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  • Twitter Trends API weekly.json causing error "Cannot use object of type stdClass as array"

    - by tucson
    I have the following PHP code: $ch = curl_init(); curl_setopt($ch, CURLOPT_URL,$URL); curl_setopt($ch, CURLOPT_RETURNTRANSFER,1); $result = curl_exec($ch); curl_close($ch); $obj = json_decode($result); foreach ($obj[0]->trends as $trend) echo utf8_decode($trend->name); which works fine for URL #1 (into the variable $URL): http://api.twitter.com/1/trends/1.json?exclude=hashtags but causes an error "Cannot use object of type stdClass as array" for URL #2: http://api.twitter.com/1/trends/weekly.json?exclude=hashtags I have searched for a while, but can't figure out a code to fix this and handle both URLs. Any help would be much appreciated.

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  • Problems with sticky footer html css

    - by CJava
    I'm having trouble making a sticky footer, whatever I do the code completely messes up and re-arranged positioning of other elements. I'm using multiple div elements. I have tried pretty much most tutorials on stickying footers online like http://www.cssstickyfooter.com/using-sticky-footer-code.html Help would be much appreciated. Thanks a lot! html: <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <meta name="generator" content="HTML Tidy for Linux (vers 25 March 2009), see www.w3.org"> <title>Southend-on-Sea Independant Tourist Guide</title> <!--Attached CSS to keep constant throughout site--> <link rel="stylesheet" type="text/css" href="style.css"> <meta http-equiv="content-type" content="text/html; charset=utf-8"> <meta name="description" content="An independant tourist guide on Southend-on-Sea"> <meta name="keywords" content="southend, southend-on-sea, tourist guide, tourist, independant"> <meta name="author" content="Callum Stevens"> <link rel="shortcut icon" type="image/x-icon" href="/favicon.ico"><!--[if !IE 7]> <style type="text/css"> #wrap {display:table;height:100%} </style> <![endif]--> <link rel="stylesheet" type="text/css" href="style.css"> <link rel="stylesheet" type="text/css" href="navigation.css"> </head> <body> <div id="container"> <div id="content"> <div id="header"> <table width="200" border="0" align="center" cellpadding="0" cellspacing="0"> <tr> <td><img src="southendpiersept2006edit.jpg" width="700" height="389" alt="southend pier site logo"></td> </tr> </table> </div> <div id="navigation"> <ul> <li class="home"><a href="index.htm">Home</a></li> <li class="places"><a href="places.htm">Places to go</a></li> <li class="things"><a href="things.htm">Things to do</a></li> <li class="where"><a href="where.htm">Where to stay</a></li> <li class="getting"><a href="getting.htm">Getting&lt; here/a&gt;</a></li> <li class="about"><a href="getting.htm"></a><a href="getting.htm"></a><a href="about.htm">About the town</a></li> <li class="contact"><a href="contact.htm">Contact us</a></li> </ul> <table width="700" border="0" align="center" cellpadding="0" cellspacing="0"> <tr> <td></td> </tr> </table> </div> <br> <br> <h1>Southend-On-Sea</h1> <br> <h2>Welcome to Southend-On-Sea Tourist Information Site. You're #1 stop for finding out about Southend!</h2> <br> <h3>This site aims to help you in getting here, finding accomodation, and letting you know whats going on.</h3> <p>paragraph</p> <p id="p2">paragraph2</p> </div> </div> <div id="footer"></div> </body> </html> style.css: html, body { margin: 0px; padding: 0px; text-align:center } body{ background: url(bg.jpg) repeat-x;} #content { text-align:center width:67%; } h2 { text-transform: capitalize;} navigation.css #navigation ul { width: 700px; height: 50px; position: absolute; /** Places image at the top of the page **/ top: 389px; /** Determines the height from the top of the page **/ left: 15.3%; /** Determines the width from the left of the page **/ background: url(menu.jpg) no-repeat 0 0; list-style: none; margin: 0; padding: 0; } #navigation li { display: inline; } #navigation li a:link, #navigation li a:visited { border: none; width: 100px; height: 50px; display: block; position: absolute; top: 0; text-indent: -7000px; outline: none; } #navigation li.home a:link, #navigation li.home a:visited { left: 0; } #navigation li.places a:link, #navigation li.places a:visited { left: 100px } #navigation li.things a:link, #navigation li.things a:visited { left: 200px } #navigation li.where a:link, #navigation li.where a:visited { left: 300px } #navigation li.getting a:link, #navigation li.getting a:visited { left: 400px } #navigation li.about a:link, #navigation li.about a:visited { left: 500px } #navigation li.contact a:link, #navigation li.contact a:visited { left: 600px } #navigation li.home a:hover { background: url(menu.jpg) no-repeat 0 -50px; } #navigation li.places a:hover { background: url(menu.jpg) no-repeat -100px -50px; } #navigation li.things a:hover { background: url(menu.jpg) no-repeat -200px -50px; } #navigation li.where a:hover { background: url(menu.jpg) no-repeat -300px -50px; } #navigation li.getting a:hover { background: url(menu.jpg) no-repeat -400px -50px; } #navigation li.about a:hover { background: url(menu.jpg) no-repeat -500px -50px; } #navigation li.contact a:hover { background: url(menu.jpg) no-repeat -600px -50px; }

