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  • odd resharper indentation formatting for opject intializers

    - by bitbonk
    For some strange reason when I have nested object intializers it always gets the last '}' wrong. It is not indented at all as shown in the following example: namespace MyNameSpace { internal static class MyClass { static MyClass() { var bla = new Bla { Name = "Bla" }; bla.Blub = new Blub { Name = "Blub", Blap = new Blap { Name = "Blap", Visible = true }, Blob = new Blob { Name = "Blob" }, Blib = new Blib { Blep = new Heater { Name = "Bleb" }, Id = 1, Blap = new Blap { Name = "Blap" } } // <---- wrong !!! }; } } } Any idea what I can do against it ?

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  • How can I use a value from a session variable as part of the group name in signalR

    - by user1844734
    Hi I am trying to set up signalR to distribute messages to web users the problem is that the one site holds different 'areas' and also 'user types'. The Area is decided when the user visits the site by passing a url parameter, this is then stored in a session variable, The 'user type' is by default not logged in then changed when the user logs in to there user type (returned from a webservice) and stored in a User object. My aim was to connect to the hub using signalR when the user visits the site and add the users connectionId to a groupname, using the 'area id' from the session and the 'user type id' from the User object in the context. The problem I am having is that I can obtain the user id but when it comes to the area id signalR cannot access the session. I understand the reasoning behind not allowing the session available in signalR but does any one know if there is a way to enable this or an alternative way that I can gain access to the users area so that I can create these unique groups.

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  • Is there a way to get Apache to serve files with the question mark in their name?

    - by ldrg
    I scraped a bunch of pages using wget -m -k -E. The resulting files have names in the form foo.php?bar.html. Apache guesses everything after the ? is a query string, is there a way to tell it to ignore the ? as the query string delimiter (and see foo.php?bar.html as the requested file and not foo.php)? To save you a trip to wget manpage: -m : mirror recursively -E : foo.php?bar becomes foo.php?bar.html -k : convert links in pages (foo.php?bar now links to foo.php?bar.html inside of all the pages so they display properly)

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  • Multiple apks, single listing of app for Google TV and Android Phone/Tablet

    - by Yash
    I have an Android phone/tablet apk which is currently in Play store and has these settings in its manifest file: package="com.company.xyz" android:versionCode="0803010008" android:versionName="01.00.08" > <uses-sdk android:minSdkVersion="8" android:targetSdkVersion="8" /> <uses-permission android:name="android.permission.INTERNET" /> <uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" /> <uses-permission android:name="android.permission.RECEIVE_BOOT_COMPLETED" /> <uses-permission android:name="android.permission.WAKE_LOCK" /> <uses-library android:name="com.adobe.flashplayer" android:required="true" /> <supports-screens android:anyDensity="true" android:largeScreens="true" android:normalScreens="true" android:smallScreens="false" android:xlargeScreens="true" /> <uses-feature android:name="android.hardware.touchscreen" android:required="true" /> I had uploaded another apk for GoogleTV which has the same package name com.company.xyz as the previous apk and has the following settings in its manifest file: package="com.company.xyz" android:versionCode="1203010001" android:versionName="01.00.01" > <uses-sdk android:minSdkVersion="12" android:targetSdkVersion="12" /> <uses-permission android:name="android.permission.INTERNET" /> <uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" /> <uses-permission android:name="android.permission.WAKE_LOCK" /> <uses-feature android:name="android.hardware.touchscreen" android:required="false" /> <uses-feature android:name="com.google.android.tv" android:required="true" /> <supports-screens android:largeScreens="true"/> <uses-configuration android:reqFiveWayNav="true" /> The Google TV apk never showed up on Play Store on GTV boxes, so I updated its manifest with the settings below and with everything else remaining the same package="com.company.xyz" android:versionCode="1203010002" android:versionName="01.00.02" > <supports-screens android:largeScreens="true" android:normalScreens="false" android:smallScreens="false" android:xlargeScreens="false" /> At this point, I am unable to save the app because of the Play Store error "Error: New APK version is lower than previous APK version" even though the GoogleTV apk has a higher version code than the Phone/Tablet version. Does anyone have a solution for this? Thanks!

