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  • Looking for a FormBuilder that gives me all images and sourcecode to my form

    - by Tracy Anne
    Wow, I started my search this morning and didn't think it would be so difficult to find. I'm just tired of spending hours putting together simple html forms in dreamweaver. I'm an enthusiast web developer mostly focused on php and mysql. I hate CSS and HTML and I'm looking for a simple program that will put a form together for me where I can then completely embed the form into my site. I'll do all of the programming to attach it to my database I just need the form and images. I've looked into jotform, wufoo, 123forms etc but it seems like they all want to keep my form on their servers in one way or another. It looked like jotform had a developers version but $450 bucks is a little steep for a part timer like me. Is there no simple software out there that will throw a nice stylized form together for me?

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  • get mysql_real_escape is giving me errors when I try and add security to my website

    - by Mike
    I tried doing this: @ $db = new myConnectDB(); $beerName = mysql_real_escape_string($beerName); $beerID = mysql_real_escape_string($beerID); $brewery = mysql_real_escape_string($brewery); $style = mysql_real_escape_string($style); $userID = mysql_real_escape_string($userID); $abv = mysql_real_escape_string($abv); $ibu = mysql_real_escape_string($ibu); $breweryID = mysql_real_escape_string($breweryID); $icon = mysql_real_escape_string($icon); I get this error: Warning: mysql_real_escape_string() [function.mysql-real-escape-string]: Access denied for user

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  • Recreate JoliCloud app list

    - by Josh
    I was wondering if there was any tutorial on how to recreate the pagination system used on JoliCloud. The system shows the amount of pages at the bottom along with what page you are on. It is kind of like the iOS springboard. I would like for it to get the apps via a MySQL query, but that's besides the point. I've searched Google and have found no answers on how to do this. A screen shot of the pagination system is below.

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  • When to start thinking about scalability?

    - by Rits
    I'm having a funny but also terrible problem. I'm about to launch a new (iPhone) app. It's a turn-based multiplayer game running on my own custom backend. But I'm afraid to launch. For some reason, I think it might become something big and that its popularity will kill my poor lonely single server + MySQL database. On one hand I'm thinking that if it's growing, I'd better be prepared and have a scalable infrastructure already in place. On the other hand I just feel like getting it out into the world and see what happens. I often read stuff like "premature optimization is the root of all evil" or people saying that you should just build your killer game now, with the tools at hand, and worry about other stuff like scalability later. I'd love to hear some opinions on this from experts or people with experience with this. Thanks!

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  • Could you recommend a good shopping cart script?

    - by user649482
    I'm looking for a PHP/MySQL script, free or not. Could you please recommend me one that can do the following: The site I'm trying to build requires an extensive product catalogue, which will have around 600 products. Because there are so many products they will be uploaded using a CSV file or spreadsheet. Users must be logged in to see prices Users can add products to an order form, which they can then email to admin. (NO payment processing whatsoever) They will just add products to a cart, review the cart's content and click a button to send the order The order email to admin must have the order details attached in a CSV file. Newsletter Newsletter sign up. Admin can create and send newsletter from the admin section. User Login/Member Section After users sign up they can access their member section. In this section they can Edit their details See previous orders they have made, and click a button to send that order again Thank you! (the question is also posted here but with no replies)

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  • Store HighRes photos in Database or as File?

    - by David
    I run a site which has a couple of million photos and gets over 1000 photos uploaded each day. Up to now, we haven't kept the original file that was uploaded to conserve on space. However, we are getting to a point that we are starting to see a need to have high-res original versions. I was wondering if its better to store these in the filesystem as an actual file or if its better to store them in a database (ie: mysql). The highres images would be rarely referenced but may be used when someone decides to download it or we decide to use it for rare processes like making a new set of thumbnails sizes/etc.

