Search Results

Search found 3984 results on 160 pages for 'jpg'.

Page 23/160 | < Previous Page | 19 20 21 22 23 24 25 26 27 28 29 30  | Next Page >

  • Amazon access key showing in URL for Carrierwave and Fog

    - by kcurtin
    I just switched from storing my images uploaded via Carrierwave locally to using Amazon s3 via the fog gem in my Rails 3.1 app. While images are being added, when I click on an image in my application, the URL is providing my access key and a signature. Here is a sample URL (XXX replaced the string with the info): https://s3.amazonaws.com/bucketname/uploads/photo/image/2/IMG_4842.jpg?AWSAccessKeyId=XXX&Signature=XXX%3D&Expires=1332093418 This is happening in development (localhost:3000) and when I am using heroku for production. Here is my uploader: class ImageUploader < CarrierWave::Uploader::Base include CarrierWave::RMagick storage :fog def store_dir "uploads/#{model.class.to_s.underscore}/#{mounted_as}/#{model.id}" end process :convert => :jpg process :resize_to_limit => [640, 640] version :thumb do process :convert => :jpg process :resize_to_fill => [280, 205] end version :avatar do process :convert => :jpg process :resize_to_fill => [120, 120] end end And my config/initializers/fog.rb : CarrierWave.configure do |config| config.fog_credentials = { :provider => 'AWS', :aws_access_key_id => 'XXX', :aws_secret_access_key => 'XXX', } config.fog_directory = 'bucketname' config.fog_public = false end Anyone know how to make sure this information isn't available?

    Read the article

  • populate textboxs with xml node attributes

    - by Doug
    I have Data.xml: <?xml version="1.0" encoding="utf-8" ?> <data> <album> <slide title="Autum Leaves" description="Leaves from the fall of 1986" source="images/Autumn Leaves.jpg" thumbnail="images/Autumn Leaves_thumb.jpg" /> <slide title="Creek" description="Creek in Alaska" source="images/Creek.jpg" thumbnail="images/Creek_thumb.jpg" /> </album> </data> I'd like to be able to edit the attributes of each Slide node via GridView (that has a "Select" column added.) And so far I have: protected void GridView1_SelectedIndexChanged(object sender, EventArgs e) { int selectedIndex = GridView1.SelectedIndex; LoadXmlData(selectedIndex); } private void LoadXmlData(int selectedIndex) { XmlDocument xmldoc = new XmlDocument(); xmldoc.Load(MapPath(@"..\photo_gallery\Data.xml")); XmlNodeList nodelist = xmldoc.DocumentElement.ChildNodes; XmlNode xmlnode = nodelist.Item(selectedIndex); titleTextBox.Text = xmlnode.Attributes["title"].InnerText; descriptionTextBox.Text = xmlnode.Attributes["description"].InnerText; sourceTextBox.Text = xmlnode.Attributes["source"].InnerText; thumbTextBox.Text = xmlnode.Attributes["thumbnail"].InnerText; The code for LoadXmlData is just a guess on my part - I'm new to working with xml in this way. I'd like have the user to slected the row from the gridview, then populate a set of text boxes with each slide attributed for updating back to the Data.xml file. The error I'm getting is "Object reference not set to an instance of an object" at the line: titleTextBox.Text = xmlnode.Attributes["@title"].InnerText; - so I'm not reaching the attribute "title" of the slide node. Thanks for any ideas you may have.

    Read the article

  • Generating dynamic css using php and javascript

    - by Onkar Deshpande
    I want to generate tooltip based on a dynamically changing background image in css. This is my my_css.php file. <?php header('content-type: text/css'); $i = $_GET['index']; if($i == 0) $bg_image_path = "../bg_red.jpg"; elseif ($i == 1) $bg_image_path = "../bg_yellow.jpg"; elseif ($i == 2) $bg_image_path = "../bg_green.jpg"; elseif ($i == 3) $bg_image_path = "../bg_blue.jpg"; ?> .tooltip { white-space: nowrap; color:green; font-weight:bold; border:1px solid black;; font-size:14px; background-color: white; margin: 0; padding: 7px 4px; border: 1px solid black; background-image: url(<?php echo $bg_image_path; ?>); background-repeat:repeat-x; font-family: Helvetica,Arial,Sans-Serif; font-family: Times New Roman,Georgia,Serif; filter:alpha(opacity=85); opacity:0.85; zoom: 1; } In order to use this css I added <link rel="stylesheet" href="css/my_css.php" type="text/css" media="screen" /> in my html <head> tag of javascript code. I am thinking of passing different values of 'index' so that it would generate the background image dynamically. Can anyone tell me how should I pass such values from a javascript ? I am creating the tooltip using var tooltip = document.createElement("div"); document.getElementById("map").appendChild(tooltip); tooltip.style.visibility="hidden"; and I think before calling this createElement, I should set background image.

