Search Results

Search found 13006 results on 521 pages for 'exception'.

Page 233/521 | < Previous Page | 229 230 231 232 233 234 235 236 237 238 239 240  | Next Page >

  • Java Code Error Help..please

    - by Brian
    I am getting the following error and do not know how to fix it....any help would be great...Thanks Exception in thread "main" java.lang.NullPointerException at Polynomial.add(Polynomial.java:115) at PolyTest.main(PolyTest.java:18)

    Read the article

  • access list element from thread

    - by phm
    Hello I have a "List" in the main application and I am trying to access its elements from within a thread. I am getting this exception: {"The calling thread cannot access this object because a different thread owns it."} System.SystemException {System.InvalidOperationException} Thanks

    Read the article

  • In Java What is the guaranteed way to get a FileLock from FileChannel while accessing a RandomAcces

    - by narasimha.bhat
    I am trying to use FileLock lock(long position, long size,boolean shared) in FileChannel object As per the javadoc it can throw OverlappingFileLockException. When I create a test program with 2 threads lock method seems to be waiting to acquire the lock (both exclusive and non exclusive) But when the number threads increases in the acutal scenario over lapping file lock exception is thrown and processing slows down due the block at File lock table. What is the best way to acquire lock avoiding the OverlappingFileLockException ?

    Read the article

  • How to get the result for return statement from JSON parsing?

    - by blankon91
    I've follow the code for parsing the value with JSON from here, but I get the problem in my return statement. I want to put the parsing result into my return statement. How to do that? Here is my code: public String MASUK(String user, String password) { SoapObject request = new SoapObject(WSDL_TARGET_NAMESPACE,OPERATION_NAME); PropertyInfo pi = new PropertyInfo(); pi.setName("ccduser"); pi.setValue(user); pi.setType(String.class); request.addProperty(pi); PropertyInfo pi2 = new PropertyInfo(); pi2.setName("password"); pi2.setValue(password); pi2.setType(String.class); request.addProperty(pi2); SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11); envelope.dotNet = true; envelope.setOutputSoapObject(request); HttpTransportSE httpTransport = new HttpTransportSE(SOAP_ADDRESS); try { httpTransport.call(SOAP_ACTION, envelope); SoapObject resultSOAP = (SoapObject) envelope.bodyIn; /* gets our result in JSON String */ String ResultObject = resultSOAP.getProperty(0).toString(); resultSOAP = (SoapObject) envelope.bodyIn; ResultObject = resultSOAP.getProperty(0).toString(); if (ResultObject.startsWith("{")) { // if JSON string is an object JSONObj = new JSONObject(ResultObject); Iterator<String> itr = JSONObj.keys(); while (itr.hasNext()) { String Key = (String) itr.next(); String Value = JSONObj.getString(Key); BundleResult.putString(Key, Value); // System.out.println(bundleResult.getString(Key)); } } else if (ResultObject.startsWith("[")) { // if JSON string is an array JSONArr = new JSONArray(ResultObject); System.out.println("length" + JSONArr.length()); for (int i = 0; i < JSONArr.length(); i++) { JSONObj = (JSONObject) JSONArr.get(i); BundleResult.putString(String.valueOf(i), JSONObj.toString()); // System.out.println(bundleResult.getString(i)); } } } catch (Exception exception) { } return null; }