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  • No databases showing in phpMyAdmin

    - by Thein Hla Maw
    My website is hosted in shared hosting service and is working fine with updated news stored in MySQL database. To manage the database of website, I install phpMyAdmin in a sub-folder with the same username and password used in website. When I login to phpMyAdmin, I don't see my database. phpMyAdmin is showing "No databases" in left pane. Is there any thing I need to configure in phpMyAdmin? Edited: This is the settings in config.inc.php. I can login to phpMyAdmin successfully. $cfg['Servers'][$i]['host'] = 'hostname'; $cfg['Servers'][$i]['port'] = ''; $cfg['Servers'][$i]['socket'] = ''; $cfg['Servers'][$i]['connect_type'] = 'tcp'; $cfg['Servers'][$i]['extension'] = 'mysqli'; $cfg['Servers'][$i]['auth_type'] = 'cookie'; $cfg['Servers'][$i]['user'] = 'dbuser'; $cfg['Servers'][$i]['password'] = 'password';

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  • Penny auction concept and how the timer works

    - by madi
    I am creating a penny auction site using PHP yii framework. The main consideration of the system is to update the database records of all active auctions (max 15 auctions) with the current ticker timer. I am seeking for advice on how i should design the system where every auction item will have a its own countdown timer stored in the database and when someone bids the auction item, the counter resets to 2 min. Every users who are connected to the system should see the same countdown timer for that particular auction. I am little confused on how i should design the system. Will there be a performance issue when there are frequent updates to the database (Mysql) where 15 active auctions are updated every seconds, the countdown timer decreases by a second in the database table for the particular auction. Schema Sample for auction_lots: Auction_id,startdatetime,counter_timer,status I am seeking for advice on how I should design this. Please help. Thank you!

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  • Is it Considered Good SQL practice to use GUID to link multiple tables to same Id field?

    - by Mallow
    I want to link several tables to a many-to-many(m2m) table. One table would be called location and this table would always be on one side of the m2m table. But I will have a list of several tables for example: Cards Photographs Illustrations Vectors Would using GUID's between these tables to link it to a single column in another table be considered 'Good Practice'? Will Mysql let me to have it automatically cascade updates and delete? If so, would multiple cascades lead to an issues? UPDATE I've read that GUID (a hex number) Generally takes up more space in a database and slows queries down. However I could still generate 'unique' ids by just having the table initial's as part of the id so that the table card's id would be c0001, and then Illustrations be I001. Regardless of this change, the questions still stands.

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  • Looking for full web based booking system

    - by Sandro Dzneladze
    I've searched around here but could not find any booking system that would suit my need. I hope maybe you can help me out. I've already seen question #11379 over here. Solutions provided there are not helping and scripts not interesting. I'm looking for a booking system that support infinite number of hotels/rooms/pricingschemes. There should be unlimited number of hotel owner/users, who can access control panel and set availability for their hotel. Or create seasonal prices and adjust them. I should be able to have 15% booking fee paid through credit cart. I can work on integration with my system, it just needs to have correct APi/functionality to support this. I love wordpress so if there are some nice plugins for that, I'm open for suggestions. But this is not a must. It should be php/mysql based as I'm not good at anything else :)

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  • Socialengine installation error

    - by akopacsi
    I'm trying to install Socialengine (clean install, empty database, legal license key), but I ran into this error message at Step 3 of the installation: Step 3: Setup MySQL Database Mysqli statement execute error : Prepared statement needs to be re-prepared I found a troubleshooting artice about "Bug in MySQLi Extension Causes Apache 500 Error" at http://www.socialengine.net/blog/article?id=161&article=Bug-in-MySQLi-Extension-Causes-Apache-500-Error I uploaded the fixed file and try to install again, but it still doesn't work. It terminates at Step 3 again with the same error message. I would be very grateful if you could help me. Thanks.

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  • Returning multiple results from one row [migrated]

    - by krock
    I have a set of MySQL data similar to the following: | id | type | start | end | ============================================= | 1 | event | 2011-11-01 | 2012-01-02 | | 2 | showing | 2012-11-04 | 2012-11-04 | | 3 | conference | 2012-12-01 | 2012-12-04 | | 4 | event | 2012-01-01 | 2012-01-01 | I want to retrieve events within a certain date range, but I also want to return individual results for each row that has a time span of more than one day. What's the best way to achieve this? Using PHP is a possibility, but I wanted to avoid doing this because I will need to to take pagination into account, etc. Any ideas would be greatly appreciated.

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  • How do I add restrictions for users to sign up before they can access web site?