    Read the article

  • Bullets WILL NOT dissapear in firefox

    - by DunlopBurns
    Hoping you can help me with a problem. I cannot get rid of Bullets in Firefox, i don't want any anywhere, hence my list-style-type: none!important being everywhere. It only appears in Firefox as far as i can tell. the HTML.... <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" lang="en" xml:lang="en"> <head> <title>littleprints.nl</title> <meta name="description" content="----" /> <meta name="keywords" content="----" /> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4/jquery.min.js"></script> <script type="text/javascript" src="js/slimbox2.js"></script> <link rel="stylesheet" href="css/slimbox2.css" type="text/css" media="screen" /> <link rel="stylesheet" href="layout.css"/> <link rel="stylesheet" href="style.css"/> </head> <body> <div id="container"> <div id="inline1"> <div id="mainpic"> <img src="myimages/circle.jpg" width="100%" alt="Circle bracelet"/> </div> <div id="intro"> <p>Hi and welcome to little prints NL. we make this and that all by hand with 100% silver. my name is Donna Burns and i work by commision, ive been studying for 4 years and am currently learning to become a goldsmith.</p> </div> </div> <div id="inline2"> <p>Click for more...</p> <div id="images"> <a href="myimages/photos/dogtag.jpg" rel="lightbox-gal" title="Beautiful, isn't it?" ><img src="myimages/work/chunky.gif" alt="chunky"/></a> <a href="myimages/photos/hearts.jpg" rel="lightbox-gal" title="Beautiful, isn't it?" ><img src="myimages/work/hearts.gif" alt="hearts"/></a> <a href="myimages/photos/close.jpg" rel="lightbox-gal" title="Beautiful, isn't it?" ><img src="myimages/work/close.gif" alt="close"/></a> <a href="myimages/photos/pearl.jpg" rel="lightbox-gal" title="Beautiful, isn't it?" >&nbsp;</a> <a href="myimages/photos/flower.jpg" rel="lightbox-gal" title="Beautiful, isn't it?" >&nbsp;</a> <a href="myimages/photos/frontcircle.jpg" rel="lightbox-gal" title="Beautiful, isn't it?" >&nbsp;</a> <a href="myimages/photos/dogtag.jpg" rel="lightbox-gal" title="Beautiful, isn't it?" >&nbsp;</a> </div> </div> </div><!--end container--> <div id="footer"> <div id="footalign"> <div id="social"> <ul> <li> <a href="http://www.facebook.com/littleprints" title="Little Prints"> <img src="myimages/facebook.png" width="50px" height="50px" alt="FB"/> </a> </li> <li> <a href="contact.html" title="contact"> <img src="myimages/at.gif" alt="@"/> </a> </li> </ul> </div> <div id="contact"> <p><br/>To enquire about a charm either phone:<br/> 0787463289<br/> or use one of the methods to the side.</p> </div> </div> </div> </body> </html> the CSS... * {margin: 0; padding: 0; border: 0;} html, body { background-color: #000000;image; text-align: center; font: 16px/1.8 Verdana, Arial, Helvetica, sans-serif; list-style-type: none!important; text-decoration: none;} #container { position: relative; width: 900px; top: 0; min-height: 100%; margin-left: auto; margin-right: auto; padding-top: 20px; background-image: URL(myimages/back2.gif); margin-bottom: 180px; } #footer { background-color: #555555; position: relative; clear: both; bottom: 0; width: 900px; height: auto; margin-left: auto; margin-right: auto; margin-bottom: 20px; padding-bottom: 22px; margin-top: -180px; } #inline1{ display: inline-block; margin-top: 250px; margin-bottom: 20px; } #inline2 { display: inline-block; margin-top: 30px; margin-bottom: 50px; } #mainpic { float: left; width: 68%; margin-left: 20px; } #intro { float: right; width: 20%; margin-left: auto; margin-right: 50px; margin-top: 20px; } #images { margin-bottom: 20px; margin-left: auto; margin-right: auto; } #footalign { display: inline; width:900px; list-style-type: none; } #contact { text-align: center; background-color:#555555; float: middle; list-style-type: none; } #social{ background-color:#555555; float: right; list-style: none; padding:0; padding-right: 5px; text-align:center; list-style-type: none!important; } #social img{ border: none; list-style-type: none!important; margin: 3px; } #social ul{ border: none; list-style-type: none!important; } #social a{ display:inline-block; -webkit-transition:all .5s ease-out; -moz-transition:all .5s ease-out; -ms-transition:all .5s ease-out; -o-transition:all .5s ease-out; transition:all .5s ease-out; list-style-type: none!important; } #social a:hover{ display:inline-block; -webkit-transform:translate(-10px,0px); -moz-transform:translate(0px,-10px); -ms-transform:translate(-10px,0px); -o-transform:translate(-10px,0px); transform:translate(-10px,0px); list-style-type: none!important; } #form { margin-top: 250px; margin-bottom: 50px; } .nav1 {font-family: sans-serif;font-size: 22px;text-shadow: 2px 2px 5px #000000;} a:link {text-decoration:none; color:#000000; padding:3px;} a:visited {text-decoration:none; color:#000000;} a:active {text-decoration:none; color:#555555;} a:hover {text-decoration:none; color:#555555;} .nav2 {font-family: sans-serif;font-size: 22px;text-shadow: 2px 2px 5px #ffffff;} a:link {text-decoration:none; color:#ffffff; padding:3px;} a:visited {text-decoration:none; color:#ffffff;} a:active {text-decoration:none; color:#555555;} a:hover {text-decoration:none; color:#555555;} .p1 { color: #ffffff; } div#images img { max-width: 500px; height: auto; }