    Read the article

  • Cannot run public class in one .java from another

    - by DIOS
    I have created a basic program that takes whatever is input into two textfields and exports them to a file. I would now like to encrypt that file, and alredy have the encryptor. The problem is that I cannot call it. Here is my code for the encryptor: import java.io.File; import java.io.FileInputStream; import java.io.FileOutputStream; import java.io.*; import javax.crypto.Cipher; import javax.crypto.CipherInputStream; import javax.crypto.CipherOutputStream; import javax.crypto.spec.SecretKeySpec; public class FileEncryptor { private String algo; private File file; public FileEncryptor(String algo,String path) { this.algo=algo; //setting algo this.file=new File(path); //settong file } public void encrypt() throws Exception{ //opening streams FileInputStream fis =new FileInputStream(file); file=new File(file.getAbsolutePath()); FileOutputStream fos =new FileOutputStream(file); //generating key byte k[] = "HignDlPs".getBytes(); SecretKeySpec key = new SecretKeySpec(k,algo.split("/")[0]); //creating and initialising cipher and cipher streams Cipher encrypt = Cipher.getInstance(algo); encrypt.init(Cipher.ENCRYPT_MODE, key); CipherOutputStream cout=new CipherOutputStream(fos, encrypt); byte[] buf = new byte[1024]; int read; while((read=fis.read(buf))!=-1) //reading data cout.write(buf,0,read); //writing encrypted data //closing streams fis.close(); cout.flush(); cout.close(); } public static void main (String[] args)throws Exception { new FileEncryptor("DES/ECB/PKCS5Padding","C:\\Users\\*******\\Desktop\\newtext").encrypt();//encrypts the current file. } } Here is the section of my file creator that is failing to call this: FileWriter fWriter = null; BufferedWriter writer = null; try{ fWriter = new FileWriter("C:\\Users\\*******\\Desktop\\newtext"); writer = new BufferedWriter(fWriter); writer.write(Data); writer.close(); f.dispose(); FileEncryptor encr = new FileEncryptor(); //problem lies here. encr.encrypt //public void that does the encryption. new complete(); //different .java that is working fine.

    Read the article

  • asp.net cannot update database

    - by tom
    string ConnectionString = WebConfigurationManager.ConnectionStrings["dbnameConnectionString"].ConnectionString; SqlConnection myConnection = new SqlConnection(ConnectionString); myConnection.Open(); try { string qry = "UPDATE customers SET firstname=@firstname WHERE cid=1"; SqlCommand insertQuery = new SqlCommand(qry, myConnection); insertQuery.Parameters.Add(new SqlParameter("@firstname", txtFirstname.Text)); insertQuery.ExecuteNonQuery(); myConnection.Close(); } catch (Exception ee) { } Any suggestions?

    Read the article

  • Single console in eclipse for both Server and Client

    - by rits
    I am building a client server application using Java Sockets (in Windows XP). For that I need different consoles for both Client and Server(for Input and Output operations). But in eclipse both share a single console. Is there any plugin or some sort of cheat through which I can do this. After googling I got this, http://dev.eclipse.org/newslists/news.eclipse.newcomer/msg17138.html But, this seems to be only for write operations, not read operations. Also, I tried the following to launch application manually, but even this is not working........ package mypack; import java.io.BufferedOutputStream; import java.io.File; import java.io.FileOutputStream; import java.io.IOException; import java.io.OutputStream; import java.io.PrintStream; public class MySystem { public static void changeStream(String mainFile) throws IOException{ File temp = new File(".") ; String parentPath = temp.getCanonicalPath() ; System.out.println(parentPath); //creation of batch file starts here try{ File f = new File(parentPath + "\\a.bat") ; System.out.println("Created : " + f.createNewFile()); //f.deleteOnExit() ; FileOutputStream fos = new FileOutputStream(f) ; String str = "java " + mainFile ; String batchCommand="@echo off\n"+str+"\npause\nexit"; char arr[] = batchCommand.toCharArray() ; System.out.println(str) ; for(int i = 0 ; i < arr.length ; i++){ fos.write(arr[i]) ; } fos.close() ; } catch(Exception e){ } //creation of batch file ends here //execution of batch file starts here try{ Runtime r = Runtime.getRuntime() ; System.out.println(parentPath + "\\a.bat") ; Process p = r.exec(new String[]{"cmd","/k","start a.bat"},null,new File(parentPath)) ; OutputStream os = (OutputStream)p.getOutputStream() ; System.setOut( new PrintStream(os) ) ; System.out.println("Hello"); } catch(Exception e){ e.printStackTrace(); } //execution of batch file ends here } public static void main(String[] args) throws IOException { MySystem.changeStream("MySystem") ; } }

