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  • refresh user control inside multiview

    - by daisy
    In my parentpage I have dropdownlist, multiview and button. Multiview has a user control. On click of the button i pass the selected value from dropdown to the user control and call the databind method to populate the user control with corresponding data. User control has gridview which is populated using objectDataSource. I'm using the ObjectCreating (ObjectDataSource) to set the objectInstance. 1st time everything works fine. But when the dropdown selection is changed and the button is clicked again then the user control does not refresh. What do I need to do so that the user control refreshed each time the drop down selection is changed. All the help is appreciated Thanks

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  • Winforms fixed single border on custom shaped control

    - by JD
    Hi all, I have created a custom control inheriting from a panel in .NET 3.5 The panel has a custom polygon border, which comes from a pointF array (In diagram, control is highlighted yellow). Fig 1 shows the control with BorderStyle none. Fig 2 with BorderStyle fixed-single As shown in Fig 2, the border follows the Rectangle bounding the control. IS there a way to make the border follow the actual border of the control set by the polygon? FYI the polygon is created using a GraphicsPath object. Drawing the line with GDI+ does not work, as the control clips the line and it looks awful... Fig1 Fig2

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  • Metro: Introduction to the WinJS ListView Control

    - by Stephen.Walther
    The goal of this blog entry is to provide a quick introduction to the ListView control – just the bare minimum that you need to know to start using the control. When building Metro style applications using JavaScript, the ListView control is the primary control that you use for displaying lists of items. For example, if you are building a product catalog app, then you can use the ListView control to display the list of products. The ListView control supports several advanced features that I plan to discuss in future blog entries. For example, you can group the items in a ListView, you can create master/details views with a ListView, and you can efficiently work with large sets of items with a ListView. In this blog entry, we’ll keep things simple and focus on displaying a list of products. There are three things that you need to do in order to display a list of items with a ListView: Create a data source Create an Item Template Declare the ListView Creating the ListView Data Source The first step is to create (or retrieve) the data that you want to display with the ListView. In most scenarios, you will want to bind a ListView to a WinJS.Binding.List object. The nice thing about the WinJS.Binding.List object is that it enables you to take a standard JavaScript array and convert the array into something that can be bound to the ListView. It doesn’t matter where the JavaScript array comes from. It could be a static array that you declare or you could retrieve the array as the result of an Ajax call to a remote server. The following JavaScript file – named products.js – contains a list of products which can be bound to a ListView. (function () { "use strict"; var products = new WinJS.Binding.List([ { name: "Milk", price: 2.44 }, { name: "Oranges", price: 1.99 }, { name: "Wine", price: 8.55 }, { name: "Apples", price: 2.44 }, { name: "Steak", price: 1.99 }, { name: "Eggs", price: 2.44 }, { name: "Mushrooms", price: 1.99 }, { name: "Yogurt", price: 2.44 }, { name: "Soup", price: 1.99 }, { name: "Cereal", price: 2.44 }, { name: "Pepsi", price: 1.99 } ]); WinJS.Namespace.define("ListViewDemos", { products: products }); })(); The products variable represents a WinJS.Binding.List object. This object is initialized with a plain-old JavaScript array which represents an array of products. To avoid polluting the global namespace, the code above uses the module pattern and exposes the products using a namespace. The list of products is exposed to the world as ListViewDemos.products. To learn more about the module pattern and namespaces in WinJS, see my earlier blog entry: http://stephenwalther.com/blog/archive/2012/02/22/metro-namespaces-and-modules.aspx Creating the ListView Item Template The ListView control does not know how to render anything. It doesn’t know how you want each list item to appear. To get the ListView control to render something useful, you must create an Item Template. Here’s what our template for rendering an individual product looks like: <div id="productTemplate" data-win-control="WinJS.Binding.Template"> <div class="product"> <span data-win-bind="innerText:name"></span> <span data-win-bind="innerText:price"></span> </div> </div> This template displays the product name and price from the data source. Normally, you will declare your template in the same file as you declare the ListView control. In our case, both the template and ListView are declared in the default.html file. To learn more about templates, see my earlier blog entry: http://stephenwalther.com/blog/archive/2012/02/27/metro-using-templates.aspx Declaring the ListView The final step is to declare the ListView control in a page. Here’s the markup for declaring a ListView: <div data-win-control="WinJS.UI.ListView" data-win-options="{ itemDataSource:ListViewDemos.products.dataSource, itemTemplate:select('#productTemplate') }"> </div> You declare a ListView by adding the data-win-control to an HTML DIV tag. The data-win-options attribute is used to set two properties of the ListView. The ListView is associated with its data source with the itemDataSource property. Notice that the data source is ListViewDemos.products.dataSource and not just ListViewDemos.products. You need to associate the ListView with the dataSoure property. The ListView is associated with its item template with the help of the itemTemplate property. The ID of the item template — #productTemplate – is used to select the template from the page. Here’s what the complete version of the default.html page looks like: <!DOCTYPE html> <html> <head> <meta charset="utf-8"> <title>ListViewDemos</title> <!-- WinJS references --> <link href="//Microsoft.WinJS.0.6/css/ui-dark.css" rel="stylesheet"> <script src="//Microsoft.WinJS.0.6/js/base.js"></script> <script src="//Microsoft.WinJS.0.6/js/ui.js"></script> <!-- ListViewDemos references --> <link href="/css/default.css" rel="stylesheet"> <script src="/js/default.js"></script> <script src="/js/products.js" type="text/javascript"></script> <style type="text/css"> .product { width: 200px; height: 100px; border: white solid 1px; } </style> </head> <body> <div id="productTemplate" data-win-control="WinJS.Binding.Template"> <div class="product"> <span data-win-bind="innerText:name"></span> <span data-win-bind="innerText:price"></span> </div> </div> <div data-win-control="WinJS.UI.ListView" data-win-options="{ itemDataSource:ListViewDemos.products.dataSource, itemTemplate:select('#productTemplate') }"> </div> </body> </html> Notice that the page above includes a reference to the products.js file: <script src=”/js/products.js” type=”text/javascript”></script> The page above also contains a Template control which contains the ListView item template. Finally, the page includes the declaration of the ListView control. Summary The goal of this blog entry was to describe the minimal set of steps which you must complete to use the WinJS ListView control to display a simple list of items. You learned how to create a data source, declare an item template, and declare a ListView control.

