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  • Detect if Download is Complete

    - by user604138
    I have a very simple and standard PHP force download script. How do I check if/when the download has completed in order to notify the user on the clientside? I don't even need to show the progress in real time, I am only interested in the very specific event: "when the download completes". Based on my research, it seems like it would have to be determined from the serverside as there is noondownloadready event and I don't think it is possible to intercept browser events. So it seems that my best bet would be to compare bytes sent to total bytes with some sort of clientside/severside interaction. How would I go about checking the bytes sent from the server for a PHP forced download? is there some sort of global PHP variable that store these data that I can ping with AJAX? <?php header("Content-Type: video/x-msvideo"); header("Content-Disposition: attachment; filename=\"".basename($realpath)."\";"); ... $chunksize = 1 * (1024 * 1024); // how many bytes per chunk if ($size > $chunksize) { $handle = fopen($realpath, 'rb'); $buffer = ''; while (!feof($handle)) { $buffer = fread($handle, $chunksize); echo $buffer; ob_flush(); flush(); } fclose($handle); } else { readfile($realpath); } exit(); ?> The reason I need this: For the project I am working on, it is required that after the download starts, the page redirects to (or displays) a "please wait while the download completes" page. Then, once it is complete, it should redirect to (or display) a "Your download is complete, thank you" page. I am open to other ideas that would achieve the same result.

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  • Read all sub directories within a certain folder to display a random image.

    - by Andy
    I have this code i have been using....but i need a conditional where it will read all the sub directories of /bg to select an image as opposed to a specific folder if they were on a subpage. Heres my code so far which works perfectly for all subpages to display specific images: //This would tell us its on the homepage if it helps: $this->level() == 0 //This is the code so far $path = '/home/sites/mydomain.co.uk/public_html/public/images/bg/'.$this->slug; $homepagefile = URL_PUBLIC.'public/images/bg/'.$this->slug.'/main.jpg'; $bgimagearray = array(); $iterator = new DirectoryIterator($path); foreach ($iterator as $fileinfo) { if ($fileinfo->isFile() && !preg_match('\.jpg$/', $fileinfo->getFilename())) { $bgimagearray[] = "'" . $fileinfo->getFilename() . "'"; } } $bgimage = array_rand($bgimagearray); ?> <div id="bg"> <div> <table cellspacing="0" cellpadding="0"> <tr> <td><img src="<?php echo $file.trim($bgimagearray[$bgimage], "'"); ?>" alt=""/></td> </tr> </table> </div> </div> Any help would be appreciated, im sure its not rocket science but ive tried a few ways and cant get my head around it. Thanks in advance.

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  • How can I achieve this kind of relationship (inheritance, composition, something else)?

    - by Tim
    I would like to set up a foundation of classes for an application, two of which are person and student. A person may or may not be a student and a student is always a person. The fact that a student “is a” person led me to try inheritance, but I can't see how to make it work in the case where I have a DAO that returns an instance of person and I then want to determine if that person is a student and call student related methods for it. class Person { private $_firstName; public function isStudent() { // figure out if this person is a student return true; // (or false) } } class Student extends Person { private $_gpa; public function getGpa() { // do something to retrieve this student's gpa return 4.0; // (or whatever it is) } } class SomeDaoThatReturnsPersonInstances { public function find() { return new Person(); } } $myPerson = SomeDaoThatReturnsPersonInstances::find(); if($myPerson->isStudent()) { echo 'My person\'s GPA is: ', $myPerson->getGpa(); } This obviously doesn't work, but what is the best way to achieve this effect? Composition doesn't sond right in my mind because a person does not “have a” student. I'm not looking for a solution necessarily but maybe just a term or phrase to search for. Since I'm not really sure what to call what I'm trying to do, I haven't had much luck. Thank you!

