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• Question about Benchmark funcion in Mysql ( Incredible results ).

  - by xRobot

  I have 2 tables: author with 3 millions of rows. book with 20 miles rows. . So I have benchmarked this query with a join: SELECT BENCHMARK(100000000, 'SELECT book.title, author.name FROM `book` , `author` WHERE book.id = author.book_id ') And this is the result: Query took 0.7438 sec ONLY 0.7438 seconds for 100 millions of query with a join ??? Do I make some mistakes or this is the right result ?

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• MySQL customized join query using multiple tables

  - by itgeek

  I am searching one student from each class from one group. There are different class groups and every group has different classes and every class has multiple students. See below: Group1 --> Class1, Class2 etc Class1 --> GreenStudent1, GreenStudent2 etc Class2 --> RedStudent1, RedStudent2 etc ------------------------------------------------------ SELECT table1.id, table1.myname, table1.marks table2.studentid, table2.studentname FROM table1 INNER JOIN table3 ON table1.oldid = table3.id INNER JOIN table2 ON table2.studentid = table3.newid WHERE table1.classgroup = 'SCI79' GROUP BY table1.oldid ORDER BY table1.marks DESC There are different joins applied in the query. Above mentioned query giving me correct results but I need little modification in it. Current query returning me one student from each class. What I need? I need one student from each class but only that student who has MAXIMUM table1.marks So I should have one student from each class who has maximum number in their relevant classes. Can anyone suggest some solution or rewrite this query? Thanks :)

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• MySQL JOIN with IF conditions.

  - by user333187

  Hi, I want to get some results via query simillar to: SELECT * FROM users LEFT JOIN IF (users.type = '1', 'private','company') AS details ON users.id = details.user_id WHERE users.id = 1 Any ideas?

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• MySQL - Select the last inserted row easiest way

  - by Tomas

  Hi, I would need simply select the last entered row specified by condition,e.g: SELECT ID from bugs WHERE user=Me I need to return only the very last ID entered by user 'Me'. Is there any simple way? Thank you

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• MySQL whats wrong with my foreign keys?

  - by Skiy

  Hello, what is wrong with the two foreign keys which I have marked with comments? create database db; use db; create table Flug( Flugbez varchar(20), FDatum Date, Ziel varchar(20), Flugzeit int, Entfernung int, Primary Key (Flugbez, FDatum)); create table Flugzeugtyp( Typ varchar(20), Hersteller varchar(20), SitzAnzahl int, Reisegeschw int, primary key (Typ) ); create table flugzeug( Typ varchar(20), SerienNr int, AnschDatum Date, FlugStd int, primary key(Typ,SerienNr), foreign key(Typ) references Flugzeugtyp(Typ)); create table Abflug( Flugbez varchar(20), FDatum Date, Typ varchar(20), Seriennr int, Kaptaen varchar(20), Primary key(Flugbez,FDatum,Typ,SerienNr), Foreign key(Flugbez) references Flug(Flugbez), -- Foreign key(FDatum) references Flug(FDatum), Foreign key(Typ) references Flugzeugtyp(Typ) -- ,Foreign key(SerienNr) references Flugzeug(SerienNr) ); When I uncomment these, I get: ERROR 1005 (HY000): Can't create table 'db.abflug' (errno: 150)

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• C#:checking existing record in database Mysql

  - by Meko

  HI.I searched this question inform and I found solution to change column property Unique Index.Now If I try to insert same record cmd.ExecuteNonQuery() gives error that record exist ,but how can use this exception to give user a message that record exist and must enter new one ? I am trying to make some thing like if(cmd.ExecuteNonQuery() !=true ) { MessageBox.Show("User Exists"); } But I dont know what returns cmd.ExecuteNonQuery() ? Or I must get records using reader in table and compare them with text in Textfiel?

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• MySQL: Select pages that are not tagged?

