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  • In C/C++ mode in Emacs, change face of code in #if 0...#endif block to comment face

    - by pogopop77
    I'm trying to add functionality found in some other code editors to my Emacs configuration, whereby C/C++ code within #if 0...#endif blocks is automatically set to the comment face/font. Based on my testing, cpp-highlight-mode does something like what I want, but requires user action. It seems like tying into the font-lock functionality is the correct option to make the behavior automatic. I have successfully followed examples in the GNU documentation to change the face of single-line regular expressions. For example: (add-hook 'c-mode-common-hook (lambda () (font-lock-add-keywords nil '(("\\<\\(FIXME\\|TODO\\|HACK\\|fixme\\|todo\\|hack\\)" 1 font-lock-warning-face t))))) works fine to highlight debug related keywords anywhere in a file. However, I am having problems matching #if 0...#endif as a multiline regular expression. I found some useful information in this post (How to compose region like ""), that suggested that Emacs must be told specifically to allow for multiline matches. But this code: (add-hook 'c-mode-common-hook (lambda () '(progn (setq font-lock-multiline t) (font-lock-add-keywords nil '(("#if 0\\(.\\|\n\\)*?#endif" 1 font-lock-comment-face t)))))) still does not work for me. Perhaps my regular expression is wrong (though it appears to work using M-x re-builder), I've messed up my syntax, or I'm following the wrong approach entirely. I'm using Aquamacs 2.1 (which is based on GNU Emacs 23.2.50.1) on OS X 10.6.5, if that makes a difference. Any assistance would be appreciated!

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  • Java String.split

    - by user903772
    I have the following text: ARIYALUR:ARIYALUR|CHENNAI:CHENNAI|COIMBATORE:COIMBATORE|CUDDALORE:CUDDALORE|DINDIGUL:DINDIGUL|ERODE:ERODE|KANCHEEPURAM:KANCHEEPURAM|KANYAKUMARI:KANYAKUMARI|KRISHNAGIRI:KRISHNAGIRI|MADURAI:MADURAI|NAMAKKAL:NAMAKKAL|NILGIRIS:NILGIRIS|PERAMBALUR:PERAMBALUR|PONDICHERRY:PONDICHERRY|SALEM:SALEM|THANJAVUR:THANJAVUR|THENI:THENI|THIRUVALLUR:THIRUVALLUR|THOOTHUKUDI:THOOTHUKUDI|TIRUNELVELI:TIRUNELVELI|VELLORE:VELLORE|VILLUPURAM:VILLUPURAM|VIRUDHUNAGAR:VIRUDHUNAGAR| I tried to do a split("|") but my array is made up of alphabets and not each district. Please help.

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  • Retain Delimiters when Splitting String

    - by JoeC
    Edit: OK, I can't read, thanks to Col. Shrapnel for the help. If anyone comes here looking for the same thing to be answered... print_r(preg_split('/([\!|\?|\.|\!\?])/', $string, null, PREG_SPLIT_DELIM_CAPTURE)); Is there any way to split a string on a set of delimiters, and retain the position and character(s) of the delimiter after the split? For example, using delimiters of ! ? . !? turning this: $string = 'Hello. A question? How strange! Maybe even surreal!? Who knows.'; into this array('Hello', '.', 'A question', '?', 'How strange', '!', 'Maybe even surreal', '!?', 'Who knows', '.'); Currently I'm trying to use print_r(preg_split('/([\!|\?|\.|\!\?])/', $string)); to capture the delimiters as a subpattern, but I'm not having much luck.

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  • Extract string that is delimited with constant and ends with two numbers (numbers have to be included)

    - by Edmon
    I have a text that contains string of a following structure: text I do not care about, persons name followed by two IDs. I know that: a person's name is always preceded by XYZ code and that is always followed by two, space separated numbers. Name is not always just a last name and first name. It can be multiple last or first names (think Latin american names). So, I am looking to extract string that follows the constant XYZ code and that is always terminated by two separate numbers. You can say that my delimiter is XYZ and two numbers, but numbers need to be part of the extracted value as well. From blah, blah XYZ names, names 122322 344322 blah blah I want to extract: names, names 122322 344322 Would someone please advise on the regular expression for this that would work with Python's re package.