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  • PHP Error Form - Leave Contents of Form on Redirect

    - by user1371500
    I have a simple login form in which if an error occurs such as wrong password, I need it to be able to remember the username which was entered. Would I Go about doing this PHP or Javascript as I am not allowed to use JQuery. My current PHP - (Not Including the HTML Form) <?php //MySQl Connection mysql_connect("localhost", "root", "") or die(mysql_error()); mysql_select_db("clubresults") or die(mysql_error()); //Initiates New Session - Cookie session_start(); // Start a new session // Get the data passed from the form $username = $_POST['username']; $password = md5($_POST['pass']); // Do some basic sanitizing $username = mysql_real_escape_string($username); $password = mysql_real_escape_string($password); //Performs SQL Query to retrieve Login Details from DB $sql = "select * from admin_passwords where username = '$username' and password = '$password'"; $result = mysql_query($sql) or die ( mysql_error() ); //Assigns a Variable Count to 0 $count = 0; //Exectues a loop to increment on Successful Login while ($line = mysql_fetch_assoc($result)) { $count++; } //If count is equal to 1 Redirect user to the Members Page and Set Cookie if ($count == 1) { $_SESSION['loggedIn'] = "true"; header("Location: members.php"); // This is wherever you want to redirect the user to } else { //Else Echo that login was a failure. die('Login Failed. <a href=login.php>Click Here to Try Again</a>'); } ?> Any help would be appreciated. Cheers

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  • Display attribute from XML using PHP

    - by user560411
    Hello. I need to display the id attribute of CD from the following XML file. I display correctly everything except the id. Any help would be appreciate. display code <?php $doc = new DOMDocument(); $doc->load( 'insert.xml' ); $CATEGORIES = $doc->getElementsByTagName( "CD" ); foreach( $CATEGORIES as $CD ) { $TITLES = $CD->getElementsByTagName( "TITLE" ); $TITLE = $TITLES->item(0)->nodeValue; $BANDS= $CD->getElementsByTagName( "BAND" ); $BAND= $BANDS->item(0)->nodeValue; $YEARS = $CD->getElementsByTagName( "YEAR" ); $YEAR = $YEARS->item(0)->nodeValue; echo "<b>$TITLE - $BAND - $YEAR\n</b><br>"; } ?> XML <?xml version="1.0" encoding="utf-8"?> <MY_CD> <CATEGORIES> <CD id="3231"> <TITLE>NEVER MIND THE BOLLOCKS</TITLE> <BAND>SEX PISTOLS</BAND> <YEAR>1977</YEAR> </CD> <CD id="2453"> <TITLE>NEVERMIND</TITLE> <BAND>NIRVANA</BAND> <YEAR>1991</YEAR> </CD> </CATEGORIES> </MY_CD>

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  • Trigger alert when database entries are added, not when they are removed

    - by Jeremy
    I have a jQuery script running that makes a periodic AJAX call using the following code. var a = moment(); var dayOfMonth = a.format("MMM Do"); var timeSubmitted = a.format("h:mm a"); var count_cases = -1; var count_claimed = -1; setInterval(function(){ //check if new lead was added to the db $.ajax({ type : "POST", url : "inc/new_lead_alerts_process.php", dataType: 'json', cache: false, success : function(response){ $.getJSON("inc/new_lead_alerts_process.php", function(data) { if (count_cases != -1 && count_cases != data.count) { window.location = "new_lead_alerts.php?id="+data.id; } count_cases = data.count; }); } }); This is the PHP that runs with each call: $count = mysql_fetch_array(mysql_query("SELECT count(*) as count FROM leads")); $client_id = mysql_fetch_array(mysql_query("SELECT id, client_id FROM leads ORDER BY id DESC LIMIT 1")); echo json_encode(array("count" => $count['count'], "id" => $client_id['id'], "client_id" => $client_id['client_id'])); I need to change the code so that the alert only triggers when a new entry is added to the database, not when an existing entry is removed. As it stands, the alert fires on both events. Any help is greatly appreciated.

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  • How to remove background of a image and copy into another?