    Read the article

  • Condensing repeating JQuery code

    - by Craig Ward
    I have a page that has a large image on it with a number of thumbnails. When you mouse over a thumbnail the main image changes to the image you have just rolled your mouse over. The problem is the more thumbnails I have, the more repeated code I have. How could I reduce it? The Jquery code is as follows. <script type="text/javascript"> $('#thumb1') .mouseover(function(){ $('#big_img').fadeOut('slow', function(){ $('#big_img').attr('src', '0001.jpg'); $('#big_img').fadeIn('slow'); }); }); $('#thumb2') .mouseover(function(){ $('#big_img').fadeOut('slow', function(){ $('#big_img').attr('src', 'p_0002.jpg'); $('#big_img').fadeIn('slow'); }); }); $('#thumb3') .mouseover(function(){ $('#big_img').fadeOut('slow', function(){ $('#big_img').attr('src', '_img/p_0003.jpg'); $('#big_img').fadeIn('slow'); }); }); $('#thumb4') .mouseover(function(){ $('#big_img').fadeOut('slow', function(){ $('#big_img').attr('src', '0004.jpg'); $('#big_img').fadeIn('slow'); }); }); </script> #big_img = the ID of the full size image #thumb1, #thumb2, #thumb3, #thumb4 = The ID's of the thumbnails The main code for the page is PHP if that helps.

    Read the article

  • jQuery: appendTo parent

    - by Kenneth B
    Hi guys I can't seem to get the appendTo to work. What do I do wrong? $('div:nth-child(2n) img').appendTo(parent); Current markup: <div class="container"> <img src="123.jpg" /> <p>Hey</p> </div> <div class="container"> <img src="123.jpg" /> <p>Hey</p> </div> I want this output: <div class="container"> <p>Hey</p> <img src="123.jpg" /> </div> <div class="container"> <p>Hey</p> <img src="123.jpg" /> </div> Please help me guys... I'm tearing my hair of every minute.. :-S

    Read the article

  • Indexing community images for google image search

    - by Vittorio Vittori
    Hi, I'm trying to understand how can I do to let my site be reachable from google image search spiders. I like how last.fm solution, and I thought to use a technique like his staff do to let google find artists images on their pages. When I'm looking for an artist and I search it on google image search, as often as not I find an image from last.fm artists page, I make an example: If I search the band Pure Reason Revolution It brings me here, the artist's image page http://www.last.fm/music/Pure+Reason+Revolution/+images/4284073 Now if I take a look to the image file, i can see it's named: http://userserve-ak.last.fm/serve/500/4284073/Pure+Reason+Revolution+4.jpg so if I try to undertand how the service works I can try to say: http://userserve-ak.last.fm/serve/ the server who serve the images 500/ the selected size for the image 4284073/ the image id for database Pure+Reason+Revolution+4.jpg the image name I thought it's difficult to think the real filename for the image is Pure+Reason+Revolution+4.jpg for image overwrite problems when an user upload it, in fact if I digit: http://userserve-ak.last.fm/serve/500/4284073.jpg I probably find the real image location and filename With this tecnique the image is highly reachable from search engines and easily archived. My question is, does exist some guide or tutorial to approach on this kind of tecniques, or something similar?