    - by user1867842
    How do I get my webpage not to go back when they hit the back button and are logged out and how can I add a web page to be blocked like FACEBOOK doesn't let you get into their site with out having a page or a account with them, and if you try to put something in the url and try to go to something on their site it gives you a web page that says "you have to be logged in first" . Like I don't want someone going to the url of the "index" page before they have signed up as a member they need to make an account first then they can have access to the "index" page. How do I do this. I have a website so far that has a database and the website has 5 pages so far and two of them which is the login and sign up page which are both used with php and mysql and they work fine. How do I restrict access to the main website by first having the users sign up with me for an account.

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  • What Do I Need To Know About Servers In a Web Development Role?

    - by john
    I know that may sound a little vague, so I'll try and explain a little further... After being self employed developer for many years I'm now in search of a commercial web developer role. My only experience with servers and hosting is uploading through FTP and playing around with CPanel/WHM a little. The role's I'm going for are web development PHP, MySQL, HTML, CSS type roles, but in recent interviews I've been asked questions about setting up things on the server, that I had no idea what was being said... which wasn't ideal! Without knowing more than I do, it's hard to explain what exactly I'm looking to learn, but it's basically just the server elements I should know as a web developer? If you're a web developer, do you have any dealing with the server apart from uploading files, and if so, what? Are things like Subversion(SVN) and version control systems often set up by the web development team, could that be what they were talking about?

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  • How hard it will be for the programmer to learn MS SSRS adn SSIS [closed]

    - by user75380
    I have a programming background in php/python/java for 5 years and I know MySQL and PostgreSQL. Currently in our company the MSQL Business Intelligence person is leaving his job in 4 months. I am thinking of trying to go to his place, at least try as I want to move in Business Intelligence field in SSRS and SSIS. I just want to know that is it possible for me to get my head around those things in 4 months because I have no idea how they work and how hard it will be for me to pick up those things. Can I do that? I just want to know from experienced people if I can move towards that field? At least how should I start? In my area there are shortages of person, so once I know the stuff I can get into junior jobs easily but I want to know from experienced people.

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  • When do I bite the bullet and hire a developer? [closed]

    - by Paul Seattle
    I have an awesome URL, I've had it since the mid 90's, and up until around 2002 I was having an awesome time writing music reviews and features into static pages and adding their URL to static index pages and everything was just great. Then things got complicated really fast, and for one reason or another I handed the site over to a very talented friend who turned it into a db based site run by cf. Now, here I am around twelve years later putting it all back together using mysql, php and css on a need-to-learn basis and even though I'm sooo close to where I want it to be I realize, erm, it should have been written using mysqli etc etc ad infinitum. So I'm wondering at what point do I just give in and hire a developer to take over, how much does it even cost, and how do I know I'm working with someone who is better than I am?

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  • Not Found Apadche2

    - by user285814
    i have installed apache2, actual php version, mysql server and vsftp on my new ubuntu server. I also installed wordpress and gave the user www-data all rights for /var/www/* and put it to 755. I hooked the Domain to the server with * and @ a-record. Now, everytime when i open a Page, it says 404 file not found on server. i dont know how to fix this. can you help me? Edit: I think its because mod_rewrite. i installed mod_rewrite with: sudo a2enmod rewrite sudo service apache2 restart but it still doesnt work.

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  • Using replacement to get possible outcomes to then search through HUGE amount of data

    - by Samuel Cambridge
    I have a database table holding 40 million records (table A). Each record has a string a user can search for. I also have a table with a list of character replacements (table B) i.e. i = Y, I = 1 etc. I need to be able to take the string a user is searching for, iterate through each letter and create an array of every possible outcome (the users string, then each outcome with alternative letters used). I need to check for alternatives on both lower and uppercase letters in the word A search string can be no longer than 10 characters long. I'm using PHP and a MySQL database. Does anyone have any thoughts / articles / guidance on doing this in an efficient way?

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  • Site loads Extremely slowly over HTTPS; loads perfectly over HTTP - Sudden and new issue

    - by guest234239048
    My business' website suddenly started loading extremely slowly over HTTPS last night and continues through today. The facts: Page loadtime via HTTPS - 2 minutes +, HTTP - 3 seconds max. NO updates were done on any site files in the past 2 weeks. This is on Shared Hosting HTTPS has worked perfectly over the past 9 months then suddenly failed yesterday. Hosting company and SSL issuer say there are no problems on their end. - Searches for others having similar issues return no results, it appears to be just me... Site is primarily run via php/mysql Currently attempted troubleshooting: Tried all major browsers and different versions - same result. Tried 2 separate ISPs - same result. Tried proxies - same result. Tried 3 separate computers - same result. I'm basically at a total loss here. Does anyone know what could cause such a thing to happen? Please help guide troubleshooting.