    - by Gustavo Pinent
    I'm researching about captchas. In this idea, the task is: create a image from a JPEG and remove the white background, than create another image from another JPEG, than create the final image by adding the second as a background, and copying the first one over this background preserving the transparent area created, of course. Here is the code: header("Content-Type: image/jpeg"); $nFundo = rand(0,4); $Dirs = array(rand(0,7), rand(0,7), rand(0,7), rand(0,7)); // Will be four times all $_SESSION["form_captcha"] = $Dirs; $image = ImageCreatetruecolor(320, 80); ImageAlphaBlending($image, FALSE); ImageSaveAlpha($image, TRUE); $image_seta = ImageCreateFromJPEG("_captcha-seta.jpg"); // Image do copy over $image_fundo = ImageCreateFromJPEG("_captcha-fundo-".$nFundo.".jpg"); // Image to make the background for($i=0; $i<4; $i++){ ImageCopy($image, $image_fundo, $i*80, 0, 0, 0, 80, 80); } // So far so good, a background with a pattern repeated four times $color_white = ImageColorAllocate($image_seta, 255, 255, 255); ImageColorTransparent($image_seta, $color_white); ImageSaveAlpha($image_seta, TRUE); for($i=0; $i<4; $i++){ $image_seta_rot = imageRotate($image_seta, $Dirs[$i]*45, $color_white); ImageCopyResampled($image, $image_seta_rot, $i*80, 0, 0, 0, 80, 80, 80, 80); // Try } echo(imagejpeg($image)); imagedestroy($image); I tried to replace $image_seta_rot by $image_seta ("Try" line) to see if the rotation is the problem, but even without rotation, the white wasn't removed and the image just "erase" the background created before. So the copy is failing or the white were never removed... I may create a PNG with transparent background, but will be interesting to learn how to make it dynamically, don't you think? Any ideas?

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  • codeigniter and JSON

    - by ole
    Hello all i having a problem that it only get 1 value in my database and its my title and i want to show content and username from the same table to. here is my JSON kode <script type="text/javascript"> $.getJSON( 'ajax/forumThreads', function(data) { alert(data[0].overskrift); alert(data[0].indhold); } ); </script> my controller <?php class ajax extends Controller { function forumThreads() { $this->load->model('ajax_model'); $data['forum_list'] = $this->ajax_model->forumList(); if ($data['forum_list'] !== false) { echo json_encode($data['forum_list']); } } } my model fle <?php class ajax_model extends Model { function forumList() { $this->db->select('overskrift', 'indhold', 'brugernavn', 'dato'); $this->db->order_by('id', 'desc'); $this->db->limit(5); $forum_list = $this->db->get('forum_traad'); if($forum_list->num_rows() > 0) { return $forum_list->result_array(); } else { return false; } } }

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  • PHP & HTML Purifier Error: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given

    - by TaG
    I'm trying to Integrate HTML Purifier http://htmlpurifier.org/ to filter my user submitted data but I get the following error below. And I was wondering how can I fix this problem? I get the following error. on line 22: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given line 22 is. if (mysqli_num_rows($dbc) == 0) { Here is the php code. if (isset($_POST['submitted'])) { // Handle the form. require_once '../../htmlpurifier/library/HTMLPurifier.auto.php'; $config = HTMLPurifier_Config::createDefault(); $config->set('Core.Encoding', 'UTF-8'); // replace with your encoding $config->set('HTML.Doctype', 'XHTML 1.0 Strict'); // replace with your doctype $purifier = new HTMLPurifier($config); $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.*, profile.* FROM users INNER JOIN contact_info ON contact_info.user_id = users.user_id WHERE users.user_id=3"); $about_me = mysqli_real_escape_string($mysqli, $purifier->purify($_POST['about_me'])); $interests = mysqli_real_escape_string($mysqli, $purifier->purify($_POST['interests'])); if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO profile (user_id, about_me, interests) VALUES ('$user_id', '$about_me', '$interests')"); } if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE profile SET about_me = '$about_me', interests = '$interests' WHERE user_id = '$user_id'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; } if (!$dbc) { // There was an error...do something about it here... print mysqli_error($mysqli); return; } }

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  • How to change a recursive function for count files and catalogues?

