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  • using regular expression / Remove special characters with linq to sql

    - by Prasad
    How can i use regular expressions with linq to sql in the asp.net mvc(C#) application? The columns in my MSSQL table (Products) has some special characters like (, - % ',.....). While searching for a product i need to search without that special chareters. For ex.: I have a product say (ABC-Camp's / One), when i search for "abccamp", it should pull the product. I am trying the query like: from p in _context.pu_Products where p.User_Id == userId && p.Is_Deleted == false && p.Product_Name.ToLower().Contains(text.ToLower()) select new Product { ProductId = p.Product_Id, ProductName = p.Product_Name.Replace("’", "").Replace("\"", ""), RetailPrice = p.Retail_Price ?? 0M, LotSize = p.Lot_Size > 0 ? p.Lot_Size ?? 1 : 1, QuantityInHand = p.Quantity_In_Hand ?? 0 } But i need to search without any special characters...

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  • Get a number after a character in a string...

    - by James Rattray
    I'm making my own forums and I don't want any BB code on it, but instead my own, so i've gotten [b][u][img] working etc. But i'm having problems with [quote=1][/quote] where the number is the user id... E.G lets say I quote someone So once I submit my post: (The variable $post would be:) '[quote=1] Quoted post :P[/quote]' How would I then get the number out the string? (But not the wrong number -not a number in the quoted post) (So I could then use str_replace() to replace with a table which makes it looked quoted) ?? :)

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  • Replace String pattern in Java

    - by Hirantha
    I have the following string "value=\"\\d{4}((((0[1-9])|(1[0-2]))((0[1-9])|([12]\\d)|(3[01]))?)?|(\\-(((0[1-9])|(1[0-2]))(\\-((0[1-9])|([12]\\d)|(3[01])))?)?)?)d{4}" There I want to replace all the occurrences of "{" with NCHAR(0x7B) "}" with NCHAR(0x7D). An the content in-between "{ }" should remain unchanged: Ex: \\d{4} after replacing -> NCHAR(0x7B) 4 NCHAR(0x7D). Is there a way to do this using Regular Expressions in Java?. Anyway, this can be done processing the whole string using string operations.

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  • UIWebview :: Text :: HTML :: JS

    - by user306089
    hello, 1- i load a text from a txt file 2- i show it into a html "file" 3- problem : 3-a : this code works : i create my page by code and i insert my text myText = ... loaded from an array of texts ...; NSString *myDescriptionHTML = [NSString stringWithFormat:@"<html> \n" "<head> \n" "<style type=\"text/css\"> \n" "body {font-family: \"%@\"; font-size: 1.0f + 'em'; color:#FFF;}\n" "</style> \n" "</head> \n" "<body id=\"myid\">%@</body> \n" "</html>", @"Arial", myText]; [self.myWebView loadHTMLString:myDescriptionHTML baseURL:nil]; 3-b but this one does not work : i load a html page already created and i inject my text into using JS : myText = ... loaded from an array of texts ...; [self.myWebView stringByEvaluatingJavaScriptFromString:[NSString stringWithFormat:@"document.getElementById(\"myid\").innerHTML = \"%@\";", myText]]; 3-c but this one working : same as 3-b but i init my text with a string in the code itself : myText = @"hello all"; [self.myWebView stringByEvaluatingJavaScriptFromString:[NSString stringWithFormat:@"document.getElementById(\"myid\").innerHTML = \"%@\";", myText]]; any help to understand what's wrong with 3-b ? thank you

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  • Php regular expression to match a div

    - by Thoman
    Hello all <div id="a"> <div id="b"> Foo </div> <div id="m"> Bar </div> </div> <div id="c"> Bar </div> I want find all object in id="a" and out put is <div id="a"> <div id="b"> Foo </div> <div id="m"> Bar </div> </div> Geat thanks.

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  • regexp to match string with (comma-separated) number at start and to split into number and rest?

    - by mix
    Given a string such as: 23,234,456 first second third How can I split string this into two parts, where part 1 contains the number at the beginning and part 2 contains the rest---but only if the string STARTS with a number, and the number can be comma-separated or not? In other words, I want two results: 23,234,456 and first second third. If there's a number in that string that isn't part of the first number then it should be in the second result. My best stab at this so far, to grab the number at the beginning, is something like this: ^[0-9]+(,[0-9]{3})* Which seems to grab a comma-separated or non-comma-separated number that starts the line. However, when I run this in the Javascript console I get not only the full number, but also a match on just the last 3 digits with their preceeding ,. (e.g. 23,234,456 and ,456). As for getting the rest into another var I'm having trouble. I tried working with \b, etc., but I think I must be missing something fundamental about grabbing the rest of the line. I'm doing this in Javascript in case it matters. More examples of what to match and what not to match. 2 one two three should return 2 and one two three 2345 one two three should return 2345 and one two three 2 one 2 three should return 2 and one 2 three 2,234 one two 3,000 should return 2,234 and one two 3,000 The space between parts 1 and two could be included in the beginning of part 2.