    Read the article

  • NullPointerException using datanucleus-json with S3

    - by Matt
    I'm using datanucleus 3.2.7 from Maven, trying to use the Amazon S3 JPA provider. I can successfully write data into S3, but querying either by using "SELECT u FROM User u" or "SELECT u FROM User u WHERE id = :id" causes a NullPointerException to be thrown. Using the RDBMS provider, everything works perfectly. Is there something I'm doing wrong? Main.java EntityManagerFactory factory = Persistence.createEntityManagerFactory("MyUnit"); EntityManager entityManager = factory.createEntityManager(); Query query = entityManager.createQuery("SELECT u FROM User u", User.class); List<User> users = query.getResultList(); // Null pointer exception here for(User u:users) System.out.println(u); User.java package test; import javax.persistence.*; @Entity @Table(name = "User") public class User { @Id public String id; public String name; public User(String id, String name) { this.id = id; this.name = name; } public String toString() { return id+" : "+name; } } persistence.xml <?xml version="1.0" encoding="UTF-8" ?> <persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd" version="1.0"> <persistence-unit name="MyUnit"> <class>test.User</class> <exclude-unlisted-classes /> <properties> <properties> <property name="datanucleus.ConnectionURL" value="amazons3:http://s3.amazonaws.com/" /> <property name="datanucleus.ConnectionUserName" value="xxxxx" /> <property name="datanucleus.ConnectionPassword" value="xxxxx" /> <property name="datanucleus.cloud.storage.bucket" value="my-bucket" /> </properties> <property name="datanucleus.autoCreateSchema" value="true" /> </properties> </persistence-unit> </persistence> Exception java.lang.NullPointerException at org.datanucleus.NucleusContext.isClassWithIdentityCacheable(NucleusContext.java:1840) at org.datanucleus.ExecutionContextImpl.getObjectFromLevel2Cache(ExecutionContextImpl.java:5287) at org.datanucleus.ExecutionContextImpl.getObjectFromCache(ExecutionContextImpl.java:5191) at org.datanucleus.ExecutionContextImpl.findObject(ExecutionContextImpl.java:3137) at org.datanucleus.store.json.CloudStoragePersistenceHandler.getObjectsOfCandidateType(CloudStoragePersistenceHandler.java:367) at org.datanucleus.store.json.query.JPQLQuery.performExecute(JPQLQuery.java:94) at org.datanucleus.store.query.Query.executeQuery(Query.java:1786) at org.datanucleus.store.query.Query.executeWithMap(Query.java:1690) at org.datanucleus.api.jpa.JPAQuery.getResultList(JPAQuery.java:194) at test.Main.main(Main.java:16)

    Read the article

  • Zend_Search_Lucene and range search

    - by ranza
    I have a bunch of int key fields in my index and trying to do a simple range search like this: `gender:1 AND height:[120 TO 180]` This should give me male in the height range 120 to 180. But for some reason i get this exception: `At least one range query boundary term must be non-empty term` How would i debug this? Is it just Zend_Search_Lucene being buggy?

    Read the article

  • check if a sheet exists in excel

    - by ps
    How do i check if a sheet exists in a excel using interop. I tried the following but it throws an COMException if not there.. Is there a better way of finding out than actually looking at the exception Worksheet sheet = null; Sheets worksheets = some; sheet = (Worksheet)worksheets.get_Item("sheetName"); if(sheet!=null) { //do something }

    Read the article

  • ASP.NET The underlying connection was closed: Could not establish trust relat

    - by David Lively
    When attempting to use HttpWebRequest to retrieve a page from my dev server, I get a web exception: The underlying connection was closed: Could not establish trust relationship for the SSL/TLS secure channel." The remote certificate is invalid according to the validation procedure... The url I'm attempting to read from is a plain-old http://myserver.com/mypage.asp - no SSL. The production server has a valid certificate so this shouldn't be an issue, but our dev server doesn't. Help!