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  • invite friends in a dialog in a Facebook application

    - by Shani1351
    I'm trying to create a Facebook application that displays a friend invite dialog within the application using Facebook's Javascript API (FB.ui). To do that I followed this tutorial I have two problems : The action url I've put in the request-form is "http://apps.facebook.com/appname/post_invite.php" but I see that the iframe source after the post is "http://mydomain.com/post_invite.php" and when this iframe tries to do : parent.closeInviteWidget(); I get an error saying : "Permission denied for < http: //mydomain.com (document.domain has not been set) to get property Window.closeInviteWidget from < http:// apps.facebook.com (document.domain=< http:// facebook.com)." The skip button inside the request-form opens the action url in a new window (new browser tab) and not post to itself like the invite button. How can I fix those problems? -------------------- UPDATE : -------------------------------- I've tried to do what ifaour said and changed the code to : function inviteFriends(user_name, category_id, category_name) { url = appBaseUrl + "/index.php?category_id=" + category_id; req = "<fb:req-choice url='" + url + "' label='Authorize My Application' />"; content = user_name + " opened a new category called " + category_name + ". " + req; action = 'post_invite.php'; fbmi_text = '<fb:request-form action="' + action + '" target="_self" method="post" invite="true" type="Invite" content="' + content + '" <fb:multi-friend-selector showborder="false" actiontext="Invite yor friends" email_invite="false" import_external_friends="false" /> </fb:request-form>'; FB.ui({ method:'fbml.dialog', width:'750px', fbml:fbmi_text }); } When I use FireBug and look at the invite form it looks like this: <form id="req_form_4d20682f73ddb6e71722794" content="I've opened a new category called dsfsd. <fb:req-choice url='http://apps.facebook.com/appname/index.php?category_id=60' label='Authorize My Application' /> type="Invite" invite="true" method="post" target="_self" action="http://apps.facebook.com/appname/post_invite.php"> ... </form> But I still get the same error : Permission denied for <http://mydomain.com> (document.domain has not been set) to get property Window.closeInviteWidget from <http://apps.facebook.com> (document.domain=<http://facebook.com>)...

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  • Requirements for connecting to Oracle with JDBC?