    - by user661999
    <?php function scan_dir($dirname) { $file_count = 0 ; $dir_count = 0 ; $dir = opendir($dirname); while (($file = readdir($dir)) !== false) { if($file != "." && $file != "..") { if(is_file($dirname."/".$file)) ++$file_count; if(is_dir($dirname."/".$file)) { ++ $dir_count; scan_dir($dirname."/".$file); } } } closedir($dir); echo "There are $dir_count catalogues and $file_count files.<br>"; } $dirname = "/home/user/path"; scan_dir($dirname); ?> Hello, I have a recursive function for count files and catalogues. It returns result for each catalogue. But I need a common result. How to change the script? It returns : There are 0 catalogues and 3 files. There are 0 catalogues and 1 files. There are 2 catalogues and 14 files. I want: There are 2 catalogues and 18 files.

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  • Zend_Dojo_Form not rendering in layout

    - by Grant Collins
    Hi, I have a quick question about adding Zend_Dojo_Form into Zend_layouts. I have a Zend_Dojo_Form that I want to display in the layout that is used for a particular controller. I can add the form to the layout without any issue however the dojo elements fail to render, as they would do if I added the form to a standard view. Is there any reason why this would be the case? Do I need to do something to the layout so that it will enable the components for this embedded form in the layout. Any other dojo enabled forms that are added in the view using this layout work fine. My form is created in the usual way: class QuickAddJobForm extends Zend_Dojo_Form{ public function init(){ $this->setName('quickaddjobfrm') ->setMethod('post') ->setAction('/addjob/start/); /*We now create the elements*/ $jobTitle = new Zend_Dojo_Form_Element_TextBox('jobtitle', array( 'trim' => true ) ); $jobTitle->setAttrib('style', 'width:200px;') ->addFilter('StripTags') ->removeDecorator('DtDdWrapper') ->removeDecorator('HtmlTag') ->removeDecorator('Label'); .... $this->addElements(array($jobTitle, ....)); In the controller I declare the layout and the form in the init function: public function init(){ $this->_helper->layout->setLayout('add-layout'); $form = new QuickAddJobForm(); $form->setDecorators(array(array('ViewScript', array('viewScript' => 'quickAddJobFormDecorator.phtml')))); $this->_helper->layout()->quickaddjob = $form; In my layout Where I want the form I have: echo $this->layout()->quickaddjob; Why would adding this form in the layout fail to render/add the Dojo elements? All that is currently being displayed are text boxes, rather than some of the other components such as ComboBoxes/FilteringSelects etc... Thanks in advance.

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  • ajax form handling an array

    - by moata_u
    am trying to handle an array comes from php file after submitting the form data , the value of data after submitting the form is = ARRAY but i cant use this array in any way , any idea how can i handle this array !!!! Javascript : $('#file').live('change',function(){ $('#preview').html(''); $('#preview').html('<img src="loader.gif" />'); $('#data').ajaxForm(function(data){ $(data['toshow']).insertBefore('.pic_content').hide().fadeIn(1000); }).submit(); }); PHP : .... ....etc echo json_encode(array('toshow'=>somedata,'data'=>somedata)); data come from php file {"toshow":"\r\n\t\t\t\t\r\n\t\t<table class=\"out\">\r\n\t\t\t<tr ><td class=\"img\"><a title=\"2012-06-02 01-22-09\" rel=\"prettyPhoto\" href=\"img\/2012-06-02 01-22-09.284.jpg\"><img src=\"img\/thumb\/2012-06-02 01-22-09.284.jpg\"\/><\/a><\/td><\/tr>\r\n\t\t\t\r\n\t\t\t<td>\r\n\t\t\t\t<table cellSpacing=\"1\" cellPadding=\"0\">\r\n\t\t\t\t\t<tr><td class=\"data\"><span class=\"click\">2012-06-02 01-22-09<\/span><\/td><\/tr>\r\n\t\t\t\t\t<tr><td class=\"data\"><span class=\"click\">Download<\/span><\/td><\/tr>\r\n\t\t\t\t\t<tr><td class=\"data\"><a href=\"img\/2012-06-02 01-22-09.284.jpg\"><span class=\"click\">View<\/span><\/a><\/td><\/tr>\r\n\t\t\t\t<\/table>\r\n\t\t\t<\/td>\r\n\t\t\t<\/tr>\r\n\t\t<\/table>","span":"<span class='text'><img src='greencheck.png'\/>2012-06-02 01-22-09 Uploaded ,File Size =152Kb <\/span>"}