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  • What is a good toy example to teach version control?

    - by janos
    I am looking for practical examples to use when teaching version control. Breaking down the material to basic concepts and providing examples is an obvious way to teach version control, but this can be very boring, unless the examples are really practical or interesting. One idea I have is customizing a wordpress theme. I use wordpress a lot and no theme is ever perfect, so I typically just put the theme directory in version control using any dvcs and start recording changes. The problem with this example is that not many people in the audience may be familiar with wordpress, let alone have shell access to a wordpress site to try out the commands. Preparing a mock site and giving access to everyone is also not an option for me. I need a "toy example" that can be interesting to a broad audience of software developers, and something they can try on their own computers. The tutorial will use a dvcs, but the practical example I'm looking for is only to teach the basic features of version control, ignoring the distributed features for the moment. (Now that I think of it, instead of a mock site, a customized live cd might do the trick...) Any better ideas?

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  • Control Panel for MySQL and PostgreSQL server

    - by jfreak53
    I am looking for a control panel for a CentOS system that will allow me to add user's that can control their "own" MySQL and PostgreSQL Databases. I don't want to have to spend the $25 a month for cpanel on a dedicated to do this. Plus cPanel comes with all the rest like webserver and email that I don't need these to have. Basically I want to be able to create users that can create their own databases and only see those that they have created. I want to be able to control their disk space as with most panels. They need to be able to create their own DB users as well. Kloxo won't work as it doesn't natively support PostgreSQL. I tried straight PHPMyAdmin, but it won't let the user's create their own DB's unless they can also see everyone else's. VirtualMin I just can't get to work at all! ha ha I installed it an though it works great for itself if a user signs into Usermin they can see all DB's. If they sign into PHPMyAdmin (which basically means any program that directly connects to MySQL) they see all DB's. If they login to virtualmin then yes, they only see their's. But that won't work. I can't seem to think of another way to do this. I can use webmin and usermin directly but PHPMyAdmin again let's the user's I create either see only one DB and create none, or see all DB's. So that sound's like a permission problem in MySQL and PostgreSQL.

