Search Results

Search found 14509 results on 581 pages for 'print driver'.

Page 246/581 | < Previous Page | 242 243 244 245 246 247 248 249 250 251 252 253  | Next Page >

  • Debugging (displaying) SQL command sent to the db by SQLAlchemy

    - by morpheous
    I have an ORM class called Person, which wraps around a person table: After setting up the connection to the db etc, I run the ff statement. people = session.query(Person).all() The person table does not contain any data (as yet), so when I print the variable people, I get an empty list. I renamed the table referred to in my ORM class People, to people_foo (which does not exist). I then run the script again. I was surprised that no exception was thrown when attempting to access a table that does not exist. I therefore have the following 2 questions: How may I setup SQLAlchemy so that it propagates db errors back to the script? How may I view (i.e. print) the SQL that is being sent to the db engine If it helps, I am using PostgreSQL as the db

    Read the article

  • Why is this Python class copying another class contents?

    - by fjfnaranjo
    Hello guys. I'm trying to understand an estrange behavior in Python. I have the next python code: class IntContainer: listOfInts = [] def __init__(self, initListOfInts): for i in initListOfInts: self.listOfInts.append(i) def printInts(self): print self.listOfInts if __name__ == "__main__": intsGroup1 = [1,2,3,4] intsGroup2 = [4,5,6,7] intsGroups = [intsGroup1,intsGroup2] intsContainers = [] for ig in intsGroups: newIntContainer = IntContainer(ig) intsContainers.append(newIntContainer) for ic in intsContainers: print ic.listOfInts I expect to get something like: [1, 2, 3, 4] [4, 5, 6, 7] But i get: [1, 2, 3, 4, 4, 5, 6, 7] [1, 2, 3, 4, 4, 5, 6, 7] I have check the next question: http://stackoverflow.com/questions/1876905/why-is-python-reusing-a-class-instance-inside-in-function And a lot of Python reference, but I can not understand what is happening. I think is related with the newIntContainer identifier reutilization, but I do not understand it deeply. Why Python appears to reused the last reference for the new object, even if I have added it to a permanent list? What can I do to resolve this behavior? Thanks ;)

    Read the article

  • The return value should be a list but doesn't return as expected?! - Python newbie

    - by user1432941
    Hi this must be a very simple solution that has eluded me this last hour. I've tried to build this test function where the return value of the test_cases list should match the values in the test_case_answers list but for some reason, test case 1 and test case 2 fail. When i print the return values for the test cases they return the correct answers, but for some reason test case 1 and test case 2 return False. Thanks for your help! import math test_cases = [1, 9, -3] test_case_answers = [1, 3, 0] def custom_sqrt(num): for i in range(len(test_cases)): if test_cases[i] >= 0: return math.sqrt(test_cases[i]) else: return 0 for i in range(len(test_cases)): if custom_sqrt(test_cases[i]) != test_case_answers[i]: print "Test Case #", i, "failed!" custom_sqrt(test_cases)

    Read the article

  • Parse and Break: why break cannot be used for getting out of "any" or "some" rule ?

    - by Rebol Tutorial
    Let say I have to parse a hierarchical set of tags <tag> <subtag1 attr1=value1 attr2=value2> <subtag1 attr1=value1 attr2=value2> <subtag1 attr1=value1 attr2=value2> </tag> Why can't I use break inside some or any to get out of a level hierarchy ? This would allow to do that kind of parsing instead of having a headache to do so ? I'm asking this because I read here http://www.codeconscious.com/rebol/parse-tutorial.html it would create an infinite loop This case produces an infinite loop. Because the BREAK is within a sub-rule of the rule that SOME is processing. The BREAK does not affect success/failure status or the input pointer - it just exits a rule early: rule-to-break: [(print "Break") break] == [(print "Break") break] parse "X" [some [rule-to-break] "X"] Break *Break* ... Break *Break*(escape)