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  • regular expression for challenge value

    - by Salman
    Hi what will be the regular expression to extract challenge var value i am interested in this vlaue 03AHJ_Vut9LJLOJuCsjF9PbSSMncTyUe7Y4dHX11eRLae3LGfDZ0hSfDR7jZq2ZrKJxyC-LRSSppv72oHKaQMsd-EnoVNL6p7liTh7siN26zzTA_E2rcC_JQ15613Azz4qm8HjPtAyksUdc7QZydszwolk92hBPrAAig this value changes every time we refresh it so the expression has to be generic enough to pick up what ever is the value var RecaptchaState = { site : '6LeKCL8SAAAAADV5Dr-lfY2eOEV8rubeN25BAKp2', challenge : '03AHJ_Vut9LJLOJuCsjF9PbSSMncTyUe7Y4dHX11eRLae3LGfDZ0hSfDR7jZq2ZrKJxyC-LRSSppv72oHKaQMsd-EnoVNL6p7liTh7siN26zzTA_E2rcC_JQ15613Azz4qm8HjPtAyksUdc7QZydszwolk92hBPrAAig', is_incorrect : false, programming_error : '', error_message : '', server : 'http://www.google.com/recaptcha/api/', timeout : 18000}; any help will be appreciated, or any method to extract this value in any server side lang

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  • I am using a regex snippet query string path

    - by Shelby Poston
    Using the following to load images base on two ids one is the and bookid and the out is the client. My folder structures is this. root path = flipbooks subfolders under flipbooks are books and clients in subfolder books I have and .net page title tablet. the tablet code behind checks the bookid of client and render a the tablet page with images in a flipbook fashion. because we have over 15000 records and flipbooks already created and stored in the database. I don't move the client folder under the books subfolders. I need the code below to get to the client subfolder in the query string and help to change this would be helpful. The result now is http://www.somewebsite.com/books/client/images/someimage1.jpg[^] I need the results to be http://www.somewebsite.com/client/images/someimage1.jpg[^]. I tried moving the tablet.aspx file to the root flipbooks and it works but i have provide a user name and password each time. This need to be access by the public and my root is protected. Don't want to have to change permission. I am trying to remove the /books function getParameterByName(name) { var results = RegExp('[?&]' + name + '=([^&]*)').exec(window.location.search); return results ? decodeURIComponent(results[1].replace(/\+/g, ' ')) : null; } Thanks Mission Critical

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  • Selectively search and replace certain lines using a regular expression

    - by eneveu
    I have a file containing a lot of SQL statements, such as: CREATE TABLE "USER" ( "ID" INTEGER PRIMARY KEY, "NAME" CHARACTER VARYING(50) NOT NULL, "AGE" INTEGER NOT NULL ); COPY "USER" (id, name, age) FROM stdin; 1 Skywalker 19 2 Kenobi 57 I want the column names in the COPY statements to be uppercased and quoted: COPY "USER" ("ID", "NAME", "AGE") FROM stdin; Using sed, I found the following regexp: sed -r 's/([( ])(\w+)([,)])/\1"\U\2\E"\3/g' It does replace the column names, but it is not selective enough, and replaces other words in the file: ~/test]$sed -r 's/([( ])(\w+)([,)])/\1"\U\2\E"\3/g' star_wars_example CREATE TABLE "USER" ( "ID" INTEGER PRIMARY "KEY", "NAME" CHARACTER VARYING("50")NOT "NULL", "AGE" INTEGER NOT NULL ); COPY "USER" ("ID", "NAME", "AGE") FROM stdin; 1 Skywalker 19 2 Kenobi 57 To avoid this problem, I want sed to only apply my regexp to the lines starting with COPY and ending with FROM stdin;. I have looked into lookahead / lookbehind, but they are not supported in sed. They seem to be supported in super-sed, but I am currently using Cygwin (Windows is mandatory here...) and it does not seem available in the package list. Is there a way to force sed to only consider specific line? I've considered piping my file through grep before applying sed, but other lines will then disappear from the output. Am I missing something obvious? It would be great if the answer was easily applicable on a default Cygwin install. I guess I could try installing super-sed on cygwin, but I'd like to know if there are more obvious ideas

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  • Javascript place in header

    - by JibW
    I am not clear why its not working the javascript code when I add it to the header section as follows. We can place a javascript code within the body as follows <html> <head> <title> Simple Test </title> </head> <body> <div id="mydiv"> This is the div content </div> <script type="text/javascript" > document.getElementById("mydiv").innerHTML=Date(); </script> </body> </html> But when I place the same JavaScript code in the header section it doesn't work. <html> <head> <title> Simple Test </title> <script type="text/javascript" > document.getElementById("mydiv").innerHTML=Date(); </script> </head> Can Someone please explain the issue. I know I can Write a JavaScript function in header and call it in an event. But can't we Use in this way. If Can't why.