    - by Lord Torgamus
    I'm a newbie to Java-related web development, and I can't seem to get a simple program with JDBC working. I'm using off-the-shelf Oracle 10g XE and the Eclipse EE IDE. From the books and web pages I've checked so far, I've narrowed the problem down to either an incorrectly written database URL or a missing JAR file. I'm getting the following error: java.sql.SQLException: No suitable driver found for jdbc:oracle://127.0.0.1:8080 with the following code: import java.sql.*; public class DatabaseTestOne { public static void main(String[] args) { String url = "jdbc:oracle://127.0.0.1:8080"; String username = "HR"; String password = "samplepass"; String sql = "SELECT EMPLOYEE_ID FROM EMPLOYEES WHERE LAST_NAME='King'"; Connection connection; try { connection = DriverManager.getConnection(url, username, password); Statement statement = connection.createStatement(); System.out.println(statement.execute(sql)); connection.close(); } catch (SQLException e) { System.err.println(e); } } } What is the proper format for a database URL, anyways? They're mentioned a lot but I haven't been able to find a description. Thanks! EDIT (the answer): Based on duffymo's answer, I got ojdbc14.jar from http://www.oracle.com/technology/software/tech/java/sqlj_jdbc/htdocs/jdbc_10201.html and dropped it in the Eclipse project's Referenced Libraries. Then I changed the start of the code to ... try { Class.forName("oracle.jdbc.driver.OracleDriver"); } catch (ClassNotFoundException e) { System.err.println(e); } // jdbc:oracle:thin:@<hostname>:<port>:<sid> String url = "jdbc:oracle:thin:@GalacticAC:1521:xe"; ... and it worked.

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  • Remove the Parent tag in xml using php

    - by Wasim
    I am facing a problem in editing a xml file. <?xml version="1.0" encoding="UTF-8"?> <urlset> <url> <loc>http://www.abc.com/</loc> <lastmod>2010-04-17T17:23:57+00:00</lastmod> <changefreq>daily</changefreq> <priority>0.50</priority> </url> <url> <loc>http://www.abc.com/</loc> <lastmod>2010-04-17T17:23:57+00:00</lastmod> <changefreq>daily</changefreq> <priority>0.50</priority> </url> </urlset> I want to add one more set of records starting with <url> with its other tags, (i.e) "loc,lastmod,changefreq,priority" and than save the xml file.For adding the new record i need to remove the parent closing tag that is </urlset> and than add the rest of the records and close the main tag. Can anyone please help me solving my problem.Thanks

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  • Protecting melody monitoring with acegi in grails

    - by xain
    Hi, I have a Grails 1.2 app secured with acegi that I'm monitoring with the melody plugin for grails. I need to protect the url so only the "admin" role can access it but I'm having trouble with it - the rest of the acegi rules work just fine. In the BootStrap, I set def secureReqMap = new Requestmap(url: '/monitoring/**', configAttribute:'ROLE_ADMIN').save() Also tried with def secureReqMap = new Requestmap(url: '/monitoring', configAttribute:'ROLE_ADMIN').save() With no luck, it keeps being public. Any hints? Thanks

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  • Google Custom Search Engine not giving the expected search result.

    - by iecut
    Hi, I have been trying to create a new google custom search engine, but when I try some query,the search engine it is not giving me the expected search result.On some queries it is working fine, but on other queries, it says"no result". I tried adding the URL of the website that I wanted to search for, but there are certain pages and keywords that are not coming up in the search result when I try to search for the keyword of that page. I tired adding both the main page URL and the URL of the sub page that I want to search for, but nothing is working. There are some sub pages to the main URL that are coming in the search result.

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  • Create two semi-transparent images that when stacked produce the target image

    - by posfan12
    Due to CSS limitations I am forced to stack to semi-transparent images on my website. I won't go into detail regarding the CSS since if I can get this question answered the problem is moot. Anyway, I would like to modify image A in the GIMP such that it will look like it did originally after being stacked on top of image B. Both image A and image B have their opacities set to 50%. Image B is a solid color throughout, whereas image A has some minor details such as a gradient. Here's what it looks like before image B is applied on top (and what it should look like in the end): [URL=http://s421.photobucket.com/albums/pp292/SharkD2161/Support/Website/?action=view&current=website_testing_target_image.png][IMG]http://i421.photobucket.com/albums/pp292/SharkD2161/Support/Website/th_website_testing_target_image.png[/IMG][/URL] Here's what it looks like after image B has been applied on top: [URL=http://s421.photobucket.com/albums/pp292/SharkD2161/Support/Website/?action=view&current=website_testing_undesired_result.png][IMG]http://i421.photobucket.com/albums/pp292/SharkD2161/Support/Website/th_website_testing_undesired_result.png[/IMG][/URL] Thanks! Mike