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  • Should I enabled 802.3x hardware flow control?

    - by Stu Thompson
    What is the conventional wisdom regarding 802.3x flow control? I'm setting up a network at a new colo and am wondering if I should be enabling it or not. My oh-cool-a-bright-and-shiny-new-toy self wants to enable it, but this seems like one of those decisions that could blow up in my face later on. My network: An HP ProCurve 2510G-24 switch A pair of Debian 5 HP DL380 G5's with built-in NC373i 2-port NIC LACP'd as one link. 9000 jumbo frames enabled. (Application) A pair of hand-built Ubuntu server with 4-port Intel Pro/1000 LACP'd as one link. 9000 jumbo frames enabled. (NAS) A few other servers with with single 1Gbps ports, but one with 100Mbps. Most of this kit is 802.3x. I've been enabling it as I go along, and am about to test the network. But as my 'go live' day nears, I am worried about the 802.3x decision as I've never explicitly used it before. Also, I've read some 10-year old articles out there on the Intertubes that warn against using flow control. Should I be enabling 802.3x hardware flow control?

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  • Is there an Easier way to Get a 3 deep Panel Control from a Form in order to add a new Control to it programmatically?

    - by Mark Sweetman
    I have a VB Windows Program Created by someone else, it was programmed so that anyone could Add to the functionality of the program through the use of Class Libraries, the Program calls them (ie... the Class Libraries, DLL files) Plugins, The Plugin I am creating is a C# Class Library. ie.. .dll This specific Plugin Im working on Adds a Simple DateTime Clock Function in the form of a Label and inserts it into a Panel that is 3 Deep. The Code I have I have tested and it works. My Question is this: Is there a better way to do it? for instance I use Controls.Find 3 different times, each time I know what Panel I am looking for and there will only be a single Panel added to the Control[] array. So again Im doing a foreach on an array that only holds a single element 3 different times. Now like I said the code works and does as I expected it to. It just seems overly redudant, and Im wondering if there could be a performance issue. here is the code: foreach (Control p0 in mDesigner.Controls) if (p0.Name == "Panel1") { Control panel1 = (Control)p0; Control[] controls = panel1.Controls.Find("Panel2", true); foreach (Control p1 in controls) if (p1.Name == "Panel2") { Control panel2 = (Control)p1; Control[] controls1 = panel2.Controls.Find("Panel3", true); foreach(Control p2 in controls1) if (p2.Name == "Panel3") { Control panel3 = (Control)p2; panel3.Controls.Add(clock); } } }

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  • What reasons are there for not using a third party version control service?

    - by Earlz
    I've recently noticed a bit of a trend for my projects as of late. I use to run my own SVN server on my VPS, but recently the nail went in the coffin for that when I got my last project migrated from my server to a Mercurial repo on Bitbucket. What are some of the ramifications to this? (disregarding the change in version control systems) It seems like there has been a huge explosion in version control hosting, and companies like Bitbucket even offer private repos for free, and Github and other such services are extremely cheap now. Also, by using them you get the benefit of their infrastructure's speed and stability. What reasons are there these days to host your own version control? The only real reason I can think of is if your source code is super top secret.

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  • Add login / logout to drupal menu that's not a primary or secondary menu

    - by user367766
    Hello, Im trying to append an item to a menu that I created. I know its get the primary and secondary menus using "menu_secondary_local_tasks()" etc, and then add items within preprocess page. How would I go about this with a menu that I created? Here is the code I am using to check is the user is logged in... function themeName_check_login() { global $user; if ($user->uid) { print l("Log out, " . $user->name,"logout"); } else { print l("Log In ","user"); } } Thanks in advance, -Matt

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  • ASP.NET MVC Login ReturnUrl always NULL?

    - by aherrick
    Using Forms Authentication in ASP.NET MVC when trying to log back into a site, it puts a ReturnUrl parameter in the query string. My Logon action method accepts a "returnUrl" string. However it seems that returnUrl string is always null, even when it is clearly in the query string. Any thoughts on why this might be the case or a possible fix?