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  • PHP login, getting wrong count value from query / fetch array

    - by Chris
    Hello, *EDIT*Thanks to the comments below it has been figured out that the problem lies with the md5, without everything works as it should. But how do i implent the md5 then? I am having some troubles with the following code below to login. The database and register system are already working. The problem lies that it does not find any result at all in the query. IF the count is 0 it should redirect the user to a secured page. But this only works if i write count = 0, but this should be 0 , only if the user name and password is found he should be directed to the secure (startpage) of the site after login. For example root (username) root (password) already exists but i cannot seem to properly login with it. <?php session_start(); if (!empty($_POST["send"])) { $username = ($_POST["username"]); $password = (md5($_POST["password"])); $count = 0; $con = mysql_connect("localhost" , "root", ""); mysql_select_db("testdb", $con); $result = mysql_query("SELECT name, password FROM user WHERE name = '".$username."' AND password = '".$password."' ") or die("Error select statement"); $count = mysql_num_rows($result); if($count > 0) // always goes the to else, only works with >=0 but then the data is not found in the database, hence incorrect { $row = mysql_fetch_array($result); $_SESSION["username"] = $row["name"]; header("Location: StartPage.php"); } else { echo "Wrong login data, please try again"; } mysql_close($con); } ?>

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  • Linux: Find all symlinks of a given 'original' file? (reverse 'readlink')

    - by sdaau
    Hi all, Consider the following command line snippet: $ cd /tmp/ $ mkdir dirA $ mkdir dirB $ echo "the contents of the 'original' file" > orig.file $ ls -la orig.file -rw-r--r-- 1 $USER $USER 36 2010-12-26 00:57 orig.file # create symlinks in dirA and dirB that point to /tmp/orig.file: $ ln -s $(pwd)/orig.file $(pwd)/dirA/ $ ln -s $(pwd)/orig.file $(pwd)/dirB/lorig.file $ ls -la dirA/ dirB/ dirA/: total 44 drwxr-xr-x 2 $USER $USER 4096 2010-12-26 00:57 . drwxrwxrwt 20 root root 36864 2010-12-26 00:57 .. lrwxrwxrwx 1 $USER $USER 14 2010-12-26 00:57 orig.file -> /tmp/orig.file dirB/: total 44 drwxr-xr-x 2 $USER $USER 4096 2010-12-26 00:58 . drwxrwxrwt 20 root root 36864 2010-12-26 00:57 .. lrwxrwxrwx 1 $USER $USER 14 2010-12-26 00:58 lorig.file -> /tmp/orig.file At this point, I can use readling to see what is the 'original' (well, I guess the usual term here is either 'target' or 'source', but those in my mind can be opposite concepts as well, so I'll just call it 'original') file of the symlinks, i.e. $ readlink -f dirA/orig.file /tmp/orig.file $ readlink -f dirB/lorig.file /tmp/orig.file ... However, what I'd like to know is - is there a command I could run on the 'original' file, and find all the symlinks that point to it? In other words, something like (pseudo): $ getsymlinks /tmp/orig.file /tmp/dirA/orig.file /tmp/dirB/lorig.file Thanks in advance for any comments, Cheers!

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  • Memory fragmentation @ boost::asio ?