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  • How to embed a font in website

    - by Mayur
    Hi All, I am trying to embed my custom font in my web site, got a link folder from http://www.fontsquirrel.com/fontface/generator this site after uploading a font on this site, it gives me a css @font-face { font-family: 'VoltaEFTU-Regular'; src: url('voltaeftu-regular-webfont.eot'); src: local('?'), url('voltaeftu-regular-webfont.woff') format('woff'), url('voltaeftu-regular-webfont.ttf') format('truetype'), url('voltaeftu-regular-webfont.svg#webfonttKmU3jX8') format('svg'); font-weight: normal; font-style: normal; } but its not working in my machines how can i embed a font in my web site.... Thanks Mayur Mate

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  • error message: clientside validation

    - by user281180
    What is the meaning of the following error message?How can I use the EnableClienTValidation()? Error 3 'System.Web.Mvc.HtmlHelper' does not contain a definition for 'EnableClientValidation' and no extension method 'EnableClientValidation' accepting a first argument of type 'System.Web.Mvc.HtmlHelper' could be found (are you missing a using directive or an assembly reference?) c:\Dev\DEV\test3\Code\MvcUI\Views\Customer\Create.aspx 11 13 MvcUI I have reference the following:`" type="text/javascript" <script src="<%=Url.Content("~/Scripts/jquery.validate.js")%>" type="text/javascript"></script> <script src="<%= Url.Content("~/Scripts/MicrosoftAjax.js")%>" type="text/javascript"></script> <script src="<%= Url.Content("~/Scripts/MicrosoftMvcAjax.js")%>" type="text/javascript"></script> <script src="<%= Url.Content("~/Scripts/MicrosoftMvcJQueryValidation.js" )%>" type="text/javascript"></script> `

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  • styles/style.css No mapping found for HTTP request

    - by sonx
    Hi, it seems my styles folder added under the web folder is not getting mapped by dispatcher servlet on my JSP's. I get WARN : org.springframework.web.servlet.PageNotFound - No mapping found for HTTP request with URI [/onlinebasket/styles/style.css] in DispatcherServlet with name 'onlinebasket' here's my dispatcher servlet <servlet-mapping> <servlet-name>onlinebasket</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> and i this is my CSS URL on JSP <link rel="stylesheet" href="<c:url value="/styles/sytle.css"/>" type="text/css"/> This folder is on the web folder.

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  • getting web page data as json object?

    - by encryptor
    I have a url, the data of which page i need as a json object. I ve tried xmlhttprequest and ajaxobject both but doesnt work. It doesnt even give a responseText when I give it as an alert Ill post both the code snippets here. url = http://mydomain.com:port/a/b/c AJAX : var ajaxRequest = new ajaxObject(URL); ajaxRequest.callback = function (responseText,responseStatus) { alert(responseStatus); JSONData = responseText.parseJSON(); processData(JSONData); } USING xmlhttprequest: var client = new XMLHttpRequest(); client.open('GET',URL,true ); data = JSON.parse(client.responseText); alert(data.links.length); can someone please help me out with this. I understand cross scripting may be an issue, but how to come over it? and shouldn't then too it should give the alerts as zero or null

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  • joining relative urls?

    - by heffaklump
    So i want to join strings with relative urls in Javascript. base url = "http://www.adress.com/more/evenmore" with relative url = "../../adress" = "http://www.adress.com/adress" relative url = "../adress" = "http://www.adress.com/more/adress" What would be the best way? I was thinking of using regexp and checking how many "../" i find, then subtracting that amount from the baseurl and adding them to what is left.