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  • XSLT adding elements on the same path

    - by Stefan
    Consider the following XML: <?xml version="1.0" encoding="ISO-8859-1"?> <catalog> <cd> <title>Empire Burlesque</title> <artist> <name>Bob</name> <surname>Dylan</surname> </artist> <country>USA</country> <company>Columbia</company> <price>10.90</price> <year>1985</year> </cd> </catalog> I want to add elements to this XML using XSLT, to get the following result: <?xml version="1.0" encoding="ISO-8859-1"?> <catalog> <cd> <title>Empire Burlesque</title> <artist> <name>Bob</name> <surname>Dylan</surname> <!-- NEW --> <middlename>???</middlename> </artist> <country>USA</country> <company>Columbia</company> <price>10.90</price> <year>1985</year> <!-- NEW --> <comment>great one</comment> </cd> <!-- NEW --> <cd> <title>Hide your heart</title> <artist> <name>Bonnie</name> <surname>Tyler</surname> </artist> <country>UK</country> <company>CBS Records</company> <price>9.90</price> <year>1988</year> </cd> </catalog> To achieve that, I wrote the following XSLT: <?xml version="1.0" encoding="ISO-8859-1"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template name="injectXml"> <xsl:param name="whatToInject"/> <xsl:copy> <xsl:copy-of select="node() | @*"/> <xsl:copy-of select="$whatToInject"/> </xsl:copy> </xsl:template> <xsl:template match="//catalog"> <xsl:call-template name="injectXml"> <xsl:with-param name="whatToInject"> <cd> <title>Hide your heart</title> <artist> <name>Bonnie</name> <surname>Tyler</surname> </artist> <country>UK</country> <company>CBS Records</company> <price>9.90</price> <year>1988</year> </cd> </xsl:with-param> </xsl:call-template> </xsl:template> <xsl:template match="//cd[year=1985]"> <xsl:call-template name="injectXml"> <xsl:with-param name="whatToInject"> <comment>great one</comment> </xsl:with-param> </xsl:call-template> </xsl:template> <xsl:template match="//cd[year=1985]/artist"> <xsl:call-template name="injectXml"> <xsl:with-param name="whatToInject"> <middlename>???</middlename> </xsl:with-param> </xsl:call-template> </xsl:template> </xsl:stylesheet> Why it's not working? How to do it?

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  • Using cascade in NHibernate

    - by Tyler
    I have two classes, call them Monkey and Banana, with a one-to-many bidirectional relationship. Monkey monkey = new Monkey(); Banana banana = new Banana(); monkey.Bananas.Add(banana); banana.Monkey = monkey; hibernateService.Save(banana); When I run that chunk of code, I want both monkey and banana to be persisted. However, it's only persisting both when I explicitly save the monkey and not vice versa. Initially, this made sense since only my Monkey.hbm.xml had a mapping with cascade="all". <set name="Bananas" inverse="true" cascade="all"> <key column="Id"/> <one-to-many class="Banana"/> </set> I figured I just needed to add the following to my Banana.hbm.xml file: <many-to-one name="Monkey" column="Id" cascade="all" /> Unfortunately, this resulted in a Parameter index is out of range error when I tried to run the snippet of code. I investigated this error and found this post, but I still don't see what I'm doing wrong. I have the relationship mapped once on each side as far as I can tell. For full disclosure, here are the two mapping files: Monkey.hbm.xml <class name="Monkey" table="monkies" lazy="true"> <id name="Id"> <generator class="increment" /> </id> <property name="Name" /> <set name="Bananas" inverse="true" cascade="all"> <key column="Id"/> <one-to-many class="Banana"/> </set> </class> Banana.hbm.xml <class name="Banana" table="bananas" lazy="true"> <id name="Id"> <generator class="increment" /> </id> <property name="Name" /> <many-to-one name="Monkey" column="Id" cascade="all" /> </class>

