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  • MySQL update query, how to skip empty values?

    - by Pawel
    I've got such query: $sql = "UPDATE test_accs SET acc_owner = '$owner_id', acc_policy_version = '$version', acc_policy_last_update = '$approved', acc_policy_next_update = '$renewed' WHERE acc_id = '1'"; Now, all of these values on the web folmular are optional, one can set one of these values, two, or so. Now, after I submit the form, it goes in the query like that: UPDATE test_accs SET acc_owner = '2', acc_policy_version = '1.2', acc_policy_last_update = '2012-12-19', acc_policy_next_update = '2012-12-18' WHERE acc_id = '1' It works only when I submit all values from the form. Can you please show me how could it work even if not all the values has been sent, just for example one of them? When I set one value (f.ex. policy version), it looks like that: UPDATE test_accs SET acc_owner = '', acc_policy_version = '1.2', acc_policy_last_update = '', acc_policy_next_update = '' WHERE acc_id = '1' and it isn't working. It might be possible cause of the acc_owner table values? #1366 - Incorrect integer value: '' for column 'acc_owner' at row 1 Thanks in advice.

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  • Definition of domains in mySQL?

    - by mal
    I'm working on a college exercise and have the following question: What is the domain of the "country" table? My understanding of domain is that it defines the possible values of an attribute. This means that the table "country" doesn't have a domain, but the various attributes in the table "country" have their own domains. For example the attribute "SurfaceArea" has the domain FLOAT(10,2) and the attribute "Name" has the domain CHAR(52). Is this correct?

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  • Preventing entire JOINed MYSQL query from failing when one field is missing within a WHERE clause

    - by filip o
    I am doing a couple of joins with a variable in the WHERE clause. I'm not sure if I am doing everything as efficiently as I could, or even using the best practices but my issue is that half my tables have data for when tableC.type=500, and the other half don't resulting in the entire query failing. SELECT tableA.value1 , tableB.value2, tableC.value3 FROM tableA JOIN tableB ON tableB.id=tableA.id JOIN tableC ON tableC.id=tableB.id WHERE tableA.category=$var && tableC.type=500; What I would like to happen is to still get tableA.value1 and tableB.value2 even if there is no field in tableC with a type=500. any thoughts? i'm totally stumped as how to approach this...

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  • MySQL: Use CASE/ELSE value as join parameter

    - by DRJ
    I'm trying to join the NAME and PHOTO from USERS table to the TRANSACTIONS table based on who is the payer or payee. It keeps telling me can't find the table this -- What am I doing wrong? SELECT name,photo,amount,comment, ( CASE payer_id WHEN 72823 THEN payee_id ELSE payer_id END ) AS this FROM transactions RIGHT JOIN users ON (users.id=this) WHERE payee_id=72823 OR payer_id=72823

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  • mysql query to concat information from 3 tables - getting incorrect result count

    - by iPfaffy
    I have 3 tables in my database. ab_contacts id first_name last_name addressbook_id ab_addressbooks name id co_comments id link_id comment I'd like to create a query that will let me select all the contacts and comments related to them in a given addressbook. To select all the people in a given addressbook, I can use: select count(*) from ab_contacts where addressbook_id = '50'; This returns 8152 people. However, when I run my query: select ab_contacts.first_name, ab_contacts.last_name, ab_contacts.email, ab_addressbooks.name, co_comments.comments from ab_contacts JOIN ab_addressbooks ON (ab_contacts.addressbook_id = ab_addressbooks.id) JOIN co_comments ON (ab_contacts.id = co_comments.link_id) WHERE ab_contacts.addressbook_id = '50';` the format works, but I only get 1045 results. I'm sure there is something I am missing, but I cannot figure it out. Any help would be greatly appreciated.

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  • MySQL: Update table column from subquery result

    - by Jhourlad Estrella
    On the Members table are columns "MemberID" and "PointsEarned". I want to update the PointsEarned column from the result of this query: SELECT m.MemberID, m.UserName, ( (SELECT COUNT(*) FROM EventsLog as e WHERE e.MemberID=m.MemberID AND e.EventsTypeID=2)*10 ) + ( (SELECT COUNT(*) FROM EventsLog as e WHERE e.MemberID=m.MemberID AND e.EventsTypeID=3)*3 ) + ( (SELECT COUNT(*) FROM ChatMessages as c WHERE c.MemberID=m.MemberID)*.1 ) as PointsEarned FROM Members as m Can anybody tell me how I should do it with a single query? Thanks!

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  • Casting a Calculated Column in a MySQL view.