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  • jQuery AJAX Redirection problem

    - by meosoft
    Hello please consider this: On page A I have a link that takes you to page B when JS is off, but when JS is on, I want to replace content on current page with content from the page B. Pages A and B are in fact the same script that is able to tell AJAX calls from regular ones and serve the content appropriately. Everything works fine, as long as there are no redirects involved. But, sometimes there is a 301 redirect and what seems to be happening is that client browser then makes a second request, which will return with a 200 OK. Only the second request is sent without a X-Requested-With header, therefore I cannot tell within my script wether it came from AJAX or not, and will send a complete page instead of just the content. I have tried checking for 301 status code in my error, success, and complete handlers but none of them worked. It seems to be handling the 301 behind the scenes. Could anyone help me with this? jQuery 1.4, PHP 5 Edit: People requested the code to this, which I didn't think was necessary but here goes: // hook up menu ajax loading $('#menu a').live("click", function(){ // update menu highlight if($(this).parents('#menu').size() > 0){ $("#menu>li").removeClass("current_page_item"); $(this).parent().addClass("current_page_item"); } // get the URL where we will be retrieving content from var url = $(this).attr('href'); window.location.hash = hash = url; $.ajax({ type: "GET", url: url, success: function(data){ // search for an ID that is only present if page is requested directly if($(data).find('#maincontent').size() > 0){ data = $(data).find('#maincontent .content-slide *').get(); } // the rest is just animating the content into view $("#scroller").html(data); $('.content-slide').each(setHeight); $('.content-slide').animate({ left: "0px" }, 1000, 'easeOutQuart', function(){ $('#home').css("left", "-760px").html(data); $('#scroller').css("left", "-760px"); $('.content-slide').each(setHeight); } ); } }); return false; });

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  • twitter basic authorisation not working?

    - by Bunny Rabbit
    URL url = new URL("http://twitter.com/statuses/update.xml"); HttpURLConnection conn = (HttpURLConnection) url.openConnection(); conn.setDoOutput(true); String cridentials = new sun.misc.BASE64Encoder().encode((username + ":" + password).getBytes()); conn.setRequestProperty ("Authorization", "Basic " + cridentials); OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream()); wr.write(status); wr.flush(); wr.close(); why the above code for updating twitter status is not working ? i am running it on google app engine.

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  • PHP RegExpr error Unkown modifier '('

    - by Anonymous
    I have this regular expression: ([http://some.url.com/index.php?showtopic=\"]*)([0-9]+(?:\.[0-9]*)?) its for extracting links to topics from forum Now when i use it in my script $url = "([http://some.url.com/index.php?showtopic=\"]*)([0-9]+(?:\.[0-9]*)?)"; preg_match_all spits: "Unknown modifier '('" Can anyone help me with this obviously stupid problem

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  • Ie7 float problems and hiperlinks not clickable

    - by Uffo
    Markup <ul class="navigation clearfix"> <li class="navigation-top"></li> <div class="first-holder" style="height:153px;"> <dl class="hold-items clearfix"> <dd class="clearfix with"><a href="http://site.com" title="Protokoll">Protokoll</a></dd> <dd class="with-hover"><a href="http://site.com" title="Mein/e Unternehmen">Mein/e Unternehmen</a></dd> <dd class="with"><a class="face-me" href="http://site.com" title="Erweiterte Suche">Erweiterte Suche</a></dd> <dd class="with"><a href="http://site.com" title="Abmelden">Abmelden</a></dd> </dl> </div><!--[end] /.first-holder--> <li class="navigation-bottom"></li> </ul><!--[end] /.navigation--> Css: .first-holder{height:304px;position:relative;width:178px;overflow:hidden;margin-bottom:0px;padding-bottom: 0px;} .hold-items{top:0px;position:absolute;} .navigation dd.with{line-height:38px;background:url('/images/sprite.png') no-repeat -334px -46px;width:162px;height:38px;padding-bottom:0px;overflow: hidden;} .navigation dd.with a{position:relative;outline:0;display:block;font-weight:bold;color:#3f78c0;padding-left:10px;line-height:38px;} .with-hover{background:url('/images/sprite.png') no-repeat -505px -47px;width:178px;height:38px;line-height:38px;overflow:none;} .with-hover a{position:relative;display:block;font-weight:bold;color:#fff;padding-left:10px} .navigation-top{background:url('/images/sprite.png') no-repeat -694px -46px;width:160px;height:36px;} .navigation-top a{display:block;outline:0;height:20px;padding-top:18px;padding-left:138px;} .navigation-top a span{display:block;background:url('/images/sprite.png') no-repeat -212px -65px;width:8px;height:6px;} .navigation-bottom{background:url('/images/sprite.png') no-repeat -784px -402px;width:160px;height:37px;} .navigation-bottom a{display:block;outline:0;height:20px;padding-top:18px;padding-left:138px;} .navigation-bottom a span{display:block;background:url('/images/sprite.png') no-repeat -212px -74px;width:8px;height:6px;} Also the links, are not clickable, if I click on a link in IE7 it doesn't do the action..it doesn't redirect me to the location. This is how it looks in IE7: http://screencast.com/t/MGY4NjljZjc This is how it look in IE8,Firefox,Chrome and so on http://screencast.com/t/MzhhMDQ1M What I'm doing wrong PS: .navigation-top a span and .navigation-bottom a span I'm using some where else, but that it's ok it works fine.