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  • Windows Login Integration

    - by Dusty Roberts
    Hi Peeps. I am building facial recognition software for a certain purpose, however, as a spin-off i would like to use that same software / concept, to automatically recognize me when i sit in front of the PC, and log me in. recognition is handled.. however, i need to incorporate this into windows, the same way fingerprint logins work. where can i go to get some more info on the doing this?

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  • Login Script for PostGreSQL and PHP not working =[

    - by MrEnder
    Ok I'm quite new at logins what not so bare with me here lol but I gota learn so don't discourage me. I tried this so far <?php $error = ""; $conn = pg_connect("host=localhost dbname=brittains_db user=brittains password=XXXX" ); $sql = "SELECT * FROM logins"; $result = pg_query($conn, $sql); if($_SERVER["REQUEST_METHOD"] == "GET") { $userName=""; $password=""; } else if($_SERVER["REQUEST_METHOD"] == "POST") { $userName=trim($_POST["userNameLogin"]); $password=trim($_POST["passwordLogin"]); if(pg_fetch_result($results, $userName, "userName")==true && pg_fetch_result($results, $password, "userName")==true) { setcookie("userIDforDV", $userName, time()+43200); } else { $error = "Your username and or password is incorrect"; } } $userName = $_COOKIE['userIDforDV']; if(isset($userName) && $userName!="") { echo "Welcome " . $userName; } echo $error; ?> <form> <table> <tr> <td class="signupTd"> User Name:&nbsp; </td> <td> <input type="text" name="userNameLogin" value="" size="20" /> </td> </tr> <tr> <td class="signupTd"> Password:&nbsp; </td> <td> <input type="password" name="passwordLogin" value="" size="20" /> </td> </tr> <tr> <td class="signupTd" colspan="2"> <input type="submit" name="submit" value="Submit"/> </td> </tr> </table> </form> that was the idea I came up with... but its prolly a really bad idea and it doesn't work... how might I go about this properly? I need really detailed descriptions please. Thanks a tun Shelby

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  • Making a login Using JavaScript, Will Incorporate PHP Later

    - by TIMOTHY
    not sure why my code wont work, im teaching myself javascript i know php moderatly and i also know the intelligence of using java to hold a password and username, but at the moment i just want the script to work. <html> <head> <title>34webs</title> <link rel="stylesheet" href="css/lightbox.css" type="text/css" media="screen" /> <link rel="stylesheet" type="text/css" media="screen" href="main.css"> <script type="text/javascript" src="js/prototype.js"></script> <script type="text/javascript" src="js/scriptaculous.js?load=effects,builder"></script> <script type="text/javascript" src="js/lightbox.js"></script> <script type="javascript" > function logintry (){ var usern = document.logn.username.value; var passw = document.logn.password.value; if(usern == blue && passw == bluee){ alert('password is correct!'); }else{ alert('password is wrong'); } } </script> </head> <body> <div id="bod"> <div id="nav"> <p id="buttonhead">34 web</p> <a href="#" class="button">HOME</a> <a href="#" class="button">NEWS</a> <a href="#" class="button">DOWNLOADS</a> <a href="#" class="button">ERA</a> <a href="#" class="button">IE BROWSER</a> <a href="#" class="button">DRIVERS</a> <form name="logn"> <table style="margin:0 auto; background:#0174DF; color:white;"> <tr> <td> Username<br> <input type="text" name="username" value=""> </td> </tr> <tr> <td> Password<br> <input type="password" name="password" value=""> </td> </tr> <tr> <td style="text-align:center;"> <input type="button" name="Submit" value="submit" onclick= javascript: logintry()> </td> </tr> </table> </form> </div>

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  • Login problem with php

    - by shinod
    I want to prevent multiple log in with same log in credentials simultaneously. So I made a column login_status and set it to 1 when some one logging in and change to 0 when logging out besides I set session after successful logged in. If user won't click on log out(in case of user close tab or because of some network problem) it doesn't update database and then one can't use that log in credentials again. So I use a ajax call to set current time stamp in database with related log in credentials and it is updated in each 2 minutes if user not navigate from that page. Then if some one attempts to log in with same log in credentials, it will check these time stamp if column login_status is 1, then if the time stamp is older than 3 minutes it allows the log in.Then it solving that problem. But the new problem is if user closes the tab or browser window and after 3 minutes one can log in with same log in credentials from somewhere and if the previous user open that page automatically it will log in as session is already set. How can I prevent this.