    Read the article

  • Flash AS3 loading XML into listbox

    - by Anne
    I am able to load my XML file into flash and trace results. Want to populate listbox with information from xml file. Structure of xml file: <eBorders> <item> <thumb>borderTh/blank_th.jpg</thumb> <file>border/blank.jpg</file> </item> <item> <thumb>borderTh/border1_th.jpg</thumb> <file>border/border1.jpg</file> </item> </eBorders> AS3 code: var myLoader:URLLoader = new URLLoader(); myLoader.load(new URLRequest("xml/borders.xml")); var dp:DataProvider = new DataProvider("borders.xml"); border_lb.dataProvider = dp; border_lb.iconField = "iconSource"; border_lb.rowHeight = 45; function processXML(e:Event):void { myXML = new XML(e.target.data); for(var i:int=0;i<myXML.*.length(); i++){ dp.addItem({iconSource:myXML.item.thumb.[i]}); } } Code is producing error I can't find. Thank you in advance for any help you might offer. Annie

    Read the article

  • Replace relative urls to absolute

    - by Rocky Singh
    I have the html source of a page in a form of string with me: <html> <head> <link rel="stylesheet" type="text/css" href="/css/all.css" /> </head> <body> <a href="/test.aspx">Test</a> <a href="http://mysite.com">Test</a> <img src="/images/test.jpg"/> <img src="http://mysite.com/images/test.jpg"/> </body> </html> I want to convert all the relative paths to absolute. I want the output be: <html> <head> <link rel="stylesheet" type="text/css" href="http://mysite.com/css/all.css" /> </head> <body> <a href="http://mysite.com/test.aspx">Test</a> <a href="http://mysite.com">Test</a> <img src="http://mysite.com/images/test.jpg"/> <img src="http://mysite.com/images/test.jpg"/> </body> </html> Note: I want only the relative paths to be converted to absolute ones in that string. The absolute ones which are already in that string should not be touched, they are fine to me as they are already absolute. Can this be done by regex or other means?

    Read the article

  • jQuery UI sortable - sorting images

    - by GSTAR
    I've just implemented the jQuery UI sortable plugin for a set of images. The markup I have is as follows: <ul id="images" class="ui-sortable"> <li id="7884029"><img src="/images/member/4698568/7884029_t.jpg" alt="" /></li> <li id="7379458"><img src="/images/member/4698568/7379458_t.jpg" alt="" /></li> <li id="1704208"><img src="/images/member/4698568/1704208_t.jpg" alt="" /></li> <li id="1750715"><img src="/images/member/4698568/1750715_t.jpg" alt="" /></li> <li id="4364912"><img src="/images/member/4698568/4364912_t.png" alt="" /></li> </ul> <script type="text/javascript"> /*<![CDATA[*/ jQuery(function($) { jQuery('#images').sortable({'delay':'100'}); }); /*]]>*/ </script> The LI id is the 'name' column in the DB table - I prefer not to display the ID column. Now my question is how do I capture the sorting? I understand this would be an AJAX request but I have no idea how to do it. I have set up a sort_order column in my DB table and I am using PHP as my scripting language. I could do with a code example. EDIT: Ideally I prefer if the sort order is applied upon moving an item, i.e. I do not want to enclose it all in a form.

    Read the article

  • How do I reference my MainViewController from another class?

    - by todd412
    Hi, I am building an iPhone Utility app that uses UIImageView to display an animation. Within the MainViewController's viewDidLoad() method, I am creating an instance of a CustomClass, and then setting up the animations: - (void)viewDidLoad { [super viewDidLoad]; cc = [CustomClass new]; NSArray * imageArray = [[NSArray alloc] initWithObjects: [UIImage imageNamed:@"image-1-off.jpg"], [UIImage imageNamed:@"image-2-off.jpg"], [UIImage imageNamed:@"image-3-off.jpg"], [UIImage imageNamed:@"image-4-off.jpg"], nil]; offSequence = [[UIImageView alloc] initWithFrame:CGRectMake(0, 0, 320, 480)]; offSequence.animationImages = imageArray; offSequence.animationDuration = .8; offSequence.contentMode = UIViewContentModeBottomLeft; [self.view addSubview:offSequence]; [offSequence startAnimating]; } That works fine. However, I would like to be able to move all the above code that sets up the UIImageView into my CustomClass. The problem is in the second to last line: [self.view addSubview:offSequence]; I basically need to replace 'self' with a reference to the MainControllerView, so I can call addSubview from within my CustomClass. I tried creating an instance var of CustomClass called mvc and a setter method that takes a reference to the MainViewController as an argument as such: - (void) setMainViewController: (MainViewController *) the_mvc { mvc = the_mvc; } And then I called it within MainViewController like so: [cc setMainController:MainViewController:self]; But this yields all sorts of errors which I can post here, but it strikes me that I may be overcomplicating this. Is there an easier way to reference the MainViewController that instanatiated my CustomClass?