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  • PHP + CURL How to get file name

    - by Gunjan
    I'm trying to download users profile picture from facebook in PHP using this function public static function downloadFile($url, $options = array()) { if (!is_array($options)) $options = array(); $options = array_merge(array( 'connectionTimeout' => 5, // seconds 'timeout' => 10, // seconds 'sslVerifyPeer' => false, 'followLocation' => true, // if true, limit recursive redirection by 'maxRedirs' => 2, // setting value for "maxRedirs" ), $options); // create a temporary file (we are assuming that we can write to the system's temporary directory) $tempFileName = tempnam(sys_get_temp_dir(), ''); $fh = fopen($tempFileName, 'w'); $curl = curl_init($url); curl_setopt($curl, CURLOPT_FILE, $fh); curl_setopt($curl, CURLOPT_CONNECTTIMEOUT, $options['connectionTimeout']); curl_setopt($curl, CURLOPT_TIMEOUT, $options['timeout']); curl_setopt($curl, CURLOPT_HEADER, false); curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, $options['sslVerifyPeer']); curl_setopt($curl, CURLOPT_FOLLOWLOCATION, $options['followLocation']); curl_setopt($curl, CURLOPT_MAXREDIRS, $options['maxRedirs']); curl_exec($curl); curl_close($curl); fclose($fh); return $tempFileName; } The problem is it saves the file in the /tmp directory with a random name and without the extension. How can I get the original name of the file (I'm more interested in the original extension) The important things here are: The url actually redirects to image so i cant get it from original url the final url does not have the file name in headers

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  • Saving animated GIFs using urllib.urlopen (image saved does not animate)

    - by wenbert
    I have Apache2 + Django + X-sendfile. My problem is that when I upload an animated GIF, it won't "animate" when I output through the browser. Here is my code to display the image located outside the public accessible directory. def raw(request,uuid): target = str(uuid).split('.')[:-1][0] image = Uploads.objects.get(uuid=target) path = image.path filepath = os.path.join(path,"%s.%s" % (image.uuid,image.ext)) response = HttpResponse(mimetype=mimetypes.guess_type(filepath)) response['Content-Disposition']='filename="%s"'\ %smart_str(image.filename) response["X-Sendfile"] = filepath response['Content-length'] = os.stat(filepath).st_size return response UPDATE It turns out that it works. My problem is when I try to upload an image via URL. It probably doesn't save the entire GIF? def handle_url_file(request): """ Open a file from a URL. Split the file to get the filename and extension. Generate a random uuid using rand1() Then save the file. Return the UUID when successful. """ try: file = urllib.urlopen(request.POST['url']) randname = rand1(settings.RANDOM_ID_LENGTH) newfilename = request.POST['url'].split('/')[-1] ext = str(newfilename.split('.')[-1]).lower() im = cStringIO.StringIO(file.read()) # constructs a StringIO holding the image img = Image.open(im) filehash = checkhash(im) image = Uploads.objects.get(filehash=filehash) uuid = image.uuid return "%s" % (uuid) except Uploads.DoesNotExist: img.save(os.path.join(settings.UPLOAD_DIRECTORY,(("%s.%s")%(randname,ext)))) del img filesize = os.stat(os.path.join(settings.UPLOAD_DIRECTORY,(("%s.%s")%(randname,ext)))).st_size upload = Uploads( ip = request.META['REMOTE_ADDR'], filename = newfilename, uuid = randname, ext = ext, path = settings.UPLOAD_DIRECTORY, views = 1, bandwidth = filesize, source = request.POST['url'], size = filesize, filehash = filehash, ) upload.save() #return uuid return "%s" % (upload.uuid) except IOError, e: raise e Any ideas? Thanks! Wenbert