    - by Chris Brent
    I have a view that contains a calculated column. Is there are a way to cast it as a CHAR or VARCHAR rather than a VARBINARY ? Obviously, I have tried using CAST(... as CHAR) but it gives an error. Here is a simple replicable example. CREATE VIEW view_example AS SELECT concat_ws('_', lpad(9, 3,'0'), lpad(1,3,'0'), date_format(now(),'%Y%m%d%H%i%S')) AS calculated_field_id; This is how my view is created: describe view_example; +---------------------+---------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +---------------------+---------------+------+-----+---------+-------+ | calculated_field_id | varbinary(27) | YES | | NULL | | +---------------------+---------------+------+-----+---------+-------+ select version(); +-----------------------+ | version() | +-----------------------+ | 5.0.51a-community-log | +-----------------------+

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  • Can't connect to MySQL database hosted in CloudBees

    - by user3692698
    I have a free CloudBees account and created a free ClearDB database using their wizards. My trouble is when I use their connection information (whether I try to connect from my Java app, or an outside tool - SQLyog to be exact) I take the error: Access denied for user 'b51dbc5757d79f'@'%' to database 'mywiki. The username provided by CloudBees does not contain those extra characters that the error message is displaying which seems like it would be a problem, but I'm not sure there is anything I can do about that since everything is configured for me. The username I am given is: b51dbc5757d79f - which I can delete and rebuild after sharing here :)

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  • Calling a Function Based on a String Which Contains the Function Name

    - by Phonethics
    var foo1,foo2; switch (fn) { case "fade" : foo1 = "fadeOut"; foo2 = "fadeIn"; break; case "slide" : foo1 = "slideUp"; foo2 = "slideDown"; break; } eval("$('.cls1')." + foo1 + "();"); currentSlideIndex = currentSlideIndex + n; eval("$('.cls1')." + foo2 + "();"); Any better way to achieve this without using eval ? Im not a very big fan of using eval unless absolutely necessary.

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  • mysql joining three specific tables

    - by sam lim
    Here what i would like to pull date from this three table. Table users i have three columns uid, username , data(text) Table users_order i have three columns uid, orders_id , users_email Table order_products i have three columns orders_id, product_id, product_name I would like to use product_id as the ref/search to pull the user info from those three tables. If product_id = 5 The query will display uid; username; users_email; orders_id; product_name; data (text) how would i right the sql query for this situation. Thanks,

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  • PHP - MySQL - Select runs indefinitely

    - by John
    I have three tables listings: id, pid, beds, baths, etc, etc, etc, db locations: id, pid, zip, lat, lon, etc, etc, etc, db images id, pid, height, width, raw, etc, etc, db id, pid & db are indexed. db just references the mls provider a particular item came from. in images the raw column holds raw image data there are about 15k rows in listings/locations, and about 120k rows in images so there are multiple rows that have the same pid. when i do "select pid from listings" or "select pid from locations" the query completes successfully in about 100ms. when i do "select pid from images" it just hangs in sqlyog and never completes... i was thinking since the raw column contains alot of information that it might be trying to select that too, but my query doesn't try to select that so I can't imagine why it's taking so long... any idea why this is happening??

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  • I need to cut a portion of a string in linux

    - by Abeed Salam
    I have a file in a folder like this: installer-x86_64-XXX.XX-diagnostic.run The XXX.XX is a version number and I need the version number only. How to do it in linux? I have this code: #!/bin/bash current_ver=$(find /mnt/builds/current -name '*.run'|awk -F/ '{print $NF}') So this gives me just the name of the file correctly (minus the location, which I dont want). But how do I only get the XXX.XX version number into a variable such as $version

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  • MySQL Queries using Doctrine & CodeIgniter

    - by 01010011
    Hi, How do I write plane SQL queries using Doctrine connection object and display the results? For example, how do I perform: SELECT * FROM table_name WHERE column_name LIKE '%anything_similar_to_this%'; using Doctrine something like this (this example does not work) $search_key = 'search_for_this'; $conn = Doctrine_Manager::connection(); $conn->execute('SELECT * FROM table_name WHERE column_name LIKE ?)', $search_key); echo $conn;

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  • MySql Alter Syntax error with mulitple FK

    - by acidzombie24
    If i do the first one i have no problem. When i do addition i get a syntax error. What is wrong with the syntax? The error says syntax error near [entire 2nd line] alter table `ban_Status` add FOREIGN KEY (`banned_user`) REFERENCES `user_data`(`id`) alter table `ban_Status` add FOREIGN KEY (`banned_user`) REFERENCES `user_data`(`id`), FOREIGN KEY (`banning_user`) REFERENCES `user_data`(`id`), FOREIGN KEY (`unban_user`) REFERENCES `user_data`(`id`)

