt', 'r') small_file1 = open('small_file1.txt', 'w') for line in big_file: if 'T' in line: small_file1.write(line) big_file.close() small_file1.close() How do I calculate the time deltas between the two messages and sort out these messages from the main log?

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  • Why are these strings escaping from my regular expression in python?

    - by dohkoxar
    In my code, I load up an entire folder into a list and then try to get rid of every file in the list except the .mp3 files. import os import re path = '/home/user/mp3/' dirList = os.listdir(path) dirList.sort() i = 0 for names in dirList: match = re.search(r'\.mp3', names) if match: i = i+1 else: dirList.remove(names) print dirList print i After I run the file, the code does get rid of some files in the list but keeps these two especifically: ['00. Various Artists - Indie Rock Playlist October 2008.m3u', '00. Various Artists - Indie Rock Playlist October 2008.pls'] I can't understand what's going on, why are those two specifically escaping my search.

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  • How to make if-elif-else statement in python more space-saving?

    - by Neverland
    I have a lot of if-elif-else statements in my code if message == '0' or message == '3' or message == '5' or message == '7': ... elif message == '1' or message == '2' or message == '4' or message == '6' or message == '8': ... else: ... Is it possible to format this in a more space-saving way? I tried it this way: if message == '0' or '3' or '5' or '7': ... elif message == '1' or '2' or '4' or '6' or '8': ... else: ... But without success.

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  • Geometry library for python (or C++) for CAD-like operations?

    - by gct
    I'm trying to put together a simple program that will let me visualize a series of consecutive cuts on a wood panel using a router with a particular cutting head. I'm trying to find a decent geometry library that will give me a shortcut through the CAD-like stuff. Specifically, I'd like to be able to define a rectangular solid (the wood panel) and then define a bit profile shape, and take cuts through the rectangular solid (sometimes on a straight line, sometimes on a circular arc). Does anyone know of anything that will do this?

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  • List in a Python class shares the same object over 2 different instances?

    - by zfranciscus
    I created a class: class A: aList = [] now I have function that instantiate this class and add items into the aList. note: there are 2 items for item in items: a = A(); a.aList.append(item); I find that the first A and the second A object has the same number of items in their aList. I would expect that the first A object will have the first item in its list and the second A object will have the second item in its aList. Can anyone explain how this happens ? PS: I manage to solve this problem by moving the aList inside a constructor : def __init__(self): self.aList = []; but I am still curious about this behavior

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  • What would happen if a same file being read and appended at the same time(python programming)?

    - by Shane
    I'm writing a script using two separate thread one doing file reading operation and the other doing appending, both threads run fairly frequently. My question is, if one thread happens to read the file while the other is just in the middle of appending strings such as "This is a test" into this file, what would happen? I know if you are appending a smaller-than-buffer string, no matter how frequently you read the file in other threads, there would never be incomplete line such as "This i" appearing in your read file, I mean the os would either do: append "This is a test" - read info from the file; or: read info from the file - append "This is a test" to the file; and such would never happen: append "This i" - read info from the file - append "s a test". But if "This is a test" is big enough(assuming it's a bigger-than-buffer string), the os can't do appending job in one operation, so the appending job would be divided into two: first append "This i" to the file, then append "s a test", so in this kind of situation if I happen to read the file in the middle of the whole appending operation, would I get such result: append "This i" - read info from the file - append "s a test", which means I might read a file that includes an incomplete string?

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  • How do you check the presence of many keys in a Python dictinary?

    - by Thierry Lam
    I have the following dictionary: sites = { 'stackoverflow': 1, 'superuser': 2, 'meta': 3, 'serverfault': 4, 'mathoverflow': 5 } To check if there are more than one key available in the above dictionary, I will do something like: 'stackoverflow' in sites and 'serverfault' in sites The above is maintainable with only 2 key lookups. Is there a better way to handle checking a large number of keys in a very big dictionary?

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  • how to get the parent dir location using python..