    Read the article

  • Regular Expression Program

    - by david robers
    Hi I have the following text: SMWABCCA ABCCAEZZRHM NABCCAYJG XABCCA ABCCADK ABCCASKIYRH ABCCAKY PQABCCAK ABCCAKQ This method takes a regex in out by the user and SHOULD print out the Strings it applies to but seems to print out something completely different: private void matchIt(String regex) { Pattern p = Pattern.compile(regex); Matcher m = null; boolean found = false; for(int i = 0; i < data.length; i++){ m = p.matcher(data[i]); if(m.find()){ out.println(data[i]); found = true; } } if(!found){ out.println("Pattern Not Found"); } } When inputting "[C]" It outputs: SMWABCCA ABCCAEZZRHM NABCCAYJG XABCCA ABCCADK ABCCASKIYRH ABCCAKY PQABCCAK ABCCAKQ Any ideas why? I think I'm using m.find() improperly...

    Read the article

  • Json request with Javascript

    - by chota
    Hi, I am just beginner on java script and JSON and never had done any work in these before. My employer has just asked me to create the basic POC of these. Scenario: I have a REST API and when i call it, it returns back response in JSON format. Need to To: Create a HTML page and use javascript to call that REST API and capture JSON response and print in the same HTML page. <script type="text/javascript"> function loadMe() { loadJSON('http://myrestAPI'); } function loadJSON(url) { //Help me here to capture the response and print in html page. } </script> I would appreciate your help. This might be simple, but for me i have no idea because i never have done anything similar in java script and json. I goggled but could not find anything. Thanks, chota

    Read the article

  • Why use threading data race will occur, but will not use gevent

    - by onlytiancai
    My test code is as follows, using threading, count is not 5,000,000 , so there has been data race, but using gevent, count is 5,000,000, there was no data race . Is not gevent coroutine execution will atom "count + = 1", rather than split into a one CPU instruction to execute? # -*- coding: utf-8 -*- import threading use_gevent = True use_debug = False cycles_count = 100*10000 if use_gevent: from gevent import monkey monkey.patch_thread() count = 0 class Counter(threading.Thread): def __init__(self, name): self.thread_name = name super(Counter, self).__init__(name=name) def run(self): global count for i in xrange(cycles_count): if use_debug: print '%s:%s' % (self.thread_name, count) count = count + 1 counters = [Counter('thread:%s' % i) for i in range(5)] for counter in counters: counter.start() for counter in counters: counter.join() print 'count=%s' % count

    Read the article

  • python compare time

    - by Jesse Siu
    i want to using python create filter for a log file. get recent 7 days record. but when i didn't know how to compare time. like current time is 11/9/2012, i want to get records from 04/9/2012 to now the log file like Sat Sep 2 03:32:13 2012 [pid 12461] CONNECT: Client "66.249.68.236" Sat Sep 2 03:32:13 2012 [pid 12460] [ftp] OK LOGIN: Client "66.249.68.236", anon password "[email protected]" Sat Sep 2 03:32:14 2012 [pid 12462] [ftp] OK DOWNLOAD: Client "66.249.68.236", "/pub/10.5524/100001_101000/100022/readme.txt", 451 i using this one def OnlyRecent(line): print time.strptime(line.split("[")[0].strip(),"%a %b %d %H:%M:%S %Y") print time.time() if time.strptime(line.split("[")[0].strip(),"%a %b %d %H:%M:%S %Y") < time.time(): return True return False But it shows (2012, 9, 2, 3, 32, 13, 5, 246, -1) 1347332968.08 (2012, 9, 2, 3, 32, 13, 5, 246, -1) 1347332968.08 (2012, 9, 2, 3, 32, 14, 5, 246, -1) 1347332968.08 the time format is different, and it can't compare time. So how to set this comparison in 7 days. Thanks

    Read the article

  • remove the spaces...