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  • Can you notice what's wrong with my PHP or MYSQL code?

    - by Jenna
    I am trying to create a category menu with sub categories. I have the following MySQL table: -- -- Table structure for table `categories` -- CREATE TABLE IF NOT EXISTS `categories` ( `ID` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(1000) NOT NULL, `slug` varchar(1000) NOT NULL, `parent` int(11) NOT NULL, `type` varchar(255) NOT NULL, PRIMARY KEY (`ID`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=66 ; -- -- Dumping data for table `categories` -- INSERT INTO `categories` (`ID`, `name`, `slug`, `parent`, `type`) VALUES (63, 'Party', '/category/party/', 0, ''), (62, 'Kitchen', '/category/kitchen/', 61, 'sub'), (59, 'Animals', '/category/animals/', 0, ''), (64, 'Pets', '/category/pets/', 59, 'sub'), (61, 'Rooms', '/category/rooms/', 0, ''), (65, 'Zoo Creatures', '/category/zoo-creatures/', 59, 'sub'); And the following PHP: <?php include("connect.php"); echo "<ul>"; $query = mysql_query("SELECT * FROM categories"); while ($row = mysql_fetch_assoc($query)) { $catId = $row['id']; $catName = $row['name']; $catSlug = $row['slug']; $parent = $row['parent']; $type = $row['type']; if ($type == "sub") { $select = mysql_query("SELECT name FROM categories WHERE ID = $parent"); while ($row = mysql_fetch_assoc($select)) { $parentName = $row['name']; } echo "<li>$parentName >> $catName</li>"; } else if ($type == "") { echo "<li>$catName</li>"; } } echo "</ul>"; ?> Now Here's the Problem, It displays this: * Party * Rooms >> Kitchen * Animals * Animals >> Pets * Rooms * Animals >> Zoo Creatures I want it to display this: * Party * Rooms >> Kitchen * Animals >> Pets >> Zoo Creatures Is there something wrong with my loop? I just can't figure it out.

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  • Mysql return value as 0 in the fetch result.

    - by Karthik
    I have this two tables, -- -- Table structure for table `t1` -- CREATE TABLE `t1` ( `pid` varchar(20) collate latin1_general_ci NOT NULL, `pname` varchar(20) collate latin1_general_ci NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1 COLLATE=latin1_general_ci; -- -- Dumping data for table `t1` -- INSERT INTO `t1` VALUES ('p1', 'pro1'); INSERT INTO `t1` VALUES ('p2', 'pro2'); -- -------------------------------------------------------- -- -- Table structure for table `t2` -- CREATE TABLE `t2` ( `pid` varchar(20) collate latin1_general_ci NOT NULL, `year` int(6) NOT NULL, `price` int(3) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1 COLLATE=latin1_general_ci; -- -- Dumping data for table `t2` -- INSERT INTO `t2` VALUES ('p1', 2009, 50); INSERT INTO `t2` VALUES ('p1', 2010, 60); INSERT INTO `t2` VALUES ('p3', 2007, 200); INSERT INTO `t2` VALUES ('p4', 2008, 501); my query is, SELECT * FROM `t1` LEFT JOIN `t2` ON t1.pid = t2.pid Getting the result, pid pname pid year price p1 pro1 p1 2009 50 p1 pro1 p1 2010 60 p2 pro2 NULL NULL NULL My question is, i want to get the price value is 0 instead of NULL. How can i write the query to getting the price value is 0. Thanks in advance for help.

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  • How do you convert a parent-child (adjacency) table to a nested set using PHP and MySQL?