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  • using a stored procedure for login in c#

    - by Jin Yim
    Hi all, If I run a store procedure with two parameter values (admin, admin) (parameters : admin, admin) I get the following message : Session_UID User_Group_Name Sys_User_Name NULLAdministratorsNTMSAdmin No rows affected. (1 row(s) returned) @RETURN_VALUE = 0 Finished running [dbo].[p_SYS_Login]. -- To get the same message in c# I used the code following : string strConnection = Settings.Default.ConnectionString; using (SqlConnection conn = new SqlConnection(strConnection)) { using (SqlCommand cmd = new SqlCommand()) { SqlDataReader rdr = null; cmd.Connection = conn; cmd.CommandText = "p_SYS_Login"; cmd.CommandType = CommandType.StoredProcedure; SqlParameter paramReturnValue = new SqlParameter(); paramReturnValue.ParameterName = "@RETURN_VALUE"; paramReturnValue.SqlDbType = SqlDbType.Int; paramReturnValue.SourceColumn = null; paramReturnValue.Direction = ParameterDirection.ReturnValue; cmd.Parameters.Add(paramReturnValue); cmd.Parameters.Add(paramGroupName); cmd.Parameters.Add(paramUserName); cmd.Parameters.AddWithValue("@Sys_Login", "admin"); cmd.Parameters.AddWithValue("@Sys_Password", "admin"); try { conn.Open(); rdr = cmd.ExecuteReader(); string test = (string)cmd.Parameters["@RETURN_VALUE"].Value; while (rdr.Read()) { Console.WriteLine("test : " + rdr[0]); } } catch (Exception ex) { string message = ex.Message; string caption = "MAVIS Exception"; MessageBoxButtons buttons = MessageBoxButtons.OK; MessageBox.Show( message, caption, buttons, MessageBoxIcon.Warning, MessageBoxDefaultButton.Button1); } finally { cmd.Dispose(); conn.Close(); } } } but I get nothing in SqlDataReader rdr ; is there something I am missing ? Thanks

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  • Login Problem Windows Authentication

    - by user109280
    Duplicate of: http://stackoverflow.com/questions/881928/windows-authentication-trusted-connection-problem I logged in the Windows Server(Machine 1) as "abc\user1 ". Windows Server machine is in abc domain. MSSQL Server is in the "abc" domain on Machine 1 and have mixed mode.authentication. It has account "abc\user1 " and "abc\user2 ". Both has role of sysadmin and serveradmin. I logged in another machine(Machine 2) using "abc\user2 ". Same Domain. Run the ant which connect to MSSQL Server. URL is formed as follows. jdbc:sqlserver://%DB_IP%:%DB_PORT%;SelectMethod=cursor;integratedSecurity=true;DatabaseName=dbname; 1) From Machine 2, If I use "abc\user2" credential for connection, then it works fine. since integratedSecurity=true. 2) From Machine 2, If I use "abc\user1" credential for connection, then it doesn't fine, since integratedSecurity=true and take System Credentials i.e "abc\user2". Even if I make integratedSecurity=false , then also it doesn't connect using "abc\user1" What changes to URL I have make to work for "abc\user1" from Machine2 for connection. what properties to be added in url? OR Driver doesn't support to use another domain\User Credentials? What need to set on MSSQL Server ?? Deepak

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  • REST client website login

    - by Jordan
    I have written a REST service that uses WSSE as an authentication method but i want to be able to use this rest service through a browser by creating a website around the service. I want the user to be able to log in on the website then when they view, for example the "view users" page an ajax request is made to test.com/users and back comes the list. The part i'm trying to get my head around is the logging in/out on the website and keeping the user logged in across pages. Since in a true REST implementation there's no state held on the server, i can't use $_SESSION and now i don't know where to start! What is the best way to go about this? Do i still need to store session information on the server then possibly use cURL to make the request? Thanks Jay