    Read the article

  • Prepare community images for google image search indexing

    - by Vittorio Vittori
    Hi, I'm trying to understand how can I do to let my site be reachable from google image search spiders. I like how last.fm solution, and I thought to use a technique like his staff do to let google find artists images on their pages. When I'm looking for an artist and I search it on google image search, as often as not I find an image from last.fm artists page, I make an example: If I search the band Pure Reason Revolution It brings me here, the artist's image page http://www.last.fm/music/Pure+Reason+Revolution/+images/4284073 Now if I take a look to the image file, i can see it's named: http://userserve-ak.last.fm/serve/500/4284073/Pure+Reason+Revolution+4.jpg so if I try to undertand how the service works I can try to say: http://userserve-ak.last.fm/serve/ the server who serve the images 500/ the selected size for the image 4284073/ the image id for database Pure+Reason+Revolution+4.jpg the image name I thought it's difficult to think the real filename for the image is Pure+Reason+Revolution+4.jpg for image overwrite problems when an user upload it, in fact if I digit: http://userserve-ak.last.fm/serve/500/4284073.jpg I probably find the real image location and filename With this tecnique the image is highly reachable from search engines and easily archived. My question is, does exist some guide or tutorial to approach on this kind of tecniques, or something similar?

    Read the article

  • Java/Groovy File IO Replacing an Image File with it's own Contents - Why Does This Work?

    - by jboyd
    I have some JPG files that need to be replaced at runtime with a JFIF standardized version of themselves (we are using a vendor that gives us JPG that do not have proper headers so they don't work in certain applications)... I am able to create a new file from the existing image, then get a buffered image from that file and write the contents right back into the file without having to delete it and it works... imageSrcFolder.eachFileMatch ( ~/.*\.jpg/, { BufferedImage bi = ImageIO.read( it ) ImageIO.write( bi, "jpg", it ) }); The question I have is why? Why doesn't the file end up doubled in size? Why don't I have to delete it first? Why am I able to take a file object to an existing file and then treat it as if it were a brand new one? It seems that what I consider to be a "file" is not what the File object in java actually is, or else this wouldn't work at all. My code does exactly what I want it to do, but I'm not convinced it always will... it just seems way too easy

    Read the article

  • Prepare your site images for google image search indexing

    - by Vittorio Vittori
    Hi, I'm trying to understand how can I do to let my site be reachable from google image search spiders. I like how last.fm solution, and I thought to use a technique like his staff do to let google find artists images on their pages. When I'm looking for an artist and I search it on google image search, as often as not I find an image from last.fm artists page, I make an example: If I search the band Pure Reason Revolution It brings me here, the artist's image page http://www.last.fm/music/Pure+Reason+Revolution/+images/4284073 Now if I take a look to the image file, i can see it's named: http://userserve-ak.last.fm/serve/500/4284073/Pure+Reason+Revolution+4.jpg so if I try to undertand how the service works I can try to say: http://userserve-ak.last.fm/serve/ the server who serve the images 500/ the selected size for the image 4284073/ the image id for database Pure+Reason+Revolution+4.jpg the image name I thought it's difficult to think the real filename for the image is Pure+Reason+Revolution+4.jpg for image overwrite problems when an user upload it, in fact if I digit: http://userserve-ak.last.fm/serve/500/4284073.jpg I probably find the real image location and filename With this tecnique the image is highly reachable from search engines and easily archived. My question is, does exist some guide or tutorial to approach on this kind of tecniques, or something similar?

    Read the article

  • How can i fetch the large image from url

    - by Kutbi
    i used below code to fetch the image from url.but its not working for large image.. i missing something to add for that type of image to fetch. imgView = (ImageView)findViewById(R.id.ImageView01); imgView.setImageBitmap(loadBitmap("http://www.360technosoft.com/mx4.jpg")); //imgView.setImageBitmap(loadBitmap("http://sugardaddydiaries.com/wp-content/uploads/2010/12/how_do_i_get_sugar_daddy.jpg")); //setImageDrawable("http://sugardaddydiaries.com/wp-content/uploads/2010/12/holding-money-copy.jpg"); //Drawable drawable = LoadImageFromWebOperations("http://www.androidpeople.com/wp-content/uploads/2010/03/android.png"); //imgView.setImageDrawable(drawable); /* try { ImageView i = (ImageView)findViewById(R.id.ImageView01); Bitmap bitmap = BitmapFactory.decodeStream((InputStream)new URL("http://sugardaddydiaries.com/wp-content/uploads/2010/12/holding-money-copy.jpg").getContent()); i.setImageBitmap(bitmap); } catch (MalformedURLException e) { System.out.println("hello"); } catch (IOException e) { System.out.println("hello"); }*/ } protected Drawable ImageOperations(Context context, String string, String string2) { // TODO Auto-generated method stub try { InputStream is = (InputStream) this.fetch(string); Drawable d = Drawable.createFromStream(is, "src"); return d; } catch (MalformedURLException e) { e.printStackTrace(); return null; } catch (IOException e) { e.printStackTrace(); return null; } }