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  • Removing whitespace in Java string?

    - by waitinforatrain
    Hi guys, I'm writing a parser for some LISP files. I'm trying to get rid of leading whitespace in a string. The string contents are along the lines of: :FUNCTION (LAMBDA (DELTA PLASMA-IN-0) (IF (OR (>= #61=(+ (* 1 DELTA) PLASMA-IN-0) 100) (<= #61# 0)) PLASMA-IN-0 #61#)) The tabs are all printed as 4 spaces in the file, so I want to get rid of these leading tabs. I tried to do this: string.replaceAll("\\s{4}", " ") - but it had no effect at all on the string. Does anyone know what I'm doing wrong? Is it because it is a multi-line string? Thanks

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  • Regular Expression doesn't match

    - by dododedodonl
    Hi All, I've got a regular expression in my cocoa-touch app (using RegexKitLite). NSString *week = [[NSString alloc] initWithFormat:@"%@", [pageContent stringByReplacingOccurrencesOfRegex:@"<select name=\"week\" class=\"selectbox\" style='width:134' onChange=\"doDisplayTimetable(NavBar, topDir);\">(.+?)<option value=\"(.+?)\">(.+?)</option>" withString:@"$2"]]; I expect it to match with the section of this (what is in NSString pageContent): <span class="selection"> <nobr> Periode<br> <span class="absatz"> &nbsp;<br> </span> <select name="week" class="selectbox" style='width:134' onChange="doDisplayTimetable(NavBar, topDir);"> <option value="14">17-5 - 16-7</option> </select> </nobr> </span> But it doesn't... I need the value of the option, it is possible that there is more than one (in that case I need them both separated by a ,. Can someone help me out? Regards, Dodo

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  • Finding if a sentence contains a specific phrase in Ruby

    - by TenJack
    Right now I am seeing if a sentence contains a specific word by splitting the sentence into an array and then doing an include to see if it contains the word. Something like: "This is my awesome sentence.".split(" ").include?('awesome') But I'm wondering what the fastest way to do this with a phrase is. Like if I wanted to see if the sentence "This is my awesome sentence." contains the phrase "my awesome sentence". I am scraping sentences and comparing a very large number of phrases, so speed is somewhat important.

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  • User will input some filter criteria -- how can I turn it into a regular expression for String.match

    - by envinyater
    I have a program where the user will enter a string such as PropertyA = "abc_*" and I need to have the asterisk match any character. In my code, I'm grabbing the property value and replacing PropertyA with the actual value. For instance, it could be abc_123. I also pull out the equality symbol into a variable. It should be able to cover this type of criteria PropertyB = 'cba' PropertyC != '*-this' valueFromHeader is the lefthand side and value is the righthand side. if (equality.equals("=")) { result = valueFromHeader.matches(value); } else if (equality.equals("!=")) { result = !valueFromHeader.matches(value); } EDIT: The existing code had this type of replacement for regular expressions final String ESC = "\\$1"; final String NON_ALPHA = "([^A-Za-z0-9@])"; final String WILD = "*"; final String WILD_RE_TEMP = "@"; final String WILD_RE = ".*"; value = value.replace(WILD, WILD_RE_TEMP); value = value.replaceAll(NON_ALPHA,ESC); value = value.replace(WILD_RE_TEMP, WILD_RE); It doesn't like the underscore here... abcSite_123 != abcSite_123 (evaluates to true) abcSite_123$1.matches("abcSite$1123") It doesn't like the underscore...