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  • How do I get Facebook Application Login to work

    - by Javaaaa
    I just started making an application for Facebook, however I ran into problem early on. The first step I want people to do is to give permission to access their profile. All over the web are examples of how to do this with: $user_id = $facebook->require_login(); However, this is the way it works using the Old PHP API. I have downloaded and installed the new one in my application folder and it is not working anymore. My question is (and i really have been searching for an answer for a long time) what is the code to do this with the new API? (and related question: is it better to use the old API, or learn to work with the new one when I am just starting making apps right now) I have this code now; <?php // Awesome Facebook Application // // Name: - // require_once 'facebook-php-sdk/src/facebook.php'; // Create our Application instance. $facebook = new Facebook(array( 'appId' => $app_id, 'secret' => $app_secret, 'cookie' => true )); $loginUrl = $facebook->getLoginUrl(array( 'req_perms' => 'email,user_birthday,publish_stream,sms,status_update,user_location' )); echo "<p>hello, <fb:name uid=\"$user_id\" useyou=\"false\" />!</p>"; ?>

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  • Searching for the right pattern to handle login data

    - by stevebot
    Hi all, I'm working on a controller that handles logins for a Web app. These logins will come from multiple clients but will all contain the same data. However, depending on the client, this data will be interpreted into common entities for our webapp differently. For instance, we have a user code that gets sent in, and in one case we may use the first four digits of the code, and in another case 12 digits of the code to map to a field on a User entity. Instead of handling this all in the controller and having big nasty if blocks of logic, I would like to use a pattern to handle how this information gets ingested into our application. What are your opinions?

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  • Link Button on asp.net user control not firing

    - by andyriome
    Hi I have a user control, which is added to another user control. The nested user control is built up of a gridview, an image button and a link button. The nested user control is added to the outer control as a collection object based upon the results bound to the gridview. The problem that I have is that my link button doesn't work. I click on it and the event doesn't fire. Even adding a break point was not reached. As the nested user control is added a number of times, I have set image button to have unique ids and also the link button. Whilst image button works correctly with its java script. The link button needs to fire an event in the code behind, but despite all my efforts, I can't make it work. I am adding the link button to the control dynamically. Below is the relevant code that I am using: public partial class ucCustomerDetails : System.Web.UI.UserControl { protected override void CreateChildControls( ) { base.CreateChildControls( ); string strUniqueID = lnkShowAllCust.UniqueID; strUniqueID = strUniqueID.Replace('$','_'); this.lnkShowAllCust.ID = strUniqueID; this.lnkShowAllCust.Click += new EventHandler(this.lnkShowAllCust_Click); this.Controls.Add(lnkShowAllCust); } protected override void OnInit (EventArgs e) { CreateChildControls( ); base.OnInit(e); } protected override void OnLoad(EventArgs e) { base.EnsureChildControls( ); } protected void Page_Load(object sender, EventArgs e) { if (IsPostBack) { CreateChildControls( ); } } protected void lnkShowAllCust_Click(object sender, EventArgs e) { this.OnCustShowAllClicked(new EventArgs ( )); } protected virtual void OnCustShowAllClicked(EventArgs args) { if (this.ViewAllClicked != null) { this.ViewAllClicked(this, args); } } public event EventHandler ViewAllClicked; } I have been stuggling with this problem for the last 3 days and have had no success with it, and I really do need some help. Can anyone please help me?

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  • Creating a session user login php

    - by user2419393
    I'm stuck on how to create a session for a user who logs in. I got the part of checking to make sure the log in information corresponds with the database information, but is stuck on how to take the email address and store into a session. Here is my php code below. <?php include '../View/header.php'; session_start(); require('../model/database.php'); $email = $_POST['username']; $password = $_POST['password']; $sql = "SELECT emailAddress FROM customers WHERE emailAddress ='$email' AND password = '$password'"; $result = mysql_query($sql, $db); if (!$result) { echo "DB Error, could not query the database\n"; echo 'MySQL Error: ' . mysql_error(); exit; } while ($row = mysql_fetch_assoc($result)) { echo $row['emailAddress']; } mysql_free_result($result); ?>

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