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  • Position a div relative to a top-level container?

    - by Seifeddine Dridi
    I'm trying to model an HTML document which only contains div elements positioned in absolute. For each div, properties left and top are precalculated wrt. the top-level div, but a problem occurs with nested divs since according to the CSS standard an element is positioned relative to its first ancestral element whose positioning is either relative or absolute. Does anyone know any workaround? EDIT: small code snippet that demonstrates the problem <html> <body style="background-color: #444444"> <div style="position: relative; background-color: white;"> <div style="position: absolute; background-color: red; width: 4cm; height: 3cm; top: 1cm">div 1 <div style="position: absolute; background-color: green; top: 4cm"> div 1.1</div> </div> </div> </body> </html> The green div is expected to be positioned right after the red div, instead there is a gap of 1cm in between.

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  • How to using String.split in this case?

    - by hoang nguyen
    I want to write a fuction like that: - Input: "1" -> return : "1" - Input: "12" -> return : ["1","2"] If I use the function split(): String.valueOf("12").split("") -> ["","1","2"] But, I only want to get the result: ["1","2"]. What the best way to do this? Infact, I can do that: private List<String> decomposeQuantity(final int quantity) { LinkedList<String> list = new LinkedList<String>(); int parsedQuantity = quantity; while (parsedQuantity > 0) { list.push(String.valueOf(parsedQuantity % 10)); parsedQuantity = parsedQuantity / 10; } return list; } But, I want to use split() for having an affective code

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  • HTACCESS redirection with a word replacement in url

    - by Marwen
    I'm having trouble with this reg expression which i belive is correct, but it is not working. What im trying to do is redirect bunch of urls containing a specific string like this: http://www.example.com/**undesired-string**_another-string to http://www.example.com/**new-string**_another-string and http://www.example.com/folder/**undesired-string**/another-string to http://www.example.com/folder/**new-string**/another-string So i have this code in the .htaccess: <IfModule mod_rewrite.c> RewriteEngine On RewriteBase / RewriteRule (.+)+(undesired-string)+(.+) $1new-string$2 [R=301,L] </IfModule> This should replace ANY undesired-string in any url to new-string, but it is not working, any idea why ? Thank you

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  • Erroneous Matches with Regular Expression

    - by Ballsacian1
    $regexp = '/(?:<input\stype="hidden"\sname="){1}([a-zA-Z0-9]*)(?:"\svalue="1"\s\/>)/'; $response = '<input type="hidden" name="7d37dddd0eb2c85b8d394ef36b35f54f" value="1" />'; preg_match($regexp, $response, $matches); echo $matches[1]; // Outputs: 7d37dddd0eb2c85b8d394ef36b35f54f So I'm using this regular expression to search for an authentication token on a webpage implementing Joomla in order to preform a scripted login. I've got all this working but am wondering what is wrong with my regular expression as it always returns 2 items. Array ( [0] => [1] => 7d37dddd0eb2c85b8d394ef36b35f54f) Also the name of the input I'm checking for changes every page load both in length and name.

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  • Using BASH - Find CSS block or definition and print to screen

    - by Brian
    I have a number of .css files spread across some directories. I need to find those .css files, read them and if they contain a particular class definition, print it to the screen. For example, im looking for ".ExampleClass" and it exists in /includes/css/MyStyle.css, i would want the shell command to print .ExampleClass { color: #ff0000; }

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  • Using varible in re.match in python

    - by screwuphead
    I am trying to create an array of things to match in a description line. So I cant ignore them later on in my script. Below is a sample script that I have been working on, on the side. Basically I am trying to take a bunch of strings and match it against a bunch of other strings. AKA: asdf or asfs or wrtw in string = true continue with script if not print this. import re ignorelist = ['^test', '(.*)set'] def guess(a): for ignore in ignorelist: if re.match(ignore, a): return('LOSE!') else: return('WIN!') a = raw_input('Take a guess: ') print guess(a) Thanks

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  • How do i convert this Mod_rewrite rule to nginx

    - by bacho
    This is the Htacces rule: RewriteEngine on RewriteRule ^([A-Za-z0-9-]+)/?$ ir.php?id=$1 how should I pass it to a Nginx compliant rewrite rule... i read the doc and did this: rewrite ^([A-Za-z0-9-]+)/?$ ir.php?id=$1 last; But didnt work. and another question: Is there any equivalent of .htaccess to Nginx (per directory rules) Thanks