    - by tekknolagi
    !/usr/bin/python import random lower_a = ['a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z'] upper_a = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z'] num = ['0', '1', '2', '3', '4', '5', '6', '7', '8', '9'] all = [] all = " ".join("".join(lower_a) + "".join(upper_a) + "".join(num)) all = all.split() x = 0 while x < 10: for i in range(7): a = random.choice(all) print a, print x += 1 what i want to do is remove the spaces from the output what it gives now is Z 3 a A I K R G B i N 9 c E v g E r A N 8 e B 6 d v H O c a V 8 c x y b g 2 W a T T f 8 H T r 6 E p D K l 5 p u x q 8 P Z 9 T n I W X n B Q

    Read the article

  • Alternative to css3 not selector

    - by Raynos
    Are there any alternatives to the :not css3 selector that are compliant with IE8 (and quirks mode). Either in css or javascript/jquery that emulates the selector or something similar. I am using *:not as follows below. Feel free to recommend a solution that avoids the use of :not completely. @media screen { #printable { visibility: hidden; } } @media print { *:not(#printable) { visibility: hidden; } #printable { position: absolute; visibility: visible; } } Note that the use of :not is tied to the use of @media print so just using a simple jQuery solution to apply css to $(":not(#printable)") won't work without being clever. Including an entire library like ie9.js or selectivirz isn't an option as it can effect various other parts of the pages and would involve a large section of re-testing. a jsfiddle that shows it working in browsers that support :not http://jsfiddle.net/Raynos/TjKbz/

    Read the article

  • Check and avoid if a char is being entered in a int

    - by John
    Hi.... This is a exremely stupid question but i need help with this.... I'm trying to make a small program that i made robust and needed some help with tht.... int num1; int num2 = 0; System.out.print("Enter number 1: "); num1 = kb.nextInt(); while(num2<num1) { System.out.print("Enter number 2: "); num2 = kb.nextInt(); } Number 2 has to be greater than number 1 Also i want the program to automatically check and ignore if the user enters a char instead of an int... Cause right now when a user enters lets say "r" instead of a number the program just exists....

    Read the article

  • Why is Python 3.1 throwing a SyntaxError when printing after loop?

    - by bubersson
    Hi, I'm trying to run this snippet in Python 3.1 console and I'm getting SyntaxError: >>> while True: ... a=5 ... if a<6: ... break ... print("hello") File "<stdin>", line 5 print("hello") ^ SyntaxError: invalid syntax >>> (This is just shortened code to make a point.) Am I missing something? Is there some other Magic I don't know about? Thanks for your help (since this is my first StackOverflow question and I'm not a native English speaker)

    Read the article

  • TCP Scanner Python MultiThreaded

    - by user1473508
    I'm trying to build a small tcp scanner for a netmask. The code is as follow: import socket,sys,re,struct from socket import * host = sys.argv[1] def RunScanner(host): s = socket(AF_INET, SOCK_STREAM) s.connect((host,80)) s.settimeout(0.1) String = "GET / HTTP/1.0" s.send(String) data = s.recv(1024) if data: print "host: %s have port 80 open"%(host) Slash = re.search("/", str(host)) if Slash : netR,_,Wholemask = host.partition('/') Wholemask = int(Wholemask) netR = struct.unpack("!L",inet_aton(netR))[0] for host in (inet_ntoa(struct.pack("!L", netR+n)) for n in range(0, 1<<32-Wholemask)): try: print "Doing host",host RunScanner(host) except: pass else: RunScanner(host) To launch : python script.py 10.50.23.0/24 The problem I'm having is that even with a ridiculous low settimeout value set, it takes ages to cover the 255 ip addresses since most of them are not assigned to a machine. How can i make a way faster scanner that wont get stuck if the port is close.MultiThreading ? Thanks !

    Read the article

  • In Python, is it better to use list comprehensions or for-each loops?

    - by froadie
    Which of the following is better to use and why? Method 1: for k, v in os.environ.items() print "%s=%s" % (k, v) Method 2: print "\n".join(["%s=%s" % (k, v) for k,v in os.environ.items()]) I tend to lead towards the first as more understandable, but that might just be because I'm new to Python and list comprehensions are still somewhat foreign to me. Is the second way considered more Pythonic? I'm assuming there's no performance difference, but I may be wrong. What would be the advantages and disadvantages of these 2 techniques? (Code taken from Dive into Python)

    Read the article

  • How to write a list to a text file in the correct format

    - by lia1000
    I've got this piece of code that I want to write the output to a text file but with the correct format i.e. no brackets, single quotes so it appears as a formatted list. This is the code: file = open("env5.txt", "w"); for key in os.environ.keys(): env = os.environ[key]; key1 = key; list = str([key, env]).replace("'","").replace('[]', ''); list2 = list[1:-1]; print(list2); file.writelines(list2); file.close(); This is the original code: for key in os.environ.keys(): print(key, os.environ[key]); Many thanks

    Read the article

  • My cookies won't stay (PHP).

