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  • Tell a user whether they have already viewed an item in a list. How?

    - by user2738308
    It is pretty common for a web application to display a list of items and for each item in the list to indicate to the current user whether they have already viewed the associated item. An approach that I have taken in the past is to store HasViewed objects that contain the Id of a viewed item and the Id of the User who has viewed that item. When it comes time to display a list of items this requires querying for the items, and separately querying for the HasViewed objects, and then combining the results into a set of objects constructed solely for the purpose of displaying them in the view. Each e.g li then uses the e.g. has_viewed property of the objects constructed above. I would like to know whether others take a different approach and can recommend alternative ways to achieve this functionality.

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  • Let a model instance choose appropriate view class using category. Is it good design?

    - by Denis Mikhaylov
    Assume I have abstract base model class called MoneySource. And two realizations BankCard and CellularAccount. In MoneysSourceListViewController I want to display a list of them, but with ListItemView different for each MoneySource subclass. What if I define a category on MoneySource @interface MoneySource (ListItemView) - (Class)listItemViewClass; @end And then override it for each concrete sublcass of MoneySource, returning suitable view class. @implementation CellularAccount (ListItemView) - (Class)listItemViewClass { return [BankCardListView class]; } @end @implementation BankCard (ListItemView) - (Class)listItemViewClass { return [CellularAccountListView class]; } @end so I can ask model object about its view, not violating MVC principles, and avoiding class introspection or if constructions. Thank you!

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  • IT User Adoption Survey - UPK Users we need YOU!

    - by user708585
    Oracle UPK is teaming with Neochange, a recognized user adoption leader, to produce the 4th IT Adoption Insight Report Complete the following survey for a chance to win an Apple IPad!* Help develop insight into the challenges and trends occurring in IT Adoption by participating in the 2012 survey. The information gathered is used to prepare the 2012 IT Adoption Insight Report, used by industry leaders to understand challenges and trends in IT Adoption. This year the report focuses on understanding the business impact of various end-user strategies and adoption barriers. This survey should take no more than 15 minutes of your time and each participant will receive a complimentary copy of the report: https://www.surveymonkey.com/s/2012_Adoption_Insight_Report To view the prior report: IT Adoption Insight Report Thank you in advance for your participation! *One Apple iPad will be given away to a randomly selected survey participant who completes the survey by January 15, 2012. The winner will be notified by email by January 31, 2012.

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  • Run a script with user interaction on log out / shutdown?

    - by lumbric
    I'd like to run a script on shut down, which interrupts the logout process and and pops up a window with zenity. My target is to get autofsck working with lightdm. It seems to work with 12.04 after installing the old *.deb file, if one runs the check script manually. In order to use it, it should run automatically on log out and ask the user if she/he wants to check the disc on shutdown. There is the option session-cleanup-script in the file /etc/lightdm/lightdm.conf which seems to work, if a bash file with full path is used (I can't place the command directly there). But if I press shutdown, there is no time for a user choice. Is there any other option to solve this problem?

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  • How can I set up private, per-user sections on Joomla?

    - by Michael Paulukonis
    For this weekend's GiveCamp project, my team has been tasked with adding some functionality to an existing Joomla-powered website for a non-profit. A certain type of user will login, and have access to a personal area where they can upload files, check for messages, see tasks that have been assigned, etc. Each user would have their own area. They would not be creating pages, and their information would only be visible to themselves (or a site-administrator, of course. No sort of weird HIPAA privacy involved). None of us have worked with Joomla before, but we'd like to help this non-profit. We're not sure if we're searching using the wrong terms, or if we're just not finding it. Is such a solution possible in Joomla? And/or are we better off building some standalone solution that interfaces with the same mySQL database as Joomla?