    - by zjm1126
    this code is get the templates/blog1/page.html in b.py: path = os.path.join(os.path.dirname(__file__), os.path.join('templates', 'blog1/page.html')) but i want to get the parent dir location: a |---b.py |---templates |--------blog1 |-------page.html and how to get the a location thanks

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  • speed of map() vs. list comprehension vs. numpy vectorized function in python

    - by mcstrother
    I have a function foo(i) that takes an integer and takes a significant amount of time to execute. Will there be a significant performance difference between any of the following ways of initializing 'a': a = [foo(i) for i in xrange(100)] , a = map(foo, range(100)) , and vfoo = numpy.vectorize(foo) vfoo(range(100)) ? (I don't care whether the output is a list or a numpy array). Is there some other better way of doing this? Thanks.

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  • why can't I use "&&" in python to mean 'and'?

    - by Sergio Tapia
    Here's my code: # F. front_back # Consider dividing a string into two halves. # If the length is even, the front and back halves are the same length. # If the length is odd, we'll say that the extra char goes in the front half. # e.g. 'abcde', the front half is 'abc', the back half 'de'. # Given 2 strings, a and b, return a string of the form # a-front + b-front + a-back + b-back def front_back(a, b): # +++your code here+++ if len(a) % 2 == 0 && len(b) % 2 == 0: return a[:(len(a)/2)] + b[:(len(b)/2)] + a[(len(a)/2):] + b[(len(b)/2):] else: #todo! Not yet done. :P return I'm getting an error in the IF conditional. What am I doing wrong?

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  • Python - How to wake up a sleeping process- multiprocessing?

    - by user1162512
    I need to wake up a sleeping process ? The time (t) for which it sleeps is calculated as t = D/S . Now since s is varying, can increase or decrease, I need to increase/decrease the sleeping time as well. The speed is received over a UDP procotol. So, how do I change the sleeping time of a process, keeping in mind the following:- If as per the previous speed `S1`, the time to sleep is `(D/S1)` . Now the speed is changed, it should now sleep for the new time,ie (D/S2). Since, it has already slept for D/S1 time, now it should sleep for D/S2 - D/S1. How would I do it? As of right now, I'm just assuming that the speed will remain constant all throughout the program, hence not notifying the process. But how would I do that according to the above condition? def process2(): p = multiprocessing.current_process() time.sleep(secs1) # send some packet1 via UDP time.sleep(secs2) # send some packet2 via UDP time.sleep(secs3) # send some packet3 via UDP Also, as in threads, 1) threading.activeCount(): Returns the number of thread objects that are active. 2) threading.currentThread(): Returns the number of thread objects in the caller's thread control. 3) threading.enumerate(): Returns a list of all thread objects that are currently active. What are the similar functions for getting activecount, enumerate in multiprocessing?

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  • Is there a better way to write this URL Manipulation in Python?

    - by dnolen
    I'm curious if there's a simpler way to remove a particular parameter from a url. What I came up with is the following. This seems a bit verbose. Libraries to use or a more pythonic version appreciated. parsed = urlparse(url) if parsed.query != "": params = dict([s.split("=") for s in parsed.query.split("&")]) if params.get("page"): del params["page"] url = urlunparse((parsed.scheme, None, parsed.path, None, urlencode(params.items()), parsed.fragment,)) parsed = urlparse(url)

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  • Putting newline in matplotlib label with TeX in Python?

    - by user248237
    How can I add a newline to a plot's label (e.g. xlabel or ylabel) in Matplotlib? For example, plt.bar([1, 2], [4, 5]) plt.xlabel("My x label") plt.ylabel(r"My long label with $\Sigma_{C}$ math \n continues here") Ideally i'd like the y-labeled to be centered too. Is there a way to do this? It's important that the label have both tex (enclosed in '$') and the newline. thanks.

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  • How to censor IP addresses in a file with Python?

    - by Julio
    Hello everyone. I have a log file containing some Whois entries with relative IP addresses which I want to censor like: 81.190.123.123 in 81.190.xxx.xxx. Is there a way to make such a conversion and rewrite the file contents without modifying the rest? Thank you for the help!

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