    - by Poni
    I'm pretty much stuck with a question I never got an answer for, a question which addresses an extremely important issue; memory fragmentation at boost::asio. Found nothing at the documentation nor here at SO. The functions at boost::asio, for example async_write() & async_read_some() always allocate something. (in my case it's 144 & 96 bytes respectively, in VC9 Debug build). How do I know about it? I connect a client to the "echo server" example provided with this library. I put a breakpoint at "new.cpp" at the code of "operator new(size_t size)". Then I send "123". Breakpoint is hit! Now using the stack trace I can clearly see that the root to the "new" call is coming from the async_write() & async_read_some() calls I make in the function handlers. So memory fragmentation will come sooner or later, thus I can't use ASIO, and I wish I could! Any idea? Any helpful code example?

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  • PHP dynamic Page-level DocBlocks

    - by Obmerk Kronen
    I was wondering if there is a way to interact with the Page-level DocBlocks. My question is more specifically about wordpress plugin development, but this question has arised also in a non-wordpress environments. The reason is mainly the possibility to easily change VERSIONS and names throughout a large project with maybe a constant definition - but that will reflect also in the docblock.. The following example Docblock is from a wordpress plugin I write - /* Plugin Name: o99 Auxilary Functions v0.4.7 Plugin URI: http://www.myurl.com Description: some simple description that nobody reads. Version: 0.4.7 Author: my cool name Author URI: http://www.ok-alsouri.com */ Is there a way to transform it into : $ver = '0.4.7'; $uri = 'http://www.myurl.com'; $desc = 'some simple description that nobody reads.'; $mcn = 'my cool name'; etc.. etc.. /* Plugin Name: o99 Auxilary Functions ($ver) Plugin URI: ($uri) Description: ($desc) Version: ($ver) Author: ($mcn) Author URI: ($$uri) */ obviously for echo to work I would need to break the docblock itself, and I can not WRITE the docblock directly into it´s own file . In shorts : can I "generate" a docblock with php itself somehow (I would think that the answer is - "no" for the page itself.. But maybe I am wrong and someone has some neat hack :-) ) Is that even possible ?

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  • Custom stream wrappers, what could they be useful for in web applications?

    - by michael
    I suppose the concept is language agnostic, but I don't know what it's called in other languages. In PHP they're Stream Wrappers. In short, a wrapper class that allows manipulation of a streamable resource (resource that can be read to/written to/seek into, such as a file, a db, an url). For example, in a template engine (a view), upon including a template file such as: include "view.wrapper://path/to/my/template/file.phtml"; my custom wrapper, declared elsewhere and associated with "view.wrapper", would first intercepts the file to replace such things as short tags (<?=) with a more verbose counterpart (<?php echo). This allows developers to use short tags in views, even if the server isn't set to allow it. It can also be applied to the preprocessing of views pseudo syntax such as {@myVar} (e.g. replacing it with $this->myVar). This is only one application of custom stream wrappers, but the feature seems powerful enough to make me think that there are others that could make life a lot simpler for developers. What have you built, or thought about building, custom stream wrappers for? where have you seen some interesting implementations? I'm particularly interested in their applications in web development.

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  • pathogen#infect not updating the runtimepath

    - by Taylor Price
    I have started working with pathogen.vim with gvim on Windows, following Tim Pope's setup guide at his github repository here. However, I'm running into the problem that pathogen#infect() does not seem to be modifying the runtimepath (as seen by running :echo &runtimepath in gvim). The simple test case _vimrc that I came up with is as follows. Please note that pathogen gets loaded just fine. "Set a base directory. let $BASE_DIR='H:\development\github\vimrc' "Source pathogen since it's not in the normal autoload directory. source $BASE_DIR\autoload\pathogen.vim "Start up pathogen call pathogen#infect() "call pathogen#infect('$BASE_DIR\functions') Neither running pathogen#infect() without an argument (which should add the bundles directory under the vimfiles directory) nor specifying a directory to contain files works. Substituting the pathogen#infect() call with pathogen#runtime_prepend_subdirectories('$BASE_DIR\functions'), which is what pathogen#infect() does fails to change the runtimepath as well. Any ideas that I've missed? Any more information that would be helpful? My repository with the non-trivial example is here.