    Read the article

  • Creating a method for wrapping a loaded image in a UIImageView

    - by eco_bach
    I have the following un my applicationDidFinishLaunching method UIImage *image2 = [UIImage imageWithContentsOfFile:[[NSBundle mainBundle] pathForResource:@"image2.jpg" ofType:nil]]; view2 = [[UIImageView alloc] initWithImage:image2]; view2.hidden = YES; [containerView addSubview:view2]; I'm simply adding an image to a view. But because I need to add 30-40 images I need to wrap the above in a function (which returns a UIImageView) and then call it from a loop. This is my first attempt at creating the function -(UIImageView)wrapImageInView:(NSString *)imagePath { UIImage *image = [UIImage imageWithContentsOfFile:[[NSBundle mainBundle] pathForResource:imagePath ofType:nil]]; UIImageView *view = [[UIImageView alloc] initWithImage:image]; view.hidden = YES; } And then to invoke it I have the following so far, for simplicity I am only wrapping 3 images //Create an array and add elements to it NSMutableArray *anArray = [[NSMutableArray alloc] init]; [anArray addObject:@"image1.jpg"]; [anArray addObject:@"image2.jpg"]; [anArray addObject:@"image3.jpg"]; //Use a for each loop to iterate through the array for (NSString *s in anArray) { UIImageView *wrappedImgInView=[self wrapImage:s]; [containerView addSubview:wrappedImgInView]; NSLog(s); } //Release the array [anArray release]; I have 2 general questions 1-Is my approach correct?, ie following best practices, for what I am trying to do (load a multiple number of images(jpgs, pngs, etc.) and adding them to a container view) 2-For this to work properly with a large number of images, do I need to keep my array creation separate from my method invocation? Any other suggestions welcome!

    Read the article

  • loopedSlider jQuery plugin problem

    - by kil4
    Hi i use loopedSlider link text and there is html source. <div id="loopedSlider"> <div class="container"> <div class="slides"> <div><img src="01.jpg" alt="" /></div> <div><img src="02.jpg" alt="" /></div> <div><img src="03.jpg" alt="" /></div> <div><img src="04.jpg" alt="" /></div> </div></div><a href="#" class="previous">previous</a> <a href="#" class="next">next</a><ul class="pagination"> <li><a href="#">1</a></li> <li><a href="#">2</a></li> <li><a href="#">3</a></li> <li><a href="#">4</a></li> Is there possible to insert div like this: <div class="slides"> <div> <div class="newdiv">Some text</div> </div> </div> If i insert this div "newdiv" inside is not showing? Any solution ?

    Read the article

  • Creating Thumbnails with CFImage Aborting Because of Server Load?

    - by nephilite
    I am uploading in image via a form and I want to, in addition to saving the image, save a variety of thumbnails in both png and jpg format. To do this I am using the code below. The initial image uploads fine but then, after spinning for a moment I get an error of: "Request aborted due to heavy system load." (from my host crystaltech), and none of the thumbnails have made it through. I've tried it with even just one resize (and no converts) and it still fails. What am I doing wrong? This issue is somewhat urgent....Thanks! ` <cffile action="upload" destination="#Application.filePath#Icons\#app#Icon.png" filefield="Icon" nameconflict="overwrite"> <cfimage source="#Application.filePath#Icons\#app#Icon.png" action="resize" width="50%" height="50%" destination="#Application.filePath#Icons\#app#Icon_Half.png" overwrite="yes"> <cfimage source="#Application.filePath#Icons\#app#Icon.png" action="resize" width="25%" height="25%" destination="#Application.filePath#Icons\#app#Icon_Quarter.png" overwrite="yes"> <cfimage source="#Application.filePath#Icons\#app#Icon.png" action="convert" destination="#Application.filePath#Icons\#app#Icon.jpg"> <cfimage source="#Application.filePath#Icons\#app#Icon_Half.png" action="convert" destination="#Application.filePath#Icons\#app#Icon_Half.jpg"> <cfimage source="#Application.filePath#Icons\#app#Icon_Quarter.png" action="convert" destination="#Application.filePath#Icons\#app#Icon_Quarter.jpg"> `