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  • Made a .dmg for a project; user can't open it - "no mountable file systems"

    - by dragonridingsorceress
    Hello, We don't know a great deal about Macs. We had to make an installer, and were told to try a .dmg So we put together version 1, and it seemed to work. We had one application file, which had our icon, and one folder. The user was instructed to drag these into the Applications folder, of which there was the Mac version of a shortcut in the dmg. Then we were told we needed to update files, and assured that we could do so via drag-and-drop. So we did; we dragged them into the folder in the dmg. We tested it (on the computer we were using to edit the dmg) and it seemed to work. So we burnt it onto a disk (along with a windows installer that actually works!). I've just gotten an email from the recipient. She's got a Mac laptop. She inserted the disk, doubleclicked on it, doubleclicked on the .dmg, and got a Warning: no mountable file systems. Screenshot: http://www.flickr.com/photos/97292258@N00/5101670174/ I have the dmg (not on a disk) and am able to open it with no difficulty. How can we get it to work for our recipient?

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  • Single Full Name field in registration form user submits only first what to enter in my backend as last?

    - by Anagio
    On a registration form I have a single input called Full Name. The strings are parsed with http://code.google.com/p/php-name-parser/ so if a person enters their full name middle or any quantity of strings it's handled just fine and the app creates the user in a billing system with it's API. The form validates and checks for two strings in the field otherwise it won't post. I'd like to remove this validation but a last name is required by the API. You cannot post an empty last name to the API. Users are signing up for a trial so I don't want them having to deal with many form fields. The only place the last name shows up visible to the user is in their account settings page. If they end their trial and start a paid plan they'd have to enter their billing details which asks with two fields for their First, Last, and other billing information. What is an alternative to submitting "Doe", "Default", "Empty" in place of them not filling in their last name?

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  • How to Access User Directory shared by Apache on OS X Mountain Lion?

    - by schluchc
    When trying to access the local user web page on localhost/~username, I get a "403 Forbidden". The system web page in /Library/WebServer/Documents is accessible on localhost/ though, so I assume Apache is working fine. I know that this problem has been discussed several times, also on superuser. I implemented and checked all I could find, but I still couldn't solve the problem and would be glad if someone had a suggestion for this particular case: sudo apachectl -t returns Syntax OK. I have a username.conf file in /etc/apache2/users/: <Directory "/Users/username/Sites/"> Options Indexes MultiViews FollowSymLinks AllowOverride AuthConfig Limit Order allow,deny Allow from all </Directory> as proposed here [SuperUser] and in several other tutorials. The permissions of the username.conf file are -rw-r--r-- root wheel, as they should be. The httpd.conf is unchanged and therefore contains the line Include /private/etc/apache2/extra/httpd-userdir.conf. That file in turn contains UserDir Sites Include /private/etc/apache2/users/*.conf <IfModule bonjour_module> RegisterUserSite customized-users </IfModule> So the httpd*.conf files should be ok. The permissions of /Users/username/Sites is drwxr-xr-x 10 username staff and -rw-r--r--@ 1 username staff for the index.html. In the error log I simply get a [Sun Nov 25 22:14:32 2012] [error] [client 127.0.0.1] (13)Permission denied: access to /~username/ denied. And yes, after each change I did the sudo apachectl restart. Any help no how to solve the problem or how to further analyze it would be highly appreciated!

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  • Déploiement et configuration réseau (firewall) d'une instance CloudStack avec Apache préinstallé, troisième tutoriel d'une série sur Cloudstack

    Bonjour, Citation: CloudStack est un logiciel de cloud computing open source pour la création, la gestion et le déploiement de services de cloud d'infrastructure. Il utilise des hyperviseurs existants tels que KVM, vSphere, XenServer et / XCP pour la virtualisation. En plus de sa propre API, CloudStack prend également en charge les Amazon Web Services. Voici une série de tests effectués par Ikoula sur ce logiciel. Je vous présente ce troisième tutoriel sur Cloudstack:Déploiement...

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  • Déployer une instance Debian 7 avec un WordPress prêt à l'emploi en quelques secondes avec CloudStack, quatrième tutoriel d'une série sur Cloudstack

    Bonjour, Citation: CloudStack est un logiciel de cloud computing open source pour la création, la gestion et le déploiement de services de cloud d'infrastructure. Il utilise des hyperviseurs existants tels que KVM, vSphere, XenServer et / XCP pour la virtualisation. En plus de sa propre API, CloudStack prend également en charge les Amazon Web Services. Voici une série de tests effectués par Ikoula sur ce logiciel. Je vous présente ce quatrième tutoriel sur Cloudstack:Déployer...