    - by RemiX
    I'm building an autologin system using cookies, but one fundamental part of the functionality of the cookies fails: they are non-persistent over different sessions - or even pages! In my login script, I set the cookies like this: setcookie('userID', $userID, time()+86400); // (edited after replies) $userID has a value. Then I print the $_COOKIE variable and it says array(['base_usid'] = 1); So that's good, but when I click the home page and print the $_COOKIE variable there, it says NULL. Does anyone see the problem?

    Read the article

  • Python: Give a class its own `self` at instantiation time

    - by SuperDisk
    I've got a button class that you can instantiate like so: engine.createElement((0, 0), Button(code=print, args=("Stuff!",))) And when it is clicked it will print "Stuff!". However, I need the button to destroy itself whenever it is clicked. Something like this: engine.createElement((0, 0), Button(code=engine.killElement, args=(self,))) However, that would just kill the caller, because self refers to the caller at that moment. What I need to do is give the class its own 'self' in advance... I thought of just making the string 'self' refer to the self variable upon click, but what if I wanted to use the string 'self' in the arguments? What is the way to do this? Is my architecture all wrong or something? Thanks.

    Read the article

  • In Python what's the best way to emulate Perl's __END__?

    - by FM
    Am I correct in thinking that that Python doesn't have a direct equivalent for Perl's __END__? print "Perl...\n"; __END__ End of code. I can put anything I want here. One thought that occurred to me was to use a triple-quoted string. Is there a better way to achieve this in Python? print "Python..." """ End of code. I can put anything I want here. """

    Read the article

  • Resetting a while loop

    - by Patrick Beardmore
    I have found a confusing thing in a php script I am writing to generate some javascript. Here it is below, slightly simplified. The second while loop won't run unless I comment out the entire first while loop. Can anyone explain why? Many thanks. <?php $listid = 2; //DEMO ONLY $result1 = mysql_query("SELECT words.wid,words.wordmd5,words.word FROM words,instances WHERE words.wid = instances.wid AND instances.lid = \"$listid\""); $result1copy = $result1; $count1 = 1; while( $row = mysql_fetch_object( $result1 ) ) { print "words_left[$count1] = \"".$row->word."\";\n"; //Increment the array counter (starts at 1) $count1++; } ?> //Some javascript <?php $count2 = 1; while( $row = mysql_fetch_object( $result1copy ) ) { print " $count2 then $row->wordmd5 "; $count2++; } ?>

    Read the article

  • can list be converted into string

    - by PARIJAT
    Actually i have extracted some data from the file and want to write it in the file 2 but the program says 'sequence item 1: expected string, list found', I want to know how i can convert buffer[] ie string into sequence, so that it could be saved in file 2...I am new to the python please help* file = open('/ddfs/user/data/k/ktrip_01/hmm.txt','r') file2 = open('/ddfs/user/data/k/ktrip_01/hmm_write.txt','w') buffer = [] rec = file.readlines() for line in rec : field = line.split() print '>',field[0] term = field[0] buffer.append(term) print field[1], field[2], field[6], field[12] term1 = field [1] buffer.append(term1) term2 = field[2] buffer.append[term2] term3 = field[6] buffer.append[term3] term4 = field[12] buffer.append[term4] file2.write(buffer) file.close() file2.close()

    Read the article

  • Why doesn't list.get(0).equals(null) work?