    Read the article

  • Images from url to listview

    - by Andres
    I have a listview which I show video results from YouTube. Everything works fine but one thing I noticed is that the way it works seems to be a bit slow and it might be due to my code. Are there any suggestions on how I can make this better? Maybe loading the images directly from the url instead of using a webclient? I am adding the listview items in a loop from video feeds returned from a query using the YouTube API. The piece of code which I think is slowing it down is this: Feed<Video> videoFeed = request.Get<Video>(query); int i = 0; foreach (Video entry in videoFeed.Entries) { string[] info = printVideoEntry(entry).Split(','); WebClient wc = new WebClient(); wc.DownloadFile(@"http://img.youtube.com/vi/" + info[0].ToString() + "/hqdefault.jpg", info[0].ToString() + ".jpg"); string[] row1 = { "", info[0].ToString(), info[1].ToString() }; ListViewItem item = new ListViewItem(row1, i); YoutubeList.Items.Add(item); imageListSmall.Images.Add(Bitmap.FromFile(info[0].ToString() + @".jpg")); imageListLarge.Images.Add(Bitmap.FromFile(info[0].ToString() + @".jpg")); } public static string printVideoEntry(Video video) { return video.VideoId + "," + video.Title; } As you can see I use a Webclient which downloads the images so then I can use them as image in my listview. It works but what I'm concerned about is speed..any suggestions? maybe a different control all together?

    Read the article

  • Problems with video conversions through the web (local host)

    - by ron-d
    Hello, I get the following errors when I attempt video format conversions called from the local host: “An invalid media type was specified” for M4V to WMV conversions. “One or more arguments are invalid” for MP4 to WMV conversions. Here are the details of the problems: I’ve written a dll in C# that accepts videos in the formats AVI, WMV, M4V and MP4 and performs the following actions: Creates a copy of the input video in WMV format . Creates a WAV file of the input video audio portion. Creates a JPG image from a frame of the input video. I attached the dll to an ASP.NET web project that performs the dll actions. When tested through the developer studio, the actions are performed as intended for all formats. When I place the web project in place to be read when the local host is called through the web browser, the following behavior takes place: WMV format: All actions performed as intended. AVI format: Creates WMV file – OK Creates JPG image – OK Creates empty WAV file – problem. M4V format: Creates empty WAV file – problem. Does not create WMV file -problem Does not create JPG file –problem Throws me the error “An invalid media type was specified” MP4 format: Creates empty WAV file – problem. Does not create WMV file -problem Does not create JPG file –problem Throws me the error “One or more arguments are invalid” When I check their security property, all the files have the same permission access parameters (when I check their security property. Can anyone guide me as to how to solve these problems when the web project is called from the local host? Thank you.

    Read the article

  • PHP & WP: Render Certain Markup Based on True False Condition

    - by rob
    So, I'm working on a site where on the top of certain pages I'd like to display a static graphic and on some pages I would like to display an scrolling banner. So far I set up the condition as follows: <?php $regBanner = true; $regBannerURL = get_bloginfo('stylesheet_directory'); //grabbing WP site URL ?> and in my markup: <div id="banner"> <?php if ($regBanner) { echo "<img src='" . $regBannerURL . "/style/images/main_site/home_page/mock_banner.jpg' />"; } else { echo 'Slider!'; } ?> </div><!-- end banner --> In my else statement, where I'm echoing 'Slider!' I would like to output the markup for my slider: <div id="slider"> <img src="<?php bloginfo('stylesheet_directory') ?>/style/images/main_site/banners/services_banners/1.jpg" alt="" /> <img src="<?php bloginfo('stylesheet_directory') ?>/style/images/main_site/banners/services_banners/2.jpg" alt="" /> <img src="<?php bloginfo('stylesheet_directory') ?>/style/images/main_site/banners/services_banners/3.jpg" alt="" /> ............. </div> My question is how can I throw the div and all those images into my else echo statement? I'm having trouble escaping the quotes and my slider markup isn't rendering.