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  • How do I draw part of parabola using iText ? Or how do I create quadratic bezier curves from cubic b

    - by drasto
    I need to draw a shape whose boundaries are parts of parabola (that is quadratic bezier curves) using iText. I have found only method for drawing cubic bezier curves in PdfContentByte class. So how do I draw quadratic bezier curves using iText ? One way would be to use method for cubic bezier curves. Is it possible to draw quadratic bezier curves as a cubic bezier curves (with 2 control points). I gues it is but I cannot make up the formula. If somebody states the formula tu "translate" cubic bezier curves to quadratic that would solve the problem. Any other ways to draw quadratic bezier(parts of parabola) curves in iText (and filled shapes made of them) is also the solution. Thanks

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  • In T-SQL how to display columns for given table name?

    - by salvationishere
    I am trying to list all of the columns from whichever Adventureworks table I choose. What T-sQL statement or stored proc can I execute to see this list of all columns? I want to use my C# web app to input one input parameter = table_name and then get a list of all the column_names as output. Right now I am trying to execute the sp_columns stored proc which works, but I can't get just the one column with select and exec combined. Does anybody know how to do this?

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  • Ant build classpath jar generates "error in opening zip file"

    - by Uberpuppy
    I have a project built in eclipse with a dependencies on 3rd party jars. I'm trying to generate a suitable build file for ant - using eclipses built-in export-ant buildfile feature as a starting block. When I run the build target I get the following error: [javac] error: error reading /base/repo/FabTrace/lib/apache/geronimo/specs/geronimo-j2ee-management_1.0_spec/1.0/geronimo-j2ee-management_1.0_spec-1.0.jar; error in opening zip file And the whole build file (auto-generated by eclipse) looks like this: (NB: the error above always references the first jar listed in the classpath) <project basedir="." default="build" name="FabTrace"> <property environment="env"/> <property name="ECLIPSE_HOME" value="/opt/apps/eclipse"/> <property name="debuglevel" value="source,lines,vars"/> <property name="target" value="1.5"/> <property name="source" value="1.5"/> <path id="JUnit 4.libraryclasspath"> <pathelement location="${ECLIPSE_HOME}/plugins/org.junit4_4.5.0.v20090824/junit.jar"/> <pathelement location="${ECLIPSE_HOME}/plugins/org.hamcrest.core_1.1.0.v20090501071000.jar"/> </path> <path id="FabTrace.classpath"> <pathelement location="bin"/> <pathelement location="lib/apache/geronimo/specs/geronimo-j2ee-management_1.0_spec/1.0/geronimo-j2ee-management_1.0_spec-1.0.jar"/> <pathelement location="lib/apache/geronimo/specs/geronimo-jms_1.1_spec/1.0/geronimo-jms_1.1_spec-1.0.jar"/> <pathelement location="lib/commons-collections/commons-collections/3.2/commons-collections-3.2.jar"/> <pathelement location="lib/commons-io/commons-io/1.4/commons-io-1.4.jar"/> <pathelement location="lib/commons-lang/commons-lang/2.1/commons-lang-2.1.jar"/> <pathelement location="lib/commons-logging/commons-logging/1.1/commons-logging-1.1.jar"/> <pathelement location="lib/commons-logging/commons-logging-api/1.1/commons-logging-api-1.1.jar"/> <pathelement location="lib/javax/activation/activation/1.1/activation-1.1.jar"/> <pathelement location="lib/javax/jms/jms/1.1/jms-1.1.jar"/> <pathelement location="lib/javax/mail/mail/1.4/mail-1.4.jar"/> <pathelement location="lib/javax/xml/bind/jaxb-api/2.1/jaxb-api-2.1.jar"/> <pathelement