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  • Mysql query question

    - by brux
    I have 2 tables: Customer: customerid - int, pri-key,auto fname - varchar sname -varchar housenum - varchar street -varchar Items: itemid - int,pri-key,auto type - varchar collectiondate - date releasedate - date customerid - int I need a query which will get me all items that have a releasedate 3 days prior to (and including) the current date. i.e The query should return customerid,fname,sname,street,housenum,type,releasedate for all items which have releasedate within (and including)3 days prior today thanks in advance

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  • counting sub rows in mysql

    - by moustafa
    i have 2 table ok catgories and artilces i have this structure catgories web > design > photoshop > layers web > design > photoshop > effects and each one is a catgory and layers catgories has 100 article and effects catgories has 50 article now i want when count the articles 'web' catgory it show 150 article how i can do this give me an example

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  • How to insert form data into MySQL database table

    - by Richard
    So I have this registration script: The HTML: <form action="register.php" method="POST"> <label>Username:</label> <input type="text" name="username" /><br /> <label>Password:</label> <input type="text" name="password" /><br /> <label>Gender:</label> <select name="gender"> <optgroup label="genderset"> <option value="Male">Male</option> <option value="Female">Female</option> <option value="Hermaphrodite">Hermaphrodite</option> <option value="Not Sure!!!">Not Sure!!!</option> </optgroup> </select><br /> <input type="submit" value="Register" /> </form> The PHP/SQL: <?php $username = $_POST['username']; $password = $_POST['password']; $gender = $_POST['gender']; mysql_query("INSERT INTO registration_info (username, password, gender) VALUES ('$username', '$password', '$gender') ") ?> The problem is, the username and password gets inserted into the "registration_info" table just fine. But the Gender input from the select drop down menu doesn't. Can some one tell me how to fix this, thanks.

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  • mySQL query not returning correct results!

    - by Pete Herbert Penito
    Hi! This query that I have is returning therapists whose 'therapistTable.activated' is equal to false as well as those set to true! so it's basically selecting all of the db, any advice would be appreciated! ` $query = "SELECT therapistTable.* FROM therapistTable WHERE therapistTable.activated = 'true' ORDER BY therapistTable.distance "; `

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  • Removing the last character of a string IF it is $variable

    - by KeenLearner
    Hi there, I've made a little script to convert titles into url friendly things. ie: 'I am a title' becomes 'I_am_a_title' My script basically goes through and turns spaces, apostrophes, commas etc etc into an underscore. The problem is, sometimes my url's end up like this: 'i_am_a_title_' with a trailing underscore... So i figure, add a little bit to go through and search to see if the last character is an underscore on the final result, and if it is, then swap it. I looked into the strrchr() function but I seem to be hitting a wall of my own understanding. How is this sort of thing accomplished?

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  • Average of a Sum in Mysql query

    - by chupeman
    I am having some problems creating a query that gives me the average of a sum. I read a few examples here in stackoverflow and couldn't do it. Can anyone help me to understand how to do this please? This is the data I have: Basically I need the average transaction value by cashier. I can't run a basic avg because it will take all rows but each transaction can have multiple rows. At the end I want to have: Cashier| Average| 131 | 44.31 |(Which comes from the sum divided by 3 transactions not 5 rows) 130 | 33.15 | etc. This is the query I have to SUM the transactions but don't know how or where to include the AVG function. SELECT `products`.`Transaction_x0020_Number`, Sum(`products`.`Sales_x0020_Value`) AS `SUM of Sales_x0020_Value`, `products`.`Cashier` FROM `products` GROUP BY `products`.`Transaction_x0020_Number`, `products`.`Date`, `products`.`Cashier` HAVING (`products`.`Date` ={d'2010-06-04'}) Any help is appreciated.

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  • How to output items in Order in MySQL?

    - by RailsRor
    I have a column called "menu_order" which has no default value. When I select the contents of this column using the following select statement: SELECT * FROM categories ORDER BY menu_order ASC It lists the category items that have nothing as their menu order first and then the one's that have 1's and 2's and 3's. Is there any way to prevent SQL from take nothing to come before numbers when I am trying to list things in order? So for example, if I have: cat_name | menu_order ---------------------- Lunch | 1 Dinner | And I perform my query, the output should be: Lunch Dinner Not: Dinner Lunch

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