    - by mrbinky3000
    I've spent the last few hours trying to find the solution to this question online. I've found plenty of examples on how to convert from nested set to adjacency... but few that go the other way around. The examples I have found either don't work or use MySQL procedures. Unfortunately, I can't use procedures for this project. I need a pure PHP solution. I have a table that uses the adjacency model below: id parent_id category 1 0 ROOT_NODE 2 1 Books 3 1 CD's 4 1 Magazines 5 2 Books/Hardcover 6 2 Books/Large Format 7 4 Magazines/Vintage And I would like to convert it to a Nested Set table below: id left right category 1 1 14 Root Node 2 2 7 Books 3 3 4 Books/Hardcover 4 5 6 Books/Large Format 5 8 9 CD's 6 10 13 Magazines 7 11 12 Magazines/Vintage Here is an image of what I need: I have a function, based on the pseudo code from this forum post (http://www.sitepoint.com/forums/showthread.php?t=320444) but it doesn't work. I get multiple rows that have the same value for left. This should not happen. <?php /** -- -- Table structure for table `adjacent_table` -- CREATE TABLE IF NOT EXISTS `adjacent_table` ( `id` int(11) NOT NULL AUTO_INCREMENT, `father_id` int(11) DEFAULT NULL, `category` varchar(128) DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=8 ; -- -- Dumping data for table `adjacent_table` -- INSERT INTO `adjacent_table` (`id`, `father_id`, `category`) VALUES (1, 0, 'ROOT'), (2, 1, 'Books'), (3, 1, 'CD''s'), (4, 1, 'Magazines'), (5, 2, 'Hard Cover'), (6, 2, 'Large Format'), (7, 4, 'Vintage'); -- -- Table structure for table `nested_table` -- CREATE TABLE IF NOT EXISTS `nested_table` ( `id` int(11) NOT NULL AUTO_INCREMENT, `lft` int(11) DEFAULT NULL, `rgt` int(11) DEFAULT NULL, `category` varchar(128) DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ; */ mysql_connect('localhost','USER','PASSWORD') or die(mysql_error()); mysql_select_db('DATABASE') or die(mysql_error()); adjacent_to_nested(0); /** * adjacent_to_nested * * Reads a "adjacent model" table and converts it to a "Nested Set" table. * @param integer $i_id Should be the id of the "root node" in the adjacent table; * @param integer $i_left Should only be used on recursive calls. Holds the current value for lft */ function adjacent_to_nested($i_id, $i_left = 0) { // the right value of this node is the left value + 1 $i_right = $i_left + 1; // get all children of this node $a_children = get_source_children($i_id); foreach ($a_children as $a) { // recursive execution of this function for each child of this node // $i_right is the current right value, which is incremented by the // import_from_dc_link_category method $i_right = adjacent_to_nested($a['id'], $i_right); // insert stuff into the our new "Nested Sets" table $s_query = " INSERT INTO `nested_table` (`id`, `lft`, `rgt`, `category`) VALUES( NULL, '".$i_left."', '".$i_right."', '".mysql_real_escape_string($a['category'])."' ) "; if (!mysql_query($s_query)) { echo "<pre>$s_query</pre>\n"; throw new Exception(mysql_error()); } echo "<p>$s_query</p>\n"; // get the newly created row id $i_new_nested_id = mysql_insert_id(); } return $i_right + 1; } /** * get_source_children * * Examines the "adjacent" table and finds all the immediate children of a node * @param integer $i_id The unique id for a node in the adjacent_table table * @return array Returns an array of results or an empty array if no results. */ function get_source_children($i_id) { $a_return = array(); $s_query = "SELECT * FROM `adjacent_table` WHERE `father_id` = '".$i_id."'"; if (!$i_result = mysql_query($s_query)) { echo "<pre>$s_query</pre>\n"; throw new Exception(mysql_error()); } if (mysql_num_rows($i_result) > 0) { while($a = mysql_fetch_assoc($i_result)) { $a_return[] = $a; } } return $a_return; } ?