location="lib/javax/xml/stream/stax-api/1.0-2/stax-api-1.0-2.jar"/> <pathelement location="lib/junit/junit/4.4/junit-4.4.jar"/> <pathelement location="lib/log4j/log4j/1.2.15/log4j-1.2.15.jar"/> <pathelement location="lib/apache/camel/camel-jms-2.0-M1.jar"/> <pathelement location="lib/spring/spring-2.5.6.jar"/> <pathelement location="lib/apache/camel/camel-bundle-2.0-M1.jar"/> <pathelement location="lib/backport-util-concurrent/backport-util-concurrent-3.1.jar"/> <pathelement location="lib/commons-pool/commons-pool-1.4.jar"/> <pathelement location="lib/apache/camel/camel-activemq-1.1.0.jar"/> <pathelement location="lib/apache/activemq/activemq-camel-5.2.0.jar"/> <pathelement location="lib/jencks/jencks-2.2-all.jar"/> <pathelement location="lib/jencks/jencks-amqpool-2.2.jar"/> <pathelement location="lib/activemq/apache-activemq-5.3.1/activemq-all-5.3.1.jar"/> <pathelement location="lib/activemq/apache-activemq-5.3.1/lib/optional/xbean-spring-3.6.jar"/> <pathelement location="lib/activemq/apache-activemq-5.3.1/lib/activemq-core-5.3.1.jar"/> <pathelement location="lib/activemq/apache-activemq-5.3.1/lib/camel-jetty-2.2.0.jar"/> <pathelement location="lib/activemq/apache-activemq-5.3.1/lib/web/jetty-6.1.9.jar"/> <pathelement location="lib/activemq/apache-activemq-5.3.1/lib/web/jetty-util-6.1.9.jar"/> <pathelement location="lib/activemq/apache-activemq-5.3.1/lib/web/jetty-xbean-6.1.9.jar"/> <pathelement location="lib/activemq/apache-activemq-5.3.1/lib/optional/activemq-optional-5.3.1.jar"/> <pathelement location="lib/activemq/apache-activemq-5.3.1/lib/web/geronimo-servlet_2.5_spec-1.2.jar"/> <pathelement location="lib/activemq/apache-activemq-5.3.1/lib/optional/spring-beans-2.5.6.jar"/> <pathelement location="lib/activemq/apache-activemq-5.3.1/lib/optional/spring-context-2.5.6.jar"/> <pathelement location="lib/activemq/apache-activemq-5.3.1/lib/optional/spring-core-2.5.6.jar"/> <path refid="JUnit 4.libraryclasspath"/> </path> <target name="init"> <mkdir dir="bin"/> <copy includeemptydirs="false" todir="bin"> <fileset dir="src/main/java"> <exclude name="**/*.launch"/> <exclude name="**/*.java"/> </fileset> </copy> <copy includeemptydirs="false" todir="bin"> <fileset dir="src/test/java"> <exclude name="**/*.launch"/> <exclude name="**/*.java"/> </fileset> </copy> <copy includeemptydirs="false" todir="bin"> <fileset dir="config"> <exclude name="**/*.launch"/> <exclude name="**/*.java"/> </fileset> </copy> </target> <target name="clean"> <delete dir="bin"/> </target> <target depends="clean" name="cleanall"/> <target depends="build-subprojects,build-project" name="build"/> <target name="build-subprojects"/> <target depends="init" name="build-project"> <echo message="${ant.project.name}: ${ant.file}"/> <javac debug="true" debuglevel="${debuglevel}" destdir="bin" source="${source}" target="${target}"> <src path="src/main/java"/> <classpath refid="FabTrace.classpath"/> </javac> <javac debug="true" debuglevel="${debuglevel}" destdir="bin" source="${source}" target="${target}"> <src path="src/test/java"/> <classpath refid="FabTrace.classpath"/> </javac> <javac debug="true" debuglevel="${debuglevel}" destdir="bin" source="${source}" target="${target}"> <src path="config"/> <classpath refid="FabTrace.classpath"/> </javac> </target> </project> (I know there's eclipse specific stuff in here. But I get the same results with or without it.) I've done ye old google search and trawled around without success. I can confirm that all the jars do really exist. I've also tried from the commandline and as sudo - again, same results. Any help would be greatly appreciated. Cheers

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  • How does this code break the Law of Demeter?