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  • How can a regular user be notified of a required reboot?

    - by Andre
    I am administrating multiple machines on which I am admin and the users have not admin-rights. The machines are configured to pull and install updates automatically. A new kernel will require a reboot. On Ubuntu Precise this was made visible to the user through the color change of the shutdown-menu in the upper right corner (it turned red). Now, on Ubuntu Trusty, there is not color change anymore. Also, the Update Manager will not pop up for regular users reminding them of an outstanding reboot. How can a regular user know that a reboot is required?

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  • How do I allow a non-default user to use serial device ttyUSB0?

    - by lucaghera
    I have an Ubuntu 11.10 system with 2 users: The first was created during the installation The second instead was created after. It belongs to the sudoers group. Now the problem is that when the second tries to use a device ttyUSB0 the following error is returned: "Could not open serial port /dev/ttyUSB0" I was able to fix it by using: sudo chown :second_user /dev/ttyUSB0 However when I disconnect the device and reconnect it the problem comes back. Is there a way to allow different users to access the devices? I suppose I have to add the user to a specific group. Currently the owner is root and the group is dialout. However I'm not sure about the group and I don't know how to add the user. Thanks!

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  • System.getProperty("user.dir") cannot get my project root path ,but the path which my eclipse is located

    - by facebook-100005613813158
    As the title goes , I have class named GetException.java,inside it ,I read a xml file in a static code block like(Because this document is shared): static{ ... document = db.parse(new File(System.getProperty("user.dir")+"/src/exception/ExceptionCode.xml")); ... } To test if the file path is correct, I write a main function just inside GetException.java, it proves that the path is correct ,xml file can be read successfully. My project root dir is "/home/wuchang/workspace/MongodbI". But When this Class is loaded from other class,such as I called one of its static functions , it reports the error message: /home/mrs/??/eclipse/src/exception/ExceptionCode.xml (No such file or directory) /home/mrs/??/eclipse/ is actually my eclipse installation directory.So , I wander how System.getProperty("user.dir") returned the eclipse installation directory to me ,instead of my project root directory?

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  • SQL Server 2008 System Functions to Monitor the Instance, Database, Files, etc.

    SQL Server provides several system meta data functions which allow users to obtain property values of different SQL Server objects and securables. Although you can also use the SQL Server catalog views or Dynamic Management Views to obtain much of this information, in some circumstances the system meta data functions simplify the process. In this tip I am going to demonstrate some of the available system meta data functions and their usage in different scenarios.

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  • How can I use LightDM for user-defined sessions?

    - by Philipp
    If I unterstand it correctly, LightDM has replaced GDM per default. I wonder if it's possible to make it run the things I put in my .xinitrc file ... what I need is an option below "Unity" and "Unity 2D" which says "Run a user-defined session". Is that possible? Should be the easiest thing, but I did not get a clue so far. I export and define and run a lot of things in this file, so it's pretty important for me to have control over that. What I do NOT want is a custom session in /usr/some/where, I only want it to run the stuff from each user's xinitrc (or similar).

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  • How can I have puppet deploy ssh keys for virtual users?