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  • JavaScript two-dimensional Array to PHP

    - by vi
    Hi I have to send a two-dimensional JavaScript Array to a PHP page. Indeed, I'm working on a form-builder, in which the user can add or remove fields. These fields are added (or removed) using JavaScript (jQuery). When the user is done and hit a 'publish' button, I have to get all the fields concerned and send them to a PHP page which would build a real form with it. I found a way to do it but I'm pretty sure it's not very clean : addedFields = new Array(); $("#add-info .field").each(function() { addedFields.push(new Array($(this).find('.name').val(), $(this).find('.type').val(), $(this).find('.size').val())); }); Basically, the ".field" class objects are <tr> and the ".name", ".type" and ".size" objects are inputs. So I get an array of [name, type, size], then I convert it into a string using addedFields = addedFields.join(";"); Finally, I go to the PHP form that way ; document.location.href = "create.php?addedfields=" + addedFields; Concerning the PHP code, I create a PHP array using the explode() function: $addedFields = explode(";", $_GET['addedfields']); and then I use it again for each element in the array: foreach ($addedFields as $field) { $field = explode(",", $field); echo "<li>Field with name : '$field[0]', of '$field[1]' type and with a size of $field[2]"; }

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  • Passing Javascript value to PHP Variable using ajax

    - by shels
    I am trying to use a Flash detection script to assess whether Flash Plugin is enabled in the user browser so that a different page loads. The Flash detection script is as follows, using jquery 1.8.2 and jquery.jqplugin 1.0.2 <script type="text/javascript" src="jquery-1.8.2.min.js"></script> <script type="text/javascript" src="jquery.jqplugin.1.0.2.min.js"></script> <script type="text/javascript"> $(document).ready(function() { $("#withflash").hide(); $("#noflash").hide(); if ($.browser.flash == true) $("#withflash").show (); else $("#noflash").show (); }); </script> <div id="withflash">Flash Supported</div> <div id="noflash">Flash Not Supported</div> I get the display that "Flash Supported" if Flash Plugin is present.. I need to capture the value whether flash plugin value is true in a php variable $hasFlashSupport as below: <?php echo " $hasFlashSupport"; exit; ?> I am aware that PHP is server based and Javascript is client based.. Hence Ajax would be a nice option to capture the javascript variable to my php variable. I am totally ignorant about Ajax syntax and how to achieve it. Request the experts here to help me out with the code on how this can be achieved... Thanking all of you in advance..

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  • Performing a MYSQL query based off of $_GET results

    - by Michael N
    When a user clicks an item on my items page, it takes them to blank page template using $_GET to pass the item brand and model through. I'd like to perform another MYSQL query when that user clicks through to populate the blank page with the product details from my database. I'd like to retrieve the single row using the model number (unique ID) to populate the page with the information. I've tried a couple of things but am having a little difficulty. On my blank item page, I have $brand = $_GET['Brand']; $modelnumber = $_GET['ModelNumber']; $query = mysql_query("SELECT * FROM items WHERE `Model Number` = '$modelnumber'"); $results = mysql_fetch_row($query); echo $results; I think having ''s around Model Number is causing troubles, but without them, I get a Warning: mysql_fetch_row() expects parameter 1 to be resource, boolean given error. My database columns looks like Brand | Model Number | Price | Description | Image A few other things I have tried include $query = mysql_query("SELECT * FROM item WHERE Model Number = $_GET['ModelNumber']"); Which gave me a syntax error. I've also tried concatenating the $_GET which gives me a mysql_fetch_row() expects parameter 1 to be resource, boolean given error Which leads me to believe that I'm also going about displaying the results incorrectly. I'm not sure if I need to put it in a where loop like I have with my previous page which displays all items in the database because this is just displaying one.