> This is the output of the above script. INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '2', '5', 'Hard Cover' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '2', '7', 'Large Format' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '1', '8', 'Books' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '1', '10', 'CD\'s' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '10', '13', 'Vintage' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '1', '14', 'Magazines' ) INSERT INTO nested_table (id, lft, rgt, category) VALUES( NULL, '0', '15', 'ROOT' ) As you can see, there are multiple rows sharing the lft value of "1" same goes for "2" In a nested-set, the values for left and right must be unique. Here is an example of how to manually number the left and right ID's in a nested set: UPDATE - PROBLEM SOLVED First off, I had mistakenly believed that the source table (the one in adjacent-lists format) needed to be altered to include a source node. This is not the case. Secondly, I found a cached page on BING (of all places) with a class that does the trick. I've altered it for PHP5 and converted the original author's mysql related bits to basic PHP. He was using some DB class. You can convert them to your own database abstraction class later if you want. Obviously, if your "source table" has other columns that you want to move to the nested set table, you will have to adjust the write method in the class below. Hopefully this will save someone else from the same problems in the future. <?php /** -- -- Table structure for table `adjacent_table` -- DROP TABLE IF EXISTS `adjacent_table`; CREATE TABLE IF NOT EXISTS `adjacent_table` ( `id` int(11) NOT NULL AUTO_INCREMENT, `father_id` int(11) DEFAULT NULL, `category` varchar(128) DEFAULT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=8 ; -- -- Dumping data for table `adjacent_table` -- INSERT INTO `adjacent_table` (`id`, `father_id`, `category`) VALUES (1, 0, 'Books'), (2, 0, 'CD''s'), (3, 0, 'Magazines'), (4, 1, 'Hard Cover'), (5, 1, 'Large Format'), (6, 3, 'Vintage'); -- -- Table structure for table `nested_table` -- DROP TABLE IF EXISTS `nested_table`; CREATE TABLE IF NOT EXISTS `nested_table` ( `lft` int(11) NOT NULL DEFAULT '0', `rgt` int(11) DEFAULT NULL, `id` int(11) DEFAULT NULL, `category` varchar(128) DEFAULT NULL, PRIMARY KEY (`lft`), UNIQUE KEY `id` (`id`), UNIQUE KEY `rgt` (`rgt`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1; */ /** * @class tree_transformer * @author Paul Houle, Matthew Toledo * @created 2008-11-04 * @url http://gen5.info/q/2008/11/04/nested-sets-php-verb-objects-and-noun-objects/ */ class tree_transformer { private $i_count; private $a_link; public function __construct($a_link) { if(!is_array($a_link)) throw new Exception("First parameter should be an array. Instead, it was type '".gettype($a_link)."'"); $this->i_count = 1; $this->a_link= $a_link; } public function traverse($i_id) { $i_lft = $this->i_count; $this->i_count++; $a_kid = $this->get_children($i_id); if ($a_kid) { foreach($a_kid as $a_child) { $this->traverse($a_child); } } $i_rgt=$this->i_count; $this->i_count++; $this->write($i_lft,$i_rgt,$i_id); } private function get_children($i_id) { return $this->a_link[$i_id]; } private function write($i_lft,$i_rgt,$i_id) { // fetch the source column $s_query = "SELECT * FROM `adjacent_table` WHERE `id` = '".$i_id."'"; if (!$i_result = mysql_query($s_query)) { echo "<pre>$s_query</pre>\n"; throw new Exception(mysql_error()); } $a_source = array(); if (mysql_num_rows($i_result)) { $a_source = mysql_fetch_assoc($i_result); } // root node? label it unless already labeled in source table if (1 == $i_lft && empty($a_source['category'])) { $a_source['category'] = 'ROOT'; } // insert into the new nested tree table // use mysql_real_escape_string because one value "CD's" has a single ' $s_query = " INSERT INTO `nested_table` (`id`,`lft`,`rgt`,`category`) VALUES ( '".$i_id."', '".$i_lft."', '".$i_rgt."', '".mysql_real_escape_string($a_source['category'])."' ) "; if (!$i_result = mysql_query($s_query)) { echo "<pre>$s_query</pre>\n"; throw new Exception(mysql_error()); } else { // success: provide feedback echo "<p>$s_query</p>\n"; } } } mysql_connect('localhost','USER','PASSWORD') or die(mysql_error()); mysql_select_db('DATABASE') or die(mysql_error()); // build a complete copy of the adjacency table in ram $s_query = "SELECT `id`,`father_id` FROM `adjacent_table`"; $i_result = mysql_query($s_query); $a_rows = array(); while ($a_rows[] = mysql_fetch_assoc($i_result)); $a_link = array(); foreach($a_rows as $a_row) { $i_father_id = $a_row['father_id']; $i_child_id = $a_row['id']; if (!array_key_exists($i_father_id,$a_link)) { $a_link[$i_father_id]=array(); } $a_link[$i_father_id][]=$i_child_id; } $o_tree_transformer = new tree_transformer($a_link); $o_tree_transformer->traverse(0); ?>