    - by Dave Jarvis
    The following code breaks the Law of Demeter: public class Student extends Person { private Grades grades; public Student() { } /** Must never return null; throw an appropriately named exception, instead. */ private synchronized Grades getGrades() throws GradesException { if( this.grades == null ) { this.grades = createGrades(); } return this.grades; } /** Create a new instance of grades for this student. */ protected Grades createGrades() throws GradesException { // Reads the grades from the database, if needed. // return new Grades(); } /** Answers if this student was graded by a teacher with the given name. */ public boolean isTeacher( int year, String name ) throws GradesException, TeacherException { // The method only knows about Teacher instances. // return getTeacher( year ).nameEquals( name ); } private Grades getGradesForYear( int year ) throws GradesException { // The method only knows about Grades instances. // return getGrades().getForYear( year ); } private Teacher getTeacher( int year ) throws GradesException, TeacherException { // This method knows about Grades and Teacher instances. A mistake? // return getGradesForYear( year ).getTeacher(); } } public class Teacher extends Person { public Teacher() { } /** * This method will take into consideration first name, * last name, middle initial, case sensitivity, and * eventually it could answer true to wild cards and * regular expressions. */ public boolean nameEquals( String name ) { return getName().equalsIgnoreCase( name ); } /** Never returns null. */ private synchronized String getName() { if( this.name == null ) { this.name == ""; } return this.name; } } Questions How is the LoD broken? Where is the code breaking the LoD? How should the code be written to uphold the LoD?

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  • Navigating to nodes using xpath in flat structure

    - by James Berry
    I have an xml file in a flat structure. We do not control the format of this xml file, just have to deal with it. I've renamed the fields because they are highly domain specific and don't really make any difference to the problem. <attribute name="Title">Book A</attribute> <attribute name="Code">1</attribute> <attribute name="Author"> <value>James Berry</value> <value>John Smith</value> </attribute> <attribute name="Title">Book B</attribute> <attribute name="Code">2</attribute> <attribute name="Title">Book C</attribute> <attribute name="Code">3</attribute> <attribute name="Author"> <value>James Berry</value> </attribute> Key things to note: the file is not particularly hierarchical. Books are delimited by an occurance of an attribute element with name='Title'. But the name='Author' attribute node is optional. Is there a simple xpath statement I can use to find the authors of book 'n'? It is easy to identify the title of book 'n', but the authors value is optional. And you can't just take the following author because in the case of book 2, this would give the author for book 3. I have written a state machine to parse this as a series of elements, but I can't help thinking there would have been a way to directly get the results that I want.

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  • Problems with php:(

    - by Marin
    Please help me again! I have problems with this code: <?php $pathThemes = INC_DIR . "themes"; $d = dir($pathThemes); while (false !== ($entry = $d->read())) { $fileInfo = pathinfo($pathThemes . '/' . $entry); if ('php' == $fileInfo['extension']) { include_once($pathThemes . '/' . $entry); $name = $fileInfo['filename']; if (!$GLOBALS['fc_config']['themes'][$name]['name']) { unset($GLOBALS['fc_config']['themes'][$name]); } } } ?> It says me: Notice: Undefined index: name in C:\wamp\www\FlashChat_v607\chat\inc\include_themes.php on line 10 Notice: Undefined index: name in C:\wamp\www\FlashChat_v607\chat\inc\include_themes.php on line 10 Notice: Undefined index: name in C:\wamp\www\FlashChat_v607\chat\inc\include_themes.php on line 10 Notice: Undefined index: name in C:\wamp\www\FlashChat_v607\chat\inc\include_themes.php on line 10 Help me plz;(

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  • RESTful design, how to name pages outside CRUD et al?