  - by lauthiamkok

  Hi, I have a db with two tables like these below, page table pg_id title 1 a 2 b 3 c 4 d tagged table tagged_id pg_id 1 1 2 4 I want to select the pages which are tagged, I tried with this query below but doesn't work, SELECT * FROM root_pages LEFT JOIN root_tagged ON ( root_tagged.pg_id = root_pages.pg_id ) WHERE root_pages.pg_id != root_tagged.pg_id It returns zero - Showing rows 0 - 1 (2 total, Query took 0.0021 sec) But I want it to return pg_id title 2 b 3 c My query must have been wrong?? How can I return the pages which are not tagged correctly? Thanks.

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• Entering Content Into A MySQL Database Via A Form

  - by ThatMacLad

  I've been working on creating a form that submits content into my database but I decided that rather than using a drop down menu to select the date I'd rather use a textfield. I was wondering what changes I will need to make to my table creation file. <?php mysql_connect ('localhost', 'root', 'root') ; mysql_select_db ('tmlblog'); $sql = "CREATE TABLE php_blog ( id int(20) NOT NULL auto_increment, timestamp int(20) NOT NULL, title varchar(255) NOT NULL, entry longtext NOT NULL, PRIMARY KEY (id) )"; $result = mysql_query($sql) or print ("Can't create the table 'php_blog' in the database.<br />" . $sql . "<br />" . mysql_error()); mysql_close(); if ($result != false) { echo "Table 'php_blog' was successfully created."; } ?> It's the timestamp that I need to edit to enter in via a textfield. The Title and Entry are currently being entered via that method anyway.

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• PHP & MySQL checked checkbox problem

  - by BeepU

  I'm trying to check if the checkbox has been checked and display the check mark for the user to see when they check there account settings. I want to know how can I fix this problem using PHP so that the check mark is displayed every time the user views their account settings? Here is the HTML. <input type="checkbox" name="privacy_policy" id="privacy_policy" value="yes" />

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• In PHP + MySQL, How do I join many tables with conditions

  - by Moe

  Hi, I'm trying to get the users full activity throughout the website. I need to Join many tables throughout the database, with that condition that it is one user. What I currently have written is: SELECT * FROM comments AS c JOIN rphotos AS r ON c.userID = r.userID AND c.userID = '$defineUserID'; But What it is returning is everything about the user, but it repeats rows. For instance, for one user he has 6 photos and 5 comments So I expect the join to return 11 rows. Instead it returns 30 results like so: PhotoID = 1; CommentID = 1; PhotoID = 1; CommentID = 2; PhotoID = 1; CommentID = 3; and so on... What am i doing wrong?

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• Fighing system in Php & MYSQL

  - by Gully

  I am working on a game like Mafia Wars and i am trying to get the fighting system working but i keep getting lose trying to work out who is going to win the fight and it still needs to know if the stats are close then there is a random chace of them winning. $strength = $my_strength; $otherplayerinfo = mysql_query("SELECT * FROM accounts WHERE id='$player_id'"); $playerinfo = mysql_fetch_array($otherplayerinfo); $players_strength = $playerinfo['stre']; $players_speed = $playerinfo['speed']; $players_def = $playerinfo['def']; if($players_strength > $strength){ $strength_point_player = 1; $strength_point_your = 0; }else{ $strength_point_your = 1; $strength_point_player = 0; } I was trying a point system but i still could not do it.

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• string.replace seriously broken with \

  - by Blub

  "C://test/test/test.png" -> blub blub = blub.Replace(@"/", @"\"); result = "C:\\\\test\\test\\test.png" how does that make sense? It replaces a single / with two \ ?