    Read the article

  • Android Facebook SDK : post message without showing facebook page

    - by someone_ smiley
    I am trying to integrate Facebook to my Android app for social post. I have downloaded latest Facebook sdk from here and apply all setup require to post to facebook. Now i can post to facebook. But problem is that, when i run sample program from facebook sdk, a browser like page is open and user have to enter message himself there. but i dont want this page to showed up. i want a fixed message to post directly without opening facebook dialog box. But if there is noway to avoid this, please tell me how can i fixed certain part of message so that user can't modified it. Thanks in Advance Edit: this is message i got after using this project 04-10 11:44:34.691: I/dalvikvm(719): Failed resolving Lnet/xeomax/TestRocket/TestRocket; interface 22 'Lnet/xeomax/FBRocket/LoginListener;' 04-10 11:44:34.691: W/dalvikvm(719): Link of class 'Lnet/xeomax/TestRocket/TestRocket;' failed 04-10 11:44:34.691: D/AndroidRuntime(719): Shutting down VM 04-10 11:44:34.701: W/dalvikvm(719): threadid=1: thread exiting with uncaught exception (group=0x40015560) 04-10 11:44:34.781: E/AndroidRuntime(719): FATAL EXCEPTION: main 04-10 11:44:34.781: E/AndroidRuntime(719): java.lang.RuntimeException: Unable to instantiate activity ComponentInfo{net.xeomax.TestRocket/net.xeomax.TestRocket.TestRocket}: java.lang.ClassNotFoundException: net.xeomax.TestRocket.TestRocket in loader dalvik.system.PathClassLoader[/data/app/net.xeomax.TestRocket-1.apk] 04-10 11:44:34.781: E/AndroidRuntime(719): at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:1569) 04-10 11:44:34.781: E/AndroidRuntime(719): at android.app.ActivityThread.handleLaunchActivity(ActivityThread.java:1663) 04-10 11:44:34.781: E/AndroidRuntime(719): at android.app.ActivityThread.access$1500(ActivityThread.java:117) 04-10 11:44:34.781: E/AndroidRuntime(719): at android.app.ActivityThread$H.handleMessage(ActivityThread.java:931) 04-10 11:44:34.781: E/AndroidRuntime(719): at android.os.Handler.dispatchMessage(Handler.java:99) 04-10 11:44:34.781: E/AndroidRuntime(719): at android.os.Looper.loop(Looper.java:130) 04-10 11:44:34.781: E/AndroidRuntime(719): at android.app.ActivityThread.main(ActivityThread.java:3683) 04-10 11:44:34.781: E/AndroidRuntime(719): at java.lang.reflect.Method.invokeNative(Native Method) 04-10 11:44:34.781: E/AndroidRuntime(719): at java.lang.reflect.Method.invoke(Method.java:507) 04-10 11:44:34.781: E/AndroidRuntime(719): at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:839) 04-10 11:44:34.781: E/AndroidRuntime(719): at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:597) 04-10 11:44:34.781: E/AndroidRuntime(719): at dalvik.system.NativeStart.main(Native Method) 04-10 11:44:34.781: E/AndroidRuntime(719): Caused by: java.lang.ClassNotFoundException: net.xeomax.TestRocket.TestRocket in loader dalvik.system.PathClassLoader[/data/app/net.xeomax.TestRocket-1.apk] 04-10 11:44:34.781: E/AndroidRuntime(719): at dalvik.system.PathClassLoader.findClass(PathClassLoader.java:240) 04-10 11:44:34.781: E/AndroidRuntime(719): at java.lang.ClassLoader.loadClass(ClassLoader.java:551) 04-10 11:44:34.781: E/AndroidRuntime(719): at java.lang.ClassLoader.loadClass(ClassLoader.java:511) 04-10 11:44:34.781: E/AndroidRuntime(719): at android.app.Instrumentation.newActivity(Instrumentation.java:1021) 04-10 11:44:34.781: E/AndroidRuntime(719): at android.app.ActivityThread.performLaunchActivity(ActivityThread.java:1561) 04-10 11:44:34.781: E/AndroidRuntime(719): ... 11 more