    Read the article

  • Access denied to path , when uploading image to folder in server

    - by apekshabs
    Am getting error when you are going to upload the file on specified folder in the server. Here I am going to upload P6100083.jpg in storeimg folder. When I am going to upload I am getting the following error: Access to the path 'C:\inetpub\vhosts\bookmygroups.com\httpdocs\storeimg\P6100083.jpg' is denied. Can anyone help me... How to use permisiion and were to use... My code is while uploading image if (FileUpload1.HasFile) { float fileSize = FileUpload1.PostedFile.ContentLength; float floatConverttoKB = fileSize / 1024; float floatConverttoMB = floatConverttoKB / 1024; string DirName = "storeimg"; string savepath = Server.MapPath(DirName + "/"); DirectoryInfo dir = new DirectoryInfo(savepath); // string savepath = "C:\\Documents and Settings\\ssis3\\My Documents\\Visual Studio 2005\\WebSites\\finalbookgroups\\" + DirName + "\\"; if (fileSize < 4194304) { string filename = Server.HtmlEncode(FileUpload1.FileName); string extension = System.IO.Path.GetExtension(filename).ToUpper(); if (extension.Equals(".jpg") || extension.Equals(".JPG") || extension.Equals(".JPEG") || extension.Equals(".GIF")) { savepath += filename; FileUpload1.SaveAs(savepath); } } Thanks in advance

    Read the article

  • Selections and radioing - JavaScript

    - by Wayne
    I have a list like this: <ul> <li id="adm-thumb" onclick="javascript:addBanner('bowling.jpg');"> <div class="adm-tick"></div> <img src="img/banners/bowling.jpg" /></li> <li id="adm-thumb" onclick="javascript:addBanner('kcc.jpg');"> <div class="adm-tick"></div> <img src="img/banners/kcc.jpg" /></li> <li id="adm-thumb" onclick="javascript:addBanner('paintballing.png');"> <div class="adm-tick"></div> <img src="img/banners/paintballing.png" /></li> </ul> <input id="bannername" type="text" /> When one item is clicked, the value inside the addBanner() will be added to the input field, however, I want one list to be selected (which is done by css to make it look like it has) when it is equal to the value of the input value. If the value is equals to the value in the addBanner value then the clicked item should have a red background. e.g. function addBanner(label) { var Field = document.getElementById('bannername'); Field.value = label; if(Field.value != label) { // I have no idea what to put here } } Something like a div button that acts like a radio button.

    Read the article

  • Generating ul from array with php fails

    - by Toni Michel Caubet
    Given a $files array I am trying to generate a list, like this: <ul class=""> <? for($i=0;$i < count($files); $i++) { $text = str_replace("http://domain.com/files/uploads/", "", $files[$i]); $file = $files[$i]; $notme = sesion()>0 && $obj['id'] != sesion(); ?> <li> <a target="_blank" href="<?=$file?>"><?=$text?></a> <? if($notme){ ?> <span class="add_to_files" data-file="<?=$file?>">Agregar al gestor</span> <? } ?> </li> <? } ?> </ul> This is the output: Please note how the span html is wrong, <ul class=""> <li> <a href="http://domain.com/files/uploads/388400967232883.jpg" target="_blank">388400967232883.jpg</a> <span target="_blank" href="http://domain.com/files/uploads/388400967232883.jpg" url"="" data-file="&lt;a class=" class="add_to_files">http://domain.com/files/uploads/388400967232883.jpg"&gt;Agregar al gestor</span> </li> </ul> Any idea why?

    Read the article

  • PHP: problem rendering large images (error 321)

    - by JP19
    Hi ... its me again with a php problem :) Following is part of my PHP script which is rendering JPEG images. ... $tf=$requested_file; $image_type="jpeg"; header("Content-type: image/${image_type}"); $CMD="\$image=imagecreatefrom${image_type}('$tf'); image${image_type}(\$image);"; eval($CMD); exit; ... There is no syntactical error, because above code is working fine for small images, but for large images, it gives: Error 321 (net::ERR_INVALID_CHUNKED_ENCODING): Unknown error. in the browser. To be sure, I created two images using imagemagick from same source image - one resized to 10% of original and other 90%. http://mostpopularsports.net/images/misc/ttt10.jpg works http://mostpopularsports.net/images/misc/ttt90.jpg gives Error 301 in the browser. There is a related question with solution posted by OP here Error writing content through Apache. but I cannot understand how to make the fix. Can someome help me with it? I have looked at the headers in Chrome. For the first request, everything is fine. For the second request - the request headers are all garbled. Both images are jpeg (as they are created from imagemagick. But still to be sure I checked): misc/ttt10.jpg: JPEG image data, JFIF standard 1.01 misc/ttt90.jpg: JPEG image data, JFIF standard 1.01 Finally, the way I fixed is, remove the Transfer-Encoding: chunked header from the response. [This header was sent by apache only when the data was large enough]. (I had an internal proxy, so did it in the proxy script - otherwise one may need to do it in apache settings). There were some good answers and I have selected the one that helped me solve the problem best. thanks JP

    Read the article

< Previous Page | 19 20 21 22 23 24 25 26 27 28 29 30  | Next Page >