    - by sscirrus
    Hi all, I'm working on a site that has quite a few pages that fall outside my limited understanding of RESTful design, which is essentially: Create, Read, Update, Delete, Show, List Here's the question: what is a good system for labeling actions/routes when a page doesn't neatly fall into CRUD/show/list? Some of my pages have info about multiple tables at once. I am building a site that gives some customers a 'home base' after they log on. It does NOT give them any information about themselves so it shouldn't be, for example, /customers/show/1. It does have information about companies, but there are other pages on the site that do that differently. What do you do when you have these situations? This 'home-base' is shown to customers and it mainly has info about companies (but not uniquely so). Second case: I have a table called 'Matchings' in between customers and companies. These matchings are accessed in completely different ways on different parts of the site (different layouts, different CSS sheets, different types of users accessing them, etc. They can't ALL be matchings/show. What's the best way to label the others? Thanks very much. =)

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  • NHibernate Mapping problem

    - by Bernard Larouche
    My database is being driven by my NHibernate mapping files. I have a Category class that looks like the following : public class Category { public Category() : this("") { } public Category(string name) { Name = name; SubCategories = new List<Category>(); Products = new HashSet<Product>(); } public virtual int ID { get; set; } public virtual string Name { get; set; } public virtual string Description { get; set; } public virtual Category Parent { get; set; } public virtual bool IsDefault { get; set; } public virtual ICollection<Category> SubCategories { get; set; } public virtual ICollection<Product> Products { get; set; } and here is my Mapping file : <property name="Name" column="Name" type="string" not-null="true"/> <property name="IsDefault" column="IsDefault" type="boolean" not-null="true" /> <property name="Description" column="Description" type="string" not-null="true" /> <many-to-one name="Parent" column="ParentID"></many-to-one> <bag name="SubCategories" inverse="true"> <key column="ParentID"></key> <one-to-many class="Category"/> </bag> <set name="Products" table="Categories_Products"> <key column="CategoryId"></key> <many-to-many column="ProductId" class="Product"></many-to-many> </set> when I try to create the database I get the following error : failed: The INSERT statement conflicted with the FOREIGN KEY SAME TABLE constraint "FK9AD976763BF05E2A". The conflict occurred in database "CoderForTraders", table "dbo.Categories", column 'CategoryId'. The statement has been terminated. I looked on the net for some answers but found none. Thanks for your help

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  • How to properly test Hibernate length restriction?