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• [mysql] having a number in

  - by Wiika

  Hi all, ID Name Hidden 1 Mika 1,4,2 2 Loca 0 3 Nosta 4 4 Like 2 can someone give me a query that will return as a result rows ID 1 & 3 something like this SELECT * FROM table WHERE Hidden HAVING(4) Thanks, I Appreciate

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• Scanning string in perl

  - by Alphaneo

  What is the best way to achieve sscanf like functionality in perl? I am looking now looking at the sscanf module, Which is better, Option-1: Going sscanf way? Option-2: Regex way? [I am a beginner when it comes to Regex]

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• Best way to limit results in MySQL with user subcategories

  - by JM4

  I am trying to essentially solve for the following: 1) Find all users in the system who ONLY have programID 1. 2) Find all users in the system who have programID 1 AND any other active program. My tables structures (in very simple terms are as follows): users userID | Name ================ 1 | John Smith 2 | Lewis Black 3 | Mickey Mantle 4 | Babe Ruth 5 | Tommy Bahama plans ID | userID | plan | status --------------------------- 1 | 1 | 1 | 1 2 | 1 | 2 | 1 3 | 1 | 3 | 1 4 | 2 | 1 | 1 5 | 2 | 3 | 1 6 | 3 | 1 | 0 7 | 3 | 2 | 1 8 | 3 | 3 | 1 9 | 3 | 4 | 1 10 | 4 | 2 | 1 11 | 4 | 4 | 1 12 | 5 | 1 | 1 I know I can easily find all members with a specific plan with something like the following: SELECT * FROM users a JOIN plans b ON (a.userID = b.userID) WHERE b.plan = 1 AND b.status = 1 but this will only tell me which users have an 'active' plan 1. How can I tell who ONLY has plan 1 (in this case only userID 5) and how to tell who has plan 1 AND any other active plan? Update: This is not to get a count, I will actually need the original member information, including all the plans they have so a COUNT(*) response may not be what I'm trying to achieve.

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• mysql join on two indexes takes long time!!

  - by Alaa

  Hi All I have a custom query in dripal, this query is: select count(distinct B.src) from node A, url_alias B where concat('node/',A.nid)= B.src; now, nid in node is primary key and i have made src as an index in url_alias table. after waiting for more than a minute i got this: +-----------------------+ | count(distinct B.src) | +-----------------------+ | 325715 | +-----------------------+ 1 row in set (1 min 24.37 sec) now my question is: why did this query take this long, and how to optimize it?? Thanks for your help

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• How do I execute this query in MYSQL?

  - by alex

  Suppose I have a column with words: orange grape orange orange apple orange grape banana How do I execute a query to get the top 10 words, as well as their count?

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• JQuery Ajax Updating MySQL Database, But Not Running Success Function

  - by myrmidon16

  I am currently using the JQuery ajax function to call an exterior PHP file, in which I select and add data in a database. Once this is done, I run a success function in JavaScript. What's weird is that the database is updating successfully when ajax is called, however the success function is not running. Here is my code: <!DOCTYPE html> <head> <script type="text/javascript" src="jquery-1.6.4.js"></script> </head> <body> <div onclick="addtask();" style="width:400px; height:200px; background:#000000;"></div> <script> function addtask() { var tid = (Math.floor(Math.random() * 3)) + 1; var tsk = (Math.floor(Math.random() * 10)) + 1; if(tsk !== 1) { $.ajax({ type: "POST", url: "taskcheck.php", dataType: "json", data: {taskid:tid}, success: function(task) {alert(task.name);} }); } } </script> </body> </html> And the PHP file: session_start(); $connect = mysql_connect('x', 'x', 'x') or die('Not Connecting'); mysql_select_db('x') or die ('No Database Selected'); $task = $_REQUEST['taskid']; $uid = $_SESSION['user_id']; $q = "SELECT task_id, taskname FROM tasks WHERE task_id=" .$task. " LIMIT 1"; $gettask = mysql_fetch_assoc(mysql_query($q)); $q = "INSERT INTO user_tasks (ut_id, user_id, task_id, taskstatus, taskactive) VALUES (null, " .$uid. ", '{$gettask['task_id']}', 0, 1)"; $puttask = mysql_fetch_assoc(mysql_query($q)); $json = array( "name" => $gettask['taskname'] ); $output = json_encode($json); echo $output; Let me know if you have any questions or comments, thanks.