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  • retrieving variables with jquery ajax

    - by vick
    <div class="lead_detail_box_routing"> <div class="lead_detail_box_left">location 1</div> <div class="lead_detail_box_right">Route</div> <div class="lead_detail_box_left">location 2</div> <div class="lead_detail_box_right">Route</div> <div class="lead_detail_box_left">location 3</div> <div class="lead_detail_box_right">Route</div> <div class="lead_detail_box_left">location 4</div> <div class="lead_detail_box_right">Route</div> <div id="results" style="text-align:center;"></div> </div> <!-- end lead_detail and routing--> e.g. when user clicks on "route" I want my jquery-manual-routing.php to get the "3" .. so far I have: <script type="text/javascript"> $(document).ready(function() { $("a#route").click(function() { $("#results").load( "jquery-manual-routing.php", { route_to: ???? } ); return false; }); }); </script> so in my php script, when the user clicks on route next to location 3 I want to be able to grab $_GET['route_to'] =3; Also note that my table already has the class assigned since I am using css to style it The answer will be pure php echo

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  • sprintf bug with php & apache in windows?

    - by potatoe
    I've run into a strange problem on a WAMP server setup (PHP version 5.3.0, Apache 2.2.11). When using sprintf to output a number, I occasionally get erroneous characters in the output string. Example: (not trimmed from anything, this is the only code in the script) $dt1 = new DateTime('now'); $dt2 = new DateTime('now - 10 min'); $interval = $dt1->diff($dt2); $number = 10.0; $string = sprintf("%.1f", $number); echo "number: $number, string: $string\n"; If I run this at the command prompt with PHP CLI, I get the expected output: number: 10, string: 10.0 However, if I serve it using Apache, in the browser I get number: 10, string: :.0 with a colon where '10' should be. (Note that ':' is the next ascii character in sequence after '9', if $number is 0-9, everything works. Numbers greater than 10 appear to use ascii equivalents - so 11 is ';', 12 is '<', etc.) The strangest part is that the first four lines in the above code sample seem to affect the results. Logically, those statements should have no impact, but if I comment them out or remove them the problem goes away. Any ideas? Anyone else able to replicate this?

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  • curl run out very slowly.

    - by sabuj
    here is my code bellow: $url = "http://localhost/Test/post_output.php"; $post_data = array ( "foo" => "bar", "query" => "Nettuts", "action" => "Submit" ); $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $url); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); // we are doing a POST request curl_setopt($ch, CURLOPT_POST, 1); // adding the post variables to the request curl_setopt($ch, CURLOPT_POSTFIELDS, $post_data); curl_setopt($ch, CURLINFO_HEADER_OUT, true); curl_setopt($ch, CURLOPT_VERBOSE, true); // some output will go to stderr / error_log curl_setopt($ch, CURLOPT_TIMEOUT, 10); curl_setopt(CURLOPT_CONNECTTIMEOUT, 5); $output = curl_exec($ch); $errStr = curl_error($ch); $errNum = curl_errno($ch); $head = curl_getinfo($ch, CURLINFO_HEADER_OUT); $ci = curl_getinfo($ch); print_r(array($head, $errStr, $errNum, $ci)); exit; curl_close($ch); echo $output; This script outputs very slowly. Even outputs nothing... can anyone help out this. Thanks...

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  • How to first get different related values from diferent SQL tables (PHP)

    - by Ole Jak
    I am triig to fill options list. I have 2 tables USERS and STREAMS I vant to get all streams and get names of users assigned to that streams. Users consists of username and id Streams consists of id, userID, streamID I try such code: <?php global $connection; $query = "SELECT * FROM streams "; $streams_set = mysql_query($query, $connection); confirm_query($streams_set); $streams_count = mysql_num_rows($streams_set); while ($row = mysql_fetch_array($streams_set)){ $userid = $row['userID']; global $connection; $query2 = "SELECT email, username "; $query2 .= "FROM users "; $query2 .= "WHERE id = '{$userid}' "; $qs = mysql_query($query2, $connection); confirm_query($qs); $found_user = mysql_fetch_array($qs); echo ' <option value="'.$row['streamID'].'">'.$row['userID'].$found_user.'</option> '; } ?> But it does not return USER names from DB=( So what shall I do to this code to see usernames as "options" text?

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