    - by Cesar
    I have a POJO mapped with Hibernate for persistence. In my mapping I specify the following: <class name="ExpertiseArea"> <id name="id" type="string"> <generator class="assigned" /> </id> <version name="version" column="VERSION" unsaved-value="null" /> <property name="name" type="string" unique="true" not-null="true" length="100" /> ... </class> And I want to test that if I set a name longer than 100 characters, the change won't be persisted. I have a DAO where I save the entity with the following code: public T makePersistent(T entity){ transaction = getSession().beginTransaction(); transaction.begin(); try{ getSession().saveOrUpdate(entity); transaction.commit(); }catch(HibernateException e){ logger.debug(e.getMessage()); transaction.rollback(); } return entity; } Actually the code above is from a GenericDAO which all my DAOs inherit from. Then I created the following test: public void testNameLengthMustBe100orLess(){ ExpertiseArea ea = new ExpertiseArea( "1234567890" + "1234567890" + "1234567890" + "1234567890" + "1234567890" + "1234567890" + "1234567890" + "1234567890" + "1234567890" + "1234567890"); assertTrue("Name should be 100 characters long", ea.getName().length() == 100); ead.makePersistent(ea); List<ExpertiseArea> result = ead.findAll(); assertEquals("Size must be 1", result.size(),1); ea.setName(ea.getName()+"1234567890"); ead.makePersistent(ea); ExpertiseArea retrieved = ead.findById(ea.getId(), false); assertTrue("Both objects should be equal", retrieved.equals(ea)); assertTrue("Name should be 100 characters long", (retrieved.getName().length() == 100)); } The object is persisted ok. Then I set a name longer than 100 characters and try to save the changes, which fails: 14:12:14,608 INFO StringType:162 - could not bind value '12345678901234567890123456789012345678901234567890123456789012345678901234567890123456789012345678901234567890' to parameter: 2; data exception: string data, right truncation 14:12:14,611 WARN JDBCExceptionReporter:100 - SQL Error: -3401, SQLState: 22001 14:12:14,611 ERROR JDBCExceptionReporter:101 - data exception: string data, right truncation 14:12:14,614 ERROR AbstractFlushingEventListener:324 - Could not synchronize database state with session org.hibernate.exception.DataException: could not update: [com.exp.model.ExpertiseArea#33BA7E09-3A79-4C9D-888B-4263314076AF] //Stack trace 14:12:14,615 DEBUG GenericDAO:87 - could not update: [com.exp.model.ExpertiseArea#33BA7E09-3A79-4C9D-888B-4263314076AF] 14:12:14,616 DEBUG JDBCTransaction:186 - rollback 14:12:14,616 DEBUG JDBCTransaction:197 - rolled back JDBC Connection That's expected behavior. However when I retrieve the persisted object to check if its name is still 100 characters long, the test fails. The way I see it, the retrieved object should have a name that is 100 characters long, given that the attempted update failed. The last assertion fails because the name is 110 characters long now, as if the ea instance was indeed updated. What am I doing wrong here?

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  • MS Access 2003 - Option Group frame: can I add text boxes that are part of the frame instead of rad

    - by Justin
    Ok so this maybe a simple/silly question but I don't know so here goes: In access let's say I want to have a frame control, so I click the option group button and add it to the desgin surface. However, I am not wanting to use this as a option group with radio button selection, instead I would like to add text boxes instead the frame, so that when I reference the frame, it references every control instead of it, hence the text boxes, cbo boxes, etc.....just as it would if they were radio option selections. So can you do this? I want whatever controls I add inside the frame to be easily referenced (i.e. make all controls visible just by using frameExample.visible = true) so that I can build my own tab control groupings..... can this be done? Thanks! EDIT: What I am trying to accomplish is having a form that includes a collection of controls (input controls - cbo boxes, text boxes, etc), that serve as the Main record information. These are saved to a table via an INSERT statement on button_click because this form is unbound. Next I have 8 categories that are relative per each main record (and data that goes along with it). Each of these categories could have a sub form area and a button click that bring it's relative form into the sub form area. These sub forms would be unbound as well as I would just save data via SQL statement. So i know I could accomplish this by running the insert statement from the parent form, on the main collection control's data that would create the KeyID number, then run a SQL statement that would turn around and load that KeyID number right back onto the page in a hidden text box. Then when I click one of the sub forms and load its relative collection of controls, I could then save that data along with KeyID for each of these sub-forms/tables. SO...... I was wondering if instead you could define these controls as a collection so that you could hide and make visible all the ones you need on button clicks and avoid the need for additional forms (subs). I know that if a user enters data into a text box, and then somewhere along the way that box becomes hidden, the data still exists in it and still ends up in the SQL statement.... So I want all these controls to exist on the same form, but I thought what is I could encapsulate them into a frame like an option group, then I could call the frame and all the relative controls would be called up (made visible) as needed. Sorry for the long explanation but I thought it would help.

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  • How can I efficiently group a large list of URLs by their host name in Perl?