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  • MySQL PHP | "SELECT FROM table" using "alphanumeric"-UUID. Speed vs. Indexed Integer / Indexed Char

    - by dropson
    At the moment, I select rows from 'table01' using: SELECT * FROM table01 WHERE UUID = 'whatever'; The UUID column is a unique index. I know this isn't the fastest way to select data from the database, but the UUID is the only row-identifier that is available to the front-end. Since I have to select by UUID, and not ID, I need to know what of these two options I should go for, if say the table consists of 100'000 rows. What speed differences would I look at, and would the index for the UUID grow to large, and lag the DB? Get the ID before doing the "big" select 1. $id = "SELECT ID FROM table01 WHERE UUID = '{alphanumeric character}'"; 2. $rows = SELECT * FROM table01 WHERE ID = $id; Or keep it the way it is now, using the UUID. 1. SELECT FROM table01 WHERE UUID '{alphanumeric character}'; Side note: All new rows are created by checking if the system generated uniqueid exists before trying to insert a new row. Keeping the column always unique. The "example" table. CREATE TABLE Table01 ( ID int NOT NULL PRIMARY KEY, UUID char(15), name varchar(100), url varchar(255), `date` datetime ) ENGINE = InnoDB; CREATE UNIQUE INDEX UUID ON Table01 (UUID);

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  • Mysql - Help me alter this query to apply AND logic instead of OR in searching?

    - by sandeepan-nath
    First execute these tables and data dumps :- CREATE TABLE IF NOT EXISTS `Tags` ( `id_tag` int(10) unsigned NOT NULL auto_increment, `tag` varchar(255) default NULL, PRIMARY KEY (`id_tag`), UNIQUE KEY `tag` (`tag`), KEY `id_tag` (`id_tag`), KEY `tag_2` (`tag`), KEY `tag_3` (`tag`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=18 ; INSERT INTO `Tags` (`id_tag`, `tag`) VALUES (1, 'key1'), (2, 'key2'); CREATE TABLE IF NOT EXISTS `Tutors_Tag_Relations` ( `id_tag` int(10) unsigned NOT NULL default '0', `id_tutor` int(10) default NULL, KEY `Tutors_Tag_Relations` (`id_tag`), KEY `id_tutor` (`id_tutor`), KEY `id_tag` (`id_tag`) ) ENGINE=InnoDB DEFAULT CHARSET=latin1; INSERT INTO `Tutors_Tag_Relations` (`id_tag`, `id_tutor`) VALUES (1, 1), (2, 1); The following query finds all the tutors from Tutors_Tag_Relations table which have reference to at least one of the terms "key1" or "key2". SELECT td . * FROM Tutors_Tag_Relations AS td INNER JOIN Tags AS t ON t.id_tag = td.id_tag WHERE t.tag LIKE "%key1%" OR t.tag LIKE "%key2%" Group by td.id_tutor LIMIT 10 Please help me modify this query so that it returns all the tutors from Tutors_Tag_Relations table which have reference to both the terms "key1" and "key2" (AND logic instead of OR logic). Please suggest an optimized query considering huge number of data records (the query should NOT individually fetch two sets of tutors matching each keyword and then find the intersection).

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  • Mysql Query is not working in edited jTable code, why?

    - by Furkan Kadioglu
    I'm using this example: www.jtable.org I've downloaded the jTable PHP version. I then edited the script. The jTable simple version is working, but my edited version isn't. I can create a list, but I can't add a row; this code is causing problems. However, PHP doesn't display any error messages. else if($_GET["action"] == "create") { //Insert record into database $result = mysql_query("INSERT INTO veriler(bolge, sehir, firma, adres, tel, web) VALUES('" . $_POST["bolge"] . "', '" . $_POST["sehir"] . "', '" . $_POST["firma"] . "', '" . $_POST["adres"] . "', '" . $_POST["tel"] . "', '" . $_POST["web"] . "'"); //Get last inserted record (to return to jTable) $result = mysql_query("SELECT * FROM veriler WHERE id = LAST_INSERT_ID();"); $row = mysql_fetch_array($result); //Return result to jTable $jTableResult = array(); $jTableResult['Result'] = "OK"; $jTableResult['Record'] = $row; print json_encode($jTableResult); } What is the problem?

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