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  • Getting the title of a page in PHP

    - by Francesc
    Hi. When I want to get the title of a remote webiste, I use this script: function get_remotetitle($urlpage) { $file = @fopen(($urlpage),"r"); $text = fread($file,16384); if (preg_match('/<title>(.*?)<\/title>/is',$text,$found)) { $title = $found[1]; } else { $title = 'Title N/A'; } return $title; } But when I parase a webiste title with accents, I get "?". But if I look in PHPMyAdmin, I see the accents correctly. What's happening?

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  • Mutually exclusive regular expressions

    - by CaptnCraig
    If I have a list of regular expressions, is there an easy way to determine that no two of them will both return a match for the same string? That is, the list is valid if and only if for all strings a maximum of one item in the list will match the entire string. It seems like this will be very hard (maybe impossible?) to prove definitively, but I can't seem to find any work on the subject. The reason I ask is that I am working on a tokenizer that accepts regexes, and I would like to ensure only one token at a time can match the head of the input.

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  • split with javascript

    - by Sourabh
    Hi below is something I am trying to do with JavaScript. If I have string like str = "how are you? hope you are doing good" ; now I want to split it with ? but I dont want to lose the "?". Instead I want to break the string just after the question mark such a way that question mark is with the first segment that we have after splitting str what should I get is ["how are you?","hope you are doing good"] I am not sure if it can be done with Javascript split() function ,please help.

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  • Is it possible to "learn" a regular expression by user-provided examples?

    - by DR
    Is it possible to "learn" a regular expression by user-provided examples? To clarify: I do not want to learn regular expressions. I want to create a program which "learns" a regular expression from examples which are interactively provided by a user, perhaps by selecting parts from a text or selecting begin or end markers. Is it possible? Are there algorithms, keywords, etc. which I can Google for? EDIT: Thank you for the answers, but I'm not interested in tools which provide this feature. I'm looking for theoretical information, like papers, tutorials, source code, names of algorithms, so I can create something for myself.

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  • Regular Expression - Capture and Replace Select Sequences

    - by Chad
    Take the following file... ABCD,1234,http://example.com/mpe.exthttp://example/xyz.ext EFGH,5678,http://example.com/wer.exthttp://example/ljn.ext Note that "ext" is a constant file extension throughout the file. I am looking for an expression to turn that file into something like this... ABCD,1234,http://example.com/mpe.ext ABCD,1234,http://example/xyz.ext EFGH,5678,http://example.com/wer.ext EFGH,5678,http://example/ljn.ext In a nutshell I need to capture everything up to the urls. Then I need to capture each URL and put them on their own line with the leading capture. I am working with sed to do this and I cannot figure out how to make it work correctly. Any ideas?

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  • extract variables from an expression using javascript regexp

    - by powerboy
    For example, here is a string representing an expression: var str = 'total = sum(price * qty) * 1.09875'; I want to extract variables (i.e., 'total', 'price' and 'qty' but not 'sum' since 'sum' is a function name) from this expression. What is the regexp pattern in javascript? Variable name consists of letters, digits, or the underscore, beginning with letters or the underscore.

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  • regular expresson of variables

    - by Kevinniceguy
    what is re of string of 0 and 1 that contain an even number of zeros and even number of ones..... its not or in the middle....its an and...and even number of ones so i got something like (1*01*01*)*(0*10*10*)* does it look good?

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  • preg_replace - don't include string if $4 is blank

    - by bradenkeith
    I have this expression: $regex_phone = '/^(?:1(?:[. -])?)?(?:\((?=\d{3}\)))?([2-9]\d{2})' .'(?:(?<=\(\d{3})\))? ?(?:(?<=\d{3})[.-])?([2-9]\d{2})' .'[. -]?(\d{4})(?: (?i:ext)\.? ?(\d{1,5}))?$/'; if(!preg_match($regex_phone, $data['phone'])){ $error[] = "Please enter a valid phone number."; }else{ $data['phone'] = preg_replace($regex_phone, '($1) $2-$3 ext.$4', $data['phone']); } That will take a phone number such as: 803-888-8888 ext 2 as well as 803-888-8888 First number formats as: (803) 888-8888 ext.2 -- the desired effect Second number formats as: (803) 888-8888 ext. -- blank extension How can I set it so that if $4 is blank, that ext. won't show? Thanks so much for any help you can offer. I hope this was clear.

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