    - by jesper
    I have text file that contains over one million URLs. I have to process this file in order to assign URLs to groups, based on host address: { 'http://www.ex1.com' = ['http://www.ex1.com/...', 'http://www.ex1.com/...', ...], 'http://www.ex2.com' = ['http://www.ex2.com/...', 'http://www.ex2.com/...', ...] } My current basic solution takes about 600 MB of RAM to do this (size of file is about 300 MB). Could you provide some more efficient ways? My current solution simply reads line by line, extracts host address by regex and puts the url into a hash. EDIT Here is my implementation (I've cut off irrelevant things): while($line = <STDIN>) { chomp($line); $line =~ /(http:\/\/.+?)(\/|$)/i; $host = "$1"; push @{$urls{$host}}, $line; } store \%urls, 'out.hash';

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  • Downloading jQuery UI: Ok, so what part of this mess do I copy to the server?

    - by Martha
    From the "should be simple, but..." files: Trying to get started with jQuery UI. Went to the site, used their custom builder thingy to assemble the parts I need, made myself a custom theme using the Theme Roller, downloaded the zip file thus produced, unzipped it on my local drive. Ok, so I have 37 folders, 311 files, and a total of 2.4 MB. Ain't no way in hell all this is going on the server. What parts do I need to put there? 'css' 'custom-theme': jquery-ui-1.8.custom.css, 'images' subfolder with 12 .png images 'development-bundle' 'demos': demos.css, index.html, plus 18 subfolders, but I'm guessing "not needed" 'docs': 17 .html files, but again, I'm guessing "not needed" 'external': 4 .js files, one .css 'themes': 'base' and 'custom-theme' subfolders, each with 8 or 9 .css files and an 'images' subfolder with about a dozen images 'ui': 25 .js files, an 'i18n' subfolder with 53 .js files, and a 'minified' subfolder with 24 .js files 'js': jquery-1.4.2.min.js and jquery-ui-1.8.custom.min.js Also, the file structure. Our server is set up something like this: root admin (administrative tools) css forms (the gist of the site lives here) images include (asp code snippets that are used by multiple pages) js (just a few things right now, like an ancient wheezing spelling checker) As far as I can tell, the jQuery css files assume that (1) each theme is in its own folder, and (2) each folder has its own images subfolder. How can I convince it otherwise? i.e. put the necessary .js files in the 'js' folder, the .css files in the 'css' folder, and the images in the 'images' folder?

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  • How to display part of an image for the specific width and height?

    - by Brady Chu
    Recently I participated in a web project which has a huge large of images to handle and display on web page, we know that the width and height of images end users uploaded cannot be control easily and then they are hard to display. At first, I attempted to zoom in/out the images to rearch an appropriate presentation, and I made it, but my boss is still not satisfied with my solution, the following is my way: var autoResizeImage = function(maxWidth, maxHeight, objImg) { var img = new Image(); img.src = objImg.src; img.onload = function() { var hRatio; var wRatio; var Ratio = 1; var w = img.width; var h = img.height; wRatio = maxWidth / w; hRatio = maxHeight / h; if (maxWidth == 0 && maxHeight == 0) { Ratio = 1; } else if (maxWidth == 0) { if (hRatio < 1) { Ratio = hRatio; } } else if (maxHeight == 0) { if (wRatio < 1) { Ratio = wRatio; } } else if (wRatio < 1 || hRatio < 1) { Ratio = (wRatio <= hRatio ? wRatio : hRatio); } if (Ratio < 1) { w = w * Ratio; h = h * Ratio; } w = w <= 0 ? 250 : w; h = h <= 0 ? 370 : h; objImg.height = h; objImg.width = w; }; }; This way is only intended to limit the max width and height for the image so that every image in album still has different width and height which are still very urgly. And right at this minute, I know we can create a DIV and use the image as its background image, this way is too complicated and not direct I don't want to take. So I's wondering whether there is a better way to display images with the fixed width and height without presentation distortion? Thanks.

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