    - by Pheezy
    I am trying to get puppet to assign authorized ssh keys for virtual users but I keep getting the following error: err: Could not retrieve catalog: Could not parse for environment production: Syntax error at 'user'; expected '}' at /etc/puppet/modules/users/manifests/ssh_authorized_keys.pp:9 I believe my configuration are correct (listed below) but is there a syntax error or scoping issue I am missing? I would simply like to assign users to nodes and have those users automagically have their ssh keys installed. Is there maybe a better way to do this and I'm just overthinking it? # /etc/puppet/modules/users/virtual.pp class user::virtual { @user { "user": home => "/home/user", ensure => "present", groups => ["root","wheel"], uid => "8001", password => "SCRAMBLED", comment => "User", shell => "/bin/bash", managehome => "true", } # /etc/puppet/modules/users/manifests/ssh_authorized_keys.pp ssh_authorized_key { "user": ensure => "present", type => "ssh-dss", key => "AAAAB....", user => "user", } # /etc/puppet/modules/users/init.pp import "users.pp" import "ssh_authorized_keys.pp" class user::ops inherits user::virtual { realize( User["user"], ) } # /etc/puppet/manifests/modules.pp import "sudo" import "users" # /etc/puppet/manifests/nodes.pp node basenode { include sudo } node 'testbox' inherits basenode { include user::ops } # /etc/puppet/manifests/site.pp import "modules" import "nodes" # The filebucket option allows for file backups to the server filebucket { main: server => 'puppet' } # Set global defaults - including backing up all files to the main filebucket and adds a global path File { backup => main } Exec { path => "/usr/bin:/usr/sbin/:/bin:/sbin" }

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  • How can I tell SELinux to give vsftpd write access in a specific directory?

    - by Arcturus
    Hello. I've set up vsftpd on my Fedora 12 server, and I'd like to have the following configuration. Each user should have access to: his home directory (/home/USER); the web directory I created for him (/web/USER). To achieve this, I first configured vsftpd to chroot each user to his home directory. Then, I created /web/USER with the correct permissions, and used mount --bind /web/USER /home/USER/Web so that the user may have access to /web/USER through /home/USER/Web. I also turned on the SELinux boolean ftp_home_dir so that vsftpd is allowed to write in users' home directories. This works very well, except that when a user tries to upload or rename a file in /home/USER/Web, SELinux forbids it because the change must also be done to /web/USER, and SELinux doesn't give vsftpd permission to write anything to that directory. I know that I could solve the problem by turning on the SELinux boolean allow_ftpd_full_access, or ftpd_disable_trans. I also tried to use audit2allow to generate a policy, but what it does is generate a policy that gives ftpd write access to directories of type public_content_t; this is equivalent to turning on allow_ftpd_full_access, if I understood it correctly. I'd like to know if it's possible to configure SELinux to allow FTP write access to the specific directory /web/USER and its contents, instead of disabling SELinux's FTP controls entirely.

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  • Login URL using authentication information in Django

    - by fuSi0N
    I'm working on a platform for online labs registration for my university. Login View [project views.py] from django.http import HttpResponse, HttpResponseRedirect, Http404 from django.shortcuts import render_to_response from django.template import RequestContext from django.contrib import auth def index(request): return render_to_response('index.html', {}, context_instance = RequestContext(request)) def login(request): if request.method == "POST": post = request.POST.copy() if post.has_key('username') and post.has_key('password'): usr = post['username'] pwd = post['password'] user = auth.authenticate(username=usr, password=pwd) if user is not None and user.is_active: auth.login(request, user) if user.get_profile().is_teacher: return HttpResponseRedirect('/teachers/'+user.username+'/') else: return HttpResponseRedirect('/students/'+user.username+'/') else: return render_to_response('index.html', {'msg': 'You don\'t belong here.'}, context_instance = RequestContext(request) return render_to_response('login.html', {}, context_instance = RequestContext(request)) def logout(request): auth.logout(request) return render_to_response('index.html', {}, context_instance = RequestContext(request)) URLS #========== PROJECT URLS ==========# urlpatterns = patterns('', (r'^media/(?P<path>.*)$', 'django.views.static.serve', {'document_root': settings.MEDIA_ROOT }), (r'^admin/', include(admin.site.urls)), (r'^teachers/', include('diogenis.teachers.urls')), (r'^students/', include('diogenis.students.urls')), (r'^login/', login), (r'^logout/', logout), (r'^$', index), ) #========== TEACHERS APP URLS ==========# urlpatterns = patterns('', (r'^(?P<username>\w{0,50})/', labs), ) The login view basically checks whether the logged in user is_teacher [UserProfile attribute via get_profile()] and redirects the user to his profile. Labs View [teachers app views.py] from django.http import HttpResponse, HttpResponseRedirect, Http404 from django.shortcuts import render_to_response from django.template import RequestContext from django.contrib.auth.decorators import user_passes_test from django.contrib.auth.models import User from accounts.models import * from labs.models import * def user_is_teacher(user): return user.is_authenticated() and user.get_profile().is_teacher @user_passes_test(user_is_teacher, login_url="/login/") def labs(request, username): q1 = User.objects.get(username=username) q2 = u'%s %s' % (q1.last_name, q1.first_name) q2 = Teacher.objects.get(name=q2) results = TeacherToLab.objects.filter(teacher=q2) return render_to_response('teachers/labs.html', {'results': results}, context_instance = RequestContext(request)) I'm using @user_passes_test decorator for checking whether the authenticated user has the permission to use this view [labs view]. The problem I'm having with the current logic is that once Django authenticates a teacher user he has access to all teachers profiles basically by typing the teachers username in the url. Once a teacher finds a co-worker's username he has direct access to his data. Any suggestions would be much appreciated.