    - by Jessy
    The first index is set to null (empty), but it doesn't print the right output, why? //set the first index as null and the rest as "High" String a []= {null,"High","High","High","High","High"}; //add array to arraylist ArrayList<Object> choice = new ArrayList<Object>(Arrays.asList(a)); for(int i=0; i<choice.size(); i++){ if(i==0){ if(choice.get(0).equals(null)) System.out.println("I am empty"); //it doesn't print this output } }

    Read the article

  • PHP variable question

    - by Kyle Parisi
    This works: $customerBox = mysql_query("MY SQL STATEMENT HERE"); $boxRow = mysql_fetch_array($customerBox); $customerBox = mysql_query("MY SQL STATEMENT AGAIN"); while($item = mysql_fetch_assoc($customerBox)) { foreach ($item as $columnName = $value) { if (empty($value)) { print $columnName; } } } This does not: $customerBox = mysql_query("MY SQL STATEMENT HERE"); $boxRow = mysql_fetch_array($customerBox); while($item = mysql_fetch_assoc($customerBox)) { foreach ($item as $columnName = $value) { if (empty($value)) { print $columnName; } } } Why? I guess I don't understand how variables work yet.

    Read the article

  • Subtype polymorphism and arrays

    - by user133466
    Computer[] labComputers = new Computer[10]; with public class Computer { ... void toString(){ // print computer specs } } public class Notebook extends Computer{ ... void toString(){ // print computer specs + laptop color } } each subscripted variable labComputers[i] can reference either a Computer object or a Notebook object because Notebook is a subclass of Computer. For the method call labComputers[i].toString(), polymorphism ensures that the correct toString method is called. I wonder what if we do Notebook[] labComputers = new Notebook[10]; what kind or error would I get if I reference with Computer object and a Notebook object

    Read the article

  • Pagination, next page doesn`t display

    - by user1738013
    if I click page 2 that`s error: Not Found The requested URL /rank/GetAll/30 was not found on this server. My link is: http://localhost/rank/GetAll/30 Model: Rank_Model <?php Class Rank_Model extends CI_Model { public function __construct() { parent::__construct(); } public function record_count() { return $this->db->count_all("ranking"); } public function fifa_rank($limit, $start) { $this->db->limit($limit, $start); $query = $this->db->get("ranking"); if ($query->num_rows() > 0) { foreach ($query->result() as $row) { $data[] = $row; } return $data; } return false; } } ?> Controller: Rank <?php if ( ! defined('BASEPATH')) exit('No direct script access allowed'); class rank extends CI_Controller { function __construct() { parent::__construct(); $this->load->helper("url"); $this->load->helper(array('form', 'url')); $this->load->model('Rank_Model','',TRUE); $this->load->library("pagination"); } function GetAll() { $config = array(); $config["base_url"] = base_url() . "rank/GetAll"; $config["total_rows"] = $this->Rank_Model->record_count(); $config["per_page"] = 30; $config["uri_segment"] = 3; $this->pagination->initialize($config); $page = ($this->uri->segment(3)) ? $this->uri->segment(3) : 0; $data["results"] = $this->Rank_Model->fifa_rank($config["per_page"], $page); $data['errors_login'] = array(); $data["links"] = $this->pagination->create_links(); $this->load->view('left_column/open_fifa_rank',$data); } } View Open: open_fifa_rank <?php $this->load->view('mains/header'); $this->load->view('login/loggin'); $this->load->view('mains/menu'); $this->load->view('left_column/left_column_before'); $this->load->view('left_column/menu_left'); $this->load->view('left_column/left_column'); $this->load->view('center/center_column_before'); $this->load->view('left_column/fifa_rank'); $this->load->view('center/center_column'); $this->load->view('right_column/right_column_before'); $this->load->view('login/zaloguj'); $this->load->view('right_column/right_column'); $this->load->view('mains/footer'); ?> and View: fifa_rank <table> <thead> <tr> <td>Pozycja</td> <td>Kraj</td> <td>Punkty</td> <td>Zmiana</td> </tr> </thead> <?php foreach($results as $data) {?&gt; <tbody> <tr> <td><?php print $data->pozycja;?></td> <td><?php print $data->kraj;?></td> <td><?php print $data->punkty;?></td> <td><?php print $data->zmiana;?></td> </tr> <?php } ?> </tbody> </table> <p><?php echo $links; ?></p> Maybe you know where is my problem? Now I know where is my problem. In first page I have link: http://localhost/index.php/rank/GetAll But on the next: http://localhost/rank/GetAll/30 In secend link, I don`t have index.php. How can I fix it?

    Read the article

< Previous Page | 242 243 244 245 246 247 248 249 250 251 252 253  | Next Page >