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• Displaying name instead of ID PHP MySQL

  - by Derek

  Hi, I need something simple; I have page where a user clicks an author to see the books associated with that author. On my page displaying the list of books for the author, I want a simple HTML title saying: 'The books for: AUTHORNAME' I can get the page to display author ID but not the name. When the user clicks the link in the previous page of the author, it looks likes this: <a href="viewauthorbooks.php?author_id=<?php echo $row['author_id']?>"><?php echo $row['authorname']?></a> And then on the 'viewauthorbooks.php?author_id=23' I have declared this at the start: $author_id = $_GET['author_id']; $authorname = $_GET['authorname']; And finally, 'The books for: AUTHORNAME, where it says AUTHORNAME, I have this: echo $authorname (With PHP tags, buts its not letting me put them in!) And this doesnt show anything, however if I change it to author_id, it displays the correct author ID that has been clicked, but its not exactly user friendly!! Can anyone help me out!

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• Best database (mysql) structure for this case:

  - by robert

  we have three types of data (tables): Book (id,name,author...) ( about 3 million of rows) Category (id,name) ( about 2000 rows) Location (id,name) ( about 10000 rows) A Book must have at least 1 type of Category (up to 3) AND a Book must have only one Location. I need to correlate this data to get this query faster: Select Books where Category = 'cat_id' AND Location = 'loc_id' Select Books where match(name) against ('name of book') AND Location = 'loc_id' Please I need some help. Thanks

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• How to sanitize this particular mysql query ?

  - by justjoe

  i got this SQL query where post_title taken from $_GET $sql = "SELECT ID FROM $wpdb-posts WHERE $wpdb-posts.post_title = '5-desain-web-colourful'"; What is the best way to sanitize this and make it more safe ?

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• formatting mysql data for ouptut into a table

  - by bsandrabr

  Following on from a question earlier today this answer was given to read the data into an array and separate it to print vehicle type and then some data for each vehicle. <?php $sql = "SELECT * FROM apparatus ORDER BY vehicleType"; $getSQL = mysql_query($sql); // transform the result set: $data = array(); while ($row = mysql_fetch_assoc($getSQL)) { $data[$row['vehicleType']][] = $row; } ?> <?php foreach ($data as $type => $rows): ?> <h2><?php echo $type?></h2> <ul> <?php foreach ($rows as $vehicleData):?> <li><?php echo $vehicleData['name'];?></li> <?php endforeach ?> </ul> <?php endforeach ?> This is almost perfect for what I want to do but I need to print out two columns from the database ie ford and mondeo before going into the second foreach loop. I've tried print $rows['model'] and all the other combinations I can think of but that doesn't work. Any help much appreciated

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• Help with PHP MySQL join

  - by kester martinez

  Please help me to understand proper join syntax. I have table named inventory which has: trans_id trans_items items -> item_id trans_user employees -> person_id trans_date trans_comment trans_inventory As you can see above, trans_items is a foreign key in items table, and trans_user is a foreign key in employees table. Now what I want to do is to display in HTML the inventory table, but instead of displaying the item id, I want the ITEM NAME to be displayed. Here is what I have done. Please note I'm using CodeIgniter. public function getData(array $inputs) { $this->db->select('trans_items, trans_user, trans_date, trans_inventory, trans_comment'); $this->db->from('inventory'); $this->db->order_by('trans_date desc'); return $this->db->get()->result_array(); }

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• how to confine to write a string in specific list ,on google-app-engine

  - by zjm1126

  class FirstModel(db.Model): p = db.StringProperty({option:['aa','bb','cc']}) the error is : NameError: name 'option' is not defined what should i do ,thanks

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• Using LIKE in MySQL SELECT fields

  - by Kristopher Ives

  I've been trying to select the status of doing a LIKE comparison: SELECT (`my_column` LIKE '%thepattern'%) AS `did_match` Thanks!

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