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  • TypeError: unbound method make_request() must be called with XX instance, but how?

    - by Dave
    Running the code below I get E TypeError: unbound method make_request() must be called with A instance as first argument (got str instance instead) I dont want to set make_request method as static, I want to call it from an instance of an object. The example http://pytest.org/latest/fixture.html#fixture-function # content of ./test_smtpsimple.py import pytest @pytest.fixture def smtp(): import smtplib return smtplib.SMTP("merlinux.eu") def test_ehlo(smtp): response, msg = smtp.ehlo() assert response == 250 assert "merlinux" in msg assert 0 # for demo purposes My code """ """ import pytest class A(object): """ """ def __init__(self, name ): """ """ self._prop1 = [name] @property def prop1(self): return self._prop1 @prop1.setter def prop1(self, arguments): self._prop1 = arguments def make_request(self, sex): return 'result' def __call__(self): return self @pytest.fixture() def myfixture(): """ """ A('BigDave') return A def test_validateA(myfixture): result = myfixture.make_request('male') assert result =='result'

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  • set a default saving data in a selection box in HABTM model

    - by vincent low
    here is my problem which in my system. my system allow user to add event, which include date, time, places. In the other hand, user are allow to choose the "Event sharing to" some of other user. So i successful to created and share to other user, when the user login which are being choose to share with the event, he is able to view for that particular event. But the problem is, when user add the event, he must choose for his own name also in the select box. If not he will be unable to read the event that he had created. So i need to save a default data to my model, which is whenever the user got choose the sharing event or not, it also will save the data to his user id. here is my code for select box, what can i edit and do to let it set a default saving value which is always save with the user own data?? input('User',array( 'label' = 'Select Related Potential', 'options' = $users, //'id'='user', 'style'='width:250px;height:100px', //'selected' = $ownUserId )); ? i try to solve by adding 1 more row to the add.ctp, but the permission just set to the own user who created it, the other user i choose is unable to read. $form-input('User',array( 'label' = 'Select Related Potential', 'options' = $users, //'id'='user', 'style'='width:250px;height:100px', 'selected' = $ownUserId )); $form-input('User',array('type'='hidden','value'=$ownUserId));

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  • In PHP, is it possible to create an instance of an class without calling class's constructor ?

    - by Rachel
    By any means, is it possible to create an instance of an php class without calling its constructor ? I have Class A and while creating an instance of it am passing file and in constructor of Class A am opening the file. Now in Class A, there is function which I need to call but am not required to pass file and so there is not need to use constructor functionality of opening file as am not passing file. So my question is, Is it possible by any means to create an instance of an PHP class without calling its constructor ?

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  • How can I create a new class instance from a class within a (static) class?