    Read the article

  • A Question about using jython when run a receving socket in python

    - by abusemind
    Hi, I have not a lot of knowledge of python and network programming. Currently I am trying to implement a simple application which can receive a text message sent by the user, fetch some information from the google search api, and return the results via text message to the user. This application will continue to listening to the users messages and reply immediately. How I get the text short message sent by the user? It's a program named fetion from the mobile supplier in China. The client side fetion, just like a instant communication tool, can send/receive messages to/from other people who are using mobile to receive/send SMS. I am using a open source python program that simulates the fetion program. So basically I can use this python program to communate with others who using cell phone via SMS. My core program is based on java, so I need to take this python program into java environment. I am using jython, and now I am available to send messages to users by some lines of java codes. But the real question is the process of receving from users via SMS. In python code, a new thread is created to continuously listen to the user. It should be OK in Python, but when I run the similar process in Jython, the following exception occurs: Exception in thread Thread:Traceback (most recent call last): File "D:\jython2.5.1\Lib\threading.py", line 178, in _Thread__bootstrap self.run() File "<iostream>", line 1389, in run File "<iostream>", line 1207, in receive File "<iostream>", line 1207, in receive File "<iostream>", line 150, in recv File "D:\jython2.5.1\Lib\select.py", line 223, in native_select pobj.register(fd, POLLIN) File "D:\jython2.5.1\Lib\select.py", line 104, in register raise _map_exception(jlx) error: (20000, 'socket must be in non-blocking mode') The line 150 in the python code is as follows: def recv(self,timeout=False): if self.login_type == "HTTP": time.sleep(10) return self.get_offline_msg() pass else: if timeout: infd,outfd,errfd = select([self.__sock,],[],[],timeout)//<---line 150 here else: infd,outfd,errfd = select([self.__sock,],[],[]) if len(infd) != 0: ret = self.__tcp_recv() num = len(ret) d_print(('num',),locals()) if num == 0: return ret if num == 1: return ret[0] for r in ret: self.queue.put(r) d_print(('r',),locals()) if not self.queue.empty(): return self.queue.get() else: return "TimeOut" Because of I am not very familiar with python, especially the socket part, and also new in Jython use, I really need your help or only advice or explanation. Thank you very much!

    Read the article

  • android 2.2 google map error

    - by shenbryant
    I used google.map api to develop a project which works well on android 2.1. But when I run the same project on android 2.2, it encountered some errors. The shown errors are " -- AndroidRuntime FATAL EXCEPTION:main -- AndroidRuntime java.lang.NoClassDefFoundError:android.net.NetworkConnectivityListener -- AndroidRuntime at com.google.android.maps.MapActivity.onCreate(MapActivity.java:199) " I don't know where is the problem? Can anyone help me? I will apreciate it very much!

    Read the article

  • Silverlight WCF connection blocking

    - by Rafal
    Hi I have a problem calling WCF Service Method by Silverlight App. I keep getting Error in Fidler: [Fiddler] Connection to localhost failed. Exception Text: Can not connect because the target machine actively refused it: 1:50045 I use Win 7, port 50045 is unlocked. My App.config and ServiceReferences.ClientConfig are OK... Please HELP:)

    Read the article

  • Visual Studio soft-crashing when encountering XAML Errors in initialize.

    - by Aren
    I've been having some serious issues with Visual Studio 2010 as of late. It's been crashing in a peculiar way when I encounter certain types of XAML errors during the InitializeComponent() of a control/window. The program breaks and visual studio gears up like it's catching an exception (because it is) and then stops midway displaying a broken highlight in my XAML file with no details as to what is wrong. Example: There is not pop outs, or details Anywhere about what is wrong, only a callstack that points to my InitializeComponent() call. Now normally I'd just do some trial and error to fix this problem, and find out where i messed up, but the real problem isn't my code. Visual Studio is rendered completely useless at this point. It reports my application still in "Running" mode. The Stop/Break/Restart buttons on the toolbar or in the menus don't do anything (but grey out). Closing the application does not stop this behaviour, closing visual studio gets it stuck in a massive loop where it yells at me complaining every file open is not in the debug project, then repeats this process when i have exausted every open file. I have to force-close devenv.exe, and after this happening 3-4 times in a row it's a lot of wasted time (as my projects are usually pretty big and studio can be quite slow @ loading). To the point Has anyone else experienced this? How can I stop studio from locking up. Can I at LEAST get information out of this beast another way so i can fix my XAML error sooner rather than after 3-4 trial-and-error compiles yielding the same crash? Any & All help would be appreciated. Visual Studio 2010 version: 10.0.30319.1RTM Edit & Update FWIW, mostly the errors that cause this are XamlParseExceptions (I figured this out after i found what was wrong with my XAML). I think I need to be clearer though, Im not looking for the solution to my code problem, as these are usually typos / small things, I'm looking for a solution to VStudio getting all buggered up as a result. The particular error in the above image that 100% for sure caused this was a XamlParseException caused by forgetting a Value attribute on a data trigger. I've fixed that part but it still doesn't tell my why my studio becomes a lump of neutered program when a perfectly normal exception is thrown in the parsing of the XAML. Code that will cause this issue (at least for me) This is the base template WPF Application, with the following Window.xaml code. The problem is a missing Value="True" on the <DataTrigger ...> in the template. It generates a XamlParseException and Visual Studio Crashes as described above when debugging it. Final Notes The following solutions did not help me: Restarting Visual Studio Rebooting Reinstalling Visual Studio

    Read the article

  • How to save a stream on google drive?