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  • ruby enclose selected whole words in brackets

    - by astropanic
    @string = "Sometimes some stupid people say some stupid words" @string.enclose_in_brackets("some") # => "Sometimes {some} stupid people say {some} stupid words" How should the method enclose_in_brackets look ? Please keep in mind, I want only enclose whole words, (I don't want "{Some}times {some} stupid....", the "sometimes" word should be left unchanged

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  • Allow alphanumeric, punctuation, and spaces

    - by bccarlso
    I'm pretty new to regular expressions, and MAN do they give me a headache. They are so intimidating! For an email campaign I'm doing, a user will click a link out of the email with a few URL parameters filled in for them, to make filling out a form easier. I want to prevent any injection hacks or whatever it's called, but need to allow the $_GET parameters to be alphanumeric, have punctuation, and have spaces. If someone has a good method for this, I'd appreciate it, but right now I have: foreach($_GET as $m=>$n) { $get[$m] = preg_replace('(^[a-z0-9 \-\_\.]+)i',' ',$n); } I would like to be able to replace all characters NOT found with this regular expression, which I believe I use ?!, but I can't get that to work either. Any help in getting this to work would be appreciated!

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  • JavaScript regular expressions to validate string

    - by Activist
    I'm not that good with regular expressions... I need a JavaScript regular expression that will do the following: The string can contain letters (upper and lower case), but not punctuations such as éàïç... The string can contain numbers (0..9) anywhere in the string, except on the first position. The string can contain underscores (_). Valid strings: foo foo1 foo_bar fooBar Invalid strings: 1foo -- number as first character foo bar -- space föo -- punctuation ö Many thanks!

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  • Javascript simple regexp doesn't work

    - by bah
    Hi, I have this code, it looks alright and is really basic, but i can't make it work: function checkValid(elem){ var abc = elem.value; var re = "/[0-9]/"; var match = re.test(abc); alert(match); } It matches 0 and 9, but not 1 to 8, what's wrong here? Thanks.

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  • How do you make a regular expression that matches a word with one randomly inserted character?

    - by Dfowj
    Hey all, i want to use a regular expression to match a word with one specified character randomly placed within it. I also want to keep that 'base' word's characters in their original order. For example, with the 'base' word of test and the specified character of 'y', i want the regular expression to match all the following, and ONLY the following: ytest, tyest, teyst, tesyt, testy Incase it matters, im working in javascript and using the dojo toolkit. Thanks!

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  • Trying to match what is before /../ but after / with regular expressions

    - by tim
    I am trying to match what is before /../ but after / with regular expressions, but i want it to look back and stop at the first / I feel like I am close but it just looks at the first slash and then takes everything after it like... input is this: this/is/a/./path/that/../includes/face/./stuff/../hat and my regular expression is #\/(.*)\.\.\/# matching /is/a/./path/that/../includes/face/./stuff/../ instead of just that/../ and stuff/../ how can i adapt what i'm doing to work?

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  • Converting time period strings to value/unit pair

    - by randomtoor
    I need to parse the contents of a string that represents a time period. The format of the string is value/unit, e.g.: 1s, 60min, 24h. I would separate the actual value (an int) and unit (a str) to separated variables. At the moment I do it like this: def validate_time(time): binsize = time.strip() unit = re.sub('[0-9]','',binsize) if unit not in ['s','m','min','h','l']: print "Error: unit {0} is not valid".format(unit) sys.exit(2) tmp = re.sub('[^0-9]','',binsize) try: value = int(tmp) except ValueError: print "Error: {0} is not valid".format(time) sys.exit(2) return value,unit However, it is not ideal as things like 1m0 are also (wrongly) validated (value=10,unit=m). What is the best way to validate/parse this input?

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  • regular expression repeating subexpression

    - by Michael Z
    I have the following text <pattern name="pattern1"/> <success>success case 1</success> <failed> failure 1</failed> <failed> failure 2</failed> <unknown> unknown </unknown> <pattern name="pattern2"/> <success>success case 2</success> <otherTag>There are many other tags.</otherTag> <failed> failure 3</failed> And the regular expression <failed>[\w|\W]*?</failed> matches all the lines contains failed tag. What do I need to to if I want to include the lines contains pattern tag as well? Basically, I want the following output: <pattern name="pattern1"/> <failed> failure 1</failed> <failed> failure 2</failed> <pattern name="pattern2"/> <failed> failure 3</failed> I am doing this in javascript, I do not mind of doing some intermediate steps.

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