    - by Mervin
    I'm new to Java (have experience with C#), This is what i want to do: public final class MyClass { public class MyRelatedClass { ... } } public class OtherRandomClass { public void DoStuff() { MyRelatedClass data = new MyClass.MyRelatedClass(); } } which gives this error in Eclipse: "No enclosing instance of type BitmapEffects is accessible. Must qualify the allocation with an enclosing instance of type BitmapEffects (e.g. x.new A() where x is an instance of BitmapEffects)." this is possible in C# with static classes , how should it be done here?

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  • Program freezing when syncing a ldap database (100+ entries added)

    - by djerry
    Hey guys, I'm updating a ldap database. I need to add a list of users to the db. I've written a simple foreach loop. There are about 180 users i need to add, but at the 128th user, the program freezes. I know ldap is really used for querying (fast), and that adding and modifying entries will not go as smooth as a search query, but is it normal that the program freezes while doing this? I'll post some code just in case. public static void SyncLDAPWithMySql(Novell.Directory.Ldap.LdapConnection _conn) { List<User> users = GetUsers(); int iteller = 0; foreach (User user in users) { if (!UserAlreadyInLdap(user, _conn)) { TelUser teluser = new TelUser(); teluser.Telephone = user.E164; teluser.Uid = user.E164; teluser.Company = "/"; teluser.Dn = ""; teluser.Name = "/"; teluser.DisplayName = "/"; teluser.FirstName = "/"; TelephoneDA.InsertUser(_conn, teluser ); } Console.WriteLine(iteller + " : " + user.E164); iteller++; } } private static bool UserAlreadyInLdap(User user, Novell.Directory.Ldap.LdapConnection _conn) { List<TelUser> users = TelephoneDA.GetAllEntries(_conn); foreach (TelUser teluser in users) { if (teluser.Telephone.Equals(user.E164)) return true; } return false; } public static int InsertUser(LdapConnection conn, TelUser user) { int iResponse = IsTelNumberUnique(conn, user.Dn, user.Telephone); if (iResponse == 0) { LdapAttributeSet attrSet = MakeAttSet(user); string dnForPhonebook = configurationManager.AppSettings.Get("phonebookDn"); LdapEntry ent = new LdapEntry("uid=" + user.Uid + "," + dnforPhonebook, attrSet); try { conn.Add(ent); } catch (Exception ex) { Console.WriteLine(ex.Message); } } return iResponse; } Am i adding too many entries at a time??? Thanks in advance.

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  • How do I dynamically update an instance array to hold a list of dynamic methods on instantiation?

    - by Will
    I am trying to dynamically define methods based on xml mappings. This works really well. However I want to create an instance variable that is a array of the dynamically defined methods. My code looks something like this def xml_attr_reader(*args) xml_list = "" args.each do |arg| string_val = "def #{arg}; " + " xml_mapping.#{arg}; " + "end; " self.class_eval string_val xml_hash = xml_list + "'#{arg}'," end self.class_eval "@xml_attributes = [] if @xml_attributes.nil?;" + "@xml_attributes = @xml_attributes + [#{xml_list}];" + "puts 'xml_attrs = ' + @xml_attributes.to_s;" + "def xml_attributes;" + " puts 'xml_attrs = ' + @xml_attributes.to_s;" + " @xml_attributes;" + "end" end So everything works except when I call xml_attributes on an instance it return null (and prints out 'xml_attrs = '). While the puts before the definition actually prints out the correct array. (when I instantiate the instance)

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  • Given an instance of a Ruby object, how do I get its metaclass?

    - by Stanislaus Wernstrom
    Normally, I might get the metaclass for a particular instance of a Ruby object with something like this: class C def metaclass class << self; self; end end end # This is this instance's metaclass. C.new.metaclass => #<Class:#<C:0x01234567>> # Successive invocations will have different metaclasses, # since they're different instances. C.new.metaclass => #<Class:#<C:0x01233...>> C.new.metaclass => #<Class:#<C:0x01232...>> C.new.metaclass => #<Class:#<C:0x01231...>> Let's say I just want to know the metaclass of an arbitrary object instance obj of an arbitrary class, and I don't want to define a metaclass (or similar) method on the class of obj. Is there a way to do that?

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