    - by atu0830
    My application running on google app engine, so can not use File. I want to save a pdf file on other site to google drive, but get a IllegalArgumentException file.setMimeType("application/pdf"); mediaContent = new InputStreamContent(file.getMimeType(), url.openStream()); try { File result = getDrive().files().insert(file, mediaContent) .execute(); return result.getId(); } catch (Exception e) { e.printStackTrace(); } Thanks

    Read the article

  • Getting started with XSD validation with .NET

    - by Rosarch
    Here is my first attempt at validating XML with XSD. The XML file to be validated: <?xml version="1.0" encoding="utf-8" ?> <config xmlns="Schemas" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="config.xsd"> <levelVariant> <filePath>SampleVariant</filePath> </levelVariant> <levelVariant> <filePath>LegendaryMode</filePath> </levelVariant> <levelVariant> <filePath>AmazingMode</filePath> </levelVariant> </config> The XSD, located in "Schemas/config.xsd" relative to the XML file to be validated: <?xml version="1.0" encoding="utf-8" ?> <xs:schema xmlns:xs="http://www.w3.org/2001/XMLSchema" elementFormDefault="qualified"> <xs:element name="config"> <xs:complexType> <xs:sequence> <xs:element name="levelVariant"> <xs:complexType> <xs:sequence> <xs:element name="filePath" type="xs:anyURI"> </xs:element> </xs:sequence> </xs:complexType> </xs:element> </xs:sequence> </xs:complexType> </xs:element> </xs:schema> Right now, I just want to validate the XML file precisely as it appears currently. Once I understand this better, I'll expand more. Do I really need so many lines for something as simple as the XML file as it currently exists? The validation code in C#: public void SetURI(string uri) { XElement toValidate = XElement.Load(Path.Combine(PATH_TO_DATA_DIR, uri) + ".xml"); // begin confusion // exception here string schemaURI = toValidate.Attributes("xmlns").First().ToString() + toValidate.Attributes("xsi:noNamespaceSchemaLocation").First().ToString(); XmlSchemaSet schemas = new XmlSchemaSet(); schemas.Add(null, schemaURI); XDocument toValidateDoc = new XDocument(toValidate); toValidateDoc.Validate(schemas, null); // end confusion root = toValidate; } Running the above code gives this exception: The ':' character, hexadecimal value 0x3A, cannot be included in a name. Any illumination would be appreciated.

    Read the article

  • Stop MediaScanner scanning of certain directory

    - by kape123
    Is there a way to notify MediaScanner service on Android platform not to scan certain directories? I have application that encrypts images on SD card and after I do that MediaScanner goes wild in LogCat (writing out "not JPEG" exception... and there are time I have over 1000 pics in directory). Thanks

    Read the article

  • Help I don't know how to handle this error (java.lang.RuntimeException: EMBEDDED Broker start failur

    - by HC
    I follow this tutorial (http://www.netbeans.org/kb/docs/websvc/rest-mysql.html) and it's success, but when i try with my database, it become error. I already follow step by step , but still error, anyone know how to handle this error? or it's bug too? MQJMSRA_RA4001: start:Aborting:Exception starting EMBEDDED broker=EMBEDDED Broker start failure:code = 1 java.lang.RuntimeException: EMBEDDED Broker start failure:code = 1 at com.sun.messaging.jms.ra.EmbeddedBrokerRunner.start(EmbeddedBrokerRunner.java:268) at com.sun.messaging.jms.ra.ResourceAdapter.start(ResourceAdapter.java:472)

    Read the article

  • URL load error during adding

    - by Steven
    hi, i have a string say Path ="C:\AAA\bin" which is a path to a project's bin folder. I used new URL(Path) during invocation of addURL method of URLClassLoader class. ex- addURL(sysLoader,new URL(Path)) ; its giving unknown protocol:c exception whats the problem?Help

    Read the article

< Previous Page | 229 230 231 232 233 234 235 236 237 238 239 240  | Next Page >