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  • Applescript, how to get network address of a file

    - by CRP
    We are a network of Mac computers. I would like to send email addresses to colleagues with links to files on network locations. I made the following applescript: tell application "Finder" set uuu to URL of the first item of (get the selection) set the clipboard to uuu end tell which puts the URL of the currently selected file into the clipboard, which can then be pasted into the message (using the Add Link menu item), providing, for example: file://localhost/Volumes/Commerciale/Clienti/ unfortunately these links do not work. If I select Go To Folder from the menu item, I can get to the folder using an afp:// type url. Is there any way to get this via applescript like I do with url above? Thanks

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  • how to display a image in java application

    - by Nubkadiya
    i want to display a image in my java application. i found a code to download the image from the webserver. what that code do is it takes the image and show it in the jframe. i want to use a label to show the image or soemthing else. so i can put it in my java application. can someone help me. it shouldnt be JFrame please help me here is my code Image image = null; try { URL url = new URL("http://www.personal.psu.edu/acr117/blogs/audrey/images/image-2.jpg"); image = ImageIO.read(url); } catch (IOException e) { } // Use a label to display the image JFrame frame = new JFrame(); JLabel lblimage = new JLabel(new ImageIcon(image)); frame.getContentPane().add(lblimage, BorderLayout.CENTER); frame.setSize(300, 400); frame.setVisible(true); } can someone help me

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  • Plone, behaviour of URLs

    - by jpet
    The situation is the following: I created a site with Plone, developed, used, but behind a test URL. Now it has to be published, but the test URL is not appropriate and I don't want to move the site. I think, if I use a redirect, it won't be appear in the URL-bar, only in the case of site start page. Am I wrong? (The test URL should not be used, because it will be a "semi-official" site.) What do you suggest to do? As far as I can see Plone uses absolute URLs everywhere. I can add relative URLs, but if I create a new page, a new event, etc., then they have absolute URLs on other automatically generated inner pages. Is there any way to convert these URLs to relative paths? Is there any setting possibilty where only a checkbox changes this default setting?

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  • Using URI-fragments in Ruby on rails routing

    - by Alexei
    RoR application can generate URL such as /post/10. But now I want to create a site, which works with URI-fragments like gmail. For example gmail uses the following URLs https://mail.google.com/mail/?shva=1#sent https://mail.google.com/mail/?shva=1#label/books I need to generate URL such as /#/post/10, where controller = "post", action = "show", id = "10". Of course it will be good to use standard url-helpers.

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  • MVC + Extjs + IIS6 + Wildcard Mapping = Post Form resulting in 302 object moved

    - by Orkun Balkanci
    Everything seems to work fine until i want to submit the form and update the database. Wildcard mapping works on requests like "/navigation/edit/1", but when i submit the form as: var ajaxPost = function(Url, Params) { Ext.Ajax.request({ url: Url, params: Params, method: 'POST', async: false, scope: this }); }; it says "200 bad response: syntax error" and in firebug there is "Failed to load source for: http://.../Navigation/edit/1". Any help?

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  • Where to put the application ID in YQL

    - by earlyriser
    I'm trying to read an xml response from YQL: $url = 'http://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20geo.places%20where%20woeid%3D%22'.$woeid.'%22'; if (!$xml=simplexml_load_file($url) ) { //DO STUFF } This code works. Now i'm trying to put my application ID in the url string but I don't know how it should be done. Thanks.

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